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  • Where to store Android preference keys?

    - by pixel
    When I create preference activity I define all preferences in xml file. Every preference has a key defined in this xml. But when I access preference I write: SharedPreferences appPreferences = PreferenceManager.getDefaultSharedPreferences(this); boolean foo_value = appPreferences.getBoolean("foo_key_defined_in_xml", false); Is there any way to avoid acessing "foo_key_defined_in_xml" in hard-coded way? Maybe there is a possibility to access it in R style way?

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  • [Android] Show default selection color for custom listview

    - by Diego
    Hello, I have a listview with a custom BaseAdapter. Each row of the listview has a TextView and a CheckBox. The problem is when I click (or touch) any row, the textview foreground becomes gray, instead of the default behavior (background - green, textview foreground - white). Here is the code: row.xml: <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" style="@style/layout"> <TextView android:id="@+id/main_lv_item_textView" style="@style/textViewBig" android:layout_alignParentLeft="true"/> <CheckBox android:id="@+id/main_lv_item_checkBox" style="@style/checkBox" android:layout_width="wrap_content" android:layout_alignParentRight="true"/> </RelativeLayout> Custom Adapter: public class CustomAdapter extends BaseAdapter { private List<Profile> profiles; private LayoutInflater inflater; private TextView tvName; private CheckBox cbEnabled; public CustomAdapter(List<Profile> profiles) { this.profiles = profiles; inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); } public int getCount() { return profiles.size(); } public Object getItem(int position) { return profiles.get(position); } public long getItemId(int position) { return position; } public View getView(final int position, View convertView, ViewGroup parent) { View row = inflater.inflate(R.layout.main_lv_item, null); final Profile profile = profiles.get(position); tvName = (TextView) row.findViewById(R.id.main_lv_item_textView); registerForContextMenu(tvName); cbEnabled = (CheckBox) row.findViewById(R.id.main_lv_item_checkBox); tvName.setText(profile.getName()); if (profile.isEnabled()) { cbEnabled.setChecked(true); } tvName.setOnClickListener(new OnClickListener() { public void onClick(View v) { Bundle bundle = new Bundle(); bundle.putString(PROFILE_NAME_KEY, profile.getName()); Intent intent = new Intent(context, GuiProfile.class); intent.putExtras(bundle); startActivity(intent); } }); tvName.setOnLongClickListener(new OnLongClickListener() { public boolean onLongClick(View v) { selectedProfileName = ((TextView) v).getText().toString(); return false; } }); cbEnabled.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() { public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) { if (!profile.isEnabled()) { for (Profile profile : profiles) { if (profile.isEnabled()) { profile.setEnabled(false); Database.getInstance().storeProfile(profile); } } } profile.setEnabled(isChecked); Database.getInstance().storeProfile(profile); updateListView(); } }); return row; } } Any help would be appreciated.

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  • regex breaks on \n

    - by Sourabh
    hi segmentText = <input from textarea>; testRgx = [/( \d+\.| [^\W\d_]\.|.)+?([!?.?](?= |$)|$)/g]; arrSegments = segmentText.match(testRgx); This expression fails if segmentText has \n or other white spaces in it.I want to add \n in to the list of chars that the above pattern use [!?.?] = [!?.?\n] so that the segment is separated based on the \n character

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  • Multi language CMS?

    - by Adam
    Is there any CMS such as expression engine or wordpress that allows a user to click a button and convert all the text to another language (it would have to be human generated otherwise it has too many mistakes probably). I'd like to know if there are any good solutions out there that work for real world use, in like business company websites.

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  • Is there a way for a user to disable an AlertDialog completely?

