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  • Render custom form / alter existing rendering template at runtime.

    - by Janis Veinbergs
    How do I create reusable custom new item form + preferrably, i don't want to tie this form to content type? I want to force render one hidden field (it could be render on the page, but make invisible or render on the page and display) and set field value programmatically (that's why it has to be rendered - to set it's value). Google has tons of information on how to create custom list form with sharepoint designer, but in my case, i don't want sharepoint designer for the advantages you see below. What i'm trying to achieve I want to be able to have a custom newform to create item (i don't want it to be as default). To open this newForm i would use CustomAction in item's ECB menu. In this form, i want to force render one hidden field and set it's value programmatically. I want to open this form from CustomAction ECB (item's context menu), so i don't want to set this as a default New form template for content type. <XmlDocument NamespaceURI="http://schemas.microsoft.com/sharepoint/v3/contenttype/forms"> <FormTemplates xmlns="http://schemas.microsoft.com/sharepoint/v3/contenttype/forms"> <New>ListForm</New> </FormTemplates> </XmlDocument> Idea #1 I could create custom RenderingTemplate and set Content type's new form template to my newly created template. For example, OOTB ListForm rendering template: <SharePoint:RenderingTemplate ID="ListForm" runat="server"> <Template> <SPAN id='part1'> <SharePoint:InformationBar runat="server"/> <wssuc:ToolBar CssClass="ms-formtoolbar" id="toolBarTbltop" RightButtonSeparator="&nbsp;" runat="server"> <Template_RightButtons> <SharePoint:NextPageButton runat="server"/> <SharePoint:SaveButton runat="server"/> <SharePoint:GoBackButton runat="server"/> </Template_RightButtons> </wssuc:ToolBar> <SharePoint:FormToolBar runat="server"/> <TABLE class="ms-formtable" style="margin-top: 8px;" border=0 cellpadding=0 cellspacing=0 width=100%> <SharePoint:ChangeContentType runat="server"/> <SharePoint:FolderFormFields runat="server"/> <SharePoint:ListFieldIterator runat="server" /> <SharePoint:ApprovalStatus runat="server"/> <SharePoint:FormComponent TemplateName="AttachmentRows" runat="server"/> </TABLE> <table cellpadding=0 cellspacing=0 width=100%><tr><td class="ms-formline"><IMG SRC="/_layouts/images/blank.gif" width=1 height=1 alt=""></td></tr></table> <TABLE cellpadding=0 cellspacing=0 width=100% style="padding-top: 7px"><tr><td width=100%> <SharePoint:ItemHiddenVersion runat="server"/> <SharePoint:ParentInformationField runat="server"/> <SharePoint:InitContentType runat="server"/> <wssuc:ToolBar CssClass="ms-formtoolbar" id="toolBarTbl" RightButtonSeparator="&nbsp;" runat="server"> <Template_Buttons> <SharePoint:CreatedModifiedInfo runat="server"/> </Template_Buttons> <Template_RightButtons> <SharePoint:SaveButton runat="server"/> <SharePoint:GoBackButton runat="server"/> </Template_RightButtons> </wssuc:ToolBar> </td></tr></TABLE> </SPAN> <SharePoint:AttachmentUpload runat="server"/> </Template> </SharePoint:RenderingTemplate> I only need such a minor change: <SharePoint:RenderingTemplate ID="NewRelatedListItemTemplate" runat="server"> ... <SharePoint:ListFieldIterator TemplateName="ListItemFormFieldsWithRelatedItems" runat="server" /> .. </SharePoint:RenderingTemplate> <SharePoint:RenderingTemplate ID="ListItemFormFieldsWithRelatedItems" runat="server"> <Template> <Balticovo:ListFieldIteratorExtended IncludeFields="RelatedItems" runat="server"/> </Template> </SharePoint:RenderingTemplate> Advantages over manual (SPD) custom forms In this way form is not "constant/static". If new list fields are added to list or content type afterwards, my custom form will render them (the ListFieldIterator will do it). Idea #2 Could it be that i modify existing RenderingTemplate at runtime? I would take "new forms" template (Named, for example, ListForm or it could be other than default ListForm) with SPControlTemplateManager.GetTemplateByName("ListForm") Find ListIterator control and add property TemplateName="ListItemFormFieldsWithRelatedItems" Render this template and return it? In short, i would like to create RenderingTemplate programmatically, on-the-fly and then use this template to render list's new form. Advantages I get the advantage of Idea 1 + This way i would get a bonus even if Template changes (from ListForm to CompanyCustomListForm) and my custom form won't loose my implemented functionality if i choose to change content type's rendering template later on (i can create other features not trying to rembeer to reimplement this particular stuff or other 3rd party features won't override my functionality if they use custom forms - loose coupling is it?). Now, is this (Idea #2) possible...?

