Search Results

Search found 88154 results on 3527 pages for 'encrypting code'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 185/3527 | < Previous Page | 181 182 183 184 185 186 187 188 189 190 191 192  | Next Page >

  • How do call this symbolic code transformation ?

    - by erric
    Hi, I often cross this kind of code transformation (or even mathematical transformation) (python example, but applies to any language) I've go a function def f(x): return x I use it into another one. def g(x): return f(x)*f(x) print g(2) leads to 4 But I want to remove the functional dependency, and I change the function g into def g(f): return f*f print g( f(2) ) leads to 4 too How do you call this kind of transformation, locally turning a function into a scalar ?

    Read the article

  • Code example with annotation in JavaDoc

    - by John
    Hello, my JavaDoc doesn't work when I have a code example with an annotation. Any suggestions? /** * <pre> * public class Demo { * @DemoAnnotation * public void demoMethod() { * } * } * </pre> */ @Retention(RetentionPolicy.RUNTIME) @Target({ElementType.METHOD}) public @interface DemoAnnotation {

    Read the article

  • C++ code snippet for a new baby greeting card

    - by uvts_cvs
    A friend of mine sent me this code snippet to celebrate his new baby birth: void new_baby_name() { father_surname++; } The snippet is from his point of view, he is the father and the new baby get the surname from him. I answered with this: class father_name {}; class mother_name {}; class new_baby_name: public father_name, public mother_name {}; but I am not fully satisfied of my answer...

    Read the article

  • Code formatting when using pointers

    - by HD-VRSCA
    Is there any reason why the asterisk is next to the object type in this code? I'm a little confused by the way I see this used. Some times it looks like this: NSString* stringBefore; and sometimes like this: NSString *stringBefore; Is there a difference? Or a right or wrong way to do this? Thanks

    Read the article

  • Is external JavaScript source available to scripting context inside HTML page?

    - by John K
    When an external JavaScript file is referenced, <script type="text/javascript" src="js/jquery-1.4.4.min.js"></script> is the JavaScript source (lines of code before interpretation) available from the DOM or window context in the current HTML page? I mean by using only standard JavaScript without any installed components or tools. I know tools like Firebug trace into external source but it's installed on the platform and likely has special ability outside the context of the browser sandbox.

    Read the article

  • Code is not running on .click of hyperlink

    - by coffeeaddict
    Code is not running on .click when I have this: $(".cancel").click(function() { alert("got here"); $(this).closest(":dialog").dialog("close"); }); <a class="cancel" href=""><img src="images/cancelButton.gif" border="0" /></a> It's got to be something stupid, but I cannot see it.

    Read the article

  • regex for zip-code

    - by Monu
    I need Regex which can satisfy all my three condtions for zip-code. E.g- 12345 12345-6789 12345 1234 Any pointers and suggestion would be much appreciated. Thanks !

    Read the article

  • What does this pointer-heavy C code do?

    - by justRadojko
    Could someone explain to me what should two following lines do: s.httpheaderline[s.httpheaderlineptr] = *(char *)uip_appdata; ++((char *)uip_appdata); This is taken from uIP code for microcontrollers. s - structure httpheaderline - http packet presented as a string httpheadrlineptr - integer value uip_appdata - received ethernet packet (string) If some more info is needed please let me know. BTW. Eclipse is reporting an error on the second line with message Invalid lvalue in increment so i'm trying to figure out how to solve this.

    Read the article

  • comment code in netbeans?

    - by ajsie
    a while ago i could comment any code in php with netbeans like this: /* * * */ I just typed /* ENTER and netbeans gave me that lines above. then when i typed @ it gave me a full list of all available tags (author, param and so on). i reinstalled my mac and since then it hasnt worked. someone knows why and how i can activate it? i installed the netbeans for php only.

    Read the article

  • Taking over someone else's code

    - by tom d
    I am taking over someone elses code. What are some good ways to learn what that programmer did as quickly as possible? I have been running it, stepping through it and looking at the callstack. What else can I do? Sorry I forgot to mention, but there is little documentation and I have been trying to fix simple problems. Thanks!

    Read the article

  • node.js: encrypting data that needs to be decrypted?

    - by fancy
    We are using bcrypt for passwords and data that never needs to be decrypted. What should do to protect other user information that does. For this example lets say that we didn't want a users real name to be in plain text in case someone was to obtain the db. This is somewhat sensitive data but also needs to be called from time to time and displayed in plain text. Is there a simple way to do this?

    Read the article

  • What is wrong in this c++ code?

    - by narayanpatra
    Why this coder do not show error #include <iostream> int main() { using namespace std; unsigned short int myInt = 99; unsigned short int * pMark = 0; cout << myInt << endl; pMark = &myInt; *pMark = 11; cout << "*pMark:\t" << *pMark << "\nmyInt:\t" << myInt << endl; return 0; } But this one shows : #include<iostream> using namespace std; int addnumber(int *p, int *q){ cout << *p = 12 << endl; cout << *q = 14 << endl; } #include<iostream> using namespace std; int addnumber(int *p, int *q){ cout << *p = 12 << endl; cout << *q = 14 << endl; } int main() { int i , j; cout << "enter the value of first number"; cin >> i; cout << "enter the value of second number"; cin >> j; addnumber(&i, &j); cout << i << endl; cout << j << endl; } In both the code snippets, I am assigning *pointer=somevalue. In first code it do not show any error but it shows error in the line cout << *p = 12 << endl; cout << *q = 14 << endl; What mistake I am doing ?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 181 182 183 184 185 186 187 188 189 190 191 192  | Next Page >