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  • UPDATE REGEX MYSQL

    - by Simon
    I have a table of contacts and a table of postcode data. I need to match the first part of the postcode and the join that with the postcode table... and then perform an update... I want to do something like this... UPDATE `contacts` LEFT JOIN `postcodes` ON PREG_GREP("/^[A-Z]{1,2}[0-9][0-9A-Z]{0,1}/", `contacts`.`postcode`) = `postcodes`.`postcode` SET `contacts`.`lat` = `postcode`.`lat`, `contacts`.`lng` = `postcode`.`lng` Is it possible?? Or do I need to use an external script? Many thanks.

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  • PHP MySQL join table

    - by Jordan Pagaduan
    $sql = "SELECT logs.full_name, logout.status FROM logs, logout WHERE logs.employee_id = logout.employee_id"; tables -- logs logout I'm having error on this. I search join tables in google. And that's what I got. What is wrong with this code?

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  • Mysql Replication

    - by ychian
    My current database design uses MyIsam mainly as the storage engine, I wonder if its possible to split some of the tables into MyIsam and some into Innodb in the same database. Reason of switching some of the tables to Innodb is because i need row-based locking which Innodb offers. I am not too sure whether this would have any effect on replication?

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  • Grouping timestamps by interval between timestamps, then calculating from group MySQL

    - by Emile
    To put this question into context, I'm trying to calculate "time in app" based on an event log. Assume the following table: user_id event_time 2 2012-05-09 07:03:38 3 2012-05-09 07:03:42 4 2012-05-09 07:03:43 2 2012-05-09 07:03:44 2 2012-05-09 07:03:45 4 2012-05-09 07:03:52 2 2012-05-09 07:06:30 I'd like to get the difference between the highest and lowest event_time from a set of timestamps that are within 2 minutes of eachother (and grouped by user). If a timestamp is outside of a 2 minute interval from the set, it should be considered a part of another set. Desired output: user_id seconds_interval 2 7 (because 07:03:45 - 07:03:38 is 7 seconds) 3 0 (because 07:03:42) 4 9 (because 07:03:52 - 2012-05-09 07:03:43) 2 0 (because 07:06:30 is outside 2 min interval of 1st user_id=2 set) This is what I've tried, although I can't group on seconds_interval (even if I could, I'm not sure this is the right direction): SELECT (max(tr.event_time)-min(tr.event_time)) as seconds_interval FROM some_table tr INNER JOIN TrackingRaw tr2 ON (tr.event_time BETWEEN tr2.event_time - INTERVAL 2 MINUTE AND tr2.event_time + INTERVAL 2 MINUTE) GROUP BY seconds_interval

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  • MySql Query lag time / deadlock?

    - by Click Upvote
    When there are multiple PHP scripts running in parallel, each making an UPDATE query to the same record in the same table repeatedly, is it possible for there to be a 'lag time' before the table is updated with each query? I have basically 5-6 instances of a PHP script running in parallel, having been launched via cron. Each script gets all the records in the items table, and then loops through them and processes them. However, to avoid processing the same item more than once, I store the id of the last item being processed in a seperate table. So this is how my code works: function getCurrentItem() { $sql = "SELECT currentItemId from settings"; $result = $this->db->query($sql); return $result->get('currentItemId'); } function setCurrentItem($id) { $sql = "UPDATE settings SET currentItemId='$id'"; $this->db->query($sql); } $currentItem = $this->getCurrentItem(); $sql = "SELECT * FROM items WHERE status='pending' AND id > $currentItem'"; $result = $this->db->query($sql); $items = $result->getAll(); foreach ($items as $i) { //Check if $i has been processed by a different instance of the script, and if so, //leave it untouched. if ($this->getCurrentItem() > $i->id) continue; $this->setCurrentItem($i->id); // Process the item here } But despite of all the precautions, most items are being processed more than once. Which makes me think that there is some lag time between the update queries being run by the PHP script, and when the database actually updates the record. Is it true? And if so, what other mechanism should I use to ensure that the PHP scripts always get only the latest currentItemId even when there are multiple scripts running in parrallel? Would using a text file instead of the db help?

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  • MySQL - How To Avoid Repair With Keycache?

