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• Validating Login / Changing User settings / Php Mysql

  - by Marcelo

  Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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• Usage Rails 3.0 beta 3 without ActiveRecord ORM

  - by Anton

  Hi everybody! Just installed Rails 3.0 beta 3 in Windows 7. And started playing with some easy examples class SignupController < ApplicationController def index @user = User.new(params[:user]) if method.post? and @user.save redirect_to :root end end end class User def initialize(params = {}) @email = params[:email] @passw = params[:password] end def save end end <div align="center"> <% form_for :user do |form| %> <%= form.label :email %> <%= form.text_field :email %><br /> <%= form.label :password %> <%= form.text_field :password %><br /> <%= form.submit :Register! %> <% end %> </div> When I go to /signup I'm getting this error ArgumentError in SignupController#index wrong number of arguments(0 for 1) Is there a problem with constructor or what's wrong?Please, need your help!

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• Parameters lost on login form submitted with post in JBoss

  - by Supowski

  My login page contains two forms: one for logging in and one for signing up. Shorten like this: <form name="LoginForm" id="LoginForm" method="post" action="j_security_check" > <input type="text" name="j_username" /> <input type="text" name="j_password" /> <input type="submit" value="Sing In" /> <form> <form name="SignUpForm" id="SignUpForm" method="post" action="/homepage" > <input type="text" name="loginName" /> <input type="password" name="password1" /> <input type="password" name="password2" /> <input type="submit" value="Sing Up" /> <form> I If 'Sing Up', than values of input are lost during processing and not passed into my Servlet. It works fine with GET, but than there is password in URL, so it's not the right solution :) Similar problem has been posted to community.jboss.org, but with no response: http://community.jboss.org/message/7150#7150. I'm using JBoss 4.3eap. Any help?

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• How to implement a Client-side Ajax Login on Asp.Net MVC (A link to the solution for Asp.Net Webform

  - by Matt

  Hi, I'm trying to implement a client-side ajax login on Asp.Net MVC. I used to have this set up just fine on WebForms, but now that I've moved to MVC it's giving me some troubles. If you'd like a tutorial on Client-side Ajax Login for Asp.Net Webforms, it can be found here -- Easy, A++ Now... for some reason it's not working for Asp.Net MVC. I used the exact same tutorial as for the Webforms, except when it executes the ssa.login() (equivalently: Sys.Services.AuthenticationService.login()) it's not doing anything. I have alerts in both the onLoginComplete() function and the onError() function. As well I have an alert before the ssa.login gets called and right after... function loginHandler() { var username = $("#login_UserName").val(); var password = $("#login_Password").val(); var isPersistent = $("#login_RememberMe").attr("checked"); var customInfo = null; var redirectUrl = null; // Log them in. alert("try login"); ssa.login(username, password, isPersistent, customInfo, redirectUrl, onLoginComplete, onError); alert("made it here"); } The first alert fires but the second one doesn't which means the function is failing. Here's the function I pulled from Asp.Net Ajax to show you: function(c, b, a, h, f, d, e, g) { this._invoke(this._get_path(), "Login", false, { userName: c, password: b, createPersistentCookie: a }, Function.createDelegate(this, this._onLoginComplete), Function.createDelegate(this, this._onLoginFailed), [c, b, a, h, f, d, e, g]); } Anyone have any idea of why it's failing?

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• Can't use my form

  - by Alexandr

  I have class with my form in folder /application/forms/Auth.php it looks like class Form_Auth extends Zend_Form { public function __construct() { $this->setName(); parent::__construct(); $username = new Zend_Form_Element_Text('username'); $password = new Zend_Form_Element_Password('password'); $mail = new Zend_Form_Element_Text('mail'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username,$password,$mail,$submit)); } } When i try create object $this->view->form = new Form_Auth(); is see exeption Application error Exception information: Message: Invalid name provided; must contain only valid variable characters and be non-empty Stack trace: D:\WWW\zends\application\Forms\Auth.php(8): Zend_Form-setName() d:\WWW\zends\application\controllers\RegistrationController.php(49): Form_Auth-__construct() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Action.php(513): RegistrationController-indexAction() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action-dispatch('indexAction') D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard-dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front-dispatch() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap-run() D:\WWW\zends\public\index.php(26): Zend_Application-run() {main} Request Parameters: array ( 'controller' = 'registration', 'action' = 'index', 'module' = 'default', ) the version zf is 1.10.3 what i do wrong ?

