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  • How can I identify an element from a list within another list

    - by Alex
    I have been trying to make a block of code that finds the index of the largest bid for each item. Then I was going to use the index as a way to identify the person who paid that much moneys name. However no matter what i try I can't link the person and what they have gained from the auction together. Here is the code I have been writing: It has to be able to work with any information inputted def sealedBids(): n = int(input('\nHow many people are in the group? ')) z = 0 g = [] s = [] b = [] f = [] w = []#goes by number of items q = [] while z < n: b.append([]) z = z + 1 z = 0 while z < n: g.append(input('Enter a bidders name: ')) z = z + 1 z = 0 i = int(input('How many items are being bid on?')) while z < i: s.append(input('Enter the name of an item: ')) w.append(z) z = z + 1 z = 0 for j in range(n):#specifies which persons bids your taking for k in range(i):#specifies which item is being bid on b[j].append(int(input('How much money has {0} bid on the {1}? '.format(g[j], s[k])))) print(' ') for j in range(n):#calculates fair share f.append(sum(b[j])/n) for j in range(i):#identifies which quantity of money was the largest for each item for k in range(n): if w[j] < b[k][j]: w[j] = b[k][j] q.append(k) any advice is much appreciated.

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  • Selecting Date Range on a PHP form and displaying results from MySQL database

    - by Sarah HSL
    This may be something simple but I cant understand why this wouldn't work.. I have a php form where you can select a date range from drop downs. I've given the field names day, month year, and day1, month1, year1. When clicking submit it takes you to a second php form. Here is the code for second form: <?php $username="***"; $password="***"; $database="****"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> Is there any reason this wouldn't work? I'm not sure where I am going wrong. It displays results when there is another option as well as the date such as 'status' but when this is taken out and I just want to display all the results between the date range it doesn't work.. This works: <?php $username="+++"; $password="+++"; $database="+++"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $status = $_GET['status']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE status = '$status' AND curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> But when the 'status' field is taken out (and obviously the serial drop down in the first form) it stops working...

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  • After append() how to bind a click event to just added element

    - by Pentium10
    I have this code $(".delete2").click(function() { $('#load2').fadeIn(); } I have dynamically added item via this return addSubcategory = function(){ sucategorynameval = $("#sucategoryname").val(); categoryId = $("#addcategoryid").val(); $.get("process-add-subcat.php", { "action": "add_subcategory", "sucategoryname": sucategorynameval, "categoryId":categoryId }, function(data){ //$("#main-cat-"+categoryId).load(location.href+"&pageExclusive=1 #main-cat-"+categoryId+">*",""); $("#main-cat-"+categoryId).append(data); $("#addcategoryid").val(''); $("#sucategoryname").val(''); }); The returned data contains delete2 classed item. How do I apply the click event to the newly added item?

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  • cant find div element in ajax data find

    - by Shrey
    This is my whole Ajax page which is returned <!DOCTYPE div PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <div class="CareerAjaxData">Simple Div Content</div> The jQuery script in the Main page which calls this Ajax page is $.ajax({ type : 'POST', url : url, data : data, datatype : 'html', success : function(ajaxdata) { var $tabcontent = $(ajaxdata).find('.CareerAjaxData'); console.log($tabcontent.html()); } }); But the output of Console gives: undefined I get proper response from the server. But there some problem with js I guess. whats wrong here..??

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  • Binding Data Template element to property on sub-class

    - by TerrorAustralis
    Hi guys, I have a class, for experiment sake call it foo() and another class, call it bar() I have a data template for class foo() defined in my xaml, but one of foo()'s properties is a bar() object such that foo() { Public string Name {get; set;} Public int ID {get; set;} Public bar barProp {get; set;} } and bar() { Public string Description{get; set;} } I want my data template of foo to display the Description property of bar. I have tried the simple <textblock Text="{Binding Path=barProp.Description}" /> and variants to no avail Seeking wisdom, DJ

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  • JQuery modal box form validation

