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  • Join Query Help

    - by John
    Hello, The query below works well. It pulls data from two MySQL tables, "submission" and "login." I would like to also pull data from a third table called "comment" in the same database. The table "comment" has the following fields: commentid, loginid, submissionid, comment, datecommented Two of the fields in the table "login" are called "loginid" and "username." In the query below, I would like to count all "commentid" in "comment" where "loginid" equals the "loginid" in "login" where "username" equals "$profile." How can I do this? Thanks in advance, John $sqlStr1 = "SELECT l.username, l.loginid, s.loginid, s.submissionid, s.title, s.url, s.datesubmitted, s.displayurl, l.created, count(s.submissionid) countSubmissions FROM submission AS s INNER JOIN login AS l ON s.loginid = l.loginid WHERE l.username = '$profile'";

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  • MySql left join on several regs

    - by egidiocs
    Hi there! I have this table1 idproduct(PK) | date_to_go 1 2010-01-18 2 2010-02-01 3 2010-02-21 4 2010-02-03 and this other table2 that controls date_to_go updates id | idproduct(FK) | prev_date_to_go | date_to_go | update_date 1 1 2010-01-01 2010-01-05 2009-12-01 2 1 2010-01-05 2010-01-10 2009-12-20 3 1 2010-01-10 2010-01-18 2009-12-20 4 3 2010-01-20 2010-02-03 2010-01-05 So, in this example, for table1.idproduct #1 2010-01-18 is the actual date_to_go and 2010-01-01 (table2.prev_date_to_go, first reg) is the original date_to_go . using this query select v.idproduct, v.date_to_go, p.prev_date_to_go original_date_to_go from table1 v left join produto_datas p on p.idproduto = v.idproduto group by (v.idproduto) order by v.idproduto can I assume that original_date_to_go will be the first related reg of table2? idproduct | date_to_go | original_date_to_go 1 2010-01-18 2010-01-01 2 2010-02-01 NULL 3 2010-02-21 2010-01-20 4 2010-02-03 NULL

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  • Customizing Hibernate Criteria - Adding conditions to a left join

    - by Douglas Ferguson
    I need to be able to do the following: Select * from Table1 left join Table2 on id1 = id2 AND i1 = ? Hibernate criteria doesn't allow be to specify the i1 = ? part. The existing code is using hibernate criteria and it would be a huge refactor to swap out for HQL Does anybody have any tips how I could implement this differently or any way to override the Hibernate Criteria? I'm not opposed to cracking open hibernate and modifying, but when I began to dig it, there seems to be layers upon layers of abstractions. I never found the the point where SQL is actually generated...

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  • Dealing w/ Sqlite Join results in a cursor

    - by Bill
    I have a one-many relationship in my local Sqlite db. Pretty basic stuff. When I do my left outer join I get back results that look like this: the resulting cursor has multiple rows that look like this: A1.id | A1.column1 | A1.column2 | B1.a_id_fk | B1.column1 | B1.column2 A1.id | A1.column1 | A1.column2 | B2.a_id_fk | B2.column1 | B2.column2 and so on... Is there a standard practice or method of dealing with results like this ? Clearly there is only A1, but it has many B-n relationships. I am coming close to using multiple queries instead of the "relational db way". Hopefully I am just not aware of the better way to do things. I intend to expose this query via a content provider and I would hate for all of the consumers to have to write the same aggregation logic.

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  • mySQL Left Join on multiple tables

    - by Jarrod
    Hi I'm really struggling with this query. I have 4 tables (http://oberto.co.nz/db-sql.png): Invoice_Payement, Invoice, Client and Calendar. I'm trying to create a report by summing up the 'paid_amount' col, in Invoice_Payment, by month/year. The query needs to include all months, even those with no data There query needs the condition (Invoice table): registered_id = [id] I have tried with the below query, which works, but falls short when 'paid_date' does not have any records for a month. The outcome is that month does not show in the results I added a Calendar table to resolved this but not sure how to left join to it. SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Please see the above link for a basic ERD diagram of my scenario. Thanks for reading. I've posted this Q before but I think I worded it badly.

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  • Doctrine Join DQL

    - by koko
    I's like to do a join between 2 tables on a specific ID. At the moment, I have this DQL: $q = Doctrine_Query::create() ->select('e.*, i.itemName, i.itemtypeId') ->from('Model_EventItem e') ->leftJoin('Model_Item i ON e.itemId = i.itemId') ->where('e.eventitemId = ?', $event->eventId) ->orderBy('i.itemName ASC'); The result is empty, although my eventId has a value ... Can you help me please? I there somewhere a tutorial on DQL-joins? I don't get it right with the help of the Doctrine documentation. Thanks! PS I have doctrine working in combination with Zend Framework.

