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  • Shortest distance between a point and a line segment

    - by Eli Courtwright
    I need a basic function to find the shortest distance between a point and a line segment. Feel free to write the solution in any language you want; I can translate it into what I'm using (Javascript). EDIT: My line segment is defined by two endpoints. So my line segment AB is defined by the two points A (x1,y1) and B (x2,y2). I'm trying to find the distance between this line segment and a point C (x3,y3). My geometry skills are rusty, so the examples I've seen are confusing, I'm sorry to admit.

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  • FFmpeg bitrate issue.

    - by user329840
    I'm dealing with a very big issue about bit rate , ffmpeg provide the -b option for the bit rate and for adjustment it provide -minrate and -maxrate, -bufsize but it don't work proper. If i'm giving 256kbps at -b option , when the trans-coding finishes , it provide the 380kbps. How can we achieve the constant bit rate using ffmpeg. If their is +-10Kb it's adjustable. but the video bit rate always exceed by 50-100 kbps. I'm using following command ffmpeg -i "demo.avs" -vcodec libx264 -s 320x240 -aspect 4:3 -r 15 -b 256kb \ -minrate 200kb -maxrate 280kb -bufsize 256kb -acodec libmp3lame -ac 2 \ -ar 22050 -ab 64kb -y "output.mp4" When trans-coding is done, the Media Info show overall bit rate 440kb (it should be 320kb). Is their something wrong in the command. Or i have to use some other parameter? Plz provide your suggestion its very important.

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  • Python: Get items at depth? (set library?)

    - by Mark
    I have a nested list something like this: PLACES = ( ('CA', 'Canada', ( ('AB', 'Alberta'), ('BC', 'British Columbia' ( ('van', 'Vancouver'), ), ... )), ('US', 'United States', ( ('AL', 'Alabama'), ('AK', 'Alaska'), ... I need to retrieve some data out of it. If depth is 0 I need to retrieve all the countries (and their codes), if depth == 1, I need to retrieve all the states/provinces, if depth == 2 I need to retrieve all the cities... and so forth. Is there some set library for doing stuff like this? Or can someone point me in the right direction? I started coding up a solution only to realize it wouldn't work for levels deeper than 1 because you have to go in and out of each list...

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  • how can i convert a video into image files using ffmpeg in c#?

    - by moon
    string inputpath = strFileNamePath; string outputpath = "C:\\Image\\"; //for (int iIndex = 0; iIndex < 1000; iIndex++) //{ //string fileargs = "-i" + " " + inputpath + " -ab 56 -ar 44100 -b 200 -r 15 -s 320x240 -f flv " + outputpath + "SRT.flv"; string fileargs = "-i" + " " + inputpath + " " + outputpath + "image.jpg"; System.Diagnostics.Process p = new System.Diagnostics.Process(); p.StartInfo.FileName = "C:\\Documents and Settings\\Badr\\My Documents\\Visual Studio 2008\\Projects\\Video2image2video.\\ffmpeg\\ffmpeg.exe"; p.StartInfo.Arguments = fileargs; p.StartInfo.UseShellExecute = false; p.StartInfo.CreateNoWindow = true; p.StartInfo.RedirectStandardOutput = true; p.Start(); i have this code this creates only 1 image of video i apply a loop but i repeatedly generates the initial image how can i get images of all the video thanx in advance

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  • How to best convert Flash compatible mp4 files with FFMPEG

    - by Espen Christensen
    I am trying to convert different files to a flash compatible .mp4 file with ffmpeg, but i cant seem to succeed. Off cource the objective is to get the greatest quality with the smallest filesize. So far I have this, that works but it doesnt play in a flash player of some reason, and the result isnt that great, anybody got any tips on how to improve this conversion? ffmpeg -i input.file -f mp4 -vcodec mpeg4 -r 25 -b 560000 -s 610x340 -acodec aac -ac 2 -ab 64 -ar 44100 output.file Would be great the se other peoples experiences with this type of conversion.

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  • How does one avoid "Value restriction" errors with F#'s Seq.cast?

    - by gatoatigrado
    I see that Seq has a cast function from IEnumerable to Seq, but how do I get it to work? open System.Text.RegularExpressions;; let v = Regex.Match("abcd", "(ab)");; Seq.cast (v.Captures);; This produces, error FS0030: Value restriction. The value 'it' has been inferred to have generic type val it : seq<'_a Either define 'it' as a simple data term, make it a function with explicit arguments or, if you do not intend for it to be generic, add a type annotation.

