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  • protobuf-net NOT faster than binary serialization?

    - by Ashish Gupta
    I wrote a program to serialize a 'Person' class using XMLSerializer, BinaryFormatter and ProtoBuf. I thought protobuf-net should be faster than the other two. Protobuf serialization was faster than XMLSerialization but much slower than the binary serialization. Is my understanding incorrect? Please make me understand this. Thank you for the help. Following is the output:- Person got created using protocol buffer in 347 milliseconds Person got created using XML in 1462 milliseconds Person got created using binary in 2 milliseconds Code below using System; using System.Collections.Generic; using System.Linq; using System.Text; using ProtoBuf; using System.IO; using System.Diagnostics; using System.Runtime.Serialization.Formatters.Binary; namespace ProtocolBuffers { class Program { static void Main(string[] args) { string XMLSerializedFileName = "PersonXMLSerialized.xml"; string ProtocolBufferFileName = "PersonProtocalBuffer.bin"; string BinarySerializedFileName = "PersonBinary.bin"; var person = new Person { Id = 12345, Name = "Fred", Address = new Address { Line1 = "Flat 1", Line2 = "The Meadows" } }; Stopwatch watch = Stopwatch.StartNew(); watch.Start(); using (var file = File.Create(ProtocolBufferFileName)) { Serializer.Serialize(file, person); } watch.Stop(); Console.WriteLine(watch.ElapsedMilliseconds.ToString()); Console.WriteLine("Person got created using protocol buffer in " + watch.ElapsedMilliseconds.ToString() + " milliseconds " ); watch.Reset(); watch.Start(); System.Xml.Serialization.XmlSerializer x = new System.Xml.Serialization.XmlSerializer(person.GetType()); using (TextWriter w = new StreamWriter(XMLSerializedFileName)) { x.Serialize(w, person); } watch.Stop(); Console.WriteLine(watch.ElapsedMilliseconds.ToString()); Console.WriteLine("Person got created using XML in " + watch.ElapsedMilliseconds.ToString() + " milliseconds"); watch.Reset(); watch.Start(); using (Stream stream = File.Open(BinarySerializedFileName, FileMode.Create)) { BinaryFormatter bformatter = new BinaryFormatter(); //Console.WriteLine("Writing Employee Information"); bformatter.Serialize(stream, person); } watch.Stop(); Console.WriteLine(watch.ElapsedMilliseconds.ToString()); Console.WriteLine("Person got created using binary in " + watch.ElapsedMilliseconds.ToString() + " milliseconds"); Console.ReadLine(); } } [ProtoContract] [Serializable] public class Person { [ProtoMember(1)] public int Id {get;set;} [ProtoMember(2)] public string Name { get; set; } [ProtoMember(3)] public Address Address {get;set;} } [ProtoContract] [Serializable] public class Address { [ProtoMember(1)] public string Line1 {get;set;} [ProtoMember(2)] public string Line2 {get;set;} } }

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  • Flash CS, reference root from external class

    - by Lotus
    Hi, I made this class and I put it in the same package of Timeline.as (the Document Class): package { import flash.utils.Timer; import flash.events.TimerEvent; public class Counter2 extends Timer { public function Counter2(delay:Number, repeatCount:int=0) { super(delay, repeatCount); super.addEventListener(TimerEvent.TIMER, timerHandler); } public override function start():void { super.start(); } public override function stop():void { super.stop(); } public function timerHandler(evt:TimerEvent) { trace(evt.target.currentCount); } } } This class is instanciated in Timeline.as constructor. Is there any way to reference Timeline(root) from this class? And, if so, how? Thanks!

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  • Java: I can't interact with my JFrame

    - by Wooooo
    Hi, I have a java application (1.4.2) that uses 2 JFrames. The first is Modal=true and appears on top of the second JFrame. The first JFrame allows the user to "open" a file. Once the file is ready to be displayed, the JFrame is set to setModal=false, and this.dispose() 'd of. This leaves only the second JFrame on the screen. However, I can't interact with it. The code does not throw any errors and appears to run perfectly fine. BUT I can;t interact with the second JFrame. The ONLY way to exit the JFrame is to hit the stop button on my development envirnment. I literally cannot stop the JFrame by clicking the close button, because I can't even interact with that portion of the JFrame. Any thoughts?