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  • SQL query for getting count on same table using left outer join

    - by Sasi
    Hi all, I have a table from which i need to get the count grouped on two columns. the table has two columns one datetime column and another one is success value(-1,1,0) What i am looking for is something like this... count of success value for each month month----success-----count 11------- -1 ------- 50 11------- 1 --------- 50 11------- 0 ------- 50 12------- -1 ------- 50 12------- 1 ------- 50 12------- 0 ------- 50 if there is no success value for a month then the count should be null or zero. I have tried with left outer join as well but of no use it gives the count incorrectly. Thanks in advance Sasi

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  • mysql filtering result using left outer join

    - by user288178
    my query: SELECT content.*, activity_log.content_id FROM content LEFT JOIN activity_log ON content.id = activity_log.content_id AND sess_id = '$sess_id' WHERE activity_log.content_id IS NULL AND visibility = $visibility AND content.reported < ".REPORTED_LIMIT." AND content.file_ready = 1 LIMIT 1 The purpose of that query is to get 1 row from the content table that has not been viewed by the user (identified by session_id), but it still returns contents that have been viewed. What is wrong? ( I have checked the table making sure that the content_ids are there) Note: I think this is more efficient than using subqueries, thoughts?

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  • Left Join not returning all rows

    - by DisgruntledGoat
    I have this query in MySQL: SELECT pr.*, pr7.value AS `room_price_high` FROM `jos_hp_properties` pr LEFT OUTER JOIN `jos_hp_properties2` pr7 ON pr7.property=pr.id WHERE pr7.field=23 The jos_hp_properties table has 27 rows but the query only returns one. Based on this question I think it may be because of the WHERE clause. The jos_hp_properties2 table has fields id, property, field, value, where field is a foreign key to a third table (which I don't need to get data from). Is there a way to select all the rows from the first table, including the value from table #2 where the field is 23 (or NULL if there is no field 23)?

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  • HQL join after output of subquery

    - by user350374
    Hey, Say I have 3 classes class foo1 { List prop1;} class foo2 { foo3 prop2;} class foo3{ int Id;} now I want to select distinct foo2's from foo1 and get Id of foo3. I need to write a HQL stmt for the same. I tried the following select c.Id from (select distinct(a.prop1) from foo1.prop1 as a ) as b inner join b.prop2 as c This throws an 'Antlr.Runtime.NoViableAltException How do you suggest I should go about the same. Please note the inner subquery is working fine. So if I have made some mistakes in there please ignore that. I need a method to do the latter. Thanks in Advance.

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  • Rails has_and_belongs_to_many join across 3 tables

    - by Birdman
    I have a three models: listing, category, and site. There is a many to many relationship between listing and site and there is a many to many relationship between listing and category. A listing thus belongs to one or more sites and one or more categories (a listing can appear on multiple sites and multiple categories). Given a site id and a category id, I want a set of all the listings. I understand how to get the listings from a site id (listings = site.listings) and how to get the listings from a category id (listings = category.listings), but how do I get the triple join of the set of listings from both a site id and category id? The sql would look something like (sit_id and cat_id are input): select l.name from listings l, categories_listings cl, listings_sites, ls where cl.category_id = cat_id and ls.site_id = sit_id and cl.listing_id = l.id and ls.listing_id = l.id Thanks in advance

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  • join two oracle queries

    - by coder247
    I've to query from two tables and want one result.. how can i join these two queries? First query is querying from two tables and the second one is only from one. select pt.id,pt.promorow,pt.promocolumn,pt.type,pt.image,pt.style,pt.quota_allowed,ptc.text,pq.quota_left from promotables pt,promogroups pg ,promotablecontents ptc ,promoquotas pq where pt.id_promogroup = 1 and ptc.country ='049' and ptc.id_promotable = pt.id and pt.id_promogroup = pg.id and pq.id_promotable = pt.id order by pt.promorow,pt.promocolumn select pt.id,pt.promorow,pt.promocolumn,pt.type,pt.image,pt.style,pt.quota_allowed from promotables pt where pt.type='heading'

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  • Scalable way of doing self join with many to many table

    - by johnathan
    I have a table structure like the following: user id name profile_stat id name profile_stat_value id name user_profile user_id profile_stat_id profile_stat_value_id My question is: How do I evaluate a query where I want to find all users with profile_stat_id and profile_stat_value_id for many stats? I've tried doing an inner self join, but that quickly gets crazy when searching for many stats. I've also tried doing a count on the actual user_profile table, and that's much better, but still slow. Is there some magic I'm missing? I have about 10 million rows in the user_profile table and want the query to take no longer than a few seconds. Is that possible?

