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• Thread-safe equivalent to python's time.strptime() ?

  - by Wells

  Something I wrote throws a lot of AttributeErrors when using time.strptime() inside a thread. This only seems to happen on Windows (not on Linux), but whatever…. Upon a'Googling, it seems that time.strptime() isn't considered thread-safe. Is there a better way to create a datetime object from a string? Current code looks like: val = DateFromTicks(mktime(strptime(val, '%B %d, %Y'))) But, that yields the AttributeErrors as its run inside a thread. Thanks!

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• python str.strip strange behavior

  - by Tzury Bar Yochay

  >>> t1 = "abcd.org.gz" >>> t1 'abcd.org.gz' >>> t1.strip("g") 'abcd.org.gz' >>> t1.strip("gz") 'abcd.org.' >>> t1.strip(".gz") 'abcd.or' Why does the 'g' of '.org' is gone?

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• Python Qlistview output dir

  - by ester23

  Hi all i wish make little gui with pyqt4 that show the output of "dir c:\windows\" line by line I'm looking for QlistView but i don't understand how do it. Can anyone help me?

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• handling matrix data in python

  - by Ovisek

  I was trying to progressively subtract values of a 3D matrix. The matrix looks like: ATOM 1223 ZX SOD A 11 2.11 -1.33 12.33 ATOM 1224 ZY SOD A 11 -2.99 -2.92 20.22 ATOM 1225 XH HEL A 12 -3.67 9.55 21.54 ATOM 1226 SS ARG A 13 -6.55 -3.09 42.11 ... here the last three columns are representing values for axes x,y,z respectively. now I what I wanted to do is, take the values of x,y,z for 1st line and subtract with 2nd,3rd,4th line in a iterative way and print the values for each axes. I was using: for line in map(str.split,inp): x = line[-3] y = line[-2] z = line[-1] for separating the values, but how to do in iterative way. should I do it by using Counter.

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• python win32gui finding child windows

  - by nabizan

  for example at first you have to find hwnd of skype hwnd = win32gui.FindWindow(None, 'skype') and than all his child windows and their titles child = ??? any idea?

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• Exit python program when argument is less than 0

  - by Sam

  I'd like the program to exit if the input number is less than 0, but sys.exit() isn't doing the trick. This is what I have now: if len( sys.argv ) > 1: number = sys.argv[1] if number <= 0: print "Invalid number! Must be greater than 0" sys.exit()

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• __rlshift__, __ror__ in Python

  - by Casebash

  I noticed that this recipe seems to use __rlshift__, __ror__ like operators. But, they aren't in the documentation! Can anyone explain these and perhaps point to some docs?

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• In python, what does len(list) do?

  - by nsharish

  My doubt is that if the len(list) calculates the length of the list everytime it is called or it returns the value of the builtin counter.I have a context where i need to check the length of list everytime in a loop, likelistData = [] for value in ioread(): if len(listData)=25: processlistdata() clearlistdata() listData.append(value) Should I check len(listData) every iteration, or can I have a counter for the length of the list.

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• Python CPU id, need help

  - by Derek

  Hello. How i can find process id with py2.6, windows os. I know that there is pycpuid, but i cant compile this under 2.6. Sorry for my english.

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• python and overflowing byte?

  - by Meloun

  Hi all, I need to make a variable with similar behaviour like in C lanquage. I need byte or unsigned char with range 0-255. This variable should overflow, that means... myVar = 255 myVar += 1 print myVar #!!myVar = 0!!

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• Efficient way to access a mapping of identifiers in Python

  - by sixbelo

  I am writing an app to do a file conversion and part of that is replacing old account numbers with a new account numbers. Right now I have a CSV file mapping the old and new account numbers with around 30K records. I read this in and store it as dict and when writing the new file grab the new account from the dict by key. My question is what is the best way to do this if the CSV file increases to 100K+ records? Would it be more efficient to convert the account mappings from a CSV to a sqlite database rather than storing them as a dict in memory?

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• Python - alternative to list.remove(x)?

  - by Seafoid

  Hi, I wish to compare two lists. Generally this is not a problem as I usually use a nested for loop and append the intersection to a new list. In this case, I need to delete the intersection of A and B from A. A = [['ab', 'cd', 'ef', '0', '567'], ['ghy5'], ['pop', 'eye']] B = [['ab'], ['hi'], ['op'], ['ej']] My objective is to compare A and B and delete A intersection B from A, i.e., delete A[0][0] in this case. I tried: def match(): for i in A: for j in i: for k in B: for v in k: if j == v: A.remove(j) list.remove(x) throws a ValueError.

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• check if remote host is up in python

  - by ed1t

  How would I check if the remote host is up without having a port number? Is there any other way I could check other then using regular ping. There is a possibility that the remote host might drop ping packets

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• Text to a PNG on App Engine (Python)

  - by Bemmu

  Note: I am cross-posting this from App Engine group because I got no answers there. As part of my site about Japan, I have a feature where the user can get a large PNG for use as desktop background that shows the user's name in Japanese. After switching my site hosting entirely to App Engine, I removed this particular feature because I could not find any way to render text to a PNG using the image API. In other words, how would you go about outputting an unicode string on top of an image of known dimensions (1024x768 for example), so that the text will be as large as possible horizontally, and centered vertically? Is there a way to do this is App Engine, or is there some external service besides App Engine that could make this easier for me, that you could recommend (besides running ImageMagick on your own server)?