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  • Password checking in dojo

    - by Richard
    I want to check that two passwords are the same using Dojo. Here is the HTML I have: <form id="form" action="." dojoType="dijit.form.Form" / <pPassword: <input type="password" name="password1" id="password1" dojoType="dijit.form.ValidationTextBox" required="true" invalidMessage="Please type a password" /</p <pConfirm: <input type="password" name="password2" id="password2" dojoType="dijit.form.ValidationTextBox" required="true" invalidMessage="This password doesn't match your first password" /</p <div dojoType="dijit.form.Button" onClick="onSave"Save</div </form Here is the JavaScript I have so far: var onSave = function() { if(dijit.byId('form').validate()) { alert('Good form'); } else { alert('Bad form'); } } Thanks for your help. I could do this in pure JavaScript, but I'm trying to find the Dojo way of doing it.

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  • Programmatically retrieve a form template from a SharePoint library.

    - by Dan Revell
    So an InfoPath form is deployed to a SharePoint server. It gets deployed through central admin and then activated to a particular site collection. This site collection has a forms library with the appropriate content type for the activated InfoPath form. Using the object model, how can I retrieve the form template back out of SharePoint programmatically. I know the url to the web, name of the list and the name of the form itself.

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  • Is it possible to pop open the upload file dialog without requiring the user to press Browse?

    - by superjoe30
    I think I've seen Gmail do it in Chrome or Internet Explorer, but I've never seen it in Firefox. I thought I'd ask anyways. Is it possible to do a file upload without requiring an <input type="file" />? I see that you can use iframes to automatically submit the file input, so my question is Can you programmatically pop up a file upload dialog? If so, what browsers is it supported on?

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  • How Can I Populate Default Form Data with a ManyToMany Field?

