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  • Strange declaration(templates). C++

    - by atch
    Hi, guys could anyone explain to my like to a not very inteligent child what is declared here: (this is taken from another post on this forum) template<typename C> static char (&f(ChT<int Fallback::*, &C::x>*))[1]; how I read it is: template of static function f called with (ChT*) but then I can't make sense why is there address of operator and why is there array? When explaining please picture not very inteligent child and then try to make it clear to it. Thanks for any help

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  • Problem with LINQ Where Clause

    - by Krishma
    var results = from formNumber in context.DetailTM join c in context.ClaimPeriodTM on formNumber.ClaimPeriod equals c.Cid where formNumber.FormNumber.StartsWith(fNumber) && formNumber.RegistrationNumber != registrationNumber select new { RegNo = formNumber.RegistrationNumber, CP = c.ClaimPeriod, FormNo = formNumber.FormNumber }; The AND CLAUSE with .STARTSWITH Doesn't work. If I use == operator the query works fine. I tried adding brackets to the where clause but it didn't help. Any idea what is missing. Thank you in Advance.

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  • ASP.Net check value with DBNULL

    - by c11ada
    hey all, i have the following code foreach (DataRowView dr in Data) { if (dr == System.DBNull.Value) { nedID = 1; } } but i get the following error Operator '==' cannot be applied to operands of type 'System.Data.DataRowView' and 'System.DBNull' please can some one advice me on how i can check if the value is null or DBNULL

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  • Different behavior of functors (copies, assignments) in VS2010 (compared with VS2005)

    - by Patrick
    When moving from VS2005 to VS2010 we noticed a performance decrease, which seemed to be caused by additional copies of a functor. The following code illustrates the problem. It is essential to have a map where the value itself is a set. On both the map and the set we defined a comparison functor (which is templated in the example). #include <iostream> #include <map> #include <set> class A { public: A(int i, char c) : m_i(i), m_c(c) { std::cout << "Construct object " << m_c << m_i << std::endl; } A(const A &a) : m_i(a.m_i), m_c(a.m_c) { std::cout << "Copy object " << m_c << m_i << std::endl; } ~A() { std::cout << "Destruct object " << m_c << m_i << std::endl; } void operator= (const A &a) { m_i = a.m_i; m_c = a.m_c; std::cout << "Assign object " << m_c << m_i << std::endl; } int m_i; char m_c; }; class B : public A { public: B(int i) : A(i, 'B') { } static const char s_c = 'B'; }; class C : public A { public: C(int i) : A(i, 'C') { } static const char s_c = 'C'; }; template <class X> class compareA { public: compareA() : m_i(999) { std::cout << "Construct functor " << X::s_c << m_i << std::endl; } compareA(const compareA &a) : m_i(a.m_i) { std::cout << "Copy functor " << X::s_c << m_i << std::endl; } ~compareA() { std::cout << "Destruct functor " << X::s_c << m_i << std::endl; } void operator= (const compareA &a) { m_i = a.m_i; std::cout << "Assign functor " << X::s_c << m_i << std::endl; } bool operator() (const X &x1, const X &x2) const { std::cout << "Comparing object " << x1.m_i << " with " << x2.m_i << std::endl; return x1.m_i < x2.m_i; } private: int m_i; }; typedef std::set<C, compareA<C> > SetTest; typedef std::map<B, SetTest, compareA<B> > MapTest; int main() { int i = 0; std::cout << "--- " << i++ << std::endl; MapTest mapTest; std::cout << "--- " << i++ << std::endl; SetTest &setTest = mapTest[0]; std::cout << "--- " << i++ << std::endl; } If I compile this code with VS2005 I get the following output: --- 0 Construct functor B999 Copy functor B999 Copy functor B999 Destruct functor B999 Destruct functor B999 --- 1 Construct object B0 Construct functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Destruct functor C999 Destruct object B0 Destruct functor C999 Destruct object B0 --- 2 If I compile this with VS2010, I get the following output: --- 0 Construct functor B999 Copy functor B999 Copy functor B999 Destruct functor B999 Destruct functor B999 --- 1 Construct object B0 Construct functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy functor C999 Assign functor C999 Assign functor C999 Destruct functor C999 Copy object B0 Copy functor C999 Copy functor C999 Copy functor C999 Destruct functor C999 Destruct functor C999 Copy functor C999 Assign functor C999 Assign functor C999 Destruct functor C999 Destruct functor C999 Destruct object B0 Destruct functor C999 Destruct object B0 --- 2 The output for the first statement (constructing the map) is identical. The output for the second statement (creating the first element in the map and getting a reference to it), is much bigger in the VS2010 case: Copy constructor of functor: 10 times vs 8 times Assignment of functor: 2 times vs. 0 times Destructor of functor: 10 times vs 8 times My questions are: Why does the STL copy a functor? Isn't it enough to construct it once for every instantiation of the set? Why is the functor constructed more in the VS2010 case than in the VS2005 case? (didn't check VS2008) And why is it assigned two times in VS2010 and not in VS2005? Are there any tricks to avoid the copy of functors? I saw a similar question at http://stackoverflow.com/questions/2216041/prevent-unnecessary-copies-of-c-functor-objects but I'm not sure that's the same question. Thanks in advance, Patrick

