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  • Mac Safari randomly recreating cookie when I refresh my login screen. Very bizarre

    - by mcintyre321
    We have found an issue in our app where Safari on the Mac randomly recreates a login cookie from a logged off session. I have a fiddler archive with this behaviour here. Note that some stuff has been removed from this to make it easier to get, but nothing which sets a cookie or anything has been taken out - only repetitions of requests 3-8. I'll talk you through the running order Request 1: user logs out via call to /logout.aspx - Set-Cookie returned setting cookie expiry date to 1999 Requests 2-8: user refreshes login page sending calls to root or /res/en-US/s.js - no cookie is sent to server or received back, and access is denied. I have cut out a lot of requests of this nature from the log as they are boring Request 9: request for /res/en-US/s.js - Hv3 authentication cookie has mysteriously reappeared! Wat. There was NO set-cookie! WTFF! Request 10+ : now the cookie has reappeared, the site logs the user in AGAIN The cookie, when examined in Safari looks like <dict> <key>Created</key> <real>259603523.26834899</real> <key>Domain</key> <string>.mysite.dev</string> <key>Expires</key> <date>2010-03-24T16:05:22Z</date> <key>HttpOnly</key> <string>TRUE</string> <key>Name</key> <string>.Hv3</string> <key>Path</key> <string>/</string> </dict> One thing to note is that in Safari, the cookie domain is .mysite.dev not mysite.dev (which is the cookie domain specified in web.config) - however, given that access is denied in requests 2-8, it looks like the cookie has expired OK. If you look in the list of cookies in the browser during 2-8, the .Hv3 cookie is not there. Is this our bug or Safari's? What can I do to stop it happening?

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  • Submit button on nested form submits the outer form in IE7

    - by Mike Christensen
    I have the following code on my Home.aspx page: <form id="frmJump" method="post" action="Views/ViewsHome.aspx"> <input name="JumpProject" /><input type="submit" value="Go" /> </form> However, when I click the "Go" button, the page posts back to Home.aspx rather than going to ViewsHome.aspx. I even tried adding some script to force the form to submit: <input name="JumpProject" onkeypress="if(event.keyCode == 13) { this.form.submit(); return false; }" /> But still even if I press ENTER, the Home.aspx page is reloaded. The only thing I can see that might be borking things is this form is actually a child form of the main POSTBACK form that ASP.NET injects into the page. I'm sure there's something stupid I'm missing and this post will get 800 downvotes instantly banishing me back into the n00b realm, but perhaps I haven't gotten enough sleep lately and I'm missing something stupid. This is on IE7 and an ASP.NET 4.0 backend. I also have jQuery libraries loaded on the page incase jQuery can improve this somehow. Thanks!

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  • Update Input Value With jQuery, Old Value Submitted to Form

    - by Tyler DeWitt
    I've got a form with an input with id/name league_id <form accept-charset="UTF-8" action="/user" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="?"><input name="authenticity_token" type="hidden" value="bb92urX83ivxOZZJzWLJMcr5ZSuamowO9O9Sxh5gqKo="></div> <input id="league_id" name="league_id" type="text" value="11"> <select class="sport_selector" id="sport_type_id" name="sport_type_id"><option value="5" selected="selected">Football</option> <option value="25">Women's Soccer</option> <option value="30">Volleyball</option> <option value="10">Men's Soccer</option></select> <input name="commit" type="submit" value="Save changes"> </form> In another part of my page, I have a drop down that, when changed, clears the value of league_id $("#sport_type_id").change -> $("#league_id").val(null) $(this).parents('form:first').submit() If I debug this page, I can see the value get wiped from the text box, but when the form is submitted, my controller always gets the old value. I tried changing the name of the input and got the same results.

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  • This code is not submitting to a form? Why

    - by Ankur
    Since I am using get I expect to see the submitted values appended to the queryString but instead all I see is the URL of the servlet being called with nothing added at the end. <form id="editClassList" name="editClassList" method="get" action="EditClassList"> <% HashMap<Integer,String> classes = new HashMap<Integer,String>(); classes = (HashMap<Integer,String>) request.getAttribute("classes"); %> <% if(classes.size()==0){ %> <label><input class="small-link" type="text" id="add-this-class" size="42" value="" /></label> <% } %> <% Set<Integer> classIds = new HashSet<Integer>(); classIds = classes.keySet(); Iterator<Integer> itr = classIds.iterator(); while(itr.hasNext()){ int nextId = (Integer)itr.next(); %> <label><input class="small-link" type="text" id="<% out.print(nextId); %>" size="42" value="<% out.print(classes.get(nextId)); %>" /> </label> <img id="add-class" src="images/add.png" width="16" height="16" /><br /> <label><input class="small-link" type="text" id="class-to-add" size="42" value="" /></label> <% } %> <label><input type="submit" id="save-class-btn" value="Save Class(es)" /></label> </form>