    - by NewGuyChris
    In the app I'm making, I have an "if" statement where if two strings are saved to a certain string, an AlertDialog pops up. These strings will stay the same for some users, thus having this AlertDialog constantly pop up whenever they launch the activity where the ALertDialog is set to appear. Code (I have no setNegativeButton as of yet): private void SetWarning() { AlertDialog.Builder alert = new AlertDialog.Builder(this); alert.setTitle("Warning!"); alert.setMessage(R.string.Warning); alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { //No action needed; just close the AlertDialog. } }); alert.show(); } Here is a segment of my code that makes this AlertDialog appear: SharedPreferences sharedPreferences = getSharedPreferences("MY_PREF", MODE_PRIVATE); String s = sharedPreferences2.getString("MEM1", ""); String s2 = sharedPreferences2.getString("MEM2", ""); if(s.equals("String1") && s2.equals("String2")) SetWarning(); Is there a way to make an "alert.setNegativeButton" method where if the user clicks it, the AlertDialog will NEVER appear again? I'm thinking of maybe somehow implementing another SavedPreferences somehow so it saves the users selection and will then prevent the AlertDialog from ever appearing again. So far, to no luck. I've searched to find nothing, other than people asking how to disable buttons in an AlertDialog. Thank you! New updated code: alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { //set sharedpreferences boolean called DONTSHOWAGAIN to true; SharedPreferences sharedPreferences2 = getSharedPreferences("MY_PREF", MODE_PRIVATE); Boolean dontShowAgain = sharedPreferences2.getBoolean("dontShowAgain ", false); SharedPreferences.Editor ed = sharedPreferences2.edit(); ed.putBoolean("dontShowAgain", true); ed.commit(); } }); alert.show(); } private void StringWarning() { SharedPreferences sharedPreferences2 = getSharedPreferences("MY_PREF", MODE_PRIVATE); String s = sharedPreferences2.getString("MEM1", ""); String s2 = sharedPreferences2.getString("MEM2", ""); if(s.equals("String1") && s2.equals("String2")){ if(!dontShowAgain){ SetWarningExamConflict(); } }

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  • Haskell type classes and type families (cont'd)

    - by Giuseppe Maggiore
    I need some help in figuring a compiler error which is really driving me nuts... I have the following type class: infixl 7 --> class Selectable a s b where type Res a s b :: * (-->) :: (CNum n) => (Reference s a) -> (n,(a->b),(a->b->a)) -> Res a s b which I instance twice. First time goes like a charm: instance Selectable a s b where type Res a s b = Reference s b (-->) (Reference get set) (_,read,write) = (Reference (\s -> let (v,s') = get s in (read v,s')) (\s -> \x -> let (v,s') = get s v' = write v x (_,s'') = set s' v' in (x,s''))) since the type checker infers (-->) :: Reference s a -> (n,a->b,a->b->a) -> Reference s b and this signature matches with the class signature for (--) since Res a s b = Reference s b Now I add a second instance and everything breaks: instance (Recursive a, Rec a ~ reca) => Selectable a s (Method reca b c) where type Res a s (Method reca b c) = b -> Reference s c (-->) (Reference get set) (_,read,write) = \(x :: b) -> from_constant( Constant(\(s :: s)-> let (v,s') = get s :: (a,s) m = read v ry = m x :: Reference (reca) c (y,v') = getter ry (cons v) :: (c,reca) v'' = elim v' (_,s'') = set s' v'' in (y,s''))) :: Reference s c the compiler complains that Couldn't match expected type `Res a s (Method reca b c)' against inferred type `b -> Reference s c' The lambda expression `\ (x :: b) -> ...' has one argument, which does not match its type In the expression: \ (x :: b) -> from_constant (Constant (\ (s :: s) -> let ... in ...)) :: Reference s c In the definition of `-->': --> (Reference get set) (_, read, write) = \ (x :: b) -> from_constant (Constant (\ (s :: s) -> ...)) :: Reference s c reading carefully the compiler is telling me that it has inferred the type of (--) thusly: (-->) :: Reference s a -> (n,a->(Method reca b c),a->(Method reca b c)->a) -> (b -> Reference s c) which is correct since Res a s (Method reca b c) = b -> Reference s c but why can't it match the two definitions? Sorry for not offering a more succint and standalone example, but in this case I cannot figure how to do it...

