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  • Cant connect to asterisk internal database [on hold]

    - by Bilbo
    Im trying to get a PHP script to connect to Asterisks internal mysql database. I tried the to use the standard method for example $con = mysqli_connect("192.168.1.126","root","mysql","asterisk"); However when I log into the asterisk server to access the mysql database all i need it to type "mysql" and im logged in. Im wondering is it possible for my php script to connect to asterisk internal database. The following error is shown: Warning: mysqli_connect(): (HY000/2003): Can't connect to MySQL server on '192.168.1.126' (111) in /var/www/html/project/sipSubScript.php on line 6 Failed to connect to MySQL: Can't connect to MySQL server on '192.168.1.126' (111)

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  • Alfresco Community Edition Consultants

    - by Talkincat
    I am in the process of putting together an document management system based on Alfresco Community 3.2r2. Because Alfresco will not allow its partners to work with the Community edition, I have found it devilishly tricky to find consultants that specialize in Alfresco to help me with this project. Can anyone point me in the direction of someone that can help me get this system up an running? I will mostly need help with integrating Alfresco with Active Directory (LDAP passthrough, user/group sync and SSO) and performance tuning the system. Any help is greatly appreciated.

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  • Ubuntu server failing daily

    - by deanvz
    Symptoms: Server becomes unresponsive - Increase in load, all services stop Loss of connectivity - Ping/SSH Flush MySQL hosts after reboot - As MySQL refuses new connections Intermittent Apache crashes Generally happens early morning hours - 2 days of the week are however excluded Changes made: Updated the OS - to Ubuntu 10.04.4 LTS Not sure if the MySQL server was also updated in the process Current MySQL version - mysql Ver 14.14 Distrib 5.1.63, for debian-linux-gnu (x86_64) using readline 6.1 Updated Plesk from 10.4.4 Update #47 to 11.0.9 Update #23 Rebooted on almost daily basis All crons stopped for the times corresponding to the server crashes Created a MySQL log to monitor the lock times on queries Possible causes: Failing hardware Incorrect software configuration (MySQL, Apache etc) Responsibilities: Small webserver Runs our billing system - WHMCS Responsible for CRONs Bulk-email solution - No delivery times coincide with server crashes Proposed solutions: Move machine over to VM Format and restore the Plesk server backup and take it from there? Side notes: Seems to be a general Apache failure across all our linux servers - Intermittent problem Are we doing something fundamentally wrong in the Apache config? (I understand that this is a secondary question, just making sure that it isnt possibly holding any relevance)

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  • Failed depencies: libmysqlclient.so.16 is needed

    - by user54625
    I'm trying to install something on my server that requires mysqlclient, but looking at my RPM package list I have it ("MySQL-client-5.0.91-0.glibc23"). Doing a locate on libmysqlclient gives me this: [[email protected]] ~ >> locate libmysqlclient /usr/lib64/libmysqlclient.so /usr/lib64/libmysqlclient.so.15 /usr/lib64/libmysqlclient.so.15.0.0 /usr/lib64/libmysqlclient_r.so /usr/lib64/libmysqlclient_r.so.15 /usr/lib64/libmysqlclient_r.so.15.0.0 /usr/lib64/mysql/libmysqlclient.a /usr/lib64/mysql/libmysqlclient.la /usr/lib64/mysql/libmysqlclient.so /usr/lib64/mysql/libmysqlclient_r.a /usr/lib64/mysql/libmysqlclient_r.la /usr/lib64/mysql/libmysqlclient_r.so /usr/local/cpanel/lib64/libmysqlclient.so.14 For some reason it looks like I'm missing libmysqlclient.so.16. Does anyone know why this could be? How do I go about getting it? I'm currently running CentOS 5. Thanks a lot.