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  • communication between threads in java

    - by Noona
    How can I make a thread run only if the other thread is running too, meaning, if I return from run in one thread, then I want the other to stop running too, my code looks something like this: ClientMessageHandler clientMessagehandler = new ClientMessageHandler(); ServerMessageHandler serverMessagehandler = new ServerMessageHandler(); Thread thread1 = new Thread(serverMessagehandler); Thread thread2 = new Thread(clientMessagehandler); thread2.start(); thread1.start(); i want to cause thread1 to stop running when thread2 stops running. thanks

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  • Stopping httpd causes a process started from perl CGI script to receive SIGTERM

    - by Pranav Pal
    I am running a shell script from a perl CGI script: #!/usr/bin/perl my $command = "./script.sh &"; my $pid = fork(); if (defined($pid) && $pid==0) { # background process system( $command ); } The shell script looks like this: #!/bin/sh trap 'echo trapped' 15 tail -f test.log When I run the CGI script from browser, and then stop httpd using /etc/init.d/httpd stop, the script receives a SIGTERM signal. I was expecting the script to run as a separate process and not be tied in anyway to httpd. Though I can trap the SIGTERM, I would like to understand why the script is receiving SIGTERM at all. What wrong am I doing here? I am running RHEL 5.8 and Apache HTTP server 2.4. Thanks, Pranav

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  • problems calling webservices through the https connection

    - by shivaji123
    i have done an application in BlackBerry which takes username & password with url link which is a link of server here i am calling some webservices but it is doing the connection in https so when i take the username password & url link & hit the login button it basically calls a webservice but then the application connecting to the webservice for ever & after some time i get the error massage something "unreported exception the application is not responding" .& then the application crashes out.Also i am using the SOAP client library . this is the piece of code synchronized (this) { try { _httpconn = (HttpConnection) Connector.open(url,Connector.READ_WRITE);//Connector.READ_WRITE //_httpconn =(StreamConnection)Connector.open(url); //System.out.println("-----------httpsconnection() PART--------------------"); _httpconn.setRequestMethod(HttpConnection.POST); //_httpconn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); //System.out.println("-----------httpsconnection() PART- **-------------------"); _httpconn.setRequestProperty("SOAPAction", Constants.EXIST_STR); //System.out.println("-----------httpsconnection() PART-REQUEST -------------------"); _httpconn.setRequestProperty("Content-Type", "text/soap+xml"); //System.out.println("-----------httpsconnection() PART- CONTENT-------------------"); _httpconn.setRequestProperty("User-Agent", "kSOAP/1.0"); //System.out.println("-----------httpsconnection() PART-USER Agent-------------------"); String clen = Integer.toBinaryString(input.length()); _httpconn.setRequestProperty("Content-Length", clen); //System.out.println("-----------httpsconnection() Content-Length--------------------"); _out = _httpconn.openDataOutputStream(); //System.out.println(input+"-----------input--------------------"+url); _out.write(input.getBytes()); _out.flush(); // may or may not be needed. //int rc = _httpconn.getResponseCode(); int rc = _httpconn.getResponseCode(); if(rc == HttpConnection.HTTP_OK) { isComplete = true; _in = _httpconn.openInputStream(); msg = new StringBuffer(); byte[] data = new byte[1024]; int len = 0; int size = 0; while ( -1 != (len = _in.read(data)) ) { msg.append(new String(data, 0, len)); size += len; } responsData = msg.toString(); System.out.println("-----------responsData "+responsData); } if(responsData!=null) isSuccessful = true; stop(); } catch (InterruptedIOException interrIO) { //errStr = "Network Connection hasn't succedded. "+ //"Please check APN setting."; UiApplication.getUiApplication().invokeLater(new Runnable() { public void run() { Status.show("Network Connection hasn't succedded. "+ "Please try again later."); } }); isComplete = true; System.out.println(interrIO); stop(); } catch (IOException interrIO) { System.out.println("-----------IO EXCEPTION--------- "+interrIO); //errStr = "Network Connection hasn't succedded. "+ //"Please check APN setting." ; UiApplication.getUiApplication().invokeLater(new Runnable() { public void run() { Status.show("Network Connection hasn't succedded. "+ "Please try again later." ); } }); isComplete = true; System.out.println(interrIO); stop(); } catch (Exception e) { System.out.println(e); //errStr = "Unable to connect to the internet at this time. "+ //"Please try again later."; UiApplication.getUiApplication().invokeLater(new Runnable() { public void run() { Status.show("Unable to connect to the internet at this time. "+ "Please try again later." ); } }); isComplete = true; stop(); } finally { try { if(_httpconn != null) { _httpconn.close(); _httpconn = null; } if(_in != null) { _in.close(); _in = null; } if(_out != null) { _out.close(); _out = null; } } catch(Exception e) { System.out.println(e); UiApplication.getUiApplication().invokeLater(new Runnable() { public void run() { Status.show("Unable to connect to the internet at this time. "+ "Please try again later." ); } }); } } } } can anybody help me out. Thanks in advance

