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  • Dynamic content doesn't work when loaded with ajax

    - by Wurlitzer
    I'm trying to load some dynamic content after the user has logged in, using $.ajax, like so: $.ajax({ url: "functions.php", type: "GET", data: login_info, datatype: 'html', async: false, success: function (response) { $('#main').html(response); } }); The problem is, that some events don't work, when loaded this way. I fixed the buttons with the .live() method, but a sortable list for example, doesn't work. How can I somehow refresh the DOM, and let jquery know of these new added elements? Thanks!

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  • Sort a list of dicts by dict values

    - by ensnare
    I have a list of dictionaries: [{'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}, {'title':'Apple News','title_url':'Apple_News','id':2}] I'd like to sort it by the title, so elements with A go before Z: [{'title':'Apple News','title_url':'Apple_News','id':2}, {'title':'New York Times', 'title_url':'New_York_Times','id':4}, {'title':'USA Today','title_url':'USA_Today','id':6}] What's the best way to do this? Also, is there a way to ensure the order of each dictionary key stays constant, e.g., always title, title_url, then id? Thank you.

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  • Lisp's "some" in Python?

    - by Mark Probst
    I have a list of strings and a list of filters (which are also strings, to be interpreted as regular expressions). I want a list of all the elements in my string list that are accepted by at least one of the filters. Ideally, I'd write [s for s in strings if some (lambda f: re.match (f, s), filters)] where some is defined as def some (pred, list): for x in list: res = pred (x) if res: return res return False Is something like that already available in Python, or is there a more idiomatic way to do this?

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  • [C] glist.c: No such file or directory

    - by sterh
    Hello, I have c/gtk+ application and GList which filled three elements, when i try to run following code with gdb: if (g_list_length(mw->img_list) > 0) printf(">0"); else printf("<0"); i see: Program received signal SIGSEGV, Segmentation fault. [Switching to Thread 0xb73c4700 (LWP 7936)] IA__g_list_length (list=0x6e6920) at glist.c:767 767 glist.c: No such file or directory. in glist.c What is it? Thank you.

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  • How Do I Use Multiple Versions of OpenSSL ... One for Apache and one for PHP

    - by Ken S.
    I have an Apache 2.2 (self-compiled version) server that is getting dinged during a PCI scan because it does not support TLS 1.1 or 1.2 ciphers. After some digging I found that the installed version of OpenSSL (0.9.8e) does not contain the newest TLS ciphers. So I went and downloaded and compiled the latest version of OpenSSL (1.0.1c) and have it installed in an alternate location within /opt so it wouldn't interfere with the installed version. What I would like to do is to compile Apache against the 1.0.1 libraries and keep the system-installed libraries for use with PHP, cURL, openssh, etc. I'm hoping that doing it this way will allow Apache to use the newest TLS but not break anything with any other programs that require the old libraries. I thought I could do this by adding an entry in to /etc/ld.so.conf that pointed to the new libraries, but I think this will conflict with the existing ones. i.e. two references to libcrypto could cause everything to have issues. The main reason for doing this is because of issues with PHP cURLing to external servers and having issues with the latest OpenSSL libs thus requiring edits to our PHP code. Would love some guidance on how best to accomplish this.

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  • Does add() on LinkedBlockingQueue notify waiting threads?

    - by obvio171
    I have a consumer thread taking elements from a LinkedBlockingQueue, and I make it sleep manually when it's empty. I use peek() to see if the queue empty because I have to do stuff because sending the thread to sleep, and I do that with queue.wait(). So, when I'm in another thread and add()an element to the queue, does that automatically notify the thread that was wait()ing on the queue?

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  • Erlang : flattening a list of strings

    - by ErJab
    I have a list like this: [["str1","str2"],["str3","str4"],["str5","str6"]] And I need to convert it to ["str1", "str2", "str3", "str4", "str5", "str6"] How do I do this? The problem is that I'm dealing with lists of strings, so when I do lists:flatten([["str1","str2"],["str3","str4"],["str5","str6"]]) I get "str1str2str3str4str5str6" However, if the elements of the original list where just atoms, then lists:flatten would have given me what I needed. How do I achieve the same with strings?

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  • How to define colors in XCodes' Interface Builder?

    - by favo
    Hi, I would like to copy colors between elements in the interface builder or define them using RGB values. I.e. copy the background color of a button to another button without duplicating the button. Or: Enter an exact RGB code using the interface builder. Currently I can do this only programmatically but the interface builder is meant to design the GUI, so there must be such possibilities. Thank you all in advance for your answers.

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  • How to develop a Jquery plugin to find the first child that match with a selector?

