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  • Generate a sequence of Fibonacci number in Scala

    - by qin
    def fibSeq(n: Int): List[Int] = { var ret = scala.collection.mutable.ListBuffer[Int](1, 2) while (ret(ret.length - 1) < n) { val temp = ret(ret.length - 1) + ret(ret.length - 2) if (temp >= n) { return ret.toList } ret += temp } ret.toList } So the above is my code to generate a Fibonacci sequence using Scala to a value n. I am wondering if there is a more elegant way to do this in Scala?

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  • LinkedList insert tied to inserted object

    - by wrongusername
    I have code that looks like this: public class Polynomial { List<Term> term = new LinkedList<Term>(); and it seems that whenever I do something like term.add(anotherTerm), with anotherTerm being... another Term object, it seems anotherTerm is referencing the same thing as what I've just inserted into term so that whenever I try to change anotherTerm, term.get(2) (let's say) get's changed too. How can I prevent this from happening?

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  • How to extract List<int> from Dictionary<int, string>?

    - by DaveDev
    I have a method that takes a List<int>, which is a list of IDs. The source of my data is a Dictionary<int, string> where the integers are what I want a list of. Is there a better way to get this than the following code? var list = new List<int>(); foreach (var kvp in myDictionary) { list.Add(pair.Key); } ExecuteMyMethod(list);

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  • Is it alright to call len() in a loop's conditional statement?

    - by DormoTheNord
    In C, it is considered bad practice to call strlen like this: for ( i = 0; strlen ( str ) != foo; i++ ) { // stuff } The reason, of course, is that it is inefficient since it "counts" the characters in a string multiple times. However, in Python, I see code like this quite often: for i in range ( 0, len ( list ) ): # stuff Is this bad practice? Should I store the result of len() in a variable and use that?

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  • How to test an iPhone application update?

    - by sfkaos
    I already have an iPhone application (version 1.0) available in the App Store and am ready to submit a newer version (version 1.1). How do I test the new upgrade to make sure that the current sqlite database and property list files on the earlier version do not get deleted/overwritten etc? The new version assumes the old data in both the sqlite database and property lists remain. Or better yet, is there a resource I can use to walk me through what to watch for when developing an application update?

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  • Looking into ASP.Net MVC 4.0 Mobile Development - part 1

    - by nikolaosk
    In this post I will be looking how ASP.Net MVC 4.0 helps us to create web solutions that target mobile devices.We all experience the magic that is the World Wide Web through mobile devices. Millions of people around the world, use tablets and smartphones to view the contents of websites,e-shops and portals.ASP.Net MVC 4.0 includes a new mobile project template and the ability to render a different set of views for different types of devices.There is a new feature that is called browser overriding which allows us to control exactly what a user is going to see from your web application regardless of what type of device he is using.In order to follow along this post you must have Visual Studio 2012 and .Net Framework 4.5 installed in your machine.Download and install VS 2012 using this link.My machine runs on Windows 8 and Visual Studio 2012 works just fine.It will work fine in Windows 7 as well so do not worry if you do not have the latest Microsoft operating system.1) Launch VS 2012 and create a new Web Forms application by going to File - >New Project - > ASP.Net MVC 4 Web Application and then click OKHave a look at the picture below  2) From the available templates select Mobile Application and then click OK.Have a look at the picture below 3) When I run the application I get the mobile view of the page. I would like to show you what a typical ASP.Net MVC 4.0 application looks like. So I will create a new simple ASP.Net MVC 4.0 Web Application. When I run the application I get the normal page view.Have a look at the picture below.On the left is the mobile view and on the right the normal view. As you can see we have more or less the same content in our mobile application (log in,register) compared with the normal ASP.Net MVC 4.0 application but it is optimised for mobile devices. 4) Let me explain how and when the mobile view is selected and finally rendered.There is a feature in MVC 4.0 that is called Display Modes and with this feature the runtime will select a view.If we have 2 views e.g contact.mobile.cshtml and contact.cshtml in our application the Controller at some point will instruct the runtime to select and render a view named contact.The runtime will look at the browser making the request and will determine if it is a mobile browser or a desktop browser. So if there is a request from my IPhone Safari browser for a particular site, if there is a mobile view the MVC 4.0 will select it and render it. If there is not a mobile view, the normal view will be rendered.5) In the  ASP.Net MVC 4.0 (Internet application) I created earlier (not the first project which was a mobile one) I can run it once more and see how it looks on the browser. If I want to view it with a mobile browser I must download one emulator like Opera Mobile.You can download Opera Mobile hereWhen I run the application I get the same view in both the desktop and the mobile browser. That was to be expected. Have a look at the picture below 6) Then I create another version of the _Layout.mobile.cshtml view in the Shared folder.I simply copy and paste the _Layout.cshtml  into the same folder and then rename it to _Layout.mobile.cshtml and then just alter the contents of the _Layout.mobile.cshtml.When I run again the application I get a different view on the desktop browser and a different one on the Opera mobile browser.Have a look at the picture below ?he Controller will instruct the ASP.Net runtime to select and render a view named _Layout.mobile.cshtml when the request will come from a mobile browser.?he runtime knows that a browser is a mobile one through the ASP.Net browser capability provider. Hope it helps!!!

