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  • Python - List and Loop in one def

    - by Dunwitch
    I'm trying to get the def wfsc_pod1 and wfsc_ip into the same def. I'm not quite sure how to approach the problem. I want wfsc_pod1 to display all the information for name, subnet and gateway. Then wfsc_ip shows the ip addresses below it. I also get a None value when I run it as it. Not sure why. Anything more pythonic is more appreciated. class OutageAddress: subnet = ["255.255.255.0", "255.255.255.1"] # Gateway order is matched with names gateway = ["192.168.1.1", "192.168.1.2", "192.168.1.3", "192.168.1.4", "192.168.1.5", "192.168.1.6", "192.168.1.7", "192.168.1.8", "192.168.1.9"] name = ["LOC1", "LOC2", "LOC3", "LOC4", "LOC5", "LOC6", "LOC7", "LOC8", "LOC9"] def wfsc_pod1(self): wfsc_1 = "%s\t %s\t %s\t" % (network.name[0],network.subnet[0],network.gateway[0]) return wfsc_1 def wfsc_ip(self): for ip in range(100,110): ip = "192.168.1."+str(ip) print ip network = OutageAddress() print network.wfsc_pod1() print network.wfsc_ip()

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  • Working with a list, performing arithmetic logic in Python

    - by haea ohoh
    Suppose I have made a large list of numbers, and I want to make another one which I will add, pairwise, with the first list. Here's the first list, A: [109, 77, 57, 34, 94, 68, 96, 72, 39, 67, 49, 71, 121, 89, 61, 84, 45, 40, 104, 68, 54, 60, 68, 62, 91, 45, 41, 118, 44, 35, 53, 86, 41, 63, 111, 112, 54, 34, 52, 72, 111, 113, 47, 91, 107, 114, 105, 91, 57, 86, 32, 109, 84, 85, 114, 48, 105, 109, 68, 57, 78, 111, 64, 55, 97, 85, 40, 100, 74, 34, 94, 78, 57, 77, 94, 46, 95, 60, 42, 44, 68, 89, 113, 66, 112, 60, 40, 110, 89, 105, 113, 90, 73, 44, 39, 55, 108, 110, 64, 108] And here's B: [35, 106, 55, 61, 81, 109, 82, 85, 71, 55, 59, 38, 112, 92, 59, 37, 46, 55, 89, 63, 73, 119, 70, 76, 100, 49, 117, 77, 37, 62, 65, 115, 93, 34, 107, 102, 91, 58, 82, 119, 75, 117, 34, 112, 121, 58, 79, 69, 68, 72, 110, 43, 111, 51, 102, 39, 52, 62, 75, 118, 62, 46, 74, 77, 82, 81, 36, 87, 80, 56, 47, 41, 92, 102, 101, 66, 109, 108, 97, 49, 72, 74, 93, 114, 55, 116, 66, 93, 56, 56, 93, 99, 96, 115, 93, 111, 57, 105, 35, 99] How might I generate the arithmatic addition logic, processing each pairwise value one by one (A[0] and B[0], through A[99], B[99]) and producing the list C (A[0] + B[0] through A[99]+ B[99])?

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  • optimize python code

    - by user283405
    i have code that uses BeautifulSoup library for parsing. But it is very slow. The code is written in such a way that threads cannot be used. Can anyone help me about this? I am using beautifulsoup library for parsing and than save in DB. if i comment the save statement, than still it takes time so there is no problem with database. def parse(self,text): soup = BeautifulSoup(text) arr = soup.findAll('tbody') for i in range(0,len(arr)-1): data=Data() soup2 = BeautifulSoup(str(arr[i])) arr2 = soup2.findAll('td') c=0 for j in arr2: if str(j).find("<a href=") > 0: data.sourceURL = self.getAttributeValue(str(j),'<a href="') else: if c == 2: data.Hits=j.renderContents() #and few others... #... c = c+1 data.save() Any suggestions? Note: I already ask this question here but that was closed due to incomplete information.

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  • Python - Problems using mechanize to log into a difficult website

    - by user1781599
    × 139886 I am trying to log in to betfair.com by using mechanize. I have tried several ways but it always fail. This is the code I have developed so far, can anyone help me to identify what is wrong with it and how I can improve it to log into my betfair account? Thanks, import cookielib import urllib import urllib2 from BeautifulSoup import BeautifulSoup import mechanize from mechanize import Browser import re bf_username_name = "username" bf_password_name = "password" bf_form_name = "loginForm" bf_username = "xxxxx" bf_password = "yyyyy" urlLogIn = "http://www.betfair.com/" accountUrl = "https://myaccount.betfair.com/account/home?rlhm=0&" # This url I will use to verify if log in has been successful br = mechanize.Browser(factory=mechanize.RobustFactory()) br.addheaders = [("User-Agent","Mozilla/5.0 (Macintosh; Intel Mac OS X 10_5_8) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.90 Safari/537.1")] br.open(urlLogIn) br.select_form(nr=0) print br.form br.form[bf_username_name] = bf_username br.form[bf_password_name] = bf_password print br.form #just to check username and psw have been recorded correctly responseSubmit = br.submit() response = br.open(accountUrl) text_file = open("LogInResponse.html", "w") text_file.write(responseSubmit.read()) #this file should show the home page with me logged in, but it show home page as if I was not logged it text_file.close() text_file = open("Account.html", "w") text_file.write(response.read()) #this file should show my account page, but it should a pop up with an error text_file.close()

