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  • Twisted: how-to bind a server to a specified IP address? (solved)

    - by daccle
    I want to have a twisted service (started via twistd) which listens to TCP/POST request on a specified port on a specified IP address. By now I have a twisted application which listens to port 8040 on localhost. It is running fine, but I want it to only listen to a certain IP address, say 10.0.0.78. How-to manage that? This is a snippet of my code: application = service.Application('SMS_Inbound') smsInbound = resource.Resource() smsInbound.putChild('75sms_inbound',ReceiveSMS(application)) smsInboundServer = internet.TCPServer(8001, webserver.Site(smsInbound)) smsInboundServer.setName("SMS Handling") smsInboundServer.setServiceParent(application)

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  • asp.net global resources problem

    - by Bystrik Jurina
    Hello. I have a weird problem with global resources in my asp.net mvc web application. I have some resources in separate project(not a web app project). Those resources have following settings: Build action: Embedded Resource, Copy To Output Directory: Do not copy, Custom Tool: ResXFileCodeGenerator. When I change an existing value in resource file, build solution in release mode and upload neccesary dll files back to server, the previous values in resources are still shown. However, when I add a new key into resource file, the value of this key is shown properly. I do not have this problem during debugging on localhost. Thanks

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  • oomla.. GoDaddy.. FileZilla ... :S

    - by user282659
    have created a a website in my localhost computer using Joomla Now I want to launch the site into the web.. So I brought a domain from GoDaddy.com .. Im a newbie into this and I was using This Tutorial in order to set up the website... Now Im Stuck in the Step 08 Which asks to upload some files into the web host directory... I used FileZilla as my FTP Client .. When I give the host name and the password, Port number as 21 and try to login it says.. Connection Timed Out.. and says.. Could Not Connect to server . Plase explain m on how to use the FileZilla.. And Solve th above problem ..

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  • What is wrong with selecting with my drop down element.

    - by Babiker
    <html> <head> <script type='text/javascript' language='javascript' src="http://localhost/javascript/jquery-1.4.2.js"> </script> <script type='text/javascript' language='javascript'> $(document).ready(function(){ $("#button").mousedown(function(){ dropDownMenu = $("#dropDownMenu"); alert(dropDownMenu.options[0].text); }); }); </script> </head> <body> <select id="dropDownMenu"><option>Test</option></select><br> <input id="button" type="button"> </body> </html>

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  • PHP loop position

    - by Jordan Pagaduan
    Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: $dbc = mysql_connect("localhost" , "root" , "") or die (mysql_error()); mysql_select_db('blog_data') or die (mysql_error()); $sql = "SELECT * FROM img_uploaded"; $result = mysql_query($sql); while($rows=mysql_fetch_array($result)) { if ($rows) { echo "<tr><td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td></tr>"; } else { echo "<td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td>"; } }

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  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

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  • how to get values sent by location.replace(URL)

    - by kawtousse
    hi everyone, In my javascript function I do livke this in order to redirect parameters to servlet: var ids1=document.getElementById("projet").value; document.location.href("http://localhost:8080/Opc_Web_App/ServletAffectation?ids1="+ids1); and in the servlet I do the following to get Value: String idprojet= request.getParameter("projet"); System.out.println("le projet selectionné est :" +idprojet); the problem that i didnt have the result of System.out.print in my screen; so in other terms the servlet didn't get the parameter. I can not see the problemn untill now. Please help. Thank you.

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  • Why is my upload-of-a-file code putting 2 sets of files into my directory? (PHP)

    - by ggfan
    When I upload a file using this code, it puts a copy of the file in the "uploads" folder(which is what I want) but it also puts a copy in my root. I only want the files going to the uploads folder. define ('GW_UPLOADPATH', 'uploads/'); $upfile= GW_UPLOADPATH . $_FILES['userfile']['name']; if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { if(!move_uploaded_file($_FILES['userfile']['tmp_name'], $upfile)) //this is saying if the file isn't moved to $upfile. { echo 'Problem: could not move file to destination directory'; exit; } } else { echo 'Problem: Possible file upload attack. Filename: '; //this could be an attack b/c it might be from localhost. echo $_FILES['userfile']['name']; exit; } echo 'File uploaded successfully<br><br>';

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  • How to display Youtube videos in a jQuery lightbox (Wordpress)?

    - by janoChen
    I tried lightbox-plus, fancybox, etc... But I couldn't figure how to do it. Those videos are images posts with a link containing a Youtube video: <p><a href="http://www.youtube.com/watch?v=zUN826BdvV4"> <img class="alignnone size-thumbnail wp-image-40" title="Screenshot" src="http://localhost/custom-post-type/ wp-content/uploads/2011/01/Screenshot2-150x150.png" alt="" width="150" height="150" /></a></p> Fancybox for Wordpress, for example, let me add a lightbox to images, but if the image links to a Youtube video it doesn't work. Any suggestions?

