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  • mysql left join queries

    - by Mike79
    I have a question about the snippet below. I'm wondering, if the first query doesn't bring any results, would I still get the results for the second query? select * from ( -- first query ) as query1 left join ( -- second query ) as query2 on query1.id=query2.id left join ( -- third query ) as query3 on query1.id=query3.id; Update: what I need is a full join, however, MySQL does not support it, what would be a good way to emulate this?

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  • How to manually build mysql cache

    - by hamstar
    I have a table of over 150,000 rows of which most would be updated daily. I have mysql caching turned on so the pages load faster however everytime the database is updated the pages load slow again, which I assume is the cache building itself again. So at the moment I have resorted to doing a wget -m --delete-after http://localhost/ on the server however this takes about 4 hours to complete and moves something like 13 gig. Is there a better way to do this?

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  • How to version control data stored in mysql

    - by Shawn
    I'm trying to use a simple mysql database but tweak it so that every field is backed up up to an indefinite number of versions. The best way I can illustrate this is by replacing each and every field of every table with a stack of all the values this field has ever had (each of these values should be timestamped). I guess it's kind of like having customized version control for all my data.. Any ideas on how to do this?

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  • php mysql search

    - by mckenzie
    Hello, My code contain SELECT * FROM newchap WHERE company LIKE '%$company%' OR Category LIKE '%$cat%' It works perfectly however, when the field $company contain empty, it return all result in MYSQL. How to prevent it?

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  • Using MySQL variables in a query

    - by Jon Tackabury
    I am trying to use this MySQL query: SET @a:=0; UPDATE tbl SET sortId=@a:=@a+1 ORDER BY sortId; Unfortunately I get this error: "Parameter '@a' must be defined" Is it possible to batch commands into 1 query like this, or do I need to create a stored procedure for this?

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  • How do I generate site map from MySQL database

    - by mathew
    Hi all I am new to Php and working on a project which needs to generate sitemaps from URLS which stored in MySQL database. how can I do this?? Is there any one have any idea?? site maps can be in php extension too and only requirement is list of sites display in each page

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  • MySQL Single Query Benchmarking Strategies

    - by Pepper
    Hello, I have a slow mySQL query in my application that I need to re-write. The problem is, it's only slow on my production server and only when it's not cached. The first time I run it, it will take 12 seconds, then anytime after that it'll be 500 milliseconds. Is there an easy way to test this query without it hitting the query cache so I can see the results of my refactoring? Thanks!

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  • Why would restarting MySQL make my site faster?

    - by beagleguy
    hey all, my site started dragging lately, the queries taking exceptionally longer than I would expect with properly tuned indexes. I just restarted the mysql server after 31 days uptime and every query is now substantially faster and the whole site renders 3-4 times faster. Would there be anything that jumps out at you as to why this may have been? Improper settings on my.cnf perhaps? Any ideas as to what I can start looking at to try and pinpoint why? thanks

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  • mysql IN parameter

    - by proyb2
    When the user check more than one (checkbox) option which are then combine into a string of "apple,orange,pear" SELECT id, pos, FROM $db WHERE dtime>='$now' AND jsub IN ('$arr[1]') ; When I pass the string to $arr[1], it won't work correctly, how do I split into array and get mysql IN function to process correctly?

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  • Mysql change column details

    - by Ankur
    I am trying to redefine the number of varchars a column can have (in a MySQL db). I am doing alter table obj_details IMG_SRC IMG_SRC varchar(180); I want to change the number of characters that can be used in the column IMG_SRC to 180 (it is currently 100). But I get an error saying that I should check the syntax near IMG_SRC IMG_SRC varchar(180).

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  • Permissions done on MySQL side or PHP side?

    - by Kerry
    When I am grabbing data from my table that require permissions, should all the permission be done there? Such as checking for an admin or if they can view the data (in MySQL)? Or should I grab it if they have a record at all, then check the specific actions (such as view, add, edit, delete) on the PHP side?

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  • Saving images in database mysql

    - by xRobot
    My client have created a script in php+mysql that saves images directly in the database and every images has url like this: www.example.com/image.php?id=421 In your opinion this is a very wrong solution ? Should I rebuild all the site ? There are about 1000 visits per day and about 600 images in the database. This is the site: http://tinyurl.com/3xkxdsw

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  • PHP & MySQL - saving and looping problems.

    - by R.I.P.coalMINERS
    I'm new to PHP and MySQL I want a user to be able to store multiple names and there meanings in a MySQL database tables named names using PHP I will dynamically create form fields with JQuery every time a user clicks on a link so a user can enter 1 to 1,000,000 different names and there meanings which will be stored in a table called names. Since I asked my last question I figured out how to store my values from my form using the for loop but every time I loop my values when I add one or more dynamic fields the second form field named meaning will not save the value entered also my dynamic form fields keep looping doubling, tripling and so on the entered values into the database it all depends on how many form fields are added dynamically. I was wondering how can I fix these problems? On a side note I replaced the query with echo's to see the values that are being entered. Here is the PHP code. <?php if(isset($_POST['submit'])) { $mysqli = mysqli_connect("localhost", "root", "", "site"); $dbc = mysqli_query($mysqli,"SELECT * FROM names WHERE userID='$userID'"); $name = $_POST['name']; $meaning = $_POST['meaning']; if(isset($name['0']) && mysqli_num_rows($dbc) == 0 && trim($name['0'])!=='' && trim($meaning['0'])!=='') { for($n = 0; $n < count($name); $n++) { for($m = 0; $m < count($meaning); $m++) { echo $name[$n] . '<br />'; echo $meaning[$m] . '<br /><br />'; break; } } } } ?> And here is the HTML code. <form method="post" action="index.php"> <ul> <li><label for="name">Name: </label><input type="text" name="name[]" id="name" /></li> <li><label for="meaning">Meaning: </label><input type="text" name="meaning[]" id="meaning" /></li> <li><input type="submit" name="submit" value="Save" /></li> </ul> </form> If needed I will place the JQuery code.

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