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  • Visual Basic: Newbie questions.

    - by Omega
    Hello there. I am starting to learn visual basic. So far, it is quite simple and easy to use. I am liking it! Anyway, I want to make applications a little bit more complex. So far I have done very silly things. I would appreciate if you could help me with these: How do I open a new window (form)? Maybe I click a button on my main form and another form pops up. How do I "deactivate" the main form while the new form is running? (if I try to click the main form, an error sound plays) So my second form has a text field and a "OK" button. If I click it, the second form closes activating the main form again. I want to "pass" the text in the text field from the second form to the first one. How do I do that? Thank you, I am enjoying this new programming environment (didn't use Visual Studio much before)

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  • Create variables for unknown amount of arguments?

    - by user347600
    Working on an rsync script and the portion below is in a for loop. What I want to achieve is assign a variable to every arguement after 3. Just confused if I need to create another loop for that or not: #1: name name=$1 #2: ip ip=$2 #3: user user=$3 #4+: folder exlusion #any lines higher than 3 will be created as exlcude folders ex[ARG_NUMBER]=

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  • Matlab - building an array while looping

    - by Mark
    Hello, I have a for loop that loops over one array... for i=1:length(myArray) In this loop, I want to do check on the value of myArray and add it to another array myArray2 if it meets certain conditions. I looked through the Matlab docs, but couldn't find anything on creating arrays without declaring all their values on initialization or reading data into them in one shot. Many thanks!

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  • PHP while(variable=mysql_fetch_assoc) - explanation

    - by Petr
    Hi, I have been working with C# so this is quite strange for me: while($variable=mysql_fetch_assoc) I have not been able to look up in PHP manual how it works. I guess that in each loop it advances to next element of assoc.array. But what is this generally called in PHP? I am just not used to see '=' in loop condition.

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  • Sparc Assembly Call corrupts data

    - by Sigge
    I am at the moment working with some assembler code for the Sparc processor family, and i am having some truble with a piece of code.. I think the code and output explains more, but in the short.. When i do a call to the function println my varaibels that i have written to the %fp - 8 memory location is destoryed.. here is my assembler code that i am trying to run !PROCEDURE main .section ".text" .global main .align 4 main: save %sp, -96, %sp L1: set 96, %l0 mov %l0, %o0 call initObject ; nop mov %o0, %l0 mov %l0, %o0 call Test$go ; nop mov %o0, %l0 mov %l0, %o0 call println ; nop L0: ret restore !END main !PROCEDURE Test$go .section ".text" .global Test$go .align 4 Test$go: save %sp, -96, %sp L3: mov %i0, %l0 set 0, %l0 set -8, %l1 add %fp,%l1, %l1 st %l0, [%l1] set 1, %l0 mov %l0, %o0 call println ; nop set -8, %l0 add %fp,%l0, %l0 ld [%l0], %l0 mov %l0, %o0 call println ; nop set 1, %l0 mov %l0, %i0 L2: ret restore !END Test$go Here is the assembler code for the println code .global println .type println,#function println: save %sp,-96,%sp ! block 1 .L193: ! File runtime.c: ! 42 } ! 43 ! 45 /** ! 46 Prints an integer to the standard output stream. ! 47 ! 48 @param i The integer to be printed. ! 49 */ ! 50 void println(int i) { ! 51 printf("%d\n", i); sethi %hi(.L195),%o0 or %o0,%lo(.L195),%o0 call printf mov %i0,%o1 jmp %i7+8 restore This is the out put i get when i run this piece of assembler code 1 67584 1 As u can see, the data that is located at %fp - 8 has been destroyed.. please all feedback is apritiated

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  • Sparc Assembly Call currupts data

    - by Sigge
    I am at the moment working with some assembler code for the Sparc processor family, and i am having some truble with a piece of code.. I think the code and output explains more, but in the short.. When i do a call to the function println my varaibels that i have written to the %fp - 8 memory location is destoryed.. here is my assembler code that i am trying to run !PROCEDURE main .section ".text" .global main .align 4 main: save %sp, -96, %sp L1: set 96, %l0 mov %l0, %o0 call initObject ; nop mov %o0, %l0 mov %l0, %o0 call Test$go ; nop mov %o0, %l0 mov %l0, %o0 call println ; nop L0: ret restore !END main !PROCEDURE Test$go .section ".text" .global Test$go .align 4 Test$go: save %sp, -96, %sp L3: mov %i0, %l0 set 0, %l0 set -8, %l1 add %fp,%l1, %l1 st %l0, [%l1] set 1, %l0 mov %l0, %o0 call println ; nop set -8, %l0 add %fp,%l0, %l0 ld [%l0], %l0 mov %l0, %o0 call println ; nop set 1, %l0 mov %l0, %i0 L2: ret restore !END Test$go Here is the assembler code for the println code .global println .type println,#function println: save %sp,-96,%sp ! block 1 .L193: ! File runtime.c: ! 42 } ! 43 ! 45 /** ! 46 Prints an integer to the standard output stream. ! 47 ! 48 @param i The integer to be printed. ! 49 */ ! 50 void println(int i) { ! 51 printf("%d\n", i); sethi %hi(.L195),%o0 or %o0,%lo(.L195),%o0 call printf mov %i0,%o1 jmp %i7+8 restore This is the out put i get when i run this piece of assembler code 1 67584 1 As u can see, the data that is located at %fp - 8 has been destroyed.. please all feedback is apritiated

