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  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

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  • Post method in Servlet is not being called again after being executed once

    - by SaurabhCsIITKgp
    I am implementing a database based web application using servlets. Now, when I input a parameter using a form in the jsp page, it redirects it to a servlet which subsequently adds the value to the database (the servlet creates a new table if the table doesn't already exist). The creation of the table and the addition of value works fine if the table doesn't already exists. Once it is created however and the parameter is inputted again in the form, the submit button no longer redirects it to the servlet. Nor is the value added to the database. Kindly advise me as to where I am going wrong. Following are the snippets of my code: From the JSP page (/showmanager is the urlpattern of the servlet): <form action="showmanager" method="post"> <h3>Enter name of the show: </h3> <input type="text" name="showname" value=""> <input type="hidden" name="task" value="addshow" /> <input type="button" value="Add Show"> </form> From the servlet (POST method): p rotected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if(request.getParameter("task").equals("addshow")){ this.addShow(request.getParameter("showname")); response.sendRedirect("showmanager.jsp"); } } Method to add in database: protected boolean addShow(String showname){ try{ statement =con.prepareStatement("INSERT INTO showdb10(name) VALUES ('"+showname+"')"); if(statement.executeUpdate()>0){ return true; } } catch(Exception e) { try{ statement =con.prepareStatement("create table showdb10 (id int NOT NULL AUTO_INCREMENT, name varchar(255) NOT NULL, date varchar(20),time varchar(20), b_total int, o_total int, b_avbl int, o_avbl int, b_price double(10,2), o_price double(10,2), seat_no varchar(20), transaction_id varchar(255), total_sales double(10,2), paymnt_artists double(10,2), paymnt_othr double(10,2), flag varchar(20), PRIMARY KEY(id))"); statement.executeUpdate(); statement =con.prepareStatement("INSERT INTO showdb10(name) VALUES ('"+showname+"')"); if(statement.executeUpdate()>0){ return true; } }catch(Exception e2){} } return false; }

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  • drop down and post data to data base

    - by DAFFODIL
    This is a form which retrieves data from db and displays them in table. At the beginning of each row there will be a check box. If there are 10 rows fetched, I ii check 5 rows and insert them in to diff db but here when, I click drop down box data is getting in to db automatically,bcoz I use onchange event. Any alternative to prevent this to happen. Data should be inserted only when, I click submit button. Any help will be appreciated <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("form1", $con); error_reporting(E_ALL ^ E_NOTICE); $nam=$_REQUEST['select1']; $row=mysql_query("select * from inv where name='$nam'"); while($row1=mysql_fetch_array($row)) { $Name=$row1['Name']; $Address =$row1['Address']; $City=$row1['City']; $Pincode=$row1['Pincode']; $No=$row1['No']; $Date=$row1['Date']; $DCNo=$row1['DCNo']; $DcDate=$row1['DcDate']; $YourOrderNo=$row1['YourOrderNo']; $OrderDate=$row1['OrderDate']; $VendorCode=$row1['VendorCode']; $SNo=$row1['SNo']; $descofgoods=$row1['descofgoods']; $Qty=$row1['Qty']; $Rate=$row1['Rate']; $Amount=$row1['Amount']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> <script type="text/javascript"> function ram(id) { var q=document.getElementById('qty_'+id).value; var r=document.getElementById('rate_'+id).value; document.getElementById('amt_'+id).value=q*r; } </script> </head> <body> <form id="form1" name="form1" method="post" action=""> <table width="1315" border="0"> <script type="text/javascript"> function g() { form1.submit(); } </script> <tr> <th>Name</th> <th align="left"><select name="select1" onchange="g();"> <option value="" selected="selected">select</option> <?php $row=mysql_query("select Name from inv "); while($row1=mysql_fetch_array($row)) { ?> <option value="<?php echo $row1['Name'];?>"><?php echo $row1['Name'];?></option> <?php } ?> </select></th> </tr> <tr> <th>Address</th> <th align="left"><textarea name="Address"><?php echo $Address;?></textarea></th> </tr> <tr> <th>City</th> <th align="left"><input type="text" name="City" value='<?php echo $City;?>' /></th> </tr> <tr> <th>Pincode</th> <th align="left"><input type="text" name="Pincode" value='<?php echo $Pincode;?>'></th> </tr> <tr> <th>No</th> <th align="left"><input type="text" name="No2" value='<?php echo $No;?>' readonly="" /></th> </tr> <tr> <th>Date</th> <th align="left"><input type="text" name="Date" value='<?php echo $Date;?>' /></th> </tr> <tr> <th>DCNo</th> <th align="left"><input type="text" name="DCNo" value='<?php echo $DCNo;?>' readonly="" /></th> </tr> <tr> <th>DcDate:</th> <th align="left"><input type="text" name="DcDate" value='<?php echo $DcDate;?>' /></th> </tr> <tr> <th>YourOrderNo</th> <th align="left"><input type="text" name="YourOrderNo" value='<?php echo $YourOrderNo;?>' readonly="" /></th> </tr> <tr> <th>OrderDate</th> <th align="left"><input type="text" name="OrderDate" value='<?php echo $OrderDate;?>' /></th> </tr> <tr> <th width="80">VendorCode</th> <th width="1225" align="left"><input type="text" name="VendorCode" value='<?php echo $VendorCode;?>' readonly="" /></th> </tr> </table> <table width="1313" border="0"> <tr> <td width="44">&nbsp;</td> <td width="71">SNO</td> <td width="527">DESCRIPTION</td> <td width="214">QUANTITY</td> <td width="214">RATE/UNIT</td> <td width="217">AMOUNT</td> </tr> <?php $i=1; $row=mysql_query("select * from inv where Name='$nam'"); while($row1=mysql_fetch_array($row)) { $SNo=$row1['SNo']; $descofgoods=$row1['descofgoods']; $Qty=$row1['Qty']; $Rate=$row1['Rate']; $Amount=$row1['Amount']; ?> <tr> <td><input type="checkbox" name="checkbox" value="checkbox" checked="checked"/></td> <td><input type="text" name="No[<?php echo $i?>]" value='<?php echo $SNo;?>' readonly=""/></td> <td><input type="text" name="descofgoods[<?php echo $i?>]" value='<?php echo $descofgoods;?>' /></td> <td><input type="text" name="qty[<?php echo $i?>]" maxlength="50000000" id="qty_<?PHP echo($i) ?>"/></td> <td><input type="text" name="Rate[<?php echo $i?>]" value='<?php echo $Rate;?>' id="rate_<?PHP echo($i) ?>" onclick="ram('<?PHP echo($i) ?>')";></td> <td><input type="text" name="Amount[<?php echo $i?>]" id="amt_<?PHP echo($i) ?>"/></td> </tr> <?php $i++;} ?> <tr> <td><input type="submit" value="submit" header("location:values to be brought for print page.php");/></td> </tr> </table> <label></label> </form> </body> </html> <?php /*error_reporting(E_ALL ^ E_NOTICE); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("form1", $con); /*if(checked=checkbox) { mysql_query="INSERT INTO invo (Name, Address, City, Pincode, No, Date, DCNo, DcDate, YourOrderNo, OrderDate, VendorCode, SNo, descofgoods, Qty, Rate, Amount) VALUES ('$_POST[Name]','$_POST[Address]','$_POST[City]','$_POST[Pincode]','$_POST[No]','$_POST[Date]','$_POST[DCNo]','$_POST[DcDate]','$_POST[YourOrderNo]','$_POST[OrderDate]','$_POST[VendorCode]','$_POST[SNo]','$_POST[descofgoods]','$_POST[qty]','$_POST[Rate]','$_POST[Amount]')"; } else { header("location:values to be brought for print page.php"); }*/ header("ins.php"); ?>