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  • Web-based (intranet / non-hosted) timesheet / project tracking tools

    - by warren
    I realize some similar questions have been asked along these lines before, but from reading-through them today, it appears they don't match my use case. I am looking for a web-based, non-hosted time and project tracking tool. I've downloaded Collabtive so far, but am looking for other suggestions, too. My list of requirements: runs on standard LAMP stack non-hosted (ie, there is an option to download and run it on a local server) not a desktop/single-user application easy-to-use - my audience is a mix of technical and non-technical folks easy to maintain - when time for upgrading comes, I'd really like to not have to rebuild the app (a la ./configure ; make ; make install) needs to support multiple users free-form project additions: we don't have a central project management authority (users should be able to add whatever they're working on, not merely from a drop-down) Does anyone here have experience with such tools? It doesn't have to be free.. but free is always nice :)

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  • Web-based (intranet / non-hosted) timesheet / project tracking tools

    - by warren
    I realize some similar questions have been asked along these lines before, but from reading-through them today, it appears they don't match my use case. I am looking for a web-based, non-hosted time and project tracking tool. I've downloaded Collabtive and Achievo so far, but am looking for other suggestions, too. My list of requirements: runs on standard LAMP stack non-hosted (ie, there is an option to download and run it on a local server) not a desktop/single-user application easy-to-use - my audience is a mix of technical and non-technical folks easy to maintain - when time for upgrading comes, I'd really like to not have to rebuild the app (a la ./configure ; make ; make install) needs to support multiple users free-form project additions: we don't have a central project management authority (users should be able to add whatever they're working on, not merely from a drop-down) Does anyone here have experience with such tools? It doesn't have to be free.. but free is always nice :)

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  • Looking for a good free or cheap task tracking system

    - by JWood
    I've finally decided that pen and paper/whiteboards are not up to the job as my workload increases so I'm looking for a good task tracking system. I need something that can track tasks in categories (projects) and allow me to assign priority to each task. I've tried iTeamWork which requires projects to have an end time which is no good for me as at least one of my projects is ongoing. I also tried Teamly which was required tasks to be set to a specific day which is no good as tasks sometimes take more than a day and I would like them organised by priority rather than specific days. Preferably looking for something hosted but I'm happy to install on our servers if it supports PHP/MySQL. Oh, and an iPhone client would be the icing on the cake! Can anyone recommend anything?

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  • What process is resurrecting mysqld?

    - by ripper234
    I'm following this guide to reset my mysql root password (I'm on ubuntu). When I kill the mysqld process, it immediately gets resurrected. The parent process ID is 1. How can I find what keeps resurrecting mysqld? $ ps -ef | grep mysql mysql 30136 1 0 07:16 ? 00:00:00 /usr/sbin/mysqld root 30295 30274 0 07:18 pts/0 00:00:00 grep --color=auto mysql $ kill -9 30136 $ ps -ef | grep mysql mysql 30302 1 2 07:18 ? 00:00:00 /usr/sbin/mysqld root 30404 30274 0 07:18 pts/0 00:00:00 grep --color=auto mysql $

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  • Migrating Identity Providers - specifying a new users password hash.

    - by Stephen Denne
    We'd like to switch Identity Provider (and Web Access Manager), and also the user directory we use, but would like to do so without users needing to change their password. We currently have the SSHA of the passwords. I'm expecting to write code to perform the migration. I don't mind how complex the code has to be, rather my concern is whether such a migration is possible at all. MS Active Directory would be our preferred user store, but I believe that it can not have new users set up in it with a particular password hash. Is that correct? What user directory stores can be populated with users already set up with a SSHA password? What Identity Provider and Access Management products work with those stores?

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  • What is this PHP process? It is crippling my server

    - by user1019588
    This process has been using 65% of my site CPU and has lasted for about 10 minutes now (aren't processes only supposed to go for a couple seconds?) It is obviously something with mysql. This makes sense because I have a lot of queries going, but something still seems a bit odd... This could have something to do with my bad PDO connection that I mentioned in the previous question. Perhaps I am opening too many connections or something like that? Here is the stats on it: Owner: mysql Priority: 0 CPU %: 61.1 Memory %: 0.4 Command:/usr/sbin/mysqld --basedir=/usr --datadir=/var/lib/mysql --plugin-dir=/usr/lib64/mysql/plugin --user=mysql --log-error=/var/lib/mysql/cvps54834319.myhost.com.err --pid-file=/var/lib/mysql/cvps54834319.myhost.com.pid Thanks for any help on this. I have over 10GHZ on my server so this is very concerning to me.

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  • Turn "log slow queries" ON.

    - by CodedK
    Hello, I'm trying to log mysql slow queries, but I can't turn it on. I will explain all my steps: Open and Edit my.cnf and add the following lines: long_query_time = 5 slow_query_log_file = /myfolder/slowq.log log_slow_queries = 1 =(I have MySQL 5.0.7) Give mysql user permitions to write on the file: chown -R mysql:mysql /var/lib/mysql Create the file: touch /myfolder/slowq.log Chmod for this file to 777. service mysqld restart From MySQL Admin Panel I can see that the "log_slow_queries" var is OFF! Also no logs are created. Thanks in advance! Best Regards, Panos.

