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  • Instantiating class by string using PHP 5.3 namespaces

    - by Kevin
    I can't get around an issue instantiating a new class by using a string variable and PHP 5.3. namespaces. For example, this works; $class = 'Reflection'; $object = new $class(); However, this does not; $class = '\Application\Log\MyClass'; $object = new $class(); A fatal error gets thrown stating the class cannot be found. However it obviously can be instantiated if using the FQN i.e.; $object = new \Application\Log\MyClass; I've found this to be aparrent on PHP 5.3.2-1 but not not in later versions. Is there a work around for this?

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  • Stopping an if clause along with the whole PHP script, but not HTML

    - by user626816
    Hello there, I've been having this problem for around an hour, and have searched the internet for answers. I've checked the PHP documentation, looked around, Googled, nothing. Anyways, my problem is that after I try to validate something (and it's wrong), if I use exit; it will also stop the HTML after. Here's what I'm talking about: if ($_POST['exampleEmail'] == "") { echo "Please enter an e-mail."; //Now I want only the PHP script to stop, however... exit; //If I use exit, then the HTML after this script (footer) doesn't show. } If anyone can help, please do. I've tried using break, but to no avail, since it's only for loops and switches. If there is a better/more correct (or simply correct if this is the wrong way), please share. I've had this problem in the past, and I just used exit then. Thanks.

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  • PHP exec error, possibly MAMP using ghostscript

    - by user1762526
    I have been trying to use ghostscript in PHP to convert pdf files to images (png, jpg). I don't really care as long as they are images. This is the code that I used. exec("gs -sDEVICE=jpeg -sOutputFile=/Applications/Mamp/htdocs/cover.jpg -r144 /Applications/Mamp/htdocs/test.pdf"); When I enter the exact same thing, without the exec and quotes obviously, into the command line it does exactly what I want. However, when I run the php file nothing happens. I am using a MAMP server and the server seems to work fine, whenever I run another file with it I have no issues. Anyone have any ideas why it might not execute right?

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  • Using PHP's $_COOKIE to create cookie.txt for cURL

    - by boogie
    Hi, I'm running Drupal and Mediawiki on my server under the same domain. They are connected to each other with extensions/modules. Meaning if I log in to Mediawiki, it automatically logs into Drupal also. Mediawiki has some extensions that filter the information shown on the page. What I want to do is to show that filtered information from Mediawiki on my Drupal page. I'm trying to fetch the data with PHP cURL, but I'm not able to force it to use the login information. How can I convert PHP's $_COOKIE into cURL cookie.txt format? I suppose after that I'm able to fetch the data from Mediawiki with the right permissions. This is what print_r($_COOKIE) outputs: [wiki_session] = gg05lhd6pcfs5g6iokhoo0gue7 [wikiUserName] = WikiSysop [wikiLoggedOut] = 20100510110913 [wikiUserID] = 1 [wikiToken] = 52cdb19a7b4a43e5a2f86939e4f54941 Thanks for any help!

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • Pretty-print HTML via PHP without validation?

    - by brianjcohen
    I'd like to automatically pretty-print (indentation, mostly) the HTML output that my PHP scripts generate. I've been messing with Tidy, but have found that in its efforts to validate and clean my code, Tidy is changing way too much. I know Tidy's intentions are good but I'm really just looking for an HTML beautifier. Is there a simpler library out there that can run in PHP and just do the pretty-printing? Or, is there a way to configure Tidy to skip all the validation stuff and just beautify?

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  • Most reliable method for uploading files in PHP w/ progress bar

    - by vanneto
    Hello everyone, I am interested in finding the most reliable method for uploading files in PHP. I need a progress bar with the upload. I have tried SWFUpload but it randomly issues an I/O Error. Even if the same file is uploaded sometimes there is an error and sometimes there is not. I have configured all the necessary INI/Mysql/Apache directives to accept large file uploads. So, I am looking for alternatives as a Flash based solution has not worked. Would Java be more relirable? I have also looked into PHP with APC. I definitely cannot afford these random errors, so any help on reliable software / suggestions on how to minimize them would be appreciated. Thank you.

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  • Any valid use of goto in PHP?

    - by nikic
    I know, there are other questions about the goto statement introduced in PHP 5.3. But I couldn't find any decent answer in there, all were of the type "last resort", "xkcd", "evil", "bad", "EVIL!!!". But no valid example. Only statements that there aren't any uses. Or statements that there are some rare use cases (again, without examples). So, the question is: "Which are the valid uses of goto in PHP". Answers for "Is goto evil" are not welcome and will get downvoted. Thanks :) Or does somebody have a link to an RFC where the decision is explained - I couldn't find one.

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  • A PHP Function that verify code language

    - by tymc
    Hi, I have a form with 2 textareas; the first one allows user to send HTML Code, the second allows to send CSS Code. I have to verify with a PHP function, if the language is correct. If the language is correct, for security, i have to check that there is not PHP code or SQL Injection or whatever. What do you think ? Is there a way to do that ? Where can I find this kind of function ? Is "HTML Purifier" http://htmlpurifier.org/ a good solution ?