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  • Java MySQL Query Problem MySQLSyntaxErrorException When Creating a Table

    - by Aqib Mushtaq
    I fairly new to MySQL with Java, but I have executed a few successful INSERT queries however cannot seem to get the CREATE TABLE query to execute without getting the 'MySQLSyntaxErrorException' exception. My code is as follows: import java.sql.*; Statement stmt; Class.forName("com.mysql.jdbc.Driver"); String url = "jdbc:mysql://localhost:3306/mysql"; Connection con = DriverManager.getConnection(url, "root", "password"); stmt = con.createStatement(); String tblSQL = "CREATE TABLE IF NOT EXISTS \'dev\'.\'testTable\' (\n" + " \'id\' int(11) NOT NULL AUTO_INCREMENT,\n" + " \'date\' smallint(6) NOT NULL\n" + ") ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;"; stmt.executeUpdate(tblSQL); stmt.close(); con.close(); And the error is as follows: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''dev'.'testTable' ( 'id' int(11) NOT NULL AUTO_INCREMENT, 'date' smallint(6) N' at line 1 I would appreciate it if anyone could spot the mistake in this query, as I've tried executing this within phpMyAdmin and it works as it should. Thanks in advance.

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  • How to send check boxes ID in gridview in one string for mass update.

    - by SmartDev
    hi , I have a grid which has check boxes and when selecting the top chek box select all will select all the check box in gridview and would update .for this im using for loop where it exceutes every time and this is taking lot of time cuase there are more thn 100 records in grid . try { string StrOutputMessageDisplayDocReqCsu = string.Empty; string strid = string.Empty; string strflag = string.Empty; string strSelected = string.Empty; for (int j = 0; j < GdvDocReqMU.Rows.Count; j++) { CheckBox Chkupdate = (CheckBox)GdvDocReqMU.Rows[j].Cells[1].FindControl("chkDR"); if (Chkupdate != null) { if (Chkupdate.Checked) { strid = ((Label)GdvDocReqMU.Rows[j].FindControl("lblIDDocReqCsu")).Text; strflag = ((Label)GdvDocReqMU.Rows[j].FindControl("lblStatusDocReqCsu")).Text; cmd = new SqlCommand("sp_Update_v1", con); cmd.CommandType = CommandType.StoredProcedure; cmd.Parameters.AddWithValue("@id", strSelected); cmd.Parameters.AddWithValue("@flag", DdlStatusDocReqMU.SelectedValue); cmd.Parameters.AddWithValue("@notes", txtnotesDocReqMU.Text); cmd.Parameters.AddWithValue("@user", strUseridDRAhk); cmd.Parameters.Add(new SqlParameter("@message", SqlDbType.VarChar, 100, ParameterDirection.Output, false, 0, 50, "message", DataRowVersion.Default, null)); cmd.UpdatedRowSource = UpdateRowSource.OutputParameters; con.Open(); cmd.ExecuteNonQuery(); con.Close(); } } } //} //StrOutputMessageDisplayDocReqCsu += (string)cmd.Parameters["@message"].Value + "<br/>"; //lbldbmessDocReqAhk.Text += StrOutputMessageDisplayDocReqCsu + "<br>"; GetgridDocReq(); } catch (Exception ex) { lbldbmessDocReqAhk.Text = ex.Message.ToString(); }