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  • what happens to running/blocked runnables when executorservice is shutdown()

    - by prmatta
    I posted a question about a thread pattern today, and almost everyone suggested that I look into the ExecutorService. While I was looking into the ExecutorService, I think I am missing something. What happens if the service has a running or blocked threads, and someone calls ExecutorService.shutdown(). What happens to threads that are running or blocked? Does the ExecutorService wait for those threads to complete before it terminates? The reason I ask this is because a long time ago when I used to dabble in Java, they deprecated Thread.stop(), and I remember the right way of stopping a thread was to use sempahores and extend Thread when necessary: public void run () { while (!this.exit) { try { block(); //do something } catch (InterruptedException ie) { } } } public void stop () { this.exit = true; if (this.thread != null) { this.thread.interrupt(); this.thread = null; } } How does ExecutorService handle running threads?

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  • Can NSTask safely be used outside the main thread?

    - by neoneye
    Yesterday I read somewhere that NSTask isn't thread safe and that bothers me a lot, because I'm running a NSTask within a NSThread and is so far not experiencing any threading issues with it. My code is organized like this A: main thread -> B: worker thread -> C: worker task C: The worker task is a commandline program. B: The worker thread can start/stop the worker task and send it commands. A: The main thread can send commands to the worker thread. If NSTask is supposed to be used only within the main thread, then I'm considering moving the NSTask start/stop code to the main thread, just to prevent possible threading issues. Can NSTask be used outside the main thread? And if not then what may be the threading issues with NSTask?

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  • Prototype mouseleave for two elements

    - by TenJack
    I have created a small navigation element that is positioned right on top of another element. It is only shown when a user mousenters/mouseovers the main element. I am having some trouble with the prototype. I would like this small nav element to be hidden when a user mouses out of the main box, but I would also like the small nav element to remain visible if a user mouses out of the main box but mouses into the small nav at the same time. This is my attempt so far with some pseudo-code to hopefully explain: $('main_box').observe('mouseenter', function(){ $('small_div').show() }) $('main_box').observe('mouseleave', function(){ if this element is $('small_div') then Event.stop() $('small_div').observe('mouseleave', function(){ if this element is $('main_box') Event.stop observe $('main_box') mouseleave else $('small_div').hide(); }) else $('small_div').hide(); }) The main thing I'm having trouble with is figuring out what element the mouse is over at a given point in time. Is there a way to do something like: on mouseleave do blah unless the mouse is over a specific element then do not do blah?

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  • how to set BUILD_MAC_SDK_EXPERIMENTAL=1 on Mac 10.7?

    - by Nguyen Minh Binh
    I am building Android OS source on Mac 10.7 follow instructions at: http://source.android.com/source/building.html. Below are the error code when I try to run lunch full-eng BinhNguyens-MacBook:WORKING_DIRECTORY CuongLy$ lunch full-eng 2012-10-04 14:02:58.544 xcodebuild[645:80b] XcodeColors: load (v10.1) 2012-10-04 14:02:58.560 xcodebuild[645:80b] XcodeColors: pluginDidLoad: build/core/combo/HOST_darwin-x86.mk:62: ***************************** build/core/combo/HOST_darwin-x86.mk:63: * Can not find SDK 10.6 at /Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.6.sdk build/core/combo/HOST_darwin-x86.mk:65: * If you wish to build using higher version of SDK, build/core/combo/HOST_darwin-x86.mk:66: * try setting BUILD_MAC_SDK_EXPERIMENTAL=1 before build/core/combo/HOST_darwin-x86.mk:67: * rerunning this command build/core/combo/HOST_darwin-x86.mk:69: ***************************** build/core/combo/HOST_darwin-x86.mk:70: * Stop.. Stop. Please tell me how to set BUILD_MAC_SDK_EXPERIMENTAL=1 ?

