Is call to function object inlined?
- by dehmann
In the following code, Foo::add calls a function via a function object:
struct Plus {
inline int operator()(int x, int y) const {
return x + y;
}
};
template<class Fct>
struct Foo {
Fct fct;
Foo(Fct f) : fct(f) {}
inline int add(int x, int y) {
return fct(x,y); // same efficiency adding directly?
}
};
Is this the same efficiency as calling x+y directly in Foo::add? In other words, does the compiler typically directly replace fct(x,y) with the actual call, inlining the code, when compiling with optimizations enabled?
