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  • Mac OS X keeps "old" environment variable around

    - by Xymak1y
    So far I had /Applications/play-1.2.5/ added to my $PATH variable. Now I'm working with 2.2.1, which I installed in /Applications/play-2.2.1 and changed in ~/.bash_profile (which is getting sourced at startup). However, when printing $PATH, 1.2.5 is somehow still around: mbp:~ user$ echo $PATH /usr/local/share/npm/bin:/Applications/play-2.2.1:/usr/local/heroku/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/Applications/play-1.2.5:/Applications/XAMPP/xamppfiles/bin/:/opt/X11/bin As far as I now, I only entered $PATH variables in .bash_profile, which looks like this: mbp:~ user$ cat .bash_profile source ~/.git-completion.bash ### Added by the Heroku Toolbelt export PATH="/usr/local/heroku/bin:$PATH" ### Play Framework export PATH="/Applications/play-2.2.1:$PATH" export PATH="/usr/local/share/npm/bin:$PATH" I'm also not sure where the XAMPP extension to the variable comes from. Can I see somewhere which other files are being sourced on startup?

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  • Bootstrapped Ubuntu 12.04 EC2 instance. Where to find log?

    - by nocode
    So I bootstrapped a shell script to install and run a bunch of tasks. Looks like the it ran for the most part, but I added one part and that was formatting an extra EBS volume. Pretty straightforward: mkfs.ext4 /dev/xvdf mkdir –m 000 /vol01 echo “/dev/xvdf /vol01 auto noatime 0 0” | sudo tee –a /etc/fstab sudo mount /vol01 I was able to install MongoDB, NGINX and Forever. I selected to use /dev/xdvf in the AWS console and see it. The 3rd line is not in fstab either. I've searched through various logs in /var/log/ but I don't really see much indicating the execution of the bootstrap. Logs that I see and looked through: auth.log boot.log dmesg dpkg.log syslog udev

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  • Shell script to read value from a file and compare it to another one

    - by maneeshshetty
    I have a C program which puts one unique value inside a test file (it would be a two digit number). Now I want to run a shell script to read that number and then compare with my required number (e.g. 40). The comparison should deliver "equal to" or "greater". For example: The output of the C program is written into the file called c.txt with the value 36, and I want to compare it with the number 40. So I want that comparison to be "equal to" or "greater" and then echo the value "equal" or "greater".

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  • Problem with Json in Jquery

    - by Davidslv
    Hi everyone, I have a small survey, but when i submit it says that the msg is null, i don't see where is my error. If you could help me i apreciate it. Thank you My Form with Jquery and Ajax Function <!DOCTYPE HTML> <hmtl lang="pt-PT"> <head> <title>Formul&aacute;rio</title> <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script> </head> <body> <hr /> <h3>Formulario</h3> <script type="text/javascript" charset="utf-8"> $(function () { $('#submiter').click( function() { $.ajax({ type: "POST", url: 'validar.php', dataType: 'json', success: function(msg) { alert('Mensagem '+ msg.mensagem); }, error : function () { alert('Ocorreu um erro'); } }); }); }); </script> <form id="formulario" action="" method="post" accept-charset="utf-8"> <p>Pergunta 1</p> <label for="pergunta1">sim</label><input type="radio" id="p1" name="pergunta1" value="1" /><br /> <label for="pergunta1">n&atilde;o</label><input type="radio" id="p1" name="pergunta1" value="0" /> <br /> <p>Pergunta 2</p> <label for="pergunta2">sim</label><input type="radio" name="pergunta2" value="0" /><br /> <label for="pergunta2">n&atilde;o</label><input type="radio" name="pergunta2" value="1" /> <br /> <p>Pergunta 3</p> <label for="pergunta3">sim</label><input type="radio" name="pergunta3" value="0" /><br /> <label for="pergunta3">n&atilde;o</label><input type="radio" name="pergunta3" value="1" /> <br /> <p>Pergunta 4</p> <label for="pergunta4">sim</label><input type="radio" name="pergunta4" value="0" /><br /> <label for="pergunta4">n&atilde;o</label><input type="radio" name="pergunta4" value="1" /> <br /> <p><input type="submit" id="submiter" value="Continue &rarr;"></p> </form> </body> </html> My PHP <?php if($_POST) { $pergunta1 = $_POST['pergunta1']; $pergunta2 = $_POST['pergunta2']; $pergunta3 = $_POST['pergunta3']; $pergunta4 = $_POST['pergunta4']; $calcular = $pergunta1 + $pergunta2 + $pergunta3 + $pergunta4; $var = array ('mensagem' => $calcular); echo json_encode($var); } else { $var2 = array('mensagem' => 'sem resultado'); echo json_encode($var2); } ?>