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  • deleting an object

    - by Nima
    Hi, First, when you want to free the memory assigned to an object in C++, which one is preferred? Explicitly calling deconstructor or using delete? Object* object = new Object(...); ... delete object; OR object->~Object(); Second, does the delete operator call the deconstructor implicitly? Thanks,

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  • MSIL inspection

    - by Frank Schwieterman
    I have some MSIL in byte format (result of reflection's GetMethodBody()) that I'd like to analyze a bit. I'd like to find all classes created with the new operator in the MSIL. Any ideas on how to do that programmatically?

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  • Reverse PInvoke and create a full unmanaged C# program

    - by Fire-Dragon-DoL
    I know this is a strange question but the idea is simple: I prefer C# syntax rather than C++: -Setters and getters directly inside a property -interfaces -foreach statement -possibility to declare an implicit cast operator other small things... What I really don't know is if is possible to import a c++ dll (expecially std libraries) in C# if I don't use any namespace (even System) The idea is just to write a program using everything that you will normally use in C++ (nothing from CLR so), even printf for example Thanks for any answer

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  • Objective-C Decimal to Base 16 Hex conversion

    - by JustinXXVII
    Does anyone have a code snippet or a class that will take a long long and turn it into a 16 byte Hex string? I'm looking to turn data like this long long decimalRepresentation = 1719886131591410351; and turn it into this //Base 16 Hex Output: 17DE435307A07300 The %x operator doesn't want to work for me NSLog(@"Hex: %x",decimalRepresentation); //console : "Hex: 7a072af" As you can see that's not even close. Any help is truly appreciated!

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  • Validate Boolean Query - java

    - by JavaUser
    hi, I need the java code snippet for the below logic: Following is a string and I need to validate the string based on the below condition : "100 or 200 and 345 not 550 " - Valid string "abc or 200 and 345 SAME ** 550 " - Not a Valid String 1 . the operands(eg 100,200 ..) should be positive numbers 2 . the operator should be and/or/not Thx

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  • Database model for saving random boolean expressions

    - by zarko.susnjar
    I have expressions like this: (cat OR cats OR kitten OR kitty) AND (dog OR dogs) NOT (pigeon OR firefly) Anyone having idea how to make tables to save those? Before I got request for usage of brackets, I limited usage of operators to avoid ambiguous situations. So only ANDs and NOTs or only ORs and saved those in this manner: operators id | name 1 | AND 2 | OR 3 | NOT keywords id | keyword 1 | cat 2 | dog 3 | firefly expressions id | operator | keywordId 1 | 0 | 1 1 | 1 | 2 1 | 3 | 3 which was: cat AND dog NOT firefly But now, I'm really puzzled...

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  • Defaults for null values

    - by OldFart
    Working on a Powershell script I had several places where I wanted A unless it was null, else B. Essentially the ?? operator in C#. I ended up writing the function shown below, but I can't help but think there is a built-in way to do this. Is there a better, built-in, way? function Get-ValueOrDefault() { foreach ($value in $args) { if ($value -ne $null) { return $value } } } I think this works better: function Get-ValueOrDefault() { $args | select -first 1 }

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  • Mysql bulk delete problem

    - by Nadir
    Hello, Anybody can help me with this mysql query: delete from generic__campaings_included where dealer_id not in ('2,3,4') and campaing_id = '1' When i execute this query i didnt get normal result. Exceot 2 (dealer_id) all rows deleted. How can i use "not in" with "and" operator? PS. Sorry for my english)

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  • Can't concatenate 2 arrays in PHP

    - by alex
    I've recently learned how to join 2 arrays using the + operator in PHP. But consider this code... $array = array('Item 1'); $array += array('Item 2'); var_dump($array); Output is array(1) { [0]= string(6) "Item 1" } Why does this not work? Skipping the shorthand and using $array = $array + array('Item 2') does not work either. Does it have something to do with the keys?

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  • utf-8 word boundary regex in javascript

    - by cherouvim
    In JavaScript: "ab abc cab ab ab".replace(/\bab\b/g, "AB"); correctly gives me: "AB abc cab AB AB" When I use utf-8 characters though: "aß aß? ?aß aß aß".replace(/\baß\b/g, "AB"); the word boundary operator doesn't seem to work: "aß aß? ?aß aß aß" Is there a solution to this?

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  • Fibonacci Code Golf

    - by Claudiu
    Generate the Fibonacci sequence in the fewest amount of characters possible. Any language is OK, except for one that you define with one operator, f, which prints the Fibonacci numbers. Starting point: 25 characters in Haskell: f=0:1:zipWith(+)f(tail f)

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