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  • List<T> and IEnumerable difference

    - by Jonas Elfström
    While implementing this generic merge sort, as a kind of Code Kata, I stumbled on a difference between IEnumerable and List that I need help to figure out. Here's the MergeSort public class MergeSort<T> { public IEnumerable<T> Sort(IEnumerable<T> arr) { if (arr.Count() <= 1) return arr; int middle = arr.Count() / 2; var left = arr.Take(middle).ToList(); var right = arr.Skip(middle).ToList(); return Merge(Sort(left), Sort(right)); } private static IEnumerable<T> Merge(IEnumerable<T> left, IEnumerable<T> right) { var arrSorted = new List<T>(); while (left.Count() > 0 && right.Count() > 0) { if (Comparer<T>.Default.Compare(left.First(), right.First()) < 0) { arrSorted.Add(left.First()); left=left.Skip(1); } else { arrSorted.Add(right.First()); right=right.Skip(1); } } return arrSorted.Concat(left).Concat(right); } } If I remove the .ToList() on the left and right variables it fails to sort correctly. Do you see why? Example var ints = new List<int> { 5, 8, 2, 1, 7 }; var mergeSortInt = new MergeSort<int>(); var sortedInts = mergeSortInt.Sort(ints); With .ToList() [0]: 1 [1]: 2 [2]: 5 [3]: 7 [4]: 8 Without .ToList() [0]: 1 [1]: 2 [2]: 5 [3]: 7 [4]: 2 Edit It was my stupid test that got me. I tested it like this: var sortedInts = mergeSortInt.Sort(ints); ints.Sort(); if (Enumerable.SequenceEqual(ints, sortedInts)) Console.WriteLine("ints sorts ok"); just changing the first row to var sortedInts = mergeSortInt.Sort(ints).ToList(); removes the problem (and the lazy evaluation). EDIT 2010-12-29 I thought I would figure out just how the lazy evaluation messes things up here but I just don't get it. Remove the .ToList() in the Sort method above like this var left = arr.Take(middle); var right = arr.Skip(middle); then try this var ints = new List<int> { 5, 8, 2 }; var mergeSortInt = new MergeSort<int>(); var sortedInts = mergeSortInt.Sort(ints); ints.Sort(); if (Enumerable.SequenceEqual(ints, sortedInts)) Console.WriteLine("ints sorts ok"); When debugging You can see that before ints.Sort() a sortedInts.ToList() returns [0]: 2 [1]: 5 [2]: 8 but after ints.Sort() it returns [0]: 2 [1]: 5 [2]: 5 What is really happening here?

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  • What causes a WPF ListCollectionView that uses custom sorting to re-sort its items?

    - by Drew Noakes
    Consider this code (type names genericised for the purposes of example): // Bound to ListBox.ItemsSource _items = new ObservableCollection<Item>(); // ...Items are added here ... // Specify custom IComparer for this collection view _itemsView = CollectionViewSource.GetDefaultView(_items) ((ListCollectionView)_itemsView).CustomSort = new ItemComparer(); When I set CustomSort, the collection is sorted as I expect. However I require the data to re-sort itself at runtime in response to the changing of the properties on Item. The Item class derives from INotifyPropertyChanged and I know that the property fires correctly as my data template updates the values on screen, only the sorting logic is not being called. I have also tried raising INotifyPropertyChanged.PropertyChanged passing an empty string, to see if a generic notification would cause the sorting to be initiated. No bananas. EDIT In response to Kent's suggestion I thought I'd point out that sorting the items using this has the same result, namely that the collection sorts once but does not re-sort as the data changes: _itemsView.SortDescriptions.Add( new SortDescription("PropertyName", ListSortDirection.Ascending));

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  • web2py server-side comments

    - by MikeWyatt
    In a web2py view, how do I comment out server-side code? In ASP.NET, I can surround any HTML or code tags with <%-- and --% and that block will not be compiled or sent to the client. Velocity does the same thing with #* and *#. Is there an equivalent in web2py? ASP.NET <div> <p><%=foo.bar%></p> <%-- don't print twice! <p><%=foo.bar%></p> --%> </div> web2py <div> <p><%=foo.bar%></p> ??? don't print twice! <p><%=foo.bar%></p> ??? </div>

