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  • Array data to display in table cells where col and row are given in array

    - by Saleem
    I have a array Array ( Array ( [id] => 1 , [schedule_id] => 4 , [subject] => Subject 1 , [classroom] => 1 , [time] => 08:00:00 , [col] => 1 , [row] => 1 ), Array ( [id] => 2 , [schedule_id] => 4 , [subject] => Subject 2 , [classroom] => 1 , [time] => 08:00:00 , [col] => 2 , [row] => 1 ), Array ( [id] => 3 , [schedule_id] => 4 , [subject] => Subject 3 , [classroom] => 2 , [time] => 09:00:00 , [col] => 1 , [row] => 2 ), Array ( [id] => 4 , [schedule_id] => 4 , [subject] => Subject 4 , [classroom] => 2 , [time] => 09:00:00 , [col] => 2 , [row] => 2 ) ) I want to display it in table format according to col and row value col 1 & row 1 col 2 $ row 1 1st array data 2nd array data Subject, room, time Subject, room, time 1, 1, 08:00 2, 1, 08:00 col 1 $ row 2 col 2 $ row 2 3rd array data 4th array data Subject, room, time Subject, room, time 3, 2, 09:00 4, 2, 08:00 I am new to arrays and need you support to sort this table. Thanks

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  • Can I flow divs down the page instead of across it?

    - by Brabster
    If I have a collection of div elements, I can use CSS to have them flow across the page and overflow onto the next line. Here's a simple example: <html> <head> <title>Flowing Divs</title> <style type="text/css"> .flow { float: left; margin: 4em 8em; } </style> </head> <body> <div class="container"> <div class="flow">Div 1</div> <div class="flow">Div 2</div> <div class="flow">Div 3</div> <div class="flow">Div 4</div> <div class="flow">Div 5</div> <div class="flow">Div 6</div> <div class="flow">Div 7</div> <div class="flow">Div 8</div> </div> </body> </html> Is it possible to have the divs flow down the page instead of across it, so that they would flow down columns not along lines, but still occupy the same space as they would if they flowed across? So for the example above, if they flowed into two lines of four divs, could I get the first column to contain Div1 and Div2 instead of Div1 and Div5?

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  • CUSTOM SORT XSL ?

    - by Nanda
    Hi This is my XML Structure like this input :- <MYDATA> <DETAILS> <DESCRIPTION>EASE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>COMPLEX</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>SIMPLE</DESCRIPTION> </DETAILS> </MYDATA> I want to display like this using xsl sort it mean custom sort i want to display firts simple second ease and third complex Output :- <MYDATA> <DETAILS> <DESCRIPTION>SIMPLE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>EASE</DESCRIPTION> </DETAILS> <DETAILS> <DESCRIPTION>COMPLEX</DESCRIPTION> </DETAILS> </MYDATA>

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  • Google Adwords API response parse

    - by Yun Ling
    I am trying to figure out how to parse the Adword API query response without exceptions and one issue that i came across is that sometimes, the data itself contains comma besides the comma between each column. Say i do a query on Adroup, campaign and impression by using <reportDefinition xmlns="https://adwords.google.com/api/adwords/cm/v201209"> <selector> <fields>CampaignName</fields> <fields>AdgroupName</fields> <fields>Impressions</fields> <predicates> <field>Status</field> <operator>IN</operator> <values>ENABLED</values> <values>PAUSED</values> </predicates> </selector> <reportName>Custom Adgroup Performance Report</reportName> <reportType>ADGROUP_PERFORMANCE_REPORT</reportType> <dateRangeType>LAST_7_DAYS</dateRangeType> <downloadFormat>CSV</downloadFormat> </reportDefinition> Since my campaign has comma within the string like below: "Adroup,Campaign,Impressions, Premiun Beer, Beer, Chicago, 1000" where the adgroup is "premium beer" and campaign is "Beer,Chicago". that will cause an issue if we parse this information by using comma. Does anyone know how to solve this problem?