    - by vikitor
    Hi, I was using a view to create an object for my specific project, but now I have to adapt this to another requirements, such as the creation of this object must be integrated in the creation of another one. The thing is, that this object must be created before starting to create the other one, and the way of doing it will be poping up a modal dialog box with JQuery with the form to create it. I've got to adapt the creation and it works fine, except for the validation messages. It is made in the controller like : if (not.NotName.Trim().Length == 0) { ModelState.AddModelError("NotName", "Name is required"); } if (_notification.checkIfExists(not.NotName, not.NotRecID)) { ModelState.AddModelError("NotName", "Notification already exists"); } And before with a normal view it worked fine, but now I'm not able to get the validation messages as I did. How can you get this validation messages thrown by the controller in the Modal Box? Because now when I made a mistake on purpose in the form in order to get the error it doesn't appear. I've seen the error is displayed in the site, because I've seen it on firebug, but it doesn't appear in my model box. How can I retrieve this errors? Do you know any tutorial that could help me with this? Thank you

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  • Xpath problem, getting the id(attribute) of a element, if you know the title of the element.

    - by user577823
    Hi guys, My question is, is it possible to get the Article ID, when you have the title of the article?(via xpath) Articles Article ID="1" title crack /title content blablabalbal /content /Article /Articles Because i am using this right now, it isnt working though. $xml = simplexml_load_file("Articles.xml"); $XElement = new SimpleXMLElement($xml-asXML()); $Articles = $XElement-xpath("Article"); $title = "crack"; $elements = count($Articles); for($i = 0; $i title; if($Titles == $title) //This is not working? i dont know why? { $AID = (string)$Articles[$i][@"ID"]; } }

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  • Ruby on Rails - pass variable to nested form

    - by Krule
    I am trying to build a multilingual site using Rails, but I can't figure out how to pass variable to nested form. Right now I am creating nested form like this. @languages.each do @article.article_locale.build(:language_id => language.id) end But i would like to pass value of language to it so i can distinguish fields. Something like this. @languages.each do |language| @language = language @article.article_locale.build(:language_id => language.id) end However, I always end up with language of the last loop iteration. Any way to pass this variable? -- edit -- In the end, since I've got no answer I have solved this problem so it, at least, works as it should. Following code is my partial solution. In model: def self.languages Language.all end def self.language_name language = [] self.languages.each_with_index do |lang, i| language[i] = lang.longname end return language end In Controller: def new @article = Article.new Article.languages.each do |language| @article.article_locale.build(:language_id => language.id) end end In HAML View: -count = 0 -f.fields_for :article_locale do |al| %h3= Article.language_name[count] -count+=1 -field_set_tag do %p =al.label :name, t(:name) =al.text_field :name %p =al.label :description, t(:description) =al.text_area :description =al.hidden_field :language_id It's not the most elegant solution I suppose, but it works. I would really love if I could get rid of counter in view for instance.

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  • XSLT for-each loop for element collection

    - by brain_pusher
    Is it possible to make a for-each loop in XSLT not for a node set, but for my own collection of elements? For example, I split some string and have a string collection as a result. And I need to create a node for each item in the collection. I know that issue can be solved with a recursive template, but I want to know if it is possible to avoid a recursion.

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  • C#: HTTPWebResponse using application/x-www-form-urlencoded

    - by CSharpened
    So I sent an HTTPWebRequest using application/x-www-form-urlencoded as my content type. I assume that this means the reponse will be returned in a similar type? (EDIT: Have now been told this isn't the case) My question is this. How do I access the different key/value pairs returned in the response. My code so far looks like this. I can of course read the string but surely there is a better way to access the data other than ripping the string apart. HttpWebResponse response = SendPOSTRequest("https://site/page?Service=foo", content.ToString(), "", "", true); string responseCode = response.StatusCode.ToString(); string responseStatusDescription = response.StatusDescription; StreamReader sr = new StreamReader(response.GetResponseStream()); string result = sr.ReadToEnd(); I tried using XML/linq to read the elements into an XDocument but of course it is not being returned in XML form. Assume I have 3 or 4 different pieces of information in there how could I read them out? EDIT: I have just checked and the data is being returned as text/plain. How can this be processed easily? EDIT: The response string once retrieved via a streamreader is: VPSProtocol=2.23 Status=OK StatusDetail=Server transaction registered successfully. VPSTxId={FDC93F3D-FC64-400D-875F-0B7E855AD81F} SecurityKey=***** NextURL=https://foo.com/PaymentPage.asp?TransactionID={875F-0B7E855AD81F}