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• How can I cluster short messages [Tweets] based on topic ? [Topic Based Clustering]

  - by Jagira

  Hello, I am planning an application which will make clusters of short messages/tweets based on topics. The number of topics will be limited like Sports [ NBA, NFL, Cricket, Soccer ], Entertainment [ movies, music ] and so on... I can think of two approaches to this Ask for users to tag questions like Stackoverflow does. Users can select tags from a predefined list of tags. Then on server side I will cluster them on based of tags. Pros:- Simple design. Less complexity in code. Cons:- Choices for users will be restricted. Clusters will not be dynamic. If a new event occurs, the predefined tags will miss it. Take the message, delete the stopwords [ predefined in a dictionary ] and apply some clustering algorithm to make a cluster and depending on its popularity, display the cluster. The cluster will be maintained according to its sustained popularity. New messages will be skimmed and assigned to corresponding clusters. Pros:- Dynamic clustering based on the popularity of the event/accident. Cons:- Increased complexity. More server resources required. I would like to know whether there are any other approaches to this problem. Or are there any ways of improving the above mentioned methods? Also suggest some good clustering algorithms.I think "K-Nearest Clustering" algorithm is apt for this situation.

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• Integrate OpenId into an existing site

  - by Andrea

  I have a working web application which already has a login and registration system. I'm looking for some advice on how to do it. Until now, users have a username, an email, a password and some optional fields. The registrartion is the usual process with email confirmation. Now I'd like to allow users to use OpenId. So I have added an openid field to the table. There are two different login forms, and users which are already registered can add their openid info and use either login form. The problem is with new users who come on the site for the first time and try to login with OpenId. I create a new user for them, and I don't need a password, but still I need at least a username, which is used on the site (I'm not sure if the email is needed). So my problems are: 1) How do I manage validation? Some fields are required for some users, (e.g. a password) but not for some others. I mean, I can do this, but it immediately gets messy. 2) Should I ask for a username and email on the first OpenId login? On the one hand I'd say yes, but I fear this vanishes the advantages of using OpenId, that is, not having to provide details. 3) I could get the details via SReg or AttributeExchange, but most providers have a bad support for those. For instance my Gmail OpenId account does not tell the email (!). Is there some place to learn more about the current support for these extensions?

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• POSTmethod and PHP- login verification

  - by Neethusha

  I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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• Resolving the WMI DNS Host Name

  - by Stephen Murby

  I am trying to make a comparison between a machine name i have retrieved from AD, and the DNS Host Name i want to get using WMI from the machine. I currently have: foreach (SearchResult oneMachine in allMachinesCollected) { pcName = oneMachine.Properties["name"][0].ToString(); ConnectionOptions setupConnection = new ConnectionOptions(); setupConnection.Username = USERNAME; setupConnection.Password = PASSWORD; setupConnection.Authority = "ntlmdomain:DOMAIN"; ManagementScope setupScope = new ManagementScope("\\\\" + pcName + "\\root\\cimv2", setupConnection); setupScope.Connect(); ObjectQuery dnsNameQuery = new ObjectQuery("SELECT * FROM Win32_ComputerSystem"); ManagementObjectSearcher dnsNameSearch = new ManagementObjectSearcher(setupScope, dnsNameQuery); ManagementObjectCollection allDNSNames = dnsNameSearch.Get(); string dnsHostName; foreach (ManagementObject oneName in allDNSNames) { dnsHostName = oneName.Properties["DNSHostName"].ToString(); if (dnsHostName == pcName) { shutdownMethods.ShutdownMachine(pcName, USERNAME, PASSWORD); MessageBox.Show(pcName + " has been sent the reboot command"); } } } } But i get a ManagementException dnsHostName = oneName.Properties["DNSHostName"].ToString(); << here saying not found. Any ideas?

