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  • java annotations - problem with calling a locator class from a Vaadin Project

    - by George
    Hello, I'm not sure how to explain this without writing several pages so I hope the actual code is more expressive. I've made a jar containing multiple annotation declaration similar to the following: @Target(ElementType.PACKAGE) @Retention(RetentionPolicy.RUNTIME) public @interface MarkedPackage { } then I have made a test jar containing several classes in several packages and marked just one package with the above annotation (with package-info.java) like below: @myPackage.MarkedPackage package package.test.jar; this jar had in its build path the jar containing the annotations. then I made a static class that has a method (LoadPlugins) that retrieves a list with all the jars of a directory. Then it searches through the jars for the 'package-info' class and checks if that classes package contains the MarkedPackage annotation. by calling this: if (checkPackageAnnotation(thisClass.getPackage())) where thisClass is the package-info class retrieved via a classloader. and: public static boolean checkPackageAnnotation(AnnotatedElement elem) { System.out.println(elem.getAnnotations().length); if (elem == null || !elem.isAnnotationPresent(MarkedPackage.class)) return false; return true; } the elem.getAnnotatios().length is there for debug purposes. And the problem appears when I call the method from the static class: if I call it from a main function: public class MyMain { public static void main(String[] args){ PluginUtils.LoadPlugins(); } } everything works perfectly it displays '1' from that System.out.println(elem.getAnnotations().length); But if I call it from a button from my Vaadin project: header.addComponent(new Button("CallThat", new Button.ClickListener() { public void buttonClick(ClickEvent event) { PluginUtils.LoadPlugins(); } })); It displays '0' from that System.out.println(elem.getAnnotations().length); Also I should mention that I created the main inside my Vaadin project so it would have the exact same build path and resources. Is there a problem with web applications and that "@Retention(RetentionPolicy.RUNTIME)" ? hope I was clear enough... Hope someone has a solution for me... If you need more information - let me know. Thank you.

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  • On Windows, what filename extensions denote an executable?

    - by Ken
    On Windows, *.exe, *.bat, *.cmd, and *.com all represent programs or shell scripts that can be run, simply by double-clicking them. Are there any other filename extensions that indicate a file is executable? EDIT: When I jump into a new project (or back into an old project!), one of the common things I want to do when looking around is to find out what tools there are. On Unix (which I've used for decades), there's an execute bit, so this is as simple as: find . -executable -type f I figured that on Windows, which seems to have a much more complex mechanism for "is this executable (and how do I execute it)", there would be a relatively small number of file name extensions which would serve roughly the same purpose. For my current project, *.exe *.bat *.cmd is almost certainly sufficient, but I figured I'd ask if there was an authoritative list.

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  • PHP MINISERVER DOWNLOAD RESUME-ERROR! Resource id # 4

