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  • Performing non-blocking requests? - Django

    - by RadiantHex
    Hi folks, I have been playing with other frameworks, such as NodeJS, lately. I love the possibility to return a response, and still being able to do further operations. e.g. def view(request): do_something() return HttpResponse() do_more_stuff() #not possible!!! Maybe Django already offers a way to perform operations after returning a request, if that is the case that would be great. Help would be very much appreciated! =D

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  • jQuery AJAX requests with Rails 3

    - by elsurudo
    I'm trying to do a manual jQuery AJAX request the following way: $("#user_plan_id").change(function() { $("#plan_container").load('/plans/' + this.value); }); I have the "rails.js" file included in my header, and a "<%= csrf_meta_tag %". I see from my log that the request IS getting to the server (although without the authenticity token... does rails.js even do this?), but the response is a 302 (Found) rather than 200, and no data actually gets rendered. Any ideas?

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  • How to keep a shell open across multiple ajax requests in PHP?

    - by Joost van Doorn
    I need to use a shell across multiple ajax requests. Basically this means that the next request should be able to continue with the same shell where the other process left off. The purpose is to communicate with daemons like FTP to open an FTP connection and log in and in the next request continue with that connection and be able to use it for uploads. But it's not limited to only the FTP daemon (as I know that FTP is supported in PHP).

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  • Apache mod_rewrite - prefer files over directories with pretty URLs

    - by Jesse
    I want to have pretty urls so http://www.domain.com/foo will return http://www.domain.com/foo.php The issue is that there is a directory that has the same name. I have another page at http://www.domain.com/foo/bar/baz and right now my server just returns the directory listing of foo when I request http://www.domain.com/foo Pseudocode: If the request plus ".php" is a file rewrite out the file instead of the directory Actual Code: RewriteEngine On RewriteBase / RewriteCond %{SCRIPT_FILENAME}\.php -f RewriteRule (.*) $1.php [NC,L]

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  • Error handling in the RequestHandler without embedding in URI

    - by hyn
    When a user sends a filled form, I want to print an error message in case there is an input error. One of the GAE sample codes does this by embedding the error message in the URI. Inside the form handler (get): self.redirect('/compose?error_message=%s' % message) and in the handler (get) of redirected URI, gets the message from request: values = { 'error_message': self.request.get('error_message'), ... Is there a way to accomplish the same without embedding the message in the URI?

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  • SVNkit not working on UNIX

    - by Gabriel Parenza
    I am trying to checkout files on Unix using SVNkit. The same code was working on Windows box. Am I missing something here? svn: handshake_failure: remotely generated; fatal svn: OPTIONS request failed on '/svn/repos/branches/Package1' Error code desription:: RA layer request failed Error code:: 175002

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  • Copy binary image data into a string

    - by Alien01
    I need to send image data over network using HttpSendRequest POST request. For this purpose I am creating a string , adding some parameters to string, then I need to add raw image data. Now I would like to know how can I send the image in post request.

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  • invite friends in a dialog in a Facebook application

    - by Shani1351
    I'm trying to create a Facebook application that displays a friend invite dialog within the application using Facebook's Javascript API (FB.ui). To do that I followed this tutorial I have two problems : The action url I've put in the request-form is "http://apps.facebook.com/appname/post_invite.php" but I see that the iframe source after the post is "http://mydomain.com/post_invite.php" and when this iframe tries to do : parent.closeInviteWidget(); I get an error saying : "Permission denied for < http: //mydomain.com (document.domain has not been set) to get property Window.closeInviteWidget from < http:// apps.facebook.com (document.domain=< http:// facebook.com)." The skip button inside the request-form opens the action url in a new window (new browser tab) and not post to itself like the invite button. How can I fix those problems? -------------------- UPDATE : -------------------------------- I've tried to do what ifaour said and changed the code to : function inviteFriends(user_name, category_id, category_name) { url = appBaseUrl + "/index.php?category_id=" + category_id; req = "<fb:req-choice url='" + url + "' label='Authorize My Application' />"; content = user_name + " opened a new category called " + category_name + ". " + req; action = 'post_invite.php'; fbmi_text = '<fb:request-form action="' + action + '" target="_self" method="post" invite="true" type="Invite" content="' + content + '" <fb:multi-friend-selector showborder="false" actiontext="Invite yor friends" email_invite="false" import_external_friends="false" /> </fb:request-form>'; FB.ui({ method:'fbml.dialog', width:'750px', fbml:fbmi_text }); } When I use FireBug and look at the invite form it looks like this: <form id="req_form_4d20682f73ddb6e71722794" content="I've opened a new category called dsfsd. <fb:req-choice url='http://apps.facebook.com/appname/index.php?category_id=60' label='Authorize My Application' /> type="Invite" invite="true" method="post" target="_self" action="http://apps.facebook.com/appname/post_invite.php"> ... </form> But I still get the same error : Permission denied for <http://mydomain.com> (document.domain has not been set) to get property Window.closeInviteWidget from <http://apps.facebook.com> (document.domain=<http://facebook.com>)...