    - by dvancouver
    I have had some experience with optimizing the my.cnf file but my database has around 4 million records (MyISAM). I am trying to restore from a mysqldump but every time I do I eventually get the dreaded "Repair With Keycache", that may take days. Is there anyway to get past this and let it roll as "Repair By Sorting"? I have 2GB RAM, Dual Cores, lots of extra hard-drive space. Snip out of my.cnf: set-variable = max_connections=650 set-variable = key_buffer=256M set-variable = myisam_sort_buffer_size=64M set-variable = join_buffer=1M set-variable = record_buffer=1M set-variable = sort_buffer_size=2M set-variable = read_buffer_size=2M set-variable = query_cache_size=32M set-variable = table_cache=1024 set-variable = thread_cache_size=256 set-variable = wait_timeout=7200 set-variable = connect_timeout=10 set-variable = max_allowed_packet=16M set-variable = max_connect_errors=10 set-variable = thread_concurrency=8

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  • Help with MySQL Join Statement

    - by JasonS
    Hi, I just built a website and have realised that I need to have a top 3 highest rated albums.. I haven't built in something that keeps track of the ratings. Ratings are stored separately. Can someone show me how to put these together please. SELECT id, name FROM albums LIMIT 3 SELECT rating FROM ratings WHERE url=CONCAT('albums/show/', album.id) Let me just flesh it out a bit. I need to get back the following: From the albums table. id, name. From the ratings table I need to get back the average rating. ROUND((rating+rating+rating) / total ratings) The ratings. Users can rate everything on my website so I have a generic ratings table. The rating is stored with the url of the page it applies to. Hence, to get album ratings I need to have 'albums/show/{album_id}'. In hind sight I should have had a type and id field but it is a bit late now with a lunch iminient. Any help is much appreciated.

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  • using SET datatype in mysql

    - by Dan Snyder
    Is it possible to set a varaible to a query result such as: DECLARE result INT; SET result = (SELECT index FROM table WHERE data = 'xxxx' LIMIT 1); Assuming of course you know that there will only be one result set

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  • MySQL SET and ENUM types in CakePHP framework

    - by Andrew Bashtannik
    Hi! I need to use SET and ENUM types in my CakePHP 1.3 project. I found some advices, but all them are too old (2004-2006) and full of crazy methods, like modifying cake's core files. Also, CakePHP developers said that SET and ENUM types are not supported. Example: I have SET('alpha','beta') field, and I need to use this data as checkboxes in add & edit actions. Is there any way to add normal support (Form helpers etc.) of SET and ENUM fields?

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  • MYSQL query to return rows that are NOT in a set

    - by iglurat
    Hi, I have two tables: Contact (id,name) Link (id, contact_id, source_id) I have the following query which works that returns the contacts with the source_id of 8 in the Link table. SELECT name FROM `Contact` LEFT JOIN Link ON Link.contact_id = Contact.id WHERE Link.source_id=8; However I am a little stumped on how to return a list of all the contacts which are NOT associated with source_id of 8. A simple != will not work as contacts without any links are not returned. Thanks.

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  • I need unusual ordering mysql results

    - by Patrick
    Im trying to order results ASCENDING from the current date this is what im using now; SELECT * FROM friends JOIN bdays ON bdays.user = friends.friendname WHERE username = $userid ORDER BY DATE_FORMAT(date, '%m %d') any ideas? example ordering by date now, sorts the birthdays starting at january what i need, is instead of starting the list at january, is starting it from the current date. So, instead of; January February March April May June July August September November December It will order them like this; April (current month/day) May June July August September November December January February March April (all the way up to yesterday)

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  • MySQL column not found

    - by vian
    The SQL query without where statement runs great and outputs good results, but when I include WHERE condition it shows Unknown column 'date1' in 'where clause'. What's the problem? SELECT IF(e.weekly, DATE_ADD(DATE(e.time), INTERVAL CEIL(DATEDIFF('2010-04-08', e.time)/7) WEEK), DATE(e.time)) AS `e.date1`, `v`.`lat`, `v`.`lng` FROM `events` AS `e` INNER JOIN `venues` AS `v` ON e.venue_id = v.id WHERE e.date1 > '2010-09-01'

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  • PHP and MySQL problem?