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  • producing a typewriter-like effect

    - by Tony Ennis
    Android newb here. Please use small words :-) I'd like to simulate typewriter output on my Android. The output being displayed is generated by a game and is somewhat freeform. The effect I want to see individual characters appear at a rate of about 6 characters a second. When a 'carriage return' is seen, I'd like to insert a delay then resume typing on the left. What are some suggestions on views? Would the view of choice for this be a TextView? Even that seems like overkill for this read-only coarsely scrolling output. I saw something on this thread about an AsyncTask. That looks useful. Perhaps my game will write to some manner of buffer, and a subclass of AsyncTask will pull characters out every .15 seconds or so, add them to the TextView, then invalidate() the TextView? Sound like a plan?

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  • Zend Framework: how to remove rendered views in the controller?

    - by takpar
    i want to render one of these sets of views: head body-$id1 foot OR head body-$id2 foot which set exsists. i do it like this: try { $this->render("head"); $this->render("body-$id1"); $this->render("foot"); } catch (Exception $e) { $this->render("head"); $this->render("body-$id2"); $this->render("foot"); } but it causes the head view be rendered twice if body-$id1 does not exists. do you have a better solution? in another saying, may i check the existance of body-$id1 before rendering it?

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  • In MVC framworks (such as Ruby on Rails), does usually Model spell as singular and controller and vi

    - by Jian Lin
    I usually see Ruby on Rails books using script/generate model Story name:string link:string which is a singular Story, while when it is controller script/generate controller Stories index then the Story now is Stories, which is plural. Is this a standard on Ruby on Rails? Is it true in other MVC frameworks too, like CakePHP, Symfony, Django, or TurboGears? I see that in the book Rails Space, the controller is also called User, which is the same as the model name, and it is the only exception I see. Update: also, when scaffold is done on Ruby on Rails, then automatically, the model is singular and the controller and view are both plural.

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  • General approach for posting business logic status messages to UI?

    - by generalt
    Hello all. I have been struggling with this question for awhile now, and I haven't reached a conclusion. I'm not typically a UI programmer, so forgive the noobishness. I'm writing a typical application with a UI layer (WPF) and a business layer. I want to post status messages to the UI from the business layer (perhaps deep within the business layer), but I don't want the business layer to have any knowledge of the UI. Is there a generally accepted pattern for this? I was thinking to have a message queue of some sort to which the business layer posts status messages, and have the view model of the UI subscribe to that queue and intercept messages from the queue and route them to the UI. Is that a good approach? Is there somewhere else I should start? Thank you.

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  • Client Id for Property (ASP.Net MVC)

    - by Felipe
    Hi guys... I'm begginer in asp.net mvc, and i have a doubs: I'm trying to do a label for a TextBox in my View and I'd like to know, how can I take a Id that will be render in client to generete scripts... for example: <label for="<%=x.Name.?ClientId?%>"> Name: </label> <%=Html.TextBoxFor(x=>x.Name) %> What need I put in "?ClientId?" to make sure that correct Id will be render to the corresponding control ? Thanks Cheers

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  • MVC 3 ModelView passing parameters between view & controller

