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  • Do I have to use mysql_real_escape_string if I bind parameters?

    - by Babak
    I have the following code: function dbPublish($status) { global $dbcon, $dbtable; if(isset($_GET['itemId'])) { $sqlQuery = 'UPDATE ' . $dbtable . ' SET active = ? WHERE id = ?'; $stmt = $dbcon->prepare($sqlQuery); $stmt->bind_param('ii', $status, $_GET['itemId']); $stmt->execute(); $stmt->close(); } } Do I need to mysql_real_escape_string in this case or am i okay?

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  • How to fix unresolved external symbol due to MySql Connector C++?

    - by Chan
    Hi everyone, I followed this tutorial http://blog.ulf-wendel.de/?p=215#hello. I tried both on Visual C++ 2008 and Visual C++ 2010. Either static or dynamic, the compiler gave me the same exact error messages: error LNK2001: unresolved external symbol _get_driver_instance Has anyone experience this issue before? Update: + Additional Dependencies: mysqlcppconn.lib + Additional Include Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\include + Additional Libraries Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\lib\opt Thanks, Chan Nguyen

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  • Adding binary checkbox values to MySQL database using PHP

    - by klyv
    I'm new to PHP, and I am creating a basic CMS using PHP and MySQL. I'm struggling to get the checkbox information from my HTML page across into the database. How can I make the values to appear as binary 0 or 1 values? The HTML document is written as follows: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Create your news page</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head> <body> <fieldset> <legend>Checked components will show in the page</legend> <form method="POST" action="http://*********.php"> <span class="label">Header</span> <input type="checkbox" name="header" value="HEADER"> <br> <span class="label">Footer</span> <input type="checkbox" name="footer" value="FOOTER"> <hr> <span class="label">Local news</span> <input type="checkbox" name="local" value="LOCALNEWS"> <br> <span class="label">National news</span> <input type="checkbox" name="national" value="NATIONALNEWS"> <br> <span class="label">International news</span> <input type="checkbox" name="international" value="INTERNATIONALNEWS"> <p> <input type="submit"> </form> </fieldset> </body> </html> And the PHP document is written as follows: <?php $user="user_***"; $password="*********"; $database="dbxyz"; mysql_connect("localhost", $user, $password); mysql_select_db($database, $db_handle); mysql_select_db("dbxyz"); if(isset($_POST['layout'])) { foreach($_POST['layout'] as $value { $insert="INSERT INTO layout (header, footer, local, national, international) VALUES ('$value')"; mysql_query($insert); } } ?>

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  • mysql index optimization for a table with multiple indexes that index some of the same columns

    - by Sean
    I have a table that stores some basic data about visitor sessions on third party web sites. This is its structure: id, site_id, unixtime, unixtime_last, ip_address, uid There are four indexes: id, site_id/unixtime, site_id/ip_address, and site_id/uid There are many different types of ways that we query this table, and all of them are specific to the site_id. The index with unixtime is used to display the list of visitors for a given date or time range. The other two are used to find all visits from an IP address or a "uid" (a unique cookie value created for each visitor), as well as determining if this is a new visitor or a returning visitor. Obviously storing site_id inside 3 indexes is inefficient for both write speed and storage, but I see no way around it, since I need to be able to quickly query this data for a given specific site_id. Any ideas on making this more efficient? I don't really understand B-trees besides some very basic stuff, but it's more efficient to have the left-most column of an index be the one with the least variance - correct? Because I considered having the site_id being the second column of the index for both ip_address and uid but I think that would make the index less efficient since the IP and UID are going to vary more than the site ID will, because we only have about 8000 unique sites per database server, but millions of unique visitors across all ~8000 sites on a daily basis. I've also considered removing site_id from the IP and UID indexes completely, since the chances of the same visitor going to multiple sites that share the same database server are quite small, but in cases where this does happen, I fear it could be quite slow to determine if this is a new visitor to this site_id or not. The query would be something like: select id from sessions where uid = 'value' and site_id = 123 limit 1 ... so if this visitor had visited this site before, it would only need to find one row with this site_id before it stopped. This wouldn't be super fast necessarily, but acceptably fast. But say we have a site that gets 500,000 visitors a day, and a particular visitor loves this site and goes there 10 times a day. Now they happen to hit another site on the same database server for the first time. The above query could take quite a long time to search through all of the potentially thousands of rows for this UID, scattered all over the disk, since it wouldn't be finding one for this site ID. Any insight on making this as efficient as possible would be appreciated :) Update - this is a MyISAM table with MySQL 5.0. My concerns are both with performance as well as storage space. This table is both read and write heavy. If I had to choose between performance and storage, my biggest concern is performance - but both are important. We use memcached heavily in all areas of our service, but that's not an excuse to not care about the database design. I want the database to be as efficient as possible.

