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  • How to print contents from a session variable by looping in a foreach statement

    - by itsover9000
    im trying to write a code where can print and loop through the contents of my session variable by using a foreach statement here is my code <form class="form form-inline" method = "post" action="reportmaker.php"> <select name="rfield"> <option value="">--Select Field--</option> <?php $sc2=mysql_query("SELECT * from searchcolumn s left join report_fields r on s.scol_id=r.field_id where s.category != 'wh'"); foreach($sc2 as $sc){ ?> <option value="<?php echo $sc[advsearch_col]; ?>"><?php echo $sc[advsearch_name]; ?></option> <?php } ?> </select> <button type="submit" value = "submit" id="add" name="add" class="btn pull-right">Add More</button> </form> <?php if(isset($_POST['add'])) { $_SESSION['temp'][]=$_POST['rfield']; } if($_SESSION[temp][]!=""){ foreach($_SESSION[temp][] as $temp) { echo $temp; } } ?> the error that appears with this code is Fatal error: Cannot use [] for reading the line where the error is is this if($_SESSION[temp][]!=""){ i need to print the contents of the session array and this is the only way i know how is there a way to fix this? thanks =========EDIT thanks for the answers guys i finally got it

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  • Execute codes in a different page but remain on the same actual php page

    - by chupinette
    I have a complicated problem here..I have codes to send mail using PEAR which i have tested in a php page called testmail.php. Now i have my actual application an a page called Cart.php where i have a button called Place Order. When i click on this button, it actually redirects to a url called : http://localhost/final/index.php?OrderSuccessful which actually displays a message on the page and sends an email. The problem is that when i put the code for email in Cart.php, i get errors. But when i put the url http://localhost/final/testmail.php it actually works. So i was thinking, is there a way to execute the codes from that testmail.php by remaining on the page Cart.php? include('Mail.php'); $mail = Mail::factory("mail"); $headers = array("From"=>"[email protected]", "Subject"=>"Your order has been placed "); $body = "lol"; $mail->send("[email protected]", $headers, $body); I get the error Assigning the return value of new by reference is deprecated

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  • Workaround for PHP SOAP request failure when wsdl defines service port binding as https and port 80?

    - by scooterhanson
    I am consuming a SOAP web service using php5's soap extension. The service' wsdl was generated using Axis java2wsdl, and whatever options are used during generation result in the port binding url being listed as https://xxx.xxx.xxx.xxx**:80** If I download the wsdl to my server, remove the port 80 specification from the port binding location value, and reference the local file in my soapclient call it works fine. However, if I try to reference it remotely (or download it and reference it locally, as-is) the call fails with a soap fault. I have no input into the service side so I can't make them change their wsdl-generation process. So, unless there's a way to make the soapclient ignorant of the port, I'm stuck with using a locally modified copy of someone else' wsdl (which I'd rather not do). Any thoughts on how to make my soapclient ignore the port 80?

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  • PHP - How to get, and display the biggest values from a database?

    - by Dodi300
    Hello. Can anyone tell me how to get and display the biggest values from a database? I have multiple values in my database with the heading "gmd", but how would I get only the first 3 biggest ones to be displayed? How would I do it in this example: $query = "SELECT gmd FROM account"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { } Thanks.

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  • Dynamically add data stored in php to nested json