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  • How to implement cancellable worker thread

    - by Arnold Zokas
    Hi, I'm trying to implement a cancellable worker thread using the new threading constructs in System.Threading.Tasks namespace. So far I have have come up with this implementation: public sealed class Scheduler { private CancellationTokenSource _cancellationTokenSource; public System.Threading.Tasks.Task Worker { get; private set; } public void Start() { _cancellationTokenSource = new CancellationTokenSource(); Worker = System.Threading.Tasks.Task.Factory.StartNew( () => RunTasks(_cancellationTokenSource.Token), _cancellationTokenSource.Token ); } private static void RunTasks(CancellationToken cancellationToken) { while (!cancellationToken.IsCancellationRequested) { Thread.Sleep(1000); // simulate work } } public void Stop() { try { _cancellationTokenSource.Cancel(); Worker.Wait(_cancellationTokenSource.Token); } catch (OperationCanceledException) { // OperationCanceledException is expected when a Task is cancelled. } } } When Stop() returns I expect Worker.Status to be TaskStatus.Canceled. My unit tests have shown that under certain conditions Worker.Status remains set to TaskStatus.Running. Is this a correct way to implement a cancellable worker thread?

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  • Server HTTP Load times slow?

    - by cdog5000
    Hello, My server @ codemeh.com (HTTP Server) seems to be randomly loading slowly, I cannot tell if it just my forums (http://www.codemeh.com/forums/) that are loading slowly or if the WHOLE site is just loading slowly since my forums are the largest thing on the site right now. load average: 0.02, 0.17, 0.20 That is super low to my knowledge. I have tried Google Page Analytic plug-in for FireFox to solve the problem but nothing comes up that is VERY bad. If someone could investigate this for me since I am very new at apache and server configurations. Thanks! (top): PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 7493 www-data 15 0 98.2m 16m 9092 S 3 0.8 0:27.24 apache2 26429 www-data 15 0 98.2m 15m 7392 S 3 0.7 0:03.45 apache2 26477 www-data 17 0 98.2m 15m 7396 S 3 0.7 0:03.16 apache2 1 root 15 0 2468 1384 1156 S 0 0.1 0:00.49 init 1367 root 25 0 2564 816 660 S 0 0.0 0:00.00 xinetd 1526 root 15 0 29576 5420 1976 S 0 0.3 1:02.69 fail2ban-server 3703 root 15 0 13512 9312 1696 S 0 0.4 0:11.59 miniserv.pl 3915 postfix 15 0 6056 1652 1320 S 0 0.1 0:00.00 pickup 4010 root 15 0 4548 1296 972 S 0 0.1 0:37.36 ntpd 7448 root 15 0 98528 26m 20m S 0 1.3 0:00.27 apache2 7454 www-data 18 0 33580 2616 368 S 0 0.1 0:00.04 apache2 7528 www-data 18 0 108m 24m 15m S 0 1.2 0:27.60 apache2 7974 root 16 0 8700 2728 2164 S 0 0.1 0:00.08 sshd 8123 cdog5000 15 0 8832 1596 896 S 0 0.1 0:00.00 sshd 8126 cdog5000 18 0 4484 1716 1384 S 0 0.1 0:00.00 bash 8141 cdog5000 15 0 2344 980 796 R 0 0.0 0:00.11 top 13461 root 15 0 8700 2728 2164 S 0 0.1 0:00.07 sshd 13567 cdog5000 18 0 8832 1492 896 S 0 0.1 0:00.33 sshd 13569 cdog5000 18 0 4484 1728 1388 S 0 0.1 0:00.09 bash 17983 root 15 0 4392 1268 988 S 0 0.1 0:00.00 su 17987 root 15 0 4516 1752 1380 S 0 0.1 0:00.09 bash 18081 www-data 15 0 98.2m 14m 6588 S 0 0.7 0:04.91 apache2 20000 www-data 15 0 98.3m 15m 8040 S 0 0.8 0:02.45 apache2 20019 www-data 15 0 98.2m 14m 6808 S 0 0.7 0:04.97 apache2 30343 root 15 0 3964 1012 764 S 