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  • How can I modify the BAT file in this post so it will randomly select 1 background contained in a folder containing multiple backgrounds?

    - by Radical924
    Is there a way to modify the bat file from this post here: How do I set the desktop background on Windows from a script? so that it will randomly select 1 background image from a folder containing multiple images??? AND I would also like the background to randomly change to one of the backgrounds randomly contained in the same folder. If this is possible how would I modify the bat file below??? @echo off reg add "hkcu\control panel\desktop" /v wallpaper /t REG_SZ /d "" /f reg add "hkcu\control panel\desktop" /v wallpaper /t REG_SZ /d "C:\[LOCATION OF WALLPAPER HERE]" /f reg delete "hkcu\Software\Microsoft\Internet Explorer\Desktop\General" /v WallpaperStyle /f reg add "hkcu\control panel\desktop" /v WallpaperStyle /t REG_SZ /d 2 /f RUNDLL32.EXE user32.dll,UpdatePerUserSystemParameters exit Also I noticed that this bat file won't work usually (9 times out of 10)... I receive an "ERROR: The system was unable to find the specified registry key or value." I have Windows 7 64-BIT Home Premium Service Pack 1

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  • how to include screen's session name in hardstatus?

    - by fungusakafungus
    I use different screen sessions for different projects. Starting screen like screen -S project1. Now, I'd like to mention 'project1' in hardstatus line. Session name can be obtained from environment variable STY: STY=13539.project1. But how to get this into screen? I've tried backtick command and %` in hardstatus, but I can't seem to get it right. What I did: .screenrc: hardstatus string '%H:%`' backtick 0 30 30 echo $STY no luck, empty %`. backtick 0 30 30 sessionname still no luck, sessionname: Not found

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  • Add folder name to beginning of filename - getting multiple renames

    - by Flibble Wibble
    I've used dbenham's excellent response to the question of how to add the folder name to the beginning of a filename in a cmd script. @echo off pushd "Folder" for /d %%D in (*) do ( for %%F in ("%%~D\*") do ( for %%P in ("%%F\..") do ( ren "%%F" "%%~nxP_%%~nxF" ) ) ) popd What I'm finding is that seemingly randomly (though it probably isn't) sometimes the script will run through several child folders and rename correctly but then it gets to a folder where it gets stuck in a loop and starts adding the folder name repeatedly to the file inside. I have 90,000 files in 300 folders to rename this weekend. Any chance you can guess the cause? PS: Is there a maximum number of files that are acceptable in each folder?

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  • BASH_ENV ignored on solaris?

    - by Peeter Joot
    In my .bash_profile, executed for both my interactive and non-interactive logins are BASH_ENV=$HOME/.myinteractivestuff export BASH_ENV doing this for bash on Linux works fine, but on Solaris is not sourced: bash --version GNU bash, version 3.00.16(1)-release (sparc-sun-solaris2.10) Curiously, if I invoke screen within my login shell, BASH_ENV is then read. Are any restrictions on when $BASH_ENV is respected on Solaris? In my case I'm logging in with ssh using putty, but also tried unix to unix ssh, and telnet and see the same. Note that I know that my BASH_ENV variable assignment is being executed since I can echo this variable after login without any trouble (ie: ruling out the obvious possibility that my .bash_profile is also not being read).