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• What is the best way to handle the Connections to MySql from c#

  - by srk

  I am working on a c# application which connects to MySql server. There are about 20 functions which will connect to database. This application will be deployed in 200 over machines. I am using the below code to connect to my database which is identical for all the functions. The problem is, i can some connections were not closed and still alive when deployed in 200 over machines. Connection String : <add key="Con_Admin" value="server=test-dbserver; database=test_admindb; uid=admin; password=1Password; Use Procedure Bodies=false;" /> Declaration of the connection string Globally in application [Global.cs] : public static MySqlConnection myConn_Instructor = new MySqlConnection(ConfigurationSettings.AppSettings["Con_Admin"]); Function to query database : public static DataSet CheckLogin_Instructor(string UserName, string Password) { DataSet dsValue = new DataSet(); //MySqlConnection myConn = new MySqlConnection(ConfigurationSettings.AppSettings["Con_Admin"]); try { string Query = "SELECT accounts.str_nric AS Nric, accounts.str_password AS `Password`," + " FROM accounts " + " WHERE accounts.str_nric = '" + UserName + "' AND accounts.str_password = '" + Password + "\'"; MySqlCommand cmd = new MySqlCommand(Query, Global.myConn_Instructor); MySqlDataAdapter da = new MySqlDataAdapter(); if (Global.myConn_Instructor.State == ConnectionState.Closed) { Global.myConn_Instructor.Open(); } cmd.ExecuteScalar(); da.SelectCommand = cmd; da.Fill(dsValue); Global.myConn_Instructor.Close(); } catch (Exception ex) { Global.myConn_Instructor.Close(); ExceptionHandler.writeToLogFile(System.Environment.NewLine + "Target : " + ex.TargetSite.ToString() + System.Environment.NewLine + "Message : " + ex.Message.ToString() + System.Environment.NewLine + "Stack : " + ex.StackTrace.ToString()); } return dsValue; }

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• How to link different Servlet together?

  - by Harry Pham

  First of all, I did not use Spring MVC. :) :) Just want to get it out first. Now what I have is different JSP pages that making calls to different Servlets. All the pieces work great individually but I kind of need to link them together. If all of jsp pages make GET request then it would be easy, since I would just pass a type via the web address, and on my servlet side, I would just enumerated through all the parameter, determine which type is it, and delegate to the right servlet. But not all jsp pages make GET request, some make POST request via form. Let see example A.jsp $.getJSON('GenericServlet?type=A', ... GenericServlet.java String type = request.getParameter("type"); if(type.equals("A")){ //Somehow delegate to Servlet A (Not sure how to do that yet :)) } but in B.jsp I would have something like this B.jsp <form action="GenericServlet" method="post"> <table border=0 cellspacing=10 cellpadding=0> <tr> <td>User Name:</td> <td><input type="text" name="username" size=22/></td> </tr> <tr> <td>Password:</td> <td><input type="password" name="password" size=22/></td> </tr> </table> <input type="submit" value="Create User" /> </form> It kind of hard for me to determine in GenericServlet.java that this need to go to servletB

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• Providing custom database functionality to custom asp.net membership provider

