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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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  • How to stop attributes from being pickled in Python

    - by Ries
    I am using gnosis.xml.pickle to convert an object of my own class to xml. The object is initialized so that: self.logger = MyLogger() But when I do dump the object to a string I get an exception stating that the pickler encountered an unpickleable type . Is there a way to 'tag' the logger attribute so that pickler will know not to try and pickle that attribute?

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  • Python: for statement behavior

    - by BandGap
    Hi all. My question concerns the output of this statement: for x in range(4), y in range(4): print x print y Results in: [0, 1, 2, 3] 2 True 2 It seems there is a comparison involved, I just can't figure out why the output is structured like this.

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  • Sorting and alligning the contents of a text file in Python

    - by Emily Price
    Hello In my program I have a text file that I read from and write to. However, I would like to display the contents of the text file in an alligned and sorted manner. The contents currently read- name, score name, score Would I have to convert this information into lists in order to be able to do this? If so, how do I go about doing this? Thankyou

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  • Python: Regex outputs 12_34 - I need 1234

    - by Guy F-W
    So I have input coming in like: 12_34 5_6_8_2 4___3 1234 and the output I need from it is: 1234, 5682, 43, 1234 I'm currently working with r'[0-9]+[0-9_]*'.replace('_','') which (as far as I can tell) successfully rejects any input which is not a combination of numeric digits and under-scores, where the underscore cannot be the first character. However, replacing the _ with the empty string causes 12_34 to come out as 12 and 34. Is there a better method than 'replace' for this? Or could I adapt my regex to deal with this problem?

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  • Python sort 2-D list by time string

    - by Mark Kennedy
    How do I sort a multi dimensional list like this based on a time string? The sublists can be of different sizes (i.e. 4 and 5, here) I want to sort by comparing the first time string in each sublist (sublist[-4]) x = (['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5]) The sorted result would be sortedX = (['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5]) I tried the following: sortedX = sorted(x, key=lambda k : k[-4]) #k[-4] is the first time string and it works but it doesn't respect the sublist size ordering

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  • difference between 2 pieces Python code

    - by draw
    Hello, I'm doing an exercise as following: # B. front_x # Given a list of strings, return a list with the strings # in sorted order, except group all the strings that begin with 'x' first. # e.g. ['mix', 'xyz', 'apple', 'xanadu', 'aardvark'] yields # ['xanadu', 'xyz', 'aardvark', 'apple', 'mix'] # Hint: this can be done by making 2 lists and sorting each of them # before combining them. sample solution: def front_x(words): listX = [] listO = [] for w in words: if w.startswith('x'): listX.append(w) else: listO.append(w) listX.sort() listO.sort() return listX + listO my solution: def front_x(words): listX = [] for w in words: if w.startswith('x'): listX.append(w) words.remove(w) listX.sort() words.sort() return listX + words as I tested my solution, the result is a little weird. Here is the source code with my solution: http://dl.dropbox.com/u/559353/list1.py. You might want to try it out.

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  • Python Beautiful Soup .content Property

    - by Robert Birch
    What does BeautifulSoup's .content do? I am working through crummy.com's tutorial and I don't really understand what .content does. I have looked at the forums and I have not seen any answers. Looking at the code below.... from BeautifulSoup import BeautifulSoup import re doc = ['<html><head><title>Page title</title></head>', '<body><p id="firstpara" align="center">This is paragraph <b>one</b>.', '<p id="secondpara" align="blah">This is paragraph <b>two</b>.', '</html>'] soup = BeautifulSoup(''.join(doc)) print soup.contents[0].contents[0].contents[0].contents[0].name I would expect the last line of the code to print out 'body' instead of... File "pe_ratio.py", line 29, in <module> print soup.contents[0].contents[0].contents[0].contents[0].name File "C:\Python27\lib\BeautifulSoup.py", line 473, in __getattr__ raise AttributeError, "'%s' object has no attribute '%s'" % (self.__class__.__name__, attr) AttributeError: 'NavigableString' object has no attribute 'name' Is .content only concerned with html, head and title? If, so why is that? Thanks for the help in advance.

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  • Python get raw_input but manually decide when string is done

    - by Jasie
    I want someone to type words in the console, and autocomplete from a list when they hit "tab" key. However, raw_input won't return a string until someone hits [Enter]. How do I read characters into a variable until the user hits [Enter]? *Note: I don't want to use import readline for autocompletion because of OS issues.

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  • More elegant way to initialize list of duplicated items in Python

    - by Claudiu
    If I want a list initialized to 5 zeroes, that's very nice and easy: [0] * 5 However if I change my code to put a more complicated data structure, like a list of zeroes: [[0]] * 5 will not work as intended, since it'll be 10 copies of the same list. I have to do: [[0] for i in xrange(5)] that feels bulky and uses a variable so sometimes I even do: [[0] for _ in " "] But then if i want a list of lists of zeros it gets uglier: [[[0] for _ in " "] for _ in " "] all this instead of what I want to do: [[[0]]*5]*5 Has anyone found an elegant way to deal with this "problem"?

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  • Python Pandas operate on row

    - by wuha
    Hi my dataframe look like: Store,Dept,Date,Sales 1,1,2010-02-05,245 1,1,2010-02-12,449 1,1,2010-02-19,455 1,1,2010-02-26,154 1,1,2010-03-05,29 1,1,2010-03-12,239 1,1,2010-03-19,264 Simply, I need to add another column called '_id' as concatenation of Store, Dept, Date like "1_1_2010-02-05", I assume I can do it through df['id'] = df['Store'] +'' +df['Dept'] +'_'+df['Date'], but it turned out to be not. Similarly, i also need to add a new column as log of sales, I tried df['logSales'] = math.log(df['Sales']), again, it did not work.

