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  • Why am I getting "(304) Not Modified" error on some links when using HttpWebRequest?

    - by Greg
    Hi, Any ideas why on some links that I try to access using HttpWebRequest I am getting "The remote server returned an error: (304) Not Modified." in the code? The code I'm using is from Jeff's post here. Note the concept of the code is a simple proxy server, so I'm pointing my browser at this locally running piece of code, which gets my browsers request, and then proxies it on by creating a new HttpWebRequest, as you'll see in the code. It works great for most sites/links, but for some this error comes up. You will see one key bit in the code is where it seems to copy the http header settings from the browser request to it's request out to the site, and it copies in the header attributes. Not sure if the issue is something to do with how it mimics this aspect of the request and then what happens as the result comes back? case "If-Modified-Since": request.IfModifiedSince = DateTime.Parse(listenerContext.Request.Headers[key]); break; I get the issue for example from http://en.wikipedia.org/wiki/Main_Page thanks

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  • Combining the streams:Web application

    - by Surendra J
    This question deals mainly with streams in web application in .net. In my webapplication I will display as follows: bottle.doc sheet.xls presentation.ppt stackof.jpg Button I will keep checkbox for each one to select. Suppose a user selected the four files and clicked the button,which I kept under. Then I instantiate clasees for each type of file to convert into pdf, which I wrote already and converted them into pdf and return them. My problem is the clases is able to read the data form URL and convert them into pdf. But I don't know how to return the streams and merge them. string url = @"url"; //Prepare the web page we will be asking for HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url); request.Method = "GET"; request.ContentType = "application/mspowerpoint"; request.UserAgent = "Mozilla/4.0+(compatible;+MSIE+5.01;+Windows+NT+5.0"; //Execute the request HttpWebResponse response = (HttpWebResponse)request.GetResponse(); //We will read data via the response stream Stream resStream = response.GetResponseStream(); //Write content into the MemoryStream BinaryReader resReader = new BinaryReader(resStream); MemoryStream PresentaionStream = new MemoryStream(resReader.ReadBytes((int)response.ContentLength)); //convert the presention stream into pdf and save it to local disk. But I would like to return the stream again. How can I achieve this any Ideas are welcome.

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  • Getting 404 page not found connecting to webDAV

    - by Cragly
    I am trying to connect to a secure webDAV folder and download a file. I am having problems just trying to get a response from the server and as it keeps giving me a 404 page not found error as soon as I call Request.GetResponse(). I can connect to the webDAV folder using Windows Explorer by mapping a drive but cannot seem to do this in code. I have looked at other post on this site and others online but most seem to concentrate on connecting to Outlook. Has anybody else had this issue? The code I am using is as follows: string URI = "https://transfer.mycompany.com/myDirectory/myFile.csv"; string username = "username"; string password = "password"; Request = (HttpWebRequest) WebRequest.Create(URI); Request.Credentials = new NetworkCredential(username, password); Request.Method = WebRequestMethods.Http.Get; Request.Headers.Add("Translate", "f"); Response = (HttpWebResponse) Request.GetResponse(); contentLength = Convert.ToInt64(Response.GetResponseHeader("Content-Length"));

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  • Getting 404 Not Found connecting to webDAV

    - by Cragly
    I am trying to connect to a secure webDAV folder and download a file. I am having problems just trying to get a response from the server and as it keeps giving me a 404 Not Found error as soon as I call Request.GetResponse(). I can connect to the webDAV folder using Windows Explorer by mapping a drive but cannot seem to do this in code. I have looked at other post on this site and others online but most seem to concentrate on connecting to Outlook. Has anybody else had this issue? The code I am using is as follows: string URI = "https://transfer.mycompany.com/myDirectory/myFile.csv"; string username = "username"; string password = "password"; Request = (HttpWebRequest) WebRequest.Create(URI); Request.Credentials = new NetworkCredential(username, password); Request.Method = WebRequestMethods.Http.Get; Request.Headers.Add("Translate", "f"); Response = (HttpWebResponse) Request.GetResponse(); contentLength = Convert.ToInt64(Response.GetResponseHeader("Content-Length"));