  - by IrfanRaza

  Hello friends, I am creating custom membership provider for my asp.net application. I have also created a separate class "DBConnect" that provides database functionality such as Executing SQL statement, Executing SPs, Executing SPs or Query and returning SqlDataReader and so on... I have created instance of DBConnect class within Session_Start of Global.asax and stored to a session. Later using a static class I am providing the database functionality throughout the application using the same single session. In short I am providing a single point for all database operations from any asp.net page. I know that i can write my own code to connect/disconnect database and execute SPs within from the methods i need to override. Please look at the code below - public class SGI_MembershipProvider : MembershipProvider { ...... public override bool ChangePassword(string username, string oldPassword, string newPassword) { if (!ValidateUser(username, oldPassword)) return false; ValidatePasswordEventArgs args = new ValidatePasswordEventArgs(username, newPassword, true); OnValidatingPassword(args); if (args.Cancel) { if (args.FailureInformation != null) { throw args.FailureInformation; } else { throw new Exception("Change password canceled due to new password validation failure."); } } ..... //Database connectivity and code execution to change password. } .... } MY PROBLEM - Now what i need is to execute the database part within all these overriden methods from the same database point as described on the top. That is i have to pass the instance of DBConnect existing in the session to this class, so that i can access the methods. Could anyone provide solution on this. There might be some better techniques i am not aware of that. The approach i am using might be wrong. Your suggessions are always welcome. Thanks for sharing your valuable time.

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• Can't diagnose my MySQL root user problem

  - by George Crawford

  Hi all, I have a problem with the MySQL root user in My MySQL setup, and I just can't for the life of me work out how to fix it. It seems that I have somehow messed up the root user, and my access to databases is now very erratic. For reference, I'm using MAMP on OS X to provide the MySQL server. I'm not sure how much that matters though - I'd guess that whatever I've done will require a command-line fix to solve it. I can start MySQL using MAMP as usual, and access databases using the 'standard' users I have created for my PHP apps. However, the root user, which I use in my MySQL GUI client, and also in phpMyAdmin, can only access the "information_schema" database, as well as two I have created manually, and presumably (and mistakenly) left permissions wide open for. My 15 or so other databases cannot be accessed my the root user. When I load up phpMyAdmin, the home screen says: "Create new database: No Privileges". I certainly did at some stage change my root user's password using the MAMP dialog. But I don't remember if I did anything else which might have caused this problem. I've tried changing the password again, and there seems to be no change in the issue. I've also tried resetting root password using the command line, including starting mysql manually with --skip-grant-tables then flushing privs, but again, nothing seems to fix the issue. I've come to the end of my ideas, and would very much appreciate some step-by-step advice and diagnosis from one of the experts here! Many thanks for your help.

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• Insert Stored Procedure does not Create Database Record

  - by SidC

  Hello All, I have the following stored procedure: ALTER PROCEDURE Pro_members_Insert @id int outPut, @LoginName nvarchar(50), @Password nvarchar(15), @FirstName nvarchar(100), @LastName nvarchar(100), @signupDate smalldatetime, @Company nvarchar(100), @Phone nvarchar(50), @Email nvarchar(150), @Address nvarchar(255), @PostalCode nvarchar(10), @State_Province nvarchar(100), @City nvarchar(50), @countryCode nvarchar(4), @active bit, @activationCode nvarchar(50) AS declare @usName as varchar(50) set @usName='' select @usName=isnull(LoginName,'') from members where LoginName=@LoginName if @usName <> '' begin set @ID=-3 RAISERROR('User Already exist.', 16, 1) return end set @usName='' select @usName=isnull(email,'') from members where Email=@Email if @usName <> '' begin set @ID=-4 RAISERROR('Email Already exist.', 16, 1) return end declare @MemID as int select @memID=isnull(max(ID),0)+1 from members INSERT INTO members ( id, LoginName, Password, FirstName, LastName, signupDate, Company, Phone, Email, Address, PostalCode, State_Province, City, countryCode, active,activationCode) VALUES ( @Memid, @LoginName, @Password, @FirstName, @LastName, @signupDate, @Company, @Phone, @Email, @Address, @PostalCode, @State_Province, @City, @countryCode, @active,@activationCode) if @@error <> 0 set @ID=-1 else set @id=@memID Note that I've "inherited" this sproc and the database. I am trying to insert a new record from my signup.aspx page. My SQLDataSource is as follows: <asp:SqlDataSource runat="server" ID="dsAddMember" ConnectionString="rmsdbuser" InsertCommandType="StoredProcedure" InsertCommand="Pro_members_Insert" ProviderName="System.Data.SqlClient"> The click handler for btnSave is as follows: Protected Sub btnSave_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btnSave.Click Try dsAddMember.DataBind() Catch ex As Exception End Try End Sub When I run this page, signup.aspx, provide required fields and click submit, the page simply reloads and the database table does not reflect the newly-inserted record. Questions: 1. How do I catch the error messages that might be returned from the sproc? 2. Please advise how to change signup.aspx so that the insert occurs. Thanks, Sid

