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  • Defer Eclipse Treeviewer loading by DeferredTreeContentManager

    - by qichuan
    I understand there is an approach to defer TreeViewer loading by using DeferredTreeContentManager, learnt from this useful tutorial. However, this mechanism requires the model to implement IDeferredWorkbenchAdapter interface, which introduces problem to my legacy immutable model classes. Is it possible to use DeferredTreeContentManager without having model implementing IDeferredWorkbenchAdapter interface?

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  • swing: event listener support class

    - by Jason S
    Is there any preexisting class that helps support add/remove EventListener operations? (kind of like PropertyChangeSupport) I'm trying to partition my code into a model and view in Java. I have some data that arrives erratically, and would like the model to support some kind of EventListener so that a view can subscribe to changes in the model. The data is numerous + complicated enough that I don't want to have to do the whole fine-grained Javabeans property change support; rather I would just like to allow notification that the model has changed in a coarse way. how can I best do this?

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  • How do you set the default source for the Output window in Visual Studio?

    - by Grank
    We added a SharePoint BDC model project to a solution in Visual Studio 2010. Ever since, whenever the solution is built, instead of showing the Build output in the Output window, it insists on having "SharePoint Tools" selected in the "Show Output from:" drop-down, just to say "Model validation started ... Model validation completed with no errors." Short of shutting off any SharePoint projects in the build configuration, can this behavior be overridden?

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  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

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  • my jComboBox does not react to my keyListener and actionPerform perfroms weired stuff

    - by aladdin
    hi I am trying to search for UserName and return values onto jComboBox, here is the code public void actionPerformed(java.awt.event.ActionEvent e) { sr = new Search(((String) jComboBoxReceiver.getSelectedItem())); usrList = sr.searchUser(); String[] userList = new String[usrList.size()] ; for(int i=0;i<usrList.size();i++){ userList[i]= usrList.get(i).getUserName(); } model = new DefaultComboBoxModel(userList); jComboBoxReceiver.setModel(model); } However, if i do that, it does perform correctly, however, it will go search for the first item again, which is very confusing... then i tried using key Pressed if(e.getKeyCode()==13){ sr = new Search(((String) jComboBoxReceiver.getSelectedItem())); usrList = sr.searchUser(); String[] userList = new String[usrList.size()] ; for(int i=0;i<usrList.size();i++){ userList[i]= usrList.get(i).getUserName(); } model = new DefaultComboBoxModel(userList); jComboBoxReceiver.setModel(model); } And this one does not react at all ...

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  • Django adminsite customize search_fields query

    - by dArignac
    Howdy! In the django admin you can set the search_fields for the ModelAdmin to be able to search over the properties given there. My model class has a property that is not a real model property, means it is not within the database table. The property relates to another database table that is not tied to the current model through relations. But I want to be able to search over it, so I have to somehow customize the query the admin site creates to do the filtering when the search field was filled - is this possible and if, how? I can query the database table of my custom property and it then returns the ids of the model classes fitting the search. This then, as I said, has to flow into the admin site search query. Thanks!

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  • Django models & Python class attributes

    - by Geo
    The tutorial on the django website shows this code for the models: from django.db import models class Poll(models.Model): question = models.CharField(max_length=200) pub_date = models.DateTimeField('date published') class Choice(models.Model): poll = models.ForeignKey(Poll) choice = models.CharField(max_length=200) votes = models.IntegerField() Now, each of those attribute, is a class attribute, right? So, the same attribute should be shared by all instances of the class. A bit later, they present this code: class Poll(models.Model): # ... def __unicode__(self): return self.question class Choice(models.Model): # ... def __unicode__(self): return self.choice How did they turn from class attributes into instance attributes? Did I get class attributes wrong?

