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  • T-SQL Hierarchy to duplicate Dependent Objects tree view in SQL Server 2005

    - by drewg
    Hi Id like to map the calling stack from one master stored procedure through its hundreds of siblings. i can see it in the dialog, but cannot copy or print it, but couldnt trap anythiing worthwhile in proflier. do you know what sproc fills that treeview? i must be a recursive CTE that reads syscomments or information_schema.routines, but its beyond my chops, though i can imagine it thanks in advance drew

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  • How to set up a simple table view in Cocoa

    - by happyCoding25
    Hello, I was wondering if anyone could give me an example or point me to some example code of how to use an NSTableView. I know how to use it in core data but I would like to do this just using plain cocoa code. All I need is a simple add and remove button. Also is it possible to have cocoa write the data to a text file or plist? Thanks for any help

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  • View list of all JavaScript variables in Google Chrome Console

    - by GRboss
    Hello everyone. In Firebug the DOM tab shows a list of all your public variables and objects. In Chrome's console you have to type the name of the public variable or object you want to explore. Is there a way - or at least a command - for Chrome's console to display a list all the public variables and objects? It will save a lot of typing. Thank you all Stefanos

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  • Animating and rotating an image in a Surface View

    - by jax
    I would like to animate movement on a SurfaceView . Ideally I would like to also be notified once the animation had finished. For example: I might have a car facing North. If I wanted to animate it so that it faces South for a duration of 500ms, how could I do that? I am using a SurfaceView so all animation must be handled manually, I don't think I can use XML or the android Animator classes. Also, I would like to know the best way to animate something continuously inside a SurfaceView (ie. a walk cycle)

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  • ASP.NET MVC: View does not get rendered with updated model value

    - by Newton
    I'm experiencing the a challenge in populating the child records. My previous code was like - <%= Html.TextBox("DyeOrder.Summary[" + i + "].Ratio", Model.DyeOrder.Summary[i].Ratio.ToString("#0.00"), ratioProperties) %> This code does not render the updated values after post back. To resolve this issue my work around was like - <%= "<input id='DyeOrder_Summary_" + i + "__Ratio' name='DyeOrder.Summary[" + i + "].Ratio' value='" + Model.DyeOrder.Summary[i].Ratio.ToString("#0.00") + "' " + ratioCss + " type='text' />"%> This is very clumsy to me. Is there any better ideas...

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  • How to view existing data in Core Data?

    - by mshsayem
    Well, may be this question is silly, but I couldn't find a way (except programmatically). I built a project (for iPhone OS 3.0) which uses Core Data. The xcdatamodel file shows the schema description, but I want to see the data in tabular form (like the management studio for mssql server or phpmyadmin for mysql). Is there any way (except coding)? What is that? Also, which file (in disk/device) those data are stored into? [ I built the tutorial (from apple) on Core Data, named Locations. They used this line somewhere in the code: NSURL *storeUrl = [NSURL fileURLWithPath: [[self applicationDocumentsDirectory] stringByAppendingPathComponent: @"Locations.sqlite"]]; But, I did not see any "xxxxx.sqlite" file in project location (nor in the disk).]

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  • Coupling an MFC CListCtrl and CTreeCtrl to get a view of the whole tree, not just one node at a time

    - by omatai
    Consider Windows Explorer (or regedit or similar). To the left side, there is a tree view, and to the right, a list view. In all cases I know of, the contents of the right view reflect the attributes of the selected node from the left pane. This is all well and good... but just not what I want. The nodes of the tree I want to display have a very few attributes (2-3) associated with each node - a reasonable amount to display horizontally as a row in a table. Rather than waste all that list view space on a single node with very few properties, I would like to have my list view display a table of the whole tree's properties (as the part of the tree currently expanded). So the nth line in the left view (tree) will correspond directly to the nth line in the right view (list/table), and I will get a decent overview of the properties of my tree. Does anyone know of code that does this? I am guessing that slaving a CListCtrl to a CTreeCtrl would be the way to go, and somehow overriding the vertical scrolling functions so that they are locked together. I'm just not sure that it is possible to lock the scrolls together like this... among other things! All advice gratefully welcomed :-)

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  • List view new line for new values

    - by Luke
    The following code produces a ListView with the names of the customers: private void displayDeliveries() { lstDeliveryDetails.Items.Clear(); foreach (Delivery d in mainForm.myDeliveries) { lstDeliveryDetails.Items.Add(d.DeliveryName); } } If I add, (d.DeliveryAddress), how can I get it to line up alongside the correct name?

