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  • Pass in a value into Python Class through command line

    - by chrissygormley
    Hello, I have got some code to pass in a variable into a script from the command line. The script is: import sys, os def function(var): print var class function_call(object): def __init__(self, sysArgs): try: self.function = None self.args = [] self.modulePath = sysArgs[0] self.moduleDir, tail = os.path.split(self.modulePath) self.moduleName, ext = os.path.splitext(tail) __import__(self.moduleName) self.module = sys.modules[self.moduleName] if len(sysArgs) > 1: self.functionName = sysArgs[1] self.function = self.module.__dict__[self.functionName] self.args = sysArgs[2:] except Exception, e: sys.stderr.write("%s %s\n" % ("PythonCall#__init__", e)) def execute(self): try: if self.function: self.function(*self.args) except Exception, e: sys.stderr.write("%s %s\n" % ("PythonCall#execute", e)) if __name__=="__main__": test = test() function_call(sys.argv).execute() This works by entering ./function <function> <arg1 arg2 ....>. The problem is that I want to to select the function I want that is in a class rather than just a function by itself. The code I have tried is the same except that function(var): is in a class. I was hoping for some ideas on how to modify my function_call class to accept this. Thanks for any help.

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  • Python - Compress Ascii String

    - by n0idea
    I'm looking for a way to compress an ascii-based string, any help? I need also need to decompress it. I tried zlib but with no help. What can I do to compress the string into lesser length? code: def compress(request): if request.POST: data = request.POST.get('input') if is_ascii(data): result = zlib.compress(data) return render_to_response('index.html', {'result': result, 'input':data}, context_instance = RequestContext(request)) else: result = "Error, the string is not ascii-based" return render_to_response('index.html', {'result':result}, context_instance = RequestContext(request)) else: return render_to_response('index.html', {}, context_instance = RequestContext(request))

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  • python - from matrix to dictionary in single line

    - by Sanich
    matrix is a list of lists. I've to return a dictionary of the form {i:(l1[i],l2[i],...,lm[i])} Where the key i is matched with a tuple the i'th elements from each list. Say matrix=[[1,2,3,4],[9,8,7,6],[4,8,2,6]] so the line: >>> dict([(i,tuple(matrix[k][i] for k in xrange(len(matrix)))) for i in xrange(len(matrix[0]))]) does the job pretty well and outputs: {0: (1, 9, 4), 1: (2, 8, 8), 2: (3, 7, 2), 3: (4, 6, 6)} but fails if the matrix is empty: matrix=[]. The output should be: {} How can i deal with this?

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  • python multiprocessing member variable not set

    - by Jake
    In the following script, I get the "stop message received" output but the process never ends. Why is that? Is there another way to end a process besides terminate or os.kill that is along these lines? from multiprocessing import Process from time import sleep class Test(Process): def __init__(self): Process.__init__(self) self.stop = False def run(self): while self.stop == False: print "running" sleep(1.0) def end(self): print "stop message received" self.stop = True if __name__ == "__main__": test = Test() test.start() sleep(1.0) test.end() test.join()

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  • Python and sqlite3 - importing and exporting databases

    - by JPC
    I'm trying to write a script to import a database file. I wrote the script to export the file like so: import sqlite3 con = sqlite3.connect('../sqlite.db') with open('../dump.sql', 'w') as f: for line in con.iterdump(): f.write('%s\n' % line) Now I want to be able to import that database. I tried: import sqlite3 con = sqlite3.connect('../sqlite.db') f = open('../dump.sql','r') str = f.read() con.execute(str) but I'm not allowed to execute more than one statement. Is there a way to get it to run a .sql script directly?

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  • python destructuring-bind dictionary contents

    - by Stephen
    Hi, I am trying to 'destructure' a dictionary and associate values with variables names after its keys. Something like params = {'a':1,'b':2} a,b = params.values() but since dictionaries are not ordered, there is no guarantee that params.values() will return values in the order of (a,b). Is there a nice way to do this? Thanks

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  • Python/Django Concatenate a string depending on whether that string exists

    - by Douglas Meehan
    I'm creating a property on a Django model called "address". I want address to consist of the concatenation of a number of fields I have on my model. The problem is that not all instances of this model will have values for all of these fields. So, I want to concatenate only those fields that have values. What is the best/most Pythonic way to do this? Here are the relevant fields from the model: house = models.IntegerField('House Number', null=True, blank=True) suf = models.CharField('House Number Suffix', max_length=1, null=True, blank=True) unit = models.CharField('Address Unit', max_length=7, null=True, blank=True) stex = models.IntegerField('Address Extention', null=True, blank=True) stdir = models.CharField('Street Direction', max_length=254, null=True, blank=True) stnam = models.CharField('Street Name', max_length=30, null=True, blank=True) stdes = models.CharField('Street Designation', max_length=3, null=True, blank=True) stdessuf = models.CharField('Street Designation Suffix',max_length=1, null=True, blank=True) I could just do something like this: def _get_address(self): return "%s %s %s %s %s %s %s %s" % (self.house, self.suf, self.unit, self.stex, self.stdir, self.stname, self.stdes, self.stdessuf) but then there would be extra blank spaces in the result. I could do a series of if statements and concatenate within each, but that seems ugly. What's the best way to handle this situation? Thanks.

