Search Results

Search found 41048 results on 1642 pages for 'rails load order'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 163/1642 | < Previous Page | 159 160 161 162 163 164 165 166 167 168 169 170  | Next Page >

  • What technologies are needed to be a freelance web developer / designer targeting small businesses?

    - by Jason Wirth
    First off, I'm not looking for this answer: "learn PHP/MySQL, JQuery, HTML/CSS...." My background, I wear many hats, and do many things. Currently I manage investment accounts with a business partner who is also a friend. He happens to be attending business / law school perusing a joint JD and MBA. As a result, we're putting our into "coast", maintaining our current clients, but not acquiring more. Recently I've picked up some freelance graphic design / web development / online marketing side work (Photoshop, HTML/CSS, WordPress) through some personal networks. The work is enjoyable; now I'm thinking about expanding it into a larger business with these primary goals: augment my finances (I'm shooting for about $1,000-2,000 per mo.), learn new technologies, involve myself with meaningful work. As an entrepreneur I don't mind the aspects of running a business that hassle other freelancers... -- the marketing -- the billing -- etc. I'm considering targeting the small to middle market businesses and organizations where I can contribute in marketing, design, and development building projects from the ground up. Thus I'll have freedom to decide the specific technology (I won't have to work with an existing code base). What kinds of projects should I focus on? What technologies are a good fit for this style of work? For example: It might be fun to develop with Ruby on Rails. However, maybe a lot of projects would be rolling out e-commerce solutions. Thus, I should focus on PHP due to more shopping cart options, skipping ROR entirely.

    Read the article

  • Update Boolean attributes from another controller

    - by sidonstackoverflow
    I have Users controller and session controller . I want to update one user attribute from session controller . How can i do that ?? I am currently using rails 4.0 . Users controller: class UsersController < ApplicationController def show if Spec.find_by_user_id params[:id] @user = User.find(params[:id]) @spec = Spec.find_by_user_id params[:id] else if params[:id] == session[:id] redirect_to spec_edit_path(params[:id]) else redirect_to(community_index_path, {:notice => "Sorry there was an error"}) end end end def index end def new @user = User.new end def create @user = User.new(user_params) if @user.save flash[:success] = "Welcome buddy !" redirect_to @user else render 'new' end end private def user_params params.require(:user).permit(:name, :email, :password, :password_confirmation) end end Sessions Controller : class SessionsController < ApplicationController def new end def create user = User.find_by(email: params[:session][:email]) if user && user.authenticate(params[:session][:password]) session[:user_id] = user.id User.update(user.status, 'true') redirect_to root_url, :notice => 'You successfully logged in ' else flash.now[:error] = 'Invalid email/password combination' # Not quite right! render 'new' end end def destroy session[:user_id] = nil redirect_to root_url, :notice => 'You successfully logged out ' end end In above code when User logged in i just want to update my boolean column status at users table from sessions controller , but i failed . I am thankful to whom would like to answer my question !

    Read the article

  • Applying for job: how to showcase work done for (private) past clients?

    - by user33445566
    I want to apply for my first "real" (read: non-freelance) Ruby on Rails job. I've built several apps already. My best work (also the most logically complicated app) was for a freelance client, and I'd like to show it to potential employers. Only problem is: it isn't online anymore. And I've lost touch with the client. How can I include this work in my portfolio? About the app: It's a Facebook game. The client's business idea for this app was not the best. It was never going to make any money. I think it was kind of a vanity side project for him. The logo and graphics are nice-looking, though, and were designed by the client. I've actually spent a lot of time recently recoding most of the app, and adding a full test suite. I want to showcase the BDD / TDD skills I've acquired. I'm not very familiar with the etiquette (/law?) concerning this situation. Can I just put my new version of the app up at a free Heroku URL (perhaps with a "credits" section, where I credit the ideas and graphic designs to my former client)? NOTE: Again, this is just to show potential employers. I am not trying to market the app as my idea, or attract any users. Can I put some or all of the code on GitHub? What if I don't put the code up publicly, but merely send a tarball to potential employers? Do I need to ask permission from my former client (and what if he says no)? The last thing I want to do is get in any legal trouble, or offend people I'm trying get a job from. But I believe that my work and experience on this app are my highest recommendation for getting a job.