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  • How one can apply Hindi Matras(Vowels) on Roman letters?

    - by stacker
    How one can apply Hindi Matras(Vowels) on Roman letters? These Hindi Vowels work well on Roman letters on I-Phone by flipping Hindi and Roman keyboard. Is there any keyboard for this type of application? For Example: open facility ??? ???????? o?pn f??c?lt? ..........How one can Merge these dotted circles with Roman letters? This merging works on I-phone using Hindi/English keyboard. http://translate.google.com/#hi/en/open%20facility%0A%E0%A4%93%E0%A4%AA%E0%A4%A8%20%E0%A4%AB%E0%A5%88%E0%A4%B8%E0%A4%BF%E0%A4%B2%E0%A4%BF%E0%A4%9F%E0%A5%80%0Ao%E0%A5%8Bpn%20f%E0%A5%88%E0%A4%BFc%E0%A4%BFlt%E0%A5%80

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  • Algorithm for Determining Variations of Differing Lengths

    - by joseph.ferris
    I have four objects - for the sake of arguments, let say that they are the following letters: A B C D I need to calculate the number of variations that can be made for these under the following two conditions: No repetition Objects are position agnostic Taking the above, this means that with a four object sequence, I can have only one sequence that matches the criteria (since order is not considered for being unique): ABCD There are four variations for a three object combination from the four object pool: ABC, ABD, ACD, and BCD There are six variations for a two object combination from the four object pool: AB, AC, AD, BC, BD, and CD And the most simple one, if taken on at a time: A, B, C, and D I swear that this was something covered in school, many, many years ago - and probably forgotten since I didn't think I would use it. :-) I am anticipating that factorials will come into play, but just trying to force an equation is not working. Any advice would be appreciated.

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  • LDAP "Insufficient Access"

    - by mon4goos
    I am trying to create an LDAP filter string. In each LDAP entry there is an attribute called "status" that has many values, some of which are of the regex form "[ab][0-9][1-9]". For example, "a20" or "b81". All other values for the "status" attribute are just alphabetical characters. I only want to let through entries that have a "status" value of the first form. When I construct an LDAP filter such as (status=a*) I get an "Insufficient Access" error. However, if I change the query to (status=a1*) that works fine. Is there any reason for this? If there behavior is unavoidable, can anyone thing of a way to get only the entries I want.

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  • Shortest distance between a point and a line segment

    - by Eli Courtwright
    I need a basic function to find the shortest distance between a point and a line segment. Feel free to write the solution in any language you want; I can translate it into what I'm using (Javascript). EDIT: My line segment is defined by two endpoints. So my line segment AB is defined by the two points A (x1,y1) and B (x2,y2). I'm trying to find the distance between this line segment and a point C (x3,y3). My geometry skills are rusty, so the examples I've seen are confusing, I'm sorry to admit.

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  • File in binary form

    - by Abhi
    Dear All I want to write data into the file in binary form. I was trying using the mentioned below FILE *fp = fopen("binaryoutput.rgb888", "ab+"); for(int m=0; m<height; m++) { for (int n=0; n< width; n++) { temp = (pOutputImg+m*3+n*3); // here temp is a pointer to a unsigned char fprintf(fp,"%u",*temp); } } fclose(fp); I am able to get data which is strored at pOutputImg but not in binary form. Can anyone guide me the correct step.. Thanks in advance

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  • Shortest distance between two line segments

    - by Frank
    I need a function to find the shortest distance between two line segments. A line segment is defined by two endpoints. So for example one of my line segments (AB) would be defined by the two points A (x1,y1) and B (x2,y2) and the other (CD) would be defined by the two points C (x1,y1) and D (x2,y2). Feel free to write the solution in any language you want and I can translate it into javascript. Please keep in mind my geometry skills are pretty rusty. I have already seen http://stochastix.wordpress.com/2008/12/28/distance-between-two-lines/ and I am not sure how to translate this into a function. Thank you so much for help.

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  • How do I Benchmark RESTful Service with Variable Parameters?