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  • ASP.NET Application Level vs. Session Level and Global.asax...confused

    - by contactmatt
    The following text is from the book I'm reading, 'MCTS Self-Paced Training Kit (Exam 70-515) Web Applications Development with ASP.NET 4". It gives the rundown of the Application Life Cycle. A user first makes a request for a page in your site. The request is routed to the processing pipeline, which forwards it to the ASP.NET runtime. The ASP.NET runtime creates an instance of the ApplicationManager class; this class instance represents the .NET framework domain that will be used to execute requests for your application. An application domain isolates global variables from other applications and allows each application to load and unload separately, as required. After the application domain has been created, an instance of the HostingEnvironment class is created. This class provides access to items inside the hosting environment, such as directory folders. ASP.NET creates instances of the core objects that will be used to process the request. This includes HttpContext, HttpRequest, and HttpResponse objects. ASP.NET creates an instance of the HttpApplication class (or an instance is reused). This class is also the base class for a site’s Global.asax file. You can use this class to trap events that happen when your application starts or stops. When ASP.NET creates an instance of HttpApplication, it also creates the modules configured for the application, such as the SessionStateModule. Finally, ASP.NET processes request through the HttpApplication pipleline. This pipeline also includes a set of events for validating requests, mapping URLs, accessing the cache, and more. The book then demonstrated an example of using the Global.asax file: <script runat="server"> void Application_Start(object sender, EventArgs e) { Application["UsersOnline"] = 0; } void Session_Start(object sender, EventArgs e) { Application.Lock(); Application["UsersOnline"] = (int)Application["UsersOnline"] + 1; Application.UnLock(); } void Session_End(object sender, EventArgs e) { Application.Lock(); Application["UsersOnline"] = (int)Application["UsersOnline"] - 1; Application.UnLock(); } </script> When does an application start? Whats the difference between session and application level? I'm rather confused on how this is managed. I thought that Application level classes "sat on top of" an AppDomain object, and the AppDomain contained information specific to that Session for that user. Could someone please explain how IIS manages Applicaiton level classes, and how an HttpApplication class sits under an AppDomain? Anything is appreciated.

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  • sql statement "into outfile" not working with jdbc

    - by Celeste Berus
    I am attempting to add an "export to CSV" feature to a webapp that displays data from a MySQL database. I have a written a "queryExecuter" class to execute queries from my servlet. I have used this to successfully execute insert queries so I know the connection works etc however queries with the "into outfile" statement are simply not executing. Here is my code, the java class... import java.sql.Connection; import java.sql.DriverManager; import java.sql.Statement; import java.sql.ResultSet; public class queryExecuter { public void exportToCSV(String query) { DBase db = new DBase(); Connection conn = db.connect( mydatabaseurl ,"myusername","mypassword"); db.exportData(conn,query); } } class DBase { public DBase() { } public Connection connect(String db_connect_str, String db_userid, String db_password) { Connection conn; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); conn = DriverManager.getConnection(db_connect_str, db_userid, db_password); } catch(Exception e) { e.printStackTrace(); conn = null; } return conn; } public void exportData(Connection conn,String query) { Statement stmt; try { stmt = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE); stmt.execute(query); } catch(Exception e) { e.printStackTrace(); stmt = null; } } }; The servlet... import java.io.IOException; import java.io.PrintWriter; import java.sql.SQLException; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import javax.servlet.*; import javax.servlet.http.*; import java.io.*; public class MyExportServlet extends HttpServlet { public void doPost(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { String query = "select into outfile 'theoutfile.txt' * from mytable;"; request.setAttribute("query", query); queryExecuter mydata = new queryExecuter(); mydata.exportToCSV(query); RequestDispatcher view = request.getRequestDispatcher("ConfirmationPage.jsp"); view.forward(request, response); } } Any help would be greatly appreciated. Thank you

