Search Results

Search found 33911 results on 1357 pages for 'mysql select'.

Page 158/1357 | < Previous Page | 154 155 156 157 158 159 160 161 162 163 164 165  | Next Page >

  • Not able to create a datasource registration with WAMP MysQL 5.0 in DBArtisan

    - by Alf Christophersen
    I try in a test version of DBArtisan to set up a datasource and register both servere as localhost, database to use, my username and password, but, when testing the connection, I get message that connection failed. Hooking up from eg. Delphi and other utilities run nicely. But not DBArtisan, Is MySQL 5.0 not supported yet ?? Or is it WAMP that is the culprit naming the service wampmysqld insted of just mysqld ??

    Read the article

  • How do you debug MySQL stored procedures?

    - by Cory House
    My current process for debugging stored procedures is very simple. I create a table called "debug" where I insert variable values from the stored procedure as it runs. This allows me to see the value of any variable at a given point in the script, but is this is there a better way to debug MySQL stored procedures?

    Read the article

  • Php + mysql transactions examples

    - by Donator
    I really haven't found normal example of php file where mysql transactions are being used. Can you show me simple example of that? And one more question. I've already created a lot of programming and didn't use transaction, maybe I can put any php function or smth to header.php that if one mysql_query fails, then others too? Thank you.

    Read the article

  • MYSQL and Array with PHP for create Tag Cloud

    - by asilloo
    Hi, I'm trying to make a Tag cloud for every user in own page, I'm using PHP5 and Mysql, My table named "tags" and I want to make a array but in short way. The table like below, The array can be like for user1 array={[car,1],[cat,null],[pen,1],[dvd,1],[cd,null]} Username totaltag tag1 tag2 tag3 tag4 tag5 admin 5 car cat pen dvd cd user1 1 1 1 user2 1 2 12 1 user3 3 2 10 1

    Read the article

  • mysql insert with auto-increment column

    - by czuroski
    Hello, I am trying to insert data into a mysql table from a csv file. I am using the infile sql command, but I am having trouble because the first column of the table is an id that is set as an auto increment field. what do I have to set my first column value to in order to get this to work, or can I do it at all? Thanks

    Read the article

  • mysql to codeigniter active record help

    - by JoeM05
    Active record is a neet concept but sometimes I find it difficult to get more complicated queries to work. I find this is at least one place the CI docs are lacking. Anyway, This is the sql I wrote. It returns the expected results of quests not yet completed by the user that are unlocked and within the users level requirements: SELECT writing_quests . * FROM `writing_quests` LEFT OUTER JOIN members_quests_completed ON members_quests_completed.quest_id = writing_quests.id LEFT OUTER JOIN members ON members.id = $user_id WHERE writing_quests.unlocked =1 AND writing_quests.level_required <= $userlevel AND members_quests_completed.user_id IS NULL This is the codeigniter active record query, it returns all quests that are unlocked and within the users level requirement: $this->db->select('writing_quests.*'); $this->db->from('writing_quests'); $this->db->join('members_quests_completed', 'members_quests_completed.quest_id = writing_quests.id', 'left outer'); $this->db->join('members', "members.id = $user_id", 'left outer'); $this->db->where('writing_quests.unlock', 1); $this->db->where('writing_quests.level_required <=', $userlevel); $this->db->where('members_quests_completed.user_id is null', null, true); I'm guessing there is something wrong with the way I am asking for Nulls. To be thorough, I figured I'd include everything.

    Read the article

  • how to activate trigger after all the bulk insert(s) in mysql

    - by JPro
    I am using mysql and there are bulk inserts that goes on to my table. My doubt is if I create a trigger specifying after insert, then the trigger will get activated for every insert after, which I do not want to happen. Is there any way to activate a trigger after all the bulk inserts are completed? Any advice? Thanks.

    Read the article

  • MySQL - Update the same column twice

    - by uzioriluzan
    Hello, I need to update a column in a mysql table. If I do it in two steps as below, is the column "col" updated twice in the disk ? update table SET col=3*col, col=col+2; or is it written only once as in : update table SET col=3*col+2; Thanks

    Read the article

  • Unique text field in MySQL and php

    - by Jonathan
    I've created a salt using; md5(rand(0,10000000)); (there is probably a better way?) There doesn't seem to be possible to make a text field unique in MYSQL. So how do I check if the salt has already been used for a previous user? Or should I generate the salt based on the current date/time? as it is impossible for 2 users to register at exactly the same time correct?

    Read the article

  • Connecting FLEX 3.0, JAVA WITH MYSQL

    - by Nithi
    How to connect to MYSQL DB from Java, create table, insert data, retrieve it with datatypes. How to make use of the data to/from in Flex application. plz help me out.. i have basic knowledge in sending and receiving messages using BlazeDS. and calling JAVA METHODS USING ...

    Read the article

  • PHP Array in MySQL IN() function?