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  • MYSQL Select and group by date

    - by Gil
    I'm not sure how create a right query to get the result I'm looking for. What I have is 2 tables. first has ID, Name columns and second has date and adminID, which is referenced from table 1 column ID. Now, what I want to get is basically number of times each admin loged in per day during the month. From structure like this one I want to get per day and month data so result would be similar to 1, 2, 2 march total 5 for admin 4. ID | Date ------------------ 4 | 2010/03/01 4 | 2010/03/04 4 | 2010/03/04 4 | 2010/03/05 4 | 2010/03/05

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  • Optimize GROUP BY&ORDER BY query

    - by Jan Hancic
    I have a web page where users upload&watch videos. Last week I asked what is the best way to track video views so that I could display the most viewed videos this week (videos from all dates). Now I need some help optimizing a query with which I get the videos from the database. The relevant tables are this: video (~239371 rows) VID(int), UID(int), title(varchar), status(enum), type(varchar), is_duplicate(enum), is_adult(enum), channel_id(tinyint) signup (~115440 rows) UID(int), username(varchar) videos_views (~359202 rows after 6 days of collecting data, so this table will grow rapidly) videos_id(int), views_date(date), num_of_views(int) The table video holds the videos, signup hodls users and videos_views holds data about video views (each video can have one row per day in that table). I have this query that does the trick, but takes ~10s to execute, and I imagine this will only get worse over time as the videos_views table grows in size. SELECT v.VID, v.title, v.vkey, v.duration, v.addtime, v.UID, v.viewnumber, v.com_num, v.rate, v.THB, s.username, SUM(vvt.num_of_views) AS tmp_num FROM video v LEFT JOIN videos_views vvt ON v.VID = vvt.videos_id LEFT JOIN signup s on v.UID = s.UID WHERE v.status = 'Converted' AND v.type = 'public' AND v.is_duplicate = '0' AND v.is_adult = '0' AND v.channel_id <> 10 AND vvt.views_date >= '2001-05-11' GROUP BY vvt.videos_id ORDER BY tmp_num DESC LIMIT 8 And here is a screenshot of the EXPLAIN result: So, how can I optimize this?

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  • mysql view performance

    - by vamsivanka
    I have a table for about 100,000 users in it. First Case: explain select * from users where state = 'ca' when i do an explain plan for the above query i got the cost as 5200 Second Case: Create or replace view vw_users as select * from users Explain select * from vw_users where state = 'ca' when i do an explain plan on the second query i got the cost as 100,000. How does the where clause in the view work ?? Is the where clause applied after the view retrieves all the rows. Please let know, how can i fix this issue. Thanks

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  • Query not returning rows in a table that don't have corresponding values in another [associative] ta

    - by Obay
    I have Table: ARTICLES ID | CONTENT --------------- 1 | the quick 2 | brown fox 3 | jumps over 4 | the lazy Table: WRITERS ID | NAME ---------- 1 | paul 2 | mike 3 | andy Table: ARTICLES_TO_WRITERS ARTICLE_ID | WRITER_ID ----------------------- 1 | 1 2 | 2 3 | 3 To summarize, article 4 has no writer. So when I do a "search" for articles with the word "the": SELECT a.id, a.content, w.name FROM articles a, writers w, articles_to_writers atw WHERE a.id=atw.article_id AND w.id=atw.writer_id AND content LIKE '%the%' article 4 does not show up in the result: ID | CONTENT | NAME ----------------------- 1 | the quick | paul How do I make article 4 still appear in the results even though it has no writers?