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  • Open Terminal Here, as Root (OS X)

    - by cwd
    There is a pretty awesome applescript called "Open Terminal Here" ( http://www.entropy.ch/software/applescript/ ) which you can add to your finder's toolbar and click when you want to launch a terminal console which is set to that directory. Sometimes I need to be root, and so I end up starting terminal, doing something like sudo -i and then I have to change back to the previous directory because the sudo command is landing me in /var/root. I'm using sudo -i because I like it to load things like aliases / the bash profile. The script is applescript, and here's the important part of how it works: ... set cmd to "cd " & quoted form of the_path & " && echo $'\\ec'" ... tell application "Terminal" activate do script with command cmd How do I get this to load as root?

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  • cPanel configuration appears to allow unauthenticated SMTP - how to fix?

    - by ttsiodras
    One of my clients is using a cPanel-based Virtual Dedicated Server that appears to allow unauthenticated SMTP: bash$ echo EHLO | nc mail.clientscompany.com 25 ... 250-SIZE 52428800 250-PIPELINING 250-AUTH PLAIN LOGIN 250-STARTTLS 250 HELP It therefore appears that anyone (esp. spammers) can use his mail server to send whatever - I just connected from my DSL connection at home, and... bash$ nc mail.clientscompany.com 25 HELO clientscompany.com MAIL FROM: [email protected] RCPT TO: [email protected] DATA From: <[email protected]> To: <[email protected]> Date: ... Subject: ... Blah . QUIT I just tested this, and sure enough, it sent a mail from "[email protected]". Since I am not familiar with cPanel and WHM, can someone provide pointers to configure his mail server to (a) only accept TLS connections and (b) only authenticated ones (i.e. with user/password, not just plain connections). Thanks for any help.

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  • mysql_fetch_array() problem

    - by Marty
    So I have 3 DB tables that are all identical in every way (data is different) except the name of the table. I did this so I could use one piece of code with a switch like so: function disp_bestof($atts) { extract(shortcode_atts(array( 'topic' => '' ), $atts)); $connect = mysql_connect("localhost","foo","bar"); if (!$connect) { die('Could not connect: ' . mysql_error()); } switch ($topic) { case "attorneys": $bestof_query = "SELECT * FROM attorneys p JOIN (awards a, categories c, awardLevels l) ON (a.id = p.id AND c.id = a.category AND l.id = a.level) ORDER BY a.category, a.level ASC"; $category_query = "SELECT * FROM categories"; $db = mysql_select_db('roanoke_BestOf_TopAttorneys'); $query = mysql_query($bestof_query); $categoryQuery = mysql_query($category_query); break; case "physicians": $bestof_query = "SELECT * FROM physicians p JOIN (awards a, categories c, awardLevels l) ON (a.id = p.id AND c.id = a.category AND l.id = a.level) ORDER BY a.category, a.level ASC"; $category_query = "SELECT * FROM categories"; $db = mysql_select_db('roanoke_BestOf_TopDocs'); $query = mysql_query($bestof_query); $categoryQuery = mysql_query($category_query); break; case "dining": $bestof_query = "SELECT * FROM restaurants p JOIN (awards a, categories c, awardLevels l) ON (a.id = p.id AND c.id = a.category AND l.id = a.level) ORDER BY a.category, a.level ASC"; $category_query = "SELECT * FROM categories"; $db = mysql_select_db('roanoke_BestOf_DiningAwards'); $query = mysql_query($bestof_query); $categoryQuery = mysql_query($category_query); break; default: $bestof_query = "switch on $best did not match required case(s)"; break; } $category = ''; while( $result = mysql_fetch_array($query) ) { if( $result['category'] != $category ) { $category = $result['category']; //echo "<div class\"category\">"; $bestof_content .= "<h2>".$category."</h2>\n"; //echo "<ul>"; Now, this whole thing works PERFECT for the first two cases, but the third one "dining" breaks with this error: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource ... on line 78 Line 78 is the while() at the bottom. I have checked and double checked and can't figure what the problem is. Here's the DB structure for 'restaurants': CREATE TABLE `restaurants` ( `id` int(10) NOT NULL auto_increment, `restaurant` varchar(255) default NULL, `address1` varchar(255) default NULL, `address2` varchar(255) default NULL, `city` varchar(255) default NULL, `state` varchar(255) default NULL, `zip` double default NULL, `phone` double default NULL, `URI` varchar(255) default NULL, `neighborhood` varchar(255) default NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=249 DEFAULT CHARSET=utf8 Does anyone see what I'm doing wrong here? I'm passing "dining" to the function and as I said before, the first two cases in the switch work fine. I'm sure it's something stupid...