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  • Using jquery Autocomplete on textbox control in c#

    - by Abid Ali
    When I run this code I get alert saying Error. My Code: <script type="text/javascript"> debugger; $(document).ready(function () { SearchText(); }); function SearchText() { $(".auto").autocomplete({ source: function (request, response) { $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "Default.aspx/GetAutoCompleteData", data: "{'fname':'" + document.getElementById('txtCategory').value + "'}", dataType: "json", success: function (data) { response(data.d); }, error: function (result) { alert("Error"); } }); } }); } </script> [WebMethod] public static List<string> GetAutoCompleteData(string CategoryName) { List<string> result = new List<string>(); using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["DbConnection"].ConnectionString)) { using (SqlCommand cmd = new SqlCommand("select fname from tblreg where fname LIKE '%'+@CategoryText+'%'", con)) { con.Open(); cmd.Parameters.AddWithValue("@CategoryText", CategoryName); SqlDataReader dr = cmd.ExecuteReader(); while (dr.Read()) { result.Add(dr["fname"].ToString()); } return result; } } } I want to debug my function GetAutoCompleteData but breakpoint is not fired at all. What's wrong in this code? Please guide. I have attached screen shot above.

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • MySQL query returning mysql_error

    - by Sebastian
    This returns mysql_error: <?php $name = $_POST['inputName2']; $email = $_POST['inputEmail2']; $instruments = $_POST['instruments']; $city = $_POST['inputCity']; $country = $_POST['inputCountry']; $distance = $_POST['distance']; // ^^ These all echo properly ^^ // CONNECT TO DB $dbhost = "xxx"; $dbname = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)"; $result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here if (!$result) { echo "There was a problem with the signup process. Please try again later."; } else { echo "Success"; } } ?> N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty. Bonus question: is my script secure enough or is there more I could do?

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  • JDBC going to the wrong address

    - by DCSoft
    When I try and connect it my mysql database with JDBC in java, it doesn't go to my web server. Here is the code String dbtime; String dbUrl = "jdbc:mysql://184.172.176.18:3306/dcsoft_dcsoft_balloon"; String dbUser = "myuser"; String dcPass = "mypass"; String dbClass = "com.mysql.jdbc.Driver"; String query = "Select * FROM users"; try { Class.forName("com.mysql.jdbc.Driver"); Connection con = DriverManager.getConnection(dbUrl, dbUser, dcPass); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery(query); while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } //end while con.close(); } //end try catch(ClassNotFoundException e) { e.printStackTrace(); } catch(SQLException e) { e.printStackTrace(); } This code is supposed to go to my web server but it gives this error java.sql.SQLException: Access denied for user 'dcsoft_dcsoft_java'@'jamesposse.force9.co.uk' (using password: YES) jamesposse.force9.co.uk is the not the address im trying to connect to I'm trying to connect to 184.172.176.18:3306. Thanks.

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  • how to add data in Table of Jasper Report using Java

    - by Areeb Gillani
    i am here to ask you just a simple question that i am trying to pass data to a jasper report using java but i dont know how to to, because the table data is very dynamic thats y cannot pass sql query. any idea for this. i have a 2D array of object type, where i have all the data... so how can i pass that... Thanx in advance...!:) ConnectionManager con = new ConnectionManager(); con.establishConnection(); String fileName = "Pmc_Bill.jrxml"; String outFileName = "OutputReport.pdf"; HashMap params = new HashMap(); params.put("PName", pname); params.put("PSerial", psrl); params.put("PGender",pgen); params.put("PPhone",pph); params.put("PAge",page); params.put("PRefer",pref); params.put("PDateR",dateNow); try { JasperReport jasperReport = JasperCompileManager.compileReport(fileName); if(jasperReport != null ) System.out.println("so far so good "); // Fill the report using an empty data source JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, new JRTableModelDataSource(tbl.getModel()));//con.connection); try{ JasperExportManager.exportReportToPdfFile(jasperPrint, outFileName); System.out.printf("File exported sucessfully"); }catch(Exception e){ e.printStackTrace(); } JasperViewer.viewReport(jasperPrint); } catch (JRException e) { JOptionPane.showMessageDialog(null, e); e.printStackTrace(); System.exit(1); }