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• INSERT data from Textbox to Postgres SQL

  - by user1479013

  I just learn how to connect C# and PostgresSQL. I want to INSERT data from tb1(Textbox) and tb2 to database. But I don't know how to code My previous code is SELECT from database. this is my code private void button1_Click(object sender, EventArgs e) { bool blnfound = false; NpgsqlConnection conn = new NpgsqlConnection("Server=127.0.0.1;Port=5432;User Id=postgres;Password=admin123;Database=Login"); conn.Open(); NpgsqlCommand cmd = new NpgsqlCommand("SELECT * FROM login WHERE name='" + tb1.Text + "' and password = '" + tb2.Text + "'",conn); NpgsqlDataReader dr = cmd.ExecuteReader(); if (dr.Read()) { blnfound = true; Form2 f5 = new Form2(); f5.Show(); this.Hide(); } if (blnfound == false) { MessageBox.Show("Name or password is incorrect", "Message Box", MessageBoxButtons.OK, MessageBoxIcon.Exclamation, MessageBoxDefaultButton.Button1); dr.Close(); conn.Close(); } } So please help me the code.

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• starting rails in test environment

  - by Brian D.

  I'm trying to load up rails in the test environment using a ruby script. I've tried googling a bit and found this recommendation: require "../../config/environment" ENV['RAILS_ENV'] = ARGV.first || ENV['RAILS_ENV'] || 'test' This seems to load up my environment alright, but my development database is still being used. Am I doing something wrong? Here is my database.yml file... however I don't think it is the issue development: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_development pool: 5 username: root password: dev host: localhost # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_test pool: 5 username: root password: dev host: localhost production: adapter: mysql encoding: utf8 reconnect: false database: BrianSite_production pool: 5 username: root password: dev host: localhost I can't use ruby script/server -e test because I'm trying to run ruby code after I load rails. More specifically what I'm trying to do is: run a .sql database script, load up rails and then run automated tests. Everything seems to be working fine, but for whatever reason rails seems to be loading in the development environment instead of the test environment. Here is a shortened version of the code I am trying to run: system "execute mysql script here" require "../../config/environment" ENV['RAILS_ENV'] = ARGV.first || ENV['RAILS_ENV'] || 'test' describe Blog do it "should be initialized successfully" do blog = Blog.new end end I don't need to start a server, I just need to load my rails code base (models, controllers, etc..) so I can run tests against my code. Thanks for any help.

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• I can't insert data into my database

  - by Ken

  I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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• Error with MySQL Query

  - by Ken

  Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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• Inserting default "admin" user into database during Rails App startup

  - by gbc

  I'm building my first real rails application for a little in-house task. Most of the application tasks require authentication/authorization. The first time the app starts up (or starts with a wiped db), I'd like the process to be: User logs into the admin panel using "admin" & "admin" for authentication info. User navigates to admin credentials editing page and changes name and password to something safer so that "admin" & "admin" is no longer a valid login. To achieve this result, I'd like to stuff a default username & password combination into the database on if the application starts up and detects that there are no user credentials in the 'users' table. For example: if User.count == 0 User.create(:name => "admin", :password => "admin") end However, I'm unsure where to place that code. I tried adding an initializer script in the config/initializers, but the error I received appeared to indicate that the model classes weren't yet loaded into the application. So I'm curious to know at what point I can hook into the application startup cycle and insert data into the database through ActiveRecord before requests are dispatched.