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  • Unicode filename to python subprocess.call()

    - by otrov
    I'm trying to run subprocess.call() with unicode filename, and here is simplified problem: n = u'c:\\windows\\notepad.exe ' f = u'c:\\temp\\nèw.txt' subprocess.call(n + f) which raises famous error: UnicodeEncodeError: 'ascii' codec can't encode character u'\xe8' Encoding to utf-8 produces wrong filename, and mbcs passes filename as new.txt without accent I just can't read any more on this confusing subject and spin in circle. I found here lot of answers for many different problems in past so I thought to join and ask for help myself Thanks

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  • Join a list of lists together into 1 list in Python

    - by dotty
    Hay All. I have a list which consists of many lists, here is an example [ [Obj, Obj, Obj, Obj], [Obj], [Obj], [ [Obj,Obj], [Obj,Obj,Obj] ] ] Is there a way to join all these items together as 1 list, so the output will be something like [Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj] Thanks

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  • Plotting a cumulative graph of python datetimes

    - by ventolin
    Say I have a list of datetimes, and we know each datetime to be the recorded time of an event happening. Is it possible in matplotlib to graph the frequency of this event occuring over time, showing this data in a cumulative graph (so that each point is greater or equal to all of the points that went before it), without preprocessing this list? (e.g. passing datetime objects directly to some wonderful matplotlib function) Or do I need to turn this list of datetimes into a list of dictionary items, such as: {"year": 1998, "month": 12, "date": 15, "events": 92} and then generate a graph from this list? Sorry if this seems like a silly question - I'm not all too familiar with matplotlib, and would like to save myself the effort of doing this the latter way if matplotlib can already deal with datetime objects itself.

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  • Python: find <title>

    - by Peter
    I have this: response = urllib2.urlopen(url) html = response.read() begin = html.find('<title>') end = html.find('</title>',begin) title = html[begin+len('<title>'):end].strip() if the url = http://www.google.com then the title have no problem as "Google", but if the url = "http://www.britishcouncil.org/learning-english-gateway" then the title become "<!doctype html public "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <base href="http://www.britishcouncil.org/" /> <META http-equiv="Content-Type" Content="text/html;charset=utf-8"> <meta name="WT.sp" content="Learning;Home Page Smart View" /> <meta name="WT.cg_n" content="Learn English Gateway" /> <META NAME="DCS.dcsuri" CONTENT="/learning-english-gateway.htm">..." What is actually happening, why I couldn't return the "title"?

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  • javascript-aware html parser for Python ~

    - by znetor
    <html> <head> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> </head> <body> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> <div><a href="http://www.google.com">f*** js</a></div> </body> </html> I want use xpath to catch all lable object in the html page above... In [1]: import lxml.html as H In [2]: f = open("test.html","r") In [3]: c = f.read() In [4]: doc = H.document_fromstring(c) In [5]: doc.xpath('//a') Out[5]: [<Element a at a01d17c>] In [6]: a = doc.xpath('//a')[0] In [7]: a.getparent() Out[7]: <Element div at a01d41c> I only get one don't generate by js~ but firefox xpath checker can find all lable!? http://i.imgur.com/0hSug.png how to do that??? thx~! <html> <head> </head> <body> <script language="javascript"> function over(){ a.innerHTML="mouse me" } function out(){ a.innerHTML="<a href='http://www.google.com'>google</a>" } </script> <body><li id="a"onmouseover="over()" onmouseout="out()">mouse me</li> </body> </html>

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  • Dealing with regular expressions, Python

    - by Gusto
    I want to remove some symbols from a string using a regular expression, for example: == (that occur both at the beginning and at the end of a line), * (at the beginning of a line ONLY). def some_func(): clean = re.sub(r'= {2,}', '', clean) #Removes 2 or more occurrences of = at the beg and at the end of a line. clean = re.sub(r'^\* {1,}', '', clean) #Removes 1 or more occurrences of * at the beginning of a line. What's wrong with my code? It seems like expressions are wrong. How do I remove a character/symbol if it's at the beginning or at the end of the line (with one or more occurrences)?

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  • building a pairwise matrix in scipy/numpy in Python from dictionaries

    - by user248237
    I have a dictionary whose keys are strings and values are numpy arrays, e.g.: data = {'a': array([1,2,3]), 'b': array([4,5,6]), 'c': array([7,8,9])} I want to compute a statistic between all pairs of values in 'data' and build an n by x matrix that stores the result. Assume that I know the order of the keys, i.e. I have a list of "labels": labels = ['a', 'b', 'c'] What's the most efficient way to compute this matrix? I can compute the statistic for all pairs like this: result = [] for elt1, elt2 in itertools.product(labels, labels): result.append(compute_statistic(data[elt1], data[elt2])) But I want result to be a n by n matrix, corresponding to "labels" by "labels". How can I record the results as this matrix? thanks.