    - by Eli
    I'm currently working on benchmarking a RESTful service I've made, and part of that is making sure it runs in a reasonable amount of times for a large array of parameters. For example, let's say I have RESTful API of the form some_site.com/item?item_id=y. In that case to be sure my service is working as fast as I'd like it to work, I'd want to try out many values for y one by one, preferably coming from some text file. I can't figure out any way of doing this in ab or httperf. I'm open to using a different benchmarking program if I have, but would prefer something simple and light. What I want to do seems like something pretty standard, so I'm guessing there must already be a program that let's me do it, but an hour or so of googling hasn't gotten me an answer. Ideas?

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  • Retrieving data from an encrypted text file?

    - by user
    Let's say I have a text file contains my data. data : ab bc de - encrypted data on text file : ba cb ed I want to find bc from text file, so I have to decrypt the text file with this code : SL:=TStringList.create; SL.LoadFromFile(textfile) SLtemp:=TStringList.create; for I := 0 to SL.Count - 1 do SLtemp.Add(ReverseString(SL[i])); //decrypt SL.Free; for I := 0 to SLtemp.Count - 1 do if SLtemp[i] = 'bc' then begin showmessage('found'); break; end; SLtemp.Free; I think my way is wasting resources. I have to load whole file to memory and decrypt them. I need some suggestions here to find quickly a specific line from an encrypted text. Thanks.

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  • c++ to vb.net , problem with callback function

    - by johan
    I'm having a hard time here trying to find a solution for my problem. I'm trying to convert a client API funktion from C++ to VB.NET, and i think have some problems with the callback function. parts of the C++ code: typedef struct{ BYTE m_bRemoteChannel; BYTE m_bSendMode; BYTE m_nImgFormat; // =0 cif ; = 1 qcif char *m_sIPAddress; char *m_sUserName; char *m_sUserPassword; BOOL m_bUserCheck; HWND m_hShowVideo; }CLIENT_VIDEOINFO, *PCLIENT_VIDEOINFO; CPLAYER_API LONG __stdcall MP4_ClientStart(PCLIENT_VIDEOINFO pClientinfo,void(CALLBACK *ReadDataCallBack)(DWORD nPort,UCHAR *pPacketBuffer,DWORD nPacketSize)); void CALLBACK ReadDataCallBack(DWORD nPort,UCHAR *pPacketBuffer,DWORD nPacketSize) { TRACE("%d\n",nPacketSize); } ..... aa5.m_sUserName = "123"; aa5.m_sUserPassword="w"; aa5.m_bUserCheck = TRUE; MP4_ClientSetTTL(64); nn1 = MP4_ClientStart(&aa5,ReadDataCallBack); if (nn1 == -1) { MessageBox("error"); return; } SDK description: MP4_ClientStart This function starts a connection. The format of the call is: LONG __stdcall MP4_ClientStart(PCLIENT_VIDEOINFO pClientinfo, void(*ReadDataCallBack)(DWORD nChannel,UCHAR *pPacketBuffer,DWORD nPacketSize)) Parameters pClientinfo holds the information. of this connection. nChannel holds the channel of card. pPacketBuffer holds the pointer to the receive buffer. nPacketSize holds the length of the receive buffer. Return Values If the function succeeds the return value is the context of this connection. If the function fails the return value is -1. Remarks typedef struct{ BYTE m_bRemoteChannel; BYTE m_bSendMode; BYTE m_bImgFormat; char *m_sIPAddress; char *m_sUserName; char *m_sUserPassword; BOOL m_bUserCheck; HWND m_hShowVideo; } CLIENT_VIDEOINFO, * PCLIENT_VIDEOINFO; m_bRemoteChannel holds the channel which the client wants to connect to. m_bSendMode holds the network mode of the connection. m_bImgFormat : Image format, 0 is main channel video, 1 is sub channel video m_sIPAddress holds the IP address of the server. m_sUserName holds the user’s name. m_sUserPassword holds the user’s password. m_bUserCheck holds the value whether sends the user’s name and password or not. m_hShowVideo holds Handle for this video window. If m_hShowVideo holds NULL, the client can be record only without decoder. If m_bUserCheck is FALSE, we will send m_sUserName and m_sUserPassword as NULL, else we will send each 50 bytes. The length of m_sIPAddress and m_sUserName must be more than 50 bytes. ReadDataCallBack: When the library receives a packet from a server, this callback is called. My VB.Net code: Imports System.Runtime.InteropServices Public Class Form1 Const WM_USER = &H400 Public Structure CLIENT_VIDEOINFO Public m_bRemoteChannel As Byte Public m_bSendMode As Byte Public m_bImgFormat As Byte Public m_sIPAddress As String Public m_sUserName As String Public m_sUserPassword As String Public m_bUserCheck As Boolean Public m_hShowVideo As Long 'hWnd End Structure Public Declare Function MP4_ClientSetNetPort Lib "hikclient.dll" (ByVal dServerPort As Integer, ByVal dClientPort As Integer) As Boolean Public Declare Function MP4_ClientStartup Lib "hikclient.dll" (ByVal nMessage As UInteger, ByVal hWnd As System.IntPtr) As Boolean <DllImport("hikclient.dll")> Public Shared Function MP4_ClientStart(ByVal Clientinfo As CLIENT_VIDEOINFO, ByRef ReadDataCallBack As CALLBACKdel) As Long End Function Public Delegate Sub CALLBACKdel(ByVal nPort As Long, <MarshalAs(UnmanagedType.LPArray)> ByRef pPacketBuffer As Byte(), ByVal nPacketSize As Long) Public Sub CALLBACK(ByVal nPort As Long, <MarshalAs(UnmanagedType.LPArray)> ByRef pPacketBuffer As Byte(), ByVal nPacketSize As Long) End Sub Public mydel As New CALLBACKdel(AddressOf CALLBACK) Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim Clientinfo As New CLIENT_VIDEOINFO() Clientinfo.m_bRemoteChannel = 0 Clientinfo.m_bSendMode = 0 Clientinfo.m_bImgFormat = 0 Clientinfo.m_sIPAddress = "193.168.1.100" Clientinfo.m_sUserName = "1" Clientinfo.m_sUserPassword = "a" Clientinfo.m_bUserCheck = False Clientinfo.m_hShowVideo = Me.Handle 'Nothing MP4_ClientSetNetPort(850, 850) MP4_ClientStartup(WM_USER + 1, Me.Handle) MP4_ClientStart(Clientinfo, mydel) End Sub End Class here is some other examples of the code in: C# http://blog.csdn.net/nenith1981/archive/2007/09/17/1787692.aspx VB ://read.pudn.com/downloads70/sourcecode/graph/250633/MD%E5%AE%A2%E6%88%B7%E7%AB%AF%28VB%29/hikclient.bas__.htm ://read.pudn.com/downloads70/sourcecode/graph/250633/MD%E5%AE%A2%E6%88%B7%E7%AB%AF%28VB%29/Form1.frm__.htm Delphi ://read.pudn.com/downloads91/sourcecode/multimedia/streaming/349759/Delphi_client/Unit1.pas__.htm