    - by Trez
    Is it possible to assign php array in MySQL IN() function? for example, $numbers = array('8001254656','8886953265','88864357445','80021536245'); $sql = mysql_query("SELECT * FROM `number_table` WHERE `number` IN ($numbers)"); Any Ideas? Thanks,

    Read the article

  • easy mysql query question

    - by Ahmet vardar
    Hi, here is the "msg" table on mysql sent_to customer msg read ------- -------- ------ ----- 45 3 bla 0 34 4 bla 1 34 6 bla 0 45 3 bla 0 56 7 bla 1 45 8 bla 0 for example user whose id number is 45 logs in, i want him to see this, you have 2 unread msg to your "number 3" customer you have 1 unread msg to your "number 8" customer like a news feed what query should i use for this ? thx

    Read the article

  • Mysql query, need suggestion or solution

    - by Xi Kam
    Can anyone help me, i have two tables and i need records from both the table //////////////////////////////++ Query 1 ++//////////////////////////////////// SELECT SUM(rec_issued) AS issed, regen_id, YEAR(issue_date) AS iYear, MONTH(issue_date) AS iMonth FROM `view_rec_issued` WHERE `regen_id` = 2 GROUP BY YEAR(issue_date) DESC, MONTH(issue_date) DESC ORDER BY issue_date ASC issed regen_id iYear iMonth 424 2 2011 3 4340 2 2011 4 4235 2 2011 5 10570 2 2012 2 4761 2 2012 3 5000 2 2012 4 3700 2 2012 5 3414 2 2012 6 3700 2 2012 7 2992 2 2012 8 995 2 2012 10 ![Result from Query 1][1] //////////////////////////////++ Query 2 ++//////////////////////////////////// SELECT SUM(total_redem) AS redemed, regen_id, YEAR(redemption_date) AS rYear, MONTH(redemption_date) AS rMonth FROM `recredem_month_wise` WHERE `regen_id` = 2 GROUP BY YEAR(redemption_date) DESC, MONTH(redemption_date) DESC order by redemption_date ASC redemed regen_id rYear rMonth 424 2 2011 3 260 2 2011 4 6523 2 2011 5 1070 2 2011 6 200 2 2011 10 500 2 2011 11 9750 2 2012 2 5000 2 2012 3 5500 2 2012 4 3803 2 2012 5 3700 2 2012 7 3000 2 2012 8 ![Result from Query 2][2] But i want it as - issed regen_id iYear iMonth redemed regen_id rYear rMonth 424 2 2011 3 424 2 2011 3 4340 2 2011 4 260 2 2011 4 4235 2 2011 5 6523 2 2011 5 NULL NULL NULL NULL 1070 2 2011 6 NULL NULL NULL NULL 200 2 2011 10 NULL NULL NULL NULL 500 2 2011 11 10570 2 2012 2 9750 2 2012 2 4761 2 2012 3 5000 2 2012 3 5000 2 2012 4 5500 2 2012 4 3700 2 2012 5 3803 2 2012 5 3414 2 2012 6 NULL NULL NULL NULL 3700 2 2012 7 3700 2 2012 7 2992 2 2012 8 3000 2 2012 8 995 2 2012 10 NULL NULL NULL NULL ![I want this output][3] In these table regen_id is unique and i need data as YEAR and MONTH, if in any table not have the records in perticular month and year it should retrieve zero or null. But in every record year and month should equal like this - iYear = rYear and iMonth = rMonth So we can merge both the fields - No need to show year and month twice iYear and rYear = year iMonth and rMonth = month Thank You Please look at this problem.

    Read the article

  • How to store data which contains quotes in MySQL

    - by Nitz
    In one of my forms I use the rich text editor from Yahoo!. Now i want to store the data from that textarea in a MySQL database. The user can enter anything in that textarea, e.g. many double or single quotes. How can I store that data? Normally we store by adding that data in one variable and then put that in sql, but the quotes cause problems.

    Read the article

  • MySQL select date, join statistic data - how?

    - by Webnet
    I have some statistics I need to report on a monthly basis. I need my query to return 0's for statistics which aren't there. The only way I know to do this is to use SQL to generate a list of days within the specified time period and LEFT JOIN the statistic data that I need to report on. Problem is.... I've never not selected from a table like that... how do I do that?

    Read the article

  • Storing MySQL GUID/UUIDs

    - by thr
    This is the best way I could come up with to convert a MySQL GUID/UUID generated by UUID() to a binary(16): UNHEX(REPLACE(UUID(),'-','')) And then storing it in a BINARY(16) Are there any implications of doing it this way that I should know of?

    Read the article

  • Problem with mysql query in paging

    - by jasmine
    I have a very simple paging and mysql query. Im not sure that my query is right: $perPage =4; $page= (isset($GET['page']) && is_numeric($GET['page'])) ? $_GET['page'] : 1; $start = ($page * $perPage ) - $perPage ; if (is_numeric($_GET['cID'])){$cid = $_GET['cID'];} $totalCount = sprintf("SELECT COUNT(*) as 'Total' FROM content WHERE catID = %d", $cid ) ; $count = mysql_query($totalCount); $rowCount = mysql_fetch_array($count); $sql = sprintf("SELECT id, title, abstract, content_image FROM content WHERE catID = %d ORDER BY id DESC LIMIT %d, %d", $cid, $start, $perPage ); $query = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($query)){ echo $row['id'].' : '. $row['title'] .'<br>'; } with /categories.php?cID=1&page=2 and /categories.php?cID=1&page=1 The output is: 95 : titlev 94 : titlex 93 : titlec 92 : titleb and not changed. What is wrong in my query? Thanks in advance

    Read the article

  • MySQL 5 left join unknown column

    - by NP
    I had the below query working in mysql 4.1, but does not in 5.0: SELECT * FROM email e, event_email ee LEFT JOIN member m on m.email=e.email WHERE ee.email_id = e.email_id The error: 1054 (Unknown column 'e.email' in 'on clause')

    Read the article

< Previous Page | 154 155 156 157 158 159 160 161 162 163 164 165  | Next Page >