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  • trying to backup mysql database using php

    - by user225269
    I got this code from this site: http://www.php-mysql-tutorial.com/wikis/mysql-tutorials/using-php-to-backup-mysql-databases.aspx But I'm just a beginner so I don't know what the config.php and opendb.php suppose to mean. Do I have to create those 2 files in order for this code to work? If yes, then how do I create it, it isn't included in the site how to create it. <?php include 'config.php'; include 'opendb.php'; $tableName = 'mypet'; $backupFile = 'backup/mypet.sql'; $query = "SELECT * INTO OUTFILE '$backupFile' FROM $tableName"; $result = mysql_query($query); include 'closedb.php'; ?> can I just include these lines on the top code so that I will not be putting the include 'opendb.php' anymore: $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Hospital", $con);

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  • Learning OOP in PHP, trying to refactor my code. Can't connect to database anymore.

    - by Cortopasta
    Thought I understood how classes work, then I tried this code: class user { var $dbcon; var $dbinfo; var $con; var $error; function dbConnect() { $this->dbinfo['server'] = "localhost"; $this->dbinfo['database'] = "foolish_faith"; $this->dbinfo['user'] = "user"; $this->dbinfo['password'] = "password"; $this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database']; $this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']); $this->dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $this->error = $this->dbcon->errorInfo(); if ($error[0] != "") { print "Error!"; print_r($error); } } } Now it just spits out this error: Fatal error: Uncaught exception 'PDOException' with message 'invalid data source name' in E:\PortableApps\xampp\htdocs\dbcon.php:24 Stack trace: #0 E:\PortableApps\xampp\htdocs\dbcon.php(24): PDO-__construct('', NULL, NULL) #1 E:\PortableApps\xampp\htdocs\login.php(4): user-dbConnect() #2 {main} thrown in E:\PortableApps\xampp\htdocs\dbcon.php on line 24 Can anybody see what I'm doing wrong, as I'm sure it has to do with my lack of knowledge when it comes to classes?

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  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

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  • PHP Dropdown menu [closed]

    - by rShetty
    <br><h2>Select a Tag</h2></br> <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("portal", $con); $query = "SELECT tag_name FROM tags"; $result = mysql_query($query); ?> <select name="tag_name" id="abc"> <option size=30 selected>Select</option> <?php while($array = mysql_fetch_assoc($result)){ ?> <option value ="<?php echo $array['tag_name'];?>"><?php echo $array['tag_name'];?> </option> <?php } ?> </select> <br><br> This is a snippet of code for getting the dropdown menu in the page. I have a database named portal and table named tags with tag_name as the attribute. Do help me to find the error in the program. I am not getting the tag_names in the dropdown menu

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  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • How to create festival calendar in ASP.net

    - by Atul
    I want to make a festival calendar using asp.net from that I used two ajax calendar and one textbox it is a festival textbox where we enter festival which FromDate and ToDate respectively. I want to do this as following point If I enter in textbox Christmas and Choose Fromdate=25/12/2011 and ToDate=31/12/2011 then it will be valid If I choose fromDate=25/12/2011 and ToDate=24/12/2011 then it will invalid If I choose Fromdate=25/12/2011 and Todate=28/12/2011 then also it is invalid because it coming in between 25/12/2011 and 31/12/2011 If I Choose fromdate=1/1/2011 and ToDate=1/1/2011 then it is valid If I choose fromdate=21/12/2011 and 25/12/2011 then it is invalid because of already Christmas done in 1/1/2011 And all date should show in gridview like 25-dec-2011 format Here is my code: DateTime dt1 = Convert.ToDateTime(txt_fromdate.Text); DateTime dt2 = Convert.ToDateTime(txt_todate.Text); if (dt1 > dt2) { con.Open(); com = new SqlCommand("BTNN_MovieDB_Festival_Details_Insert", con); com.Parameters.Add("@fromdate", SqlDbType.VarChar).Value = dateformat_mmdd(txt_fromdate.Text.ToString().Trim()); com.Parameters.Add("@todate", SqlDbType.VarChar).Value = dateformat_mmdd(txt_todate.Text.ToString().Trim()); com.Parameters.Add("@return", SqlDbType.VarChar).Direction = ParameterDirection.ReturnValue; com.ExecuteNonQuery(); con.Close(); showdata(); } else if (dt1 < dt2) { lblerror.Text = "ToDate should be greater than FromDate"; }

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  • jQuery: change a css value if a option is selected

    - by Ivan Castellanos
    I'm trying to make an option dropdown menu and I got stuck when I try to show a textbox if the option 'other' is selected. there's what I have: <span id="con-country"><label for="country">Country: </label> <select name="country" required="required"> <option value="usa">United States</option> <option value="uk">United Kingdom</option> <option id="other" value="other">Other</option> </select> </span> <span id="con-specify"> <label for="specify">Specify: </label> <input type="text" name="specify" id="c-specify" required="required"></input> </span> CSS: #con-specify{ margin-left: 50px; display: none; } Simple huh?, the problem is that I don't know how to do the code in jQuery So, if the user select other in the menu, then the textbox should appear, how can I do that?