    - by Tobias Vandenbempt
    I've been playing with MVC 3 in a test project and have the following issue. I have Group & Subscriber entities and those are coupled through a SubscriberGroup table. Using the DetailView of Group I open a view of SubscriberGroup containing all subscribers. This list has the option to filter. So far it all works, however when I call the AddToGroup method on the controller it fails. Specifically it goes into the method but doesn't pass the subscriberCheckedModels list. Am I doing something wrong? View: SubscriberGroup Index.aspx <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.master" Inherits="System.Web.Mvc.ViewPage<Mail.Models.SubscriberCheckedListViewModel>" %> … <h2 class="common-box-title"> Add Subscribers to Group</h2> <p> <% using (Html.BeginForm("Index", "SubscriberGroup")) { %> <input name="filter" id="filter" type="text" /> <input type="submit" value="Search" /> <%} %> </p> <% using (Html.BeginForm("AddToGroup", "SubscriberGroup", Model,FormMethod.Get, null)) { %> <fieldset> <div style="display: inline-block; width: 70%; vertical-align: top;"> <% if (Model.subscribers.Count() != 0) { %> <table class="hor-minimalist-b"> <tr> <th> Add To Group </th> <th> Full Name </th> <th> Email </th> <th> Customer </th> </tr> <% foreach (var item in Model.subscribers) { %> <tr> <td> <%= Html.CheckBoxFor(modelItem => item.AddToGroup)%> </td> <td> <%= Html.DisplayFor(modelItem => item.subscriber.LastName)%> <%= Html.ActionLink(item.subscriber.FirstName + " " + item.subscriber.LastName, "Details", new { id = item.subscriber.SubscriberID })%> </td> <td> <%: Html.DisplayFor(modelItem => item.subscriber.Email)%> </td> <td> <%: Html.DisplayFor(modelItem => item.subscriber.Customer.Company)%> <%= Html.HiddenFor(modelItem => item.subscriber) %> </td> </tr> <% } %> <% ViewBag.subscribers = Model.subscribers; %> probeersel <%= Html.HiddenFor(model => model.subscribers) %> probeersel </table> <%} %> <%else { %> <p> No subscribers found.</p> <%} %> <input type="submit" value="Add Subscribers" /> </div> </fieldset> <%} %> Controller: SubscriberGroupController using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using System.Web.Security; using Mail.Models; namespace Mail.Controllers { public class SubscriberGroupController : Controller { private int groupID; private MailDBEntities db = new MailDBEntities(); // // GET: /SubscriberGroup/ public ActionResult Index(int id) { groupID = id; MembershipUser myObject = Membership.GetUser(); Guid UserID = Guid.Parse(myObject.ProviderUserKey.ToString()); UserCustomer usercustomer = db.UserCustomers.Single(s => s.UserID == UserID); var subscribers = from subscriber in db.Subscribers where (subscriber.CustomerID == usercustomer.CustomerID) | (subscriber.CustomerID == 0) select new SubscriberCheckedModel { subscriber = subscriber, AddToGroup = false }; SubscriberCheckedListViewModel test = new SubscriberCheckedListViewModel(); test.subscribers = subscribers; return View(test); } [HttpPost] public ActionResult Index(string filter) { MembershipUser myObject = Membership.GetUser(); Guid UserID = Guid.Parse(myObject.ProviderUserKey.ToString()); UserCustomer usercustomer = db.UserCustomers.Single(s => s.UserID == UserID); var subscribers2 = from subscriber in db.Subscribers where ((subscriber.FirstName.Contains(filter)|| subscriber.LastName.Contains(filter)) && (subscriber.CustomerID == usercustomer.CustomerID || subscriber.CustomerID == 0)) select new SubscriberCheckedModel { subscriber = subscriber, AddToGroup = false }; SubscriberCheckedListViewModel test = new SubscriberCheckedListViewModel(); test.subscribers = subscribers2.ToList(); return View(test); } [HttpPost] public ActionResult AddToGroup(SubscriberCheckedListViewModel test) { //test is null return RedirectToAction("Details", "Group", new { id = groupID }); } } } ViewModel: SubscriberGroupModel using System.Collections.Generic; using Mail; namespace Mail.Models { public class SubscriberCheckedModel { public Subscriber subscriber { get; set; } public bool AddToGroup { get; set; } } public class SubscriberCheckedListViewModel { public IEnumerable<SubscriberCheckedModel> subscribers { get; set; } } }

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  • Can't view order in magento