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  • fetching rows from mysql table and displaying them as JGROWL notifications

    - by jeansymolanza
    hey guys, i am having problems implementing my php/mysql code into a jgrowl if you are familiar with jgrowl you will know it delivers notifications like Growl does for OS X i am trying to get it read all the records from my table but at the moment it is only displaying one record as a notification and it loops through it 4 times another problem is that if i have 5 rows in the table then jgrowl will only display 4 notifications are going to be viewed how do i get it to view all the records in the table as notifications and how do i display the total number of records (5) as notifications and account for the missing one at the moment thanking you guys in advance... God bless <script type="text/javascript"> // In case you don't have firebug... if (!window.console || !console.firebug) { var names = ["log", "debug", "info", "warn", "error", "assert", "dir", "dirxml", "group", "groupEnd", "time", "timeEnd", "count", "trace", "profile", "profileEnd"]; window.console = {}; for (var i = 0; i < names.length; ++i) window.console[names[i]] = function() {}; } (function($){ $(document).ready(function(){ // This specifies how many messages can be pooled out at any given time. // If there are more notifications raised then the pool, the others are // placed into queue and rendered after the other have disapeared. $.jGrowl.defaults.pool = 5; var i = 1; var y = 1; setInterval( function() { if ( i < <?php echo $totalRows_comment; ?> ) { <?php echo '$.jGrowl("'.$row_comment['comment'].'",'; ?> { sticky: true, log: function() { console.log("Creating message " + i + "..."); }, beforeOpen: function() { console.log("Rendering message " + y + "..."); y++; } }); } i++; } , 1000 ); }); })(jQuery); </script> <p> </span> <p>

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  • MySQL Volleyball Standings

    - by Torez
    I have a database table full of game by game results and want to know if I can calculate the following: GP (games played) Wins Loses Points (2 points for each win, 1 point for each lose) Here is my table structure: CREATE TABLE `results` ( `id` int(10) unsigned NOT NULL auto_increment, `home_team_id` int(10) unsigned NOT NULL, `home_score` int(3) unsigned NOT NULL, `visit_team_id` int(10) unsigned NOT NULL, `visit_score` int(3) unsigned NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ; And a few testing results: INSERT INTO `results` VALUES(1, 1, 21, 2, 25); INSERT INTO `results` VALUES(2, 3, 21, 4, 17); INSERT INTO `results` VALUES(3, 1, 25, 3, 9); INSERT INTO `results` VALUES(4, 2, 7, 4, 22); INSERT INTO `results` VALUES(5, 1, 19, 4, 20); INSERT INTO `results` VALUES(6, 2, 24, 3, 26); Here is what a final table would look like: +-------------------+----+------+-------+--------+ | Team Name | GP | Wins | Loses | Points | +-------------------+----+------+-------+--------+ | Spikers | 4 | 4 | 0 | 8 | | Leapers | 4 | 2 | 2 | 6 | | Ground Control | 4 | 1 | 3 | 5 | | Touch Guys | 4 | 0 | 4 | 4 | +-------------------+----+------+-------+--------+

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  • I'm confused about encryption and SSL

    - by ChowKiko
    while my friends and I planning to run our own website, we're confused about the encryption where hackers can TAPPING or in social engineering it's WIRE TAPPING, but I don't know how do they call it in Computers today... Well guys, I just want to know how encryption works with websites if we are using PHP+MYSQL? Is it ok to use user login ---- (PHP) encrypt inputted value then (PHP) will decrypt and validate it going to (MySQL) user login ---- (PHP) encrypt inputted value and decrypt the (MySQL) data if they are similar... Is it similar if we use $_SESSION without encryption inside PHP going to MySQL?or PHP encryption also helps the manipulation of binaries?..I'm so confused T_T... In regards to what I stated above, can a hacker hook the data if the server uses $_SESSION? Is $_SESSION safe?... IF THE HACKER CAN HOOK it? is it necessary to use SSL on our website? and why do some Merchandise websites use SSL and likewise facebook also uses SSL? what is the best suit for you if there is no SSL? encrypting the DATA using PHP going to MySQL or even without encryption while the PHP server uses $_SESSION?...

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  • How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

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  • SQL Outer Join on a bunch of Inner Joined results