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  • how can we apply client side validation on fileupload control in ASP.NET to check filename contain s

    - by subodh
    I am working on ASP.NET3.5 platform. I have used a file upload control and a asp button to upload a file. Whenever i try to upload a file which contain special characterlike (file#&%.txt) it show crash and give the messeage Server Error in 'myapplication' Application. A potentially dangerous Request.Files value was detected from the client (filename="...\New Text &#.txt"). Description: Request Validation has detected a potentially dangerous client input value, and processing of the request has been aborted. This value may indicate an attempt to compromise the security of your application, such as a cross-site scripting attack. You can disable request validation by setting validateRequest=false in the Page directive or in the configuration section. However, it is strongly recommended that your application explicitly check all inputs in this case. Exception Details: System.Web.HttpRequestValidationException: A potentially dangerous Request.Files value was detected from the client (filename="...\New Text &#.txt"). Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. how can i prevent this crash using javascript at client side?

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  • [grails] setting cookies when render type is "contentType: text/json"

    - by Robin Jamieson
    Is it possible to set cookies on response when the return render type is set as json? I can set cookies on the response object when returning with a standard render type and later on, I'm able to get it back on the subsequent request. However, if I were to set the cookies while rendering the return values as json, I can't seem to get back the cookie on the next request object. What's happening here? These two actions work as expected with 'basicForm' performing a regular form post to the action, 'withRegularSubmit', when the user clicks submit. // first action set the cookie and second action yields the originally set cookie def regularAction = { // using cookie plugin response.setCookie("username-regular", "regularCookieUser123",604800); return render(view: "basicForm"); } // called by form post def withRegularSubmit = { def myCookie = request.getCookie("username-regular"); // returns the value 'regularCookieUser123' return render(view: "resultView"); } When I switch to setting the cookie just before returning from the response with json, I don't get the cookie back with the post. The request starts by getting an html document that contains a form and when doc load event is fired, the following request is invoked via javascript with jQuery like this: var someUrl = "http://localhost/jsonAction"; $.get(someUrl, function(jsonData) { // do some work with javascript} The controller work: // this action is called initially and returns an html doc with a form. def loadJsonForm = { return render(view: "jsonForm"); } // called via javascript when the document load event is fired def jsonAction = { response.setCookie("username-json", "jsonCookieUser456",604800); // using cookie plugin return render(contentType:'text/json') { 'pair'('myKey': "someValue") }; } // called by form post def withJsonSubmit = { def myCookie = request.getCookie("username-json"); // got null value, expecting: jsonCookieUser456 return render(view: "resultView"); } The data is returned to the server as a result of the user pressing the 'submit' button and not through a script. Prior to the submit of both 'withRegularSubmit' and 'withJsonSubmit', I see the cookies stored in the browser (Firefox) so I know they reached the client.

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  • How to upload image to remote server in iphone?

    - by Atulkumar V. Jain
    Hi Everybody, I am trying to upload a image which i am clicking with the help of the camera. I am trying the following code to upload the image to the remote server. -(void)searchAction:(UIImage*)theImage { UIDevice *dev = [UIDevice currentDevice]; NSString *uniqueId = dev.uniqueIdentifier; NSData * imageData = UIImagePNGRepresentation(theImage); NSString *postLength = [NSString stringWithFormat:@"%d",[imageData length]]; NSString *urlString = [@"http://www.amolconsultants.com/im.jsp?" stringByAppendingString:@"imagedata=iPhoneV0&mcid="]; urlString = [urlString stringByAppendingString:uniqueId]; urlString = [urlString stringByAppendingString:@"&lang=en_US.UTF-8"]; NSLog(@"The URL of the image is :- %@", urlString); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; [request setURL:[NSURL URLWithString:urlString]]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:imageData]; NSURLConnection *conn=[[NSURLConnection alloc] initWithRequest:request delegate:self]; if (conn == nil) { NSLog(@"Failed to create the connection"); } } But nothing is getting posted. Nothing comes in the console window also. I am calling this method in the action sheet. When the user clicks on the 1st button of the action sheet this method is called to post the image. Can anyone help me with this... Any code will be very helpful... Thanx in advance...