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  • Python If Statement Defaults to an elif

    - by Brad Carvalho
    Not sure why my code is defaulting to this elif. But it's never getting to the else statement. Even going as far as throwing index out of bound errors in the last elif. Please disregard my non use of regex. It wasn't allowed for this homework assignment. The problem is the last elif before the else statement. Cheers, Brad if item == '': print ("%s\n" % item).rstrip('\n') elif item.startswith('MOVE') and not item.startswith('MOVEI'): print 'Found MOVE' elif item.startswith('MOVEI'): print 'Found MOVEI' elif item.startswith('BGT'): print 'Found BGT' elif item.startswith('ADD'): print 'Found ADD' elif item.startswith('INC'): print 'Found INC' elif item.startswith('SUB'): print 'Found SUB' elif item.startswith('DEC'): print 'Found DEC' elif item.startswith('MUL'): print 'Found MUL' elif item.startswith('DIV'): print 'Found DIV' elif item.startswith('BEQ'): print 'Found BEQ' elif item.startswith('BLT'): print 'Found BLT' elif item.startswith('BR'): print 'Found BR' elif item.startswith('END'): print 'Found END' elif item.find(':') and item[(item.find(':') -1)].isalpha(): print 'Mya have found a label' else: print 'Not sure what I found'

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  • Python breaks for a certain amount

    - by Brian Cox
    All, I am not very good at explaining so i will let my comments do it! #this script is to calculate some of the times table up to 24X24 and also miss some out #Range of numbers to be calculated numbers=range(1,25) for i in numbers: for w in numbers: print(str(i)+"X"+str(w)+"="+str(i*w)) #here i want to break randomly (skip some out) e.g. i could be doing the 12X1,12X2 and then 12X5 i have no limit of skips. Update Sorry if this is not clear i want it to break from the inner loop for a random amount of times

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  • python and palindromes

    - by tekknolagi
    i recently wrote a method to cycle through /usr/share/dict/words and return a list of palindromes using my ispalindrome(x) method here's some of the code...what's wrong with it? it just stalls for 10 minutes and then returns a list of all the words in the file def reverse(a): return a[::-1] def ispalindrome(a): b = reverse(a) if b.lower() == a.lower(): return True else: return False wl = open('/usr/share/dict/words', 'r') wordlist = wl.readlines() wl.close() for x in wordlist: if not ispalindrome(x): wordlist.remove(x) print wordlist

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  • Python finding substring between certain characters using regex and replace()

    - by jCuga
    Suppose I have a string with lots of random stuff in it like the following: strJunk ="asdf2adsf29Value=five&lakl23ljk43asdldl" And I'm interested in obtaining the substring sitting between 'Value=' and '&', which in this example would be 'five'. I can use a regex like the following: match = re.search(r'Value=?([^&>]+)', strJunk) >>> print match.group(0) Value=five >>> print match.group(1) five How come match.group(0) is the whole thing 'Value=five' and group(1) is just 'five'? And is there a way for me to just get 'five' as the only result? (This question stems from me only having a tenuous grasp of regex) I am also going to have to make a substitution in this string such such as the following: val1 = match.group(1) strJunk.replace(val1, "six", 1) Which yields: 'asdf2adsf29Value=six&lakl23ljk43asdldl' Considering that I plan on performing the above two tasks (finding the string between 'Value=' and '&', as well as replacing that value) over and over, I was wondering if there are any other more efficient ways of looking for the substring and replacing it in the original string. I'm fine sticking with what I've got but I just want to make sure that I'm not taking up more time than I have to be if better methods are out there.

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  • Unable to open images with Python's Image.open()

    - by ensnare
    My code reads: import Image def generateThumbnail(self, width, height): """ Generates thumbnails for an image """ im = Image.open(self._file) When I call this function, I get an error: ? AttributeError: type object 'Image' has no attribute 'open' However in the console: import Image im = Image.open('test.jpg') I have no problem. Any ideas? Thanks!

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  • Error with python decorator

    - by Timmy
    I get this error object has no attribute 'im_func' with this class Test(object): def __init__(self, f): self.func = f def __call__( self, *args ): return self.func(*args) pylons code: class TestController(BaseController): @Test def index(self): return 'hello world'

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  • How to find links and modify an Html using BeautifulSoup in Python

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com">this if foo</a> <a href="http://www.bar.com">this if bar</a> </p> using BeautifulSoup, i would like to change this Html in: <p> <a href="http://www.foo.com">this if foo[1]</a> <a href="http://www.bar.com">this if bar[2]</a> </p> saving parsed links in a dictionary with a result like this: links_dict = {"1":"http://www.foo.com","2":"http://www.bar.com"} Is it possible to do this using BeautifulSoup? Any valid alternative?