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  • Group panel of WPF ListBox

    - by rulestein
    I have a listbox that is grouping the items with a GroupStyle. I would like add a control at the bottom of the stackpanel that holds all of the groups. This additional control needs to be part of the scrolling content so that the user would scroll to the bottom of the list to see the control. If I were using a listbox without the groups, this task would be easy by modifying the ListBox template. However, with the items grouped, the ListBox template seems to only apply on a per group basis. I can modify the GroupStyle.Panel, but that doesn't allow me to add items to that panel. <ListBox> <ListBox.ItemsPanel> <ItemsPanelTemplate> <WrapPanel/> </ItemsPanelTemplate> </ListBox.ItemsPanel> <ListBox.GroupStyle> <GroupStyle> <GroupStyle.Panel> <ItemsPanelTemplate> <VirtualizingStackPanel/> **<----- I would like to add a control to this stackpanel** </ItemsPanelTemplate> </GroupStyle.Panel> <GroupStyle.ContainerStyle> <Style TargetType="{x:Type GroupItem}"> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="{x:Type GroupItem}"> <Grid> <ItemsPresenter /> </Grid> </ControlTemplate> </Setter.Value> </Setter> </Style> </GroupStyle.ContainerStyle> </GroupStyle> </ListBox.GroupStyle> This should give an idea of what I need to do:

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  • spyr validation text with jquery serialize()

    - by oz1453
    Code like this : <form> <ol> <li> <fieldset> <legend>test</legend> <ol> <li> <label for="qwerty">qwerty</label> <span id="sprytextfield1"> <input name="qwerty" type="text" id="qwerty" /> <span class="textfieldRequiredMsg">error no qwerty input</span></span> </li> </ol> </fieldset> </li> </ol> <p style="text-align:right;"> <input type="reset" value="reset" /> <input type="submit" value="submit" /> </p> </form> <script type="text/javascript"> $('form').submit(function() { alert($(this).serialize()); return false; }); <!-- var sprytextfield1 = new Spry.Widget.ValidationTextField("sprytextfield1", "none", {validateOn:["blur"]}); //--> </script> I want to do. when i click the submit button serialize the form but when no error with spyr. if the spyr validation text error appears don t serialize or alert. i think.i must make a if condition before alert.

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  • How to change the link color of the current page with CSS

    - by Josh Curren
    How do I display the link for the current page different from the others? I would like to swap the colors of the text and background. This is what I currently have: The HTML: <div id="header"> <ul id="navigation"> <li class="bio"><a href="http://www.jacurren.com/">Home</a></li> <li class="theatre"><a href="http://www.jacurren.com/theatre.php">Theatre</a></li> <li class="prog"><a href="http://www.jacurren.com/programming.php">Programming</a></li> <li class="resume"><a href="http://www.jacurren.com/resume.php">R&eacute;sum&eacute;</a></li> <li class="portf"><a href="http://www.jacurren.com/portfolio.php">Portfolio</a></li> <li class="contact"><a href="http://www.jacurren.com/contact.php">Contact</a></li> </ul> </div> The CSS: #navigation{ margin:0; padding:0; background:#000000; height:34px; list-style:none; position: relative; top: 80px; } #navigation li{ float:left; clear:none; list-style:none; } #navigation li a{ color:#A60500; display:block; font-size:12px; text-decoration:none; font-weight:bold; padding:10px 18px; } #navigation li a:hover{ color:#640200; background-color:#000000; }

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  • get another sequence elements'value in one sequence.

