Have an indicator
in the form of an image which
is displayed
in a graphics viewport.
The indicator can be any colour
the user selects so we created a single image with a pallette
and change a specific color
in the pallette to
the one
the user picks using
the following code.
/// <summary>
/// Copies
the image
and sets transparency
and fill colour of
the copy.
The image
is intended to be a simple filled shape such as a square
/// with
the inside all
in one colour.
/// </summary>
/// <remarks>Assumes
the fill colour to be changed
is Red,
/// black
is the boundary colour
and off white (RGB 233,233,233)
is the colour to be made transparent</remarks>
/// <param name="image"></param>
/// <param name="fillColour"></param>
/// <returns></returns>
protected Bitmap CopyWithStyle(Bitmap image, Color fillColour)
{
ColorPalette selectionIndicatorPalette = image.Palette;
int fillColourIndex = selectionIndicatorPalette.IndexOf(Color.Red);
selectionIndicatorPalette.Entries[fillColourIndex] = fillColour;
image.Palette = selectionIndicatorPalette;
Bitmap tempImage = image;
tempImage.MakeTransparent(transparentColour);
return tempImage;
}
To be honest I'm not sure if this
is a bit cludgy
and there
is some smarter approach or not, so any thoughts there would help. However
the main issue
is that this appears to work fine on Win7 but
in vista
and XP
the color does not change. Has any one seen this before. I've found one or two articles that suggest there are some differences
in ARGB
between them but nothing particularly concrete. Any help greatfully accepted.