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  • WiX COM+ error code

    - by Stefan
    I'm trying to register COM+ with WiX. I get the following error. Where can I find the meaning of error code -2146368486? RegisterComPlusAssemblies: DLL: <file name> ComPlusInstallExecute: ErrorInfo: Name='<file name>', ErrorCode='-2146368486', MajorRef='<name>', MinorRef='<invalid>' ComPlusInstallExecute: ErrorInfo: Name='<name>', ErrorCode='-2146368486', MajorRef='<guid>', MinorRef='<invalid>' ComPlusInstallExecute: ErrorInfo: Name='<name>', ErrorCode='-2146368486', MajorRef='<guid>', MinorRef='<invalid>' ComPlusInstallExecute: Error 0x80110401: Failed to install components ComPlusInstallExecute: Error 0x80110401: Failed to register native assembly ComPlusInstallExecute: Error 0x80110401: Failed to register assembly, key: <assembly> ComPlusInstallExecute: Error 0x80110401: Failed to register assemblies

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  • How to get application context path in spring-ws?

    - by Dhaliwal
    I am using Spring-WS to create a webservice. In my project, I have created a Helper class to reads sample response and request xml file which are located in my /src/main/resource folder. When I am unit-testing my webservice application 'locally', I use the System.getProperty("user.dir") to get the application context folder. The following is a method that I created in the Helper class to help me retrieve the file that I am interested in my resource folder. public static File getFileFromResources(String filename) { System.out.println("Getting file from resource folder"); File request = null; String curDir = System.getProperty("user.dir"); String contextpath = "C:\\src\\main\\resources\\"; request = new File(curDir + contextpath + filename); return request; } However, after 'publishing' the compiled WAR file to the ../webapps folder to the Apache Tomcat directory, I realise that System.getProperty("user.dir") no longer returns my application context path. Instead, it is returning the Apache Tomcat root directory as shown C:\Program Files\Apache Software Foundation\Tomcat 6.0\src\main\resources\SampleClientFile I cant seem to find any information about getting the root folder of my webservice. I have seen examples on Spring web application where I can retrieve the context path by using the following : request.getSession().getServletContext().getContextPath() But in this case, I am using a Spring web application where there is a servlet context in the request. But the Spring-WS, my entry point is an endpoint. How can I get the context path of my webservice application. I am expecting a context path of something like C:\Program Files\Apache Software Foundation\Tomcat 6.0\webapps\clientWebService\WEB-INF\classes Could someone suggest a way to achieve this?

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  • curl cookie not creating on success

    - by Bin
    Hi I'm using cUrl(PHP) to post a login request and store response in cookie file. In my second request I'm passing cookie in header and post data to verify it. Issue is that cookie file is not created in first succesful request results in failure for second request. Please suggest me where I'm doing wrong. $cookiefile="/var/www/html/dimdim/cook.txt"; $url_log="http://my.dimdim.com/api/auth/login"; $p_log='request={"account":"bin6k","password":"password","group":"all"}'; $url_ver="http://my.dimdim.com/api/auth/verify"; $p_ver='request={"account":"bin6k","password":"password","group":"all"}'; $ch = curl_init(); //curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookiefile); curl_setopt($ch, CURLOPT_URL,$url_log); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p_log); ob_start(); // prevent any output $retval=curl_exec ($ch); // execute the curl command ob_end_clean(); // stop preventing output curl_close ($ch); //print_r($retval); unset($ch); $ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookiefile); curl_setopt($ch, CURLOPT_URL,$url_ver); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p_log); $buf2 = curl_exec ($ch); curl_close ($ch); echo "".htmlentities($buf2);

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  • Distinct Value Array for View Controller Index Using Core Data