    - by koko
    Hi, I've been setting up a fresh magento 1.4.0.1 install, working great so far. I did some test orders just to see. Everything works fine, but when I click on "view order" under "my orders", I get a bunch of error messages: There has been an error processing your request Notice: iconv_substr() [function.iconv-substr]: Unknown error (0) in /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php on line 98 Trace: #0 [internal function]: mageCoreErrorHandler(8, 'iconv_substr() ...', '/data/web/A1423...', 98, Array) #1 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php(98): iconv_substr('1', 0, 50, 'UTF-8') #2 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php(173): Mage_Core_Helper_String-substr('1', 0, 50) #3 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Helper/String.php(112): Mage_Core_Helper_String-str_split('1', 50) #4 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/sales/order/items/renderer/default.phtml(58): Mage_Core_Helper_String-splitInjection('1') #5 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #6 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #7 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #8 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #9 /data/web/A14237/htdocs/magento/app/code/core/Mage/Sales/Block/Items/Abstract.php(137): Mage_Core_Block_Abstract-toHtml() #10 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/sales/order/items.phtml(52): Mage_Sales_Block_Items_Abstract-getItemHtml(Object(Mage_Sales_Model_Order_Item)) #11 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #12 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #13 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #14 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #15 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(516): Mage_Core_Block_Abstract-toHtml() #16 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(467): Mage_Core_Block_Abstract-_getChildHtml('order_items', true) #17 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/sales/order/view.phtml(64): Mage_Core_Block_Abstract-getChildHtml('order_items') #18 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #19 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #20 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #21 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #22 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(516): Mage_Core_Block_Abstract-toHtml() #23 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(463): Mage_Core_Block_Abstract-_getChildHtml('sales.order.vie...', true) #24 /data/web/A14237/htdocs/magento/app/code/core/Mage/Page/Block/Html/Wrapper.php(52): Mage_Core_Block_Abstract-getChildHtml('', true, true) #25 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Page_Block_Html_Wrapper-_toHtml() #26 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Text/List.php(43): Mage_Core_Block_Abstract-toHtml() #27 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Text_List-_toHtml() #28 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(516): Mage_Core_Block_Abstract-toHtml() #29 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(467): Mage_Core_Block_Abstract-_getChildHtml('content', true) #30 /data/web/A14237/htdocs/magento/app/design/frontend/base/default/template/page/2columns-left.phtml(48): Mage_Core_Block_Abstract-getChildHtml('content') #31 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(189): include('/data/web/A1423...') #32 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(225): Mage_Core_Block_Template-fetchView('frontend/base/d...') #33 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Template.php(242): Mage_Core_Block_Template-renderView() #34 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Block/Abstract.php(674): Mage_Core_Block_Template-_toHtml() #35 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Model/Layout.php(536): Mage_Core_Block_Abstract-toHtml() #36 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Action.php(389): Mage_Core_Model_Layout-getOutput() #37 /data/web/A14237/htdocs/magento/app/code/core/Mage/Sales/controllers/OrderController.php(100): Mage_Core_Controller_Varien_Action-renderLayout() #38 /data/web/A14237/htdocs/magento/app/code/core/Mage/Sales/controllers/OrderController.php(136): Mage_Sales_OrderController-_viewAction() #39 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Action.php(418): Mage_Sales_OrderController-viewAction() #40 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Router/Standard.php(254): Mage_Core_Controller_Varien_Action-dispatch('view') #41 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Controller/Varien/Front.php(177): Mage_Core_Controller_Varien_Router_Standard-match(Object(Mage_Core_Controller_Request_Http)) #42 /data/web/A14237/htdocs/magento/app/code/core/Mage/Core/Model/App.php(304): Mage_Core_Controller_Varien_Front-dispatch() #43 /data/web/A14237/htdocs/magento/app/Mage.php(596): Mage_Core_Model_App-run(Array) #44 /data/web/A14237/htdocs/magento/index.php(78): Mage::run('', 'store') #45 {main} gtx, koko

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  • Partial view links not working in Fire Fox

    - by user329540
    I have a MVC4 asp.net application, I have two layouts a main layout for the main page and a second layout for the nested pages. The problem I have is with the second layout, on this layout I call a partial view which has my navigation links. In IE the navigation menu displays fine and when each item is clicked it navigates as expected. However in FF when the page renders the navigation bar is displayed but it has no 'click functionality' if you will its as if its simply text. My layout of nested page: <header> <img src="../../Images/fronttop.png" id="nestedPageheader" alt="Background Img"/> <div class="content-wrapper"> <section > <nav> <div id="navcontainer"> </div> </nav> </section> <div> </header> The script to retreive partial view and information for dynamic links on layout page. <script type="text/javascript"> var menuLoaded = false; $(document).ready(function () { if($('#navcontainer')[0].innerHTML.trim() == "") { $.ajax({ url: "@Url.Content("~/Home/MenuLayout")", type: "GET", success: function (response, status, xhr) { var nvContainer = $('#navcontainer'); nvContainer.html(response); menuLoaded = true; }, error: function (XMLHttpRequest, textStatus, errorThrown) { var nvContainer = $('#navcontainer'); nvContainer.html(errorThrown); } }); } }); </script> May partial view: @model Mscl.OpCost.Web.Models.stuffmodel <div class="menu"> <ul> <li><a>@Html.ActionLink("Home", "Index", "Home")</a></li> <li><a>@Html.ActionLink("some stuff", "stuffs", "stuff")</a></li> <li> <h5><a><span>somestuff</span></a></h5> <ul> <li><a>stuffs1s</a> <ul> @foreach (var image in Model.stuffs.Where(g => g.Grouping == 1)) { <li> <a>@Html.ActionLink(image.Title, "stuffs", "stuff", new { Id = image.CategoryId }, null)</a> </li> } </ul> </li> </ul> </il> </ul> </div> I need to know why this works fine in IE but why its not working in FF(all versions). Any assistance would be appreciated.