    - by snikolov
    $httpsock = @socket_create_listen("9090"); if (!$httpsock) { print "Socket creation failed!\n"; exit; } while (1) { $client = socket_accept($httpsock); $input = trim(socket_read ($client, 4096)); $input = explode(" ", $input); $range = $input[12]; $input = $input[1]; $fileinfo = pathinfo($input); switch ($fileinfo['extension']) { default: $mime = "text/html"; } if ($input == "/") { $input = "index.html"; } $input = ".$input"; if (file_exists($input) && is_readable($input)) { echo "Serving $input\n"; $contents = file_get_contents($input); $output = "HTTP/1.0 200 OK\r\nServer: APatchyServer\r\nConnection: close\r\nContent-Type: $mime\r\n\r\n$contents"; } else { //$contents = "The file you requested doesn't exist. Sorry!"; //$output = "HTTP/1.0 404 OBJECT NOT FOUND\r\nServer: BabyHTTP\r\nConnection: close\r\nContent-Type: text/html\r\n\r\n$contents"; if(isset($range)) { list($a, $range) = explode("=",$range); str_replace($range, "-", $range); $size2 = $size-1; $new_length = $size-$range; $output = "HTTP/1.1 206 Partial Content\r\n"; $output .= "Content-Length: $new_length\r\n"; $output .= "Content-Range: bytes $range$size2/$size\r\n"; } else { $size2=$size-1; $output .= "Content-Length: $new_length\r\n"; } $chunksize = 1*(1024*1024); $bytes_send = 0; $file = "a.mp3"; $filesize = filesize($file); if ($file = fopen($file, 'r')) { if(isset($range)) $output = 'HTTP/1.0 200 OK\r\n'; $output .= "Content-type: application/octet-stream\r\n"; $output .= "Content-Length: $filesize\r\n"; $output .= 'Content-Disposition: attachment; filename="'.$file.'"\r\n'; $output .= "Accept-Ranges: bytes\r\n"; $output .= "Cache-Control: private\n\n"; fseek($file, $range); $download_rate = 1000; while(!feof($file) and (connection_status()==0)) { $var_stat = fread($file, round($download_rate *1024)); $output .= $var_stat;//echo($buffer); // is also possible flush(); sleep(1);//// decrease download speed } fclose($file); } /** $filename = "dada"; $file = fopen($filename, 'r'); $filesize = filesize($filename); $buffer = fread($file, $filesize); $send = array("Output"=$buffer,"filesize"=$filesize,"filename"=$filename); $file = $send['filename']; */ //@ob_end_clean(); // $output .= "Content-Transfer-Encoding: binary"; //$output .= "Connection: Keep-Alive\r\n"; } socket_write($client, $output); socket_close ($client); } socket_close ($httpsock); hey guys i have create a miniwebserver downloader it can download files from your server, however i am unable to resume my download when i download the file i get Resource id # 4 and also i cant resume the download,i would like to know how i can monitor record the client output how much bandwidth he has downloaded perl has something like this put its hardcore if possible kindly provide me with some pointers thank you :)

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  • QueryHistory against a codeplex project hangs indefinitely

    - by Robaticus
    I'm working on a TFS utility that gets the changesets for a particular project in TFS. I've got a home TFS 2010 server which I primarily use for testing, but I decided to give it a try against a codeplex project to which I contribute. That way, I can test functionality against a larger number of changesets than I have locally. While it works fine in my environment, heading out over the wire to codeplex has left me stumped. My application queries the history, but then, when trying to iterate through the history (which is when it lazy-loads the IEnumerable), my application hangs. Looking at Intellitrace, I see a couple of "first chance" exceptions that the "item doesn't exist at the specified version"-- which is patently not true, as I'm trying to get history for "$/" at VersionSpec.Latest. I also see two or three consecutive server 500 errors being returned to me after forcing debugging to pause. Other operations (like GetItems() ) work fine, so I'm pretty sure authentication isn't an issue. Any thoughts? Here's the code: IEnumerable items = vcs.QueryHistory("$/", VersionSpec.Latest, 1, RecursionType.None, null, null, null, 5, true, false); List<ChangesetItem> returnList = new List<ChangesetItem>(); foreach (Changeset cs in items) //hangs here on first iteraiton { ChangesetItem newItem = new ChangesetItem() { ChangesetId = cs.ChangesetId, //ChangesetNote = cs.CheckinNote.Values[0].Value, Comment = cs.Comment, Committer = cs.Committer, CreationDate = cs.CreationDate }; returnList.Add(newItem); }

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  • Auto populate input based on file name with AngularJS