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  • HOSTNAME environment variable on Linux

    - by infogrind
    On my Linux box (Gentoo Linux 2.6.31 to be specific) I have noticed that the HOSTNAME environment variable is available in my shell, but not in scripts. For example, $ echo $HOSTNAME returns xxxxxxxx.com, but $ ruby -e 'puts ENV["HOSTNAME"]' returns nil On the other hand, the USER environment variable, for instance, is available both in the shell and in scripts. I have noticed that USER appears in the list of environment variables that appears when I type export i.e., declare -x USER="infogrind" but HOSTNAME doesn't. I suspect the issue has something to do with that. My questions: 1) how can I make HOSTNAME available in scripts, and 2) for my better understanding, where is this variable initially set, and why is it not "exported"?

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  • Restarting Nagios Using PHP

    - by X-Ware
    I am making a tool that is interacting with NAGIOS where some config files should be added so a restart will be needed. What I need to know is how to restart NAGIOS using PHP code since this tool is written in PHP .. when I try to do this using: shell_exec("service nagios restart"); changes do not take place but when I do this manually by the console all changes I did using the PHP script are applied ... after 2 minutes research I found that I am asking linux to execut this command while I am logged in as apache user so I changed the command to: shell_exec('echo "mypass" | sudo -S service nagios restart'); still having the same problem ... new config files are not read until I restart manually any suggestions will be appreciated :)

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  • Apache+FastCGI Timeout Error: "has failed to remain running for 30 seconds given 3 attempts, its restart interval has been backed off to 600 seconds"

    - by Sadjad Fouladi
    I've recently installed mod_fastcgi and Apache 2.2. I have a simple cgi script as below (test.fcgi): #!/bin/sh echo sadjad But when I invoke 'mysite.com/test.fcgi' I see "Internal Server Error" after a short period of time. The error.log file shows this error message: [Tue Jan 31 22:23:57 2006] [warn] FastCGI: (dynamic) server "~/public_html/oaduluth/dispatch.fcgi" has failed to remain running for 30 seconds given 3 attempts, its restart interval has been backed off to 600 seconds This is my .htaccess file: AddHandler fastcgi-script .fcgi RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ django.fcgi/$1 [QSA,L] What could the problem be? Is it my .htaccess file?

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  • Runtime error in C code (strange double conversion)