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  • jQuery, selecting form elements by name, getting: Error: uncaught exception: Syntax error, unrecogni

    - by Mark Steudel
    I'm trying to select an select element by name I found this thread showing how to do it, and I followed it but I'm getting Syntax error. I'm using jquery 1.4.1, here's my code. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>TODO supply a title</title> <script type="text/javascript" src="/js/jquery-1.4.1.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ alert( $('select[@name="country[0]"]').val() ); }) </script> </head> <body> <form> <select name="country[0]"> <option value="23">test</option> </select> </form> </body> </html> Thanks in advance for any insight. MS

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  • jquery accordion - keeps hiding parent element?

    - by PopRocks4344
    Well, I fixed my original question by including after the closing tags, but now, those links won't open? So, basically, in the html below, I'm trying so that only the services section slides open, but I want the h3 tags to open those links... <div id="sp-accordion"> <h3><a href="/?page_id=3">Home</a></h3><div></div> <h3><a href="/?page_id=2">About Us</a></h3><div></div> <h3><a href="#"> Services</a></h3> <div> <p><a href="/?page_id=16">S1</a></p> <p><a href="/?page_id=14">S2</a></p> <p><a href="/?page_id=20">S3</a></p> </div> <h3><a href="/?page_id=9">Contact Us</a></h3><div></div> <h3><a href="/?page_id=5">Tips</a></h3><div></div> <h3><a href="/?page_id=108">Jobs</a></h3><div></div> <h3><a href="/?page_id=131">Newsletter</a></h3><div></div> </div> The accordion works, insomuch that when you click on the h3 tag, the container slides open, however, when it slides open, it hides the h3 before it. So, in the html below, when I click on "Services" the div beneath it slides open, but the About Us h3 disappears... This is the html: <div id="sp-accordion"> <h3><a href="/?page_id=3">Home</a></h3> <h3><a href="/?page_id=2">About Us</a></h3> <h3><a href="#"> Services</a></h3> <div> <p><a href="/?page_id=16">S1</a></p> <p><a href="/?page_id=14">S2</a></p> <p><a href="/?page_id=20">S3</a></p> </div> <h3><a href="/?page_id=9">Contact Us</a></h3> <h3><a href="/?page_id=5">Tips</a></h3> <h3><a href="/?page_id=108">Jobs</a></h3> <h3><a href="/?page_id=131">Newsletter</a></h3> </div> I'm using jquery ui, so the jquery is just this: $(document).ready(function() { $("#sp-accordion").accordion({autoHeight:false}); });

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  • DOM accessing element JS

    - by Michael
    Given the following xml <rss> <channel> ... <pubDate>20/30/2099</pubDate> ... <item> ... <pubDate>10/30/2099</pubDate> ... </item> ... <item> ... <pubDate>40/30/2099</pubDate> ... </item> ... <channel> </rss> how would I efficiently access pudDate in channel and items as array, as well as pudDate in that array.

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  • How to access the element of a list/vector that passed by reference in C++

    - by bsoundra
    Hi all, The problem is passing lists/vectors by reference int main(){ list<int> arr; //Adding few ints here to arr func1(&arr); return 0; } void func1(list<int> * arr){ // How Can I print the values here ? //I tried all the below , but it is erroring out. cout<<arr[0]; // error cout<<*arr[0];// error cout<<(*arr)[0];//error //How do I modify the value at the index 0 ? func2(arr);// Since it is already a pointer, I am passing just the address } void func2(list<int> *arr){ //How do I print and modify the values here ? I believe it should be the same as above but // just in case. } Is the vectors any different from the lists ? Thanks in advance. Any links where these things are explained elaborately will be of great help. Thanks again.