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  • Jquery mobile function calls before Ajax Request end

    - by rpmlins
    Here is my problem. When My Home page shows, I call the LoadUser functions, which on success, sets the globalUser variable with the returned json, and after it loads I call the alert function but it says globalUser is undefined. I have tried many other work arounds, but I always get the undefined mesage. If I call the alert(globalUser); on the success function, it works as expected alerting the object. $('#Home').live('pageshow', function(event) { $.when(LoadUser()).done(function(a1) { alert(globalUser); }); }); function LoadUser() { $.ajax({ // connects with the web service and validate de user input url: "http://localhost:51396/Icademy.asmx/GetUser", contentType: "application/json; charset=utf-8", data: { "userName": "'rodrigo'" }, dataType: "jsonp", success: function(json) { globalUser = JSON.parse(json.d); return globalUser; }, error: function(ret) { alert("Um erro ocorreu, tente novamente mais tarde."); } }); }

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  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

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  • Getting an Ajax response from Zend Framework Controller

    - by JavaLava
    I'm doing an Ajax request on one of my views to a Controller but I am unable to send back a response to the Ajax method. In the snippet below, I am trying to send the word 'hellopanda' back but in the alert message, I'll get data as an object. View : $.ajax({ type: "POST", url: "localhost/some-activity", data: dataString, success: function(data) { alert( "Data is: " + data); //do something with data }, error: function(data){ alert( "Data is: " + data); //do something with data }, onComplete: function(){ } }); Controller: public function someActivityAction(){ //do stuff echo "hellopanda"; } I'm pretty sure the echo is the problem. Any insights on to how to do a proper response to the view would be greatly appreciated.

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  • WCF service code in window application

    - by Mariya
    Hello, I am using C#.net application code. I require to call service for Window Application and i am using below code to open service Host, using (ServiceHost host = new ServiceHost( typeof(class1), new Uri[] { new Uri("net.pipe://localhost") }) ) { } & Then we have clinet Console application to connect to serviceHost. Problem is, When i create service/Client application Using Conslole Application both are working fine. But if i call servide code form Window application to connect to console client it gives Error for Binding Error like("No End Point/Address found to test") Can any one help me to run service from C# window application ? Thanks

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  • Array to string conversion in (cant get it to work)

    - by user2966551
    ok I am trying to pull a a specific row of data that corresponds to the username logged in. on my page I have started my session but for some reason I cant get the code to work.i keep getting a "Array to string conversion in " on the line " WHERE username = '$_SESSION[user]'");" what am I doing wrong? if I set username = a set username it works but I need it to draw from the session id so it will display different values based on whos logged in. <?php $con=mysqli_connect("localhost","root","xxx","xxxx"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $result = mysqli_query($con,"SELECT * FROM users WHERE username = '$_SESSION[user]'"); while($row = mysqli_fetch_array($result)) { echo $row['username'] . " " . $row['att']; echo "<br>"; } ?>

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

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  • Facing difficulty in moving the two id's

    - by user1806560
    By means of <?php echo $productlist->productid;?> in href i am passing the productid,its fine based on that i can able to display the items. The url is looking like this when i am passing like this http://localhost/sample/index.php/userlogin/items/35 . <ul class="left_menu"> <li class="odd"><a href="<?php echo BASE_INDEX_URL;?>/userlogin/items/<?php echo $productlist->productid;?>"> <?php echo $productlist->productname; ?> </a></li> </ul> My model is taking the value like this public function items($productid=0) { } But i want to pass one more id as categoryid in the href, how can i do that My model is taking the value like this(for 2 parameters) public function items($productid=0,$categoryid=0) { }

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  • Shell Prompt Line Wrapping Issue

    - by Rob
    I've done something to break my Bash Shell Prompt in OS X (10.5.7) Terminal. This is the PS1 that I had configured: PS1='\[\e[1;32m\]\h\[\e[0m\]:\[\e[1;34m\]\w\[\e[0m\]\$ ' As far as I can tell I have the color commands escaping correctly. However when I scroll up and down in my command history I often get line wrapping issues if the historic commands wrap onto multiple lines. I simplified my prompts to the following: PS1='\[\e[1m\]\h:\w\$ \[\e[0m\]' PS2='> ' And I still see something like: localhost:~/Library/Application Support/Firefox/Profiles/knpmxpup.Defau lt/extensions/{1A2D0EC4-75F5-4c91-89C4-3656F6E44B68}$ expocd \{1A2D0EC4-7 5F5-4c91-89C4-3656F6E export PS1="\[ \e[1;32m\]\h\[\e[0m\]: cd Library/Appl ication\ Support/ I've also tried \033 instead of \e. I just included PS2 up there for information, I haven't changed that from the install default. If I completely remove the color codes then everything works fine, any ideas?