    - by b.dot
    Hi, I'm trying to create an index representing the first letter value of each record in a Core Data store to be used in a table view controller. I'm using a snippet of the code from Apple's documentation. I would simply like to produce an array or dictionary of distinct values as the result. My store already has the character defined within each record object. Questions: 1) I'm having a problem understanding NSDictionaryResultType. Where does the resulting dictionary object get received so that I can assign it's keys to the view controller? The code seems to only return an array. 2) If I include the line containing NSDictionaryResultType, I get no returns. 3) I realize that I could do this in a loop, but I'm hoping this will work. Thanks! NSEntityDescription *entity = [NSEntityDescription entityForName:@"People" inManagedObjectContext:managedObjectContext]; NSFetchRequest *request = [[NSFetchRequest alloc] init]; [request setEntity:entity]; [request setResultType:NSDictionaryResultType]; // This line causes no no results. [request setReturnsDistinctResults:YES]; [request setPropertiesToFetch :[NSArray arrayWithObject:@"alphabetIndex"]]; NSError *error; NSArray *objects = [managedObjectContext executeFetchRequest:request error:&error];

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  • Autotest notifications on Ubuntu virtual environment

    - by Luciano
    I am having trouble getting Rails autotest notifications to work on the Engine Yard Vagrant environment. On the Mac, I normally get the notifications via Growl. However, on the virtual environment (which runs Ubuntu) that doesn't work. I tried running Linux notification setups such as libnotify+autotest-notification, but I get the following error: libnotify-Message: Unable to get session bus: /bin/dbus-launch terminated abnormally with the following error: Autolaunch error: X11 initialization failed. ** (notify-send:1004): CRITICAL **: dbus_g_proxy_connect_signal: assertion `DBUS_IS_G_PROXY (proxy)' failed ** (notify-send:1004): CRITICAL **: dbus_g_proxy_connect_signal: assertion `DBUS_IS_G_PROXY (proxy)' failed ** (notify-send:1004): CRITICAL **: dbus_g_proxy_call: assertion `DBUS_IS_G_PROXY (proxy)' failed Another path would be to have Growl receive the notifications remotely, but I don't even know where to begin with that... Any suggestions?

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  • How to implement a 'safe' periodical executer without using the Rails helpers?

    - by Robbie
    I am very new to Ruby on Rails and was never really big on writing JavaScript, so the built in helpers were like a tiny silce of heaven. However I have recently learned that using the helper methods creates "obtrusive javascript" so I am doing a tiny bit of refactoring to get all this messy code out of my view. I'm also using the Prototype API to figure out what all these functions do. Right now, I have: <%= periodically_call_remote(:url => {:action => "tablerefresh", :id => 1 }, :frequency => '5', :complete => "load('26', 'table1', request.responseText)")%> Which produces: <script type="text/javascript"> //<![CDATA[ new PeriodicalExecuter(function() {new Ajax.Request('/qrpsdrail/grids/tablerefresh/1', {asynchronous:true, evalScripts:true, onComplete:function(request){load('26', 'table1', request.responseText)}, parameters:'authenticity_token=' + encodeURIComponent('dfG7wWyVYEpelfdZvBWk7MlhzZoK7VvtT/HDi3w7gPM=')})}, 5) //]]> </script> My concern is that the "encodeURIComponent" and the presence of "authenticity_token" are generated by Rails. I'm assuming these are used to assure the validity of a request. (Ensuring a request comes from a currently active session?) If that is the case, how can I implement this in application.js 'safely'? It seems that the built in method, although obtrusive, does add some beneficial security. Thanks, in advance, to all who answer.