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  • CSS 100 percent height body and element

    - by Tim
    I am having an issue making one of my elements 100% within an overall layout that is 100%. I have tried different positioning solutions and I either end up with hidden content the floats behind the footer at the bottom, or the content ends up going behind the footer, and carrys on after the footer. Here is what I have for the page layout. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en-US"> <head> <style> *{margin:0} html,body{margin:0; padding:0; height:100%} .wrapper{position:relative; margin:0 auto -200px; height:auto !important; height:100%; min-height:100%} .container{width:930px; margin:0 auto; text-align:left} .right{float:right; width:680px; background:#FFF; margin:60px 10px 0 0; padding:0} .left{float:left; width:240px} .content{padding:10px} .footer{position:absolute; width:100%} .footer,.push{height:200px} </style> </head> <body> <div class="wrapper"> left content footer </div> </body> </html> The layout for the page being 100% height and footer at the bottom works it just the div with the class name content that I would like to be 100% as well and push the footer further down if the content reaches the footer and not disappear. Any help most appreciated. http://img686.imageshack.us/img686/7725/screenshotbj.png

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  • How to bind a servlet to a context?

    - by simpatico
    I got javax.servlet.ServletException: Error instantiating servlet class servlets.MemoServlet javax.naming.NameNotFoundException: Name servlets.MemoServlet is not bound in this Context when using <form action="MemoServlet"> I know I could use managedbeans, but I've to use servlets. I suspect the problem has to do with JSF. context.xml: <?xml version="1.0" encoding="UTF-8"?> <Context antiJARLocking="true" path="/MemoWeb/faces"/> web.xml: <servlet-mapping> <servlet-name>MemoServlet</servlet-name> <url-pattern>/faces/MemoServlet</url-pattern> </servlet-mapping> <servlet> <servlet-name>MemoServlet</servlet-name> <servlet-class>servlets.MemoServlet</servlet-class> </servlet> I seem to have this problem all over the place: com.sun.faces.mgbean.ManagedBeanCreationException: An error occurred performing resource injection on managed bean userManager .... Caused by: javax.naming.NameNotFoundException: Name user.UserManager is not bound in this Context

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  • How to insert <li> element on <ul> using pure javascript

    - by Damiii
    I am having an issue with javascript and i don't know how to solve it ... Actually my code is working good with jsfiddle, but when i try to insert on my HTML page ,it simply doesnt work anymore ... What i want to, is to add the < li on < ul each time i tried to hit the button named "Add" ! HTML code: .... <td width="50%" valign="top"> <b> SUPER: </b> <ul id="ul"> </ul> </td> .... <input type="submit" value="Add" onclick="add()"/> .... JavaScript code: <script type="text/javascript"> function add(){ var ul = document.getElementById("ul"); var li = document.createElement("li"); li.innerHTML = "LoL"; ul.appendChild(li); } </script> The result with that code : it doesn't add anything on my HTML page when i try to hit the button... Thankfully,

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  • draggable out the parent element

    - by Luca Romagnoli
    Hi i have 2 div <div style="width:50px;height:100px;overflow:auto" id="outer"> <div class="kind_div">hello</div> </div> i tried the draggable function of jquery ui: $("div.kind_div").draggable({ cursor: 'crosshair', containment: 'document', appendTo: 'body' }); i can drag the kind_div but it remains into the outer div I want drag it in all body of my page how can i do? thanks

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  • How do you reference another element in a xaml list

    - by Ball
    I'm using xaml as a datastore because It's quick and we haven't yet defined a file format. But I can only seem to create xaml that is a pure tree, even if it is acyclic. I know how to create a list of items in xaml, but How do I share objects in two lists? Below is an example of what I'm trying to say. <CreaturFile> <CreatureFile.Monsters> <Monster Name="Kobold" x:Name="Mepo"/> <Monster Name="Goblin"/> </CreatureFile.Monsters> <CreatureFile.Encounters> <Encounter> <Reference ElementName="Mepo"/> </Encounter> </CreatureFile.Encounters> </CreatureFile>