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  • Passing Auth to API calls with Web Service References

    - by coffeeaddict
    I am new to web services. The last time I dealt with SOAP was when I created a bunch of wrapper classes that sent requests and received responses back per some response objects/classes I had created. So I had an object to send certain API requests and likewise a set of objects to hold the response back as an object so I could utilize that 3rd party API. Then someone came to me and said why not just use the wsdl and a web service. Ok, so today I went and created a "Service Reference". I see that this is what's called a "Proxy Class". You just instantiate an instance of this and then walla you have access to all the methods from the wsdl. But this leaves me with auth questions. Back when I created my own classes manually, I had a class which exposed properties that I would set then access for things like signature, username, password that got sent along with the Http request that were required by whatever 3rd party API I was using to make API calls. But then with using a Service Reference, how then would I pass this information just like I had done in my custom classes? For instance I'm going to be working with the PayPal API. It requires you to send a signature and a few other pieces of information like username and password. // Determins if API call needs to use a session based URI string requestURI = UseAuthURI == true ? _requestURIAuthBased + aSessionID : _requestURI; byte[] data = XmlUtil.DocumentToBytes(doc); // Create the atual Request instance HttpWebRequest request = CreateWebRequest(requestURI, data.Length); So how do I pass username, password, signature, etc. when using web service references for each method call? Is it as simple as specifying it as a param to the method or do you use the .Credentials and .URL methods of your proxy class object? It seems to me Credentials means windows credentials but I could be wrong. Is it limited to that or can you use that to specify those required header values that PayPal expects with each method call/API request?

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  • i need a query to retrieve the following constraint

    - by ANITHA
    I have the following tables and fields: +------------------+ +-------------------+ +---------------+ | Request | | RequestItem | | Item | +------------------+ +-------------------+ +---------------+ | + Requester_Name | | + Request_No | | + Item | +------------------+ +-------------------+ +---------------+ | + Request_No | | + Item | +------------------+ +-------------------+ I would like to filter the items which are selected under a particular request number, along with a specific requester name. How might I go about doing this?

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  • Spring MVC, forward

    - by aauser
    Is there any difference between public class Controller1 extends AbstractController { @Override protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception { return new AnotherController().handleRequest(request, response); } } and @Controller public class Controller1 { @RequestMapping ... public String handleRequest() { return "forward:/path_to_my_another_controller"; } }

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  • Whats wrong with this ASP.NET rewrite?

    - by acidzombie24
    Actually its the mono version of asp.net, XSP. In my begin request function i check the url and rewrite when necessary. In one case i do context.RewritePath("~/App_Data/public" + path); When i try to request images or anything i get a 404 instead of the content. Why?

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  • DavCInt User Agent and Options Verb Requests

    - by beckelmw
    We are getting quite a few errors in our logs where the user agent is DavCInt and verb is OPTIONS. Does anyone know who/what might be making this type of request? We are using ASP.NET MVC and all of our controller actions are decorated with HttpGet or HttpPost as appropriate so a controller supporting the request is of course not found. I know I can deny verbs in the web.config but I am looking for any insight before I do so.

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  • Dynamically Delete inline formsets in Django

    - by BenMills
    Is it possible to have Django automatically delete formsets that are not present in the request? So for example if I had three inline formsets represented in HTML when I loaded my edit page and I use javascript to remove two of those when the request is processes Django sees that those two forms are no longer their and deletes them.