    - by Ivan
    I'm trying to make a Jquery plugin (findFirst()) to find the first child with a given characteristics (something in the middle of the find() and children() functions. For instance, given this markup: <div id="start"> <div> <span>Hello world</span> <ul class="valid-result"> ... </ul> <ul class="valid-result"> <li> <ul class="not-a-result"> ... </ul> </li> </ul> <div> <ul class="valid-result"> ... </ul> </div> </div> </div> If you ask for $("#start").findFirst('ul') it should return all ul lists that I have tagged with the valid-result class, but not the ul with class not-a-result. It is, this function has to find the first elements that matches with a given selector, but not the inner elements that match this selector. This is the first time I try to code a Jquery function, and what I've already read doesn't helps me too much with this. The function I have developed is this: jQuery.fn.findFirst = function (sel) { return this.map(function() { return $(this).children().map(function() { if ($(this).is(sel)) { return $(this); } else { return $(this).findFirst(sel); } }); }); } It works in the sense it tries to return the expected result, but the format it returns the result is very rare for me. I suppose the problem is something I don't understand about Jquery. Here you have the JFiddle where I'm testing. EDIT The expected result after $("#start").findFirst('ul') is a set with all UL that have the class 'valid-result' BUT it's not possible to use this class because it doesn't exist in a real case (it's just to try to explain the result). This is not equivalent to first(), because first returns only one element!

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  • LINQ Except operator and object equality

    - by Abhijeet Patel
    Here is an interesting issue I noticed when using the Except Operator: I have list of users from which I want to exclude some users: The list of users is coming from an XML file: The code goes like this: interface IUser { int ID { get; set; } string Name { get; set; } } class User: IUser { #region IUser Members public int ID { get; set; } public string Name { get; set; } #endregion public override string ToString() { return ID + ":" +Name; } public static IEnumerable<IUser> GetMatchingUsers(IEnumerable<IUser> users) { IEnumerable<IUser> localList = new List<User> { new User{ ID=4, Name="James"}, new User{ ID=5, Name="Tom"} }.OfType<IUser>(); var matches = from u in users join lu in localList on u.ID equals lu.ID select u; return matches; } } class Program { static void Main(string[] args) { XDocument doc = XDocument.Load("Users.xml"); IEnumerable<IUser> users = doc.Element("Users").Elements("User").Select (u => new User { ID = (int)u.Attribute("id"), Name = (string)u.Attribute("name") } ).OfType<IUser>(); //still a query, objects have not been materialized var matches = User.GetMatchingUsers(users); var excludes = users.Except(matches); // excludes should contain 6 users but here it contains 8 users } } When I call User.GetMatchingUsers(users) I get 2 matches as expected. The issue is that when I call users.Except(matches) The matching users are not being excluded at all! I am expecting 6 users ut "excludes" contains all 8 users instead. Since all I'm doing in GetMatchingUsers(IEnumerable users) is taking the IEnumerable and just returning the IUsers whose ID's match( 2 IUsers in this case), my understanding is that by default "Except" will use reference equality for comparing the objects to be excluded. Is this not how "Except" behaves? What is even more interesting is that if I materialize the objects using .ToList() and then get the matching users, and call "Except", everything works as expected! Like so: IEnumerable users = doc.Element("Users").Elements("User").Select (u = new User { ID = (int)u.Attribute("id"), Name = (string)u.Attribute("name") } ).OfType().ToList(); //explicity materializing all objects by calling ToList() var matches = User.GetMatchingUsers(users); var excludes = users.Except(matches); // excludes now contains 6 users as expected I don't see why I should need to materialize objects for calling "Except" given that its defined on IEnumerable? Any suggesstions / insights would be much appreciated.

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  • Javascript permission denied. Not cross domain?

    - by Dan
    I'm working on a web app that very rarely returns a Javacript permission denied error when attempting to access document elements. I'm well aware of cross-domain issues and I am actively pursuing them as a possible cause. My question is: are there other possible causes for a permission denied exception? Just want to make sure I'm looking in to all possible avenues. Thanks!

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  • itertools.product eliminating repeated reversed tuples

