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  • Ubuntu server 12.04 on AWS - How does the passwordless sudo work for the ubuntu user?

    - by aychedee
    I'm using Ubuntu server 12.04 on Amazon. I want to add a new user that has the same behaviour as the default ubuntu user. Specifically I want passwordless sudo for this new user. So I've added a new user and went to edit /etc/sudoers (using visudo of course). From reading that file it seemed like the default ubuntu user was getting it's passwordless sudo from being a member of the admin group. So I added my new user to that. Which didn't work. Then I tried adding the NOPASSWD directive to sudoers. Which also didn't work. Anyway, now I'm just curious. How does the ubuntu user get passwordless privileges if they aren't defined in /etc/sudoers. What is the mechanism that allows this?

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  • Conventional Approaches for Passing Data to Back-End?

    - by Calvin
    Hi guys, I'm fairly new to web development, so please pardon the painfully newbie question that's about to follow. My computer science class group and I are developing a web application for class, which is built in Python (under Django) and uses jQuery on the front end. It's primarily an AJAX-ified application, and passing data from the backend to the front end is done through AJAX calls to specific URLs which return JSON. This is probably a stupid question, but what's the conventional approach for passing data in the opposite direction? We don't want to reload the page or anything, so is it an AJAX pass going the other way or something? Thanks in advance for your help!

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  • Cygwin file and directory user and group

    - by dvanaria
    I use Cygwin as my main development environment on both my home and work computers. In order to share files between the two computers, I use Dropbox, which is installed in the following folder on both computers: c:\cygwin\home\dvanaria\dropbox Everything works great, except for one thing. When I'm working on my home computer and do an ls -l on any directory, all the files show up as owned by dvanaria of group Users. But when I work from my work computer, an ls -l shows all files as being owned by Administrators and of group Domain Users. I know Cygwin uses some kind of mapping between Windows users and permissions to the /etc/passwd file. But to be honest I have no idea how this file works or how it maps to Windows under Cygwin. Could anyone help figure this out? The main problem is that I can't edit any files when using my work computer, only read them.

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  • Windows user trying install Git on Solaris

    - by nahab
    Is there simply way to install Git on Solaris as on Windows without installing any side libraries and compiling source files? And if not, why? UPD. Yes I'm looking for single package that will be easy to install. We have ~8 solaris zones using for development those we need simple way to install git fast on they. Installation should be easy because each member of team possibly will be do it and it should be fast because of big count of zones.

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  • How to add a suffix at the end of a string in PHP

    - by Golem
    I am trying to add a .html suffix at the end of all strings supplied by the user before it is entered into the database. Here's my code so far: strtolower(str_replace(" ", "_", $postTitle)); The above takes the title of the post the user it trying to make, turns it to lower case, replaces all white spaces with underscores and makes it ready to be entered into a database column called post_url. I just need it to do one more thing and that's to add a .html at the end of each post url. What is the function to do this?

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  • LINQ-to-SQL - Join, Count

    - by ile
    I have following query: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name }); Now, I need to modify this query... Other table I have is table Deals. I would like to count how many deals user created last month and last year. I tried something like this: var result = ( from role in db.Roles join user in db.Users on role.RoleID equals user.RoleID //join dealsYear in db.Deals on date.Year equals dealsYear.DateCreated.Year join dealsYear in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Year equals dealsYear.DateCreated.Year into dYear join dealsMonth in ( from deal in db.Deals group deal by deal.DateCreated into d select new { DateCreated = d.Key, dealsCount = d.Count() } ) on date.Month equals dealsMonth.DateCreated.Month into dMonth where user.CreatedByUserID == userID orderby user.FirstName ascending select new UserViewModel { UserID = user.UserID, PhotoID = user.PhotoID.ToString(), FirstName = user.FirstName, LastName = user.LastName, FullName = user.FirstName + " " + user.LastName, Email = user.Email, PhoneNumber = user.Phone, AccessLevel = role.Name, DealsThisYear = dYear, DealsThisMonth = dMonth }); but here is even syntax not correct. Any idea? Btw, is there any good book of LINQ to SQL with examples?

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • Enumerating all hamiltonian paths from start to end vertex in grid graph

    - by Eric
    Hello, I'm trying to count the number of Hamiltonian paths from a specified start vertex that end at another specified vertex in a grid graph. Right now I have a solution that uses backtracking recursion but is incredibly slow in practice (e.g. O(n!) / 3 hours for 7x7). I've tried a couple of speedup techniques such as maintaining a list of reachable nodes, making sure the end node is still reachable, and checking for isolated nodes, but all of these slowed my solution down. I know that the problem is NP-complete, but it seems like some reasonable speedups should be achievable in the grid structure. Since I'm trying to count all the paths, I'm sure that the search must be exhaustive, but I'm having trouble figuring out how to prune out paths that aren't promising. Does anyone have some suggestions for speeding the search up? Or an alternate search algorithm?