    - by b14ck
    Ok, I've been crawling google and Django documentation for over 2 hours now (as well as the IRC channel on freenode), and haven't been able to figure this one out. Basically, I have a model called Room, which is displayed below: class Room(models.Model): """ A `Partyline` room. Rooms on the `Partyline`s are like mini-chatrooms. Each room has a variable amount of `Caller`s, and usually a moderator of some sort. Each `Partyline` has many rooms, and it is common for `Caller`s to join multiple rooms over the duration of their call. """ LIVE = 0 PRIVATE = 1 ONE_ON_ONE = 2 UNCENSORED = 3 BULLETIN_BOARD = 4 CHILL = 5 PHONE_BOOTH = 6 TYPE_CHOICES = ( ('LR', 'Live Room'), ('PR', 'Private Room'), ('UR', 'Uncensored Room'), ) type = models.CharField('Room Type', max_length=2, choices=TYPE_CHOICES) number = models.IntegerField('Room Number') partyline = models.ForeignKey(Partyline) owner = models.ForeignKey(User, blank=True, null=True) bans = models.ManyToManyField(Caller, blank=True, null=True) def __unicode__(self): return "%s - %s %d" % (self.partyline.name, self.type, self.number) I've also got a forms.py which has the following ModelForm to represent my Room model: from django.forms import ModelForm from partyline_portal.rooms.models import Room class RoomForm(ModelForm): class Meta: model = Room I'm creating a view which allows administrators to edit a given Room object. Here's my view (so far): def edit_room(request, id=None): """ Edit various attributes of a specific `Room`. Room owners do not have access to this page. They cannot edit the attributes of the `Room`(s) that they control. """ room = get_object_or_404(Room, id=id) if not room.is_owner(request.user): return HttpResponseForbidden('Forbidden.') if is_user_type(request.user, ['admin']): form_type = RoomForm elif is_user_type(request.user, ['lm']): form_type = LineManagerEditRoomForm elif is_user_type(request.user, ['lo']): form_type = LineOwnerEditRoomForm if request.method == 'POST': form = form_type(request.POST, instance=room) if form.is_valid(): if 'owner' in form.cleaned_data: room.owner = form.cleaned_data['owner'] room.save() else: defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! form = form_type(defaults, instance=room) variables = RequestContext(request, {'form': form, 'room': room}) return render_to_response('portal/rooms/edit.html', variables) Now, this view works fine when I view the page. It shows all of the form attributes, and all of the default values are filled in (when users do a GET)... EXCEPT for the default values for the ManyToMany field 'bans'. Basically, if an admins clicks on a Room object to edit, the page they go to will show all of the Rooms default values except for the 'bans'. No matter what I do, I can't find a way to get Django to display the currently 'banned users' for the Room object. Here is the line of code that needs to be changed (from the view): defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! There must be some other syntax I have to use to specify the default value for the 'bans' field. I've really been pulling my hair out on this one, and would definitely appreciate some help. Thanks!

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  • How to pass form errors in session or flash? [Rails 2.3.5]

    - by yuval
    I have a create action for a form that potentially generates errors (i.e. first name is missing) and then redirects. The problem is, that when the redirect happens those form errors get lost. How could I pass those form errors in a session to be displayed back in the original form (which should still be filled out with the previous details, as in the original error_messages behavior)? Thanks!

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  • jquery hide certain form elements untill a certain textfield has been populated?

    - by Rubytastic
    I have a long signup form and would like to hide a few fields and only show them when a certain input field is populated with text, if the user types some text in this field the other form fields will show. I have looked at hide and show divs but have some trouble getting form elements hide and show them on a certain trigger ( populating a form with text ) anyone can point me in the right direction on how to implement such feature in query ? thx in advanche!

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  • JQuery: can I submit values from inputs that aren't in a form?

    - by Alvaro
    Simple as that: I have some inputs that are rendered inside another form element, but I want to submit then individually. I tried "serializing" the div that contains them, but it didn't work. Is there an easy way to do this? My code: var form = $("#my_div"); var get_data = $(form).serialize(); /* Get #my_div inputs value */ $.get(self.url_form_rendering, get_data, function (data){ /* handle server response */ }) Serialize returns "", any ideas that don't involve redesigning the layout to avoid form nesting?

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  • How can I upload and parse a vcard using ruby on rails?

    - by Angela
    I would like to be able to upload a vcard and have it parsed into my application's Model. I am thinking that Paperclip would be a way to upload, but I have no idea how to do the parse. I did a search on google, the only library that seems related is vpim, with mixed commentary. Wanted to see what brilliant ideas might be out there to solve this...thanks.

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  • is it possible to continue a file upload after a browser has been quit?

    - by sprugman
    If a user starts uploading a file (in a web app), and they close their browser before the upload completes, what happens? My guess would be that the upload gets abandoned, and the server has some garbage cleaning mechanism that kicks in eventually, but I'm not sure. Any difference between servers or server languages? Any difference between quitting the browser and just closing a window?

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  • How do I upload a file when I know the client's filepath?

    - by GJTorikian
    I'm interested in the way Sonic Living detects your iTunes library XML file. It prompts the user to approve its actions, then automatically uploads the XML file based on the client OS (and assuming the default installation path of iTunes). How the heck does it do that? None of the upload libraries I've looked at have this feature. They all assume that a user will click "Select file..." then browse around for the right thing to upload.