    - by Matthew Frederick
    I received some great help on joining a table to itself and am trying to take it to the next level. The SQL below is from the help but with my addition of the select line beginning with COUNT, the inner join to the Recipient table, and the Group By. SELECT Event.EventID AS EventID, Event.EventDate AS EventDateUTC, Participant2.ParticipantID AS AwayID, Participant1.ParticipantID AS HostID, COUNT(Recipient.ChallengeID) AS AllChallenges FROM Event INNER JOIN Matchup Matchup1 ON (Event.EventID = Matchup1.EventID) INNER JOIN Matchup Matchup2 ON (Event.EventID = Matchup2.EventID) INNER JOIN Participant Participant1 ON (Matchup1.Host = 1 AND Matchup1.ParticipantID = Participant1.ParticipantID) INNER JOIN Participant Participant2 ON (Matchup2.Host != 1 AND Matchup2.ParticipantID = Participant2.ParticipantID) INNER JOIN Recipient ON (Event.EventID = Recipient.EventID) WHERE Event.CategoryID = 1 AND Event.Resolved = 0 AND Event.Type = 1 GROUP BY Recipient.ChallengeID ORDER BY EventDateUTC ASC My goal is to get a count of how many rows in the Recipient table match the EventID in Event. This code works fine except that I also want to get results where there are 0 matching rows in Recipient. I want 15 rows (= the number of events) but I get 2 rows, one with a count of 1 and one with a count of 2 (which is appropriate for an inner join as there are 3 rows in the sample Recipient table, one for one EventID and two for another EventID). I thought that either a LEFT join or an OUTER join was what I was looking for, but I know that I'm not quite getting how the tables are actually joined. A LEFT join there gives me one more row with 0, which happens to be EventID 1 (first thing in the table), but that's all. Errors advise me that I can't just change that INNER join to an OUTER. I tried some parenthesizing and some subselects and such but can't seem to make it work.

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  • mysql query execution time - can i get this in milliseconds?

    - by Max Williams
    I'm comparing a few different approaches to getting some data in mysql, directly at the console, using the SQL_NO_CACHE option to make sure mysql keeps running the full query every time. Mysql gives me the execution time back in seconds, to two decimal places. I'd really like to get the result back in milliseconds (ideally to one or two decimal places), to get a better idea of improvements (or lack of). Is there an option i can set in mysql to achieve this? thanks, max

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  • new project; entire node.js app

    - by Jared
    I have been looking into Node.js, express and Nowjs and love how easy it is to have real time interactions between clients. My background is mostly from CodeIgniter MVC using PHP and MYSql. I want to re make a current web project of mine from scratch to make everything better and more real time with this newer technology. After researching and doing test examples I want to use node.js , express and Nowjs for the real time interactions once someone connects to the socket.io to pull data back to clients. But use Code Igniter for the control of the site and user management , possible shopping cart/store , pretty much everything else. This is purely due to time constraints and that I am already familiar with doing it that way. I have been looking at MongoDB as an alternative to MySql, Basically the app is going to be multiple chat rooms all on one page. with the ability of notifications and private messaging. Lots of data transfer and images. before I started piecing it together I wanted to get people who have already done something similar. My model would use Code Igniter and MySQL to render the page and then connect them onto a node.js server and broadcast using express and nowjs would using a mongoDB be better than mySQL for tons of messages and data being stored or MYSQL? Also does it make since to not make the whole site on Node.js , kinda piece it together like that? I was asked to re post this somewhere else as it was not up to the format for SO, OP from here http://stackoverflow.com/questions/12649469/new-project-need-some-start-up-advice-node-js-app#comment17062924_12649469

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  • Does this mySQL Stored Procedure Work?

    - by Laxmidi
    Hi, I got the following stored procedure from http://dev.mysql.com/doc/refman/5.1/en/functions-that-test-spatial-relationships-between-geometries.html Does this work? CREATE FUNCTION myWithin(p POINT, poly POLYGON) RETURNS INT(1) DETERMINISTIC BEGIN DECLARE n INT DEFAULT 0; DECLARE pX DECIMAL(9,6); DECLARE pY DECIMAL(9,6); DECLARE ls LINESTRING; DECLARE poly1 POINT; DECLARE poly1X DECIMAL(9,6); DECLARE poly1Y DECIMAL(9,6); DECLARE poly2 POINT; DECLARE poly2X DECIMAL(9,6); DECLARE poly2Y DECIMAL(9,6); DECLARE i INT DEFAULT 0; DECLARE result INT(1) DEFAULT 0; SET pX = X(p); SET pY = Y(p); SET ls = ExteriorRing(poly); SET poly2 = EndPoint(ls); SET poly2X = X(poly2); SET poly2Y = Y(poly2); SET n = NumPoints(ls); WHILE i<n DO SET poly1 = PointN(ls, (i+1)); SET poly1X = X(poly1); SET poly1Y = Y(poly1); IF ( ( ( ( poly1X <= pX ) && ( pX < poly2X ) ) || ( ( poly2X <= pX ) && ( pX < poly1X ) ) ) && ( pY > ( poly2Y - poly1Y ) * ( pX - poly1X ) / ( poly2X - poly1X ) + poly1Y ) ) THEN SET result = !result; END IF; SET poly2X = poly1X; SET poly2Y = poly1Y; SET i = i + 1; END WHILE; RETURN result; End; Usage: SET @point = PointFromText('POINT(5 5)') ; SET @polygon = PolyFromText('POLYGON((0 0,10 0,10 10,0 10))') ; SELECT myWithin(@point, @polygon) AS result ; I'm using phpMyAdmin and it blows up when using stored procedures. If this one works, then I'll try to figure out how to call it in php instead. Thanks, Laxmidi