    - by lxusharp
    I have an XML file as below, and I want to transform it with xslt. I want to achieve is: when do the for-each of "s1" elements, I want to get the corresponding "r1"'s "value" attbute value. the xslt I wrote as below, but it does not work, can anyone give a help? thanks. <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template mode="getr1" match="summary" > <xsl:param name="index"/> <xsl:value-of select="r1[$index][@value]"/> </xsl:template> <xsl:template match="/"> <html> <body> <ul> <xsl:for-each select="root/s1"> <xsl:variable name="i" select="position()"/> <li> <xsl:value-of select ="@name"/> : <!--<xsl:apply-templates mode="getr1" select="/root/summary"> <xsl:with-param name="index" select="$i" /> </xsl:apply-templates>--> <!--I want to get the corresponding r1's value according to the index --> <!-- but above code is not work.--> </li> </xsl:for-each> </ul> </body> </html> </xsl:template> </xsl:stylesheet>

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  • Why don't copy this dokument attributes from the source xml file??

    - by siegfried storr
    Hi anyone, i'm working the first time with xslt and i really don't understand why this xsl don't copy attributes from the source xml. Perhaps someone can give me a hint?? <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:variable name="rpl" select="document('ParamInvoice.xml')"/> <xsl:template match="/"> <xsl:copy> <xsl:apply-templates select="* | @*"/> </xsl:copy> </xsl:template> <xsl:template match="*"> <xsl:variable name="vInvoiceElement" select="$rpl/StoraInvoice/*[name()=name(current())]"/> <xsl:copy> <xsl:if test="$vInvoiceElement/Attribute"> <xsl:call-template name="AttributeErzeugen"> <xsl:with-param name="pAttr" select="$vInvoiceElement/Attribute"/> </xsl:call-template> </xsl:if> <xsl:apply-templates/> </xsl:copy> </xsl:template> <xsl:template name="AttributeErzeugen"> <xsl:param name="pAttr"/> <xsl:for-each select="$pAttr"> <xsl:attribute name="{@name}"><xsl:value-of select="."/></xsl:attribute> </xsl:for-each> </xsl:template> </xsl:stylesheet>

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  • How to get rid of white space between css horizontal list items?

    - by Curyous
    I've got the following test page and css. When displayed, there is a 4px gap between each list item. How do I get the items to be next to each other? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Frameset//EN" "http://www.w3.org/TR/html4/frameset.dtd"> <html> <head> <link type="text/css" rel="stylesheet" href="/stylesheets/test.css" /> </head> <body> <div> <ul class="nav"> <li class="nav"><a class="nav" href="#">One1</a></li> <li class="nav"><a class="nav" href="#">Two</a></li> <li class="nav"><a class="nav" href="#">Three</a></li> <li class="nav"><a class="nav" href="#">Four</a></li> </ul> </div> </body> </html> The css: ul.nav, ul li.nav { display: inline; margin: 0px; padding: 0px; } ul.nav { list-style-type: none; } li.nav { background-color: red; } a.nav { background-color: green; padding: 10px; margin: 0px; } a:hover.nav { background-color: gray; }

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  • JQuery tablesorter - Second click on column header doesn't resort

    - by Jonathan
    I'm using tablesorter in on a table I added to a view in django's admin (although I'm not sure this is relevant). I'm extending the html's header: {% block extrahead %} <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.js"></script> <script type="text/javascript" src="http://mysite.com/media/tablesorter/jquery.tablesorter.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#myTable").tablesorter(); } ); </script> {% endblock %} When I click on a column header, it sorts the table using this column in descending order - that's ok. When I click the same column header a second time - it does not reorder to ascending order. What's wrong with it? the table's html looks like: <table id="myTable" border="1"> <thead> <tr> <th>column_name_1</th> <th>column_name_2</th> <th>column_name_3</th> </tr> </thead> <tbody> {% for item in extra.items %} <tr> <td>{{ item.0|safe }} </td> <td>{{ item.1|safe }} </td> <td>{{ item.2|safe }} </td> </tr> {% endfor %} </tbody> </table>

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  • wordpress -> showing custom data from child pages + pagination