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  • JQuyer slide and stop issues: animated element freezes with quick mouse movement

    - by sherlock
    Here is Zi JsFiddle. In order to replicate my issue you have to hover over the link that says 'javascript', then mouseout that, then mouseback in. If you do this before the animation is complete, the pink slidedown #subMenu will freeze midway through sliding. Is there a way to prevent this from happening? I have tried some .stop()s , but i really don't want the animation to re-start every time you mouseenter or leave the .navLink . The animation should begin from where it left off. In other words, if the pink section is halfway down, and a slideDown() gets executed, the pink should not dissappear and then slide down, it should slide down from where it is. Thanks!! JS: $('header#subHeader').hide(); $('.navLink').hover(function () { if ($(this).children('div').length > 0) { var subMenu = $(this).find('.subMenu').html(); $('header#subHeader').empty().append('<div>' + subMenu + '</div>').stop().slideDown(); } else { $('header#subHeader').stop().slideUp(); } }); $('hgroup:first').on('mouseleave', function(){ $('header#subHeader').slideUp(); });

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  • Get content from HTML element in Rails

    - by Ignace
    Hey, I'm looking for a way to get the content of my div in my Rails view. I would like the literal HTML content, so only HTML and no Rails I thought inner_html would work, but I get a RJS exception (TypeError: $("content").innerHtml is not a function) Does anyone know how I can get the content? Thanks!

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  • How to disable scrolling of body element?

    - by Starx
    How to disable scrolling of body? $('body').css('overflow','hidden'); only hides the scrollbars but it does not disable the scrolling. I want to disable the scrolling of the body. But I want to keep the scrolling of other division intact.

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  • loop is cut one element of the array

    - by Walaa
    The problem is : Write a program that reads a number n and then declares an array of n elements. The program then fills the array with the first n numbers, where each number is two to the power of the previous. Finally, display array’s contents. My code : import java.util.*; public class Q1 { static Scanner scan = new Scanner (System.in); public static void main(String args [] ) { int num; int i = 0; System.out.println("Enter a number :"); num = scan.nextInt(); double [] a=new double[num]; a[0]= num ; for ( ;i<=a.length-1 ; i++) { a[i+1] = Math.pow(2,a[i]); System.out.println((int)(a[i]) ); } } } The error is : ----jGRASP exec: java Q1 Enter a number : 4 4 16 65536 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at Q1.main(Q1.java:16) ----jGRASP wedge2: exit code for process is 1. why it says that? And the number by user printed twice!

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  • Silverlight debugging, no list element view

    - by Snake
    When I'm debugging my Silverlight Appliction and I'm using a list internally I cannot hover over the list and see the items inside the list. I just see the RAW view of the list. If I want to see the items I have to write my own code which is tedious. Is this something normal to Silverlight? I DO have the correct list view when debugging in normal Console/WPF/... applications. Example: Silverlight: (link: click) See how there is no 'list view in the first example? And there in this one: And for non Silverlight: (link: click)

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  • Getting a random element in Django

    - by Sarah
    I just finished the Django tutorial and started work on my own project, however, I seem to have missed something completely. I wanted to get a random slogan from this model: from django.db import models class Slogan(models.Model): slogan = models.CharField(max_length=200) And return it in this view: from django.http import HttpResponse from swarm.sloganrotator.models import Slogan def index(request): return HttpResponse(Slogan.objects.order_by('?')[:1]) However, the view just returns 'Slogan object'. Then I thought, maybe I can access the slogan string itself by simply appending .slogan to the slice, but that gives me an error indicating that the object I have is actually a QuerySet and has no attribute slogan. I've obviously misunderstood something about Django here, but it just doesn't fall into place for me. Any help?

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