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  • Sequential access to asynchronous sockets

    - by Lars A. Brekken
    I have a server that has several clients C1...Cn to each of which there is a TCP connection established. There are less than 10,000 clients. The message protocol is request/response based, where the server sends a request to a client and then the client sends a response. The server has several threads, T1...Tm, and each of these may send requests to any of the clients. I want to make sure that only one of these threads can send a request to a specific client at any one time, while the other threads wanting to send a request to the same client will have to wait. I do not want to block threads from sending requests to different clients at the same time. E.g. If T1 is sending a request to C3, another thread T2 should not be able to send anything to C3 until T1 has received its response. I was thinking of using a simple lock statement on the socket: lock (c3Socket) { // Send request to C3 // Get response from C3 } I am using asynchronous sockets, so I may have to use Monitor instead: Monitor.Enter(c3Socket); // Before calling .BeginReceive() And Monitor.Exit(c3Socket); // In .EndReceive I am worried about stuff going wrong and not letting go of the monitor and therefore blocking all access to a client. I'm thinking that my heartbeat thread could use Monitor.TryEnter() with a timeout and throw out sockets that it cannot get the monitor for. Would it make sense for me to make the Begin and End calls synchronous in order to be able to use the lock() statement? I know that I would be sacrificing concurrency for simplicity in this case, but it may be worth it. Am I overlooking anything here? Any input appreciated.

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  • Problem in Application_Error in Global.asax

    - by mmtemporary
    my problem is User.Identity.Name or Request.Url.AbsoluteUri in exception handling is empty when exception email to me. this is Application_Code: void Application_Error(object sender, EventArgs e) { Server.Transfer("~/errors/default.aspx"); } and this is default.aspx code: protected void Page_Load(object sender, EventArgs e) { if (Server.GetLastError() == null) return; Exception ex = Server.GetLastError().GetBaseException(); if (ex == null) return; string message = string.Format("User: ", User.Identity.Name); message += Environment.NewLine; message += string.Format("AbsoluteUri: ", Request.Url.AbsoluteUri); message += Environment.NewLine; message += string.Format("Form: ", Request.Form.ToString()); message += Environment.NewLine; message += string.Format("QueryString: ", Request.QueryString.ToString()); message += Environment.NewLine; HttpBrowserCapabilities browser = Request.Browser; string s = "Browser Capabilities:\n" + "Type = " + browser.Type + "\n" + "Name = " + browser.Browser + "\n" + "Version = " + browser.Version + "\n" + "Platform = " + browser.Platform + "\n" + "Is Crawler = " + browser.Crawler + "\n" + "Supports Cookies = " + browser.Cookies + "\n" + "Supports JavaScript = " + browser.EcmaScriptVersion.ToString() + "\n" + "\n"; message += s; message += Environment.NewLine; message += ex.ToString(); Exception lastException = (Exception)Application["LastException"]; if (lastException == null || lastException.Message != ex.Message) { Application.Lock(); Application["LastException"] = ex; Application.UnLock(); SiteHelper.SendEmail(SiteHelper.AdministratorEMail, "Error!!!", message, false); } Server.ClearError(); } but i receive email like this (this is header without full exception content): User: AbsoluteUri: Form: QueryString: Browser Capabilities: Type = IE8 Name = IE Version = 8.0 Platform = WinXP Is Crawler = False Supports Cookies = True Supports JavaScript = 1.2 why username and request url is emty? this problem is exist when i replace transfer with redirect or i don't use both. tanx

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  • Saving animated GIFs using urllib.urlopen (image saved does not animate)