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  • Engineering techniques to diminish MVVM Driven Development time?

    - by Oscar Cabrero
    Hi Currently we just start releasing modules for a big project in MVVM but seems like the deliverables are starting to encounter a slowness with this model, such things as the learning curve effort and the fact that mvvm do requires a bit more code than other patterns, What Programming and software engineering techniques do you employ or thing could help us reduce the effort and speed up development? things like code generation with T4 templates, ligth MVVM frameworks, use Expression Blend, hire a designer to hanle UX. Thanks for any advice you could provide.

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  • eregi replace replacement

    - by apis17
    hi, since eregi replace was deprecated on version 5.3 i want to make my program compatible with new version of php http://php.net/manual/en/function.eregi-replace.php so, i'm trying to use preg_replace like this preg_replace(",",'','20,000.00'); but come with error i'm familiar with eregi_replace(',','','20,000.00'); i'm not familiar with regex expression. what is the best replacement for eregi_replace?

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  • PHP something faster than explode to get filename from URL

    - by FFish
    My URL's can be absolute or relative: $rel = "date/album/001.jpg"; $abs = "http://www.site.com/date/album/image.jpg"; function getFilename($url) { $imgName = explode("/", $url); $imgName = $imgName[count($imgName) - 1]; echo $imgName; } There must be a faster way to do this right? Maybe a reg expression? But that's Chinese to me..

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  • Android - binding to service

    - by tommy
    Hi: I can't seem to get an activity to bind to a service in the same package. The activity looks like this: public class myApp extends TabActivity { static private String TAG = "myApp"; private myService mService = null; private ServiceConnection mServiceConn = new ServiceConnection(){ public void onServiceConnected(ComponentName name, IBinder service) { Log.v(TAG, "Service: " + name + " connected"); mService = ((myService.myBinder)service).getService(); } public void onServiceDisconnected(ComponentName name) { Log.v(TAG, "Service: " + name + " disconnected"); } }; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); doBind(); Log.i(TAG, "Started (UI Thread)"); // set content setContentView(R.layout.main); Resources res = getResources(); // Resource object to get Drawables TabHost tabHost = getTabHost(); // The activity TabHost ... add some tabs here.... tabHost.setCurrentTab(0); } private void doBind(){ Intent i = new Intent(this,myService.class); if( bindService(i, mServiceConn, 0 )){ Log.i(TAG, "Service bound"); } else { Log.e(TAG, "Service not bound"); } } } Then the service: public class myService extends Service { private String TAG = "myService"; private boolean mRunning = false; @Override public int onStartCommand(Intent intent, int flags, int startid) { Log.i(TAG,"Service start"); mRunning = true; Log.d(TAG,"Finished onStartCommand"); return START_STICKY; } /* * Called on service stop */ @Override public void onDestroy(){ Log.i(TAG,"onDestroy"); mRunning = false; super.onDestroy(); } @Override public IBinder onBind(Intent intent) { return mBinder; } boolean isRunning() { return mRunning; } /* * class for binding */ private final IBinder mBinder = new myBinder(); public class myBinder extends Binder { myService getService() { return myService.this; } } } bindService returns true, but onServiceConnection is never called (mService is always null, so I can't do something like mService.isRunning() ) The manifest entry for the service is just: <service android:name=".myService"></service> I was copying the code direct from the Android developers site, but I must have missed something.

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  • Way to partialy match a Ruby string using Regexp

    - by Fabiano PS
    I'm working on 2 cases: assume I have those var: a = "hello" b = "hello-SP" b = "not_hello" 1 - Any partial matches I want to accept any string that has the var a inside, so b and c would match. 2 - Patterned match I want to match a string that has a inside, followed by '-', so b would match, c does not. I am having problem, because I always used the syntax /expression/ to define Regexp, so how dinamicaly define an RegExp on Ruby??

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  • Question about JSON?