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  • Is it thread safe to read a form controls value (but not change it) without using Invoke/BeginInvoke from another thread

    - by goku_da_master
    I know you can read a gui control from a worker thread without using Invoke/BeginInvoke because my app is doing it now. The cross thread exception error is not being thrown and my System.Timers.Timer thread is able to read gui control values just fine (unlike this guy: can a worker thread read a control in the GUI?) Question 1: Given the cardinal rule of threads, should I be using Invoke/BeginInvoke to read form control values? And does this make it more thread-safe? The background to this question stems from a problem my app is having. It seems to randomly corrupt form controls another thread is referencing. (see question 2) Question 2: I have a second thread that needs to update form control values so I Invoke/BeginInvoke to update those values. Well this same thread needs a reference to those controls so it can update them. It holds a list of these controls (say DataGridViewRow objects). Sometimes (not always), the DataGridViewRow reference gets "corrupt". What I mean by corrupt, is the reference is still valid, but some of the DataGridViewRow properties are null (ex: row.Cells). Is this caused by question 1 or can you give me any tips on why this might be happening? Here's some code (the last line has the problem): public partial class MyForm : Form { void Timer_Elapsed(object sender) { // we're on a new thread (this function gets called every few seconds) UpdateUiHelper updateUiHelper = new UpdateUiHelper(this); foreach (DataGridViewRow row in dataGridView1.Rows) { object[] values = GetValuesFromDb(); updateUiHelper.UpdateRowValues(row, values[0]); } // .. do other work here updateUiHelper.UpdateUi(); } } public class UpdateUiHelper { private readonly Form _form; private Dictionary<DataGridViewRow, object> _rows; private delegate void RowDelegate(DataGridViewRow row); private readonly object _lockObject = new object(); public UpdateUiHelper(Form form) { _form = form; _rows = new Dictionary<DataGridViewRow, object>(); } public void UpdateRowValues(DataGridViewRow row, object value) { if (_rows.ContainsKey(row)) _rows[row] = value; else { lock (_lockObject) { _rows.Add(row, value); } } } public void UpdateUi() { foreach (DataGridViewRow row in _rows.Keys) { SetRowValueThreadSafe(row); } } private void SetRowValueThreadSafe(DataGridViewRow row) { if (_form.InvokeRequired) { _form.Invoke(new RowDelegate(SetRowValueThreadSafe), new object[] { row }); return; } // now we're on the UI thread object newValue = _rows[row]; row.Cells[0].Value = newValue; // randomly errors here with NullReferenceException, but row is never null! }

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  • how to get value of button through jquery in formcollection with id of form collection?

    - by AbhijitPandya
    i have formcollection and two buttons like <form id="frmSubmitTax" method="post"> <input type="submit" id="btnTaxSave" value="Save" /> <input type="submit" id="btnTaxNext" value="Next" /> </form> i m submitting form through jquery and i want to get value of button while form submitting jquery code $('frmSubmitTax').live('submit', function (e) { get value of button that which button is submitted...... });

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  • how to post a form upon click on checkbox ?

    - by user281180
    I have a form (displayed as a dialog) in which I have various checkboxes. On a click on any of the checkboxes, I want to post the form values to the controller and still doesn`t want my dialog to close. How can I do that? I don`t have a submit button on the form. Ajaxpost closes the dialog after form.submit... What method can I use?