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  • SQL SERVER – Auto Recovery File Settings in SSMS – SQL in Sixty Seconds #034 – Video

    - by pinaldave
    Every developer once in a while facing an unfortunate situation where they have not yet saved the work and their SQL Server Management Studio crashes. Well, you can minimize the loss by optimizing auto recovery settings. In this video we can see how to set the auto recovery settings. Go to SSMS >> Tools >> Options >> Environment >> AutoRecover There are two different settings: 1) Save AutoRecover Information Every Minutes This option will save the SQL Query file at certain interval. Set this option to minimum value possible to avoid loss. If you have set this value to 5, in the worst possible case, you can loose last 5 minutes of the work. 2) Keep AutoRecover Information for Days This option will preserve the AutoRecovery information for specified days. Though, I suggest in case of accident open SQL Server Management Studio right away and recover your file. Do not procrastinate this important task for future dates. Related Tips in SQL in Sixty Seconds: Manage Help Settings – CTRL + ALT + F1 SSMS 2012 Reset Keyboard Shortcuts to Default A Cool Trick – Restoring the Default SQL Server Management Studio – SSMS Color Coding SQL Server Management Studio Status Bar – SQL in Sixty Seconds #023 – Video Clear Drop Down List of Recent Connection From SQL Server Management Studio SELECT TOP Shortcut in SQL Server Management Studio (SSMS) What would you like to see in the next SQL in Sixty Seconds video? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology, Video Tagged: Excel

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  • Identity R2 Event Orlando

    - by Naresh Persaud
    Take the Next Big Step in Identity Management Evolution We call the latest release of Oracle Identity Management 11gthe evolved platform. And for good reason. It simplifies the user experience, enhances security, and allows businesses to expand the reach of identity management to the cloud and mobile environments like never before. Join this important event to discuss the recent launch of Oracle Identity Management 11g. You'll learn more about the evolution of this exceptional business solution and get the unique opportunity to network with existing Oracle customers and speak directly with Oracle product experts. The agenda includes: Overview of capabilities Product demonstrations Customer and partner presentations Discussion with early adopters Register now for the event or call 1.800.820.5592 ext. 11087. Register Now Join us for this event. Thursday, December 6, 2012The Capital GrillePointe Orlando, 9101International DriveOrlando, FL 32819Get Directions Agenda 9:00 a.m. Registration & Continental Breakfast 9:30 a.m. Welcome RemarksDave Profozich, Group Vice President, Oracle 9:45 a.m. Keynote:Oracle Identity Management 11g R2Scott Bonnell, Sr. Director Product Management, Oracle 10:30 a.m. Coffee Break 10:45 a.m. Oracle 11gR2 Overview/Demo/Technical walkthroughMark Wilcox, Sr. Manager Product Management, Oracle 11:45 a.m. Closing RemarksDave Profozich, Group Vice President, Oracle 12:00 noon Networking Lunch Register now for this exclusive event or call 1.800.820.5592 ext. 11087.If you are an employee or official of a government organization, please click here for important ethics information regarding this event. Copyright © 2012, Oracle and/or its affiliates. All rights reserved. Contact Us | Legal Notices and Terms of Use | Privacy Statement SEV100122190

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  • mysql match against hebrew

    - by Devenv
    Hey, Trying to solve this for a very long time now... SELECT MATCH(name) AGAINST('??????') (hebrew) doesn't work, but SELECT MATCH(name) AGAINST('abraxas') SELECT MATCH(name) AGAINST('????????') (english, russian) work perfectly. I know it's something with character-set, but I tried all kind of settings and it didn't work. For now it's latin-1. LIKE works I'm pretty much sure that any weird language like arabic etc won't work...