    - by LouieV
    I am playing around with AngularJS and have not been able to solve this problem. I have a view that has a form to upload a file to a node server. So far I have manage to do this using some directives and a service. I allow the user to send a custom name to the POST data if they desire. What I wan to accomplish is that when the user selects a file the filename models auto populates. My view looks like: <div> <input file-model="phpFile" type="file"> <input name="filename" type="text" ng-model="filename"> <button ng-click="send()">send</button> </div> file-model is my directive that allows the file to be assigned to a scope. myApp.directive('fileModel', ['$parse', function($parse) { return { restrict: 'A', link: function(scope, element, attrs) { var model = $parse.(attrs.fileModel); var modelSetter = model.assign; element.bind('change', function() { scope.$apply(function() { modelSetter(scope, element[0].files[0]); }); }); } }]); The service: myApp.service('fileUpload', ['$http', function($http){ this.uploadFileToUrl = function(file, uploadUrl, optionals) { var fd = new FormData(); fd.append('file', file); for (var key in file) { fd.append(key, file[key]); } for(var i = 0; i < optionals.length; i++){ fd.append(optionals[i].name, optionals[i].data); } }); }]); Here as you can see I pass the file, append its properties, and append any optional properties. In the controller is where I am having the troubles. I have tried $watch and using the file-model but I get the same error either way. myApp.controller('AddCtrl', function($scope, $location, PEberry, fileUpload){ //$scope.$watch(function() { // return $scope.phpFile; //},function(newValue, oldValue) { // $scope.filename = $scope.phpFile.name; //}, true); // if ($scope.phpFiles) { // $scope.filename = $scope.phpFiles.name; // } $scope.send = function() { var uploadUrl = "/files"; var file = $scope.phpFile; //var opts = [{ name: "uname", data: file.name }] fileUpload.uploadFileToUrl(file, uploadUrl); }; }); Thank you for your help!

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  • How do I turn an array of bytes back into a file and open it automatically with C#?

    - by Ace Grace
    Hi, I am writing some code to add file attachments into an application I am building. I have add & Remove working but I don't know where to start to implement open. I have an array of bytes (from a table field) and I don't know how to make it automatically open e.g. If I have an array of bytes which is a PDF, how do I get my app to automatically open Acrobat or whatever the currently assigned application for the extension is using C#?

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  • Ruby: output not saved to file

    - by Sophie
    I'm trying to give a file as input, have it changed within the program, and save the result to a file that is output. But the output file is the same as the input file. :/ Total n00b question, but what am I doing wrong?: puts "Reading Celsius temperature value from data file..." num = File.read("temperature.dat") celsius = num.to_i farenheit = (celsius * 9/5) + 32 puts "Saving result to output file 'faren_temp.out'" fh = File.new("faren_temp.out", "w") fh.puts farenheit fh.close

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  • PHP mini-server download resulme-error! Resource id # 4

    - by snikolov
    <?php $httpsock = @socket_create_listen("9090"); if (!$httpsock) { print "Socket creation failed!\n"; exit; } while (1) { $client = socket_accept($httpsock); $input = trim(socket_read ($client, 4096)); $input = explode(" ", $input); $range = $input[12]; $input = $input[1]; $fileinfo = pathinfo($input); switch ($fileinfo['extension']) { default: $mime = "text/html"; } if ($input == "/") { $input = "index.html"; } $input = ".$input"; if (file_exists($input) && is_readable($input)) { echo "Serving $input\n"; $contents = file_get_contents($input); $output = "HTTP/1.0 200 OK\r\nServer: APatchyServer\r\nConnection: close\r\nContent-Type: $mime\r\n\r\n$contents"; } else { //$contents = "The file you requested doesn't exist. Sorry!"; //$output = "HTTP/1.0 404 OBJECT NOT FOUND\r\nServer: BabyHTTP\r\nConnection: close\r\nContent-Type: text/html\r\n\r\n$contents"; if(isset($range)) { list($a, $range) = explode("=",$range); str_replace($range, "-", $range); $size2 = $size-1; $new_length = $size-$range; $output = "HTTP/1.1 206 Partial Content\r\n"; $output .= "Content-Length: $new_length\r\n"; $output .= "Content-Range: bytes $range$size2/$size\r\n"; } else { $size2=$size-1; $output .= "Content-Length: $new_length\r\n"; } $chunksize = 1*(1024*1024); $bytes_send = 0; $file = "a.mp3"; $filesize = filesize($file); if ($file = fopen($file, 'r')) { if(isset($range)) $output = 'HTTP/1.0 200 OK\r\n'; $output .= "Content-type: application/octet-stream\r\n"; $output .= "Content-Length: $filesize\r\n"; $output .= 'Content-Disposition: attachment; filename="'.$file.'"\r\n'; $output .= "Accept-Ranges: bytes\r\n"; $output .= "Cache-Control: private\n\n"; fseek($file, $range); $download_rate = 1000; while(!feof($file) and (connection_status()==0)) { $var_stat = fread($file, round($download_rate *1024)); $output .= $var_stat;//echo($buffer); // is also possible flush(); sleep(1);//// decrease download speed } fclose($file); } /** $filename = "dada"; $file = fopen($filename, 'r'); $filesize = filesize($filename); $buffer = fread($file, $filesize); $send = array("Output"=>$buffer,"filesize"=>$filesize,"filename"=>$filename); $file = $send['filename']; */ //@ob_end_clean(); // $output .= "Content-Transfer-Encoding: binary"; //$output .= "Connection: Keep-Alive\r\n"; } socket_write($client, $output); socket_close ($client); } socket_close ($httpsock); Hey guys, I haved create a miniwebserver downloader. It can download files from your server. However, I am unable to resume my download when I download the file – I get Resource id # 4 – and I also can't resume the download. I would like to know how I can monitor and record the client output and how much bandwidth he has downloaded. Perl has something like this, but it's hardcore; if possible, kindly provide me with some pointers thank you :)