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  • python list/dict property best practice

    - by jterrace
    I have a class object that stores some properties that are lists of other objects. Each of the items in the list has an identifier that can be accessed with the id property. I'd like to be able to read and write from these lists but also be able to access a dictionary keyed by their identifier. Let me illustrate with an example: class Child(object): def __init__(self, id, name): self.id = id self.name = name class Teacher(object): def __init__(self, id, name): self.id = id self.name = name class Classroom(object): def __init__(self, children, teachers): self.children = children self.teachers = teachers classroom = Classroom([Child('389','pete')], [Teacher('829','bob')]) This is a silly example, but it illustrates what I'm trying to do. I'd like to be able to interact with the classroom object like this: #access like a list print classroom.children[0] #append like it's a list classroom.children.append(Child('2344','joe')) #delete from like it's a list classroom.children.pop(0) But I'd also like to be able to access it like it's a dictionary, and the dictionary should be automatically updated when I modify the list: #access like a dict print classroom.childrenById['389'] I realize I could just make it a dict, but I want to avoid code like this: classroom.childrendict[child.id] = child I also might have several of these properties, so I don't want to add functions like addChild, which feels very un-pythonic anyway. Is there a way to somehow subclass dict and/or list and provide all of these functions easily with my class's properties? I'd also like to avoid as much code as possible.

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  • Python what's the data structure for triple data

    - by Paul
    I've got a set of data that has three attributes, say A, B, and C, where A is kind of the index (i.e., A is used to look up the other two attributes.) What would be the best data structure for such data? I used two dictionaries, with A as the index of each. However, there's key errors when the query to the data doesn't match any instance of A.

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  • python function that returns a function from list of functions

    - by thkang
    I want to make following function: 1)input is a number. 2)functions are indexed, return a function whose index matches given number here's what I came up with: def foo_selector(whatfoo): def foo1(): return def foo2(): return def foo3(): return ... def foo999(): return #something like return foo[whatfoo] the problem is, how can I index the functions (foo#)? I can see functions foo1 to foo999 by dir(). however, dir() returns name of such functions, not the functions themselves. In the example, those foo-functions aren't doing anything. However in my program they perform different tasks and I can't automatically generate them. I write them myself, and have to return them by their name.

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  • python feedparser with yahoo weather rss

    - by mudder
    I'm trying to use feedparser to get some data from yahoos weather rss. It looks like feed parser strips out the yweather namespace data: http://weather.yahooapis.com/forecastrss?w=24260013&u=c <yweather:condition text="Fair" code="34" temp="23" date="Wed, 19 May 2010 5:55 pm EDT" /> looks like feedparser is completely ignoring that. is there away to get it?

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  • Does my function right on python?

    - by Ali Ismayilov
    Write a function which takes a string argument, and creates and returns an Employee object containing details of the employee specified by the string. The string should be assumed to have the format 12345 25000 Consultant Bart Simpson The first three items in the line will be the payroll number, salary and job title and the rest of the line will be the name. There will be no spaces in the job title but there may be one or more spaces in the name. My function: def __str__(self): return format(self.payroll, "d") + format(self.salary, "d") + ' ' \ + self.jobtitle + self.name

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  • fetching from a specified index in a set using python

    - by tipu
    I'm using pagination on a values from a set. So what this results in is me needing to get values from x to x + 20 which can be in the middle of a set with 50,000 entries. Is it possible that I can fetch these values by grabbing by the space in the set? Would it make more sense to do result = [] my_dict = dict(very_big_set) for i in range(30000, 30020) result.append(my_dict[i])

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  • in python how to remove this \n from string or list

    - by pritesh modi
    this is my main string "action","employee_id","name" "absent","pritesh",2010/09/15 00:00:00 so after name coolumn its goes to new line but here i append to list a new line character is added and make it like this way data_list*** ['"action","employee_id","name"\n"absent","pritesh",2010/09/15 00:00:00\n'] here its append the new line character with absent but actually its a new line strarting but its appended i want to make it like data_list*** ['"action","employee_id","name","absent","pritesh",2010/09/15 00:00:00']

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  • Python and ReportLab: add a string at the end of every page

    - by user608341
    Hi peoples, I'm building a pdf document with reportlab, using the Paragraph class: doc = SimpleDocTemplate(response, leftMargin=lateral_margin, rightMargin=lateral_margin, topMargin=top_bottom_margin, bottomMargin=top_bottom_margin) Document = [] Document.append(Paragraph("bla bla bla bla", my_style)) doc.build(Document) Now I want to add at the end of every page a string, how can I do that??

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