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• what is a good way to do countif in python

  - by tolomea

  I want to count how many members of an iterable meet a given condition. I'd like to do it in a way that is clear and simple and preferably reasonably optimal. My current best ideas are: sum(meets_condition(x) for x in my_list) and len([x for x in my_list if meets_condition(x)]) The first one being iterator based is presumably faster for big lists. And it's the same form as you'd use for testing any and all. However it depends on the fact that int(True) == 1, which is somewhat ugly. The second one seems easier to read to me, but it is different from the any and all forms. Does anyone have any better suggestions? is there a library function somewhere that I am missing?

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• More elegant way to initialize list of duplicated items in Python

  - by Claudiu

  If I want a list initialized to 5 zeroes, that's very nice and easy: [0] * 5 However if I change my code to put a more complicated data structure, like a list of zeroes: [[0]] * 5 will not work as intended, since it'll be 10 copies of the same list. I have to do: [[0] for i in xrange(5)] that feels bulky and uses a variable so sometimes I even do: [[0] for _ in " "] But then if i want a list of lists of zeros it gets uglier: [[[0] for _ in " "] for _ in " "] all this instead of what I want to do: [[[0]]*5]*5 Has anyone found an elegant way to deal with this "problem"?

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• python multiprocessing server connections

  - by tranimatronic

  I wish to get a list of connections to a manager. I can get last_accepted from the servers' listener, but I want all connections. There HAS to be a method I am missing somewhere to return all connections to a server or manager Please help!!

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• Combining entries, filtering of Python dictionaries

  - by matt

  I have two large lists that are filled with dictionaries. I need to combine the entries if a value from dict2==dict1 and place the newly combined matches somewhere else. I'm having trouble explaining it. List one contains: {'keyword':value, 'keyword2':value2} List two: {'keyword2':value2, 'keyword3':value3} I want a new list with dictionaries including keyword1, keyword2, and keyword3 if both lists share the same 'keyword2' value. What's the best way to do this? When I try, I only come up with tons of nested for loops. Thanks

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• Python. Strange class attributes behavior

  - by Eugene

  >>> class Abcd: ... a = '' ... menu = ['a', 'b', 'c'] ... >>> a = Abcd() >>> b = Abcd() >>> a.a = 'a' >>> b.a = 'b' >>> a.a 'a' >>> b.a 'b' It's all correct and each object has own 'a', but... >>> a.menu.pop() 'c' >>> a.menu ['a', 'b'] >>> b.menu ['a', 'b'] How could this happen? And how to use list as class attribute?

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• how to rename a file using python..

  - by zjm1126

  i want change 'a.txt' to 'b.kml' thanks

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• python domain name split name and extension

  - by bobsr

  How would you split a domain name that will return name and extension

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• Python indentation in "empty lines"

  - by niscy

  Which is preferred ("." indicating whitespace)? A) def foo(): x = 1 y = 2 .... if True: bar() B) def foo(): x = 1 y = 2 if True: bar() My intuition would be B (that's also what vim does for me), but I see people using A) all the time. Is it just because most of the editors out there are broken?

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• Iterating through a range of dates in Python

  - by ShawnMilo

  This is working fine, but I'm looking for any feedback on how to do it better. Right now I think it's better than nested loops, but it starts to get Perl-one-linerish when you have a generator in a list comprehension. Any suggestions are welcome. day_count = (end_date - start_date).days + 1 for single_date in [d for d in (start_date + timedelta(n) for n in range(day_count)) if d <= end_date]: print strftime("%Y-%m-%d", single_date.timetuple()) Notes: I'm not actually using this to print; that's just for demo purposes. The variables start_date and end_date are datetime.date objects, because I don't need the timestamps (they're going to be used to generate a report). I checked the StackOverflow questions which were similar before posting this, but none were exactly the same. Sample Output (for a start date of 2009-05-30 and an end date of 2009-06-09): 2009-05-30 2009-05-31 2009-06-01 2009-06-02 2009-06-03 2009-06-04 2009-06-05 2009-06-06 2009-06-07 2009-06-08 2009-06-09

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• change values in a list - python

  - by ariel

  I have this code: a=[['a','b','c'],['a','f','c'],['a','c','d']] for x in a: for y in x: if 'a' in x: x.replace('a','*')` but the result is: a=[['a','b','c'],['a','f','c'],['a','c','d']] and bot a=[['b','c'],['f','c'],['c','d']] What should I do so the changes will last?

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• eliminating multiple occurrences of whitespace in a string in python

  - by tipu

  If I have a string "this is a string" How can I shorten it so that I only have one space between the words rather than multiple? (The number of white spaces is random) "this is a string"

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