    Read the article

  • model association or controller?

    - by andybritton
    I'm trying to create a rails app that allows users to submit information about their pets. I've come to a point where my knowledge is limited and I don't know enough about what/how this could be done so I'm hoping this will be relatively easy to answer. At the moment I have a model called Pet, this model currently stores basic information like name, picture etc but it also holds more specific data like type, breed, date of birth etc. What I would like to be able to do is create a page that can match various records without having to be manually categorized if that makes sense so a users pet could be matched to other pets with the same breed, age etc. I've read about nested models as I understand this information could be submitted to 2 models in one form but I am not sure whether this could be done directly in a separate controller which would only be visible to users with pets in these matched "groups" if that makes sense. So in essence is it best practice to use 1 table to store all the information and just use a controller to match pets based on rows having the same values or would it be far simpler to have a form with a nested model and link 2 tables together? The main feature needs to be matching without a user having to create a group or categorize pets so the second model would need to add id's to an array instead of just creating more and more rows.

    Read the article

  • how to deal with controller mutations

    - by Milovan Zogovic
    During development process, things are constantly changing (especially in early phases). Requirements change, UI changes, everything changes. Pages that clearly belonged to specific controller, mutated to something completely different in the future. For example. Lets say that we have website for managing Projects. One page of the website was dedicated to managing existing, and inviting new members of specific project. Naturally, I created members controller nested under projects which had proper responsibility. Later in the development, it turned out that it was the only page that was "configuring the project" in some way, so additional functionalities were added to it: editing project description setting project as a default ... In other words, this page changed its primary responsibility from managing project members to managing project itself. Ideally, this page should be moved to "edit" action of "projects" controller. That would mean that all request and controller specs need to refactored too. Is it worth the effort? Should it be done? Personally, I am really starting to dislike the 1-1 relationship between views and controllers. Its common situation that we have 1 page (view) that handles 2 or more different resources. I think we should have views completely decoupled from controllers, but rails is giving us hard time to achieve this. I know that AJAX can be used to solve this issue, but I consider it an improvisation. Is there some other kind of architecture (other than MVC) that decouples views from controllers?

    Read the article

  • Social Network ( Help) [on hold]

    - by brunocascio
    I am in a great "problem" so to speak , and I need opinions to decide. The problem is to create a social network without knowing the number of users who use it (but if thinking if they were sufficient ) . The question is which language and framework to use .... I do not mind having to learn new technologies and / or languages ??. I am among PHP ( Laravel - Symfony - other? ) Ruby ( Ruby on Rails 4? ) Javascript ( Ember , express, locomotive , other? ) Python ( Django ) Java ( Grails , Play, other?) I have experience in both PHP and frameworks. In Symfony developed part of it, but I got tired having to do a thousand configurations for all . I know very little about Ruby , but I saw very easy . I do not know are saying the performance. Javascript costs me to get used to their paradigm , and do not know if at all sure to cover everything with Javascript. Django and python ( very poor knowledge ) Java , experience in data structure and android , but not web . Regarding the / s databases: In my head I have to MongoDB and costs change of opinion by another database with respect to documentation and EASE performance . But .......... frameworks have no support at all clear . I also thought of mixing technologies for using a tecnlogía backend and the frontend other. As I read in the new social network Origo . They use Symfony for REST and javascript for the frontend . ( Backbone , Underscore and RequireJS ) What do you recommend me ?

    Read the article

  • How can I load style resources from a dynamically loaded Silverlight application (XAP)?