    - by GaVrA
    Hello! You can see here what i am doing: http://www.arvag.net/otkrijte-svet/leto/ So its pulling 2 custom fields from child pages, one of them is just url for the image on the left, and the other field is that text showing on the right. Now, what i want to do is to add pagination there. The code i have now will just simply show all child pages, but i want to show only 5 child pages, so if user want to see 6th child page he would have to click on link for "Page 2" and so on. The code im using to display these child pages is this: <?php $pages = get_pages('child_of='.$post->ID.'&sort_column=post_title&sort_order=desc'); $count = 0; foreach($pages as $page) { $short_info = get_post_meta($page->ID,'info',true); $image = get_post_meta($page->ID,'slika',true); $count++; ?> <div class='preview_slika left'><img src="<?php echo $image ?>" alt="<?php echo $page->post_title ?>" /></div> <div class='preview_info right'> <h2><?php echo $page->post_title ?></h2> <p><?php echo $short_info ?></p> <a href="<?php echo get_page_link($page->ID) ?>">Više o >></a> </div> <div class='clear'></div> <?php } ?> So any idea what to do to get what i need?

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  • Is it possible to embed a flash player in a table and retain the table properties

    - by user1494241
    I'd like to embed a music (flash) player in a table with clickable images but the embed code seems to throw the table properties off - it extends the width of the table. Is it possible to embed the player on the same row as the image whilst still retaining the table width? Here's what I've been using: <table width="620" border="0" cellspacing="0" cellpadding="0"> <tr> <td> <div align="left"><object height="18" width="100%"> <param name="movie" value="https://player.soundcloud.com/player.swf?url=http%3A%2F%2Fapi.soundcloud.com%2Fplaylists%2F1253725&amp;auto_play=false&amp;player_type=tiny&amp;font=Georgia&amp;color=9a6600&show_playcount=false&default_width=375&default_height=40&show_user=false"></param> <param name="allowscriptaccess" value="always"></param> <param name="wmode" value="transparent"></param><embed wmode="transparent" allowscriptaccess="always" height="18" src="https://player.soundcloud.com/player.swf?url=http%3A%2F%2Fapi.soundcloud.com%2Fplaylists%2F1253725&amp;auto_play=false&amp;player_type=tiny&amp;font=Georgia&amp;color=9a6600&show_playcount=false&default_width=375&default_height=40&show_user=false" type="application/x-shockwave-flash" width="100%"></embed> </object> </td> <td> <div align="right"><img src="http://dl.dropbox.com/u/31856944/Virb/splash_freedownload-2.png" border="0" width="245" height="42" usemap="#Map" /></div> </td> <tr> <td> <div align="right"><img src="http://dl.dropbox.com/u/31856944/Virb/splash_share-2.png" border="0" width="620" height="31" usemap="#Map2" /></div> </td> </tr> </table>

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  • Jquery Select Problem

    - by oraclee
    Hi; Jquery Code: $("[id$=mytable] tr").click(function() { alert($(this).html()); }); Html: <table id="mytable"> <tr> <td class="locked">1</td> <td>2</td> <td>3</td> </tr> <tr> <td class="locked">a</td> <td>b</td> <td>c</td> </tr> </table> i need only "td class='locked'" click return this click: <td class="locked">1</td> output: <tr> <td class="locked">1</td> <td>2</td> <td>3</td> </tr>

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  • Finding the index of a list item in jQuery

    - by Tim Piele
    I have an unordered list of eight items. On page load the first five <li> have default thumbnail images in them and the 6th one has a 1px by 1px placeholder image with the ID of $('#last'). When a user inserts a new image it replaces the 'src' of $('#last') with their new image. It's not the most efficient way but it works. <ul> <li><img src="img1.png" /></li> <li><img src="img2.png" /></li> <li><img src="img3.png" /></li> <li><img src="img4.png" /></li> <li><img src="img5.png" /></li> <li><img src="1px.png" id="last"/></li> <li></li> <li></li> </ul> When the user adds a new image the ID of $('#last') is removed and I use each() to find the next empty <li> and insert the 1px by 1px image in it, with an ID of $('#last') so it is ready for the next image upload. At this point I need to get the index() of the <li> that now has the 1px by 1px image in it, whose ID is $('#last'), so that I can store the index in the session, so when a user comes back to the page the $('#last') ID is still set and ready to accept another image. How do I get the index of the <li> with that image in it, since it was set after page load? Is there a way to use delegate() or on() to get it? i.e. how do I get the index of an element that was set after page load?