    - by Miro Hassan
    I have a strange runtime error in my C code. The Integers comparison here works fine. But in the Decimals comparison, I always get that the second number is larger than the first number, which is false. I am pretty new to C and programming in general, so this is a complex application to me. #include <stdio.h> #include <stdbool.h> #include <stdlib.h> int choose; long long neLimit = -1000000000; long long limit = 1000000000; bool big(a,b) { if ((a >= limit) || (b >= limit)) return true; else if ((a <= neLimit) || (b <= neLimit)) return true; return false; } void largerr(a,b) { if (a > b) printf("\nThe First Number is larger ..\n"); else if (a < b) printf("\nThe Second Number is larger ..\n"); else printf("\nThe Two Numbers are Equal .. \n"); } int main() { system("color e && title Numbers Comparison && echo off && cls"); start:{ printf("Choose a Type of Comparison :\n\t1. Integers\n\t2. Decimals \n\t\t I Choose Number : "); scanf("%i", &choose); switch(choose) { case 1: goto Integers; break; case 2: goto Decimals; break; default: system("echo Please Choose a Valid Option && pause>nul && cls"); goto start; } } Integers: { system("title Integers Comparison && cls"); long x , y; printf("\nFirst Number : \t"); scanf("%li", &x); printf("\nSecond Number : "); scanf("%li", &y); if (big(x,y)) { printf("\nOut of Limit .. Too Big Numbers ..\n"); system("pause>nul && cls") ; goto Integers; } largerr(x,y); printf("\nFirst Number : %li\nSecond Number : %li\n",x,y); goto exif; } Decimals: { system("title Decimals Comparison && cls"); double x , y; printf("\nFirst Number : \t"); scanf("%le", &x); printf("\nSecond Number : "); scanf("%le", &y); if (big(x,y)) { printf("\nOut of Limit .. Too Big Numbers ..\n"); system("pause>nul && cls") ; goto Decimals; } largerr(x,y); goto exif; } exif:{ system("pause>nul"); system("cls"); main(); } }

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  • PHP - Accessing a value selected in Combobox

    - by Pavitar
    I want to write a code that should let me select from a drop down list and onClick of a button load the data from a mysql database.However I cannot access the value selected in the drop down menu.I have tried to access them by $_POST['var_name'] but still can't do it. I'm new to PHP. Following is my code: <?php function load(){ $department = $_POST['dept']; $employee = $_POST['emp']; //echo "$department"; //echo "$employee"; $con = mysqli_connect("localhost", "root", "pwd", "payroll"); $rs = $con->query("select * from dept where deptno='$department'"); $row = $rs->fetch_row(); $n = $row[0]; $rs->free(); $con->close(); } ?> <html> <head> <title>Payroll</title> </head> <body> <h1 align="center">IIT Department</h1> <form method="post"> <table align="center"> <tr> <td> Dept Number: <select name="dept"> <option value="10" selected="selected">10</option> <option value="20">20</option> <option value="30">30</option> <option value="40">40</option> </select> </td> <td> <input type="button" value="ShowDeptEmp" name="btn1"> </td> <td> Job: <select name="job"> <option value="President" selected="selected">President</option> <option value="Manager">Manager</option> <option value="Clerk">Clerk</option> <option value="Salesman">Salesman</option> <option value="Analyst">Analyst</option> </select> </td> <td> <input type="button" value="ShowJobEmp" name="btn1"> </td> </tr> </table> </form> <?php if(isset($_POST['dept']) && $_POST['dept'] != "") load(); ?> </body> </html>

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  • Different behaviour of script locally and over ssh

    - by neorg
    I have a script on a server-A Script-A #!/bin/bash -l echo "script-A.sh" | change-environment.sh When I ssh onto server-A and execute it, it works fine. However, when I ssh user@server-A ./script-A.sh Script-A executes, but throws an undefined variable error in change-environment.sh. change-environment.sh runs in the c shell(I have no control over the script so the method I have used is about the only way I can use it), but everything else is in bash. Had found a similar question at I can run a script locally, but cannot do "ssh HOSTNAME /path/to/script.sh". However, there was no solution to the issue and it was a year old.

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  • psql editor setting on Ubuntu

    - by dezso
    The situation is the following. This is an Ubuntu box: Linux ns3mx3 2.6.32-41-server #89-Ubuntu SMP Fri Apr 27 22:33:31 UTC 2012 x86_64 GNU/Linux Which means that when I first issue \e in psql, I'm asked to choose an editor. Then there is the .selected_editor file, which contains # Generated by /usr/bin/select-editor SELECTED_EDITOR="/usr/bin/mcedit-debian" So far this is OK (it's my problem that I consider this completely useless, but never mind). Then I set up a .psqlrc file: \set PSQL_EDITOR /usr/bin/vim \set EDITOR /usr/bin/vim \set VISUAL /usr/bin/vim As you can see, I wanted to be sure not to miss a candidate variable for editor setting. The file is used as expected: test=# \echo :EDITOR /usr/bin/vim But when I issue the \e command, none of these is used - I fall back to SELECTED_EDITOR. The situation remains just the same if I append an \unset SELECTED_EDITOR to the .psqlrc file. Now how can I make .psqlrc setting win over the default editor? (PostgreSQL version id 9.1.4)

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  • `for` loop of Microsoft `cmd`: how can I process only the files with a certain extension?