    - by HoGo
    I am trying to dynamicaly generate data in json for jQuery gantt chart. I know PHP but am totally green with JavaScript. I have read dozen of solutions on how dynamicaly add data to json, and tried few dozens of combinations and nothing. Here is the json format: var data = [{ name: "Sprint 0", desc: "Analysis", values: [{ from: "/Date(1320192000000)/", to: "/Date(1322401600000)/", label: "Requirement Gathering", customClass: "ganttRed" }] },{ name: " ", desc: "Scoping", values: [{ from: "/Date(1322611200000)/", to: "/Date(1323302400000)/", label: "Scoping", customClass: "ganttRed" }] }, <!-- Somoe more data--> }]; now I have all data in php db result. Here it goes: $rows=$db->fetchAllRows($result); $rowsNum=count($rows); And this is how I wanted to create json out of it: var data=''; <?php foreach ($rows as $row){ ?> data['name']="<?php echo $row['name'];?>"; data['desc']="<?php echo $row['desc'];?>"; data['values'] = {"from" : "/Date(<?php echo $row['from'];?>)/", "to" : "/Date(<?php echo $row['to'];?>)/", "label" : "<?php echo $row['label'];?>", "customClass" : "ganttOrange"}; } However this does not work. I have tried without loop and replacing php variables with plain text just to check, but it did not work either. Displays chart without added items. If I add new item by adding it to the list of values, it works. So there is no problem with the Gantt itself or paths. Based on all above I assume the problem is with adding plain data to json. Can anyone please help me to fix it?

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  • PHP rewrite to included file - is this a valid script?

    - by Poni
    Hi all! I've made this question: http://stackoverflow.com/questions/2921469/php-mutual-exclusion-mutex As said there, I want several sources to send their stats once in a while, and these stats will be showed at the website's main page. My problem is that I want this to be done in an atomic manner, so no update of the stats will overlap another one running in the background. Now, I came up with this solution and I want you PHP experts to judge it. stats.php <?php define("my_counter", 12); ?> index.php <?php include "stats.php"; echo constant("my_counter"); ?> update.php <?php $old_error_reporting = error_reporting(0); include "stats.php"; define("my_stats_template",' <?php define("my_counter", %d); ?> '); $fd = fopen("stats.php", "w+"); if($fd) { if (flock($fd, LOCK_EX)) { $my_counter = 0; try { $my_counter = constant("my_counter"); } catch(Exception $e) { } $my_counter++; $new_stats = sprintf(constant("my_stats_template"), $my_counter); echo "Counter should stand at $my_counter"; fwrite($fd, $new_stats); } flock($fd, LOCK_UN); fclose($fd); } error_reporting($old_error_reporting); ?> Several clients will call the "update.php" file once every 60sec each. The "index.php" is going to use the "stats.php" file all the time as you can see. What's your opinion?

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  • How can I get columns name from select query in php?

    - by Farshad Mehrvarzan
    I want to execute a SELECT query but I don't how many columns to select. Like: select name, family from persons; How can I know which columns to select? "I am currently designing a site for the execute query by users. So when the user executes this query, I won't know which columns selected. But when I want to show the results and draw a table for the user I should know which columns selected."

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  • Linux web server shared hosting file errors

    - by dfilkovi
    I'm using a shared hosting to host my website and have some problems with files from time to time. First, one of my file (php) was missing a part of code (nothing to do with hackers just a random piece of code was missing), then after some time a value inside a mysql table was also missing a part, then a whole table column disappeared, after that a whole file on my site disappeared and lastly again some code from a file disappeared, my hosting service says it has nothing to do with them, but this is stupid, how can this happen, no hacker attack could do such a thing, I believe it's some kind of a disk corruption or bad backup. Anyone have any ideas?

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  • Cpu usage from top command

    - by kairyu
    How can i get the result like example following. Any command or scripts? Snapshot u1234 3971 1.9 0.0 0 0 ? Z 20:00 0:00 [php] u1234 4243 3.8 0.2 64128 43064 ? D 20:00 0:00 /usr/bin/php /home/u1234/public_html/index.php u1234 4289 5.3 0.2 64128 43064 ? R 20:00 0:00 /usr/bin/php /home/u1234/public_html/index.php u1234 4312 9.8 0.2 64348 43124 ? D 20:01 0:00 /usr/bin/php /home/u1234/public_html/index.php u1235 4368 0.0 0.0 30416 6604 ? R 20:01 0:00 /usr/bin/php /home/u1235/public_html/index.php u1236 4350 2.0 0.0 34884 13284 ? D 20:01 0:00 /usr/bin/php /home/u1236/public_html/index.php u1237 4353 13.3 0.1 51296 30496 ? S 20:01 0:00 /usr/bin/php /home/u1237/public_html/index.php u1238 4362 63.0 0.0 0 0 ? Z 20:01 0:00 [php] u1238 4366 0.0 0.1 51352 30532 ? R 20:01 0:00 /usr/bin/php /home/u1238/public_html/index.php u1239 4082 3.0 0.0 0 0 ? Z 20:00 0:01 [php] u1239 4361 26.0 0.1 49104 28408 ? R 20:01 0:00 /usr/bin/php /home/u1239/public_html/index.php u1240 1980 0.4 0.0 0 0 ? Z 19:58 0:00 [php] CPU TIME = 8459.71999999992 This result i got from hostgator support :) I was used "top -c" but they do not show "/home/u1239/public_html/index.php Thanks