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  • problem using the xsl method for-each

    - by joe
    Using XSL I am trying to turn this XML: <book><title>This is a <b>great</b> book</title></book> into this XML: <book>This is a <bold>great</bold> book</book> using this xsl: <xsl:for-each select="book/title/*"> <xsl:choose> <xsl:when test="name() = 'b'"> <bold> <xsl:value-of select="text()"/> </bold> </xsl:when> <xsl:otherwise> <xsl:value-of select="text()"/> </xsl:otherwise> </xsl:choose> </xsl:for-each> but my output is looking like this: <book><bold>great</bold></bold> Can anyone explain why the root text of <title> is getting lost? I believe my for-each select statement may need to be modified but I can't figure out what is should be. Keep in mind that I cannot use an <xsl:template match> because of the complexity of my style sheet. Thanks!

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  • The scroll viewer is not updating in silverlight

    - by Malcolm
    I have an image inside scroll viewer and i have a control for zooming the image and in zooming event i change the scale of an image ,as below : void zoomSlider_ValueChanged(object sender, RoutedPropertyChangedEventArgs<double> e) { scale.ScaleX = e.NewValue; scale.ScaleY = e.NewValue; //scroll is a name of scrolviewer scroll.UpdateLayout(); } And a xaml below <Grid x:Name="Preview" Grid.Column="1"> <Border x:Name="OuterBorder" BorderThickness="1" BorderBrush="#A3A3A3" > <Border x:Name="InnerBorder" BorderBrush="Transparent" Margin="2" > <Grid Background="White" > <Grid.ColumnDefinitions> <ColumnDefinition Width="*"/> </Grid.ColumnDefinitions> <ScrollViewer x:Name="scroll" HorizontalScrollBarVisibility="Auto" Grid.Column="0" VerticalScrollBarVisibility="Auto" HorizontalAlignment="Stretch" VerticalAlignment="Stretch" Themes:ThemeManager.StyleKey="TreeScrollViewer"> <Image Source="../charge_chargeline.PNG" > <Image.RenderTransform> <CompositeTransform x:Name="**scale**" /> </Image.RenderTransform> </Image> </ScrollViewer> <Border HorizontalAlignment="Center" CornerRadius="0,0,2,2" Width="250" Height="24" VerticalAlignment="Top"> <Border.Background> <LinearGradientBrush StartPoint="0,0" EndPoint="0,1"> <GradientStop Color="#CDD1D4" Offset="0.0"/> <GradientStop Color="#C8CACD" Offset="1.0"/> </LinearGradientBrush> </Border.Background> <ChargeEntry:Zoom x:Name="zoominout" /> </Border> </Grid> </Border> </Border> </Grid>

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  • Launch a new page in Zend/php on button click

    - by BlueMonster
    PHP & Zend Noob here I've downloaded the skeleton project from here: https://github.com/zendframework/ZendSkeletonApplication Say i want to open a new page that simply displays "hello world" text if click on the "ZF2 Development Portal" button(bottom left green button) on the page that launches --- how do i do this? See image: I've read through this tutorial, but i'm not sure how the model, view, or controller are actually launched? See tutorial: http://blog.wilgucki.pl/2012/07/tworzenie-modulw-w-zend-framework-2.html From looking at the code, i know that i will have to change this line of code: <div class="span4"> <h2><?php echo $this->translate('Follow Development') ?></h2> <p><?php echo sprintf($this->translate('Zend Framework 2 is under active development. If you are interested in following the development of ZF2, there is a special ZF2 portal on the official Zend Framework website which provides links to the ZF2 %swiki%s, %sdev blog%s, %sissue tracker%s, and much more. This is a great resource for staying up to date with the latest developments!'), '<a href="http://framework.zend.com/wiki/display/ZFDEV2/Home">', '</a>', '<a href="http://framework.zend.com/zf2/blog">', '</a>', '<a href="http://framework.zend.com/issues/browse/ZF2">', '</a>') ?></p> <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> </div> More specifically this line: <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> but i'm really confused as to what i'm supposed to change it to in order to launch a new page. Any ideas? Thanks in advance!