    - by Tom
    I've followed Tim Heuer's video for dynamically loading other XAP's (into a 'master' Silverlight application), as well as some other links to tweak the loading of resources and am stuck on the particular issue of loading style resources from within the dynamically loaded XAP (i.e. the contents of Assets\Styles.xaml). When I run the master/hosting applcation, it successfully streams the dynamic XAP and I can read the deployment info etc. and load the assembly parts. However, when I actuall try to create an instance of a form from the Dynamic XAP, it fails with Cannot find a Resource with the Name/Key LayoutRootGridStyle which is in it's Assets\Styles.xaml file (it works if I run it directly so I know it's OK). For some reason these don't show up as application resources - not sure if I've totally got the wrong end of the stick, or am just missing something? Code snippet below (apologies it's a bit messy - just trying to get it working first) ... '' # Here's the code that reads the dynamic XAP from the web server ... '' #... wCli = New WebClient AddHandler wCli.OpenReadCompleted, AddressOf OpenXAPCompleted wCli.OpenReadAsync(New Uri("MyTest.xap", UriKind.Relative)) '' #... '' #Here's the sub that's called when openread is completed '' #... Private Sub OpenXAPCompleted(ByVal sender As Object, ByVal e As System.Net.OpenReadCompletedEventArgs) Dim sManifest As String = New StreamReader(Application.GetResourceStream(New StreamResourceInfo(e.Result, Nothing), New Uri("AppManifest.xaml", UriKind.Relative)).Stream).ReadToEnd Dim deploymentRoot As XElement = XDocument.Parse(sManifest).Root Dim deploymentParts As List(Of XElement) = _ (From assemblyParts In deploymentRoot.Elements().Elements() Select assemblyParts).ToList() Dim oAssembly As Assembly = Nothing For Each xElement As XElement In deploymentParts Dim asmPart As AssemblyPart = New AssemblyPart() Dim source As String = xElement.Attribute("Source").Value Dim sInfo As StreamResourceInfo = Application.GetResourceStream(New StreamResourceInfo(e.Result, "application/binary"), New Uri(source, UriKind.Relative)) If source = "MyTest.dll" Then oAssembly = asmPart.Load(sInfo.Stream) Else asmPart.Load(sInfo.Stream) End If Next Dim t As Type() = oAssembly.GetTypes() Dim AppClass = (From parts In t Where parts.FullName.EndsWith(".App") Select parts).SingleOrDefault() Dim mykeys As Array If Not AppClass Is Nothing Then Dim a As Application = DirectCast(oAssembly.CreateInstance(AppClass.FullName), Application) For Each strKey As String In a.Resources.Keys If Not Application.Current.Resources.Contains(strKey) Then Application.Current.Resources.Add(strKey, a.Resources(strKey)) End If Next End If Dim objectType As Type = oAssembly.GetType("MyTest.MainPage") Dim ouiel = Activator.CreateInstance(objectType) Dim myData As UIElement = DirectCast(ouiel, UIElement) Me.splMain.Children.Add(myData) Me.splMain.UpdateLayout() End Sub '' #... '' # And here's the line that fails with "Cannot find a Resource with the Name/Key LayoutRootGridStyle" '' # ... System.Windows.Application.LoadComponent(Me, New System.Uri("/MyTest;component/MainPage.xaml", System.UriKind.Relative)) '' #... any thoughts?

