Search Results

Search found 4517 results on 181 pages for 'expression sketchflow'.

Page 16/181 | < Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >

  • Help with Regular Expression

    - by shivesh
    Hello I need help with Regular Expression, I want to match each section (number and it's text - 2 groups), the text can be multi line, each section ends when another section starts (another number) or when .END is reached or EOF. Demo Expression: \(\d{1,3}\) ([\s\S]*?)(\.END|\(\d{1,3}\)) Input text: (1) some text some text some text some text some text some text (2) some text some textsome text (3) some textsome text some textsome textsome text (4) some text .END first group should match number (with brackets) and second group should match corresponded text.

    Read the article

  • How to process this string via regular expression

    - by iiduce
    my string style like this: expression1/field1+expression2*expression3+expression4/field2*expression5*expression6/field3 a real style mybe like this: computer/(100)+web*mail+explorer/(200)*bbs*solution/(300) "+" and "*" represent operator "computer","web"...represent expression (100),(200) represent field num . field num may not exist. I want process the string to this: /(100)+web*+explorer/(200)bbs/(300) rules like this: if expression length is more than 3 and its field is not (200), then add brackets to it.

    Read the article

  • Question regarding php Regular expression filenames

    - by jason
    I am very bad at regular expressions, but I have a regular expression that is working okay, except for one issue: /\/(.*?).php/ I only need this regular expression to find things like: /this-a-valid-page.php {some words here} /anotherpage.php { some words here} http://www.google.com but do not find URLs the problem i am having is that it find this parts of full URLS i want it to avoid these all together. http://www.google.com/page.php because i have another function that does something different than the filename reg exp.

    Read the article

  • php Dollar amount Regular Expression

    - by Thildemar
    I am have completed javascript validation of a form using Regular Expressions and am now working on redundant verification server-side using PHP. I have copied this regular expression from my jscript code that finds dollar values, and reformed it to a PHP friendly format: /\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/ Specifically: if (preg_match("/\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/", $_POST["cost"])){} While the expression works great in javascript I get : Warning: preg_match() [function.preg-match]: Compilation failed: nothing to repeat at offset 1 when I run it in PHP. Anyone have a clue why this error is coming up?

    Read the article

  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

    Read the article

  • extract variables from an expression using javascript regexp

    - by powerboy
    For example, here is a string representing an expression: var str = 'total = sum(price * qty) * 1.09875'; I want to extract variables (i.e., 'total', 'price' and 'qty' but not 'sum' since 'sum' is a function name) from this expression. What is the regexp pattern in javascript? Variable name consists of letters, digits, or the underscore, beginning with letters or the underscore.

    Read the article

  • regular expression for challenge value

    - by Salman
    Hi what will be the regular expression to extract challenge var value i am interested in this vlaue 03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig this value changes every time we refresh it so the expression has to be generic enough to pick up what ever is the value var RecaptchaState = { site : '6LeKCL8SAAAAADV5Dr-lfY2eOEV8rubeN25BAKp2', challenge : '03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig', is_incorrect : false, programming_error : '', error_message : '', server : 'http://www.google.com/recaptcha/api/', timeout : 18000}; any help will be appreciated, or any method to extract this value in any server side lang

    Read the article

  • Regular expression from font to span (size and colour) and back (VB.NET)

    - by chapmanio
    Hi, I am looking for a regular expression that can convert my font tags (only with size and colour attributes) into span tags with the relevant inline css. This will be done in VB.NET if that helps at all. I also need a regular expression to go the other way as well. To elaborate below is an example of the conversion I am looking for: <font size="10">some text</font> To then become: <span style="font-size:10px;">some text</span> So converting the tag and putting a "px" at the end of whatever the font size is (I don't need to change/convert the font size, just stick px at the end). The regular expression needs to cope with a font tag that only has a size attribute, only a color attribute, or both: <font size="10">some text</font> <font color="#000000">some text</font> <font size="10" color="#000000">some text</font> <font color="#000000" size="10">some text</font> I also need another regular expression to do the opposite conversion. So for example: <span style="font-size:10px;">some text</span> Will become: <font size="10">some text</font> As before converting the tag but this time removing the "px", I don't need to worry about changing the font size. Again this will also need to cope with the size styling, font styling, and a combination of both: <span style="font-size:10px;">some text</span> <span style="color:#000000;">some text</span> <span style="font-size:10px; color:#000000;">some text</span> <span style="color:#000000; font-size:10px;">some text</span> I apprecitate this is a lot to ask, I am hopeless with regular expressions and need to find a way of making these conversions in my code. Thanks so much to anyone that can/is willing to help me!