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  • Removing empty space with jQuery after deleting Selectable item

    - by Tx3
    I have two ordered lists and user can move items between them. I am using jQuery UI's Selectable for both of them. Problem is that when I move item from the middle of the list it leaves an empty space behind. How can I make list shrink according to the how many items is actually in the list? HTML <ol id="allUnits"> <li class="ui-state-default">Item 1</li> <li class="ui-state-default">Item 2</li> <li class="ui-state-default">Item 3</li> <li class="ui-state-default">Item 4</li> <li class="ui-state-default">Item 5</li> </ol> <input id="arrowRight" type="image" alt="Move item to right" src="<%= Url.Content("~/Content/Images/arrowRight.png")%>" /> <input id="arrowLeft" type="image" alt="Move item to left" src="<%= Url.Content("~/Content/Images/arrowLeft.png")%>" /> <ol id="productUnits"> <li class="ui-state-default">Item 1</li> <li class="ui-state-default">Item 2</li> <li class="ui-state-default">Item 3</li> <li class="ui-state-default">Item 4</li> <li class="ui-state-default">Item 5</li> </ol> jQuery $().ready(function () { $("#allUnits").selectable(); $("#productUnits").selectable(); $('#arrowRight').click(function () { return !$('#allUnits .ui-selected').remove().appendTo('#productUnits').removeClass(".ui-selected"); }); $('#arrowLeft').click(function () { return !$('#productUnits .ui-selected').remove().appendTo('#allUnits').removeClass(".ui-selected"); }); });

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  • How do i select all text nodes using XSL?

    - by user323719
    I want to get the generate-id(.) of all the text nodes after node and before node . I am looking for some generic XSL and not tightly coupled to the sample input pattern mentioned below. For any input pattern i want to get the ids of all the text nodes between node and . Sample input for better understanding: <a> <b> <c> This is first text node </c> </b> <d> <e> This is my second text node </e> <f> This is my <m/>third text node </f> <g> One more text node </g> <h> <i> This is my fourth text node </i> </h> <j> This is my fifth <n/>text node </j> <k> <l> This is my sixth text node </l> </k> </d> </a> Expected output: Generate id of the text nodes with values "third text node ", "One more text node", "This is my fourth text node", "This is my fifth" which lie inbetween nodes <m/> and <n/> Please give your ideas.

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  • hy i dont get the check value in check box?

    - by udaya
    Hi I have a check box when check that check box the id corresponding to the check box is placed on a text box ... but when there is only single value in the database i cant get the check value why? here is my code <? if(isset($AcceptFriend)) {?> <form action="<?=site_url()?>friends/Accept_Friend" name="orderform" id="orderform" method="post" style="background:#CCCC99"> <input type="text" name="chId" id="chId" > <table border="0" height="50%" id="chkbox" width="50%" > <tr> <? foreach($AcceptFriend as $row) {?> <tr> <td>Name</td><td><?=$row['dFrindName'].'</br>';?></td> <td> <input type="checkbox" name="checkId" id="checkId" value="<? echo $row['dMemberId']; ?>" onClick="get_check_value()" ></td> </tr> <? }}?> </tr> <tr> <td width="10px"><input type="submit" name="submit" id="submit" class="buttn" value="AcceptFriend"></td></tr> </table> </form> This is the script i am using function get_check_value() { var c_value = ""; for (var i=0; i < document.orderform.checkId.length; i++) { if (document.orderform.checkId[i].checked) { c_value = c_value + document.orderform.checkId[i].value + "\n"; } } alert(c_value); document.getElementById('chId').value= c_value; }