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  • JQuery/AJAX: Loading external DIVs using dynamic content

    - by ticallian
    I need to create a page that will load divs from an external page using Jquery and AJAX. I have come across a few good tutorials, but they are all based on static content, my links and content are generated by PHP. The main tutorial I am basing my code on is from: http://yensdesign.com/2008/12/how-to-load-content-via-ajax-in-jquery/ The exact function i need is as follows: Main page contains a permanent div listing some links containing a parameter. Upon click, link passes parameter to external page. External page filters recordset against parameter and populates div with results. The new div contains a new set of links with new parameters. The external div is loaded underneath the main pages first div. Process can then be repeated creating a chain of divs under each other. The last div in the chain will then direct to a new page collating all the previously used querystrings. I can handle all of the PHP work with populating the divs on the main and external pages. It's the JQuery and AJAX part i'm struggling with. $(document).ready(function(){ var sections = $('a[id^=link_]'); // Link that passes parameter to external page var content = $('div[id^=content_]'); // Where external div is loaded to sections.click(function(){ //load selected section switch(this.id){ case "div01": content.load("external.php?param=1 #section_div01"); break; case "div02": content.load("external.php?param=2 #section_div02"); break; } }); The problem I am having is getting JQuery to pass the dynamically generated parameters to the external page and then retrieve the new div. I can currently only do this with static links (As above).

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  • NSMagedObjectContext, threads and NSFechedResultsController

    - by tmpz
    Dear iphone developers, Core Data newbie speaking here. In my application I have two NSManagedObjectContext that refer to that same NSPersistentStorageController. One ManagedObjectContext (c1) is in the main thread --created when I create a NSFetchedResultsController -- and the second ManagedObjectContext (c2) created in a second thread, running in the background, detached from the main thread. In the background thread I pull some data off a website and insert the entities created for the pulled data in the thread's ManagedObjectContext (c2). In the meanwhile, the main thread sits doing nothing and displaying a UITableView whose data do be display should be provided by the NSFetchedResultsController. When the background thread has finished pulling the data and inserting entities in c2, c2 saves, and the background thread notifies the main thread that the processing has finished before it exiting. As a matter of fact, the entities that I have inserted in c2 are know by c1 because it can ask it about one particular entity with [c1 existingObjectWithID:ObjectID error:&error]; I would expect at this point, if I call on my tableview reloadData to see some rows showing up with the data I pulled from the web in the background thread thanks to the NSFetchedResults controller which should react to the modifications of its ManagedObjectContext (c1). But nothing is happening! Only if I restart the application I see what I have previously pulled from the web! Where am I doing things wrong? Thank you in advance!

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  • What is causing this template-related compile error? (c++)

    - by Setien
    When I try to compile this: #include <map> #include <string> template <class T> class ZUniquePool { typedef std::map< int, T* > ZObjectMap; ZObjectMap m_objects; public: T * Get( int id ) { ZObjectMap::const_iterator it = m_objects.find( id ); if( it == m_objects.end() ) { T * p = new T; m_objects[ id ] = p; return p; } return m_objects[ id ]; } }; int main( int argc, char * args ) { ZUniquePool< std::string > pool; return 0; } I get this: main.cpp: In member function ‘T* ZUniquePool<T>::Get(int)’: main.cpp:12: error: expected `;' before ‘it’ main.cpp:13: error: ‘it’ was not declared in this scope I'm using GCC 4.2.1 on Mac OS X. It works in VS2008. I'm wondering whether it might be a variation of this problem: http://stackoverflow.com/questions/1364837/why-doesnt-this-c-template-code-compile But as my error output is only partially similar, and my code works in VS2008, I am not sure. Can anyone shed some light on what I am doing wrong?

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  • Creating New Object of Other Class dynamicly ?

