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• Conversion failed when converting the varchar value to data type int

  - by desi

  *I have a varchar(1000) column declared as field that contains all numbers, as shown below. And I want to execute the following script. I need this to work please Declare @PostalCode varchar(1000)=0 set @PostalCode ='7005036,7004168,7002314,7001188,6998955' Select hl.* From CountryLocation cl INNER JOIN refPostalCodes pc ON pc.PostalCode = hl.PostalCode where pc.Postalcode in (@PostalCode) and pc.notDeleted = 1

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• mysql extra columns with same name from two tables

  - by salmane

  Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

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• I want to read a big text file

  - by Rozer

  I want to read a big text file, what i decided to create four threads and read 25% of file by each one. and then join them. but its not more impressive. can any one tell me can i use concurrent programming for the same. as my file structure have some data as name contact compnay policyname policynumber uniqueno and I want to put all data in hashmap at last. thanks

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• difference between where and nested queries

  - by Chris H

  I'm not able to figure out the difference between these queries. I'm pretty sure that the first one is an equi-join. I'm not sure how the second one ISN'T the same as the first. The sub query in #2 selects all Ids from S, and then it returns all R's that also have those ID's, no? SELECT R.cname FROM R, S, WHERE R.Id = S.Id SELECT R.cname FROM R WHERE R.Id IN (SELECT S.Id FROM S)

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• help with sql query - in access 2007

  - by Gold

  hi i have 2 tables table items has 144602 records table A has 27721 records code in items = BAR8 in A i want to show all records that equal i try this: SELECT Items.Code, A.BAR8 FROM Items INNER JOIN A ON Items.Code = A.BAR8; and i get 28048 records !!! i need to get 27721 , how to do it ? thank's in advance

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• Sql string adding problem

  - by Woland

  SELECT a.one + ' test ' +b.two from table1 a right join table1 on a.id =b.id The problem is that when one is null then it the whole string is null, is there some kind of trick to bypass this problem msSQL 2005

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• Detecting Completion of an Array of Threads

  - by Harsha

  I have created an array of threads and started all of them. How to know whether all threads have completed work. I don't want to use thread.wait or thread.join.

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• Using Joins vs Entity associations

  - by shivesh

  I am learning Entity framework and linq-to-entities. It's possible to get cross values from multiple tables using JOINS (join keyword) or using the navigation fields ( associations) in which case the framework knows how to reference the cross data. My question is what to use when?

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• "Ambiguous column name" error on one particular server

  - by jazbit

  This simple query throws the "Ambiguous column name TaskID" error on one db-server only. This is ridiculous. We tested this with the same database structure on different servers and different versions of ms sql (2005/2008), and it's only THIS particular client's server that throws the error. I'm actually frustrated. SELECT Tasks.TaskID FROM Tasks INNER JOIN TaskHelpers ON TaskHelpers.TaskID = Tasks.TaskID order by TaskID Yes, I know I can put "Tasks.TaskID" into the order by clause, but for some reasons I can't.

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• What would be better, (1 database + 4 tables) or (2 databases + 2 tables each) ?

  - by griseldas

  Hi there, I would like to be advised on what would be better (in regards to performance) A) 1 DATABASE with 4 tables or B) 2 DATABASES (same server), each with 2 tables. The tables size and usage are more or less similar, so the 2 tables on Database 1 would be similar usage/size to the 2 tables on database 2 The tables could have +500,000 records and the 2 tables on each database are not related (no join queries etc between them) Thanks in advance for your comments

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• Firebird 2.1 + EXISTS = query bug?

  - by Atlas

  Using Delphi 2009 + Firebird 2.1.3. Database is ODS 11.1, default char set is UTF8. My prepared query is as follows: SELECT a.po_id, a.po_no FROM purchase_order a WHERE EXISTS (SELECT 1 FROM sales_order_item z1 JOIN purchase_order_item z2 ON z2.so_item_id = z1.so_item_id AND z2.po_id = a.po_id WHERE z1.so_id = :soid) ORDER BY a.po_no Now when I loop this say 1000 times because I have 1000 x so_id, the CPU usage get at 100% for FBSERVER.EXE Anyone encountered this problem?

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• How to select distinct in SQl Server 2008 but for only one field out of many?

  - by bakerjr

  I have a query: SELECT Content.content_name, Language2.Name, Language2.language_id, Content.id, Content.content_description, FROM Language AS Language2 LEFT JOIN contents AS Content ON (Language2.language_id = Content.language_id) How do I select only the distinct content_name?

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• has any gae code like 'tribes' in this site .