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  • Python: Improving long cumulative sum

    - by Bo102010
    I have a program that operates on a large set of experimental data. The data is stored as a list of objects that are instances of a class with the following attributes: time_point - the time of the sample cluster - the name of the cluster of nodes from which the sample was taken code - the name of the node from which the sample was taken qty1 = the value of the sample for the first quantity qty2 = the value of the sample for the second quantity I need to derive some values from the data set, grouped in three ways - once for the sample as a whole, once for each cluster of nodes, and once for each node. The values I need to derive depend on the (time sorted) cumulative sums of qty1 and qty2: the maximum value of the element-wise sum of the cumulative sums of qty1 and qty2, the time point at which that maximum value occurred, and the values of qty1 and qty2 at that time point. I came up with the following solution: dataset.sort(key=operator.attrgetter('time_point')) # For the whole set sys_qty1 = 0 sys_qty2 = 0 sys_combo = 0 sys_max = 0 # For the cluster grouping cluster_qty1 = defaultdict(int) cluster_qty2 = defaultdict(int) cluster_combo = defaultdict(int) cluster_max = defaultdict(int) cluster_peak = defaultdict(int) # For the node grouping node_qty1 = defaultdict(int) node_qty2 = defaultdict(int) node_combo = defaultdict(int) node_max = defaultdict(int) node_peak = defaultdict(int) for t in dataset: # For the whole system ###################################################### sys_qty1 += t.qty1 sys_qty2 += t.qty2 sys_combo = sys_qty1 + sys_qty2 if sys_combo > sys_max: sys_max = sys_combo # The Peak class is to record the time point and the cumulative quantities system_peak = Peak(time_point=t.time_point, qty1=sys_qty1, qty2=sys_qty2) # For the cluster grouping ################################################## cluster_qty1[t.cluster] += t.qty1 cluster_qty2[t.cluster] += t.qty2 cluster_combo[t.cluster] = cluster_qty1[t.cluster] + cluster_qty2[t.cluster] if cluster_combo[t.cluster] > cluster_max[t.cluster]: cluster_max[t.cluster] = cluster_combo[t.cluster] cluster_peak[t.cluster] = Peak(time_point=t.time_point, qty1=cluster_qty1[t.cluster], qty2=cluster_qty2[t.cluster]) # For the node grouping ##################################################### node_qty1[t.node] += t.qty1 node_qty2[t.node] += t.qty2 node_combo[t.node] = node_qty1[t.node] + node_qty2[t.node] if node_combo[t.node] > node_max[t.node]: node_max[t.node] = node_combo[t.node] node_peak[t.node] = Peak(time_point=t.time_point, qty1=node_qty1[t.node], qty2=node_qty2[t.node]) This produces the correct output, but I'm wondering if it can be made more readable/Pythonic, and/or faster/more scalable. The above is attractive in that it only loops through the (large) dataset once, but unattractive in that I've essentially copied/pasted three copies of the same algorithm. To avoid the copy/paste issues of the above, I tried this also: def find_peaks(level, dataset): def grouping(object, attr_name): if attr_name == 'system': return attr_name else: return object.__dict__[attrname] cuml_qty1 = defaultdict(int) cuml_qty2 = defaultdict(int) cuml_combo = defaultdict(int) level_max = defaultdict(int) level_peak = defaultdict(int) for t in dataset: cuml_qty1[grouping(t, level)] += t.qty1 cuml_qty2[grouping(t, level)] += t.qty2 cuml_combo[grouping(t, level)] = (cuml_qty1[grouping(t, level)] + cuml_qty2[grouping(t, level)]) if cuml_combo[grouping(t, level)] > level_max[grouping(t, level)]: level_max[grouping(t, level)] = cuml_combo[grouping(t, level)] level_peak[grouping(t, level)] = Peak(time_point=t.time_point, qty1=node_qty1[grouping(t, level)], qty2=node_qty2[grouping(t, level)]) return level_peak system_peak = find_peaks('system', dataset) cluster_peak = find_peaks('cluster', dataset) node_peak = find_peaks('node', dataset) For the (non-grouped) system-level calculations, I also came up with this, which is pretty: dataset.sort(key=operator.attrgetter('time_point')) def cuml_sum(seq): rseq = [] t = 0 for i in seq: t += i rseq.append(t) return rseq time_get = operator.attrgetter('time_point') q1_get = operator.attrgetter('qty1') q2_get = operator.attrgetter('qty2') timeline = [time_get(t) for t in dataset] cuml_qty1 = cuml_sum([q1_get(t) for t in dataset]) cuml_qty2 = cuml_sum([q2_get(t) for t in dataset]) cuml_combo = [q1 + q2 for q1, q2 in zip(cuml_qty1, cuml_qty2)] combo_max = max(cuml_combo) time_max = timeline.index(combo_max) q1_at_max = cuml_qty1.index(time_max) q2_at_max = cuml_qty2.index(time_max) However, despite this version's cool use of list comprehensions and zip(), it loops through the dataset three times just for the system-level calculations, and I can't think of a good way to do the cluster-level and node-level calaculations without doing something slow like: timeline = defaultdict(int) cuml_qty1 = defaultdict(int) #...etc. for c in cluster_list: timeline[c] = [time_get(t) for t in dataset if t.cluster == c] cuml_qty1[c] = [q1_get(t) for t in dataset if t.cluster == c] #...etc. Does anyone here at Stack Overflow have suggestions for improvements? The first snippet above runs well for my initial dataset (on the order of a million records), but later datasets will have more records and clusters/nodes, so scalability is a concern. This is my first non-trivial use of Python, and I want to make sure I'm taking proper advantage of the language (this is replacing a very convoluted set of SQL queries, and earlier versions of the Python version were essentially very ineffecient straight transalations of what that did). I don't normally do much programming, so I may be missing something elementary. Many thanks!