    - by Alex
    Hi all, I have a fairly simple question: In Javascript how can I return the boolean (if its found in the JSON) rather than the actual value? Example: var myJSON = { "foo" : "bar", "bar" : "foo" }; var keyToLookFor = "foo"; var found = myJSON[keyToLookFor]; if (found) { // I know I can test if the string exists in the if } // but is there a way I could just return something like: return found; // instead of testing found in the if statement and then returning true?

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  • NullPointerException on TextView

    - by Stephen Adipradhana
    i get a null pointer exception and the program crash on each time i want to update the highscore text using setText(). what causes this problem? this code is when i set my layout, the layout is a part of the gameView using opengl, and i put the highscore textview on the upper left corner public void onCreate(Bundle savedInstanceState) { SFEngine.display = ((WindowManager)getSystemService(Context.WINDOW_SERVICE)).getDefaultDisplay();//ambl ukuran width height layar super.onCreate(savedInstanceState); gameView = new SFGameView(this); gameView.setLayoutParams(new RelativeLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.MATCH_PARENT)); RelativeLayout layout = new RelativeLayout(this); layout.setLayoutParams(new FrameLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.MATCH_PARENT)); TextView textBox = new TextView(this); textBox.setId(1); textBox.setText("HIGH SCORE"); textBox.setBackgroundColor(Color.BLUE); textBox.setWidth(SFEngine.display.getWidth()/2); textBox.setHeight(50); Button pauseButton = new Button(this); pauseButton.setText("PAUSE"); pauseButton.setHeight(50); pauseButton.setWidth(SFEngine.display.getWidth()/2); pauseButton.setOnTouchListener(new OnTouchListener(){ public boolean onTouch(View v, MotionEvent e) { //pause game SFEngine.isPlaying = false; Intent i1 = new Intent(SFGames.this, pause.class); gameView.onPause(); startActivityForResult(i1,0);//hrs pk result soalny mw blk lg return true; } }); RelativeLayout.LayoutParams lp_pause = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT); RelativeLayout.LayoutParams lp_hs = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT); lp_hs.addRule(RelativeLayout.ALIGN_PARENT_LEFT); lp_pause.addRule(RelativeLayout.ALIGN_PARENT_TOP); lp_pause.addRule(RelativeLayout.ALIGN_PARENT_RIGHT); textBox.setLayoutParams(lp_hs); pauseButton.setLayoutParams(lp_pause); layout.addView(gameView); layout.addView(textBox); layout.addView(pauseButton); setContentView(layout); and here is the setText code public boolean onTouchEvent (MotionEvent event){//buat nerima input user if(!SFEngine.isPlaying){ finish(); } textBox.setText("High Score :" + SFEngine.score);//here is the source of the prob .....

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  • C preprocessor: using #if inside #define?

    - by Wxy
    I want to write a macro that spits out code based on the boolean value of its parameter. So say DEF_CONST(true) should be expanded into "const", and DEF_CONST(false) should be expanded into nothing. Clearly the following doesn't work because we can't use another preprocessor inside #defines: #define DEF_CONST(b_const) \ #if (b_const) \ const \ #endif Any idea about how to do it?

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  • Do I need to specify a return type for an anonymous function in javascript / typescript?

    - by Anne
    I have the following function: $('td:eq(' + iColumn + ') input', oSettings.oApi._fnGetTrNodes(oSettings)) .each(function () { aData.push(this.value); }); In typescript I am getting a message saying: Error 3 Function declared a non-void return type, but has no return expression Why am I getting this message? I can resolve the message by saying "return true". Should I always specify a return type for this?

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  • Help with SQL query in C#

    - by DanSogaard
    I'm trying to rename the columns. The syntax should be the column name between double quotes incase of two words, like this: SELECT p_Name "Product Name" from items So I'm trying to do it in C# code like this: string sqlqry1 = "SELECT p_Name \"Prodcut Name\" from items"; But I get an error: Syntax error (missing operator) in query expression 'p_Name "Prodcut Name"'. It seems am having somthing wrong with the quotes, but I can't figure out.

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