    Read the article

  • rubygem Twitter4R Issues

    - by Leonardo Dario Perna
    Hi everyone, I'm trying to get started with twitter4r but I'm having some issues: Why I can't load the gem in IRB? $ sudo gem install twitter4r Successfully installed twitter4r-0.3.2 1 gem installed Installing ri documentation for twitter4r-0.3.2... Installing RDoc documentation for twitter4r-0.3.2... $ irb require 'rubygems' = false require 'twitter4r' LoadError: no such file to load -- twitter4r from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from (irb):2 I've downloaded the http://files.rubyforge.vm.bytemark.co.uk/twitter4r/twitter4rails.post-0_2_4.zip app and it works only with twitter4r-0.2.4 and NOT with last version twitter4r-0.3.2: $ script/server ./script/../config/boot.rb:26:Warning: Gem::SourceIndex#search support for String patterns is deprecated, use #find_name = Booting Mongrel (use 'script/server webrick' to force WEBrick) = Rails application starting on http://0.0.0.0:3000 = Call with -d to detach = Ctrl-C to shutdown server ** Starting Mongrel listening at 0.0.0.0:3000 ** Starting Rails with development environment... Exiting /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require': no such file to load -- twitter/rails (MissingSourceFile) from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:495:in `require' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:342:in `new_constants_in' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:495:in `require' from /Users/leonardodarioperna/Projects/Kaaaki/marrakaaaki/ twitter4rails.post-0_2_4/config/environment.rb:64 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/activesupport-1.4.2/lib/active_support/ dependencies.rb:495:in `require' ... 23 levels... from /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ ruby/gems/1.8/gems/rails-1.2.3/lib/commands/server.rb:39 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3 Last thing, in the /config/environment.rb I need to specify: RAILS_GEM_VERSION = '1.2.3' unless defined? RAILS_GEM_VERSION if I use my last rails version: RAILS_GEM_VERSION = '2.3.4' unless defined? RAILS_GEM_VERSION I get this error: $ script/server -p3002 = Booting Mongrel = Rails 2.3.4 application starting on http://0.0.0.0:3000 /Library/Ruby/Site/1.8/rubygems.rb:280:in `activate': can't activate activerecord (= 1.15.6, runtime) for [], already activated activerecord-2.3.4 for ["rails-2.3.4"] (Gem::LoadError) from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:35:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:156:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:521:in `new_constants_in' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:156:in `require' from /Library/Ruby/Gems/1.8/gems/twitter4r-0.2.4/lib/twitter/rails.rb: 6 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.4/lib/ active_support/dependencies.rb:156:in `require' ... 8 levels... from /Library/Ruby/Gems/1.8/gems/rails-2.3.4/lib/commands/server.rb: 84 from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `gem_original_require' from /Library/Ruby/Site/1.8/rubygems/custom_require.rb:31:in `require' from script/server:3 And that's all :-) Thank you!

    Read the article

  • Complex Rails queries across multiple tables, unions, and will_paginate. Solved.

    - by uberllama
    Hi folks. I've been working on a complex "user feed" type of functionality for a while now, and after experimenting with various union plugins, hacking named scopes, and brute force, have arrived at a solution I'm happy with. S.O. has been hugely helpful for me, so I thought I'd post it here in hopes that it might help others and also to get feedback -- it's very possible that I worked on this so long that I walked down an unnecessarily complicated road. For the sake of my example, I'll use users, groups, and articles. A user can follow other users to get a feed of their articles. They can also join groups and get a feed of articles that have been added to those groups. What I needed was a combined, pageable feed of distinct articles from a user's contacts and groups. Let's begin. user.rb has_many :articles has_many :contacts has_many :contacted_users, :through => :contacts has_many :memberships has_many :groups, :through => :memberships contact.rb belongs_to :user belongs_to :contacted_user, :class_name => "User", :foreign_key => "contacted_user_id" article.rb belongs_to :user has_many :submissions has_many :groups, :through => :submissions group.rb has_many :memberships has_many :users, :through => :memberships has_many :submissions has_many :articles, :through => :submissions Those are the basic models that define my relationships. Now, I add two named scopes to the Article model so that I can get separate feeds of both contact articles and group articles should I desire. article.rb # Get all articles by user's contacts named_scope :by_contacts, lambda {|user| {:joins => "inner join contacts on articles.user_id = contacts.contacted_user_id", :conditions => ["articles.published = 1 and contacts.user_id = ?", user.id]} } # Get all articles in user's groups. This does an additional query to get the user's group IDs, then uses those in an IN clause named_scope :by_groups, lambda {|user| {:select => "DISTINCT articles.*", :joins => :submissions, :conditions => {:submissions => {:group_id => user.group_ids}}} } Now I have to create a method that will provide a UNION of these two feeds into one. Since I'm using Rails 2.3.5, I have to use the construct_finder_sql method to render a scope into its base sql. In Rails 3.0, I could use the to_sql method. user.rb def feed "(#{Article.by_groups(self).send(:construct_finder_sql,{})}) UNION (#{Article.by_contacts(self).send(:construct_finder_sql,{})})" end And finally, I can now call this method and paginate it from my controller using will_paginate's paginate_by_sql method. HomeController.rb @articles = Article.paginate_by_sql(current_user.feed, :page => 1) And we're done! It may seem simple now, but it was a lot of work getting there. Feedback is always appreciated. In particular, it would be great to get away from some of the raw sql hacking. Cheers.