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  • A general declaration for all inherited classes

    - by Soham
    Consider, there is a class called SuperClass from which, ClassA, ClassB, ClassC is derived. From each one of those derived Classes, there are further more two classes are derived each called ChildClassAA and ChildClassAB[AB stands for Bth Child class from the Ath Class.Lets not really pull our hair on this nomenclature]. Now, ideally, I want to declare a general type as a private member of another Class say IndependentClass which can be initialized during run time as either of the objects of type ClassAor ClassB or ClassC and even the derived classes like ClassAA or ClassAB. Is there a possible way to do it?

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  • Badword filter in PHP?

    - by morpheous
    I am writing a badword filter in PHP. I have a list of badwords in an array and the method cleanse_text() is written like this: public static function cleanse_text($originalstring){ if (!self::$is_sorted) self::doSort(); return str_ireplace(self::$badwords, '****', $originalstring); } This works trivially, for exact matches, but I wanted to also censor words that have been disguised like 'ab*d' where 'abcd' is a bad word. This is proving to be a bit more difficult. Here are my questions: Is a badword filter worth bothering with (it is a site for professionals so a certain minimum decorum is required - I would have thought) Is it worth the hustle of trying to capture obvious work arounds like 'f*ck' - or should I not attempt to filter those out. Is there a better way of writing the cleanse_text() method above?

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  • How to insert complex strings into Actionscript?

    - by Ole Jak
    How to insert complex strings into Actionscript? So I have a string -vvv -I rc w:// v dv s="60x40" --ut="#scode{vcode=FV1,acode=p3,ab=128,ch=2,rate=4400}:dup{dt=st{ac=http{mime=v/x-flv},mux=mpeg{v},dt=:80/sm.fv}}" How to insert it into code like public var SuperPuperComplexString:String = new String(); SuperPuperComplexString = TO_THAT_COMPLEX_STRING; That string has so many problems like some cart of it can happen to be like regexp BUTI DO NOT want it to be parsed as any kind of reg exp - I need It AS IT IS!) How to put that strange string into variable (put it not inputing it thru UI - hardcode it into AS code)?