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  • Validating an Autocomplete field in Django

    - by anonymous coward
    I have models similar to the following: class Band(models.Model): name = models.CharField(unique=True) class Event(models.Model): name = models.CharField(max_length=50, unique=True) bands = models.ManyToManyField(Band) and essentially I want to use the validation capability offered by a ModelForm that already exists for Event, but I do not want to show the default Multi-Select list (for 'bands') on the page, because the potential length of the related models is extremely long. I have the following form defined: class AddEventForm(ModelForm): class Meta: model = Event fields = ('name', ) Which does what is expected for the Model, but of course, validation could care less about the 'bands' field. I've got it working enough to add bands correctly, but there's no correct validation, and it will simply drop bad band IDs. What should I do so that I can ensure that at least one (correct) band ID has been sent along with my form? For how I'm sending the band-IDs with auto-complete, see this related question: http://stackoverflow.com/questions/1528059/

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  • I am confused about how to use @SessionAttributes

    - by yusaku
    I am trying to understand architecture of Spring MVC. However, I am completely confused by behavior of @SessionAttributes. Please look at SampleController below , it is handling post method by SuperForm class. In fact, just field of SuperForm class is only binding as I expected. However, After I put @SessionAttributes in Controller, handling method is binding as SubAForm. Can anybody explain me what happened in this binding. ------------------------------------------------------- @Controller @SessionAttributes("form") @RequestMapping(value = "/sample") public class SampleController { @RequestMapping(method = RequestMethod.GET) public String getCreateForm(Model model) { model.addAttribute("form", new SubAForm()); return "sample/input"; } @RequestMapping(method = RequestMethod.POST) public String register(@ModelAttribute("form") SuperForm form, Model model) { return "sample/input"; } } ------------------------------------------------------- public class SuperForm { private Long superId; public Long getSuperId() { return superId; } public void setSuperId(Long superId) { this.superId = superId; } } ------------------------------------------------------- public class SubAForm extends SuperForm { private Long subAId; public Long getSubAId() { return subAId; } public void setSubAId(Long subAId) { this.subAId = subAId; } } ------------------------------------------------------- <form:form modelAttribute="form" method="post"> <fieldset> <legend>SUPER FIELD</legend> <p> SUPER ID:<form:input path="superId" /> </p> </fieldset> <fieldset> <legend>SUB A FIELD</legend> <p> SUB A ID:<form:input path="subAId" /> </p> </fieldset> <p> <input type="submit" value="register" /> </p> </form:form>

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  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • Returning a local object from a function

    - by pocoa
    Is this the right way to return an object from a function? Car getCar(string model, int year) { Car c(model, year); return c; } void displayCar(Car &car) { cout << car.getModel() << ", " << car.getYear() << endl; } displayCar(getCar("Honda", 1999)); I'm getting an error, "taking address of temporary". Should I use this way: Car &getCar(string model, int year) { Car c(model, year); return c; }

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  • ASP.NET MVC. Hot to guess autogenerated id value ?

    - by Andrew Florko
    My web form contains list of dynamic fields that are generated like this: <% for (int i = 0; i < Model.Options.Count; i++) { %> ... <%= Html.Hidden("Options[" + i + "].Id", Model.Options[i].Id)%> <%= Html.CheckBox("Options[" + i + "].Selected", Model.Options[i].Selected)%> ... This maps perfectly on array of controller method parameters as described in Model Binding To A List article. I want to add label for checkboxes to title them, but I have to guess their ids in hmtl layout. Options[" + i + "].Selected turns into Options_0__Selected How can I avoid hardcoding Id generation in-built asp.net mvc rules? Thank you advance.

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  • Using a backwards relation (i.e FOO_set) for ModelChoiceField in Django

    - by Bwmat
    I have a model called Movie, which has a ManyToManyField called director to a model called Person, and I'm trying to create a form with ModelChoiceField like so: class MovieSearchForm(forms.Form): producer = forms.ModelChoiceField(label='Produced by', queryset=movies.models.Person.producer_set, required=False) but this seems to be failing to compile (I'm getting a ViewDoesNotExist exception for the view that uses the form, but it goes away if I just replace the queryset with all the person objects), I'm guessing because '.producer_set' is being evaluated too 'early'. How can I get this work? here are the relevant parts of the movie/person classes: class Person(models.Model): name = models.CharField(max_length=100) class Movie(models.Model): ... producer = models.ForeignKey(Person, related_name="producers") director = models.ForeignKey(Person, related_name="directors") What I'm trying to do is get ever Person who is used in the producer field of some Movie.