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  • PHP - Too many mysql_query("SELECT .. ") .. ?

    - by Mike
    Hey, I'm making an e-shop and to display the tree of categories and all the products with their multiple variations of prices I made like more than 150 mysql_query("SELECT ..."); queries on one page. (If I count the "while" loops). Is it too many, and if yes, can it have any negative effect? (ofc. it takes longer to load the data ..) Also can I anyhow achieve the effect of this code without doing it that way? $result2 = mysql_query("SELECT * FROM ceny WHERE produkt_id='$id' ORDER BY gramaz"); $result3 = mysql_query("SELECT * FROM ceny WHERE produkt_id='$id' ORDER BY gramaz"); $result4 = mysql_query("SELECT * FROM ceny WHERE produkt_id='$id' ORDER BY gramaz"); $result5 = mysql_query("SELECT * FROM ceny WHERE produkt_id='$id' ORDER BY gramaz"); while( $row2 = mysql_fetch_array( $result2 )) { } while( $row3 = mysql_fetch_array( $result2 )) { } while( $row4 = mysql_fetch_array( $result2 )) { } while( $row5 = mysql_fetch_array( $result2 )) { } Thanks, Mike.

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  • Same-directory includes failing on a Fedora server with PHP.

    - by JimmySawczuk
    I have a couple files that look like this: index.php: <?php include('includes/header.php'); ... includes/header.php: <?php include('config.php'); ... The error I get is Warning: require(config.php) [function.require]: failed to open stream: No such file or directory in [dir]/includes/header.php on line 2 Fatal error: require() [function.require]: Failed opening required 'config.php' (include_path='.:/usr/share/pear:/usr/share/php') in [dir]/includes/header.php on line 2 I did some further debugging: when I add the call system('pwd'); to includes/header.php, it shows [dir], where it should say [dir]/includes. Adding the 'includes/' to the include path works, but isn't desirable because that would fail on the production server. The above code works on a production server, and worked fine on my development Fedora server, until I tried to change my development environment so that the Fedora server's document root is a mounted CIFS share. Any ideas? Thanks.

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  • What's the best technique to protect my framework from visitors who are not logged in?

    - by Hermet
    First of all, I would like to say that I have used the search box looking for a similar question and was unsuccessful, maybe because of my poor english skills. I have a a 'homemade' framework. I have certain PHP files that must only be visible for the admin. The way I currently do this is check within every single page to see if a session has been opened. If not, the user gets redirected to a 404 page, to seem like the file which has been requested doesn't exist. I really don't know if this is guaranteed to work or if there's a better and more safe way because I'm currently working with kind of confidential data that should never become public. Could you give me some tips? Or leave a link where I could find some? Thank you very much, and again excuse me for kicking the dictionary. EDIT What I usually write in the top of each file is something like this <?php include("sesion.php"); $rs=comprueba(); //'check' if ($rs==1) { ?> And then, at the end <?php } ?> Is it such a butched job, isn't it? EDIT Let's say I have a customers list in a file named customers.php That file may be currently on http://www.mydomain.com/admin/customers.php and it must only be visible for the admin user. Once the admin user has been logged in, I create a session variable. That variable is what I check on the top of each page, and if it exists, the customers list is shown. If not, the user gets redirected to the 404 page. Thank you for your patience. I really appreciate.