    Read the article

  • How to use will_paginate with a nested resource in Rails?

    - by Sue Petersen
    I'm new to Rails, and I'm having major trouble getting will_paginate to work with a nested resource. I have two models, Statement and Invoice. will_paginate is working on Statement, but I can't get it to work on Invoice. I know I'd doing something silly, but I can't figure it out and the examples I've found on google won't work for me. statement.rb class Statement < ActiveRecord::Base has_many :invoices def self.search(search, page) paginate :per_page => 19, :page => page, :conditions => ['company like ?', "%#{search}%"], :order => 'date_due DESC, company, supplier' end end statements_controller.rb <irrelevant code clipped for readability> def index #taken from the RAILSCAST 51, will_paginate podcast @statements = Statement.search(params[:search], params[:page]) end I call this in the view like so, and it works: <%= will_paginate @statements %> But I can't figure out how to get it to work for Invoices: invoice.rb class Invoice < ActiveRecord::Base belongs_to :statement def self.search(search, page) paginate :per_page => 19, :page => page, :conditions => ['company like ?', "%#{search}%"], :order => 'employee' end end invoices_controller.rb class InvoicesController < ApplicationController before_filter :find_statement #TODO I can't get will_paginate to work w a nested resource def index #taken from the RAILSCAST 51, will_paginate podcast @invoices = Invoice.search(params[:search], params[:page]) end def find_statement @statement_id = params[:statement_id] return(redirect_to(statements_url)) unless @statement_id @statement = Statement.find(@statement_id) end end And I try to call it like this: <%= will_paginate (@invoices) % The most common error message, as I play with this, is: "The @statements variable appears to be empty. Did you forget to pass the collection object for will_paginate?" I don't have a clue what the problem is, or how to fix it. Thanks for any help and guidance!

    Read the article

  • My Rails app is returning HTTP 500 for all its URLs, but nothing shows up in the log file. How can I

    - by mipadi
    I have a Rails app that is running on a production server with Apache and Phusion Passenger. The app works fine locally when using Mongrel, but whenever I try to load a URL on the production server, it returns HTTP 500. I know the server is working properly, because I can get the static elements of the application (e.g., JavaScript files, stylesheets, images) just fine. I've also checked the Passenger status and it is loading the app (it must be, since the app's 500 Internal Server Error page is returned, not just the default Apache one). Also, when I load the app via script/console production and do something like app.get("/"), 500 is also returned. The problem is that there is nothing in the log files to indicate the problem. production.log is empty. The Apache error logs show no problems with Apache, either. I'm stumped as to what's going on and I'm not sure how to diagnose the problem. I know I may have been a bit vague, but can anyone give a suggestion on what the problem may be? Or at least a way I can go about diagnosing it?

    Read the article

  • Can .NET load and parse a properties file equivalent to Java Properties class?

    - by Tai Squared
    Is there an easy way in C# to read a properties file that has each property on a separate line followed by an equals sign and the value, such as the following: ServerName=prod-srv1 Port=8888 CustomProperty=Any value In Java, the Properties class handles this parsing easily: Properties myProperties=new Properties(); FileInputStream fis = new FileInputStream (new File("CustomProps.properties")); myProperties.load(fis); System.out.println(myProperties.getProperty("ServerName")); System.out.println(myProperties.getProperty("CustomProperty")); I can easily load the file in C# and parse each line, but is there a built in way to easily get a property without having to parse out the key name and equals sign myself? The C# information I have found seems to always favor XML, but this is an existing file that I don't control and I would prefer to keep it in the existing format as it will require more time to get another team to change it to XML than parsing the existing file.