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  • Groovy & Grails Concurrency ( quartz, executor )

    - by Pietro
    What I'm trying to do is to run multiple threads at some starting time. Those threads must stay alive for 90minutes after start. During the 90minutes they execute something after a random sleep time (ex: 5minutes to 15minutes). Here is a pseudo code on how I would implement it. The problem is that doing it in this way the threads run in an unexpected way. How can I implement correctly something like this? Class MyJob { static triggers = { cron name: 'first', cronExpression: "0 30 21 * * FRI" cron name: 'second', cronExpression: "0 30 19 * * FRI" cron name: 'third', cronExpression: "0 30 17 * * FRI" def myService def execute() { switch( between trigger name ) case 'first': model = Model.findByAttribute(...) ... myService.run( model, start_time ) break; ... } } class MyService { def run( model, start_time ) { def end_time = end_time.plusMinutes(90) model.fields.each( field -> Thread.start { executeSomeTasks( field, start_time, end_time ) } ) } def executeSomeTasks( field, start_time, end_time ) { while( start_time < end_time ) { ...do something ... sleep( Random.nextInt( 1000 ) ); } } }

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  • dynamic searchable fields, best practice?

    - by boblu
    I have a Lexicon model, and I want user to be able to create dynamic feature to every lexicon. And I have a complicate search interface that let user search on every single feature (including the dynamic ones) belonged to Lexicon model. I could have used a serialized text field to save all the dynamic information if they are not for searching. In case I want to let user search on all fields, I have created a DynamicField Model to hold all dynamically created features. But imagine I have 1,000,000,000 lexicon, and if one create a dynamic feature for every lexicon, this will result creating 1,000,000,000 rows in DynamicField model. So the sql search function will become quite inefficient while a lot of dynamic features created. Is there a better solution for this situation? Which way should I take? searching for a better db design for dynamic fields try to tuning mysql(add cache fields, add index ...) with current db design

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  • Django: Set foreign key using integer?

    - by User
    Is there a way to set foreign key relationship using the integer id of a model? This would be for optimization purposes. For example, suppose I have an Employee model: class Employee(models.Model): first_name = models.CharField(max_length=100) last_name = models.CharField(max_length=100) type = models.ForeignKey('EmployeeType') and EmployeeType(models.Model): type = models.CharField(max_length=100) I want the flexibility of having unlimited employee types, but in the deployed application there will likely be only a single type so I'm wondering if there is a way to hardcode the id and set the relationship this way. This way I can avoid a db call to get the EmployeeType object first.

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  • how to get SOURCE

    - by laknath27
    i do some development with jena ontology API.my ontology file in my local machine..when i'm going to read the model.. there is an error.. and i made ontology with protege and tried to read that file. String SOURCE = "http://www.owl-ontologies.com/Ontology1275995702";(it's XML:base value) //String NS = SOURCE + "#"; //InputStream in = FileManager.get().open("tourism.owl"); OntModel model = ModelFactory.createOntologyModel(OntModelSpec.OWL_MEM); model.read(SOURCE,"RDF/XML"); OntClass paper = model.getOntClass( SOURCE + "srilanka" ); how can i fix this?

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  • django access to parent

    - by SledgehammerPL
    model: class Product(models.Model): name = models.CharField(max_length = 128) (...) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive And now I'd like to get list of the most often useable products: ReceiptComponent.objects.values('product').annotate(Count('product')).order_by('-product__count' the example result: [{'product': 3, 'product__count': 5}, {'product': 6, 'product__count': 4}, {'product': 5, 'product__count': 3}, {'product': 7, 'product__count': 2}, {'product': 1, 'product__count': 2}, {'product': 11, 'product__count': 1}, {'product': 8, 'product__count': 1}, {'product': 4, 'product__count': 1}, {'product': 9, 'product__count': 1}] It's almost what I need. But I'd prefer having Product object not product value, because I'd like to use this in views.py for generating list.

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  • Can this django query be improved?