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  • Linking how PHP/HTML

    - by Azzyh
    Hello. Alright so im done doing pages with frames, and know i splitted up my design to top.php and bottom.php. In top.php it's linking to style.css and ajax_framework.js and such.. Now this works great until i tried to include top.php & bottom.php in videos/index.php (another dirr), i did like this: include "../top.php"; <-- and the originally index.php --> include "../bottom.php"; Now when i enter the site, it wont load style.css, probably because it thinks that style.css needs to be in videos/ directory, same goes with ajax_framework.js that are both files are on the parent ../ directory. Now what do i do? Some method or technique to solve this in a good way? So i dont have to copy style.css and ajax_framework.js into every directory i have, because then later if i want to change something i would need to change in all directories, which would be my last thing i want to do.. hope you got some nice techniques thank you

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  • PHP include doesn't work

    - by Chris
    I'm not sure how simple is this to solve, but I assume I'm doing something wrong. I'm new to PHP, so bear with me, please. When I started learning PHP, I always placed all my project files into the same folder along with index.php and thus included everything like this: <?php include('./translation.php'); ?> Later on in the process of learning as I gained experience and my skill increased, I had to start using folders and place my files into sub folders. I ended up successfully including my files with the following: <?php include('../translation.php'); ?> My trouble-free coding took an unexpected turn when I decided to start using sub-sub folders. After placing all the files even deeper into the file structure I was shocked to find out that I cannot include them anymore, using: <?php include('.../translation.php'); ?> Now I'm lost. What did I do wrong? Am I to understand that I cannot include files deeper than 2 directories in the project? Should I start using a different file system?

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  • How to name uploaded files in php to prevent them from being overwritten?

    - by user156814
    I'm trying to add user submitted articles to my website, (only for admins). With each article comes an option to upload up to 3 images. My database is set up like this Articles id user_id title body date_added last_edited Photos id (auto_increment) article_id First I save the article in the database, then I upload the photo (temporarily) then I create a new photo record in the database saving the article_id. Then I rename the uploaded photo to be the same as the primary key of the photo record, and to be a png. $filename = $photo->id . '.png'; I figured this would be a good way to prevent files form being overwritten. This seems flawed to me. Any suggestions on how I should save my records and photos? Thanks

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  • How to make an add friend/defriend function in PHP?

    - by user300371
    I have created a site where people can create a profile. But I am trying to figure out how to start on making an add friend button so users can have friends. In my user table, i have user_id, first_name, last_name, email, etc. Should I somehow relate the user_id of the user and the friend in a friend table? I am a novice to programming, so these things are still new to me. Thanks!

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  • PHP in_array() can't even match a single character. Strict is set to true.

    - by solefald
    I've seen a million of these threads here already, and read through every single one already. Including some serious time Googling. Nothing complicated. All I have to do is check if a single character in a loop matches my alphabet array. print_r($alphabet); // all 26 letters Array ( [0] => a [1] => b [2] => c ... [23] => x [24] => y [25] => z ) print_r($emptyLetters); // dynamic array. Array ( [0] => b [1] => s ) foreach($alphabet as $letter): { echo $letter . '<br />' // Correctly prints out every letter from $alphabet. if(in_array($letter, $emptyLetters, true)): // $strict is set // do something endif; } What the hell is going on??? I do not understand what i am doing wrong.... I tried every combination and option possible, but for some reason even array_search() is bit working...