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  • script to count the occurence of the particular string in the given time interval

    - by pruthvi
    We are trying to write a script "sendemail.sh" to count the number of occurrence of a particular string in a log file "SendEmail.log" within the given interval. We have a log file. In that we are searching for a pattern "ReqInputMsgLog" and need to count the number of times it occurred in the given period for eg: from "2014-08-19 11:30" to "2014-08-19 11:34". And our script look like this: #!/bin/sh enterdate=$1 echo $enterdate enddate=$2 enterdate1=`date +%s -d $enterdate +"%Y-%m-%d %H:%M"` echo $enterdate1 enddate1=`date +%s -d $enddate +"%Y-%m-%d %H:%M"` echo $enddate count=0 cat SendEmail.log | grep "ReqInputMsgLog" | awk -F "[" '{print $3}' | awk -F "," '{print $1}' > /con/scripts_server/file.txt for line in `cat /con/scripts_server/file.txt` do logdate=`echo $line | awk -F : '{print $1":"$2}'` if [[ $logdate < $enddate1 ]]; then count=`expr $count + 1` fi done echo $count But when we are trying to execute the script by the below command its not showing the proper count. ./sendemail.sh "2014-08-19 11:30" "2014-08-19 11:34" Log file is very big one. Small chunk has been posted here. INFO [SIBJMSRAThreadPool : 5] [2014-08-19 11:18:24,471] SendEmail - 8/19/14 11:18 AM,ECCF25B0-0147-4000-E000-1B830A3C05A9,ReqInputMsgLog,SendEmail,<?xml version="1.0" encoding="UTF-8"?> <in:sendEmailRequestMsg xmlns:in="http://EmailMed/EmailMedInterface" xmlns:ns0="wsdl.http://EmailMed/EmailMedInterface" xmlns:ns1="http://EmailMed/EmailMedInterface" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:me="wsdl.http://EmailMed/EmailMedInterface" xsi:type="me:sendEmailRequestMsg"> <in:sendEmail xmlns:xci0="http://EmailMed/EmailMedInterface"> INFO [SIBJMSRAThreadPool : 7] [2014-08-19 11:18:14,235] SendEmail - 8/19/14 11:18 AM,ECCEFDB2-0147-4000-E000-1B830A3C05A9,ReqInputMsgLog,SendEmail,<?xml version="1.0" encoding="UTF-8"?> <in:sendEmailRequestMsg xmlns:in="http://EmailMed/EmailMedInterface" xmlns:ns0="wsdl.http://EmailMed/EmailMedInterface" xmlns:ns1="http://EmailMed/EmailMedInterface" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:me="wsdl.http://EmailMed/EmailMedInterface" xsi:type="me:sendEmailRequestMsg"> <in:sendEmail xmlns:xci0="http://EmailMed/EmailMedInterface"> INFO [SIBJMSRAThreadPool : 7] [2014-08-19 11:18:14,241] SendEmail - xmlText: <?xml version="1.0" encoding="UTF-8"?> after awk command we will get a file "/con/scripts_server/file.txt" which looks similar like below: 2014-08-19 11:28:03 2014-08-19 11:28:06 2014-08-19 11:28:17 2014-08-19 11:28:53 2014-08-19 11:29:02 2014-08-19 11:29:47 2014-08-19 11:29:57 2014-08-19 11:30:07 2014-08-19 11:30:17 2014-08-19 11:30:19 2014-08-19 11:30:19 2014-08-19 11:30:22 2014-08-19 11:30:25 2014-08-19 11:30:25 2014-08-19 11:30:36 2014-08-19 11:30:51 2014-08-19 11:30:56 2014-08-19 11:30:59 2014-08-19 11:30:59 2014-08-19 11:31:08 2014-08-19 11:31:25 2014-08-19 11:32:19 2014-08-19 11:32:22 2014-08-19 11:32:27 2014-08-19 11:32:28 2014-08-19 11:32:41 2014-08-19 11:32:49 2014-08-19 11:32:59 2014-08-19 11:33:27 2014-08-19 11:33:41 2014-08-19 11:34:07 2014-08-19 11:34:14 2014-08-19 11:34:21 2014-08-19 11:34:25 2014-08-19 11:34:38 2014-08-19 11:34:50 2014-08-19 11:34:58

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  • mysql-connector-c++ - ‘get_driver_instance’ is not a member of ‘sql::mysql’