    - by Meko
    I am trying to create new object of other class in a for loop. like for(int i =0;i<10;i++){ Computer p1=new Computer(10,20); } and when I try anywhere to reach p1.someAction(); it say you must declare p1. But if I declare it on top of program how can I create again in loop? I also try only Computer p1; but it gave exeption ..

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  • Smarter println that shows the depth in the stack

    - by Hectoret
    I am using System.out.println in my code to track the execution of a program and get some useful output. This creates results like this in the console: Main function. Program starts. Method getArea. Getting values Method getSide. Side is 6 Method getArea. First value is 6 Method getSide. Side is 8 Method getArea. Second value is 8 Method getArea. Area is 48 Main function. The final area is 48 I would like to create tha method, which adds a space in front of the output every time the code goes deeper in the method call stack. For example, the same code but instead of using System.out.println, now with Misc.smartPrintln: Main function. Program starts. Method getArea. Getting values Method getSide. Side is 6 Method getArea. First value is 6 Method getSide. Side is 8 Method getArea. Second value is 8 Method getArea. Area is 48 Main function. The final area is 48 The method would have this definition: public static void smartPrintln(String string); I don't know how to implement this functionality. Any ideas how to solve this? And, could the use of a logger offer this functionality?

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  • Looping Gridview when the button is click

    - by Nyan
    Hi all, I have create a girdview in dialog and in the girdview I added a check boxes, so that, the user can check/uncheck the gridview. And there is a button which send back the information about the check values to the server. My problem is I don't know how to loop the gridview. Is there a way to loop the girdview. Or is there other way to achieve? Thanks in advance for any help Nyan

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  • Console window now showing

    - by CoffeeAddict
    I have this in one of my NUnit tests. I'm using R# to step through my test. The console window is not popping up to show me the contents for that foreach loop...not sure what I'm missing but yes, there is data for it to loop through so it's not like there's no data here foreach (PostEntry post in posts) { Console.WriteLine("id: " + post.Id); Console.WriteLine("title: " + post.Title); Console.WriteLine("body: " + post.Body); Console.ReadLine(); }

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  • ruby looping question

    - by jonepatr
    Hello! I want to make a loop on a variable that can be altered inside of the loop. first_var.sort.each do |first_id, first_value| second_var.sort.each do |second_id, second_value_value| difference = first_value - second_value if difference >= 0 second_var.delete(second_id) else second_var[second_id] += first_value if second_var[second_id] == 0 second_var.delete(second_id) end first_var.delete(first_id) end end end How do I do this, because this doesn't work?

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  • Canvas draw calls are rendering out of sequence

    - by Tom Murray
    I have the following code for writing draw calls to a "back buffer" canvas, then placing those in a main canvas using drawImage. This is for optimization purposes and to ensure all images get placed in sequence. Before placing the buffer canvas on top of the main one, I'm using fillRect to create a dark-blue background on the main canvas. However, the blue background is rendering after the sprites. This is unexpected, as I am making its fillRect call first. Here is my code: render: function() { this.buffer.clearRect(0,0,this.w,this.h); this.context.fillStyle = "#000044"; this.context.fillRect(0,0,this.w,this.h); for (var i in this.renderQueue) { for (var ii = 0; ii < this.renderQueue[i].length; ii++) { sprite = this.renderQueue[i][ii]; // Draw it! this.buffer.fillStyle = "green"; this.buffer.fillRect(sprite.x, sprite.y, sprite.w, sprite.h); } } this.context.drawImage(this.bufferCanvas,0,0); } This also happens when I use fillRect on the buffer canvas, instead of the main one. Changing the globalCompositeOperation between 'source-over' and 'destination-over' (for both contexts) does nothing to change this. Paradoxically, if I instead place the blue fillRect inside the nested for loops with the other draw calls, it works as expected... Thanks in advance!

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  • Qt - 2 QMainWindow glued - Size of Layout

    - by user1773603
    I have a main window that I center this way in main.cpp : int main(int argc, char *argv[]) { QApplication app(argc, argv); QMainWindow *qmain = new QMainWindow; Ui_MainWindow ui; ui.setupUi(qmain); QRect r = qmain->geometry(); r.moveCenter(QApplication::desktop()->availableGeometry().center()); qmain->setGeometry(r); qmain->show(); return app.exec(); } In this "qmain" main window, I can create another QMainWindow and I try to make stick (or glue I don't know how to say) the two windows. Actually, I would like the right-top corner of the first one to be located at the left-top of the second one. For this, I use the following Ui_MainWindow's member function : void Ui_MainWindow::generate_IC() { qmenu = new QMainWindow; DiskMenu = new Ui_DiskGalMenu; DiskMenu->setupUi(qmenu); setInitialDiskMenuPosition(qmenu, this); qmenu->show(); } and the setInitialDiskMenuPosition : void Ui_MainWindow::setInitialDiskMenuPosition(QMainWindow *MainWindow, Ui_MainWindow *parent) { QSize size = parent->widget->size(); QDesktopWidget* desktop = QApplication::desktop(); int width = desktop->width(); int height = desktop->height(); int mw = size.width(); int mh = size.height(); int right = (width/2) + (mw/2); int top = (height/2) - (mh/2); MainWindow->move(right, top); } But the problem is that I don't get exactly what I want since the centralwidget size "parent- widget-size()" only returns the size of the widget and not the whole "qmain" parent window. So I have a light shift because the borders of the "qmain" window are not taken in account like it is shown below : If I could have access to the size of the whole parent window... If anyone could help me