0 0.0 0:00.03 vsftpd 30382 root 15 0 2304 908 716 S 0 0.0 0:00.62 cron 30401 mysql 17 0 141m 17m 5416 S 0 0.9 1:02.20 mysqld 30424 root 15 0 5472 912 504 S 0 0.0 0:00.04 sshd 30473 syslog 15 0 1916 676 536 S 0 0.0 0:01.02 syslogd 30611 amavis 15 0 33872 25m 2292 S 0 1.2 0:03.11 amavisd-new 31890 amavis 18 0 34888 24m 1792 S 0 1.2 0:00.00 amavisd-new 31891 amavis 18 0 34888 24m 1784 S 0 1.2 0:00.00 amavisd-new 32397 clamav 18 0 104m 84m 1272 S 0 4.1 1:06.46 clamd 32563 clamav 15 0 12832 5716 4440 S 0 0.3 0:01.29 freshclam 32573 root 23 0 1892 456 372 S 0 0.0 0:00.00 courierlogger 32575 root 18 0 2096 684 544 S 0 0.0 0:00.01 authdaemond 32583 root 23 0 1892 360 284 S 0 0.0 0:00.00 courierlogger 32584 root 24 0 2000 612 516 S 0 0.0 0:00.00 couriertcpd 32598 root 23 0 1892 360 284 S 0 0.0 0:00.00 courierlogger 32599 root 25 0 2000 612 516 S 0 0.0 0:00.00 couriertcpd 32604 root 18 0 1892 460 372 S 0 0.0 0:00.00 courierlogger 32605 root 18 0 2000 624 532 S 0 0.0 0:00.00 couriertcpd 32607 root 18 0 2308 404 256 S 0 0.0 0:00.02 authdaemond 32608 root 18 0 2096 260 116 S 0 0.0 0:00.03 authdaemond 32609 root 15 0 2308 404 256 S 0 0.0 0:00.03 authdaemond 32610 root 18 0 2096 260 116 S 0 0.0 0:00.02 authdaemond 32612 root 18 0 2308 404 256 S 0 0.0 0:00.02 authdaemond 32621 root 24 0 1892 364 284 S 0 0.0 0:00.00 courierlogger 32622 root 25 0 2000 608 516 S 0 0.0 0:00.00 couriertcpd 32633 root 15 0 105m 936 716 S 0 0.0 0:02.26 nscd 32719 root 16 0 6252 1680 1344 S 0 0.1 0:01.24 master 32738 postfix 15 0 6188 1776 1400 S 0 0.1 0:00.44 qmgr 32758 postfix 15 0 6492 2564 1788 S 0 0.1 0:00.14 tlsmgr (/etc/apache2/sites-available/default): NameVirtualHost * <VirtualHost *> ServerAdmin webmaster@localhost DocumentRoot /var/www/web1/web/ <Directory /var/www/web1/web/> Options Indexes MultiViews AllowOverride None Order allow,deny allow from all </Directory> </VirtualHost> I have fail2ban server and I dont have any firewall at this point and time that I know of. SMF is 2.0 RC4 and apache version is 2.2.14. I run a MySQL server on another box in the same DC (Persistent Connection). I installed eAccelerator today and it didnt help.

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  • android compilation

    - by user1241903
    I am trying to compile android source v2.3.4. When I give "make -j32", I am getting result like this.I am using fedora 14(32 bit). [root@localhost WORKING_DIRECTORY]# make -j32 ============================================ PLATFORM_VERSION_CODENAME=REL PLATFORM_VERSION=2.3.4 TARGET_PRODUCT=full TARGET_BUILD_VARIANT=eng TARGET_SIMULATOR=false TARGET_BUILD_TYPE=release TARGET_BUILD_APPS= TARGET_ARCH=arm HOST_ARCH=x86 HOST_OS=linux HOST_BUILD_TYPE=release BUILD_ID=GRJ22 ============================================ Checking build tools versions... build/core/main.mk:76: ************************************************************ build/core/main.mk:77: You are attempting to build on a 32-bit system. build/core/main.mk:78: Only 64-bit build environments are supported beyond froyo/2.2. build/core/main.mk:79: ************************************************************ build/core/main.mk:80: *** stop. Stop. [root@localhost WORKING_DIRECTORY]# Please help me to solve this issue. How to compile android source code on 32 bit os?. Thank You Rajendra

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  • Record audio via MediaRecorder