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  • Post calls RedirectToAction but view specified in RedirectToAction is not rendered

    - by W4IK
    Here's some of the html <form id="frmSubmit" action="/Viewer" style="display:none;"> <div id="renderSubmit" class="renderReport"> <input type="hidden" name="reportYear" id="reportYear" value="" /> <input type="hidden" name="reportMonth" id="reportMonth" value="" /> <input type="hidden" name="propIds" id="propIds" value="" /> <input type="hidden" name="reportName" id="reportName" value="" /> <input type="hidden" name="reportYearFrom" id="reportYearFrom" value="" /> <input type="hidden" name="reportMonthFrom" id="reportMonthFrom" value="" /> <input type="hidden" name="reportYearTo" id="reportYearTo" value="" /> <input type="hidden" name="reportMonthTo" id="reportMonthTo" value="" /> </div> </form> a little further down the page <div id="reportList" class="renderReport"> <fieldset style="width:105%;"> <legend class="reportStepLegend">Step 3. <br /> Click a report name below to view a report</legend> <br /> <% foreach (ReportMetaData item in (ReportMetaDataContainer)ViewData.Model) { %> <div> <input id=<%=item.SSRSName%> type="button" class="reportLink" value="<%=item.DisplayName%>" /> </div> <%}%> </fieldset> </div> Here's the javascript that gets called when the button is clicked $('.reportLink').click(function() { if (CheckDateAndProps() === true) { $('#reportName').val(this.id); var formData = $("#frmSubmit").serializeArray(); $.post('Home/PostViewer/', formData); } }); Note...i did have the $.post like so earlier...but it didn't seem to make any difference $.post('Home/PostViewer/', formData, function(data) { alert(data.Result); }, "json"); Here's the controller code [AcceptVerbs(HttpVerbs.Post)] public ActionResult PostViewer(string reportYear, string reportMonth, string propIds, string reportName, string reportYearFrom, string reportMonthFrom, string reportYearTo, string reportMonthTo) { return RedirectToAction("Viewer"); } All is good in the world up to this point..I'm hitting the above method and all the values are populated. Here's the get ActionResult method [AcceptVerbs(HttpVerbs.Get)] public ActionResult Viewer(string reportYear, string reportMonth, string propIds, string reportName, string reportYearFrom, string reportMonthFrom, string reportYearTo, string reportMonthTo) { return View(); } I'm hitting this too...not seeing any values in the parameters...but that's just because I haven't passed them in yet...I don't think that's whats keeping the Viewer page from displaying.? Now...one would one expect the Viewer view to be rendered...right?...well all I see is the page that this was called from...it never displays the Viewer page???!!?!? Here's the routes from global.asax routes.MapRoute( "Viewer", // Route name "Home/Viewer", // URL with parameters new { controller = "Home", action = "Viewer" } // Parameter defaults ); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = "" } // Parameter defaults ); I can browse directly to the page http://localhost:50083/Home/Viewer and when I do so I hit the get ActionResult method and the page renders just fine. Any help is greatly appreciated!