    - by Hobhouse
    Given a model structure like this: class Book(models.Model): user = models.ForeignKey(User) class Readingdate(models.Model): book = models.ForeignKey(Book) date = models.DateField() One book may have several readingdates. How do I list books having at least one readingdate within a specific year? I can do this: from_date = datetime.date(2010,1,1) to_date = datetime.date(2010,12,31) book_ids = Readingdate.objects\ .filter(date__range=(from_date,to_date))\ .values_list('book_id', flat=True) books_read_2010 = Book.objects.filter(id__in=book_ids) Is it possible to do this with one queryset, or is this the best way?

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  • Rails, destroy if blank

    - by Joseph Silvashy
    This might sound odd, but is there a 'Rails way' to have a model destroyed if a certain attribute is blank? Say I have a model like tags with just a name attribute or something, if the user edits the tag and deletes all the text out of the name field in the form I'd like the model to just be deleted. I'm aware of the reject_if method, but that doesn't seem to work.

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  • Why does JPA require a no-arg constructor for domain objects ?

    - by Jacques René Mesrine
    Why does JPA require a no-arg constructor for domain objects ? I am using eclipselink and just got this exception during deployment. Exception [EclipseLink-63] (Eclipse Persistence Services-1.1.0.r3639-SNAPSHOT): org.eclipse.persistence.exceptions.DescriptorException Exception Description: The instance creation method [com.me.model.UserVO.<Default Constructor>], with no parameters, does not exist, or is not accessible. Internal Exception: java.lang.NoSuchMethodException: com.me.model.UserVO.<init>() Descriptor: RelationalDescriptor(com.me.model.UserVO --> [DatabaseTable(user)])

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  • When using Dependency Injection with StructureMap how do I chooose among multiple constructors?

    - by Mark Rogers
    I'm trying to get structuremap to build Fluent Nhibernate's SessionSource object for some of my intregration tests. The only problem is that Fluent's concrete implementation of ISessionSource (SessionSource) has 3 constructors: public SessionSource(PersistenceModel model) { Initialize(new Configuration().Configure(), model); } public SessionSource(IDictionary<string, string> properties, PersistenceModel model) { Initialize(new Configuration().AddProperties(properties), model); } public SessionSource(FluentConfiguration config) { configuration = config.Configuration; sessionFactory = config.BuildSessionFactory(); dialect = Dialect.GetDialect(configuration.Properties); } I've tried configuring my ObjectFactory supplying an argument for the first constructor but it seems like it wants to try the second one. How do I configure my ObjectFactory so that I can choose the first constructor or perhaps even another one if I decide to use that?

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  • MySQL searching using many 'like' operators: is there a better way?

    - by DrAgonmoray
    I have a page that gets all rows from a table in a database, then displays the rows in an HTML table. That works great, but now I want to implement a 'search' feature. There is a searchbox, and search-terms are separated by a space. I am going to make it search three fields for the search terms, 'make' 'model' and 'type.' These three fields are VARCHAR(30). Currently if I wanted to search using 3 terms (say 'cool' 'abc' and '123') my query would look something like this. SELECT * FROM table WHERE make LIKE '%cool%' OR make LIKE '%abc%' OR make LIKE '%123%' OR model LIKE '%cool%' OR model LIKE '%abc%' OR model LIKE '%123%' OR type LIKE '%cool%' OR type LIKE '%abc%' OR type LIKE '%123%' That looks really bad, and it will get even worse if there are more search terms or more fields to search. My question to you: is there a better way to search? If so, what?

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  • How do I specify (1) an order and (2) a meaninful string representation for users in my Django application?

    - by David Faux
    I have a Django application with users. I have a model called "Course" with a foreign key called "teacher" to the default User model that Django provides: class Course(models.Model): ... teacher = models.ForeignKey(User, related_name='courses_taught') When I create a model form to edit information for individual courses, the possible users for the teacher field appear in this long select menu of user names. These users are ordered by ID, which is of meager use to me. How can I order these users by their last names? change the string representation of the User class to be "Firstname Lastname (username)" instead of "username"?

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