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  • Find element all of whose children have a given value

    - by cru3l
    for example, i have this xml <elements> <a> <b>6</b> <b>5</b> <b>6</b> </a> <a> <b>5</b> <b>5</b> <b>6</b> </a> <a> <b>5</b> <b>5</b> <b>5</b> <b>5</b> </a> </elements> i need a xpath query, which must return me parent tag, only if all its children are equal to 5 (a[3] in this case). Something like that //b[text()="5"]/.. but with check of all children's tags. Please note that number of children tags can be different from node to node. It's possible with only xpath query? thanks

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  • convert date error when retrieving data in twig page through doctrine

    - by user201892
    I just find this error when I retrieve all my records on twig page from the database through doctrine here is my twig code : {% extends "gestionConferenceApplicationBundle::layout.html.twig" %} {% block title "Hello " ~ name %} {% block content %} je suis un debutant <table border=2 > <th>Numéro</th> <th>Titre</th> <th>Ville</th> <th>Lieu</th> <th>Date de début</th> <th>Date de fin</th> {% for item in conferences %} <tr> <td>{{ item.id }}</td> <td>{{ item.titre }}</td> <td>{{ item.ville }}</td> <td>{{ item.lieu }}</td>* <td>{{ item.dateDebut }}</td> <td>{{ item.dateFin }}</td> </tr> {% endfor %} </table> {% endblock %} the error in the date : here it is : An exception has been thrown during the rendering of a template ("Catchable Fatal Error: Object of class DateTime could not be converted to string in C:\wamp\www\Symfony\app\cache\dev\twig\3c\dd\40a703549de9b8769fa40b82230e.php line 72") in gestionConferenceApplicationBundle:acceuil:acceuil.html.twig at line 19. do you have any idea how to convert this date or any other things in the MySql I have dateTime field and in doctrine I have : /** * @var \DateTime $dateDebut * * @ORM\Column(name="date_debut", type="datetime", nullable=false) */ private $dateDebut;

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  • XSD: Different sub-elements depending on attribute/element value

    - by AndiDog
    Another XSD question - how can I achieve that the following XML elements are both valid: <some-element> <type>1</type> <a>...</a> </some-element> <some-element> <type>2</type> <b>...</b> </some-element> The sub-elements (either <a> or <b>) should depend on the content of <type> (could also be an attribute). It would be so simple in RelaxNG - but RelaxNG doesn't support key integrity :( Is there a way to implement this in XSD? Note: XML schema version 1.1 supports <xs:alternative>, which might be a solution, but afaik no reference implementation (e.g. libxml2) supports this yet. So I'm searching for workarounds. The only way I've come up with is: <type>1</type> <some-element type="1"> <!-- simple <xs:choice> between <a> and <b> goes here --> <a>...</a> </some-element> <!-- and now create a keyref between <type> and @type -->

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  • Error in my web.xml

    - by Mercer
    Why i have an error in my web.xml when i want add servlet..? <servlet> <servlet-name>ClientServlet</servlet-name> <servlet-class>org.task.ClientServlet</servlet-class> <servlet-name>FactoryServlet</servlet-name> <servlet-class>org.task.FactoryServlet</servlet-class> <servlet-name>TraderServlet</servlet-name> <servlet-class>org.task.TraderServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ClientServlet</servlet-name> <url-pattern>/ClientServlet</url-pattern> <servlet-name>FactoryServlet</servlet-name> <url-pattern>/FactoryServlet</url-pattern> <servlet-name>TraderServlet</servlet-name> <url-pattern>/TraderServlet</url-pattern> </servlet-mapping>

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