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  • Sanitize input before executing at server in php

    - by Interfaith
    I want to let user input two variable, Name and Password in a form. I want to disable any XSS or script insert in the input values. I have the following code in the form method: <form name="form1" method="post" action="checkpw.php"> Your Name: <table> <tr><td><input class="text" name="name" onBlur="capitalize(this);" maxlength=12 type="text" /></td></tr> </table> Password: <table> <tr><td><input class="text" name="passwd" maxlength=8 type="password" /></td></tr> <tr><td align="center"><br/> <input class="text" type="submit" name="submitbt" value="Login" /> </td></tr> </table> and the following checkpw.php: <?php // Clean up the input values $post = filter_input_array(INPUT_POST, array( 'name' => FILTER_SANITIZE_STRING, 'pw' => FILTER_SANITIZE_STRING, )); if (is_null($post) || in_array(null, $post)) { header("location:login.php"); return; // missing fields (or failed filter) } // pw is the password sent from the form $pw=$_POST['passwd']; $name=$_POST['name']; if($pw == 'testpass'){ header("location:index.php"); } else { header("location:wrong.php"); } ?> Is this a secure way to ensure the form is sent to the server and executed ONLY after the input values have been sanitized? Also, the $name value i want to pass it to index.php file. I insert a code in the index.php as follow: <?php echo $name ?> But it's empty. Any idea how to resolve it?

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  • How can I use cURL to open multiple URLs simultaneously with PHP?

    - by Rob
    Here is my current code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the urls table while($resultSet = mysql_fetch_array($SQL)){ //Put all the urls into one variable // Now for some cURL to run it. $ch = curl_init($resultSet['url']); //load the urls curl_setopt($ch, CURLOPT_TIMEOUT, 2); //No need to wait for it to load. Execute it and go. curl_exec($ch); //Execute curl_close($ch); //Close it off } //While loop I'm relatively new to cURL. By relatively new, I mean this is my first time using cURL. Currently it loads one for two seconds, then loads the next one for 2 seconds, then the next. however, I want to make it load ALL of them at the same time. I'm sure its possible, I'm just unsure as to how. If someone could point me in the right direction, I'd appreciate it.

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  • cURL Affects Cookie Retrieval in PHP?

    - by CJ
    I'm not sure if I'm asking this properly. I have two PHP pages located on the same server. The first PHP page sets a cookie with an expiration and the second one checks to see if that cookie was set. if it is set, it returns "on". If it isn't set, it returns "off". If I just run the pages like "www.example.com/set_cookie.php" AND "www.example.com/is_cookie_set.php" I get an "on" from is_cookie_set.php. Heres the problem, on the set_cookie.php file I have a function called is_set. This function executes the following cURL and returns the contents ("on" or "off"). Unfortunately, the contents are always returned as "off". however, if I check the file manually ("www.example.com/is_cookie_set.php") I can see that the cookie was set. Heres the function : <?php function is_set() { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, 'http://example.com/is_cookie_set.php'); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $contents = curl_exec ($ch); curl_close ($ch); echo $contents; } ?> Please note, I'm not using cURL to GET or SET cookies, only to check a page that checks if the cookie was set. I've looked into CURLOPT_COOKIEJAR, and CURLOPT_COOKIEFILE, but I believe those are for setting cookies via cURL and I don't want to do this.

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  • Web Server Setup

    - by gustyaquino
    Hello, In my workplace, we want to implement your own web server for at leat 100 Apache/PHP/MySQL web pages. My boss is opposed to hiring skilled personnel, he think we can do ourselves. Currently, we are working with hostgator reseller account. I chose CentOS as the operating system, but I don't know the best hardware solution. HP, Dell ? What about the setup on these platforms? Thanks. PS: sorry for my bad english Edit: The purpose of this migration isn't related to performance issues. But independence.

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  • Whats the best way to deal with backups for my php/mysql application

    - by spirytus
    I'm creating php application for my client and now thinking what would be the best way to do backups, automatically if possible? I don't have much experience in this area and in case something goes wrong, or if I need to migrate, I would like to have fast way of getting it all back online. I understand "something goes wrong" is a very wide term, but lets say that someone hacks my site and wipes out database and all the files. My app. is written in php/mysql and I got access to cpanel (hosted with justhost.com if that makes any difference :). I used Joomla and it has JoomlaPack that does complete backup almost automatically and in case site fails, its easy to revert, or migrate if necessary. Is there anything like that for my configuration that would make reverting/migration, easy?

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