    - by genclik27
    I asked a question yesterday and thanks to Tim Peters, it is solved. The question is here; itertools.product eliminating repeated elements The new question is further version of this. This time I will generate tuples inside of tuples. Here is an example; lis = [[(1,2), (3,4)], [(5,2), (1,2)], [(2,1), (1,2)]] When I use it in itertools.product function this is what I get, ((1, 2), (5, 2), (2, 1)) ((1, 2), (5, 2), (1, 2)) ((1, 2), (1, 2), (2, 1)) ((1, 2), (1, 2), (1, 2)) ((3, 4), (5, 2), (2, 1)) ((3, 4), (5, 2), (1, 2)) ((3, 4), (1, 2), (2, 1)) ((3, 4), (1, 2), (1, 2)) I want to change it in a way that if a sequence has (a,b) inside of it, then it can not have (b,a). In this example if you look at this sequence ((3, 4), (1, 2), (2, 1)) it has (1,2) and (2,1) inside of it. So, this sequence ((3, 4), (1, 2), (2, 1)) should not be considered in the results. As I said, I asked similar question before, in that case it was not considering duplicate elements. I try to adapt it to my problem. Here is modified code. Changed parts in old version are taken in comments. def reverse_seq(seq): s = [] for i in range(len(seq)): s.append(seq[-i-1]) return tuple(s) def uprod(*seqs): def inner(i): if i == n: yield tuple(result) return for elt in sets[i] - reverse: #seen.add(elt) rvrs = reverse_seq(elt) reverse.add(rvrs) result[i] = elt for t in inner(i+1): yield t #seen.remove(elt) reverse.remove(rvrs) sets = [set(seq) for seq in seqs] n = len(sets) #seen = set() reverse = set() result = [None] * n for t in inner(0): yield t In my opinion this code should work but I am getting error for the input lis = [[(1,2), (3,4)], [(5,2), (1,2)], [(2,1), (1,2)]]. I could not understand where I am wrong. for i in uprod(*lis): print i Output is, ((1, 2), (1, 2), (1, 2)) Traceback (most recent call last): File "D:\Users\SUUSER\workspace tree\sequence_covering _array\denemeler_buraya.py", line 39, in <module> for i in uprod(*lis): File "D:\Users\SUUSER\workspace tree\sequence_covering _array\denemeler_buraya.py", line 32, in uprod for t in inner(0): File "D:\Users\SUUSER\workspace tree\sequence_covering _array\denemeler_buraya.py", line 22, in inner for t in inner(i+1): File "D:\Users\SUUSER\workspace tree\sequence_covering _array\denemeler_buraya.py", line 25, in inner reverse.remove(rvrs) KeyError: (2, 1) Thanks,

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  • XS:Group causes Schema to fail validation

    - by paulwhit
    I have an XML document based on a Schema that uses the xs:group element to bunch elements together. The result is an entity where name, address and phone number are defined in a group. This fails Schema validation in MS (Visual Studio) as well as XERCES (oXygen XML editor) Is there a workaround?

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  • What are pros and cons, If I choose HTML 5 for all new projects?

    - by jitendra
    Everyone, every blog is talking about HTML 5 and giving solution to use HTML in all browsers including IE6. Should we leave XHTML 1.0 now and go for HTML 5 and use JavaScript for IE6 support? Does all other desktop/mobile browser except IE6 supports HTML 5 without adding JavaScript? Will every browser render CSS written for HTML 5 elements? What about Screen- readers? What are pros and cons to choose HTML 5 for all new projects?

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  • Wait during iPhone UI modification

    - by paul simmons
    Hi, I am making modifications to elements on UI. There is no (extra) thread or any async. calls. However I want to give a slow motion effect, so wait specific time at each step in a for loop. How can I achieve this without blocking the UI?

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  • How to test my GAE site for performance

    - by Sergey Basharov
    I am building a GAE site that uses AJAX/JSON for almost all its tasks including building the UI elements, all interactions and client-server requests. What is a good way to test it for highloads so that I could have some statistics about how much resources 1000 average users per some period of time would take. I think I can create some Python functions for this purpose. What can you advise? Thanks.

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  • Ladder word-like game GUI problems