    - by uvts_cvs
    I have a the folder c:\test\ and two files in it a.txt and b.txtv. I would like to process just the files with extension equal to .txt. If I write this commands cd c:\test for %f in (*.txt) do echo %f I will get the result where both a.txt and b.txtv are listed. The same happens with cd c:\test dir *.txt It seems .txt is the same of .txtv. I have Windows XP SP3 in Italian and the result of ver is Microsoft Windows XP [Versione 5.1.2600]. The same result is from Windows 7 in English Microsoft Windows XP [Version 6.1.7601].

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  • nat with iptables, re-connecting fail within about 3 minutes

    - by xpu
    i constructed a nat with iptables, as following: echo 1 > /proc/sys/net/ipv4/ip_forward iptables -t nat -I PREROUTING -p tcp --dport 9000 -j DNAT --to xx.xx.xx.xx iptables -t nat -I POSTROUTING -p tcp --dport 9000 -j MASQUERADE service iptables save service iptables restart the configuration worked fine, but there was a problem when i disconnected and tried to reconnect again, connection will be refused within about 2~3 minutes, after that, things go fine again. what was the problem? how do i make it to accept new connection after the old one break?

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  • HTML/JS/CSS issue getting bigger by itself

    - by Azzyh
    Here's the picture to begin with. I have this check box, that when you check, then with jQuery toggle(); it hides that you see in first half of the picture (#writeComment) and shows #SCtryVOTE (what you see in the other half picture, to the right). Now i dont know why but of some reason it expands when its checked, why i dont know, is it because it needs more place than it have or? how do i make this work without having problems when its checked. Here's coding: $('#tryout').click(function () { $('#writeComment').toggle(!$(this).attr('checked')); $('#SCtryVOTE').toggle($(this).attr('checked')); }); the js jquery script part, heres the table and divs HTML part: <input type="checkbox" id="tryout"> <table align="center" width="400" cellpadding="0" cellspacing="1" id="theBoxer"> <tr style="background: #686868;"> <td align="center" valign="top" width="70" height="25" style="border:1px #FFF solid;">Opret</td> <td align="center" valign="top" width="70" height="25" style="border:1px #FFF solid;">Opret</td> </td> </tr> <tr> <td align="left" valign="top" width="70" height="112" style=""> TEST </td> <td align="left" valign="top" width="70" height="112" style=""> <div id="writeComment"> Smid en kommentar:<br> <form action="javascript:DoInsert()" method="post"> <textarea id="kommentar" name="kommentar"></textarea><br /> <input type="hidden" name="fID" id="fID" value="<? echo $_GET["id"]; ?>"> <input type="submit" name="Submit" value="Sæt ind!"> </form> </div> <div id="SCtryVOTE" style="display: none;"> <form onsubmit="if (!this.comment.cleared) clearContents( document.getElementById('comment') ); return true;" action="javascript:DoSCInsert()" method="post"> <textarea onfocus=" javascript:clearContents(this); this.cleared=true;" rows="5" cols="40" id="comment" name="comment" <?php if($vis["username"] == $pusername) { echo "DISABLED"; } ?>>Tryk for at skrive. Skal være detaljeret og grundet.</textarea> <br>Ja: <input type="radio" value="Y" id="SCvoteY" name="vote"></input> Nej: <input type="radio" id="SCvoteN" value="N" name="vote"> </input> <input type="submit" id="SCstem" name="Submit" value="Stem!"> </form> </div> Maybe you need the CSS part too for these two boxes: #writeComment{ position: relative; left: 5px; top: 10px; } #SCtryVOTE{ position: relative; left: 5px; top: 10px; }