    - by wenbert
    I have Apache2 + Django + X-sendfile. My problem is that when I upload an animated GIF, it won't "animate" when I output through the browser. Here is my code to display the image located outside the public accessible directory. def raw(request,uuid): target = str(uuid).split('.')[:-1][0] image = Uploads.objects.get(uuid=target) path = image.path filepath = os.path.join(path,"%s.%s" % (image.uuid,image.ext)) response = HttpResponse(mimetype=mimetypes.guess_type(filepath)) response['Content-Disposition']='filename="%s"'\ %smart_str(image.filename) response["X-Sendfile"] = filepath response['Content-length'] = os.stat(filepath).st_size return response UPDATE It turns out that it works. My problem is when I try to upload an image via URL. It probably doesn't save the entire GIF? def handle_url_file(request): """ Open a file from a URL. Split the file to get the filename and extension. Generate a random uuid using rand1() Then save the file. Return the UUID when successful. """ try: file = urllib.urlopen(request.POST['url']) randname = rand1(settings.RANDOM_ID_LENGTH) newfilename = request.POST['url'].split('/')[-1] ext = str(newfilename.split('.')[-1]).lower() im = cStringIO.StringIO(file.read()) # constructs a StringIO holding the image img = Image.open(im) filehash = checkhash(im) image = Uploads.objects.get(filehash=filehash) uuid = image.uuid return "%s" % (uuid) except Uploads.DoesNotExist: img.save(os.path.join(settings.UPLOAD_DIRECTORY,(("%s.%s")%(randname,ext)))) del img filesize = os.stat(os.path.join(settings.UPLOAD_DIRECTORY,(("%s.%s")%(randname,ext)))).st_size upload = Uploads( ip = request.META['REMOTE_ADDR'], filename = newfilename, uuid = randname, ext = ext, path = settings.UPLOAD_DIRECTORY, views = 1, bandwidth = filesize, source = request.POST['url'], size = filesize, filehash = filehash, ) upload.save() #return uuid return "%s" % (upload.uuid) except IOError, e: raise e Any ideas? Thanks! Wenbert

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  • HTTP POST with URL query parameters -- good idea or not?

    - by Steven Huwig
    I'm designing an API to go over HTTP and I am wondering if using the HTTP POST command, but with URL query parameters only and no request body, is a good way to go. Considerations: "Good Web design" requires non-idempotent actions to be sent via POST. This is a non-idempotent action. It is easier to develop and debug this app when the request parameters are present in the URL. The API is not intended for widespread use. It seems like making a POST request with no body will take a bit more work, e.g. a Content-Length: 0 header must be explicitly added. It also seems to me that a POST with no body is a bit counter to most developer's and HTTP frameworks' expectations. Are there any more pitfalls or advantages to sending parameters on a POST request via the URL query rather than the request body? Edit: The reason this is under consideration is that the operations are not idempotent and have side effects other than retrieval. See the HTTP spec: In particular, the convention has been established that the GET and HEAD methods SHOULD NOT have the significance of taking an action other than retrieval. These methods ought to be considered "safe". This allows user agents to represent other methods, such as POST, PUT and DELETE, in a special way, so that the user is made aware of the fact that a possibly unsafe action is being requested. ... Methods can also have the property of "idempotence" in that (aside from error or expiration issues) the side-effects of N 0 identical requests is the same as for a single request. The methods GET, HEAD, PUT and DELETE share this property. Also, the methods OPTIONS and TRACE SHOULD NOT have side effects, and so are inherently idempotent.

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  • NullPointerException with Servlet

    - by RonaDona
    I am calling a Servlet using its URL address. This is the URL I am typing http://localhost:7001/ryan/olympics?action=selectCatalog&id=1 This is the Servlet's URL for sure; if I change the address I get page not found This is the code for the Servlet. public class Servlet extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet { private static final long serialVersionUID = 1L; public Servlet() { super(); } public void init(ServletConfig config) throws ServletException { System.out.println("*** initializing controller servlet."); super.init(config); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String action = request.getParameter("action"); if (action.equals("selectCatalog")) { String categoryId = request.getParameter("id"); ProductModelDAO dao4 = new ProductModelDAOImpl("jpac"); if (categoryId != null && !categoryId.trim().equals("")) { CategoryDAO dao1 = new CategoryDAOImpl("jpac"); try { Category category = dao1.getCategoryName(categoryId); request.setAttribute("category", category); } catch (Exception e) { e.printStackTrace(); } } try { @SuppressWarnings("unchecked") List<Product> products = dao4 .getProductsByCategory(categoryId); request.setAttribute("products", products); } catch (Exception e) { e.printStackTrace(); } url = "SelectCatalog.jsp"; RequestDispatcher requestDispatcher = getServletContext().getRequestDispatcher(url); requestDispatcher.forward(request, response); I get the NullPointerException pointing to the RequestDispatcher's line. Any help?