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  • Cannot see user desktop when I log in

    - by Jesi
    I am very new to Ubuntu. I recently got a new laptop running Windows 7. I am using Virtual Box and just installed the Ubuntu 12.10 ISO as a new Virtual Machine within Virtual Box. Everything seemed to install just fine and I even added the Guest Additions under Devices. The problem is that I cannot see the menus and my login information. The virtual machine says it is running; however, I do not have the Applications, Places, System, etc. tray to select from. Is there something I am supposed to do after logging in to get this? I entered my password and everything seemed fine, I just don't have those drop-down menus available... Thank You! Jesi

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  • Block complete network access for one local user

    - by tumchaaditya
    Well, this is quite trivial question but I could not find a satisfactory answer even after trying many search queries both here and on Google. I want to share my PC with my room-mate. And I don't want him to access ANY network(LAN included). So, I can create an account for him and block network access for the same. I would prefer avoiding any third-party tools as far as possible. It's a simple home PC hooked up to a router for internet. No domain and other stuff. (Technically, guest account can achieve this. But somehow, the guest account on my PC has network access!)

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  • MapReduce programming system in java-actionscript

    - by eco_bach
    Just finished reading ch23 in the excellent 'Beautiful Code' http://oreilly.com/catalog/9780596510046 on Distributed Programming with MapReduce. I understand that MapReduce is a programming system designed for large-scale data processing problems, but I have a hard time getting my head around the basic examples given and how I might apply them in real world situations. Can someone give a simple example of MapReduce implemented using either java, javascript or actionscript?

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  • comparing two end() iterators

    - by aafoo
    list<int> foo; list<int> foo2; list<int>::iterator foo_end = foo.end(); list<int>::iterator foo2_end = foo2.end(); for (list<int>::iterator it = foo.begin(); it != foo2_end; ++foo) <- notice != comparison here { ... it this allowed? will it work correctly. I am inclined to think that this is implementation dependent, anyone knows if standard says anything about this?

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  • Unity no longer loads in 13.04 for main user

    - by user152973
    When Ubuntu starts up, Unity fails to load (I can only see my desktop with no unity sidebar and no system bar in the top right). I tried the advice of Unity does not start in Ubuntu 13.04 which recommended the following commands: dconf reset -f /org/compiz/ unity --reset-icons &disown I ran the commands without errors an restarted the computer, but the problem persists. I am currently running Gnome. I have looked at other pages from the Google search "ubuntu unity failed to load 13.04", but the advice was similar to above and seems to be concerned with a system upgrade in April 18, 2013. I suspect my issue is something far more recent. Please give me advice on how to restore Unity on my account or at least figure out what the problem is. Thank you. Some information that might be relevant: -Unity has worked fine on 13.04 for the 6 months that I've had it until today. (November 10, 2013) -I have set up the update tool to automatically update when available. It is very possible that the system applied some updates without my knowledge. -Interestingly, Unity works fine on the Guest account. -I have made it so the system automatically logs me in at start-up. -This is a personal laptop. No one else has access to it. -I was not doing anything with the system settings or the terminal and have not installed any new software for the past 3 days. -I am running the System76 native Linux laptop Ultra Lemur. I did not contact their support yet because it seemed unlikely that this is a System76-specific error.

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  • GUI programming, what to learn, already know console C++

    - by conqrr
    i have already learnt c++ console(love it!) and want to do gui programming, i have looked at Qt but i dont like the size of exe produced at all,even after compressing or static linking.... Shall i learn c# and gui programming?? is it easy to move from c++? what is dot net exactly by the way and how can it be useful to me and my CV in future??

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  • any ways saving user information without db

    - by hguser
    Hi: I have a application which require login,but the number of user who use the application is no more than 40. And In the application,I get some data from the sql server database where I juse have read permission,also I can not create a table in the db for user validate. ALso I do not think it is a good idea to create a user table in other database on another machine.(for example,I can create a user table in the mysql another machine,but is it desireable just for user validating)? Now I just save the user info in a .properties file,any other good idea? BTW,the programe language used in my application is java.

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  • Tips on how to notify a user of new features in your game (Android)

    - by brent777
    I have noticed a problem when releasing new features for a game that I wrote for Android and published on Google Play Store. Because my game is "stage-based" - and not a game like Hay Day, for example, where users will just go into the game every day since it can't really be finished - my users are not aware of new features that I release for the game. For example, if I publish a new version of my game and it contains a couple new stages, most of their devices will just auto-update the game and they don't even notice this and think to check out what's new. So this is why an approach like popping open a dialog that showcases the new feature(s) when they open the game for the first time after the update was done is not really sufficient. I am looking for some tips on an approach that will draw my users back into the game and then they could read more detail about new features on such a dialog. I was thinking of something like a notification that tells them to check out the new features after an update is done but I am not sure if this is a good idea. Any suggestions to help me solve this problem would be awesome.

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  • How to stay connected to the programming community?