  - by zjm1126

  in this site : http://cloud27.com/tribes/ you can join other's tribe, and create own tribe if you login. so has some open-source code do this ? thanks

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• Selecting count(*) while checking for a value in the results

  - by Rob

  SELECT COUNT(*) as Count, IF(sch.HomeTeamID = 34,true,false) AS Hawaii FROM schedule sch JOIN schools s ON s.ID = 83 WHERE (sch.HomeTeamID = 83 OR sch.AwayTeamID = 83) AND sch.SeasonID = 4 I'm trying to use count() to simplify my result but also include a field that represents wether any of the results' specific column contained a certain value. Is this possible? I'd basically like a row response with all the info I need.

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• MYSQL - Query to check against other table (hard to explain...)

  - by Sam

  I have a query that gets a list of emails who have subscribed for a newsletter trial which lasts 30 days.. $thirty = time() - 3024000; SELECT c.email FROM tbl_clients AS c JOIN tbl_clientoptions AS o ON o.client = c.id WHERE o.option = 'newsletter' AND c.datecreated $thirty What I want to do is do a check in that same query so it also returns clients OVER 30 days old if they have the tbl_clientoptions.option = 'trialoverride' (ie; a row in the client options table with the value "trialoverride") basic columns are: TBL_CLIENTS id,name,email,datecreated TBL_CLIENTOPTIONS id,client,option

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• Displaying a field as a comma separated list in Reporting Services 2005?

  - by user364720

  See title. Basically, the data in this report is set up such that each value in Field A has multiple corresponding values in Field B, and I need to display Field B as a comma-separated list. According to the internets, this is totally easy via a combination of Join() and LookupSet() in 2008... but I'm on 2005. Anyone know how I can do this?

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• PHP MySQL query help

  - by user547794

  Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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• Get top rated item using AVG mysql

  - by user1876234

  I want to find top rated item using AVG function in mysql, right now my query looks like this: SELECT a.title, AVG(d.rating) as rating FROM in8ku_content a JOIN in8ku_content_ratings d ON a.id = d.article_id ORDER BY rating DESC Problem is that it takes AVG of all items and the result is not accurate, what should be changed here to get correct result ? Tables: in8ku_content [id, title] in8ku_content_ratings [id, article_id, rating]

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• What is the best way to find the period of a (repeating) list in Mathematica?

  - by Arnoud Buzing

  What is the best way to find the period in a repeating list? For example: a = {4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2} has repeat {4, 5, 1, 2, 3} with the remainder {4, 5, 1, 2} matching, but being incomplete. The algorithm should be fast enough to handle longer cases, like so: b = RandomInteger[10000, {100}]; a = Join[b, b, b, b, Take[b, 27]] The algorithm should return $Failed if there is no repeating pattern like above.

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• Website Design Templates

  - by user347834

  I am looking fr someone to make me two website templates for my site for free. Here is a quick design of what I want:(Took me 2 minutes in Paint) http:/ /i50.tinypic.com/33p9aut.jpg (You have to push backspace on the first link to join up the http:/ and the other /)and http://i50.tinypic.com/2qmogoo.jpg Email me at [email protected] or [email protected] for more information

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• I have 2 MySql tables. How to get not all data from them in 1 sql query?

  - by Ole Jak

  I have 2 MySql tables. users with id's and username's ; streams with userId's and streamId's How to get them as / join them into one table conteining only username | streamId as SQL response? With one SQL query.

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• MySQL 'user_id' in where clause is ambiguous problem

  - by HoMe

  How can I correct the problem I keep getting from the code below which states 'user_id' in where clause is ambiguous. Thanks for the help in advance. Here is the mysql table. SELECT user.*, user_info.* FROM user INNER JOIN user_info ON user.user_id = user_info.user_id WHERE user_id='$user_id'

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• Change a link's href value based on time

  - by justSteve

  I'm coding a 'Connect to Meeting' page where i would like the link that allows attendees to join our GoToMeeting event to 'become active' 15 minutes prior to the start time. So the page users visit to see the connection info (meetingID, password) includes the start time of the meeting. I need a button ('Connect To Meeting') to change from inactive to Active when [Now() < (StartTime()-15minutes)].

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• Creating an SQL query to list all clients, who spent over 1000$

  - by Lapa

  So, I have three tables with the following rows: Customers (Customer_id and Name), Orders (Customer_id, Product_id, Quantity) and Products (Price). How do I write a query which shows all customers who spent more than 1000$? Do I have to join the tables?

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• Return all users from group(s) specified as comma delimited value

  - by todor

  I have the following two table scenario: users id groups 1 1,2,3 2 2,3 3 1,3 4 3 and groups id 1 2 3 How do I return the IDs of all users that belong to group 2 and 1 for example? Should I look into join, a helper group_membership table or function to separate the comma delimited group IDs to get something like this: group_membership user_id group_id 1 1 1 2 1 3 2 2 2 3 ... ...

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