    Read the article

  • Regular expression that matches valid IPv6 addresses

    - by Readonly
    I'm having trouble writing a regular expression that matches valid IPv6 addresses, including those in their compressed form (with "::" or leading zeros omitted from each byte pair). Can someone suggest a regular expression that would fulfill the requirement? I'm considering expanding each byte pair and matching the result with a simpler regex.

    Read the article

  • Regular Expression - Block Spam

    - by Immanuel
    Could someone lead me on finding a regular expression that blocks a comma separated list of Spam words I already have? The regular expression needs to match a string with the spam word list I already have. Not that it matters, but I am using PHP.

    Read the article

  • Regular Expression

    - by TiagoDias
    Hi all, I cannot manage to get a working regular expression (for use in ASP.NEt Validataor) for the following criteria: - I want all chars from A-Z a-z 0-9 - I don't want the Enter key I have the expression: [\w\s,.-/]*[^\n] but that don't works. Please give-me a hint, Thanks.

    Read the article

  • simple method that checks text is email with regular expression

    - by user223863
    Can't believe how difficult this seems to be all I want to is to validate a user inout using javascript to make sure that it is an email address. But can't get it to work: I am using: //validates a regulaer expression Utilities2.prototype.validateEmail = function(stringToValidateArg) { alert('about to check regexp'); var regExpPattern = /^[a-zA-Z0-9._-]+@[a-zA-Z0-9.-]+\.[a-zA-Z]{2,4}$/; alert(regExpPattern.test(stringToValidateArg)); } But this always returns false, any ideas why is it because of the regular expression?

    Read the article

  • Help needed in writing regular expression -- TCL

    - by user330727
    Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL i) ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}] I want to write an another regexp which catches/matches only the following string wherever comes ii) (XYZ) My trial: [regexp {^X([Y]*)Z$}]

    Read the article

  • Help needed in writing regular expression using TCL

    - by user330727
    Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}

    Read the article

  • nginx dynamic servername with regular expression doesn't work for co.uk

    - by redn0x
    I'm trying to setup a nginx server which dynamically loads content from a folder for a domain. To do this I'm using regular expressions in the server name like so: server_name ((?<subdomain>.+)\.)?(?<domain>.+)\.(?<tld>.*); This will create a 3 variables for nginx to use later on, for example when using the following url: test.foo.example.com this will evaluate to: $subdomain = test.foo $domain = example $tld = com The problem arises when the co.uk top-level domain is used. In this case when using the url test.foo.example.co.ukit will evaluate to: $subdomain = test.foo.cedira $domain = co $tld = uk How can I edit the regular expression so that it will also work for co.uk?

    Read the article

  • String manipulation of type String substitution in mathematical expression

    - by Peterstone
    Imagine something like exp(49/200)+(x-49/200) I want to pass as argument of the function "roundn" whatever operation that is not a addtion or a subtraction So my expresion became roundn(exp(roundn(49/200,n)),n)+(x - roundn(49/200,n) Well the expression I want to manipulate is this: exp(49/200)+exp(49/200)*(x-49/200)+1/2*exp(49/200)*(x-49/200)^2+1/6*exp(49/200)*(x- 49/200)^3+1/24*exp(49/200)*(x-49/200)^4+1/120*exp(49/200)*(x-49/200)^5+1/720*exp(49/200)*(x-49/200)^6+1/5040*exp(49/200)*(x-49/200)^7+1/40320*exp(49/200)*(x-49/200)^8+1/362880*exp(49/200)*(x-49/200)^9+1/3628800*exp(49/200)*(x-49/200)^10+1/39916800*exp(49/200)*(x-49/200)^11 I´m looking for a method (That include whatever program) not based in lenguage programming, as much batch or somithing like that... Thank you!

    Read the article

  • Regular Expression to replace part of URL in XML file

    - by Richie086
    I need a regular expression in Notepad++ to search/replace a string. My document (xml) has serveral thousand lines that look similar to this: <Url Source="Output/username/project/Content/Volume1VolumeName/TopicFileName.htm" /> I need to replace everything starting from Volume1 to .htm" / to replaced with X's or some other character to mask the actual file names in this file. So the resulting string would look like this after the search/replace was performed: <Url Source="Output/username/project/Content/Volume1XxxxxxXxxx/XxxxxXxxxXxxx.htm" /> I am working with confidential information that I cannot release to people outside of my company, but i need to send an example log file to a 3rd party for troubleshooting purposes. FYI the X's do not need to follow the upper/lower case after the replacement, i was just using different case X's for the hell of it :)

    Read the article

  • Misbehavior in regular expression in VIM

    - by poissonbreaker
    I am having a problem with a regular expression on vim. I have a pattern as follows: http:\/\/\(\w\+\.\?\)\+ [matches http://(AS MANY WORDS FOLLOWED BY DOT OR NOT ENCOUNTERS) e.g. http://wd1.wd2.com] I have a text as follows: http://wd1.wd2.com/wd3 I am trying to make this substitution on it: s/\(http:\/\/\)\(\w\+\.\?\)\+/\1wd4.wd5.com and the result is http://wd4.wd5.com /wd3 (Notice the white space inserted at the end of the replacement) How can I avoid having this inserted space? I am afraid is a bug in the regexp engine but I am not sure.