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  • Automatically registering "commands" for a command line program in python

    - by seandavi
    I would like to develop a command-line program that can process and give "help" for subcommands. To be concrete, say I have a single script called "cgent" and I would like to have subcommands "abc", "def", and "xyz" execute and accept the rest of the sys.args for processing by optparse. cgent abc [options] cgent help abc .... All of this is straightforward if I hard-code the subcommand names. However, I would like to be able to continue to add subcommands by adding a class or module (?). This is similar to the idea that is used by web frameworks for adding controllers, for example. I have tried digging through pylons to see if I can recreate what is done there, but I have not unravelled the logic. Any suggestions on how to do this? Thanks, Sean

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  • In python, what does len(list) do?

    - by nsharish
    My doubt is that if the len(list) calculates the length of the list everytime it is called or it returns the value of the builtin counter.I have a context where i need to check the length of list everytime in a loop, likelistData = [] for value in ioread(): if len(listData)=25: processlistdata() clearlistdata() listData.append(value) Should I check len(listData) every iteration, or can I have a counter for the length of the list.

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  • Deleting files by type in Python on Windows

    - by choszen
    I know how to delete single files, however I am lost in my implementation of how to delete all files in a directory of one type. Say the directory is \myfolder I want to delete all files that are .config files, but nothing to the other ones. How would I do this? Thanks Kindly

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  • replacing values in formated file with python

    - by froggy
    I have a string see attached file like that and i would like to modify it using a function Giving section name parameter name and value to set Also in case i want to modify several parameters for a same section how can i have position in file to avoid scanning x time for a same section and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question and other to pass my question an and other to pass my question d other to pass my question and other to pass my question and other to pass my question and other to pass my questionand other to pass my question and other to pass my question

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  • Python references

    - by hekevintran
    Can someone explain why the example with integers results in different values for x and y and the example with the list results in x and y being the same object? x = 42 y = x x = x + 1 print x # 43 print y # 42 x = [ 1, 2, 3 ] y = x x[0] = 4 print x # [4, 2, 3] print y # [4, 2, 3] x is y # True

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  • python matrices - list index out of range

    - by user1888493
    I am writing a function, that takes a matrix as input, such as the one below. Then the it returns the matrix' inverse, where all the 1s are changed to 0s and all the 0s changed to 1s, while keeping the diagonal from top left to bottom right 0s. An example input: g1 = [[0, 1, 1, 0], [1, 0, 0, 1], [1, 0, 0, 1], [0, 1, 1, 0]] the function should output this: g1 = [[0, 0, 0, 1], [0, 0, 1, 0], [0, 1, 0, 0], [1, 0, 0, 0]] When I run the program, it raises a list index out of range error. I'm sure this happens, because the loops I have set up are trying to access values that do not exist. But how do I allow an input of unknown row and column size? I only know how to do this with a single list, but a list of lists? Following you see the transforming function, but not the test function that calls it: def inverse_graph(graph): # take in graph # change all zeros to ones and ones to zeros r, c = 0, 0 # row, column equal zero while (graph[r][c] == 0 or graph[r][c] == 1): # while the current row has a value. while (graph[r][c] == 0 or graph[r][c] == 1): # while the current column has a value if (graph[r][c] == 0): graph[r][c] = 1 elif (graph[r][c] == 1): graph[r][c] = 0 c+=1 c=0 r+=1 c=0 r=0 # sets diagonal to zeros while (g1[r][c] == 0 or g1[r][c] == 1): g1[r][c]=0 c+=1 r+=1 return graph

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  • Python sort strings started with digits

    - by vlad
    I have the next list: a = ['1th Word', 'Another Word', '10th Word'] print a.sort() >>> ['10th Word', '1th Word', 'Another Word'] But I need: ['1th Word', '10th Word','Another Word'] Is there an easy way to do this? I tried: r = re.compile(r'(\d+)') def sort_by_number(s): m = r.match(s) return m.group(0) x.sort(key=sort_by_number) But some strings do not have numbers and this leads to an errors. Thanks.

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  • I need to make a multithreading program (python)

    - by Andreawu98
    import multiprocessing import time from itertools import product out_file = open("test.txt", 'w') P = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p','q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',] N = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] M = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] c = int(input("Insert the number of digits you want: ")) n = int(input("If you need number press 1: ")) m = int(input("If you need upper letters press 1: ")) i = [] if n == 1: P = P + N if m == 1: P = P + M then = time.time() def worker(): for i in product(P, repeat=c): #check every possibilities k = '' for z in range(0, c): # k = k + str(i[z]) # print each possibility in a txt without parentesis or comma out_file.write( k + '\n') # out_file.close() now = time.time() diff = str(now - then) # To see how long does it take print(diff) worker() time.sleep(10) # just to check console The code check every single possibility and print it out in a test.txt file. It works but I really can't understand how can I speed it up. I saw it use 1 core out of my quad core CPU so I thought Multi-threading might work even though I don't know how. Please help me. Sorry for my English, I am from Italy.

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  • Concatenation of many lists in Python

    - by Space_C0wb0y
    Suppose i have a function like this: def getNeighbors(vertex) which returns a list of vertices that are neighbors of the given vertex. Now i want to create a list with all the neighbors of the neighbors. I do that like this: listOfNeighborsNeighbors = [] for neighborVertex in getNeighbors(vertex): listOfNeighborsNeighbors.append(getNeighbors(neighborsVertex)) Is there a more pythonic way to do that?

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