    - by Isuru Madusanka
    I am trying to record audio by MediaRecorder, and I get an error, I tried to change everything and nothing works. Last two hours I try to find the error, I used Log class too and I found out that error occurred when it call recorder.start() method. What could be the problem? public class AudioRecorderActivity extends Activity { MediaRecorder recorder; File audioFile = null; private static final String TAG = "AudioRecorderActivity"; private View startButton; private View stopButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); startButton = findViewById(R.id.start); stopButton = findViewById(R.id.stop); setContentView(R.layout.main); } public void startRecording(View view) throws IOException{ startButton.setEnabled(false); stopButton.setEnabled(true); File sampleDir = Environment.getExternalStorageDirectory(); try{ audioFile = File.createTempFile("sound", ".3gp", sampleDir); }catch(IOException e){ Toast.makeText(getApplicationContext(), "SD Card Access Error", Toast.LENGTH_LONG).show(); Log.e(TAG, "Sdcard access error"); return; } recorder = new MediaRecorder(); recorder.setAudioSource(MediaRecorder.AudioSource.MIC); recorder.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP); recorder.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB); recorder.setAudioEncodingBitRate(16); recorder.setAudioSamplingRate(44100); recorder.setOutputFile(audioFile.getAbsolutePath()); recorder.prepare(); recorder.start(); } public void stopRecording(View view){ startButton.setEnabled(true); stopButton.setEnabled(false); recorder.stop(); recorder.release(); addRecordingToMediaLibrary(); } protected void addRecordingToMediaLibrary(){ ContentValues values = new ContentValues(4); long current = System.currentTimeMillis(); values.put(MediaStore.Audio.Media.TITLE, "audio" + audioFile.getName()); values.put(MediaStore.Audio.Media.DATE_ADDED, (int)(current/1000)); values.put(MediaStore.Audio.Media.MIME_TYPE, "audio/3gpp"); values.put(MediaStore.Audio.Media.DATA, audioFile.getAbsolutePath()); ContentResolver contentResolver = getContentResolver(); Uri base = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI; Uri newUri = contentResolver.insert(base, values); sendBroadcast(new Intent(Intent.ACTION_MEDIA_SCANNER_SCAN_FILE, newUri)); Toast.makeText(this, "Added File" + newUri, Toast.LENGTH_LONG).show(); } } And here is the xml layout. <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/RelativeLayout1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" > <Button android:id="@+id/start" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentTop="true" android:layout_centerHorizontal="true" android:layout_marginTop="146dp" android:onClick="startRecording" android:text="Start Recording" /> <Button android:id="@+id/stop" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignLeft="@+id/start" android:layout_below="@+id/start" android:layout_marginTop="41dp" android:enabled="false" android:onClick="stopRecording" android:text="Stop Recording" /> </RelativeLayout> And I added permission to AndroidManifest file. <?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="in.isuru.audiorecorder" android:versionCode="1" android:versionName="1.0" > <uses-sdk android:minSdkVersion="8" /> <application android:icon="@drawable/ic_launcher" android:label="@string/app_name" > <activity android:name=".AudioRecorderActivity" android:label="@string/app_name" > <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/> <uses-permission android:name="android.permission.RECORD_AUDIO" /> </manifest> I need to record high quality audio. Thanks!

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  • Find a base case for a recursive void method

    - by Evan S
    I am doing homework. I would like to build a base case for a recursion where ordering given numbers (list2) in ascending order. Purpose of writing this codes is that when all numbers are in ascending order then should stop calling a method called ascending(list2, list1); and all values in list2 should be shipped to list1. For instance, list2 = 6,5,4,3,2,1 then list2 becomes empty and list1 should be 1,2,3,4,5,6. I am trying to compare result with previous one and if matches then stop. But I can't find the base case to stop it. In addition, Both ascending() and fixedPoint() are void method. Anybody has idea? lol Took me 3 days... When I run my code then 6,5,4,3,2,1 5,6,4,3,2,1 4,5,6,3,2,1 3,4,5,6,2,1 2,3,4,5,6,1 1,2,3,4,5,6 1,2,3,4,5,6 1,2,3,4,5,6 1,2,3,4,5,6 1,2,3,4,5,6 infinite............. public class Flipper { public static void main(String[] args) { Flipper aFlipper = new Flipper(); List<Integer> content = Arrays.asList(6,5,4,3,2,1); ArrayList<Integer> l1 = new ArrayList<Integer>(content); ArrayList<Integer> l2 = new ArrayList<Integer>(); // empty list aFlipper.fixedPoint(l2,l1); System.out.println("fix l1 is "+l1); System.out.println("fix l2 is "+l2); } public void fixedPoint(ArrayList<Integer> list1, ArrayList<Integer> list2) { // data is in list2 ArrayList<Integer> temp1 = new ArrayList<Integer>(); // empty list if (temp1.equals(list2)) { System.out.println("found!!!"); } else { ascending(list2, list1); // data, null temp1 = list1; // store processed value System.out.println("st list1 is "+list1); System.out.println("st list2 is "+list2); } fixedPoint(list2, list1); // null, processed data }