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  • Run MySQL INSERT Query multiple times (insert values into multiple tables)

    - by Derek
    Hi, basically, I have 3 tables; users and projects (which is a many-to-many relationship), then I have 'usersprojects' to allow the one-to-many formation. When a user adds a project, I need the project information stored and then the 'userid' and 'projectid' stored in the usersprojects table. It sounds like its really straight forward but I'm having problems with the syntax I think!? As it stands, I have this as my INSERT queries (values going into 2 different tables): $project_id = $_POST['project_id']; $projectname = $_POST['projectname']; $projectdeadline = $_POST['projectdeadline']; $projectdetails = $_POST['projectdetails']; $user_id = $_POST['user_id']; $sql = "INSERT INTO projects (projectid, projectname, projectdeadline, projectdetails) VALUES ('{$projectid}','{$projectname}','{$projectdeadline}','{$projectdetails}')"; $sql = "INSERT INTO usersprojects (userid, projectid) VALUES ('{$userid}','{$projectid}')"; None of the information is being stored in the projects table, but the user ID is being stored in the usersprojects table (but not project ID!?)... I did have it working where the project information is stored correctly with a project ID, before I added this bit: $sql = "INSERT INTO usersprojects (userid, projectid) VALUES ('{$userid}','{$projectid}')"; But before the code above was put in, obviously no info is being stored in usersprojects table. The source code that links the script: <form id="addform" name="addform" method="POST" action="addproject-run.php"> <label>Project Name:</label> <input name="projectname" size="40" id="projectname" value="<?php if (isset($_POST['projectname'])); ?>"/><br /> <input name="user_id" input type="hidden" size="40" id="user_id" value="<?php echo $_SESSION['SESS_USERID']; ?>"/> <label>Project Deadline:</label> <input name="projectdeadline" size="40" id="projectdeadline" value="In the format of 'YYYY-MM-DD'<?php if (isset($_POST['projectdeadline'])); ?>"/><br /> <label>Project Details:</label> <textarea rows="5" cols="20" name="projectdetails" id="projectdetails"><?php if (isset($_POST['projectdetails'])); ?></textarea> <br /> <br /> <input value="Create Project" class="addbtn" type="submit" /> </form></div> So I think I'm right in saying I have the syntax for the SQL statement to be run an insert query of values into 2 tables? Any help is much appreciated! Thanks.

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  • mysql update where some field is max

    - by Syom
    The table videos has the following fields: id | average | name How can i write the query, to update the name of video, which have the max average, or the second by size average!!! i can do that with two queries, by selecting the max(average) from the table, and then update the name, where ite average equal to max or to second value, but i want to do that in one query. i think the query must look like this UPDATE videos SET name = 'something' WHERE average = MAX(average) Any suggestions?

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  • MySQL Error 1452 - Cannot add or update a child row: a foreign key constraint fails

    - by dscher
    I've looked at other people's questions on this topic but can't seem to find where my error is coming from. Any help would be greatly appreciated. I'm including as much as I can think of that might help find the problem: CREATE TABLE stocks ( id INT AUTO_INCREMENT NOT NULL, user_id INT(11) UNSIGNED NOT NULL, ticker VARCHAR(20) NOT NULL, name VARCHAR(20), rating INT(11), position ENUM("strong buy", "buy", "sell", "strong sell", "neutral"), next_look DATE, privacy ENUM("public", "private"), PRIMARY KEY(id), FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8; CREATE TABLE IF NOT EXISTS `stocks_tags` ( `stock_id` INT NOT NULL, `tag_id` INT NOT NULL, PRIMARY KEY (`stock_id`,`tag_id`), KEY `fk_stock_tag` (`tag_id`), KEY `fk_tag_stock` (`stock_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; ALTER TABLE `stocks_tags` ADD CONSTRAINT `fk_stock_tag` FOREIGN KEY (`tag_id`) REFERENCES `tags` (`id`) ON DELETE CASCADE ON UPDATE CASCADE, ADD CONSTRAINT `fk_tag_stock` FOREIGN KEY (`stock_id`) REFERENCES `stocks` (`id`) ON DELETE CASCADE ON UPDATE CASCADE; CREATE TABLE tags( id INT AUTO_INCREMENT NOT NULL PRIMARY KEY, tags VARCHAR(30), UNIQUE(tags) ) ENGINE=INNODB DEFAULT CHARSET=utf8; And the error I'm getting: Database_Exception [ 1452 ]: Cannot add or update a child row: a foreign key constraint fails (`ddmachine`.`stocks_tags`, CONSTRAINT `fk_stock_tag` FOREIGN KEY (`tag_id`) REFERENCES `tags` (`id`) ON DELETE CASCADE ON UPDATE CASCADE) [ INSERT INTO `stocks_tags` (`stock_id`, `tag_id`) VALUES (19, 'cash') ] I did see that someone else had a similar problem based on their enum columns but don't think that's it.