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  • How do I replace NOT EXISTS with JOIN?

    - by YelizavetaYR
    I've got the following query: select distinct a.id, a.name from Employee a join Dependencies b on a.id = b.eid where not exists ( select * from Dependencies d where b.id = d.id and d.name = 'Apple' ) and exists ( select * from Dependencies c where b.id = c.id and c.name = 'Orange' ); I have two tables, relatively simple. The first Employee has an id column and a name column The second table Dependencies has 3 column, an id, an eid (employee id to link) and names (apple, orange etc). the data looks like this Employee table looks like this id | name ----------- 1 | Pat 2 | Tom 3 | Rob 4 | Sam Dependencies id | eid | Name -------------------- 1 | 1 | Orange 2 | 1 | Apple 3 | 2 | Strawberry 4 | 2 | Apple 5 | 3 | Orange 6 | 3 | Banana As you can see Pat has both Orange and Apple and he needs to be excluded and it has to be via joins and i can't seem to get it to work. Ultimately the data should only return Rob

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  • mysql join default value

    - by andy
    I've been trying to use the IsNull() function to ensure that there is a value for a field. $result = mysql_query(" SELECT crawled.id,IsNull(sranking.score,0) as Score,crawled.url,crawled.title,crawled.blurb FROM crawled LEFT JOIN sranking ON crawled.id = sranking.sid WHERE crawled.body LIKE '%".$term."%' ORDER BY Score DESC LIMIT " . $start . "," . $c . " ") or die(mysql_error()); But I get the error message:Incorrect parameter count in the call to native function 'IsNull' Anybody have any ideas? I'm pretty new to mySQL.

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  • MySQL Query Join Table Selecting Highest Date Value

    - by ALHUI
    Here is the query that I run SELECT cl.cl_id, cc_rego, cc_model, cl_dateIn, cl_dateOut FROM courtesycar cc LEFT JOIN courtesyloan cl ON cc.cc_id = cl.cc_id Results: 1 NXI955 Prado 2013-10-24 11:48:38 NULL 2 RJI603 Avalon 2013-10-24 11:48:42 2013-10-24 11:54:18 3 RJI603 Avalon 2013-10-24 12:01:40 NULL The results that I wanted are to group by the cc_rego values and print the most recent cl_dateIn value. (Only Display Rows 1,3) Ive tried to use MAX on the date and group by clause, but it combines rows, 2 & 3 together showing both the highest value of dateIn and dateOut. Any help will be appreciated.

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  • MySQL - Join as zero if record Not IN

    - by Zurahn
    To explain by example, take two tables, A and B Table A id foo 1 x 2 y 3 z Table B id aid bar 1 3 50 2 1 100 An example join SELECT foo, bar FROM a, b WHERE a.id = b.aid; Garners a result of foo bar z 50 x 100 What I would like to do is get all values of foo and for any instances where there isn't a corresponding bar value, return 0 for that column. My best guess was something along the lines of SELECT foo, bar AS br FROM a, b WHERE a.id = b.aid OR a.id NOT IN (SELECT aid FROM b); But that returns duplicates and non-zero values for bar. Possible?

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  • MySQL, join one item to multiple items in a single query

    - by bschaeffer
    Say I've got two tables. One contains a list of items, and one contains pictures of the items. Something like this: Items +----+---------+ | id | name | +----+---------+ | 1 | oranges | | 2 | apples | +----+---------+ Pictures +----+---------+ | id | item_id | +----+---------+ | 1 | 1 | | 2 | 2 | | 3 | 2 | +----+---------+ My question is this: is it possible in a single query to select item 2 from Items and join all the rows in the Pictures table whose item_id references that same id? I am sure I've tried almost everything I can think of, but nothing is coming to mind. I apologize if the answer to this is simple, but It's just escaping me right now.

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  • Oracle SQL outer join query puzzle

    - by user1651446
    So I am dumb and I have this: select whatever from bank_accs b1, bank_accs b2, table3 t3 where t3.bank_acc_id = t1.bank_acc_id and b2.bank_acc_number = b1.bank_acc_number and b2.currency_code(+) = t3.buy_currency and trunc(sysdate) between nvl(b2.start_date, trunc(sysdate)) and nvl(b2.end_date, trunc(sysdate)); My problem is with the date (actuality) check on b2. Now, I need to return a row for each t3xb1 (t3 = ~10 tables joined, of course), even if there are ONLY INVALID records (date-wise) in b2. How do I outer-join this bit properly? Can't use ANSI joins, must do in a single flat query. Thanks.

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  • MYSQL: How to limit inner join?