    - by rizzo0917
    I am a beginner at c++ and figured the only way I am going to learn is to get dirty with some code. I am trying to build a program that connects to a mysql database. I am using g++, on linux. With no ide. I run "make" and this is my error: hello.cpp:38: error: ‘get_driver_instance’ is not a member of ‘sql::mysql’ make: *** [hello.o] Error 1 Here is my code including makefile. Any Help would be great! Thanks in advance ###BEGIN hello.cpp### #include <stdlib.h> #include <iostream> #include <sstream> #include <stdexcept> #include "mysql_connection.h" #include <cppconn/driver.h> #include <cppconn/exception.h> #include <cppconn/resultset.h> #include <cppconn/statement.h> #include <cppconn/prepared_statement.h> #define EXAMPLE_HOST "localhost" #define EXAMPLE_USER "root" #define EXAMPLE_PASS "" #define EXAMPLE_DB "world" using namespace std; using namespace sql::mysql; int main(int argc, const char **argv) { string url(argc >= 2 ? argv[1] : EXAMPLE_HOST); const string user(argc >= 3 ? argv[2] : EXAMPLE_USER); const string pass(argc >= 4 ? argv[3] : EXAMPLE_PASS); const string database(argc >= 5 ? argv[4] : EXAMPLE_DB); cout << "Connector/C++ tutorial framework..." << endl; cout << endl; try { sql::Driver *driver; sql::Connection *con; sql::Statement *stmt; driver = sql::mysql::get_driver_instance(); con = driver->connect("tcp://127.0.0.1:3306", "user", "password"); stmt = con->createStatement(); stmt->execute("USE " EXAMPLE_DB); stmt->execute("DROP TABLE IF EXISTS test"); stmt->execute("CREATE TABLE test(id INT, label CHAR(1))"); stmt->execute("INSERT INTO test(id, label) VALUES (1, 'a')"); delete stmt; delete con; } catch (sql::SQLException &e) { /* The MySQL Connector/C++ throws three different exceptions: - sql::MethodNotImplementedException (derived from sql::SQLException) - sql::InvalidArgumentException (derived from sql::SQLException) - sql::SQLException (derived from std::runtime_error) */ cout << "# ERR: SQLException in " << __FILE__; cout << "(" << __FUNCTION__ << ") on line " << __LINE__ << endl; /* Use what() (derived from std::runtime_error) to fetch the error message */ cout << "# ERR: " << e.what(); cout << " (MySQL error code: " << e.getErrorCode(); cout << ", SQLState: " << e.getSQLState() << " )" << endl; return EXIT_FAILURE; } cout << "Done." << endl; return EXIT_SUCCESS; } ###END hello.cpp### ###BEGIN Make File### SRCS := hello.cpp OBJS := $(SRCS:.cpp=.o) CXXFLAGS := -Wall -pedantic INCPATHS := -I/home/user/mysql-connector/include/ LIBPATHS := -L/home/user/mysql-connector/lib/ -L/home/user/mysql-connector-c/lib/ LIBS := -static -lmysqlclient -mysqlcppconn-static EXE := MyExecutable $(EXE): $(OBJS) $(CXX) $(OBJS) $(LIBPATHS) $(LIBS) -o $@ .cpp.o: $(CXX) $(CXXFLAGS) $(INCPATHS) -c $< -o $@ ###End Makefile###

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  • How to echo if field is not found?

    - by Fahad
    Hi I'm trying to figure out how to echo back if the value entered does not match when a database lookup is done. I'm using ajax to run the request and php to do the lookup ajax.js: function showResult(str) { if (str=="") { document.getElementById("description").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("description").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","getuser.php?voucher="+str,true); xmlhttp.send(null); } and getuser.php: <?php $q=$_GET["voucher"]; $con = mysql_connect('localhost', 'root', ''); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("test", $con); $sql="SELECT * FROM redemption WHERE voucher = '".$q."'"; $result = mysql_query($sql); echo "<table> <tr> <th>Name</th> <th>Product</th> <th>Address</th> <th>Status</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['product'] . "</td>"; echo "<td>" . $row['address'] ." ".$row['city'] ." ".$row['province'] ." ".$row['postal'] . "</td>"; echo "<td>" . $row['status'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> What I would like to do is that once the person enters an invalid or a voucher number that is not found I would like to return an error that "Voucher number is not found". There is also a column in the db that stores the status such as "redeemed" or "not redeemed". How could I check for both whether the voucher number exists and if it has already been redeemed? I assume it'd have to be a syntax such as $sql="SELECT * FROM redemption WHERE voucher = '".$q."'" AND status = 'not redeemed' and then use an else or case statement perhaps? Thanks in advance

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  • javax.naming.NameNotFoundException: Name [comp/env] is not bound in this Context. Unable to find [comp] error with java scheduler