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  • Where in maven project's path should I put configuration files that are not considered resources

    - by Paralife
    I have a simple java maven project. One of my classes when executing needs to load an xml configuration file from the classpath. I dont want to package such xml file when producing the jar but I want to include a default xml file in a zip assemply under a conf subfolder and I also want this default xml to be available in the unit tests to test against it. As I see it there are 2 possible places of this default xml: src/main/resources/conf/default.xml src/main/conf/default.xml Both solutions demand special pom actions: In solution 1, I get the auto copy to target folder during build which means it is available in testing but I also get it in the produced jar which i dont want. In solution 2, I get the jar as I want it(free of the xml) but I manually have to copy the xml to the target folder to be available for testing. (I dont want to add src's subfolders in test classpath. I think it is bad practice). The question is what is the best solution of the two? If the correct is 2, what is the best way to copy it to target folder? Is there any other solution better and more common than those two? (I also read http://stackoverflow.com/questions/465001/where-should-i-put-application-configuration-files-for-a-maven-project but I would like to know the most "correct solution" from the "convention over configuration" point of view and this link provides some configuration type solutions but not any convention oriented. Maybe there isnt one but I ask anyway. Also the solutions provided include AntRun plugin and appAssembler plugin and I wonder if I could do it with out them.)

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  • Visual Studio project remains "stuck" when stopped

    - by Traveling Tech Guy
    Hi, Currently developing a connector DLL to HP's Quality Center. I'm using their (insert expelative) COM API to connect to the server. An Interop wrapper gets created automatically by VStudio. My solution has 2 projects: the DLL and a tester application - essentially a form with buttons that call functions in the DLL. Everything works well - I can create defects, update them and delete them. When I close the main form, the application stops nicely. But when I call a function that returns a list of all available projects (to fill a combo box), if I close the main form, VStudio still shows the solution as running and I have to stop it. I've managed to pinpoint a single function in my code that when I call, the solution remains "hung" and if I don't, it closes well. It's a call to a property in the TDC object get_VisibleProjects that returns a List (not the .Net one, but a type in the COM library) - I just iterate over it and return a proper list (that I later use to fill the combo box): public List<string> GetAvailableProjects() { List<string> projects = new List<string>(); foreach (string project in this.tdc.get_VisibleProjects(qcDomain)) { projects.Add(project); } return projects; } My assumption is that something gets retained in memory. If I run the EXE outside of VStudio it closes - but who knows what gets left behind in memory? My question is - how do I get rid of whatever calling this property returns? Shouldn't the GC handle this? Do I need to delve into pointers? Things I've tried: getting the list into a variable and setting it to null at the end of the function Adding a destructor to the class and nulling the tdc object Stepping through the tester function application all the way out, whne the form closes and the Main function ends - it closes, but VStudio still shows I'm running. Thanks for your assistance!