    Read the article

  • Load balancing a php program to support increasing users?

    - by Dave
    I have a php program that has been written keeping in mind a single server, so there are inherent limitation to how much it can handle. For example, the developer says that his current webhosting service provides him with "50 mysql connections" which he interprets as that only 50 people can be simultaneously logged onto it. What do we need to do if we want to scale it up so it can handle a load of 500 or more? How can we adapt this program to a "load balancer" with minimal changes? The application is writen in php and uses mysql.

    Read the article

  • Passing params in rails... Breakthrough in understanding params, aka, the "aha" moment

    - by Brian McDonough
    I have a simple has_many belongs_to relationship and I want to include the parent object for the view of the belongs_to model and I have had some success, but I want it to work better. class Submission < ActiveRecord::Base belongs_to :user belongs_to :contest end class Contest < ActiveRecord::Base belongs_to :user has_many :submissions, :dependent => :destroy end In the case that works, I pass contest_id to submissions by placing it in the url: <%= link_to 'Submit Contest Entry', new_submission_path(:contest_id => @contest.id), :class => 'btn btn-primary btn-large mleft10' %> So that, combined with a hidden_field: <%= f.hidden_field :contest_id %> And a find_contest method in the controller (called with a before_filter): def find_contest #the next line is giving the error (line 76) @contest = Contest.find(params[:submission][:contest_id]) end Makes it work for submissions/new, but how do I add a find to the controller that just works across more than that one page, like if I want to access in show and index. Right now, I get an error: Started GET "/submissions?contest_id=5" for 127.0.0.1 at 2012-12-01 16:01:45 -0800 Processing by SubmissionsController#index as HTML Parameters: {"contest_id"=>"5"} User Load (0.3ms) SELECT "users".* FROM "users" WHERE "users"."id" = 2 ORDER BY users.created_at DESC LIMIT 1 Completed 500 Internal Server Error in 37ms NoMethodError (undefined method `[]' for nil:NilClass): app/controllers/submissions_controller.rb:76:in `find_contest' [edited] Adding show action for submissions: before_filter :find_contest, :except => [:index, :show, :edit, :update, :destroy] def find_contest @contest = Contest.find(params[:submission][:contest_id]) end def show contest_id = @submission.contest_id @submission = @commentable = Submission.find(params[:id]) @comments = @commentable.comments.order(:created_at).reverse respond_to do |format| format.html # show.html.erb format.json { render :json => @submission } end end

    Read the article

  • How would I order a table by the number of matching params in the where clause of an sql statement?

    - by Eitan
    I'm writing sql to search a database by a number of parameters. How would I go about ordering the result set by the items that match the most parameters in the where clause. For example: SELECT * FROM users WHERE username = 'eitan' OR email = '[email protected]' OR company = 'eitan' Username | email | company 1) eitan | [email protected] | blah 2) eitan | [email protected] | eitan 3) eitan | [email protected] | blah should be ordered like: 2, 3, 1. Thanks. (ps the query isn't that easy, has a lot of joins and a lot of OR's in the WHERE) Eitan

    Read the article

  • Can't log in with a valid password using Authlogic and Ruby on Rails?