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  • SEND VALUE TO SERVLET WITH THE JAVASCRIPT

    - by kawtousse
    hi everyone, In my JavaScript function I do like this in order to redirect parameters to servlet: var ids1=document.getElementById("projet").value; document.location.href("http://localhost:8080/Opc_Web_App/ServletAffectation?ids1="+ids1); and in the servlet I do the following to get Value: String idprojet= request.getParameter("ids1"); System.out.println("le projet selectionné est :" +idprojet); the problem that i didn't have the result of System.out.print in my screen; so in other terms the servlet didn't get the parameter. I can not see the problem until now. Please help. Thank you.

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  • Best way to utilise an include file which just includes an array in PHP

    - by alex
    Kohana's config files look like this.. here is an example of a database config file (simplified) return array( 'dbhost' => 'localhost', 'user' => 'Tom_Jones' ); I've also got a CMS which wants the connection details. Whilst the CMS uses a different user (with more rights), I'd like to know the best way to include this file and get the data out of it (so as to not repeat myself for hostname and dbname). I haven't thought up of any elegant solutions yet and have not yet dug around Kohana to see how it does it. It's late Friday here so it's probably really obvious to everyone except me. UPDATE My apologies, I forgot to include that this is using Kohana 3!

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  • In the context of an asp.net website, what's the most efficient way to check whether a User has acce

    - by scaramouch
    I have a webpage that you pass in an id parameter (via a querystring), which it then uses to fetch data from a database. Typically, a user would navigate to this page from another page that lists only those records that the user has access to. However, if they go directly to the page by typing in the URL in the Address Bar, they can effectively view any record they like. Eg. If they were to type something like http://localhost/TestSite/ClientAdmin/ManageLocation.aspx?LocationID=5 into their Address Bar, they can access the database record with the LocationID equal to five - even though they shouldn't have access to it. Now, I could solve this by doing a database check every time the page is loaded to see whether the current user has access to the record they're trying to view. However this doesn't seem very efficient given that in most cases a user won't be trying to access a record that isn't theirs. Does anyone have a better suggestion? Thanks.

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  • How do I set up gaeunit 2.0a with my Django app?

    - by J. Frankenstein
    I am trying to set up Google App Engine unit testing for my web application. I downloaded the file from here. I followed the instructions in the readmen by copying the directory gaeunit into the directory with the rest of my apps and registering 'gaeunit' in settings.py. This didn't seem sufficient to actually get things going. I also stuck url('^test(.*)', include('gaeunit.urls')) into my urls.py file. When I go to the url http://localhost:8000/test, I get the following error: [Errno 2] No such file or directory: '../../gaeunit/test' Any suggestions? I'm not sure what I've done wrong. Thanks!

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  • xmlhttprequest vs jquery load();

    - by testkhan
    i am trying to making php ajax based chat system....and i have developed it successfully...i am using jquery load() with setInterval to reload chat every 1 second and it works fine on my localhost....but when i uploaded it on my hosting server it also works fine ... but problem is that after few mintues of chat the server takes to much long gets heavy loaded so that my server goes and and site goes down... my question is that, why it is happening so far...and what is the solution...should i use standard xmlhttprequest instead of load() or $.ajax() instead of load();

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  • Symfony on virtual host (document root problem)

    - by Martin Sikora
    Hello, I'm developing an application in Symfony and on localhost (XAMPP) I want to simulate the same conditions as on the webserver. The web server is configured as follows: /www => mydomain.com /foo => foo.mydomain.com /bar => bar.mydomain.com ... I'm going to put my Symfony application into /www direcotry so there'll be: /www /www/apps /www/apps/frontend /www/apps/frontend/... /www/apps/backend /www/apps/backend/... /www/cache /www/config ... and so on... /www/web The thing is that the document root is still set to the /www directory but Symfony expects it in the /www/web. Of course it will work if I call http://mydomain.com/web but I guess you understand this is quiet stupid solution. So my question is: Is there any way how can I change/bypass the default document root setting using .htaccess or whatever?

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  • Send value to servlet with javascript

    - by kawtousse
    hi everyone, In my JavaScript function I do like this in order to redirect parameters to servlet: var ids1=document.getElementById("projet").value; document.location.href("http://localhost:8080/Opc_Web_App/ServletAffectation?ids1="+ids1); and in the servlet I do the following to get Value: String idprojet= request.getParameter("ids1"); System.out.println("le projet selectionné est :" +idprojet); the problem that i didn't have the result of System.out.print in my screen; so in other terms the servlet didn't get the parameter. I can not see the problem until now. Please help. Thank you.

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