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• Send file FTP over SSL with custom port number

  - by JM4

  I have asked the question before but in a different manner. I am trying taking form data, compiling into a temporary CSV file and trying to send over to a client via FTP over SSL (this is the only route I am interested in hearing solutions for unless there is a workaround to doing this, I cannot make changes). I have tried the following: ftp_connect - nothing happens, the page just times out ftp_ssl_connect - nothing happens, the page just times out curl library - same thing, given URL it also gives error. I am given the following information: FTPS Server IP Address TCP Port (1234) Username Password Data Directory to dump file FTP Mode: Passive very, very basic code (which I believe should initiate a connection at minimum): Code: <?php $ftp_server = "00.000.00.000"; //masked for security $ftp_port = "1234"; // masked but not 990 $ftp_user_name = "username"; $ftp_user_pass = "password"; // set up basic ssl connection $conn_id = ftp_ssl_connect($ftp_server, $ftp_port, "20"); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); echo ftp_pwd($conn_id); // / echo "hello"; // close the ssl connection ftp_close($conn_id); ?> When I run this over a SmartFTP client, everything works just fine. I just can't get it to work using PHP (which is a necessity). Has anybody had success doing this in the past? I would be very interested to hear your approach.

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• #1146 - Table 'phpmyadmin.pma_recent' doesn't exist

  - by Mumin Ali

  Solution Guys... FYI i am using xampp to use phpmyadmin. and this error happens during the process of creating a database on localhost. Below is the code for config.inc file under phpmyadmin directory: <?php /* * This is needed for cookie based authentication to encrypt password in * cookie */ $cfg['blowfish_secret'] = 'xampp'; /* YOU SHOULD CHANGE THIS FOR A MORE SECURE COOKIE AUTH! */ /* * Servers configuration */ $i = 0; /* * First server */ $i++; /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'HTTP'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = true; $cfg['Lang'] = ''; /* Bind to the localhost ipv4 address and tcp */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; /* User for advanced features */ $cfg['Servers'][$i]['controluser'] = 'pma'; $cfg['Servers'][$i]['controlpass'] = ''; /* Advanced phpMyAdmin features */ $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin'; $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark'; $cfg['Servers'][$i]['relation'] = 'pma_relation'; $cfg['Servers'][$i]['table_info'] = 'pma_table_info'; $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords'; $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages'; $cfg['Servers'][$i]['column_info'] = 'pma_column_info'; $cfg['Servers'][$i]['history'] = 'pma_history'; $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords'; $cfg['Servers'][$i]['tracking'] = 'pma_tracking'; $cfg['Servers'][$i]['userconfig'] = 'pma_userconfig'; $cfg['Servers'][$i]['recent'] = 'pma_recent'; $cfg['Servers'][$i]['table_uiprefs'] = 'pma_table_uiprefs'; /* * End of servers configuration */ ?>

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• URL-Encoded post parameters don't Bind to model

  - by Steven Klein

  I have the following Model namespace ClientAPI.Models { public class Internal { public class ReportRequest { public DateTime StartTime; public DateTime EndTime; public string FileName; public string UserName; public string Password; } } } with the following method: [HttpPost] public HttpResponseMessage GetQuickbooksOFXService(Internal.ReportRequest Request){ return GetQuickbooksOFXService(Request.UserName, Request.Password, Request.StartTime, Request.EndTime, Request.FileName); } My webform looks like this: <form method="POST" action="http://localhost:56772/Internal/GetQuickbooksOFXService" target="_blank"> <input type="text" name="StartTime" value="2013-04-03T00:00:00"> <input type="text" name="EndTime" value="2013-05-04T00:00:00"> <input type="text" name="FileName" value="Export_2013-04-03_to_2013-05-03.qbo"> <input type="text" name="UserName" value="UserName"> <input type="text" name="Password" value="*****"> <input type="submit" value="Submit"></form> My question is: I get into the GetQuickbooksOFXService function but my model has all nulls in it instead something useful. Am I doing something wrong?