    - by kbighorse
    We support a bit of an unusual scheme. We don't require a password on User creation, and use password_resets to add a password to the user later, on demand. The problem is, once a password is created, the console indicates the password is valid: user.valid_password? 'test' = true but in my UserSessions controller, @user_session.save returns false using the same password. What am I not seeing? Kimball UPDATE: Providing more details, here is the output when saving the new password: Processing PasswordResetsController#update (for 127.0.0.1 at 2011-01-31 14:01:12) [PUT] Parameters: {"commit"="Update password", "action"="update", "_method"="put", "authenticity_token"="PQD4+eIREKBfHR3/fleWuQSEtZd7RIvl7khSYo5eXe0=", "id"="v3iWW5eD9P9frbEQDvxp", "controller"="password_resets", "user"={"password"="johnwayne"}} The applicable SQL is: UPDATE users SET updated_at = '2011-01-31 22:01:12', crypted_password = 'blah', perishable_token = 'blah', password_salt = 'blah', persistence_token = 'blah' WHERE id = 580 I don't see an error per se, @user_session.save just returns false, as if the password didn't match. I skip validating passwords in the User model: class User < ActiveRecord::Base acts_as_authentic do |c| c.validate_password_field = false end Here's the simplified controller code: def create logger.info("SAVED SESSION? #{@user_session.save}") end which outputs: Processing UserSessionsController#create (for 127.0.0.1 at 2011-01-31 14:16:59) [POST] Parameters: {"commit"="Login", "user_session"={"remember_me"="0", "password"="johnwayne", "email"="[email protected]"}, "action"="create", "authenticity_token"="PQD4+eIREKBfHR3/fleWuQSEtZd7RIvl7khSYo5eXe0=", "controller"="user_sessions"} User Columns (2.2ms) SHOW FIELDS FROM users User Load (3.7ms) SELECT * FROM users WHERE (users.email = '[email protected]') ORDER BY email ASC LIMIT 1 SAVED SESSION? false CACHE (0.0ms) SELECT * FROM users WHERE (users.email = '[email protected]') ORDER BY email ASC LIMIT 1 Redirected to http://localhost:3000/login Lastly, the console indicates that the new password is valid: $ u.valid_password? 'johnwayne' = true Would love to do it all in the console, is there a way to load UserSession controller and call methods directly? Kimball

    Read the article

  • htaccess rewriterule with order in url

    - by NRoscoe
    I'm trying to put together a rewrite rule for an Apache server. It should take 'order/###' and change it to 'order.php?id=###'. For some reason it's rewriting as 'order.php/###'. If I change it to anything other than 'order' my rule works fine. Anyone know what's going on? My .htaccess file looks like this: RewriteEngine on ## tighten host RewriteCond %{HTTP_HOST} !^mydomain\.com$ [NC] RewriteRule .? http://mydomain.com%{REQUEST_URI} [R=301,L] ## Dynamic Pages RewriteRule ^order/([0-9]+)/?$ order.php?code=$1 [L,NC] ## Static Page Redirects RewriteRule ^prices$ /prices.php [L,NC] RewriteRule ^examples$ /examples.php [L,NC] I have no access to the httpd main server config file on the live server.

    Read the article

  • How to solve High Load average issue in Linux systems?