    - by TaG
    When my code is stored and saved and out putted I keep getting these slashes \\\\\ in my output text. how can I get rid of these slashes? Here is the PHP code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="about_me">About Me: </label> <textarea rows="8" cols="60" name="about_me" id="about_me"><?php if (isset($_POST['about_me'])) { echo mysqli_real_escape_string($mysqli, $_POST['about_me']); } else if(!empty($about_me)) { echo mysqli_real_escape_string($mysqli, $about_me); } ?></textarea></li> <li><label for="my-interests">My Interests: </label> <textarea rows="8" cols="60" name="interests" id="interests"><?php if (isset($_POST['interests'])) { echo mysqli_real_escape_string($mysqli, $_POST['interests']); } else if(!empty($interests)) { echo mysqli_real_escape_string($mysqli, $interests); } ?></textarea></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • PHP mySQL database check

    - by kielie
    Hi guys, I am having endless troubles with duplicate entries, so I need to check the database, and if a user has already entered that day, their entry will not be submitted and they will be redirected to a landing page that tells them they have already entered that day, and that they may only enter again tomorrow. The field I would like to check is the id_number field in the database, since each user has a unique id number, so basically, if a user with the same id number submitted on the same date they should be redirected to a landing page, how would I go about doing this? I am still new to a lot of this, so please be forgiving. Thanx in advance.

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  • mySQL Left Join on multiple tables with conditions

    - by Jarrod
    Hi, I have a problem. I have 4 tables: Invoice_Payment, Invoice, Client, and Calendar Basically, I have the below query, which works well, except, months with no date_due don't return. I.E only months with a date_due will be returned. I think I have to use a left join and join the calendar table with something like: LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field. But I'm having no luck SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Any help appreciated.

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  • MySQL Select problems

    - by John Nuñez
    Table #1: qa_returns_items Table #2: qa_returns_residues I have a long time trying to get this Result: item_code - item_quantity 2 - 1 3 - 2 IF qa_returns_items.item_code = qa_returns_residues.item_code AND status_code = 11 THEN item_quantity = qa_returns_items.item_quantity - qa_returns_residues.item_quantity ELSEIF qa_returns_items.item_code = qa_returns_residues.item_code AND status_code = 12 THEN item_quantity = qa_returns_items.item_quantity + qa_returns_residues.item_quantity ELSE show diferendes END IF I tried this Query: select SubQueryAlias.item_code, total_ecuation, SubQueryAlias.item_unitprice, SubQueryAlias.item_unitprice * total_ecuation as item_subtotal, item_discount, (SubQueryAlias.item_unitprice * total_ecuation) - item_discount as item_total from ( select ri.item_code , case status_code when 11 then ri.item_quantity - rr.item_quantity when 12 then ri.item_quantity + rr.item_quantity end as total_ecuation , rr.item_unitprice , rr.item_quantity , rr.item_discount * rr.item_quantity as item_discount from qa_returns_residues rr left join qa_returns_items ri on ri.item_code = rr.item_code WHERE ri.returnlog_code = 1 ) as SubQueryAlias where total_ecuation > 0 GROUP BY (item_code); The query returns this result: item_code - item_quantity 1 - 2 2 - 2

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  • MySQL how to sum subgroup first then sum total

    - by Sunry
    My data in table_1 and table_2. table_1 id_1 num ids_2 3 33 666,777,888 4 44 111,222,333 table_2 id_2 num 111 1 222 2 333 3 666 6 777 7 888 8 I only know how to do what I want with two steps: First LEFT JOIN to get: SELECT 1.id_1, sum(2.num) FROM table_1 AS 1 LEFT JOIN table_2 AS 2 on FIND_IN_SET(2.id_2, 1.ids_2) GROUP BY 1.id_1; id_1 sum(2.num) 3 6+7+8 4 1+2+3 Then LEFT JOIN with table_1 again to sum(table_1.num+sum(2.num)): id_1 sum(table_1.num+sum(table_2.num)) 3 6+7+8+33 4 1+2+3+44 Can I do it in only one SQL?

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  • MySQL slow query

    - by andrhamm
    SELECT items.item_id, items.category_id, items.title, items.description, items.quality, items.type, items.status, items.price, items.posted, items.modified, zip_code.state_prefix, zip_code.city, books.isbn13, books.isbn10, books.authors, books.publisher FROM ( ( items LEFT JOIN bookitems ON items.item_id = bookitems.item_id ) LEFT JOIN books ON books.isbn13 = bookitems.isbn13 ) LEFT JOIN zip_code ON zip_code.zip_code = items.item_zip WHERE items.rid = $rid` I am running this query to get the list of a user's items and their location. The zip_code table has over 40k records and this might be the issue. It currently takes up to 15 seconds to return a list of about 20 items! What can I do to make this query more efficient?