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  • How to replace only part of the match with python re.sub

    - by Arty
    I need to match two cases by one reg expression and do replacement 'long.file.name.jpg' - 'long.file.name_suff.jpg' 'long.file.name_a.jpg' - 'long.file.name_suff.jpg' I'm trying to do the following re.sub('(\_a)?\.[^\.]*$' , '_suff.',"long.file.name.jpg") But this is cut the extension '.jpg' and I'm getting long.file.name_suff. instead of long.file.name_suff.jpg I understand that this is because of [^.]*$ part, but I can't exclude it, because I have to find last occurance of '_a' to replace or last '.' Is there a way to replace only part of the match?

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  • Python If Statement Defaults to an elif

    - by Brad Carvalho
    Not sure why my code is defaulting to this elif. But it's never getting to the else statement. Even going as far as throwing index out of bound errors in the last elif. Please disregard my non use of regex. It wasn't allowed for this homework assignment. The problem is the last elif before the else statement. Cheers, Brad if item == '': print ("%s\n" % item).rstrip('\n') elif item.startswith('MOVE') and not item.startswith('MOVEI'): print 'Found MOVE' elif item.startswith('MOVEI'): print 'Found MOVEI' elif item.startswith('BGT'): print 'Found BGT' elif item.startswith('ADD'): print 'Found ADD' elif item.startswith('INC'): print 'Found INC' elif item.startswith('SUB'): print 'Found SUB' elif item.startswith('DEC'): print 'Found DEC' elif item.startswith('MUL'): print 'Found MUL' elif item.startswith('DIV'): print 'Found DIV' elif item.startswith('BEQ'): print 'Found BEQ' elif item.startswith('BLT'): print 'Found BLT' elif item.startswith('BR'): print 'Found BR' elif item.startswith('END'): print 'Found END' elif item.find(':') and item[(item.find(':') -1)].isalpha(): print 'Mya have found a label' else: print 'Not sure what I found'

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  • Python method to remove iterability

    - by Debilski
    Suppose I have a function which can either take an iterable/iterator or a non-iterable as an argument. Iterability is checked with try: iter(arg). Depending whether the input is an iterable or not, the outcome of the method will be different. Not when I want to pass a non-iterable as iterable input, it is easy to do: I’ll just wrap it with a tuple. What do I do when I want to pass an iterable (a string for example) but want the function to take it as if it’s non-iterable? E.g. make that iter(str) fails.

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  • python list/dict property best practice

    - by jterrace
    I have a class object that stores some properties that are lists of other objects. Each of the items in the list has an identifier that can be accessed with the id property. I'd like to be able to read and write from these lists but also be able to access a dictionary keyed by their identifier. Let me illustrate with an example: class Child(object): def __init__(self, id, name): self.id = id self.name = name class Teacher(object): def __init__(self, id, name): self.id = id self.name = name class Classroom(object): def __init__(self, children, teachers): self.children = children self.teachers = teachers classroom = Classroom([Child('389','pete')], [Teacher('829','bob')]) This is a silly example, but it illustrates what I'm trying to do. I'd like to be able to interact with the classroom object like this: #access like a list print classroom.children[0] #append like it's a list classroom.children.append(Child('2344','joe')) #delete from like it's a list classroom.children.pop(0) But I'd also like to be able to access it like it's a dictionary, and the dictionary should be automatically updated when I modify the list: #access like a dict print classroom.childrenById['389'] I realize I could just make it a dict, but I want to avoid code like this: classroom.childrendict[child.id] = child I also might have several of these properties, so I don't want to add functions like addChild, which feels very un-pythonic anyway. Is there a way to somehow subclass dict and/or list and provide all of these functions easily with my class's properties? I'd also like to avoid as much code as possible.

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  • Sympy python circumference

    - by Mattia Villani
    I need to display a circumference. In order to do that I thought I could calculata for a lot of x the two values of y, so I did: import sympy as sy from sympy.abc import x,y f = x**2 + y**2 - 1 a = x - 0.5 sy.solve([f,a],[x,y]) and this is what I get: Traceback (most recent call last): File "<input>", line 1, in <module> File "/usr/lib/python2.7/dist-packages/sympy/solvers/solvers.py", line 484, in solve solution = _solve(f, *symbols, **flags) File "/usr/lib/python2.7/dist-packages/sympy/solvers/solvers.py", line 749, in _solve result = solve_poly_system(polys) File "/usr/lib/python2.7/dist-packages/sympy/solvers/polysys.py", line 40, in solve_poly_system return solve_biquadratic(f, g, opt) File "/usr/lib/python2.7/dist-packages/sympy/solvers/polysys.py", line 48, in solve_biquadratic G = groebner([f, g]) File "/usr/lib/python2.7/dist-packages/sympy/polys/polytools.py", line 5308, i n groebner raise DomainError("can't compute a Groebner basis over %s" % domain) DomainError: can't compute a Groebner basis over RR How can I calculate the y's values ?

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