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  • Bit/Byte adressing - Little/Big-endnian

    - by code8230
    Consider the 16-Bit data packet below, which is sent through the network in network byte order ie Big Endian: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 (Byte num) 34 67 89 45 90 AB FF 23 65 37 56 C6 56 B7 00 00 (Value) Lets say 8945 is a 16 bit value. All others are 8 bit data bytes. On my system, which is little endian, how would the data be received and stored? Lets say, we are configured to receive 8 bytes at a time. RxBuff is the Rx buffer where data will be received. Buff is the storage buffer where data would be stored. Please point out which case is correct for data storage after reading 8 bytes at a time: 1) Buff[] = {0x34, 0x67, 0x45, 0x89, 0x90, 0xAB....... 0x00}; 2) Buff[] = {0x00, 0x00, .......0x67, 0x89, 0x45, 0x34}; Would the whole 16 bytes data be reversed or only the 2 bytes value contained in this packet?

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  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

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  • Future of Active FoxPro Pages - secured

    Finally some official news about Active FoxPro Pages, aka AFP. The German company BvL Bürosysteme Vertriebs GmbH bought all rights of Active FoxPro Pages from the insolvency stock. Being a former customer and intensive user of AFP since version 2.0 BvL has own interest in the continuation of AFP on current and future web servers. Together with their partners Christof Wollenhaupt (Foxpert Software Development & Consulting) and Jochen Kirstätter (IOS Indian Ocean Software Ltd) BvL will continue with development, support and marketing of AFP in the upcoming weeks. There will be an updated version of AFP, the relaunch of the website, re-enabling of activation server, re-establishment of support channel, and much more... Personally, I am relieved that this superb product made its way out of the dust of the past years. And of course, to be involved (again) in the development and support of Active FoxPro Pages gives me a big smile. Rest assured that there will be more articles on AFP soon! Here is the original announcement of 27th September 2010 from the online forum of German FoxPro Usergroup (dFPUG) - section Active FoxPro Pages: Liebe AFP Anwender, liebe FoxPro Gemeinde, nach den Insolvenzen der ProLib Software GmbH und der ProLib Tools GmbH gab es einige Verunsicherung über die Zukunft der Active FoxPro Pages. Wir können euch nun mitteilen, dass eine für alle Beteiligten positive Lösung gefunden wurde. Wir, die BvL Bürosysteme Vertriebs GmbH aus Berlin, haben sämtliche Rechte an der AFP aus der Insolvenzmasse vom Insolvenzverwalter abgekauft. Bereits 1987 wurde die BvL Bürosysteme Vertriebs GmbH gegründet und hat sich seit dem erfolgreich im Markt bewährt. Wir gehören auch schon seit Foxpro2.0 zur Foxpro-Gemeinde und auch mit der AFP2.0 haben wir unseren Einstieg in die AFP-Gemeinde vollzogen. Wir wollen die AFP nicht in irgendeine Schublade packen, sondern unser Ziel ist es, die AFP weiterzuentwickeln, speziell auch auf die kommenden Serverversionen. Unter der Homepage www.active-foxpro-pages.de wird es demnächst einen neuen Auftritt geben. An den Preisen soll sich nichts groß verändern, das Handbuch soll anständig aufgelegt werden und selbstverständlich soll der Support und die Weiterentwicklung eine große Aufmerksamkeit bekommen. Mit Christof Wollenhaupt und Jochen Kirstätter haben wir zwei Partner an Bord, die sich um den Support und die Weiterentwicklung kümmern werden. Christof Wollenhaupt wird maßgeblich und federführend an der Weiterentwicklung beteiligt sein. Über Christof Wollenhaupt können auch ab sofort Lizenzen gekauft werden, Christof Wollenhaupt ist für den Online-Vertrieb zuständig, der gerade aufgebaut wird. Sollte ein AFP Server aktiviert werden müssen, können sich alle bisherigen Lizenzinhaber auch direkt an Christof Wollenhaupt wenden. In den nächsten Wochen werden wir die AFP wieder auf Touren bringen. Eine aktuelle Version, eine neue Webseite, der Aktivierungsserver, ein Überblick über das leicht geänderte Lizensierungsmodell, und vieles mehr ist gerade in Arbeit. Die Zukunft und die Weiterentwicklung der AFP sind jetzt gesichert! Mit freundlichen Grüßen Ralph-Norman von Loesch Source: http://forum.dfpug.de/bodyframe.afp?msgid=728069