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• Using virtualization infrastructure for J2EE application distribution- viable alternative?

  - by Dan

  Our company builds custom J2EE web solutions. At the moment, we use standard J2EE distribution mechanisms (ear/war archives). Application servers are generally administered by our clients' IT departments and since we do not have complete control over the environment, a lot of entropy can be introduced into the solution. For example: latest app. server patch not applied conflicting third party libraries inside the app. server root server runtime and tuning parameters not configured (for example, number of connections in database pool) We are looking into using virtualization infrastructure for J2EE application distribution. Instead of sending the ear/war archive, we’d send image with application server node and our application preinstalled. Some of the benefits are same as using with using virtualization infrastructure in general, namely better use of hardware resources. For us, it reduces the entropy of hosting infrastructure - distributing VM should be less affected by hosting environment. So far, the downside I see can be in application server licenses, here they will have to use dedicated servers for our solution, but this is generally already done that way. Also, there is a complexity with maintaining virtualization infrastructure, but this is often something IT departments have more experience with than with administering and fine-tuning J2EE solutions. Anyone has experience with this model? What are the downsides? Will we not just replace one type of complexity with other?

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• trouble connecting to MySql DB (PHP)

  - by user332817

  Hi I have the following PHP code to connect to my db. <?php ob_start(); $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); ?> however I get the following error: Warning: mysql_connect() [function.mysql-connect]: [2002] A connection attempt failed because the connected party did not (trying to connect via tcp://localhost:3306) in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Warning: mysql_connect() [function.mysql-connect]: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond. in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Fatal error: Maximum execution time of 30 seconds exceeded in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 I am able to add a db/tables via phpmyadmin but I cant connect using php. here is a screenshot of my phpmyadmin page: http://img294.imageshack.us/img294/1589/sqls.jpg any help would be appreciated, thanks in advance.

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• PHP Check slave status without mysql_connect timeout issues

  - by Jonathon

  I have a web-app that has a master mysql db and four slave dbs. I want to handle all (or almost all) read-only (SELECT) queries from the slaves. Our load-balancer sends the user to one of the slave machines automatically, since they are also running Apache/PHP and serving webpages. I am using an include file to setup the connection to the databases, such as: //for master server (i.e. - UPDATE/INSERT/DELETE statements) $Host = "10.0.0.x"; $User = "xx"; $Password = "xx"; $Link = mysql_connect( $Host, $User, $Password ); if( !$Link ) ) { die( "Master database is currently unavailable. Please try again later." ); } //this connection can be used for READ-ONLY (i.e. - SELECT statements) on the localhost $Host_Local = "localhost"; $User_Local = "xx"; $Password_Local = "xx"; $Link_Local = mysql_connect( $Host_Local, $User_Local, $Password_Local ); //fail back to master if slave db is down if( !$Link_Local ) ) { $Link_Local = mysql_connect( $Host, $User, $Password ); } I then use $Link for all update queries and $Link_Local as the connection for SELECT statements. Everything works fine until the slave server database goes down. If the local db is down, the $Link_Local = mysql_connect() call takes at least 30 seconds before it gives up on trying to connect to the localhost and returns back to the script. This causes a huge backlog of page serves and basically shuts down the system (due to the extremely slow response time). Does anyone know of a better way to handle connections to slave servers via PHP? Or, is there some kind of timeout function that could be used to stop the mysql_connect call after 2-3 seconds? Thanks for the help. I searched the other mysql_connect threads, but didn't see any that addressed this issue.

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