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  • jQuery append breaks my HTML form (with submit button)

    - by JimFing
    I'm trying to create a form with a submit button via jQuery using append(). So the following: out.append('<form name="input" action="/createuser" method="get">'); out.append('Username: <input type="text" name="user" />'); out.append('<input type="submit" value="Submit" />'); out.append('</form>'); However, clicking on submit, nothing happens! However if I do the following: var s = '<form name="input" action="/createuser" method="get">' + 'Username: <input type="text" name="user" />' + '<input type="submit" value="Submit" />' + '</form>'; out.html(s); Then the submit button works fine! I'm happy to use the 2nd method, but would rather know what the problem is here. Thanks

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  • form Validation white page not showing errors

    - by Jess McKenzie
    In the example below I am wanting to do all of the 'safety' checks on the $_POST variables but it seems when I click submit I get a white page why? I am wanting it to show the errors etc Form Process: /* check if the form is submitted */ if (isset($_POST['submitButton'])) { $fullName = $_POST['fullname']; if($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($fullName)) { if (!ctype_alpha(str_replace(array("'", "-"), "",$fullName))) { $errorfullName .= '<span class="errorfullName">*First name should be alpha characters only.</span>'; } if (strlen($fullName) < 3 OR strlen($fullName) > 40) { $errorfullName .= '<span class="errorfullName">*First name should be within 3-40 characters long.</span>'; } } }

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  • Filtering results and pagination

    - by alj
    I have a template that shows a filter form and below it a list of the result records. I bind the form to the request so that the filter form sets itself to the options the user submitted when the results are returned. I also use pagination. Using the code in the pagination documentation means that when the user clicks for the next page, the form data is lost. What is the best way of dealing with pagination and filtering in this way? Passing the querystring to the paginiation links. Change the pagination links to form buttons and therefore submit the filter form at the same time, but this assumes that the user hasn't messed about with the filter options. As above but with the original data as hidden fields. ALJ

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  • How can I organize many results in a selectbox?

    - by zeckdude
    I have a select box that is part of a form. It is currently querying the addresses table and displaying the addresses into the select box. I plan on having up to 100 addresses. I'm looking for a solution where I can show all the states if the user clicks on the select box. Then if the user hovers over a state it will show all the addresses for that specific state. Then if the user clicks on an address, it will show that as the picked option in the select box. This is like a dropdown menu within a select box. Does anyone know where I can find a solution as this?

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  • Livevalidation: only validate when default value is changed

    - by usr122212
    Hello there! I am validating my html form with livevalidation and everything works great except for one feature. I have a input field with a default value age, I only want the livevalidation to validate when it says something other than "age". so maybe the user will type in 20 then the validation will fire checking its things but if left as "age" it won't check it all. But as of now, it just checks everything with a validation script and this is a problem for me as I have lots of fields in my form and some of them are optional so when I hit submit, the livevalidation checks the age field as well even if the user didnt touch it to begin with. Would this be possible with livevalidation ? Thanks for the help.

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  • How do I prevent form from redirecting after submission?

    - by Noor
    I have searched the site and I've found various solutions, most of them suggesting using return false; Problem is that I'm using this piece of code to submit the form: $(function() { $("#snd").click(function() { var dendar = "http://" + $("#inpt").val() + ":" + $("#pwd").val() + "secretsite.lol/something.xml"; $("#formen").attr("action", dendar); $("#formen").submit(); alert(dendar); return false; }); }); The alert is just there to let me know that the form has been submitted.. Thanks guys!

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  • Creating two Windows by running one as a process from another - C

    - by Jamie Keeling
    Hello, I have a windows form that has a simple menu and performs a simple operation, I want to be able to create another windows form with all the functionality of a menu bar, message pump etc.. as a seperate process so I can then share the results of the operation to the second window. I.E. 1) Form A opens Form B opens as a separate process 2)Form A performs operation 3)Form A passes results via memory to Form B 4)Form B display results I'm confused as to how to go about it, the main app runs fine but i'm not sure how to add a second window if the first one already exists. I hope it makes sense. Thanks!

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  • Creating additional Window by a thread - C

    - by Jamie Keeling
    Hello, I have a windows form that has a simple menu and performs a simple operation, I want to be able to create another windows form with all the functionality of a menu bar, message pump etc.. as a separate thread so I can then share the results of the operation to the second window. I.E. 1) Form A opens Form B opens as a separate thread 2)Form A performs operation 3)Form A passes results via memory to Form B 4)Form B display results I'm confused as to how to go about it, the main app runs fine but i'm not sure how to add a second window if the first one already exists. I hope it makes sense. Thanks!

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • Why does setting a form's enabled property crash the application?