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  • Measure load of ubuntu server

    - by user84471
    I have Ubuntu server and apache2 installed on it. I want to benchmark it using ab tool from another machine. I want to know how measure load of this program. In top is showing this: top - 06:02:19 up 3 min, 2 users, load average: 0.28, 0.26, 0.12 Tasks: 94 total, 2 running, 92 sleeping, 0 stopped, 0 zombie Cpu(s): 67.2%us, 5.5%sy, 0.0%ni, 26.3%id, 0.5%wa, 0.0%hi, 0.5%si, 0.0%st Mem: 499320k total, 342028k used, 157292k free, 42504k buffers Swap: 514044k total, 0k used, 514044k free, 71388k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1521 www-data 20 0 49180 22m 4144 S 23 4.6 0:00.68 apache2 1520 www-data 20 0 49180 22m 4152 S 22 4.6 0:00.66 apache2 1124 www-data 20 0 49180 22m 4152 S 22 4.6 0:00.70 apache2 1519 www-data 20 0 49180 22m 4152 S 20 4.6 0:00.70 apache2 1525 www-data 20 0 49180 22m 4144 S 16 4.6 0:00.47 apache2 1123 www-data 20 0 49168 22m 4152 S 9 4.6 0:00.78 apache2 1125 www-data 20 0 49168 22m 4152 S 9 4.6 0:00.77 apache2 1126 www-data 20 0 49168 22m 4152 S 9 4.6 0:00.73 apache2 1127 www-data 20 0 49168 22m 4152 S 9 4.6 0:00.74 apache2 1523 www-data 20 0 42896 14m 3388 R 5 3.1 0:00.14 apache2 1038 whoopsie 20 0 24476 3720 2856 S 0 0.7 0:00.01 whoopsie 1089 root 20 0 34060 6988 3640 S 0 1.4 0:00.05 apache2 1338 ubuntu 20 0 2832 1192 944 S 0 0.2 0:00.30 top 1417 ubuntu 20 0 9652 1456 824 S 0 0.3 0:00.02 sshd 1 root 20 0 3540 1876 1248 S 0 0.4 0:00.83 init 2 root 20 0 0 0 0 S 0 0.0 0:00.00 kthreadd 3 root 20 0 0 0 0 S 0 0.0 0:00.03 ksoftirqd/0 4 root 20 0 0 0 0 S 0 0.0 0:00.00 kworker/0:0 5 root 20 0 0 0 0 S 0 0.0 0:00.48 kworker/u:0 6 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/0 7 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/0 8 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/1 9 root 20 0 0 0 0 S 0 0.0 0:00.00 kworker/1:0 10 root 20 0 0 0 0 S 0 0.0 0:00.01 ksoftirqd/1 11 root 20 0 0 0 0 S 0 0.0 0:00.17 kworker/0:1 12 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/1 13 root 0 -20 0 0 0 S 0 0.0 0:00.00 cpuset 14 root 0 -20 0 0 0 S 0 0.0 0:00.00 khelper 15 root 20 0 0 0 0 S 0 0.0 0:00.00 kdevtmpfs 16 root 0 -20 0 0 0 S 0 0.0 0:00.00 netns 17 root 20 0 0 0 0 S 0 0.0 0:00.32 kworker/u:1 18 root 20 0 0 0 0 S 0 0.0 0:00.00 sync_supers 19 root 20 0 0 0 0 S 0 0.0 0:00.00 bdi-default 20 root 0 -20 0 0 0 S 0 0.0 0:00.00 kintegrityd 21 root 0 -20 0 0 0 S 0 0.0 0:00.00 kblockd 22 root 0 -20 0 0 0 S 0 0.0 0:00.00 ata_sff 23 root 20 0 0 0 0 S 0 0.0 0:00.00 khubd So its difficult to do it without any script or program. How can I do this?