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  • mySql table returning JSON that needs formatting for a iPhone UITableview

    - by Michael Robinson
    I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I can figure out where/how to convert this, Where would I create the formatting following: (1) In the php return? (2) the JSON instructions for deserialization? or (3) Some kinb of Obj-C coding instruction? My end use is a simple Drill Down table using the NSObject, so when I select "memberid" row, I'll get the child/detail list on the next UITableview. My Data.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance, this site rocks.

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  • MySQL: Copy a field to another table

    - by harpax
    I have a table posts that could look like this: id | title | body | created | .. ------------------------------------------- I would like to use the boolean search feature that is offered by a MyISAM Table, but the posts table is InnoDB. So I created another table 'post_contents' that looks like this: post_id | body -------------------- That table is already filled with some contents and I can use the boolean search. However, I need to move the title field in the post_contents table as well and then copy the existing title-data to the new field. I know about the INSERT .. SELECT syntax, but I don't seem to be able to create the correct query.

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  • Newbie's problems with MySQL and php

    - by Mirage81
    I'm a real newbie with php and MySQL. Now I'm working on the following code which should search the database for eg. all the Lennons living in Liverpool. 1) How should I modify "get.php" to get the text "no results" to appear if there are no search results. 2) How should I modify "index.php" to get the option values (city and lastname) straight from the database instead of having to type them one by one? 3) Am I using mysql_real_escape_string the right way? 4) Any other mistakes in the code? index.php: <form action="get.php" method="post"> <p> <select name="city"> <option value="Birmingham">Birmingham</option> <option value="Liverpool">Liverpool</option> <option value="London">London</option> </select> </p> <p> <select name="lastname"> <option value="Lennon">Lennon</option> <option value="McCartney">McCartney</option> <option value="Osbourne">Osbourne</option> </select> </p> <p> <input value="Search" type="submit"> </p> </form> get.php: <?php $city = $_POST['city']; $lastname = $_POST['lastname']; $conn = mysql_connect('localhost', 'user', 'password'); mysql_select_db("database", $conn) or die("connection failed"); $query = "SELECT * FROM users WHERE city = '$city' AND lastname = '$lastname'"; $result = mysql_query($query, $conn); $city = mysql_real_escape_string($_POST['city']); $lastname = mysql_real_escape_string($_POST['lastname']); echo $rowcount; while ($row = mysql_fetch_row($result)) { if ($rowcount == '0') echo 'no results'; else { echo '<b>City: </b>'.htmlspecialchars($row[0]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[1]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[2]); } } mysql_close($conn);

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  • Django Encoding Issues with MySQL