    - by Ruirize
    private void launchbutton_Click(object sender, EventArgs e) { launchbutton.Enabled = false; Process proc = new Process(); proc.EnableRaisingEvents = true; proc.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden; //The arguments/filename is set here, just removed for privacy. proc.Exited += new EventHandler(procExit); proc.Start(); } private void procExit(object sender, EventArgs e) { MessageBox.Show("YAY","WOOT"); Thread.Sleep(2000); launchbutton.Enabled = true; } 2 Seconds after I quit the created process, my program crashes. Why?

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • How to protect a form HTML/PHP with JS callback to AS3

    - by Jk_
    Hi guys, I'm developing a Flash website (as3) where I need to be able to upload directly to YouTube by using the DATA API. However in order to do so, I had to use a proper HTML form on top of my flash object. Why? Because of the Browser Based Upload restictions. I first hide the form using JQuery and with a little CSS the form is display just where I want it. Within flash I use ExternalInterface.call() to show/hide the form when I need it! ExternalInterface.call("YTUploader.showIt"); The upload process is working great my only problem is that the form can be displayed easily... You just need a tool like firebug and you can use the form wherever you want on my flash app. So I was wandering which will be the best way to 'protect' this form or the best way to limit its access. Any advices will be appreciated. Thanks for your time. Jk.

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  • Javascript "inlet" or "offset" function for drop-list options

    - by Camran
    I have seen on several sites that drop list values can have offsets... For example this drop-list: Fruits Apple Banana Orange Colors Red White Black The above are all options, but some have "inlets" or "offsets" or whatever you want to call it. How is this done with js? (regular js, not jquery at the moment) Thanks If you need more input let me know.

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  • Form is creating already loaded attributes in addition to new attributes, how do I ignore the first?

    - by looloobs
    In my application you: Have an admin user that signs on and that user has a role (separate model), then I use the declarative_authorization plugin to give access to certain areas. That admin user can also register new users in the system, when they do this (using Authlogic) they fill out a nested form that includes that new users' role. So what is happening is the role of the admin user is being loaded by the declarative_authorization and then the nested form using the has_many_nested_attributes is loading that existing role as well as the new role for the new user (users can have many roles). Is there some way I can tell the new User being created to ignore the role assigned to the current_user and only create the role in the form for the new user? I have looked through a lot of different things, but it seems to get more complicated that these are nested attributes. Thanks in advance.

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  • Sending Javascript variables.

    - by shinjuo
    I have a page that allows a user to choose some things in a form and it will calculate the weight using javascript. It breaks it up into 5 variables that I need to send to another page. Originally I was just having it put the variable into a text box and then I was posting that text box. However I dont want to have 5 text boxes. So now I need to somehow send or post the five variables to another page. Here is my javascript function. I need to post weightBoxOne - weightBoxFive js function function getWeight(){ var weightBoxOne; var weightBoxTwo; var totalWeight; var box = .5; var quantity = document.dhform.quantity.value; var cardSize = document.dhform.cardSize.value; if(cardSize == 0.0141){ if(quantity <= 1000){ weightBoxOne = (quantity * cardSize) + box; totalWeight = weightBoxOne; }else if(quantity > 1000 && quantity <= 2000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = ((quantity - 1000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo; }else if(quantity > 2000 && quantity <= 3000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = ((quantity - 2000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree; }else if(quantity > 3000 && quantity <= 4000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = (1000 * cardSize) + box; weightBoxFour = ((quantity - 3000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree + weightBoxFour; }else{ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = (1000 * cardSize) + box; weightBoxFour = (1000 * cardSize) + box; weightBoxFive = ((quantity - 4000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree + weightBoxFour + weightBoxFive; } }else if(cardSize == 0.00949){ if(quantity <= 4000){ weightBoxOne = (quantity * cardSize) + box; totalWeight = weightBoxOne; }else{ weightBoxOne = (4000 * cardSize) + box; weightBoxTwo = ((quantity - 4000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo; } } document.rates.weight.value = totalWeight; } //--> this is the form that was originally posting <form action="getRates.php" name="rates" method="post" onSubmit="popupform(this, 'join')"> <table style="width: 216px"> <tr> <td style="width: 115px; height: 49px;"><span class="style16">Weight</span><br/> <input type="text" id="weight" name="weight" size="10" maxlength="4"/> </td> <td align="right" style="width: 68px; height: 49px;" valign="top"><span class="style16">Zip Code</span><br/> <input type="text" id="zip" name="zip" size="10" maxlength="5"/> </td> </tr> <tr> <td style="width: 115px"> <input name="submit" type="submit" value="Get Rate Costs" style="width: 138px" />

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  • Is it possible to split a form into multiple erb modules?

    - by Ya.
    I have a large form with multiple tabs and would like to be able to split it into multiple modules and include each as a partial. Something like: main.html.erb: <%= form_for (@myobject) do |f| %> <%= render "module1" %> .... module1.html.erb: <%= f.text_field :field1 %> ... Needless to say, when I do it like this I get an error from module1 that "f" is undefined. Is there a way to split form fields into multiple modules?

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