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  • Einladung zum Oracle Partner Day 2012

    - by A&C Redaktion
    EINLADUNG: ORACLE PARTNER DAY GERMANY - 29. Oktober 2012: COMMERZBANK ARENA, Frankfurt Sehr geehrter Oracle Partner, volle Kraft voraus! Unsere Neuausrichtung und Zusammenfassung der Ressourcen, die Sie sicherlich aufmerksam verfolgt haben, ist nun abgeschlossen. Wir sind sehr überzeugt davon, dass wir alle gemeinsam von diesen Veränderungen nachhaltig profitieren werden. Nur ein Stichwort dazu: „One Oracle Red Stack“. Oracle Alliances & Channels und seine Partner können ab sofort das komplette Oracle Produktportfolio bestehend aus Oracle Software Technology, Oracle Applications und Oracle Hardware anbieten – bei bestmöglichem Support aus unserer neuen Organisation. Mein Name ist Christian Werner. Ich bin seit einigen Wochen verantwortlich für alle Alliances & Channels Bereiche in Deutschland. Frau Silvia Kaske leitet jetzt den kompletten A&C Bereich in Europe North in der Funktion als Senior Director Europe North Alliances & Channel Sales. Willkommen an Bord! Was Sie als Oracle Partner davon erwarten können? Wir haben alle unsere Kräfte konzentriert. Aus drei eigenen Bereichen wird ein großes Ganzes. Für Sie bedeutet das: fokussiertes Wachstum, geballte Kompetenz und Supportinfrastruktur. Abgestimmte Prozesse und kürzere Zeiten für Approvals. Wir meinen: Die Zeit ist reif, um jetzt gemeinsam den Hebel auf „Volle Kraft voraus“ zu legen. Und die Bedingungen für Sie sind besser als jemals zuvor, wenn Sie Ihre Kundenbasis erweitern oder neue Marktbereiche erschließen wollen. Leinen los: Kommen Sie zum Oracle Partner Day, wenn Sie wissen wollen, was sich für Sie verbessern wird: am 29. Oktober 2012 in der Commerzbank Arena in Frankfurt. Treffen Sie Ihr neu aufgestelltes A&C-Team. Erleben Sie die Produktneuheiten von der Oracle Open World in San Francisco (30. September bis 4. Oktober 2012) aus erster Hand. Nutzen Sie das neue Speed Dating-Format mit ausgewählten Oracle Experten vor Ort – für konkrete Fragen zu Vertrieb und Produkten. Ganz besonders freue ich mich, dass dieses Jahr Jürgen Kunz, SVP Technology Northern Europe & Country Leader Germany, als Keynote Speaker dabei sein wird. Ich lade Sie ganz herzlich ein und freue mich, Sie in Frankfurt zu begrüßen! Die Teilnahme ist für Sie als Oracle Partner selbstverständlich kostenfrei. Hier finden Sie weitere Informationen zum Oracle Partner Day sowie die unkomplizierte Anmeldemöglichkeit. Ich freue mich auf Sie! Ihr Christian WernerSenior Director Alliances & Channels Germany Übrigens: Direkt nach dem Oracle Partner Day findet der Oracle Day für Endkunden statt. Sie als Partner können natürlich gemeinsam mit Ihren Kunden an dieser Veranstaltung teilnehmen. Bitte melden Sie sich schnell an, da die Plätze limitiert sind. Hier finden Sie weitere Infos zum Oracle Day.

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  • Einladung zum Oracle Partner Day 2012