    - by Jordan Reiter
    Okay, so I have a MySQL database set up. Most of the tables are latin1 and Django handles them fine. But, some of them are UTF-8 and Django does not handle them. Here's a sample table (these tables are all from django-geonames): DROP TABLE IF EXISTS `geoname`; SET @saved_cs_client = @@character_set_client; SET character_set_client = utf8; CREATE TABLE `geoname` ( `id` int(11) NOT NULL, `name` varchar(200) NOT NULL, `ascii_name` varchar(200) NOT NULL, `latitude` decimal(20,17) NOT NULL, `longitude` decimal(20,17) NOT NULL, `point` point default NULL, `fclass` varchar(1) NOT NULL, `fcode` varchar(7) NOT NULL, `country_id` varchar(2) NOT NULL, `cc2` varchar(60) NOT NULL, `admin1_id` int(11) default NULL, `admin2_id` int(11) default NULL, `admin3_id` int(11) default NULL, `admin4_id` int(11) default NULL, `population` int(11) NOT NULL, `elevation` int(11) NOT NULL, `gtopo30` int(11) NOT NULL, `timezone_id` int(11) default NULL, `moddate` date NOT NULL, PRIMARY KEY (`id`), KEY `country_id_refs_iso_alpha2_e2614807` (`country_id`), KEY `admin1_id_refs_id_a28cd057` (`admin1_id`), KEY `admin2_id_refs_id_4f9a0f7e` (`admin2_id`), KEY `admin3_id_refs_id_f8a5e181` (`admin3_id`), KEY `admin4_id_refs_id_9cc00ec8` (`admin4_id`), KEY `fcode_refs_code_977fe2ec` (`fcode`), KEY `timezone_id_refs_id_5b46c585` (`timezone_id`), KEY `geoname_52094d6e` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; SET character_set_client = @saved_cs_client; Now, if I try to get data from the table directly using MySQLdb and a cursor, I get the text with the proper encoding: >>> import MySQLdb >>> from django.conf import settings >>> >>> conn = MySQLdb.connect (host = "localhost", ... user = settings.DATABASES['default']['USER'], ... passwd = settings.DATABASES['default']['PASSWORD'], ... db = settings.DATABASES['default']['NAME']) >>> cursor = conn.cursor () >>> cursor.execute("select name from geoname where name like 'Uni%Hidalgo'"); 1L >>> g = cursor.fetchone() >>> g[0] 'Uni\xc3\xb3n Hidalgo' >>> print g[0] Unión Hidalgo However, if I try to use the Geoname model (which is actually a django.contrib.gis.db.models.Model), it fails: >>> from geonames.models import Geoname >>> g = Geoname.objects.get(name__istartswith='Uni',name__icontains='Hidalgo') >>> g.name u'Uni\xc3\xb3n Hidalgo' >>> print g.name Unión Hidalgo There's pretty clearly an encoding error here. In both cases the database is returning 'Uni\xc3\xb3n Hidalgo' but Django is (incorrectly?) translating the '\xc3\xb3n' to ó. What can I do to fix this?

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  • Count query with 3 coloumn iin SQL

    - by asher baig
    I have one database Library with table named called Medien. Having multiple columns named as Fname,Mname,Lname and ISBN. I want to calculate database records with ISBN and without ISBN? I have execute following command Select COUNT(ISBN) as Verf1 FROM library.MEDIEN where verf1 = isbn; Select COUNT(ISBN) as Verf2 FROM library.MEDIEN where verf2 = isbn; Select COUNT(ISBN) as Verf3 FROM library.MEDIEN where verf3 = isbn; Select COUNT(ISBN) as Ntverf1 FROM library.MEDIENwhere verf1 != isbn; Select COUNT(ISBN) as Ntverf2 FROM library.MEDIENwhere verf2 != isbn; Select COUNT(ISBN) as Ntverf3 FROM library.MEDIENwhere verf3 != isbn; I am not sure i execute correct command or not. Because some ISBN records have Fname,Mname or Fname,Lname or Mname,Lname or Fname , Lname,Mname only respectively. Please kindly help me solving this query

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  • Selecting from 2 tables in a single query

    - by duder
    I have a table that I'm querying for value 43 in the second field and I return the value of the third field SELECT t1_field3 FROM table1 WHERE t1_field2=43 this returns 19, 39,73 t1_id t1_field2 t1_field3 ----- --------- --------- 1 43 19//// 2 43 39//// 3 43 73//// 4 73 43 5 13 40 Then I separately query a second table for additional information SELECT * FROM table2 WHERE t2_id=t1_field3 t2_id t2_field2 t2_field3 ----- --------- --------- 19 value19.2 value19.3 39 value39.2 value39.3 73 value73.2 value73.3 Is there a way I could combine both table1 and table2 in the same query?

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  • Find products that have a list of attributes.

    - by bellesebastien
    I'm stuck trying to solve a problem that's proving to be more difficult than it seems. Consider there is a table that associates products with attributes, it looks like this: Products_id | Attribute_id 21 | 456 21 | 231 21 | 26 22 | 456 22 | 26 22 | 116 23 | 116 23 | 231 Next, I have a list of attribute_ids which I want to use in order to get the products that have all the attributes in that list. For example if I search in the table above using this list (456, 26) I should get these product_ids 21 and 22. Another example, if I search for (116, 231) I should get an empty response since there are no products that have both these attributes. How can I achieve this using one query? I hope I made my question clear. Thanks.

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