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  • Symfony and uploadify

    - by Thomas
    Hi! I want to use uploadify with Symfony 1.4, but so far I couldn't. Uploadify loads correctly, I choose my files, it says that the files were successfully uploaded, but the are nowhere. (I'm doing this on localhost) Is there anybody who met this problem before? Thanks, Tom $file = $request->getParameter('file'); $filename = sha1($file->getOriginalName()).$file->getExtension($file->getOriginalExtension()); $file->save(sfConfig::get('sf_upload_dir').'/'.$filename);

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  • Can I create a new project based on GNU GPL v2?

    - by Jared Pearson
    I've found a SourceForge project with a solid core that I would like to improve. The project hasn't been updated since 2007 so I assume it is "dead". I sent an e-mail asking to become a contributor to the listed project manager last week but still haven't received a response. The project is licensed under the GNU GPL v2. I would like to contribute to the current project but that doesn't appear to be possible. Can I modify the current source version of the project and release this modified project? I would keep the same license on the modified project.

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  • How to export each open project in Eclipse as its own JAR?

    - by Freiheit
    I have several projects open in an Eclipse workspace. Like so: com.harbl.project.one com.harbl.project.two com.harbl.project.three I would like to export those as JARs in a batch such that I wind up with the following JAR files: ./com.harbl.project.one.jar ./com.harbl.project.two.jar ./com.harbl.project.three.jar Is this possible with one of the Eclipse wizards or working sets? Is my only option to export each one individually?

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  • Why does adding a reference to project targeting .NET Framework 4.0 fail?

    - by Malcolm Post
    We have two projects that are both class libraries. Project 1 is a VS 2008 project and targets the .NET Framework 3.5. Project 2 is a VS 2010 (release candidate) project that targets the .NET Framework 4.0. When I try to add a reference to Project 2 in Project 1, it fails with a less than informative error message. I know that if I change the target Framework for Project 2 to 3.5, then adding the reference will work. My question is, if I don't change the target frameworks, but convert Project 1 to VS 2010, will the referencing work? Stated another way, is there some inherent incompatiblity between class libraries targeting different framework versions, or is it failing for me because VS 2008 doesn't know about the 4.0 framework?

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  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

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  • resources at class library project

    - by Night Walker
    Hello I want to add some xml file as resource to my class library project . Any idea how to do so , and call it later? In windows application i would do it like ClassLibrary1.Properties.Resources.file.xml But here it didn't worked any idea how i do it here ?

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  • Can I create a new project based on an abandoned one licenced under GNU GPL v2?

    - by Jared Pearson
    I've found a SourceForge project with a solid core that I would like to improve. The project hasn't been updated since 2007 so I assume it is "dead". I sent an e-mail asking to become a contributor to the listed project manager last week but still haven't received a response. The project is licensed under the GNU GPL v2. I would like to contribute to the current project but that doesn't appear to be possible. Can I modify the current source version of the project and release this modified project? I would keep the same license on the modified project.

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  • C# Interop.Word Adding an Image from project resource folder

    - by iamnobody
    Hi guys. Having some image problem with Interop.Word and C#. I want to add an image in the header of the document that I am going to generate. I have this code working perfectly section.Headers[Word.WdHeaderFooterIndex.wdHeaderFooterPrimary].Shapes.AddPicture(@"C:\Logo.jpg", ref x, ref x, ref x, ref x, ref x, ref x, ref x); Problem is that I can't have "C:\Logo.jpg" in the code since after publishing the project, there would most probably be no Logo.jpg in the C folder of the user. The image is already in my project's resource folder. I've used Image.FromFile("Logo.jpg") before but .AddPicture requires a string and not an image. Any ideas? Any help would be greatly appreciated. Thanks! -- edit -- Saw this over the net: string anyPath = @"C:\logo.jpg"; Properties.Resources.logo.Save(anyPath); section.Headers.[...].Shapes.AddPicture(anyPath, ... but then I still get a generic error in GDI+ or ExternalException was unhandled.

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  • iPhone Network Share Access

    - by user361988
    I am trying to download a data file from a local network share to an iPhone device. I have placed the file on a computer on the network and can view through browsers such as Chrome or Mozilla, from any computer on the local network. However, Safari on a Mac and the iPhone do not find the file! An example of the URL I use is 'file://computer/SharedDocs/file.csv'. Why do Safari and the iPhone fail to find the file?

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