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  • PHP Longtext to display like the user wrote it

    - by yanike
    I need to know how to display information put in a database longtext field the way it was written. Like if a user writes in this below: My life is full of love I fly like wedding doves I blow passed stop signs That intersect with hate lines - I know what I am I know who I be If you can't accept me Then don't friend me I want it to display the text from the database just like the user wrote it in the textarea instead of it displaying in one like this: My life is full of love I fly like wedding doves I blow passed stop signs That intersect with hate lines I know what I am I know who I be If you can't accept me Then don't friend me How can I could it in PHP to display the information properly using PHP?

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  • How can I make sure the Sphinx daemon runs?

    - by Ethan
    I'm working on setting up a production server using CentOS 5.3, Apache, and Phusion Passenger (mod_rails). I have an app that uses the Sphinx search engine and the Thinking Sphinx gem. According to the Thinking Sphinx docs... If you actually want to search against the indexed data, then you’ll need Sphinx’s searchd daemon to be running. This can be controlled using the following tasks: rake thinking_sphinx:start rake ts:start rake thinking_sphinx:stop rake ts:stop What would be the best way to ensure that this takes place in production? I can deploy my app, then manually run rake thinking_sphinx:start, but I like to set things up so that if I have to bounce the server, everything will come back up. Should I put a call to that Rake task in an initializer? Or something in rc.local?

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  • Embeding EasyVideoPlayer Code into Wordpress Theme - Video not showing

    - by bbacarat
    I'm attempting to place some embed code into a Premium WordPress Theme. NOTE: I'm not great when it comes to php. The embed code is produced by a video player called EasyVideoPlayer. (Basically it allows me to use Amazon S3 and gives me feedback on when people stop watching the video.) This is the embed code I have: _evpInit('ZXh0cmEtbW9uZXktZnJvbS1ob21lLTEubW92'); I've opened the index.php wordpress file and placed this video embed code in between the that represents the area of the website I want it to show up. However the video is not showing. If we place both the theme and video player aside, would you expect the php code to accept what I've done or is this not the way to go about adding this embed code? NOTE:I've contacted both the Wordpress Premium Theme support at Woothemes.com and the video players support for EasyVideoPlayer.com However both tend to stop at the point that another paid product is involved! Grrreat. website is www.extramoneyfromhome.co.uk

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  • Switch between speakerphone and headset on Android

    - by user210504
    Hi! I wish to know if there is a way, using which we can switch between the speaker and headset dynamically in an android application. I am using this sample code, I found online for my experiments final float frequency = 440; float increment = (float)(2*Math.PI) * frequency / 44100; // angular increment for each sample float angle = 0; AndroidAudioDevice device = new AndroidAudioDevice( ); AudioManager am = (AudioManager)getSystemService(AUDIO_SERVICE); am.setMode(AudioManager.MODE_IN_CALL); float samples[] = new float[1024]; int count = 0; while( count < 10 ) { count++; for( int i = 0; i < samples.length; i++ ) { samples[i] = (float)Math.sin( angle ) ; angle += increment; } device.writeSamples( samples ); } device.stop(); am.setMode(AudioManager.MODE_NORMAL); ---- next class public class AndroidAudioDevice { AudioTrack track; short[] buffer = new short[1024]; public AndroidAudioDevice( ) { int minSize =AudioTrack.getMinBufferSize( 44100, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_16BIT ); track = new AudioTrack( AudioManager.STREAM_VOICE_CALL, 44100, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_16BIT, minSize, AudioTrack.MODE_STREAM); track.play(); } public void writeSamples(float[] samples) { fillBuffer( samples ); track.write( buffer, 0, samples.length ); } private void fillBuffer( float[] samples ) { if( buffer.length < samples.length ) buffer = new short[samples.length]; for( int i = 0; i < samples.length; i++ ) buffer[i] = (short)(samples[i] * Short.MAX_VALUE);; } public void stop() { track.stop(); } } As per my understanding this should play audio on headset, because we have not enabled the speaker phone. However, the audio is playing on the speaker phone. 1 Am I doing something wrong here? 2 What would be a way to switch between internal speaker and speaker phone dynamically for same code peice Any help will be appreciated.