    - by Anton
    I often find myself detached from the programming community and I generally find out about all the "cool" things that are happening after they have already happened. So my question is how do you stay connected and up to date with the programming community? Podcasts, blogs, meet ups, conventions, twitter, talking with your co-workers whatever it may be that keeps you connected. Please provide actual examples of which blogs, talks, etc you use.

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  • Creating a blocked user intercepter in Grails

    - by UltraVi01
    I am working on a social site where users can block other users. Throughout the site --dozens of places, user information is displayed. For example, user comments, reply forms, online user list.. etc etc.. The problem is that given the high number of places user info is displayed, it's becoming very difficult to check each time if that user is blocked. For example: <g:each var="comment" in="${comments}"> <g:if test="!${loggedInUser.blockedUsers.find { it == comment.user}"> show comment </g:if> </g:each> Does Grails provide any functionality that would facilitate creating some kind of filter or intercepter where I could simply exclude blocked users when iterating lists, etc? If not, what would you suggest I do?

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  • How to input data into user defined variables into MySql query

    - by user292791
    Simple Shell script echo "Enter 1 for month of March" echo "Enter 2 for month of April" echo "Enter 3 for month of May" read Month case "$Month" in 1) echo "enter establishment name" read a; mysql -u root -p $a < "March.sql";; 2) echo "enter establishment name" read b; mysql -u root -p $b < "April.sql";; 3) echo "enter establishment name" read c; mysql -u root -p $c < "May.sql";; esac done In this i have three other query files March.sql, April.sql, May.sql. i'm linking this in shell script . Example of .sql file: SELECT DISTINCT substr( a.case_no, 3, 2 ), b.case_type, b.type_name, a.case_no into outfile '/tmp/April.csv' FIELDS TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\r\n' FROM Civil_t AS a, Case_type_t AS b, disposal_proc AS c WHERE substr( a.case_no, 3, 2 ) = b.case_type AND a.date_of_decision BETWEEN '2014-04-01' AND '2014-04-30' AND a.case_no = c.case_no AND a.court_no =1; I have to alter the .sql script every time. Is there any method to read the variables from shell script and use it in mysql. For example:- echo "enter date" read a #input date Now i have read a "date" and i want to use it in March.sql query in where clause. Is there is any method of using this variable in .sql query.

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  • Distinguishing between failure and end of file in read loop

    - by celtschk
    The idiomatic loop to read from an istream is while (thestream >> value) { // do something with value } Now this loop has one problem: It will not distinguish if the loop terminated due to end of file, or due to an error. For example, take the following test program: #include <iostream> #include <sstream> void readbools(std::istream& is) { bool b; while (is >> b) { std::cout << (b ? "T" : "F"); } std::cout << " - " << is.good() << is.eof() << is.fail() << is.bad() << "\n"; } void testread(std::string s) { std::istringstream is(s); is >> std::boolalpha; readbools(is); } int main() { testread("true false"); testread("true false tr"); } The first call to testread contains two valid bools, and therefore is not an error. The second call ends with a third, incomplete bool, and therefore is an error. Nevertheless, the behaviour of both is the same. In the first case, reading the boolean value fails because there is none, while in the second case it fails because it is incomplete, and in both cases EOF is hit. Indeed, the program above outputs twice the same line: TF - 0110 TF - 0110 To solve this problem, I thought of the following solution: while (thestream >> std::ws && !thestream.eof() && thestream >> value) { // do something with value } The idea is to detect regular EOF before actually trying to extract the value. Because there might be whitespace at the end of the file (which would not be an error, but cause read of the last item to not hit EOF), I first discard any whitespace (which cannot fail) and then test for EOF. Only if I'm not at the end of file, I try to read the value. For my example program, it indeed seems to work, and I get TF - 0100 TF - 0110 So in the first case (correct input), fail() returns false. Now my question: Is this solution guaranteed to work, or was I just (un-)lucky that it happened to give the desired result? Also: Is there a simpler (or, if my solution is wrong, a correct) way to get the desired result?

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  • Anyone have a script to delete a specific local windows profile?

    - by Jordan Weinstein
    I'm looking for Powershell (preferred) script, or .CMD or .VBS, to delete a specific user profile on a workstation (WinXP) or terminal server (2000, '03 or '08). I know all about the delprof utility... That only allows you delete based on a period of inactivity. I want a script to: prompt admin for a username delete that username's profile and to delete the entire profile - registry hive too (not just the folder structure within Documents and Settings). The same way it would if you went to My Computer Properties Advanced tab User Profiles Settings and deleted profiles from there. Any ideas? All I can think of is doing an AD lookup to get the SID of the user specified, then using that to delete the correct registry hive too... something simpler would be nice though... Basically, my HelpDesk used to be local administrators on our Citrix servers and a common fix for various issues was for them to delete a user's profile on the citrix server(s) and have that user log back in - voila, whatever issue they had was resolved. Going forward, in new Citrix environment, they will no longer be local admins on those boxes, but still need to be able to delete profiles (deleting the entire profile: folder and reg hive is key). thanks.

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