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  • Can not delete row from MySQL

    - by Drew
    Howdy all, I've got a table, which won't delete a row. Specifically, when I try to delete any row with a GEO_SHAPE_ID over 150000000 it simply does not disappear from the DB. I have tried: SQLyog to erase it. DELETE FROM TABLE WHERE GEO_SHAPE_ID = 150000042 (0 rows affected). UNLOCK TABLES then 2. As far as I am aware, bigint is a valid candidate for auto_increment. Anyone know what could be up? You gotta help us, Doc. We’ve tried nothin’ and we’re all out of ideas! DJS. PS. Here is the table construct and some sample data just for giggles. CREATE TABLE `GEO_SHAPE` ( `GEO_SHAPE_ID` bigint(11) NOT NULL auto_increment, `RADIUS` float default '0', `LATITUDE` float default '0', `LONGITUDE` float default '0', `SHAPE_TYPE` enum('Custom','Region') default NULL, `PARENT_ID` int(11) default NULL, `SHAPE_POLYGON` polygon default NULL, `SHAPE_TITLE` varchar(45) default NULL, `SHAPE_ABBREVIATION` varchar(45) default NULL, PRIMARY KEY (`GEO_SHAPE_ID`) ) ENGINE=MyISAM AUTO_INCREMENT=150000056 DEFAULT CHARSET=latin1 CHECKSUM=1 DELAY_KEY_WRITE=1 ROW_FORMAT=DYNAMIC; SET FOREIGN_KEY_CHECKS = 0; LOCK TABLES `GEO_SHAPE` WRITE; INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (57, NULL, NULL, NULL, 'Region', 10, NULL, 'Washington', 'WA'); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (58, NULL, NULL, NULL, 'Region', 10, NULL, 'West Virginia', 'WV'); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (59, NULL, NULL, NULL, 'Region', 10, NULL, 'Wisconsin', 'WI'); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000042, 10, -33.8833, 151.217, 'Custom', NULL, NULL, 'Sydney%2C%20New%20South%20Wales%20%2810km%20r', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000043, 10, -33.8833, 151.167, 'Custom', NULL, NULL, 'Annandale%2C%20New%20South%20Wales%20%2810km%', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000048, 10, -27.5, 153.017, 'Custom', NULL, NULL, 'Brisbane%2C%20Queensland%20%2810km%20radius%2', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000045, 10, 43.1002, -75.2956, 'Custom', NULL, NULL, 'New%20York%20Mills%2C%20New%20York%20%2810km%', NULL); INSERT INTO `GEO_SHAPE` (`GEO_SHAPE_ID`, `RADIUS`, `LATITUDE`, `LONGITUDE`, `SHAPE_TYPE`, `PARENT_ID`, `SHAPE_POLYGON`, `SHAPE_TITLE`, `SHAPE_ABBREVIATION`) VALUES (150000046, 10, 40.1117, -78.9258, 'Custom', NULL, NULL, 'Region1', NULL); UNLOCK TABLES; SET FOREIGN_KEY_CHECKS = 1;

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  • Select From MySQL PHP

    - by Liju
    Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

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  • mysql query to dynamically convert row data to columns

    - by Anirudh Goel
    I am working on a pivot table query. The schema is as follows Sno, Name, District The same name may appear in many districts eg take the sample data for example 1 Mike CA 2 Mike CA 3 Proctor JB 4 Luke MN 5 Luke MN 6 Mike CA 7 Mike LP 8 Proctor MN 9 Proctor JB 10 Proctor MN 11 Luke MN As you see i have a set of 4 distinct districts (CA, JB, MN, LP). Now i wanted to get the pivot table generated for it by mapping the name against districts Name CA JB MN LP Mike 3 0 0 1 Proctor 0 2 2 0 Luke 0 0 3 0 i wrote the following query for this select name,sum(if(District="CA",1,0)) as "CA",sum(if(District="JB",1,0)) as "JB",sum(if(District="MN",1,0)) as "MN",sum(if(District="LP",1,0)) as "LP" from district_details group by name However there is a possibility that the districts may increase, in that case i will have to manually edit the query again and add the new district to it. I want to know if there is a query which can dynamically take the names of distinct districts and run the above query. I know i can do it with a procedure and generating the script on the fly, is there any other method too? I ask so because the output of the query "select distinct(districts) from district_details" will return me a single column having district name on each row, which i will like to be transposed to the column.