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  • jquery clickling fast

    - by Johansrk
    Hi. I have this function, that adds 31px to my style bottom on ul. It works fine, but if I click fast, it no longer adds 31px, but some weird number like 17.423px. I guess it's because the animation isn't done, and thereby by clicking fast it adds 31px to the current px amount. My thought is that I need to insert a stop(). But where? Thanks $(function () { $('.topTenTwocolumns .topTenTwocolumnsWrap .down').click(function () { if ($("ul").css("bottom") !== '2728px') { $(this).parents('.topTenTwocolumnsWrap').children('ul').stop().animate({ bottom: '+=31' }, 200); } }); });

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  • Using Timer only once

    - by zaidwaqi
    Hi, I want to use a timer only once, at 1 second after the initialization of my main form. I thought the following would have a message box saying "Hello World" just once, but actually a new message box says "Hello World" every one second. Why so? I had put t.Stop() in the tick event. Also, do I need to dispose the timer somehow to avoid memory leakage? Timer t = new Timer(); t.Interval = 1000; t.Tick += delegate(System.Object o, System.EventArgs e) { MessageBox.Show("Hello World"); t.Stop(); }; t.Start(); Please help and show if there is a better way of doing this? Thanks.

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  • how to run progress-bar through insert query ?

    - by Gold
    hi i have this insert query: try { Cmd.CommandText = @"INSERT INTO BarcodTbl SELECT * FROM [Text;DATABASE=" + PathI + @"\].[Tmp.txt];"; Cmd.ExecuteNonQuery(); Cmd.Dispose(); } catch (Exception ex) { MessageBox.Show(ex.Message); } and i have two question: how to run progress-bar from the begging to the end of the insert ? if there any error i got the error exception and the action is stop - the query stop and the BarcodTbl is empty. how i can see the error and that the query will continue to fill the table ? thank's in advance

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  • TcpListener Socket still active after program exits.

    - by lnical
    I'm trying to stop a TCP Listener as my program is exiting. I do not care about any data that is currently active on the socket or any of the active client sockets. The socket clean up code is essentially: try { myServer.Server.Shutdown(SocketShutdown.Both) } catch (Exception ex) { LogException(ex) } myServer.Server.Close(0) myServer.Stop() myServer is a TCPListener On some occasions, Shutdown will thrown an exception System.Net.Sockets.SocketException: A request to send or receive data was disallowed because the socket is not connected and (when sending on a datagram socket using a sendto call) no address was supplied at System.Net.Sockets.Socket.Shutdown(SocketShutdown how) When this happens, the socket is never released. Even after the application exits netstat shows the socket is still in the listening state. I have not been able to create definitive reproduction scenerio, it happens at seemingly random times. Client Sockets are cleaned up independently. Do you have any suggestions to help me make this socket die?

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  • Can this loop be sped up in pure Python?

    - by Noctis Skytower
    I was trying out an experiment with Python, trying to find out how many times it could add one to an integer in one minute's time. Assuming two computers are the same except for the speed of the CPUs, this should give an estimate of how fast some CPU operations may take for the computer in question. The code below is an example of a test designed to fulfill the requirements given above. This version is about 20% faster than the first attempt and 150% faster than the third attempt. Can anyone make any suggestions as to how to get the most additions in a minute's time span? Higher numbers are desireable. EDIT: This experiment is being written in Python 3.1 and is 15% faster than the fourth speed-up attempt. def start(seconds): import time, _thread def stop(seconds, signal): time.sleep(seconds) signal.pop() total, signal = 0, [None] _thread.start_new_thread(stop, (seconds, signal)) while signal: total += 1 return total if __name__ == '__main__': print('Testing the CPU speed ...') print('Relative speed:', start(60))

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