    - by Morgan Azhari
    What I'm trying to do is to update my database after a period of time. So I'm using java scheduler and connection pooling. I don't know why but my code only working once. It will print: init success success javax.naming.NameNotFoundException: Name [comp/env] is not bound in this Context. Unable to find [comp]. at org.apache.naming.NamingContext.lookup(NamingContext.java:820) at org.apache.naming.NamingContext.lookup(NamingContext.java:168) at org.apache.naming.SelectorContext.lookup(SelectorContext.java:158) at javax.naming.InitialContext.lookup(InitialContext.java:411) at test.Pool.main(Pool.java:25) ---> line 25 is Context envContext = (Context)initialContext.lookup("java:/comp/env"); I don't know why it only works once. I already test it if I didn't running it without java scheduler and it works fine. No error whatsoerver. Don't know why i get this error if I running it using scheduler. Hope someone can help me. My connection pooling code: public class Pool { public DataSource main() { try { InitialContext initialContext = new InitialContext(); Context envContext = (Context)initialContext.lookup("java:/comp/env"); DataSource datasource = new DataSource(); datasource = (DataSource)envContext.lookup("jdbc/test"); return datasource; } catch (Exception ex) { ex.printStackTrace(); } return null; } } my web.xml: <web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> <listener> <listener-class> package.test.Pool</listener-class> </listener> <resource-ref> <description>DB Connection Pooling</description> <res-ref-name>jdbc/test</res-ref-name> <res-type>javax.sql.DataSource</res-type> <res-auth>Container</res-auth> </resource-ref> Context.xml: <?xml version="1.0" encoding="UTF-8"?> <Context path="/project" reloadable="true"> <Resource auth="Container" defaultReadOnly="false" driverClassName="com.mysql.jdbc.Driver" factory="org.apache.tomcat.jdbc.pool.DataSourceFactory" initialSize="0" jdbcInterceptors="org.apache.tomcat.jdbc.pool.interceptor.ConnectionState;org.apache.tomcat.jdbc.pool.interceptor.StatementFinalizer" jmxEnabled="true" logAbandoned="true" maxActive="300" maxIdle="50" maxWait="10000" minEvictableIdleTimeMillis="300000" minIdle="30" name="jdbc/test" password="test" removeAbandoned="true" removeAbandonedTimeout="60" testOnBorrow="true" testOnReturn="false" testWhileIdle="true" timeBetweenEvictionRunsMillis="30000" type="javax.sql.DataSource" url="jdbc:mysql://localhost:3306/database?noAccessToProcedureBodies=true" username="root" validationInterval="30000" validationQuery="SELECT 1"/> </Context> my java scheduler public class Scheduler extends HttpServlet{ public void init() throws ServletException { System.out.println("init success"); try{ Scheduling_test test = new Scheduling_test(); ScheduledExecutorService executor = Executors.newScheduledThreadPool(100); ScheduledFuture future = executor.scheduleWithFixedDelay(test, 1, 60 ,TimeUnit.SECONDS); }catch(Exception e){ e.printStackTrace(); } } } Schedule_test public class Scheduling_test extends Thread implements Runnable{ public void run(){ Updating updating = new Updating(); updating.run(); } } updating public class Updating{ public void run(){ ResultSet rs = null; PreparedStatement p = null; StringBuilder sb = new StringBuilder(); Pool pool = new Pool(); Connection con = null; DataSource datasource = null; try{ datasource = pool.main(); con=datasource.getConnection(); sb.append("SELECT * FROM database"); p = con.prepareStatement(sb.toString()); rs = p.executeQuery(); rs.close(); con.close(); p.close(); datasource.close(); System.out.println("success"); }catch (Exception e){ e.printStackTrace(); } }

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  • Problem while inserting data from GUI layer to database

    - by Rahul
    Hi all, I am facing problem while i am inserting new record from GUI part to database table. I have created database table Patient with id, name, age etc....id is identity primary key. My problem is while i am inserting duplicate name in table the control should go to else part, and display the message like...This name is already exits, pls try with another name... but in my coding not getting..... Here is all the code...pls somebody point me out whats wrong or how do this??? GUILayer: protected void BtnSubmit_Click(object sender, EventArgs e) { if (!Page.IsValid) return; int intResult = 0; string name = TxtName.Text.Trim(); int age = Convert.ToInt32(TxtAge.Text); string gender; if (RadioButtonMale.Checked) { gender = RadioButtonMale.Text; } else { gender = RadioButtonFemale.Text; } string city = DropDownListCity.SelectedItem.Value; string typeofdisease = ""; foreach (ListItem li in CheckBoxListDisease.Items) { if (li.Selected) { typeofdisease += li.Value; } } typeofdisease = typeofdisease.TrimEnd(); PatientBAL PB = new PatientBAL(); PatientProperty obj = new PatientProperty(); obj.Name = name; obj.Age = age; obj.Gender = gender; obj.City = city; obj.TypeOFDisease = typeofdisease; try { intResult = PB.ADDPatient(obj); if (intResult > 0) { lblMessage.Text = "New record inserted successfully."; TxtName.Text = string.Empty; TxtAge.Text = string.Empty; RadioButtonMale.Enabled = false; RadioButtonFemale.Enabled = false; DropDownListCity.SelectedIndex = 0; CheckBoxListDisease.SelectedIndex = 0; } else { lblMessage.Text = "Name [<b>" + TxtName.Text + "</b>] alredy exists, try another name"; } } catch (Exception ex) { lblMessage.Text = ex.Message.ToString(); } finally { obj = null; PB = null; } } BAL layer: public class PatientBAL { public int ADDPatient(PatientProperty obj) { PatientDAL pdl = new PatientDAL(); try { return pdl.InsertData(obj); } catch { throw; } finally { pdl=null; } } } DAL layer: public class PatientDAL { public string ConString = ConfigurationManager.ConnectionStrings["ConString"].ConnectionString; public int InsertData(PatientProperty obj) { SqlConnection con = new SqlConnection(ConString); con.Open(); SqlCommand com = new SqlCommand("LoadData",con); com.CommandType = CommandType.StoredProcedure; try { com.Parameters.AddWithValue("@Name", obj.Name); com.Parameters.AddWithValue("@Age",obj.Age); com.Parameters.AddWithValue("@Gender",obj.Gender); com.Parameters.AddWithValue("@City", obj.City); com.Parameters.AddWithValue("@TypeOfDisease", obj.TypeOFDisease); return com.ExecuteNonQuery(); } catch { throw; } finally { com.Dispose(); con.Close(); } } } Property Class: public class PatientProperty { private string name; private int age; private string gender; private string city; private string typedisease; public string Name { get { return name; } set { name = value; } } public int Age { get { return age; } set { age = value; } } public string Gender { get { return gender; } set { gender = value; } } public string City { get { return city; } set { city = value; } } public string TypeOFDisease { get { return typedisease; } set { typedisease = value; } } } This is my stored Procedure: CREATE PROCEDURE LoadData ( @Name varchar(50), @Age int, @Gender char(10), @City char(10), @TypeofDisease varchar(50) ) as insert into Patient(Name, Age, Gender, City, TypeOfDisease)values(@Name,@Age, @Gender, @City, @TypeofDisease) GO