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  • index help for a MySQL query using greater-than operator and ORDER BY

    - by Jaymon
    I have a table with at least a couple million rows and a schema of all integers that looks roughly like this: start stop first_user_id second_user_id The rows get pulled using the following queries: SELECT * FROM tbl_name WHERE stop >= M AND first_user_id=N AND second_user_id=N ORDER BY start ASC SELECT * FROM tbl_name WHERE stop >= M AND first_user_id=N ORDER BY start ASC I cannot figure out the best indexes to speed up these queries. The problem seems to be the ORDER BY because when I take that out the queries are fast. I've tried all different types of indexes using the standard index format: ALTER TABLE tbl_name ADD INDEX index_name (index_col_1,index_col_2,...) And none of them seem to speed up the queries. Does anyone have any idea what index would work? Also, should I be trying a different type of index? I can't guarantee the uniqueness of each row so I've avoided UNIQUE indexes. Any guidance/help would be appreciated. Thanks!

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  • mySQL auto increment problem: Duplicate entry '4294967295' for key 1

    - by Josh
    I have a table of emails. The last record in there for an auto increment id is 3780, which is a legit record. Any new record I now insert is being inserted right there. However, in my logs I have the occasional: Query FAIL: INSERT INTO mail.messages (timestamp_queue) VALUES (:time); Array ( [0] => 23000 [1] => 1062 [2] => Duplicate entry '4294967295' for key 1 ) Somehow, the autoincrement jumped up to the INT max of 4294967295 Why on god's green earth would this get jumped up so high? I have no inserts with an id field. The show status for that table, Auto_increment table now reads: 4294967296 How could something like this occur? I realize the id field should perhaps be a big int, but the worry I have is that somehow this thing jumps back up. Josh

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  • Read a text file and transfer contents to mysql database

    - by Jack Brown
    I need a php script to read a .txt file. The content of the text file are like this: data.txt 145|Joe Blogs|17/03/1954 986|Jim Smith|12/01/1976 234|Paul Jones|19/07/1923 098|James Smith|12/09/1998 234|Carl Jones|01/01/1925 These would then get stored into a database like this DataID |Name |DOB 234 |Carl Jones|01/01/1925 I would be so grateful if someone could give me script to achieve this.

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  • MySQL Database Query Problem