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  • retrieve value from db in php

    - by wangdoo
    I have a db in which 1 column value will be always null.I want it to pass to next page but it is passing all values of other column except this null value column. This is my code $row=mysql_query("SELECT * FROM `thirdpartycategorymaster` WHERE ISNULL(`delete`)"); while($row1=mysql_fetch_array($row)) { <td><b><a href="catdel.php?head1=<?php echo $row1['ThirdPartyCategoryName'] . '&&msg1=' . $row1['ThirdPartyCategoryID'] . '&&ctdel=' . $row1['delete']; ?> ">Delete</a></b></td> This my db table ThirdPartyCategoryID ThirdPartyCategoryName delete 29 ecommerce NULL

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  • All PHP files getting hacked

    - by nsearle
    Hey All, Like always, just want to say thank you for all of the help and input in advance. I have a particular site that I am the web developer for and am running into a unique problem. It seems that somehow something is getting into every single PHP file on my site and adding some malware code. I have deleted the code from every page multiple times and changed FTP and DB passwords, but to no avail. The code that is added looks like this - eval(base64_decode(string)) - which the string is 3024 characters. Not sure if anyone else has ran into this problem or if any one has ideas on how I can secure my php code up. Thanks again.

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Passing a String from PHP to a JavaScript function

    - by user635614
    Hello. am trying to write a code to pass a php string when clicked on the table : <?php . . . echo("<td onclick = 'print_("$file[$i]->Name");' >". $files[$i]->Name."</td>"); ... ?> where files[] is an array, and each element is a class with Name as a String, and it is put in a ''for'' loop, Am trying to pass it to a JavaScript function where i need the name there,and it's not working,i tried passing the i variable and it was passed correctly so i thought there should be a special syntax for dealing with strings... function print_(var x) { alert(x);}

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  • Help with PHP and associative arrays

    - by errata
    Hello. I have to do a simple calculator in php based on user's input and choice from select field, something like this: <?php $a = $_GET['a']; $b = $_GET['b']; $array = array( "option1" => 0.1, "option2" => 0.15, "option3" => 0.3, "option4" => 3, "option5" => 3, "option6" => 16, "option7" => 16, "option8" => 16 ); echo "<form action='calc.php' method='get'>"; echo "<input type='text' name='a' value='".$a."'> of "; echo "<select name='b'>"; foreach ($array as $k => $v) { echo "<option value='".$v."'>".$k."</option>"; } echo "</select> "; echo "<input type='submit' value='='> "; $total_volume = $a * $b; echo $total_volume; echo "</form>"; ?> Well, for now everything works fine, but the idea is that after user submits form, the page reloads with sent amount in input field and selected option which user actually selected... First thing is easy: I just put value="a" in my input field, but I'm not sure how to make a selected option in <select> field??? I started with this: foreach ($array as $k => $v) { echo "<option value='".$v."'"; if ($b == $v) { echo " selected "; } echo ">".$k."</option>"; } ...but this is obviously not working as expected... Please help me with this easy one :) Thanks!

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  • Using PHP interfaces in Codeigniter

    - by John Stewart
    I am trying to find out how can I used PHP interfaces in my MVC design. I want to make sure that the design enforces an interface so that any new module would follow that. For example: <?php interface BaseAPI { public function postMessage($msg); } class ServiceAPI implements BaseAPI { public function postMessage($msg) { return $msg; } } class Service_Two_API implements BaseAPI { public function postMessage($msg) { return "can't do this: ".$msg; } } ?> I want to do this in CI. Is it possible? how should I design it?

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  • PHP Zip Archive sporadically creating multiple files

    - by user516558
    I have a PHP script (running PHP 5.2 on Apache 2.2) that creates a zip archive of files for a user to download. Everything seems to work just fine; the only issue I have is that periodically multiple files will be created before the ZIP archive is successfully finished. Example: archive-name.zip archive-name.zip.a09600 archive-name.zip.b09600 archive-name.zip.c09600 This does not happen every single time; only periodically - the file is still created but sometimes these extra 'files' are left on the server after it finishes. The code that creates the ZIP archive is as follows: $zip_archive = new ZipArchive(); $zip_archive->open($archiveFullName,ZIPARCHIVE::CREATE); if(!file_exists($archiveFullName)) { foreach ($completed_file_arr as $zip_file) { $isFiller = substr($zip_file,-8) == "_err.txt"; if(!$isFiller) { $zip_archive->addFile($zip_file,$localname); } else $zip_archive->addFromString ($zip_file, "The requested source file could not be found."); } } while(!$zip_archive->close()) sleep(1); //ensure that the ZIP file finishes closing

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  • retrieved upload images in php

    - by hunter
    i want to retrieve image from client (ipod) programmed in objective c i use the following code $TARGET_PATH = "pics/"; $image = $_FILES['photo']; $TARGET_PATH =$TARGET_PATH . basename( $_FILES['photo']['name']); $TARGET_PATH =$TARGET_PATH.".jpg"; if(file_exists($TARGET_PATH)) { $TARGET_PATH =$TARGET_PATH .uniqid() . ".jpg"; } if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { $TARGET_PATH="http://www.".$_SERVER["SERVER_NAME"]."/abc/".$TARGET_PATH; echo $TARGET_PATH; echo "image upload successfully";} else{ echo "could not upload image"; } this code upload five to six images successfully and after that it gives me error i.e Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 42 Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 53 could not upload image

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  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

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