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  • having trouble in mysql if statement

    - by user225269
    I just want to simplify what I am doing before, having multiple php files for all data to be listed. Here is my html form: <table border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="post" action="list.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="3">List Students</td> </tr> <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option>Year</option> <option>Address</option> </select></td></td> </tr> <tr> <td width="10"><input align="right" type="submit" name="Submit" value="Submit" > </td> </tr> </form> </table> And here's the form action: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $gyear= $_POST['general']; if ("YEAR"==$_POST['general']) { $result = mysql_query("SELECT * FROM student WHERE YEAR='{$_POST["specific"]}'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>LASTNAME</th> <th>FIRSTNAME</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['LASTNAME'] . "</td>"; echo "<td>" . $row['FIRSTNAME'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?> Please help, how do I equate the YEAR(column in mysql database) and the option box(general). if ("YEAR"==$_POST['general']) please correct me if I'm wrong.

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  • retrieving value from database in java

    - by Akcire Atienza
    I am making AGAIN another program that retrieves the inputted data/values of fields from the database I created. but this time, my inputted value will be coming from the JtextField I created. I wonder what's wrong in here bec when I'm running it the output is always null. in this program i will convert the inputted value of my JTextField into int. here it is: public class ButtonHandler implements ActionListener { public void actionPerformed(ActionEvent e) { if(e.getSource() == extendB) { ExtensionForm extend = new ExtensionForm(); extend.setVisible(true); } else if(e.getSource()== searchB) { //get text from the textField String guest = guestIDTF.getText(); //parse the string to integer for retrieving of data int id = Integer.parseInt(guest); GuestsInfo guestInfo = new GuestsInfo(id); Room roomInfo = new Room(id); String labels[] = {guestInfo.getFirstName()+" "+guestInfo.getLastName(),""+roomInfo.getRoomNo(),roomInfo.getRoomType(),guestInfo.getTime(),"11:00"}; for(int z = 0; z<labels.length; z++) { labelDisplay[z].setText(labels[z]); } in my second class it retrieves the inputted values of fields from the database I created here's the code: import java.sql.*; public class Room { private String roomType; private int guestID, roomNo; private Connection con; private PreparedStatement statement; public Room(){ try { Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection( "jdbc:mysql://localhost:3306/3moronsdb","root",""); } catch (Exception e) { e.printStackTrace(); } } public Room(int guestsID) { this(); try{ statement = con.prepareStatement("SELECT * FROM guest WHERE guestID=?"); statement.setInt(1, guestID); ResultSet rs = statement.executeQuery(); while(rs.next()){ this.guestID = rs.getInt(1); this.roomType = rs.getString(2); this.roomNo = rs.getInt(3); } }catch(Exception e){ System.out.print(e); } } //Constructor for setting rate public Room(String roomType, int roomNo) { this(); try { statement = con.prepareStatement("Insert into room(roomType, roomNo) values(?,?)"); statement.setString(1, roomType); statement.setInt(2, roomNo); statement.executeUpdate(); } catch(Exception e) { e.printStackTrace(); return; } } //getting roomType public String getRoomType(){ return roomType; } //getting roomNo public int getRoomNo(){ return roomNo; } //getting guestID public int getGuestId(){ return guestID; } } i already insert some values in my 3moronsdb which are ( 1, Classic , 103). here's my TEST main class: public class TestMain { public static void main(String [] a){ GuestsInfo guest = new GuestsInfo(1); //note that this instantiation is the other class which i just ask the other day.. (http://stackoverflow.com/questions/12762835/retrieving-values-from-database-in-java) Room rum = new Room(1); System.out.print(rum.getRoomType()+" "+ guest.getFirstName()); } } when i'm running it it only gives me null output for the Room class but i am getting the output of the GuestsInfo class which is 'Ericka'. Can you help me guys? I know I ask this kind of problem yesterday but i really don't know what's wrong in here now..

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