    - by moustafa
    I need your help!!!. I need to query a table in my database that has record of goods sold. I want the query to detect a particular product and also calculate the quantity sold. The product are 300 now, but it would increase in the future. Below is a sample of my DB Table #---------------------------- # Table structure for litorder #---------------------------- CREATE TABLE `litorder` ( `id` int(10) NOT NULL auto_increment, `name` varchar(50) NOT NULL default '', `address` varchar(50) NOT NULL default '', `xdate` date NOT NULL default '0000-00-00', `ref` varchar(20) NOT NULL default '', `code1` varchar(50) NOT NULL default '', `code2` varchar(50) NOT NULL default '', `code3` varchar(50) NOT NULL default '', `code4` varchar(50) NOT NULL default '', `code5` varchar(50) NOT NULL default '', `code6` varchar(50) NOT NULL default '', `code7` varchar(50) NOT NULL default '', `code8` varchar(50) NOT NULL default '', `code9` varchar(50) NOT NULL default '', `code10` varchar(50) NOT NULL default '', `code11` varchar(50) character set latin1 collate latin1_bin NOT NULL default '', `code12` varchar(50) NOT NULL default '', `code13` varchar(50) NOT NULL default '', `code14` varchar(50) NOT NULL default '', `code15` varchar(50) NOT NULL default '', `product1` varchar(100) NOT NULL default '0', `product2` varchar(100) NOT NULL default '0', `product3` varchar(100) NOT NULL default '0', `product4` varchar(100) NOT NULL default '0', `product5` varchar(100) NOT NULL default '0', `product6` varchar(100) NOT NULL default '0', `product7` varchar(100) NOT NULL default '0', `product8` varchar(100) NOT NULL default '0', `product9` varchar(100) NOT NULL default '0', `product10` varchar(100) NOT NULL default '0', `product11` varchar(100) NOT NULL default '0', `product12` varchar(100) NOT NULL default '0', `product13` varchar(100) NOT NULL default '0', `product14` varchar(100) NOT NULL default '0', `product15` varchar(100) NOT NULL default '0', `price1` int(10) NOT NULL default '0', `price2` int(10) NOT NULL default '0', `price3` int(10) NOT NULL default '0', `price4` int(10) NOT NULL default '0', `price5` int(10) NOT NULL default '0', `price6` int(10) NOT NULL default '0', `price7` int(10) NOT NULL default '0', `price8` int(10) NOT NULL default '0', `price9` int(10) NOT NULL default '0', `price10` int(10) NOT NULL default '0', `price11` int(10) NOT NULL default '0', `price12` int(10) NOT NULL default '0', `price13` int(10) NOT NULL default '0', `price14` int(10) NOT NULL default '0', `price15` int(10) NOT NULL default '0', `quantity1` int(10) NOT NULL default '0', `quantity2` int(10) NOT NULL default '0', `quantity3` int(10) NOT NULL default '0', `quantity4` int(10) NOT NULL default '0', `quantity5` int(10) NOT NULL default '0', `quantity6` int(10) NOT NULL default '0', `quantity7` int(10) NOT NULL default '0', `quantity8` int(10) NOT NULL default '0', `quantity9` int(10) NOT NULL default '0', `quantity10` int(10) NOT NULL default '0', `quantity11` int(10) NOT NULL default '0', `quantity12` int(10) NOT NULL default '0', `quantity13` int(10) NOT NULL default '0', `quantity14` int(10) NOT NULL default '0', `quantity15` int(10) NOT NULL default '0', `amount1` int(10) NOT NULL default '0', `amount2` int(10) NOT NULL default '0', `amount3` int(10) NOT NULL default '0', `amount4` int(10) NOT NULL default '0', `amount5` int(10) NOT NULL default '0', `amount6` int(10) NOT NULL default '0', `amount7` int(10) NOT NULL default '0', `amount8` int(10) NOT NULL default '0', `amount9` int(10) NOT NULL default '0', `amount10` int(10) NOT NULL default '0', `amount11` int(10) NOT NULL default '0', `amount12` int(10) NOT NULL default '0', `amount13` int(10) NOT NULL default '0', `amount14` int(10) NOT NULL default '0', `amount15` int(10) NOT NULL default '0', `totalNaira` double(20,0) NOT NULL default '0', `totalDollar` int(20) NOT NULL default '0', PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='InnoDB free: 4096 kB; InnoDB free: 4096 kB; InnoDB free: 409'; #---------------------------- # Records for table litorder #---------------------------- insert into litorder values (27, 'Sanyaolu Fisayo', '14 Adegboyega Street Palmgrove Lagos', '2010-05-31', '', 'DL 001', 'DL 002', 'DL 003', '', '', '', '', '', '', '', '', '', '', '', '', 'AILMENT & PREVENTION DVD- ENGLISH', 'AILMENT & PREVENTION DVD- HAUSA', 'BEAUTY CD', '', '', '', '', '', '', '', '', '', '', '', '', 800, 800, 3000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 16, 16, 20, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 12800, 12800, 60000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, '85600', 563), (28, 'Irenonse Esther', 'Lagos,Nigeria', '2010-06-01', '', 'DL 005', 'DL 008', 'FC 004', '', '', '', '', '', '', '', '', '', '', '', '', 'GET HEALTHY DVD', 'YOUR FUTURE DVD', 'FOREVER FACE CAP (YELLOW)', '', '', '', '', '', '', '', '', '', '', '', '', 1000, 900, 2000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 2, 3, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2000, 1800, 6000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, '9800', 64), (29, 'Kalu Lekway', 'Lagos, Nigeria', '2010-06-01', '', 'DL 001', 'DL 003', '', '', '', '', '', '', '', '', '', '', '', '', '', 'AILMENT & PREVENTION DVD- ENGLISH', 'BEAUTY CD', '', '', '', '', '', '', '', '', '', '', '', '', '', 800, 3000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3, 6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2400, 18000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, '20400', 133), (30, 'Dele', 'Ilupeju', '2010-06-02', '', 'DL 001', 'DL 003', '', '', '', '', '', '', '', '', '', '', '', '', '', 'AILMENT & PREVENTION DVD- ENGLISH', 'BEAUTY CD', '', '', '', '', '', '', '', '', '', '', '', '', '', 800, 3000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10, 10, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 8000, 30000, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, '38000', 250);

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