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  • How can pointers to functions point to something that doesn't exist in memory yet? Why do prototypes have different addresses?

    - by Kacy Raye
    To my knowledge, functions do not get added to the stack until run-time after they are called in the main function. So how can a pointer to a function have a function's memory address if it doesn't exist in memory? For example: using namespace std; #include <iostream> void func() { } int main() { void (*ptr)() = func; cout << reinterpret_cast<void*>(ptr) << endl; //prints 0x8048644 even though func never gets added to the stack } Also, this next question is a little less important to me, so if you only know the answer to my first question, then that is fine. But anyway, why does the value of the pointer ( the memory address of the function ) differ when I declare a function prototype and implement the function after main? In the first example, it printed out 0x8048644 no matter how many times I ran the program. In the next example, it printed out 0x8048680 no matter how many times I ran the program. For example: using namespace std; #include <iostream> void func(); int main() { void ( *ptr )() = func; cout << reinterpret_cast<void*>(ptr) << endl; } void func(){ }

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  • Why would gnu ld link order causes Signal 11 (SEGV) on startup?

    - by Benoit
    We are building a large application in C++ that includes the use of many (static) libraries. We have a problem where the application crashes on startup with a Signal 11, before we even reach main. After much debugging, we have observed that if we explicitly reference an object file so its link order is early, the program crashes on startup. If the file is referenced later (or not referenced at all), the program does not crash. To be clear, there is NO code invoked directly from this object file. However, as it is C++, there might be static objects that do get constructed (it's a CORBA IDL generated file). We use the -Wl,--start-group ... --end-group arguments to multi-pass link the symbols since the libraries are interdependent. Here is a representation of what I mean. This is what the linker's object file order is: Order 1 Order 2 Order 3 foo.o foo.o foo.o ... ... ... main.o main.o main.o crasher.o libA.o libA.o libA.o LibB.o LibB.o LibB.o LibC.o LibC.o LibC.o crasher.o Results: NO CRASH NO CRASH CRASH Does any one have an idea why the linkage order has an effect on the crash? It would be nice if we could force the crasher.o to link later, but we're really after an explanation. Also, is there a way to force the linker to place crasher.o towards the end? Just to add to the fun, in actuality, crasher.o is part of a Library in the --start/--end-group.

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  • Running a Query in SQL Plus

    - by WENzER
    Hi, I have to run a query in the loop in SQLPLUS. and the count of loop is coming from some other SQL query. So i have to declared a variable which will take the value of count. Now I want to use this variable in my query. How would i be able to do the same . Please suggest me Thanks in advance

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  • Why are my thread being terminated ?

    - by Sephy
    Hi, I'm trying to repeat calls to methods through 3 differents threads. But after I start my threads, during the next iteration of my loop, they are all terminated so nothing is executed... The code is as follows : public static void main(String[] args) { main = new Main(); pollingThread.start(); } static Thread pollingThread = new Thread() { @Override public void run() { while (isRunning) { main.poll(); // test the state of the threads try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } } }; }; public void poll() { if (clientThread == null) { clientThread = new Thread(new Runnable() { @Override public void run() { //create some objects } }); clientThread.start(); } else if (clientThread.isAlive()) { // do some treatment } if (gestionnaireThread == null) { gestionnaireThread = new Thread(new Runnable() { @Override public void run() { //create some objects }; }); gestionnaireThread.start(); } else if (gestionnaireThread.isAlive()) { // do some treatment } if (marchandThread == null) { marchandThread = new Thread(new Runnable() { @Override public void run() { // create some objects }; }); marchandThread.start(); } else if (marchandThread.isAlive()) { // do some treatment } } And for some reason, when I test the state of my different threads, they appear as runnable and then a the 2nd iteration, they are all terminated... What am I doing wrong? I actually have no error, but the threads are terminated and so my loop keeps looping and telling me the threads are terminated.... Thanks for any help.

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