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  • ASP.NET MVC Using Multiple user controls on a single .aspx(view)

    - by Pinu
    I am getting this following error , when i am tring to having two user controls in one page. The model item passed into the dictionary is of type 'System.Linq.EnumerableQuery1[Data.EventLog]' but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable1[Data.Notes]'. <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> Test </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <h2>Test</h2> <% Html.RenderPartial("~/Views/Shared/UserControl/Tracking.ascx"); %> <% Html.RenderPartial("~/Views/Shared/UserControl/Notes.ascx"); %> </asp:Content>

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  • MVC 4 iframe embedded in desktop page showing mobile view

    - by Reto Laemmler
    I use Index.cshtml and Index.mobile.cshtml. My Index.cshtml is a mobile app landing page containing an iframe to live demo the mobile web app. Index.mobile.cshtml is the mobile web app itself. The problem is, the iframe keeps loading the desktop version itself. As far as I know, I cannot configure the user agent of the iframe to a mobile type. It should be solvable with some routing but I couldn't figure out how!?

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  • C#: Immutable view of a list's objects?

    - by Rosarch
    I have a list, and I want to provide read-only access to a collection containing its contents. How can I do this? Something like: public ICollection<Foo> ImmutableViewOfInventory() { IList<Foo> inventory = new List<Foo>(); inventory.add(new Foo()); return inventory.ImmutableView(); } Additionally, an immutable IEnumerable would also be fine.

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  • RotationAsync with each row in List view

    - by Labeeb P
    Hi, From this answer in stack overflow and the sample project referred there, i got the Idea of RotationAsync, where a progress bar work fine with device rotation. But my problem is, i have a listview with each row there is progress bar. And is there any way to retain the progress while rotation for reach row. Me creating onclicklistener object for the button click listener in getview function of my adapter class. Where its onClick function call the AsyncTask class Since each getview (row) is calling different instant of my AsyncTask, i cannot make it static of single ton class. Any Idea on this. Thanks.

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  • C#:multicolumn sorting of datagrid view

    - by Bi
    I have a datagridview in a windows form with 3 columns: Serial number, Name and Date-Time. The Name column will always have either of the two values: "name1" or "name2". I need to sort these columns such that the grid displays all the rows with name values in a specific order (first display all the "name1" rows and then all the "name2" rows). Within the "name1" rows, I want the rows to be sorted by the Date-Time. Please note programmatically, all the 3 columns are strings. For example, if I have the rows: 01 |Name1 | 2010-05-05 10:00 PM 02 |Name2 | 2010-05-02 08:00 AM 03 |Name2 | 2010-05-01 08:00 AM 04 |Name1 | 2010-05-01 11:00 AM 05 |Name1 | 2010-05-04 07:00 AM needs to be sorted as 04 |Name1 | 2010-05-01 11:00 AM 05 |Name1 | 2010-05-04 07:00 AM 01 |Name1 | 2010-05-05 10:00 PM 03 |Name2 | 2010-05-01 08:00 AM 02 |Name2 | 2010-05-02 08:00 AM I am not sure how to go about using the below: myGrid.Sort(.....,ListSortDirection.Ascending)

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  • passing parameter to view in IOS after a button is pressed

    - by ghostrider
    I am new to IOS programming. So far I have been programming in android. So in android when pressing a button code for passing an argument would be like that: Intent i = new Intent(MainScreen.this,OtherScreen.class); Bundle b = new Bundle(); b.putString("data_1",data); i.putExtras(b); startActivity(i); and on the activity that opens, i would write something like this: Bundle b = getIntent().getExtras(); ski_center=b.getString("data_1"); what methods should I need to change in MainScreen and in OtherScreen in IOS to achieve the above. Basically I will have 3 buttons lets say in my MainScreen and each of it will open the Otherview but each time a different parameter will be passed. Foe example for each button i have code like these in MainScreen.m @synthesize fl; -(IBAction) ifl:(id) sender { } So I need your help in where to place the "missing" code, too.

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  • How do I bind to a custom view in Cocoa using Xcode 4?