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  • MySQL: Transactions across multiple threads

    - by Zombies
    Preliminary: I have an application which maintains a thread pool of about 100 threads. Each thread can last about 1-30 seconds before a new task replaces it. When a thread end, that thread almost always will result in inserting 1-3 records into a table, this table is used by all of the threads. Right now, no transactional support exists, but I am trying to add that now. So... Goal I want to implement a transaction for this. The rules for whether or not this transaction commits or rollback reside in the main thread. Basically there is a simple function that will return a boolean. Can I implement a transaction across multiple connections? If not, can multiple threads share the same connection? (Note: there are a LOT of inserts going on here, and that is a requirement).

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  • MYSQL: Simplify this Query for better performance

    - by Treby
    How can i simplify this code. coz this uses subquerying SELECT ub.id_product as c_pid,DATE(ub.datetime_prchs)AS datePurchased,cb.bookname, (SELECT GROUP_CONCAT(c.userid ORDER BY c.userid ASC SEPARATOR ', ') FROM user_books ub INNER JOIN campus_bookinfo cb ON ub.id_product=cb.idx_campus_bookinfo LEFT JOIN customer c ON ub.id_customer=c.id_customer WHERE ub.id_product = c_pid )as buyer, cb.iAmount FROM user_books ub INNER JOIN campus_bookinfo cb ON ub.id_product=cb.idx_campus_bookinfo LEFT JOIN customer c ON ub.id_customer=c.id_customer WHERE ub.id_customer = 29 GROUP BY bookname ORDER BY ub.datetime_prchs I need a better code for the same output.. Thanks in advance

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  • MySQL where condition but not limited by it

    - by Manny Calavera
    Hello. I would like to run a query on my database like this: SELECT SUM( t1.value ) AS total1, SUM( t2.value ) AS total2, SUM( t3.value ) AS total3, SUM( t4.value ) AS total4 FROM pay1 t1, pay2 t2, pay3 t3, pay4 t4 WHERE t1.date = '2010-04-29' AND t2.date = '2010-04-29' AND t3.date = '2010-04-29' AND t4.date = '2010-04-29' I am generating a report on payments and I would like to see a total of payments from each table based on the matching date. The problem is that some of the tables would not meet the condition of date and I want them to show up with 0 value if not. Currently, if any of the tables does not match the date, I get 0 results. I want to display value of 0 anywhere the date is not met and other fields should appear with the found values. The perfect operand for me would be "ANDOR" so that it won't be limited by any date that doesn't math in any table. Unfortunately, ANDOR does not exist as I am aware of so what should I do ? Can anyone help ? Thanks.

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  • problems with mysql "or"

    - by Simon
    i have a problem with "and" "or" syntax!!! here is my query. . . SELECT `act1`.`name`, `act1`.`surname`, `act2`.`name`, `act2`.`surname`, `act3`.`name`, `act3`.`surname` FROM videos, actors AS act1, actors AS act2, actors AS act3 WHERE videos.ident = 'somethink' AND ( act1.id = videos.id_actor1 OR act2.id = videos.id_actor2 OR act3.id = videos.id_actor3 ) it returns me all variations of {name, surname}, but why!!! i want the name and surname of first axactly, second and thirth, if they exist!!! halp me please

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  • How to simplify my country select menu PHP/mysql

    - by user342391
    I have a select menu that displays countries. It looks at the DB and judging by the value in the db shows the option as selected. Is there a simpler way off doing this than: if ($country == 'AG') {echo '<option value="AG" selected="selected">Antigua</option>';} else {echo '<option value="AG">Antigua</option>';}; if ($country == 'AR') {echo '<option value="AR" selected="selected">Argentina</option>';} else {echo '<option value="AR">Argentina</option>';}; if ($country == 'AM') {echo '<option value="AM" selected="selected">Armenia</option>';} else {echo '<option value="AM">Armenia</option>';}; if ($country == 'AW') {echo '<option value="AW" selected="selected">Aruba</option>';} else {echo '<option value="AW">Aruba</option>';}; if ($country == 'AU') {echo '<option value="AU" selected="selected">Australia</option>';} else {echo '<option value="AU">Australia</option >';}; if ($country == 'AT') {echo '<option value="AT" selected="selected">Austria</option>';} else {echo '<option value="AT">Austria</option>';}; if ($country == 'AZ') {echo '<option value="AZ" selected="selected">Azerbaijan</option>';} else {echo '<option value="AZ">Azerbaijan</option>';}; if ($country == 'BS') {echo '<option value="BS" selected="selected">Bahamas</option>';} else {echo '<option value="BS">Bahamas</option>';}; if ($country == 'BH') {echo '<option value="BH" selected="selected">Bahrain</option>';} else {echo '<option value="BH">Bahrain</option>';}; There are a lot of countries and doing this would be madness wouldn't it????

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