    - by Sergii Rechmp
    I need some help with my query. I have 2 tables: all: art|serie sootv: name|art|foo I need to get result like name|serie. My query is: SELECT t2.NAME, t1.serie FROM ( SELECT * FROM `all` WHERE `serie` LIKE '$serie' ) t1 INNER JOIN sootv t2 ON t1.art = t2.art; it works, but sootv table contains data like name|art|foo abc | 1 | 5 abc | 1 | 6 i get 2 same results. Its not what i need. Help me please - how i can get only one result: abc|1 Thanks.

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  • Sum of distinc rows after a 1-many table join

    - by Lock
    I have 2 tables that I am joining. Table 1 has 1-many relationship with table 2. That is, table 2 can return multiple rows for a single row of table 1. Because of this, the records of table 1 is duplicated for as many rows as are on table 2.. which is expected. Now, I have a sum on one of the columns from table 1, but because of the multiple rows that get returned on the join, the sum is obviously multiplying. Is there a way to get this number back to its original number? I tried dividing by the count of rows from table 2 but this didnt quite give me the expected result. Are there any analytical functions that could do this? I almost want something like "if this row has not yet been counted in the sum, add it to the sum"

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  • MySQL Join a Table if Exists Question

    - by swhitlow
    I have a DB which has a table called "config". This table could possibly have a "config_cstm" table that is related by the id to the config table. I was wondering - is there a way to dynamically check for the existence of this table in one simple select statement? In other words, something like: "select * from config (IF EXISTS config_cstm THEN LEFT OUTER JOIN config_cstm ON config.id = config_cstm.id_c" I know how I would go about checking for the existence of an existing table in PHP. I was wanting to do this all in one MySQL statement though. Any suggestions? Thanks!

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  • Count, inner join

    - by Urosh
    I have two tables: DRIVER (Driver_Id,First name,Last name,...) PARTICIPANT IN CAR ACCIDENT (Participant_Id,Driver_Id-foreign key,responsibility-yes or no,...) Now, I need to find out which driver participated in accident where responsibility is 'YES', and how many times. I did this: Select Driver_ID, COUNT (Participant.Driver_ID)as 'Number of accidents' from Participant in car accident where responsibility='YES' group by Driver_ID order by COUNT (Participant.Driver_ID) desc But, I need to add drivers first and last name from the first table(using inner join, I suppose). I don't know how, because it is not contained in either an aggregate function or the GROUP BY clause. Please help :)

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  • left join without duplicate values using MIN()

    - by Clipper87
    I have a table_1: id custno 1 1 2 2 3 3 and a table_2: id custno qty descr 1 1 10 a 2 1 7 b 3 2 4 c 4 3 7 d 5 1 5 e 6 1 5 f When I run this query to show the minimum order quantities from every customer: SELECT DISTINCT table_1.custno,table_2.qty,table_2.descr FROM table_1 LEFT OUTER JOIN table_2 ON table_1.custno = table_2.custno AND qty = (SELECT MIN(qty) FROM table_2 WHERE table_2.custno = table_1.custno ) Then I get this result: custno qty descr 1 5 e 1 5 f 2 4 c 3 7 d Customer 1 appears twice each time with the same minimum qty (& a different description) but I only want to see customer 1 appear once. I don't care if that is the record with 'e' as a description or 'f' as a description. How could I do this ? Thx!

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  • SQL SERVER – Subquery or Join – Various Options – SQL Server Engine knows the Best

    - by pinaldave
    This is followup post of my earlier article SQL SERVER – Convert IN to EXISTS – Performance Talk, after reading all the comments I have received I felt that I could write more on the same subject to clear few things out. First let us run following four queries, all of them are giving exactly same resultset. USE AdventureWorks GO -- use of = SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID = ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO -- use of in SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID IN ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO -- use of exists SELECT * FROM HumanResources.Employee E WHERE EXISTS ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO -- Use of Join SELECT * FROM HumanResources.Employee E INNER JOIN HumanResources.EmployeeAddress EA ON E.EmployeeID = EA.EmployeeID GO Let us compare the execution plan of the queries listed above. Click on image to see larger image. It is quite clear from the execution plan that in case of IN, EXISTS and JOIN SQL Server Engines is smart enough to figure out what is the best optimal plan of Merge Join for the same query and execute the same. However, in the case of use of Equal (=) Operator, SQL Server is forced to use Nested Loop and test each result of the inner query and compare to outer query, leading to cut the performance. Please note that here I no mean suggesting that Nested Loop is bad or Merge Join is better. This can very well vary on your machine and amount of resources available on your computer. When I see Equal (=) operator used in query like above, I usually recommend to see if user can use IN or EXISTS or JOIN. As I said, this can very much vary on different system. What is your take in above query? I believe SQL Server Engines is usually pretty smart to figure out what is ideal execution plan and use it. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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