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  • Image Preview in ASP.NET MVC

    - by imran_ku07
      Introduction :         Previewing an image is a great way to improve the UI of your site. Also it is always best to check the file type, size and see a preview before submitting the whole form. There are some ways to do this using simple JavaScript but not work in all browsers (like FF3).In this Article I will show you how do this using ASP.NET MVC application. You also see how this will work in case of nested form.   Description :          Create a new ASP.NET MVC project and then add a file upload and image control into your View. <form id="form1" method="post" action="NerdDinner/ImagePreview/AjaxSubmit">            <table>                <tr>                    <td>                        <input type="file" name="imageLoad1" id="imageLoad1"  onchange="ChangeImage(this,'#imgThumbnail')" />                    </td>                </tr>                <tr>                    <td align="center">                        <img src="images/TempImage.gif" id="imgThumbnail" height="200px" width="200px">                     </td>                </tr>            </table>        </form>           Note that here NerdDinner is refers to the virtual directory name, ImagePreview is the Controller and ImageLoad is the action name which you will see shortly          I will use the most popular jQuery form plug-in, that turns a form into an AJAX form with very little code. Therefore you must get these from Jquery site and then add these files into your page.          <script src="NerdDinner/Scripts/jquery-1.3.2.js" type="text/javascript"></script>        <script src="NerdDinner/Scripts/jquery.form.js" type="text/javascript"></script>            Then add the javascript function. <script type="text/javascript">function ChangeImage(fileId,imageId){ $("#form1").ajaxSubmit({success: function(responseText){ var d=new Date(); $(imageId)[0].src="NerdDinner/ImagePreview/ImageLoad?a="+d.getTime(); } });}</script>             This function simply submit the form named form1 asynchronously to ImagePreviewController's method AjaxSubmit and after successfully receiving the response, it will set the image src property to the action method ImageLoad. Here I am also adding querystring, preventing the browser to serve the cached image.           Now I will create a new Controller named ImagePreviewController. public class ImagePreviewController : Controller { [AcceptVerbs(HttpVerbs.Post)] public ActionResult AjaxSubmit(int? id) { Session["ContentLength"] = Request.Files[0].ContentLength; Session["ContentType"] = Request.Files[0].ContentType; byte[] b = new byte[Request.Files[0].ContentLength]; Request.Files[0].InputStream.Read(b, 0, Request.Files[0].ContentLength); Session["ContentStream"] = b; return Content( Request.Files[0].ContentType+";"+ Request.Files[0].ContentLength ); } public ActionResult ImageLoad(int? id) { byte[] b = (byte[])Session["ContentStream"]; int length = (int)Session["ContentLength"]; string type = (string)Session["ContentType"]; Response.Buffer = true; Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = type; Response.BinaryWrite(b); Response.Flush(); Session["ContentLength"] = null; Session["ContentType"] = null; Session["ContentStream"] = null; Response.End(); return Content(""); } }             The AjaxSubmit action method will save the image in Session and return content type and content length in response. ImageLoad action method will return the contents of image in response.Then clear these Sessions.           Just run your application and see the effect.   Checking Size and Content Type of File:          You may notice that AjaxSubmit action method is returning both content type and content length. You can check both properties before submitting your complete form.     $(myform).ajaxSubmit({success: function(responseText)            {                                var contentType=responseText.substring(0,responseText.indexOf(';'));                var contentLength=responseText.substring(responseText.indexOf(';')+1);                // Here you can do your validation                var d=new Date();                $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();            }        });  Handling Nested Form Case:          The above code will work if you have only one form. But this is not the case always.You may have a form control which wraps all the controls and you do not want to submit the whole form, just for getting a preview effect.           In this case you need to create a dynamic form control using JavaScript, and then add file upload control to this form and submit the form asynchronously  function ChangeImage(fileId,imageId)         {            var myform=document.createElement("form");                    myform.action="NerdDinner/ImagePreview/AjaxSubmit";            myform.enctype="multipart/form-data";            myform.method="post";            var imageLoad=document.getElementById(fileId).cloneNode(true);            myform.appendChild(imageLoad);            document.body.appendChild(myform);            $(myform).ajaxSubmit({success: function(responseText)                {                                    var contentType=responseText.substring(0,responseText.indexOf(';'));                    var contentLength=responseText.substring(responseText.indexOf(';')+1);                    var d=new Date();                    $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();                    document.body.removeChild(myform);                }            });        }            You also need append the child in order to send request and remove them after receiving response.

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