    - by Newt
    I'm a beginner when it comes to writing Mac apps and working with Cocoa, so please forgive my ignorance. I'm looking to create a custom view, that exposes some properties, which I can then bind to an NSObjectController. Since it's a custom view, the Bindings Inspector obviously doesn't list any of the properties I've added to the view that I can then bind to using Interface Builder. After turning to the Stackoverflow/Google for help, I've stumbled across a couple of possible solutions, but neither seem to be quite right for my situation. The first suggested creating an IBPlugin, which would then mean my bindings would be available in the Bindings Inspector. I could then bind the view to the controller using IB. Apparently IBPlugins aren't supported in Xcode 4, so that one's out the window. I'm also assuming (maybe wrongly) that IBPlugins are no longer supported because there's a better way of doing such things these days? The second option was to bind the controller to the view programmatically. I'm a bit confused as to exactly how I would achieve this. Would it require subclassing NSObjectController so I can add the calls to bind to the view? Would I need to add anything to the view to support this? Some examples I've seen say you'd need to override the bind method, and others say you don't. Also, I've noticed that some example custom views call [self exposeBinding:@"bindingName"] in the initializer. From what I gather from various sources, this is something that's related to IBPlugins and isn't something I need to do if I'm not using them. Is that correct? I've found a post on Stackoverflow here which seems to discuss something very similar to my problem, but there wasn't any clear winner as to the best answer. The last comment by noa on 12th Sept seems interesting, although they mention you should be calling exposeBinding:. Is this comment along the right track? Is the call to exposeBinding really necessary? Apologies for any dumb questions. Any help greatly appreciated.

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  • RelativeLayout - positioning a View under a ViewGroup

    - by Richard
    I have the following structure defined in an xml layout file. <RelativeLayout android:id="@+id/mainLayout" xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="wrap_content" android:layout_height="wrap_content"> <FrameLayout android:id="@+id/frame" android:layout_centerInParent="true" android:layout_width="wrap_content" android:layout_height="wrap_content" ></FrameLayout> <Button android:id="@+id/button" android:layout_below="@id/frame" android:layout_width="wrap_content" android:layout_height="wrap_content" /> </RelativeLayout> The FrameLayout is positioned correctly in the center of its parent. But the Button isn't getting positioned under it. Instead it's displaying in the top left corner. Am I doing something incorrectly or is this a bug with RelativeLayout?

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  • Edit and create nodes in a view?

    - by tputkonen
    We are storing people's class attendance information to Drupal. We would like to show this in a grid/chart, where the first column of each row shows person's name, and rest of the columns (ca. 20) either a checkbox or "X" if the user attended a class, or otherwise an non-checked box or empty column: (dates here) Jack X XXX X X Jill XX XXX XX It should also be possible to edit the attendance information on the grid. Each attendance information is a node of its own. This functionality can probably mostly be achieved using views and editablefields, but there is one problem: if a person has not attended a specific class he/she will not have at all an attendace node for that day. What would be the easiest way to create an attendace node in those cases, so that it would be possible for the end user to edit the grid by just clicking on the checkbox or typing an 'X'?

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  • Grid view update event form javascript

    - by pranay
    I have grid control select <%--Select--% </ItemTemplate> </asp:TemplateField> </columns> <pagersettings mode="NumericFirstLast" position="Top" pagebuttoncount="5" /> <pagerstyle backcolor="Pink" /> </cc:AppEngineGridView> my code on row create protected override void OnRowCreated(GridViewRowEventArgs e) { try { if (e.Row.RowType == DataControlRowType.DataRow) { e.Row.ID = this.ID + "_" + e.Row.RowIndex; e.Row.Attributes.Add("onmouseover", "this.style.cursor='pointer';this.style.font.weight='bolder';"); e.Row.Attributes.Add("onclick", "DoNav('" + ((LinkButton)e.Row.FindControl("lbtn1")).ClientID + "');"); } } protected void grduser_RowUpdating(object sender, GridViewUpdateEventArgs e) { grdview_RowClickCommand(sender, e); } Javascript : function DoNav(id) { $("#"+id).click(); } Now my question is when i click on the row it do post back but it didnt call rowupdate event How can do this i.e using javascript to call row update command of the grid.

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  • Pass form data from block to a page view in Drupal

    - by abdesignuk
    I am using the location module and views module for a postcode search, which works fine in a page display using views. However I want the user to be able to enter their postcode into a block on the homepage and clicking submit my module sends them to the page created in views and the postcode is set as a session S_SESSION['postcode'] before sending to this page, next I want the location page to load but using the session to display the locations automatically. Any ideas I am using hook_form_submit() and inside that declaring the $form_state as a session and then using $form_state['redirect'] to sent to the views page path.

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