    Read the article

  • Convert Dynamic to Type and convert Type to Dynamic

    - by Jon Canning
    public static class DynamicExtensions     {         public static T FromDynamic<T>(this IDictionary<string, object> dictionary)         {             var bindings = new List<MemberBinding>();             foreach (var sourceProperty in typeof(T).GetProperties().Where(x => x.CanWrite))             {                 var key = dictionary.Keys.SingleOrDefault(x => x.Equals(sourceProperty.Name, StringComparison.OrdinalIgnoreCase));                 if (string.IsNullOrEmpty(key)) continue;                 var propertyValue = dictionary[key];                 bindings.Add(Expression.Bind(sourceProperty, Expression.Constant(propertyValue)));             }             Expression memberInit = Expression.MemberInit(Expression.New(typeof(T)), bindings);             return Expression.Lambda<Func<T>>(memberInit).Compile().Invoke();         }         public static dynamic ToDynamic<T>(this T obj)         {             IDictionary<string, object> expando = new ExpandoObject();             foreach (var propertyInfo in typeof(T).GetProperties())             {                 var propertyExpression = Expression.Property(Expression.Constant(obj), propertyInfo);                 var currentValue = Expression.Lambda<Func<string>>(propertyExpression).Compile().Invoke();                 expando.Add(propertyInfo.Name.ToLower(), currentValue);             }             return expando as ExpandoObject;         }     }

    Read the article

  • Documentation often ommits to specify which flavour of regular expression to use, so is there a default flavour that we should all be familiar with?

    - by JW01
    Often I come across documentation that says "use a regular expression here" I have to spend quite some time digging around trying to work out which regular expression format they are expecting. As far as I can tell, there are many types of regular expression. But, at my last place of work I was made to feel stupid when I suggested adding some text to our User Documentation to specify the type of regular expression to be used. When someone says "a regular expression" what is the regular expression syntax most people expect and where is it documented? Update: I was prompted to single-out some examples - but no disrespect to these great projects: eregi docs page is not particularly helpful in explaining expected syntax. Nor can I easily work out the syntax expected here if i just land on the page from a search. No explicit mention of the regular expression pattern expected by PatternExpectation() on the SimpleTest page. etc. etc. here is a highly voted SO answer that seems to assume there is only one flavour of regular expressions.

    Read the article

  • Illegal start of expression?

    - by Fraser
    I'm trying to build a simple Android app that increments a number displayed every time a button is pressed, but I can't work out how to fix the "illegal start of expression" error I keep getting. My code: package com.clicker; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.TextView; public class Clicker extends Activity { private int clickerNumber = 0; private TextView clickerText; private Button clickerButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); clickerText = (TextView)findViewById(R.id.clickerText); final Button clickerButton = (Button)findViewById(R.id.clickerButton); clickerButton.setOnClickListener(new View.OnClickListener()); { public void onClick(); { clickerNumber = clickerNumber++; clickerText.setText(Integer.toString(clickerNumber)); } } } } And compiler output: compile: [javac] Compiling 2 source files to /home/fraser/Applications/Android/Code/Clicker/bin/classes [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:24: ')' expected [javac] clickerButton.setOnClickListener(new View.OnClickListener(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: ';' expected [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:29: ';' expected [javac] clickerText.setText(Integer.toString(clickerNumber))); [javac] ^ [javac] 5 errors

    Read the article

  • .NET Regular Expression to find actual words in text

    - by Mehdi Anis
    I am using VB .NET to write a program that will get the words from a suplied text file and count how many times each word appears. I am using this regular expression:- parser As New Regex("\w+") It gives me almost 100% correct words. Except when I have words like "Ms Word App file name is word.exe." or "is this a c# statment If(ab?1,0) ?" In such cases I get [word & exe] AND [If, a, b, 1 and 0] as seperate words. it would be nice (for my purpose) that I received word.exe and (If(ab?1,0) as words. I guess \w+ looks for white space, sentence terminating punctuation mark and other punctuation marks to determine a word. I want a similar regular Expression that will not break a word by a punctuation mark, if the punctuation mark is not the end of the word. I think end-of-word can be defined by a trailing WhiteSpace, Sentence terminating Punctuation (you may think of others). if you can suggest some regular expression 9for VB .NET) that will be great help. Thanks.

    Read the article

< Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >