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  • SQL Server 2008: Getting Login failed for user "Domain\User". Failed to open the explicitly specified database [CLIENT: IP.ADD.RR.ESS]

    - by GodEater
    This is a very similar issue to " SQL Server 2008 login problem with ASP.NET application: Failed to open the explicitly specified database " which unfortunately seems to have gone unsolved. My issue here is subtly different. Firstly the account failing login is not 'NT AUTHORITY\NETWORK SERVICE' - it's an actual domain account. Secondly, there are two machines involved - I gathered from the first question it was a single machine running both the IIS and SQL instances. The application which is trying to connect to the database is an ASP.NET one running on another server (if that makes any different, I'm not sure it does.) The ConnectionString being used in the web.config for the application is : data source=MySQLServer;initial catalog=MyDatabase;integrated security=sspi; And the Application Pool is set to NetworkService for Identity. So - in the web app, I get the following error : Cannot open database "MyDatabase" requested by the login. The login failed. Login failed for user 'MyDomain\WebServerMachineName$' In the SQL Server logs I see : Login failed for user 'MyDomain\WebServerMachineName$'. Reason: Failed to open the explicitly specified database. [CLIENT: Web.Server.IP.Address] Running this bit of SQL against the database in question : USE [MyDatabase] GO SELECT SDP.name AS [User Name], SDP.type_desc AS [User Type], UPPER(SDPS.name) AS [Database Role] FROM sys.database_principals SDP INNER JOIN sys.database_role_members SDRM ON SDP.principal_id=SDRM.member_principal_id INNER JOIN sys.database_principals SDPS ON SDRM.role_principal_id = SDPS.principal_id Gets me this result : MyDomain\WebServerMachineName$ WINDOWS_USER DB_DDLADMIN MyDomain\WebServerMachineName$ WINDOWS_USER DB_DATAREADER MyDomain\WebServerMachineName$ WINDOWS_USER DB_DATAWRITER Which appears to me to indicate I've got the permissions right. Anyone have any idea why it's not working, or how I can narrow the issue down some more?

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  • gitolite mac don't add new user to authorized_keys

    - by crashbus
    I installed gitolite and every thing works fine for me as admin. But when I'd like to add add a new user the new user can't connect to the server. After I looked into the file authorized_keys I saw that the new user wasn't added to the file. During the commit of the new public-key I get some workings: WARNING: split conf not set, gl-conf present for 'gitolite-admin' Counting objects: 6, done. Delta compression using up to 8 threads. Compressing objects: 100% (4/4), done. Writing objects: 100% (4/4), 882 bytes, done. Total 4 (delta 1), reused 0 (delta 0) remote: WARNING: split conf not set, gl-conf present for 'gitolite-admin' remote: WARNING: ?? @staff christianwaldmann markwelch remote: sh: find: command not found remote: sh: find: command not found remote: sh: sort: command not found remote: sh: find: command not found remote: /usr/local/bin/triggers/post-compile/update-gitweb-access-list: line 26: cut: command not found remote: /usr/local/bin/triggers/post-compile/update-gitweb-access-list: line 23: grep: command not found remote: /usr/local/bin/triggers/post-compile/update-gitweb-access-list: line 26: sort: command not found remote: /usr/local/bin/triggers/post-compile/update-gitweb-access-list: line 26: sed: command not found remote: sh: find: command not found remote: sh: find: command not found How can I fix it that gitolite auto-add the new user to the authorized_keys.

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  • Start & shutdown as tomcat as non-root user

    - by user53864
    How to start, shutdown and restart tomcat as non-root user. I have tomcat5.x installed on ubuntu machine(usr/share/tomcat). The tomcat directory has full permissions. When I shutdown(/usr/share/tomcat/bin/shudown.sh) or startup(/usr/share/tomcat/startup.sh) tomcat as normal user, it starts & shuts down normally as if it is executed as root user but I could not access webpage even after starting tomcat as non-root user. user1@station2:/usr/share/tomcat/webapps$ ../bin/shutdown.sh Using CATALINA_BASE: /usr/share/tomcat Using CATALINA_HOME: /usr/share/tomcat Using CATALINA_TMPDIR: /usr/share/tomcat/temp Using JRE_HOME: /usr 4 Oct, 2010 6:41:11 PM org.apache.catalina.startup.Catalina stopServer SEVERE: Catalina.stop: java.net.ConnectException: Connection refused at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:310) at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:176) at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:163) at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:384) at java.net.Socket.connect(Socket.java:546) at java.net.Socket.connect(Socket.java:495) at java.net.Socket.<init>(Socket.java:392) at java.net.Socket.<init>(Socket.java:206) at org.apache.catalina.startup.Catalina.stopServer(Catalina.java:421) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at org.apache.catalina.startup.Bootstrap.stopServer(Bootstrap.java:337) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:415)

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  • UW-IMAP server, high load for one user

    - by Bruce Garlock
    We have been experiencing a very strange anomaly, with one specific user with our UW-IMAP server. We have about 75 users using the server, and one particular user, who is in about the middle as far as used storage keeps having issues with slow speed. Most of our users all use Thunderbird 2, or Thunderbird 3. Mostly 2, because of the performance issues we have had with 3. This user was on 3, and I downgraded him to 2. The performance has gotten better, but according to the imapd processes on the server, his username is using the most CPU % and CPU time. I've already done all the usual T/S'ing: Started profile from scratch, compacted folders, re-indexed, newer faster computer, etc.. Still, this users' imapd process is always using the most CPU on the server. For troubleshooting, we setup another user which has more usage, folders, etc.. than he does, but we don't see the users process taking up most of the CPU with the imapd process. So, it almost sounds like a particular email may be the culprit, but how can we find it, if thats the problem? This has been going on for a while, and he is a management person, so his patience is about to end. Does anyone have any ideas?

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  • Notify user of message arrival in another mailbox

    - by Tim Alexander
    This is very similar to this question but has a few differences. Basically we have a user dealing with a conflict of interest case. To separate the mail from prying eyes (and the draconian routing system we have in place) the user has been granted access to a second conflicts mailbox that is only accessible to him via OWA. This has worked fine for years but now the user would like a notification to be sent to him when a message arrives in his conflicts mailbox. Initially I thought an Outlook rule would work but of course the client is never logged in so the Outlook rules are never processed. This led me to think that an Exchange Transport rule might work but the only options I can see are to Forward or Copy the message to another user. this would bypass the conflicts setup. All I really need is a notification and not the actual message to be sent. Is this at all possible with Exchange 2007? Or if not is there any thirdparty addition or workaround that anyone has come across?

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  • C# MVC: User Password Reset Controller: Issues with email addresses as usernames

    - by 109221793
    Hi guys, I have written the code below for resetting users passwords (am using the aspnet membership api) in an C# MVC application, and tested successfully on a sample tutorial application (MVC Music Store). Skip to the end if you wish to read problem description first. InactiveUsers View (Partial View) <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<System.Web.Security.MembershipUserCollection>" %> <table class="normal" style="width: 100%; background-color: White;"> <tr> <th>User Name</th> <th>Last Activity date</th> <th>Locked Out</th> </tr> <%foreach (MembershipUser user in Model){ %> <tr> <td><%: Html.RouteLink(user.UserName, "AdminPassword", new { username = user.UserName }) %></td> <td><%: user.LastActivityDate %></td> <td><%: user.IsLockedOut %></td> </tr> <% }%> </table> InactiveUsers Controller public ActionResult InactiveUsers() { var users = Membership.GetAllUsers(); return View(users); } changeUserPassword GET and POST Controllers public ActionResult changeUserPassword(string username) { ViewData["username"] = username; return View(); } [HttpPost] public ActionResult changeUserPassword(ChangePasswordModel model, FormCollection values) { string username = values["username"]; string password = values["password"]; string confirmPassword = values["confirmPassword"]; MembershipUser mu = Membership.GetUser(username); if (password == confirmPassword) { if (mu.ChangePassword(mu.ResetPassword(), password)) { return RedirectToAction("Index", "ControlPanel"); } else { ModelState.AddModelError("", "The current password does not meet requirements"); } } return View(); } I also modified the Global.asax.cs file to cater for my route in the InactiveUsers partial: // Added in 10/01/11 RouteTable.Routes.MapRoute( "AdminPassword", // routename "ControlPanel/changeUserPassword/{username}", new { controller = "ControlPanel", action = "changeUserPassword", username = UrlParameter.Optional } ); // END Now, when I tested on the MVC Music Store, all of my usernames were just words, e.g. Administrator, User, etc. However now I am applying this code to a situation in my workplace and it's not working out quite as planned. The usernames used in my workplace are actually email addresses and I think this is what is causing the problem. When I click on the RouteLink in the partial InactiveUsers view, it should bring me to the reset password page with a url that looks like this: http://localhost:83/ControlPanel/changeUserPassword/[email protected], HOWEVER, what happens when I click on the RouteLink is an error is thrown to say that the view changeUserPassword cannot be found, and the URL looks like this: http://localhost:83/ControlPanel/changeUserPassword/example1%40gmail.com - See how the '@' symbol gets messed up? I've also debugged through the code, and in my GET changeUserPassword, the username is populating correctly: [email protected], so I'm thinking it's just the URL that's messing it up? If I type in the URL manually, the changeUserPassword view displays, however the password reset function does not work. An 'Object reference not set to an instance of an object' exception is thrown at the if (mu.ChangePassword(mu.ResetPassword(), password)) line. I think if I could solve the first issue (URL '@' symbol problem) it might help me along with my second issue. Any help would be appreciated :) Stack Trace - as requested Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [InvalidOperationException: The view 'changeUserPassword' or its master was not found. The following locations were searched: ~/Views/ControlPanel/changeUserPassword.aspx ~/Views/ControlPanel/changeUserPassword.ascx ~/Views/Shared/changeUserPassword.aspx ~/Views/Shared/changeUserPassword.ascx] System.Web.Mvc.ViewResult.FindView(ControllerContext context) +495 System.Web.Mvc.ViewResultBase.ExecuteResult(ControllerContext context) +208 System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult) +39 System.Web.Mvc.<>c__DisplayClass14.<InvokeActionResultWithFilters>b__11() +60 System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation) +391 System.Web.Mvc.<>c__DisplayClass16.<InvokeActionResultWithFilters>b__13() +61 System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList`1 filters, ActionResult actionResult) +285 System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) +830 System.Web.Mvc.Controller.ExecuteCore() +136 System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) +111 System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext) +39 System.Web.Mvc.<>c__DisplayClass8.<BeginProcessRequest>b__4() +65 System.Web.Mvc.Async.<>c__DisplayClass1.<MakeVoidDelegate>b__0() +44 System.Web.Mvc.Async.<>c__DisplayClass8`1.<BeginSynchronous>b__7(IAsyncResult _) +42 System.Web.Mvc.Async.WrappedAsyncResult`1.End() +141 System.Web.Mvc.Async.AsyncResultWrapper.End(IAsyncResult asyncResult, Object tag) +54 System.Web.Mvc.Async.AsyncResultWrapper.End(IAsyncResult asyncResult, Object tag) +40 System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) +52 System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) +38 System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +8841105 System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +184

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  • iphone - UIViewController header view errors

    - by Fiona
    Hi there, So to give a little background: I've an app that has a UITableViewController- (ContactDetailViewController) In this view at the top, I require a few labels and buttons, followed by a group style tableview. So I've created a nib file containing these elements. (ContactHeaderView.xib) Then in the viewDidLoad of ContactDetailViewController I've loaded this nib as the headerView. See implementation file below: #import "ContactDetailViewController.h" #import "DisplayInfoViewController.h" #import "ActionViewController.h" @implementation ContactDetailViewController @synthesize name; @synthesize date; @synthesize nextAction; @synthesize nameLabel; @synthesize usernameLabel; @synthesize nextActionTextField; @synthesize dateLabel; @synthesize contactInfoButton; @synthesize backgroundInfoButton; @synthesize actionDoneButton; - (void)viewDidLoad { [super viewDidLoad]; } - (void)didReceiveMemoryWarning { // Releases the view if it doesn't have a superview. [super didReceiveMemoryWarning]; // Release any cached data, images, etc that aren't in use. } - (void)viewDidUnload { // Release any retained subviews of the main view. // e.g. self.myOutlet = nil; } #pragma mark Table view methods - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 1; } // Customize the number of rows in the table view. - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { return 3; } - (UIView *) tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section { if (section == 0){ UIViewController *chv = [[[UIViewController alloc] initWithNibName:@"ContactHeaderView" bundle:nil] autorelease]; // self.nameLabel.text = self.name; return chv.view; }else{ return nil; } } - (CGFloat)tableView:(UITableView *)tableView heightForHeaderInSection:(NSInteger)section{ return 300.0; } // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } // Set up the cell... return cell; } - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic may go here. Create and push another view controller. // AnotherViewController *anotherViewController = [[AnotherViewController alloc] initWithNibName:@"AnotherView" bundle:nil]; // [self.navigationController pushViewController:anotherViewController]; // [anotherViewController release]; } /* // Override to support conditional editing of the table view. - (BOOL)tableView:(UITableView *)tableView canEditRowAtIndexPath:(NSIndexPath *)indexPath { // Return NO if you do not want the specified item to be editable. return YES; } */ - (void)dealloc { [name release]; [date release]; [nextAction release]; [nameLabel release]; [usernameLabel release]; [nextActionTextField release]; [dateLabel release]; [contactInfoButton release]; [backgroundInfoButton release]; [actionDoneButton release]; [super dealloc]; } -(IBAction)displayContactInfo:(id)sender{ DisplayInfoViewController *divc = [[DisplayInfoViewController alloc] init]; divc.textView = self.nextAction; divc.title = @"Contact Info"; [self.navigationController pushViewController:divc animated:YES]; [divc release]; } -(IBAction)displayBackgroundInfo:(id)sender{ DisplayInfoViewController *divc = [[DisplayInfoViewController alloc] init]; divc.textView = self.nextAction; divc.title = @"Background Info"; [self.navigationController pushViewController:divc animated:YES]; [divc release]; } -(IBAction)actionDone:(id)sender{ ActionViewController *avc = [[ActionViewController alloc] init]; avc.title = @"Action"; avc.nextAction = self.nextAction; [self.navigationController pushViewController:avc animated:YES]; [avc release]; } @end Here's the Header File: #import <UIKit/UIKit.h> @interface ContactDetailViewController : UITableViewController { NSString *name; NSString *date; NSString *nextAction; IBOutlet UILabel *nameLabel; IBOutlet UILabel *usernameLabel; IBOutlet UITextField *nextActionTextField; IBOutlet UILabel *dateLabel; IBOutlet UIButton *contactInfoButton; IBOutlet UIButton *backgroundInfoButton; IBOutlet UIButton *actionDoneButton; } @property (nonatomic, retain) NSString *name; @property (nonatomic, retain) NSString *date; @property (nonatomic, retain) NSString *nextAction; @property (nonatomic, retain) IBOutlet UILabel *nameLabel; @property (nonatomic, retain) IBOutlet UILabel *usernameLabel; @property (nonatomic, retain) IBOutlet UITextField *nextActionTextField; @property (nonatomic, retain) IBOutlet UILabel *dateLabel; @property (nonatomic, retain) IBOutlet UIButton *contactInfoButton; @property (nonatomic, retain) IBOutlet UIButton *backgroundInfoButton; @property (nonatomic, retain) IBOutlet UIButton *actionDoneButton; -(IBAction)displayContactInfo: (id)sender; -(IBAction)displayBackgroundInfo: (id)sender; -(IBAction)actionDone: (id)sender; @end However when I run it, I get the following error message: * Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[ setValue:forUndefinedKey:]: this class is not key value coding-compliant for the key nameLabel.' In IB I've hooked up the labels/buttons/textbox to the File's Owner (set the File's Owner Class to: ContactDetailViewController) Anyone any idea what I'm doing wrong? Regards, Fiona

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  • UI View Controller crashes after interruption

    - by nosuic
    Given the multitasking of iOS I thought it wouldn't be a pain to pause and resume my app, by pressing the home button or due to a phone call, but for a particular view controller it crashes. The navigation bar is working fine i.e. when I tap "Back" it's ok, but if I try to tap controls of the displayed UI View Controller then I get EXC_BAD_ACCESS.. =/ Please find the code of my problematic View Controller below. I'm not very sure about it myself, because I used loadView to build its View, but apart from this interruption problem it works fine. StoreViewController.h #import <UIKit/UIKit.h> @protocol StoreViewDelegate <NSObject> @optional - (void)DirectionsClicked:(double)lat:(double)lon; @end @interface StoreViewController : UIViewController { double latitude; double longitude; NSString *description; NSString *imageURL; short rating; NSString *storeType; NSString *offerType; UIImageView *imageView; UILabel *descriptionLabel; id<StoreViewDelegate> storeViewDel; } @property (nonatomic) double latitude; @property (nonatomic) double longitude; @property (nonatomic) short rating; @property (nonatomic,retain) NSString *description; @property (nonatomic,retain) NSString *imageURL; @property (nonatomic,retain) NSString *storeType; @property (nonatomic,retain) NSString *offerType; @property (assign) id<StoreViewDelegate> storeViewDel; @end StoreViewController.m #import "StoreViewController.h" #import <QuartzCore/QuartzCore.h> @interface StoreViewController() -(CGSize) calcLabelSize:(NSString *)string withFont:(UIFont *)font maxSize:(CGSize)maxSize; @end @implementation StoreViewController @synthesize storeViewDel, longitude, latitude, description, imageURL, rating, offerType, storeType; - (void)mapsButtonClicked:(id)sender { } - (void)loadView { UIView *storeView = [[UIView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, 0.0f, 0.0f)]; // Colours UIColor *lightBlue = [[UIColor alloc] initWithRed:(189.0f / 255.0f) green:(230.0f / 255.0f) blue:(252.0f / 255.0f) alpha:1.0f]; UIColor *darkBlue = [[UIColor alloc] initWithRed:(28.0f/255.0f) green:(157.0f/255.0f) blue:(215.0f/255.0f) alpha:1.0f]; // Layout int width = self.navigationController.view.frame.size.width; int height = self.navigationController.view.frame.size.height; float firstRowHeight = 100.0f; int margin = width / 20; int imgWidth = (width - 3 * margin) / 2; // Set ImageView imageView = [[UIImageView alloc] initWithFrame:CGRectMake(margin, margin, imgWidth, imgWidth)]; CALayer *imgLayer = [imageView layer]; [imgLayer setMasksToBounds:YES]; [imgLayer setCornerRadius:10.0f]; [imgLayer setBorderWidth:4.0f]; [imgLayer setBorderColor:[lightBlue CGColor]]; // Load default image NSData *imageData = [NSData dataWithContentsOfFile:@"thumb-null.png"]; UIImage *image = [UIImage imageWithData:imageData]; [imageView setImage:image]; [storeView addSubview:imageView]; // Set Rating UIImageView *ratingView = [[UIImageView alloc] initWithFrame:CGRectMake(3 * width / 4 - 59.0f, margin, 118.0f, 36.0f)]; UIImage *ratingImage = [UIImage imageNamed:@"bb-rating-0.png"]; [ratingView setImage:ratingImage]; [ratingImage release]; [storeView addSubview:ratingView]; // Set Get Directions button UIButton *btn = [[UIButton alloc] initWithFrame:CGRectMake(3 * width / 4 - 71.5f, 36.0f + 2*margin, 143.0f, 63.0f)]; [btn addTarget:self action:@selector(mapsButtonClicked:) forControlEvents:UIControlEventTouchUpInside]; UIImage *mapsImgUp = [UIImage imageNamed:@"bb-maps-up.png"]; [btn setImage:mapsImgUp forState:UIControlStateNormal]; [mapsImgUp release]; UIImage *mapsImgDown = [UIImage imageNamed:@"bb-maps-down.png"]; [btn setImage:mapsImgDown forState:UIControlStateHighlighted]; [mapsImgDown release]; [storeView addSubview:btn]; [btn release]; // Set Description Text UIScrollView *descriptionView = [[UIScrollView alloc] initWithFrame:CGRectMake(0.0f, imgWidth + 2 * margin, width, height - firstRowHeight)]; descriptionView.backgroundColor = lightBlue; CGSize s = [self calcLabelSize:description withFont:[UIFont systemFontOfSize:18.0f] maxSize:CGSizeMake(width, 9999.0f)]; descriptionLabel = [[UILabel alloc] initWithFrame:CGRectMake(margin, margin, width - 2 * margin, s.height)]; descriptionLabel.lineBreakMode = UILineBreakModeWordWrap; descriptionLabel.numberOfLines = 0; descriptionLabel.font = [UIFont systemFontOfSize:18.0f]; descriptionLabel.textColor = darkBlue; descriptionLabel.text = description; descriptionLabel.backgroundColor = lightBlue; [descriptionView addSubview:descriptionLabel]; [storeView addSubview:descriptionView]; [descriptionLabel release]; [lightBlue release]; [darkBlue release]; self.view = storeView; [storeView release]; } - (void)didReceiveMemoryWarning { // Releases the view if it doesn't have a superview. [super didReceiveMemoryWarning]; // Release any cached data, images, etc. that aren't in use. } - (void)viewDidUnload { [super viewDidUnload]; // Release any retained subviews of the main view. // e.g. self.myOutlet = nil; } - (void)dealloc { [imageView release]; [descriptionLabel release]; [super dealloc]; } @end Any suggestions ? Thank you, F.

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  • JSF2 - use view scope managed bean to pass value between navigation

    - by Fekete Kamosh
    Hi all, I am solving how to pass values from one page to another without making use of session scope managed bean. For most managed beans I would like to have only Request scope. I created a very, very simple calculator example which passes Result object resulting from actions on request bean (CalculatorRequestBean) from 5th phase as initializing value for new instance of request bean initialized in next phase lifecycle. In fact - in production environment we need to pass much more complicated data object which is not as primitive as Result defined below. What is your opinion on this solution which considers both possibilities - we stay on the same view or we navigate to the new one. But in both cases I can get to previous value stored passed using view scoped managed bean. Calculator page: <?xml version='1.0' encoding='UTF-8' ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html"> <h:head> <title>Calculator</title> </h:head> <h:body> <h:form> <h:panelGrid columns="2"> <h:outputText value="Value to use:"/> <h:inputText value="#{calculatorBeanRequest.valueToAdd}"/> <h:outputText value="Navigate to new view:"/> <h:selectBooleanCheckbox value="#{calculatorBeanRequest.navigateToNewView}"/> <h:commandButton value="Add" action="#{calculatorBeanRequest.add}"/> <h:commandButton value="Subtract" action="#{calculatorBeanRequest.subtract}"/> <h:outputText value="Result:"/> <h:outputText value="#{calculatorBeanRequest.result.value}"/> <h:outputText value="DUMMY" rendered="#{resultBeanView.dummy}"/> </h:panelGrid> </h:form> </h:body> Object to be passed through lifecycle: package cz.test.calculator; import java.io.Serializable; /** * Data object passed among pages. * Lets imagine it holds something much more complicated than primitive int */ public class Result implements Serializable { private int value; public void setValue(int value) { this.value = value; } public int getValue() { return value; } } Request scoped managed bean used on view "calculator.xhtml" package cz.test.calculator; import javax.annotation.PostConstruct; import javax.faces.bean.ManagedBean; import javax.faces.bean.ManagedProperty; import javax.faces.bean.RequestScoped; @ManagedBean @RequestScoped public class CalculatorBeanRequest { @ManagedProperty(value="#{resultBeanView}") ResultBeanView resultBeanView; private Result result; private int valueToAdd; /** * Should perform navigation to */ private boolean navigateToNewView; /** Creates a new instance of CalculatorBeanRequest */ public CalculatorBeanRequest() { } @PostConstruct public void init() { // Remember already saved result from view scoped bean result = resultBeanView.getResult(); } // Dependency injections public void setResultBeanView(ResultBeanView resultBeanView) { this.resultBeanView = resultBeanView; } public ResultBeanView getResultBeanView() { return resultBeanView; } // Getters, setter public void setValueToAdd(int valueToAdd) { this.valueToAdd = valueToAdd; } public int getValueToAdd() { return valueToAdd; } public boolean isNavigateToNewView() { return navigateToNewView; } public void setNavigateToNewView(boolean navigateToNewView) { this.navigateToNewView = navigateToNewView; } public Result getResult() { return result; } // Actions public String add() { result.setValue(result.getValue() + valueToAdd); return isNavigateToNewView() ? "calculator" : null; } public String subtract() { result.setValue(result.getValue() - valueToAdd); return isNavigateToNewView() ? "calculator" : null; } } and finally view scoped managed bean to pass Result variable to new page: package cz.test.calculator; import java.io.Serializable; import javax.annotation.PostConstruct; import javax.faces.bean.ManagedBean; import javax.faces.bean.ViewScoped; import javax.faces.context.FacesContext; @ManagedBean @ViewScoped public class ResultBeanView implements Serializable { private Result result = new Result(); /** Creates a new instance of ResultBeanView */ public ResultBeanView() { } @PostConstruct public void init() { // Try to find request bean ManagedBeanRequest and reset result value CalculatorBeanRequest calculatorBeanRequest = (CalculatorBeanRequest)FacesContext.getCurrentInstance().getExternalContext().getRequestMap().get("calculatorBeanRequest"); if(calculatorBeanRequest != null) { setResult(calculatorBeanRequest.getResult()); } } /** No need to have public modifier as not used on view * but only in managed bean within the same package */ void setResult(Result result) { this.result = result; } /** No need to have public modifier as not used on view * but only in managed bean within the same package */ Result getResult() { return result; } /** * To be called on page to instantiate ResultBeanView in Render view phase */ public boolean isDummy() { return false; } }

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  • How to make mouse wheel to scroll control under mouse cursor?

    - by skevar7
    Currently, mouse wheel scrolls the control that has keyboard focus. That's not good when window has several scrollable controls, because I have to click control first and then scroll. And the same again when trying to scoll another control. Especially bad, when that control has some action associated with click (like MSDN's article list - it opens new article on click). So, is there any tool to fix mouse scroll behavior?

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  • how to create a lotus notes view that shows mails from last two days?

    - by Hemal Pandya
    How do I create a view in Lotus Notes that shows recent mails, say mails received in last two days? My naive attempt was to Create a view with Simple Search date created is in the last 2 days. While this pulls in newer mails it does not seem to clear out old mails. Which means the view contains all mails received since two days before the view was created. What is the right way to do this?

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  • How do I write find/write the script to restore a guest user in Lion (Mac OS X)?

    - by Avry
    In Mac OS X 10.7, you cannot have a guest user if you encrypt the entire drive. An alternative is to create a psuedo-guest user. One of the downsides is that the feature where the guest user is restored to original state no longer exists. How do I write a script that restores the User Template found in /System/Library/User Template/English.lproj? I would also have to figure how to activate this script either at login or on logout.

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  • SECURITY Flaws in this design for User authentication.

    - by Shao
    SECURITY Flaws in this design for User authentication. From: http://wiki.pylonshq.com/display/pylonscookbook/Simple+Homegrown+Authentication Note: a. Project follows the MVC pattern. b. Only a user with a valid username and password is allowed submit something. Design: a. Have a base controller from which all controllers are derived from. b. Before any of the actions in the derived controllers are called the system calls a before action in the base controller. c. In each controller user hardcodes the actions that need to be verified in an array. d. The before action first looks in the array that has the actions that are protected and sees if a user is logged in or not by peaking into the session. If a user is present then user is allowed to submit otherwise user is redirected to login page. What do you think?

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  • Rspec stubing view for anonymous controller

    - by Colin G
    I'm trying to test a method on the application controller that will be used as a before filter. To do this I have setup an anonymous controller in my test with the before filter applied to ensure that it functions correctly. The test currently looks like this: describe ApplicationController do controller do before_filter :authenticated def index end end describe "user authenticated" do let(:session_id){"session_id"} let(:user){OpenStruct.new(:email => "[email protected]", :name => "Colin Gemmell")} before do request.cookies[:session_id] = session_id UserSession.stub!(:find).with(session_id).and_return(user) get :index end it { should assign_to(:user){user} } end end And the application controller is like this: class ApplicationController < ActionController::Base protect_from_forgery def authenticated @user = nil end end My problem is when ever I run the test I'm getting the following error 1) ApplicationController user authenticated Failure/Error: get :index ActionView::MissingTemplate: Missing template stub_resources/index with {:handlers=>[:erb, :rjs, :builder, :rhtml, :rxml, :haml], :formats=>[:html], :locale=>[:en, :en]} in view paths "#<RSpec::Rails::ViewRendering::PathSetDelegatorResolver:0x984f310>" According to the docs the view is not rendered when running controller tests however this points to no stub existing for this action (which is understandable as the view doesn't exist) Anyone have a clue how to solve this problem or stub the view out. Cheers Colin G

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  • Allowing user to edit only the page content and some custom fields in wordpress

    - by GaVrA
    This is the site: http://www.backpackers.rs Using "User Role Editor" i have user group that can only read and edit published pages so i can have as many users as i want in that user group and they all will have only one published page on their own so they can edit only that page. Now, this is how a user in that user group currently is seeing "edit page" page: http://i39.tinypic.com/rwuesh.png What i need is to disable all those things that have a red border around it + something with custom fields. So i need to disable these things for user in that user group: ability to change status of the page entire "Attributes" block is something that he/she must not see or be able to change ability to change something in "Discussion" block he/she shouldnt see "Page revisions" block i need a way to give those users ability to use only some custom fields. Currently we have 6 custom fields, and i want to give these users ability to only use 4 of those custom fields. i need to disable these users from creating new custom fields. I dont need complete answers for these things, something to get me started is really what i need. I have been reading codex a lot, but still didnt find something to help me with this, so basically any answer is more then appreciated!

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  • Building an *efficient* if/then interface for non-technical users to build flow-control in PHP

    - by Brendan
    I am currently building an internal tool to be used by our management to control the flow of traffic. I have built an if/then interface allowing the user to set conditions for certain outcomes, however it is inefficient to use the switch statement to control the flow. How can I improve the efficiency of my code? Example of code: if($previous['route_id'] == $condition['route_id'] && $failed == 0) //if we have not moved on to a new set of rules and we haven't failed yet { switch($condition['type']) { case 0 : $type = $user['hour']; break; case 1 : $type = $user['location']['region_abv']; break; case 2 : $type = $user['referrer_domain']; break; case 3 : $type = $user['affiliate']; break; case 4 : $type = $user['location']['country_code']; break; case 5 : $type = $user['location']['city']; break; } $type = strtolower($type); $condition['value'] = strtolower($condition['value']); switch($condition['operator']) { case 0 : if($type == $condition['value']); else $failed = '1'; break; case 1 : if($type != $condition['value']); else $failed = '1'; break; case 2 : if($type > $condition['value']); else $failed = '1'; break; case 3 : if($type >= $condition['value']); else $failed = '1'; break; case 4 : if($type < $condition['value']); else $failed = '1'; break; case 5 : if($type <= $condition['value']); else $failed = '1'; break; } }

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  • Media recommendation engine - Single user system - How to start

    - by Microkernel
    Hi guys, I want to implement a media recommendation engine. I saw a similar posts on this, but I think my requirements are bit different from those, so posting here. Here is the deal. I want to implement a recommendation engine for media players like VLC, which would be an engine that has to care for only single user. Like, it would be embedded in a media player on a PC which is typically used by single user. And it will start learning the likes and dislikes of the user and gradually learns what a user likes. Here it will not be able to find similar users for using their data for recommendation as its a single user system. So how to go about this? Or you can consider it as a recommendation engine that has to be put in say iPods, which has to learn about a single user and recommend music/Movies from the collections it has. I thought of start collecting the genre of music/movies (maybe even artist name) that user watches and recommend movies from the most watched Genre, but it look very crude, isn't it? So is there any algorithms I can use or any resources I can refer up to? Regards, MicroKernel :)

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  • Make PasswordRecovery control work with locked out users ?

    - by Moe Sisko
    Example scenario in an ASP.NET application using SQL Server membership provider : 1) a user can't remember their exact password, and tries many times in a short space of time to login with an invalid password (say 5 times in a 10 minute window). This locks out the user (i.e. sets the IsLockedOut flag of the aspnet_Membership table to 1). 2) user goes to the "forgot my password" screen to try to get a new password emailed to them. This screen uses the PasswordRecovery control. User enters their correct user id, but then cannot go further in the password recovery process, since the IsLockedOut flag is 1. (They don't even get to see their security question). 3) The user would then have to phone tech support to get themselves unlocked etc. To reduce the burden on support staff, we are trying to eliminate step 3) if possible, by making the PasswordRecovery control (if possible), work with locked out users. i.e. when they enter their login ID, the security question comes up, and IF they enter the correct answer, the system will unlock the user, then send the new email to them. I'm wondering if it is possible to tweak the PasswordRecovery control to do this. Or maybe I'm approaching this the wrong way ?

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  • Django Testing: Faking User Creation

    - by Ygam
    I want to better write this test: def test_profile_created(self): self.client.post(reverse('registration_register'), data={ 'username':'ygam', 'email':'[email protected]', 'password1':'ygam', 'password2':'ygam' }) """ Test if a profile is created on save """ user = User.objects.get(username='ygam') self.assertTrue(UserProfile.objects.filter(user=user).exists()) and I just came upon this code on django-registration tests that does not actually "create" the user: def test_registration_signal(self): def receiver(sender, **kwargs): self.failUnless('user' in kwargs) self.assertEqual(kwargs['user'].username, 'bob') self.failUnless('request' in kwargs) self.failUnless(isinstance(kwargs['request'], WSGIRequest)) received_signals.append(kwargs.get('signal')) received_signals = [] signals.user_registered.connect(receiver, sender=self.backend.__class__) self.backend.register(_mock_request(), username='bob', email='[email protected]', password1='secret') self.assertEqual(len(received_signals), 1) self.assertEqual(received_signals, [signals.user_registered]) However he used a custom function for this "_mock_request": class _MockRequestClient(Client): def request(self, **request): environ = { 'HTTP_COOKIE': self.cookies, 'PATH_INFO': '/', 'QUERY_STRING': '', 'REMOTE_ADDR': '127.0.0.1', 'REQUEST_METHOD': 'GET', 'SCRIPT_NAME': '', 'SERVER_NAME': 'testserver', 'SERVER_PORT': '80', 'SERVER_PROTOCOL': 'HTTP/1.1', 'wsgi.version': (1,0), 'wsgi.url_scheme': 'http', 'wsgi.errors': self.errors, 'wsgi.multiprocess':True, 'wsgi.multithread': False, 'wsgi.run_once': False, 'wsgi.input': None, } environ.update(self.defaults) environ.update(request) request = WSGIRequest(environ) # We have to manually add a session since we'll be bypassing # the middleware chain. session_middleware = SessionMiddleware() session_middleware.process_request(request) return request def _mock_request(): return _MockRequestClient().request() However, it may be too long of a function for my needs. I want to be able to somehow "fake" the account creation. I have not much experience on mocks and stubs so any help would do. Thanks!

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • Where clause on joined table used for user defined key/value pairs

    - by Steve Wright
    Our application allows administrators to add “User Properties” in order for them to be able to tailor the system to match their own HR systems. For example, if your company has departments, you can define “Departments” in the Properties table and then add values that correspond to “Departments” such as “Jewelry”, “Electronics” etc… You are then able to assign a department to users. Here is the schema: In this schema, a User can have only one UserPropertyValue per Property, but doesn’t have to have a value for the property. I am trying to build a query that will be used in SSRS 2005 and also have it use the PropertyValues as the filter for users. My query looks like this: SELECT UserLogin, FirstName, LastName FROM Users U LEFT OUTER JOIN UserPropertyValues UPV ON U.ID = UPV.UserID WHERE UPV.PropertyValueID IN (1, 5) When I run this, if the user has ANY of the property values, they are returned. What I would like to have is where this query will return users that have values BY PROPERTY. So if PropertyValueID = 1 is of Department (Jewelry), and PropertyValueID = 5 is of EmploymentType (Full Time), I want to return all users that are in Department Jewelry that are EmployeeType of Full Time, can this be done? Here's a full data example: User A has Department(Jewelry value = 1) and EmploymentType(FullTime value = 5)User B has Department(Electronics value = 2) and EmploymentType(FullTime value = 5)User C has Department(Jewelry value = 1) and EmployementType(PartTime value = 6) My query should only return User A using the above query UPDATE: I should state that this query is used as a dataset in SSRS, so the parameter passed to the query will be @PropertyIDs and it is defined as a multi-value parameter in SSRS. WHERE UPV.PropertyValueID IN (@PropertyIDs)

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  • DataGridView not displaying data in ToolStripDropDown

    - by jblaske
    I'm utilizing the code posted by Jesper Palm here: http://stackoverflow.com/questions/280891/make-user-control-display-outside-of-form-boundry /// <summary> /// A simple popup window that can host any System.Windows.Forms.Control /// </summary> public class PopupWindow : System.Windows.Forms.ToolStripDropDown { private System.Windows.Forms.Control _content; private System.Windows.Forms.ToolStripControlHost _host; public PopupWindow(System.Windows.Forms.Control content) { //Basic setup... this.AutoSize = false; this.DoubleBuffered = true; this.ResizeRedraw = true; this._content = content; this._host = new System.Windows.Forms.ToolStripControlHost(content); //Positioning and Sizing this.MinimumSize = content.MinimumSize; this.MaximumSize = content.Size; this.Size = content.Size; content.Location = Point.Empty; //Add the host to the list this.Items.Add(this._host); } } I've translated it to VB: Public Class PopupWindow Inherits System.Windows.Forms.ToolStripDropDown Private _content As System.Windows.Forms.Control Private _host As System.Windows.Forms.ToolStripControlHost Public Sub New(ByVal content As System.Windows.Forms.Control) Me.AutoSize = False Me.DoubleBuffered = True Me.ResizeRedraw = True Me._content = content Me._host = New System.Windows.Forms.ToolStripControlHost(content) Me.MinimumSize = content.MinimumSize Me.MaximumSize = content.MaximumSize Me.Size = content.Size content.Location = Point.Empty Me.Items.Add(Me._host) End Sub End Class It works great with a PictureBox showing its information. But for some reason I cannot get the DataGridView to display anything when it is in the popup. If I pull the grid out of the popup it displays all of its information fine. If I pause during debug, the grid shows that it has all the data in it. It's just not displaying anything. Does anybody have any ideas?

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  • SugarCRM - how to make users see only child users?

    - by John
    Hello, I want to change the behaviour of Sugar CRM community version. Here's what sugar currently does: 1) Admin logs into Sugar. 2) Admin clicks on Admin tab. 3) Admin creates a new user named George with admin access 4) Under user information section, Admin makes George report to Admin (in the database, it will show users.report_to_id is the admin's user_id) 5) Admin saves and logs out 6) George logs in with his password 7) George goes to admin tab. 8) George goes to list users page and sees all users, including Admin, the person he is supposed to report to. I want to change step 8 such that George is not allowed to see the user he reports to. Additionally, he is not allowed to see his grand parent user, great grand parent user, great great grand parent user etc... George should only be able to see users that he creates. How can I achieve this? Is this even possible?

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  • How to use Castle Windsor with ASP.Net web forms?

    - by Xian
    I am trying to wire up dependency injection with Windsor to standard asp.net web forms. I think I have achieved this using a HttpModule and a CustomAttribute (code shown below), although the solution seems a little clunky and was wondering if there is a better supported solution out of the box with Windsor? There are several files all shown together here // index.aspx.cs public partial class IndexPage : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { Logger.Write("page loading"); } [Inject] public ILogger Logger { get; set; } } // WindsorHttpModule.cs public class WindsorHttpModule : IHttpModule { private HttpApplication _application; private IoCProvider _iocProvider; public void Init(HttpApplication context) { _application = context; _iocProvider = context as IoCProvider; if(_iocProvider == null) { throw new InvalidOperationException("Application must implement IoCProvider"); } _application.PreRequestHandlerExecute += InitiateWindsor; } private void InitiateWindsor(object sender, System.EventArgs e) { Page currentPage = _application.Context.CurrentHandler as Page; if(currentPage != null) { InjectPropertiesOn(currentPage); currentPage.InitComplete += delegate { InjectUserControls(currentPage); }; } } private void InjectUserControls(Control parent) { if(parent.Controls != null) { foreach (Control control in parent.Controls) { if(control is UserControl) { InjectPropertiesOn(control); } InjectUserControls(control); } } } private void InjectPropertiesOn(object currentPage) { PropertyInfo[] properties = currentPage.GetType().GetProperties(); foreach(PropertyInfo property in properties) { object[] attributes = property.GetCustomAttributes(typeof (InjectAttribute), false); if(attributes != null && attributes.Length > 0) { object valueToInject = _iocProvider.Container.Resolve(property.PropertyType); property.SetValue(currentPage, valueToInject, null); } } } } // Global.asax.cs public class Global : System.Web.HttpApplication, IoCProvider { private IWindsorContainer _container; public override void Init() { base.Init(); InitializeIoC(); } private void InitializeIoC() { _container = new WindsorContainer(); _container.AddComponent<ILogger, Logger>(); } public IWindsorContainer Container { get { return _container; } } } public interface IoCProvider { IWindsorContainer Container { get; } }