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  • SQL server 2005 agent not working

    - by flaggers
    Sql server 2005 service pack 2 version: 9.00.3042.00 All maintenance plans fail with the same error. The details of the error are:- Execute Maintenance Plan Execute maintenance plan. test7 (Error) Messages Execution failed. See the maintenance plan and SQL Server Agent job history logs for details. The advanced information section shows the following; Job 'test7.Subplan_1' failed. (SqlManagerUI) Program Location: at Microsoft.SqlServer.Management.SqlManagerUI.MaintenancePlanMenu_Run.PerformActions() At this point the following appear in the windows event log: Event Type: Error Event Source: SQLISPackage Event Category: None Event ID: 12291 Date: 28/05/2009 Time: 16:09:08 User: 'DOMAINNAME\username' Computer: SQLSERVER4 Description: Package "test7" failed. and also this: Event Type: Warning Event Source: SQLSERVERAGENT Event Category: Job Engine Event ID: 208 Date: 28/05/2009 Time: 16:09:10 User: N/A Computer: SQLSERVER4 Description: SQL Server Scheduled Job 'test7.Subplan_1' (0x96AE7493BFF39F4FBBAE034AB6DA1C1F) - Status: Failed - Invoked on: 2009-05-28 16:09:02 - Message: The job failed. The Job was invoked by User 'DOMAINNAME\username'. The last step to run was step 1 (Subplan_1). There are no entries in the SQl Agent log at all.

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  • Brother MFC + Windows 7 [closed]

    - by juFo
    I'm using Windows 7 64bit (RTM version). I bought myself a new Brother MFC6490CW but I'm having troubles with installing the drivers. When I set compatibility to Windows Vista Service Pack 2 I can only install the scanner functionality from the Brother Solution Center and not the printer driver: Printer (driver) FAILED FAILED Scanner (driver) Installed Connected PC-FAX send FAILED FAILED PC-FAX receive Installed Connected Remote Setup Installed Connected Anybody who was a fix for this? The brother drivers for windows 7 will be released at the end of October and I can't wait so long. Need my printer.. Tnx in advance.

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  • PHP echo query result in Class??

    - by Jerry
    Hi all I have a question about PHP Class. I am trying to get the result from Mysql via PHP. I would like to know if the best practice is to display the result inside the Class or store the result and handle it in html. For example, display result inside the Class class Schedule { public $currentWeek; function teamQuery($currentWeek){ $this->currentWeek=$currentWeek; } function getSchedule(){ $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } $scheduleQuery=mysql_query("SELECT guest, home, time, winner, pickEnable FROM $this->currentWeek ORDER BY time", $connection); if (!$scheduleQuery){ die("database has errors: ".mysql_error()); } while($row=mysql_fetch_array($scheduleQuery, MYSQL_NUMS)){ //display the result..ex: echo $row['winner']; } mysql_close($scheduleQuery); //no returns } } Or return the query result as a variable and handle in php class Schedule { public $currentWeek; function teamQuery($currentWeek){ $this->currentWeek=$currentWeek; } function getSchedule(){ $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } $scheduleQuery=mysql_query("SELECT guest, home, time, winner, pickEnable FROM $this->currentWeek ORDER BY time", $connection); if (!$scheduleQuery){ die("database has errors: ".mysql_error()); // create an array } $ret = array(); while($row=mysql_fetch_array($scheduleQuery, MYSQL_NUMS)){ $ret[]=$row; } mysql_close($scheduleQuery); return $ret; // and handle the return value in php } } Two things here: I found that returned variable in php is a little bit complex to play with since it is two dimension array. I am not sure what the best practice is and would like to ask you experts opinions. Every time I create a new method, I have to recreate the $connection variable: see below $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) { die("Database selection failed: " . mysql_error()); } It seems like redundant to me. Can I only do it once instead of calling it anytime I need a query? I am new to php class. hope you guys can help me. thanks.