    - by RoCkStUnNeRs
    The following is the different load with cpu time in different time limit . The below output has parsed from the top command. TIME LOAD US SY NICE ID WA HI SI ST 12:02:27 208.28 4.2%us 1.0%sy 0.2%ni 93.9%id 0.7%wa 0.0%hi 0.0%si 0.0%st 12:23:22 195.48 4.2%us 1.0%sy 0.2%ni 93.9%id 0.7%wa 0.0%hi 0.0%si 0.0%st 12:34:55 199.15 4.2%us 1.0%sy 0.2%ni 93.9%id 0.7%wa 0.0%hi 0.0%si 0.0%st 13:41:50 203.66 4.2%us 1.0%sy 0.2%ni 93.8%id 0.8%wa 0.0%hi 0.0%si 0.0%st 13:42:58 278.63 4.2%us 1.0%sy 0.2%ni 93.8%id 0.8%wa 0.0%hi 0.0%si 0.0%st Following is the additional Information of the system? cat /proc/cpuinfo processor : 0 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz stepping : 10 cpu MHz : 1992.000 cache size : 6144 KB physical id : 0 siblings : 4 core id : 0 cpu cores : 4 apicid : 0 initial apicid : 0 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe lm constant_tsc arch_perfmon pebs bts pni monitor ds_cpl vmx est tm2 ssse3 cx16 xtpr dca sse4_1 lahf_lm bogomips : 4658.69 clflush size : 64 power management: processor : 1 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz stepping : 10 cpu MHz : 1992.000 cache size : 6144 KB physical id : 0 siblings : 4 core id : 1 cpu cores : 4 apicid : 1 initial apicid : 1 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe lm constant_tsc arch_perfmon pebs bts pni monitor ds_cpl vmx est tm2 ssse3 cx16 xtpr dca sse4_1 lahf_lm bogomips : 4655.00 clflush size : 64 power management: processor : 2 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz stepping : 10 cpu MHz : 1992.000 cache size : 6144 KB physical id : 0 siblings : 4 core id : 2 cpu cores : 4 apicid : 2 initial apicid : 2 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe lm constant_tsc arch_perfmon pebs bts pni monitor ds_cpl vmx est tm2 ssse3 cx16 xtpr dca sse4_1 lahf_lm bogomips : 4655.00 clflush size : 64 power management: processor : 3 vendor_id : GenuineIntel cpu family : 6 model : 23 model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz stepping : 10 cpu MHz : 1992.000 cache size : 6144 KB physical id : 0 siblings : 4 core id : 3 cpu cores : 4 apicid : 3 initial apicid : 3 fdiv_bug : no hlt_bug : no f00f_bug : no coma_bug : no fpu : yes fpu_exception : yes cpuid level : 13 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe lm constant_tsc arch_perfmon pebs bts pni monitor ds_cpl vmx est tm2 ssse3 cx16 xtpr dca sse4_1 lahf_lm bogomips : 4654.99 clflush size : 64 power management: Memory: total used free shared buffers cached Mem: 2 1 1 0 0 0 Swap: 5 0 5 let me know why the system is getting abnormally this much high load?

    Read the article

  • Order a List (C#) by many fields?

    - by Esabe
    Hi everyone, I want to order a List of objects in C# by many fields, not just by one. For example, let's suppose I have a class called X with two Attributes, A and B, and I have the following objects, in that order: object1 = A = "a", B = "h" object2 = A = "a", B = "c" object3 = A = "b", B = "x" object4 = A = "b", B = "b" and I want to order the list by A attribute first, and when they are equals, by B element, so the order would be: "a" "c" "a" "h" "b" "b" "b" "x" As far as I know, the OrderBy method order by one parameter. Question: How can I order a C# List by more than one field? Thank you very much

    Read the article

  • Proliant ML350 Won't Load Windows

    - by Mike
    I have a HP Proliant ML350 G4 running Windows 2003 Server Std Edition that will not load Windows on boot. It gave me a BSOD while running a recent Windows update and has not been able to boot since. The BSOD was a generic error, "Hardware Fault. Contact vendor." I am not getting any errors when the machine boots--it just hangs with a black screen when Windows starts to load. The machine will not boot into safe mode either--it gets stuck after beginning to load drivers. When trying to load the Windows recovery console I get the message that Windows cannot find any hard disks on the machine. This, despite having to load the driver for my storage controller. The HP Smart Start diagnostics finds no problems with my hard disks nor anything else. What should I try next? Mainly, I just want to be able to pull the data off my hard disks.

    Read the article

  • Performance Drop Lingers after Load [closed]

    - by Charles
    Possible Duplicate: How do you do Load Testing and Capacity Planning for Databases I'm noticing a drop in performance after subsequent load tests. Although our cpu and ram numbers look fine, performance seems to degrade over time as sustained load is applied to the system. If we allow more time between the load tests, the performance gets back to about 1,000 ms, but if you apply load every 3 minutes or so, it starts to degrade to a point where it takes 12,000 ms. None of the application servers are showing lingering apache processes and the number of database connections cools down to about 3 (from a sustained 20). Is there anything else I should be looking out for here?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 159 160 161 162 163 164 165 166 167 168 169 170  | Next Page >