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  • Problem with jQuery plugin TinySort

    - by Volmar
    I'm trying to sort a list with the help of jQuery and the TinySort-plugin, and it works good but one thing is not working as i want. My Code is: <!doctype html> <html> <head> <meta charset="UTF-8" /> <title>TinySort problem</title> <script type="text/javascript" src="http://so.volmar.se/www/js/jquery.js"></script> <script type="text/javascript" src="http://so.volmar.se/www/js/jquery.tinysort.min.js"></script> <script type="text/javascript"> function pktsort(way){ if($("div#paket>ul>li.sortdiv>a#s_abc").text() == "A-S"){ $("div#paket>ul>li.sortdiv>a#s_abc").text("S-A"); $("div#paket ul li.sortable").tsort("",{place:"org",returns:true,order:"desc"}); }else{ $("div#paket>ul>li.sortdiv>a#s_abc").text("A-S"); $("div#paket ul li.sortable").tsort("",{place:"org",returns:true,order:"asc"}); } } </script> </head> <body> <div id="paket" title="Paket"> <ul class="rounded"> <li class="sortdiv">Sort: <a href="#" onclick="pktsort();" class="active_sort" id="s_abc">A-S</a></li> <li class="sortable">Almost Famous</li> <li class="sortable">Children of Men</li> <li class="sortable">Coeurs</li> <li class="sortable">Colossal Youth</li> <li class="sortable">Demonlover</li> <li class="sortable">Femme Fatale</li> <li class="sortable">I'm Not There</li> <li class="sortable">In the City of Sylvia</li> <li class="sortable">Into the Wild</li> <li class="sortable">Je rentre à la maison</li> <li class="sortable">King Kong</li> <li class="sortable">Little Miss Sunshine</li> <li class="sortable">Man on Wire</li> <li class="sortable">Milk</li> <li class="sortable">Monsters Inc.</li> <li class="sortable">My Winnipeg</li> <li class="sortable">Ne touchez pas la hache</li> <li class="sortable">Nói albinói</li> <li class="sortable">Regular Lovers</li> <li class="sortable">Shaun of the Dead</li> <li class="sortable">Silent Light</li> <li class="addmore"><b>This text is not supposed to move</b></li> </ul> </div> </body> </html> you can try it out at: http://www.volmar.se/list-prob.html MY PROBLEM IS: I don't want the <li class="addmore"> to move above all the <li class="sortable">-elements when i press the sort-link. i wan't it to always be in the bottom. you can find documentation of the TinySort plugin here. i've tried loads of combinations with place and returns propertys but i just can't get it right.

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  • Recursively created linked lists with a class, C++

    - by Jon Brant
    I'm using C++ to recursively make a hexagonal grid (using a multiply linked list style). I've got it set up to create neighboring tiles easily, but because I'm doing it recursively, I can only really create all 6 neighbors for a given tile. Obviously, this is causing duplicate tiles to be created and I'm trying to get rid of them in some way. Because I'm using a class, checking for null pointers doesn't seem to work. It's either failing to convert from my Tile class to and int, or somehow converting it but not doing it properly. I'm explicitly setting all pointers to NULL upon creation, and when I check to see if it still is, it says it's not even though I never touched it since initialization. Is there a specific way I'm supposed to do this? I can't even traverse the grid without NULLs of some kind Here's some of my relevant code. Yes, I know it's embarassing. Tile class header: class Tile { public: Tile(void); Tile(char *Filename); ~Tile(void); void show(void); bool LoadGLTextures(); void makeDisplayList(); void BindTexture(); void setFilename(char *newName); char Filename[100]; GLuint texture[2]; GLuint displayList; Tile *neighbor[6]; float xPos, yPos,zPos; };` Tile Initialization: Tile::Tile(void) { xPos=0.0f; yPos=0.0f; zPos=0.0f; glEnable(GL_DEPTH_TEST); strcpy(Filename, strcpy(Filename, "Data/BlueTile.bmp")); if(!BuildTexture(Filename, texture[0]))MessageBox(NULL,"Texture failed to load!","Crap!",MB_OK|MB_ICONASTERISK); for(int x=0;x<6;x++) { neighbor[x]=NULL; } } Creation of neighboring tiles: void MakeNeighbors(Tile *InputTile, int stacks) { for(int x=0;x<6;x++) { InputTile->neighbor[x]=new Tile();InputTile->neighbor[x]->xPos=0.0f;InputTile->neighbor[x]->yPos=0.0f;InputTile->zPos=float(stacks); } if(stacks) { for(int x=0;x<6;x++)MakeNeighbors(InputTile->neighbor[x],stacks-1); } } And finally, traversing the grid: void TraverseGrid(Tile *inputTile) { Tile *temp; for(int x=0;x<6;x++) if(inputTile->neighbor[x]) { temp=inputTile->neighbor[x]; temp->xPos=0.0f; TraverseGrid(temp); //MessageBox(NULL,"Not Null!","SHUTDOWN ERROR",MB_OK | MB_ICONINFORMATION); } } The key line is "if(inputTile-neighbor[x])" and whether I make it "if(inputTile-neighbor[x]==NULL)" or whatever I do, it just isn't handling it properly. Oh and I'm also aware that I haven't set up the list fully. It's only one direction now.

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