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  • Crontab + .sh + php

    - by Kristaps Karlsons
    Hi. I'm trying to call a shell script every 5 minutes, witch executes php file under root. # crontab -l */5 * * * * /home/regularuser/call.sh permissions: -rw-rw-rw- 1 root root 162 Jun 6 23:40 call.php -rwxr-xr-x 1 root root 66 Jun 7 01:20 call.sh call.sh contents: #!/bin/bash php -q /home/regularuser/call.php echo "request processed" My problem is that my php file doesn't get executed via crontab. However, if I call call.sh - everything works perfectly. I'm new to crontab and shell scripting, so any advice/resources are welcome.

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  • Adding to database. No repeat on refresh

    - by kevstarlive
    I have this code: Episode.php <?$feedback = new feedback; $articles = $feedback->fetch_all(); if (isset($_POST['name'], $_POST['post'])) { $cast = $_GET['id']; $name = $_POST['name']; $email = $_POST['email']; $post = nl2br ($_POST['post']); $ipaddress = $_SERVER['REMOTE_ADDR']; if (empty($name) or empty($post)) { $error = 'All Fields Are Required!'; }else{ $query = $pdo->prepare('INSERT INTO comments (cast, name, email, post, ipaddress) VALUES(?, ?, ?, ?, ?)'); $query->bindValue(1, $cast); $query->bindValue(2, $name); $query->bindValue(3, $email); $query->bindValue(4, $post); $query->bindValue(5, $ipaddress); $query->execute(); } }?> <div align="center"> <strong>Give us your feedback?</strong><br /><br /> <?php if (isset($error)) { ?> <small style="color:#aa0000;"><?php echo $error; ?></small><br /><br /> <?php } ?> <form action="episode.php?id=<?php echo $data['cast_id']; ?>" method="post" autocomplete="off" enctype="multipart/form-data"> <input type="text" name="name" placeholder="Name" /> / <input type="text" name="email" placeholder="Email" /><small style="color:#aa0000;">*</small><br /><br /> <textarea rows="10" cols="50" name="post" placeholder="Comment"></textarea><br /><br /> <input type="submit" onclick="myFunction()" value="Add Comment" /> <br /><br /> <small style="color:#aa0000;">* <b>Email will not be displayed publicly</b></small><br /> </form> </div> Include.php class feedback { public function fetch_all(){ global $pdo; $query = $pdo->prepare("SELECT * FROM comments"); $query->bindValue(1, $cast); $query->execute(); return $query->fetchAll(); } } This code updates to the database as it is suppose to. But after submission it reloads the current page as mentioned in the form action. But when I refresh the page to see the comment being added it asks to re submit. If I hit submit then the comment adds again. How can I stop this from happening? Maybe I could hide the comment box and display a thank you message but that would not stop a repeat entry. Please help. Thank you. Kev

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  • Copy any file with a specific file extension in subfolders into a folder

    - by Onyxius
    I found a script on here that would use 7zip and extract all the files in all the sub-folders of a specific folder and put them in their own folder using the script below. What I need is add to it or maybe use another script if i have to and specify where i want those files to go instead of putting them in their own folder within the folder. I don't know how to do this and hope someone would be able to help. Thanks for the help @echo on FOR /D /r %%F in ("*") DO ( pushd %CD% cd %%F FOR %%X in (*.rar *.zip *.tar) DO ( "C:\Program Files\7-zip\7z.exe" x -o"%%~nX" "%%X" ) popd )

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  • How Do I Parse a String?

    - by Russ
    I am new to bash, and I am creating a script that loops through the files in a directory and based on part of the filename, does something with the file, so far I have this: #!/bin/bash DIR="/Users/me/Documents/import/*" for f in "$DIR" do $t=?????? echo "Loading $f int $t..." done so $f will output something like this: /Users/me/Documents/import/time_dim-1272037430173 out of this, I want time_dim, the directory can be variable length and -1272037430173 is a fixed length (it's the unix timestamp btw). What is the best way to go about this?

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