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  • How do you submit an authenticated HTML form using XUL (Firefox extension) Javascript?

    - by machineghost
    I am working on a Firefox extension, and in that extension I am trying to use AJAX to submit a form on a webpage. I am using: var request = Components.classes["@mozilla.org/xmlextras/xmlhttprequest;1"].createInstance(Components.interfaces.nsIXMLHttpRequest); request.onload = loadHandler; request.open("POST", url, true); request.send(values); to make the request, and it works ... mostly. The one problem is that the form has an authentication token on it, and I need to submit that token with my POST. I tried doing a GET separately to get this token, but by the time I made my second (POST) request my session had (evidently) changed, and the authenticity token was considered invalid. Does anyone know of a way to use the XUL/Chrome Javscript to maintain a constant session across multiple requests (all "behind the scenes") for something this? I'm still a XUL n00b, so there may be a totally obvious alternative that I'm missing (eg. hidden IFRAME; I tried that briefly but couldn't get it to work).

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  • IIS doesn't send two responses to the same client at the same time (only for ASP)

    - by dr. evil
    I've got 2 ASP pages. I do a request to the first page from Firefox (which takes 30 seconds to process on server-side), and during the execution of 30 seconds I do another request from Firefox to the second page (takes less than 1 second in server-side), but it does come after 31 second. Because it waits first requests to finish. When I request to the first page from Firefox and then request the second page from IE it's just instant. So basically ASP - IIS 6 somehow limiting every client to one request (long processing request) at a time. I need to get around this problem in my .NET client application. This is tested in 3 different systems. If you want to test you can try the ASP scripts at the end. This behaviour is same in a long SQL execution or just in a time consuming ASP operation. Note: It's not about HTTP Keep Alive It's not about persistent connection limit (we tried to increase this in firefox and in .NET with Net.ServicePointManager.DefaultConnectionLimit) It's not about User Agent This doesn't happen in ASP.NET so I assume it's something to the with ASP.dll I'm trying to solve this on the client not the server. I don't have direct control over the server it's a 3rd party solution. Is there any way to get around this? Sample ASP Code: First ASP: <% Set cnn = Server.CreateObject("Adodb.Connection") cnn.Open "Provider=sqloledb;Data Source=.;Initial Catalog=master;User Id=sa;Password=;" cnn.Execute("WAITFOR DELAY '0:0:30'") cnn.Close %> Second ASP: <% Response.Write "bla bla" %>

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  • help in compare validate in c#

    - by scatman
    i have 2 textboxes that i am filling with StartDate, and Endate. i want to use the compareValidator to make sure that the StartDate is less that the EndDate. i used this: <asp:CompareValidator ID="Comp" ControlToValidate="txtStartDate" ControlToCompare="txtEndDate" Operator="LessThan" Type="Date" runat="server" Display="dynamic" Text="Failed!" /> the validator is always giving me Failed no matter what the dates are. if startdateendate or vise versa, Failed appears. i am using (MM/dd/yyyy) format in the textboxes. EDIT: ok i solved the problem. if anyone interested here is the new comparevalidator: <asp:CompareValidator ID="Comp" ControlToValidate="txtEndDate" ControlToCompare="txtStartDate" Operator="GreaterThan" Type="Date" runat="server" Display="dynamic" Text="Failed!" />

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  • php:unable to download youtube video using phptube class

    - by I Like PHP
    i m using phptube class for downloading you tube video. from this site In code i paste youtube url on a input box but there is errors below. Warning: file_get_contents(http://www.youtube.com/get_video?video_id=&t=) [function.file-get-contents]: failed to open stream: HTTP request failed! HTTP/1.0 404 Not Found and Warning: file_put_contents(./flvs/3Hx9VsqMUug.flv) [function.file-put-contents]: failed to open stream: No such file or directory in E:\xampp\htdocs\vdo\utube \functions.php on line 19 path:./flvs/3Hx9VsqMUug.flv please tell me where is problem???

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