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  • background image not showing in html

    - by Registered User
    I am having following css <!DOCTYPE html > <html> <head> <meta charset="utf-8"> <title>Black Goose Bistro Summer Menu</title> <link href='http://fonts.googleapis.com/css?family=Marko+One' rel='stylesheet' type='text/css'> <style> body { font-family: Georgia, serif; font-size: 100%; line-height: 175%; margin: 0 15% 0; background-image:url(images/bullseye.png); } #header { margin-top: 0; padding: 3em 1em 2em 1em; text-align: center; } a { text-decoration: none; } h1 { font: bold 1.5em Georgia, serif; text-shadow: .1em .1em .2em gray; } h2 { font-size: 1em; text-transform: uppercase; letter-spacing: .5em; text-align: center; } dt { font-weight: bold; } strong { font-style: italic; } ul { list-style-type: none; margin: 0; padding: 0; } #info p { font-style: italic; } .price { font-family: Georgia, serif; font-style: italic; } p.warning, sup { font-size: small; } .label { font-weight: bold; font-variant: small-caps; font-style: normal; } h2 + p { text-align: center; font-style: italic; } ); </style> </head> <body> <div id="header"> <h1>Black Goose Bistro &bull; Summer Menu</h1> <div id="info"> <p>Baker's Corner, Seekonk, Massachusetts<br> <span class="label">Hours: Monday through Thursday:</span> 11 to 9, <span class="label">Friday and Saturday;</span> 11 to midnight</p> <ul> <li><a href="#appetizers">Appetizers</a></li> <li><a href="#entrees">Main Courses</a></li> <li><a href="#toast">Traditional Toasts</a></li> <li><a href="#dessert">Dessert Selection</a></li> </ul> </div> </div> <div id="appetizers"> <h2>Appetizers</h2> <p>This season, we explore the spicy flavors of the southwest in our appetizer collection.</p> <dl> <dt>Black bean purses</dt> <dd>Spicy black bean and a blend of mexican cheeses wrapped in sheets of phyllo and baked until golden. <span class="price">$3.95</span></dd> <dt class="newitem">Southwestern napoleons with lump crab &mdash; <strong>new item!</strong></dt> <dd>Layers of light lump crab meat, bean and corn salsa, and our handmade flour tortillas. <span class="price">$7.95</span></dd> </dl> </div> <div id="entrees"> <h2>Main courses</h2> <p>Big, bold flavors are the name of the game this summer. Allow us to assist you with finding the perfect wine.</p> <dl> <dt class="newitem">Jerk rotisserie chicken with fried plantains &mdash; <strong>new item!</strong></dt> <dd>Tender chicken slow-roasted on the rotisserie, flavored with spicy and fragrant jerk sauce and served with fried plantains and fresh mango. <strong>Very spicy.</strong> <span class="price">$12.95</span></dd> <dt>Shrimp sate kebabs with peanut sauce</dt> <dd>Skewers of shrimp marinated in lemongrass, garlic, and fish sauce then grilled to perfection. Served with spicy peanut sauce and jasmine rice. <span class="price">$12.95</span></dd> <dt>Grilled skirt steak with mushroom fricasee</dt> <dd>Flavorful skirt steak marinated in asian flavors grilled as you like it<sup>*</sup>. Served over a blend of sauteed wild mushrooms with a side of blue cheese mashed potatoes. <span class="price">$16.95</span></dd> </dl> </div> <div id="toast"> <h2>Traditional Toasts</h2> <p>The ultimate comfort food, our traditional toast recipes are adapted from <a href="http://www.gutenberg.org/files/13923/13923-h/13923-h.htm"><cite>The Whitehouse Cookbook</cite></a> published in 1887.</p> <dl> <dt>Cream toast</dt> <dd>Simple cream sauce over highest quality toasted bread, baked daily. <span class="price">$3.95</span></dd> <dt>Mushroom toast</dt> <dd>Layers of light lump crab meat, bean and corn salsa, and our handmade flour tortillas. <span class="price">$6.95</span></dd> <dt>Nun's toast</dt> <dd>Onions and hard-boiled eggs in a cream sauce over buttered hot toast. <span class="price">$6.95</span></dd> <dt>Apple toast</dt> <dd>Sweet, cinnamon stewed apples over delicious buttery grilled bread. <span class="price">$6.95</span></dd> </dl> </div> <div id="dessert"> <h2>Dessert Selection</h2> <p>Be sure to save room for our desserts, made daily by our own <a href="http://www.jwu.edu/college.aspx?id=19510">Johnson & Wales</a> trained pastry chef.</p> <dl> <dt class="newitem">Lemon chiffon cake &mdash; <strong>new item!</strong></dt> <dd>Light and citrus flavored sponge cake with buttercream frosting as light as a cloud. <span class="price">$2.95</span></dd> <dt class="newitem">Molten chocolate cake</dt> <dd>Bubba's special dark chocolate cake with a warm, molten center. Served with or without a splash of almond liqueur. <span class="price">$3.95</span></dd> </dl> </div> <p class="warning"><sup>*</sup> We are required to warn you that undercooked food is a health risk.</p> </body> </html> but the background image does not appear in body tag you can see background-image:url(images/bullseye.png); this html page is bistro.html and the directory in which it is contained there is a folder images and inside images folder I have a file bullseye.png .I expect the png to appear in background.But that does not happen. For sake of question I am posting the image here also Let me know if the syntax of css wrong? following is image http://i.stack.imgur.com/YUKgg.png

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