    - by sasquatch90
    Ok so I've written my own version of game which should look like this : http://img199.imageshack.us/img199/6859/lab9a.jpg but mine looks like that : http://img444.imageshack.us/img444/7671/98921674.jpg How can I fix this ? Is there a way to do the layout completely differently ? Here's the code : Main.java : import java.util.Scanner; import javax.swing.*; import java.awt.*; public class Main { public static void main(String[] args){ final JFrame f = new JFrame("Ladder Game"); Scanner sc = new Scanner(System.in); System.out.println("Creating game data..."); System.out.println("Height: "); while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); Grid[]game = new Grid[height]; for(int L = 0; L < height; L++){ Grid row = null; int i = L+1; String s; do { System.out.println("Length "+i+", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()]; Element single = null; String[] temp = null; String[] temp2 = new String[s.length()]; temp = s.split(""); for( int j = temp2.length; j>0; j--){ temp2[j-1] = temp[j]; } for (int k = 0 ; k < temp2.length ; k++) { if( k == 0 ){ single = new Element(temp2[k], 2); } else{ single = new Element(temp2[k], 1); } line[k] = single; } row = new Grid(line); game[L] = row; } //############################################ //THE GAME STARTS HERE //############################################ JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.X_AXIS)); panel.setBackground(Color.ORANGE); panel.setBorder(BorderFactory.createEmptyBorder(10, 10, 10, 10)); for(int i = 0; i < game.length; i++){ panel.add(game[i].create()); } f.setContentPane(panel); f.pack(); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); boolean end = false; boolean word = false; String tekst; while( !end ){ while( !word ){ tekst = JOptionPane.showInputDialog("Input word: "); for(int i = 0; i< game.length; i++){ if(game[i].equalLength(tekst)){ if(game[i].equalValue(tekst)){ word = true; for(int j = 0; j< game.length; j++){ game[i].repaint(); } } } } } word = false; for(int i = 0; i < game.length; i++){ if(game[i].solved()){ end = true; } else { end = false; } } } } } Grid.java import javax.swing.*; import java.awt.*; public class Grid extends JPanel{ private Element[]e; private Grid[]g; public Grid(){} public Grid( Element[]elements ){ e = new Element[elements.length]; for(int i=0; i< e.length; i++){ e[i] = elements[i]; } } public Grid(Grid[]grid){ g = new Grid[grid.length]; for(int i=0; i<g.length; i++){ g[i] = grid[i]; } Dimension d = new Dimension(600, 600); setMinimumSize(d); setPreferredSize(new Dimension(d)); setMaximumSize(d); } public JPanel create(){ JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.PAGE_AXIS)); panel.setBorder(BorderFactory.createEmptyBorder(2, 2, 2, 2)); for(int j = 0; j < e.length; j++){ panel.add(e[j].paint()); } return panel; } @Override public void repaint(){ } public boolean equalLength(String s){ int len = s.length(); boolean equal = false; for(int j = 0; j < e.length; j++){ if(e.length == len){ equal = true; } } return equal; } public boolean equalValue(String s){ int len = s.length(); boolean equal = false; String[] temp = null; String[] temp2 = new String[len]; temp = s.split(""); for( int j = len; j>0; j--){ temp2[j-1] = temp[j]; } for(int j = 0; j < e.length; j++){ if( e[j].letter().equals(temp2[j]) ){ equal = true; } else { equal = false; } } if(equal){ for(int i = 0; i < e.length; i++){ e[i].changeState(3); } } return equal; } public boolean solved(){ boolean solved = false; for(int j = 0; j < e.length; j++){ if(e[j].getState() == 3){ solved = true; } else { solved = false; } } return solved; } @Override public String toString(){ return ""; } } Element.java import javax.swing.*; import java.awt.*; public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){ } //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public JButton paint(){ JButton button = null; if( state == EMPTY ){ button = new JButton(""); button.setBackground(Color.WHITE); } else if ( state == FIRST_LETTER ){ button = new JButton(letter); button.setBackground(Color.red); } else { button = new JButton(letter); button.setBackground(Color.yellow); } button.setSize(20,20); return button; } public void changeState(int s){ state = s; } public String letter(){ return letter; } public int getState(){ return state; } @Override public String toString(){ return "["+letter+"]"; } }

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  • Exchange 2010 - Certificate error on internal Outlook 2013 connections

    - by Lorenz Meyer
    I have an Exchange 2010 and Outlook 2003. The exchange server has a wildcard SSL certificate installed *.domain.com, (for use with autodiscover.domain.com and mail.domain.com). The local fqdn of the Exchange server is exch.domain.local. With this configuration there is no problem. Now I started upgrading all Outlook 2003 to Outlook 2013, and I start to get consistently a certificate error in Outlook : The Name on the security certificate is invalid or does not match the name of the site I understand why I get that error: Outlook 2013 is connecting to exch.domain.local while the certificate is for *.domain.com. I was ready to buy a SAN (Subject Alternate Names) Certificate, that contains the three domains exch.domain.local, mail.domain.com, autodiscover.domain.com. But there is a hindrance: the certificate provider (in my case Godaddy) requires that the domain is validated as being our property. Now it is not possible for an internal domain that is not accessible from the internet. So this turns out not to be an option. Create self-signed SAN certificate with an Enterprise CA is an other option that is barely viable: There would be certificate error with every access to webmail, and I had to install the certificate on all Outlook clients. What is a recommended viable solution ? Is it possible to disable certificate checking in Outlook ? Or how could I change the Exchange server configuration so that the public domain name is used for all connections ? Or is there another solution I'm not thinking of ? Any advice is welcome.

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  • Killing Mysql processes staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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  • Adding a Menu Item for only one Perspective

    - by Ro.
    I'm trying to add a Menu Item to the Run Menu in Eclipse via a plugin. However, I only want this Item to appear when I'm in the "Report Design" perspective (this is for BIRT). Secondly, (if possible) I'd like the menu item to be only enabled if the extension of the open file is .rptdesign. I'm not having any luck using either of the visibility or visibleWhen elements in the plugin.xml Any hints appreciated, Ro

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  • How can I compare arrays in Perl?

    - by devtech
    I have two arrays, @a and @b. I want to do a compare among the elements of the two arrays. my @a = qw"abc def efg ghy klm ghn"; my @b = qw"def ghy jgk lom com klm"; If any element matches then set a flag. Is there any simple way to do this?

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