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  • How do you determine an acceptable response time for App Engine DB requests?

    - by qiq
    According to this discussion of Google App Engine on Hacker News, A DB (read) request takes over 100ms on the datastore. That's insane and unusable for about 90% of applications. How do you determine what is an acceptable response time for a DB read request? I have been using App Engine without noticing any issues with DB responsiveness. But, on the other hand, I'm not sure I would even know what to look for in that regard :)

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  • QueryString From Shared Function

    - by Kezzer
    I'm trying to get a query string from a shared function in a code-behind model using VB.NET. You have to use HttpContext.Current.Request.QueryString("Query") in order to get it from a shared function, however doing HttpContext.Current.Request.QueryString.Count gives back 0, which obviously isn't right in my case as there's many that exist. Is there some sort of issue with using this static call from a shared function?

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  • Does Flash comply with HTTP Location header?

    - by FRKT
    Hello, does Flash comply with HTTP Location headers? For example, if Flash makes a POST request to http://www.example.org/mail and it returns Location: http://www.example.org/mail/1.xml, will Flash return the data in in 1.xml upon completing the POST request?

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  • Getting 404 when attempting to POST file to Google Cloud Storage from service account

    - by klactose
    I'm wondering if anyone can tell me the proper syntax & formatting for a service account to send a POST Object to bucket request? I'm attempting it programmatically using the HttpComponents library. I manage to get a token from my GoogleCredential, but every time I construct the POST request, I get: HTTP/1.1 403 Forbidden <?xml version='1.0' encoding='UTF-8'?><Error><Code>AccessDenied</Code><Message>Access denied.</Message><Detailsbucket-name</Details></Error The Google documentation that describes the request methods, mentions posting using html forms, but I'm hoping that wasn't suggesting the ONLY way to get the job done. I know that HttpComponents has a way to explicitly create form data by using UrlEncodedFormEntity, but it doesn't support multipart data. Which is why I went with using the MultipartEntity class. My code is below: MultipartEntity entity = new MultipartEntity( HttpMultipartMode.BROWSER_COMPATIBLE ); String token = credential.getAccessToken(); entity.addPart("Authorization", new StringBody("OAuth " + token)); String date = formatDate(new Date()); entity.addPart("Date", new StringBody(date)); entity.addPart("Content-Encoding", new StringBody("UTF-8")); entity.addPart("Content-Type", new StringBody("multipart/form-data")); entity.addPart("bucket", new StringBody(bucket)); entity.addPart("key", new StringBody("fileName")); entity.addPart("success_action_redirect", new StringBody("/storage")); File uploadFile = new File("pathToFile"); FileBody fileBody = new FileBody(uploadFile, "text/xml"); entity.addPart("file", fileBody); httppost.setEntity(entity); System.out.println("Posting URI = "+httppost.toString()); HttpResponse response = client.execute(httppost); HttpEntity resp_entity = response.getEntity(); As I mentioned, I am able to get an actual token, so I'm pretty sure the problem is in how I've formed the request as opposed to not being properly authenticated. Keep in mind: This is being performed by a service account. Which means that it does have Read/Write access Thanks for reading, and I appreciate any help!

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  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

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  • When does a PHP script end?

    - by allyourcode
    In my mind, a web app something that runs continuously; therefore, I'm confused by documentation pages that talk about the "end" of a PHP script (eg this one). Such references seem to refer to the end of each web request, but if the script ends there, doesn't that mean that the OS has to setup a whole new process for each request? That seems unlikely, because spinning up a whole new process is expensive, and be very inefficient for the whole site.

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  • Search functionality in a lightbox

    - by Salil
    Hi All, I have a page on which there is a link search. onclicking search i open a LIGHTBOX where i get a textfield and Search button. Now i want when i enter keyword in textfield and enter on submit button a result should be shown in a lighbox only. is it possible w/o ajax or i have to use ajax form only. just curious why we used get request instead of post request for Search functionality.

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