    - by A&C Redaktion
    EINLADUNG: ORACLE PARTNER DAY GERMANY - 29. Oktober 2012: COMMERZBANK ARENA, Frankfurt Sehr geehrter Oracle Partner, volle Kraft voraus! Unsere Neuausrichtung und Zusammenfassung der Ressourcen, die Sie sicherlich aufmerksam verfolgt haben, ist nun abgeschlossen. Wir sind sehr überzeugt davon, dass wir alle gemeinsam von diesen Veränderungen nachhaltig profitieren werden. Nur ein Stichwort dazu: „One Oracle Red Stack“. Oracle Alliances & Channels und seine Partner können ab sofort das komplette Oracle Produktportfolio bestehend aus Oracle Software Technology, Oracle Applications und Oracle Hardware anbieten – bei bestmöglichem Support aus unserer neuen Organisation. Mein Name ist Christian Werner. Ich bin seit einigen Wochen verantwortlich für alle Alliances & Channels Bereiche in Deutschland. Frau Silvia Kaske leitet jetzt den kompletten A&C Bereich in Europe North in der Funktion als Senior Director Europe North Alliances & Channel Sales. Willkommen an Bord! Was Sie als Oracle Partner davon erwarten können? Wir haben alle unsere Kräfte konzentriert. Aus drei eigenen Bereichen wird ein großes Ganzes. Für Sie bedeutet das: fokussiertes Wachstum, geballte Kompetenz und Supportinfrastruktur. Abgestimmte Prozesse und kürzere Zeiten für Approvals. Wir meinen: Die Zeit ist reif, um jetzt gemeinsam den Hebel auf „Volle Kraft voraus“ zu legen. Und die Bedingungen für Sie sind besser als jemals zuvor, wenn Sie Ihre Kundenbasis erweitern oder neue Marktbereiche erschließen wollen. Leinen los: Kommen Sie zum Oracle Partner Day, wenn Sie wissen wollen, was sich für Sie verbessern wird: am 29. Oktober 2012 in der Commerzbank Arena in Frankfurt. Treffen Sie Ihr neu aufgestelltes A&C-Team. Erleben Sie die Produktneuheiten von der Oracle Open World in San Francisco (30. September bis 4. Oktober 2012) aus erster Hand. Nutzen Sie das neue Speed Dating-Format mit ausgewählten Oracle Experten vor Ort – für konkrete Fragen zu Vertrieb und Produkten. Ganz besonders freue ich mich, dass dieses Jahr Jürgen Kunz, SVP Technology Northern Europe & Country Leader Germany, als Keynote Speaker dabei sein wird. Ich lade Sie ganz herzlich ein und freue mich, Sie in Frankfurt zu begrüßen! Die Teilnahme ist für Sie als Oracle Partner selbstverständlich kostenfrei. Hier finden Sie weitere Informationen zum Oracle Partner Day sowie die unkomplizierte Anmeldemöglichkeit. Ich freue mich auf Sie! Ihr Christian WernerSenior Director Alliances & Channels Germany Übrigens: Direkt nach dem Oracle Partner Day findet der Oracle Day für Endkunden statt. Sie als Partner können natürlich gemeinsam mit Ihren Kunden an dieser Veranstaltung teilnehmen. Bitte melden Sie sich schnell an, da die Plätze limitiert sind. Hier finden Sie weitere Infos zum Oracle Day.

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  • How do I install a 32-bit Java runtime on an amd64 server with multiarch?

    - by kbyrd
    I'm a long time Ubuntu user, but I haven't been following the community for the last several versions. I just did fresh default minimal amd64 install of Oneiric and I need a 32-bit JRE for a particular application. I last did this on 10.10, so I am not familiar with the multiarch stuff. Instead of installing ia32-libs, I read a bit and tried: aptitude install default-jre-headless:i386 But that just got me: The following NEW packages will be installed: default-jre-headless{b} openjdk-6-jre-headless{ab} The following packages are RECOMMENDED but will NOT be installed: icedtea-6-jre-cacao icedtea-6-jre-jamvm 0 packages upgraded, 2 newly installed, 0 to remove and 0 not upgraded. Need to get 27.3 MB of archives. After unpacking 82.1 MB will be used. The following packages have unmet dependencies: default-jre-headless: Depends: java-common which is a virtual package. openjdk-6-jre-headless: Depends: openjdk-6-jre-lib (>= 6b23~pre10-0ubuntu5) which is a virtual package. Depends: ca-certificates-java which is a virtual package. Depends: tzdata-java which is a virtual package. Depends: java-common (>= 0.28) which is a virtual package. Depends: libcups2 but it is not going to be installed. Depends: liblcms1 but it is not going to be installed. Depends: libjpeg62 but it is not going to be installed. Depends: libnss3-1d (>= 3.12.9+ckbi-1.82-0ubuntu4) but it is not going to be installed. Depends: libc6 (>= 2.11) but it is not going to be installed. Depends: libfreetype6 (>= 2.2.1) but it is not going to be installed. Depends: libgcc1 (>= 1:4.1.1) but it is not going to be installed. Depends: libstdc++6 (>= 4.1.1) but it is not going to be installed. Depends: zlib1g (>= 1:1.1.4) but it is not going to be installed. The following actions will resolve these dependencies: Keep the following packages at their current version: 1) default-jre-headless [Not Installed] 2) openjdk-6-jre-headless [Not Installed] Accept this solution? [Y/n/q/?] q Is aptitude not installing the 32-bit versions of the dependencies? What is the right way to do this? I'll likely want both a 64-bit and a 32-bit JRE if that matters.

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