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  • SQL Server 05, which is optimal, LIKE %<term>% or CONTAINS() for searching large column

    - by Spud1
    I've got a function written by another developer which I am trying to modify for a slightly different use. It is used by a SP to check if a certain phrase exists in a text document stored in the DB, and returns 1 if the value is found or 0 if its not. This is the query: SELECT @mres=1 from documents where id=@DocumentID and contains(text, @search_term) The document contains mostly XML, and the search_term is a GUID formatted as an nvarchar(40). This seems to run quite slowly to me (taking 5-6 seconds to execute this part of the process), but in the same script file there is also this version of the above, commented out. SELECT @mres=1 from documents where id=@DocumentID and textlike '%' + @search_term + '%' This version runs MUCH quicker, taking 4ms compared to 15ms for the first example. So, my question is why use the first over the second? I assume this developer (who is no longer working with me) had a good reason, but at the moment I am struggling to find it.. Is it possibly something to do with the full text indexing? (this is a dev DB I am working with, so the production version may have better indexing..) I am not that clued up on FTI really so not quite sure at the moment. Thoughts/ideas?

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  • SQL SERVER – DMV – sys.dm_exec_query_optimizer_info – Statistics of Optimizer

    - by pinaldave
    Incredibly, SQL Server has so much information to share with us. Every single day, I am amazed with this SQL Server technology. Sometimes I find several interesting information by just querying few of the DMV. And when I present this info in front of my client during performance tuning consultancy, they are surprised with my findings. Today, I am going to share one of the hidden gems of DMV with you, the one which I frequently use to understand what’s going on under the hood of SQL Server. SQL Server keeps the record of most of the operations of the Query Optimizer. We can learn many interesting details about the optimizer which can be utilized to improve the performance of server. SELECT * FROM sys.dm_exec_query_optimizer_info WHERE counter IN ('optimizations', 'elapsed time','final cost', 'insert stmt','delete stmt','update stmt', 'merge stmt','contains subquery','tables', 'hints','order hint','join hint', 'view reference','remote query','maximum DOP', 'maximum recursion level','indexed views loaded', 'indexed views matched','indexed views used', 'indexed views updated','dynamic cursor request', 'fast forward cursor request') All occurrence values are cumulative and are set to 0 at system restart. All values for value fields are set to NULL at system restart. I have removed a few of the internal counters from the script above, and kept only documented details. Let us check the result of the above query. As you can see, there is so much vital information that is revealed in above query. I can easily say so many things about how many times Optimizer was triggered and what the average time taken by it to optimize my queries was. Additionally, I can also determine how many times update, insert or delete statements were optimized. I was able to quickly figure out that my client was overusing the Query Hints using this dynamic management view. If you have been reading my blog, I am sure you are aware of my series related to SQL Server Views SQL SERVER – The Limitations of the Views – Eleven and more…. With this, I can take a quick look and figure out how many times Views were used in various solutions within the query. Moreover, you can easily know what fraction of the optimizations has been involved in tuning server. For example, the following query would tell me, in total optimizations, what the fraction of time View was “reference“. As this View also includes system Views and DMVs, the number is a bit higher on my machine. SELECT (SELECT CAST (occurrence AS FLOAT) FROM sys.dm_exec_query_optimizer_info WHERE counter = 'view reference') / (SELECT CAST (occurrence AS FLOAT) FROM sys.dm_exec_query_optimizer_info WHERE counter = 'optimizations') AS ViewReferencedFraction Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL DMV, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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  • SQL SERVER – Introduction to FIRST _VALUE and LAST_VALUE – Analytic Functions Introduced in SQL Server 2012

    - by pinaldave
    SQL Server 2012 introduces new analytical functions FIRST_VALUE() and LAST_VALUE(). This function returns first and last value from the list. It will be very difficult to explain this in words so I’d like to attempt to explain its function through a brief example. Instead of creating a new table, I will be using the AdventureWorks sample database as most developers use that for experiment purposes. Now let’s have fun following query: USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: What’s the most interesting thing here is that as we go from row 1 to row 10, the value of the FIRST_VALUE() remains the same but the value of the LAST_VALUE is increasing. The reason behind this is that as we progress in every line – considering that line and all the other lines before it, the last value will be of the row where we are currently looking at. To fully understand this statement, see the following figure: This may be useful in some cases; but not always. However, when we use the same thing with PARTITION BY, the same query starts showing the result which can be easily used in analytical algorithms and needs. Let us have fun through the following query: Let us fun following query. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: Let us understand how PARTITION BY windows the resultset. I have used PARTITION BY SalesOrderID in my query. This will create small windows of the resultset from the original resultset and will follow the logic or FIRST_VALUE and LAST_VALUE in this resultset. Well, this is just an introduction to these functions. In the future blog posts we will go deeper to discuss the usage of these two functions. By the way, these functions can be applied over VARCHAR fields as well and are not limited to the numeric field only. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • mysqld_safe Can't log to error log and syslog at the same time. Remove all --log-error configuration options for --syslog to take effect

    - by photon
    When I'm trying to install MySQL 5.5 community edition on my Ubuntu 10.04 by compiling the source code, I met the following problem: $ fg % 1 sudo ../bin/mysqld_safe --basedir=/usr/local/mysql_community_5.5/data --user=mysql --defaults-file=/etc/my.cnf [sudo] password for linnan: Sorry, try again. [sudo] password for linnan: 121023 09:26:21 mysqld_safe Can't log to error log and syslog at the same time. Remove all --log-error configuration options for --syslog to take effect. Internal program error (non-fatal): unknown logging method '/usr/local/mysql_community_5.5/log/mysql.log' 121023 09:26:21 mysqld_safe Logging to '/var/log/mysql/error.log'. Internal program error (non-fatal): unknown logging method '/usr/local/mysql_community_5.5/log/mysql.log' 121023 09:26:22 mysqld_safe Starting mysqld daemon with databases from /var/lib/mysql 121023 09:26:23 mysqld_safe mysqld from pid file /var/lib/mysql/ubuntu.pid ended It seems that the problem is related to log configuration. I've noticed a bugfix related to this problem: http://bugs.mysql.com/bug.php?id=50083 But I still have no idea how to solve it. The relative content in /etc/my.cnf: [mysqld] port = 3306 socket = /tmp/mysql.sock skip-external-locking key_buffer_size = 384M max_allowed_packet = 1M table_open_cache = 512 sort_buffer_size = 2M read_buffer_size = 2M read_rnd_buffer_size = 8M myisam_sort_buffer_size = 64M thread_cache_size = 8 query_cache_size = 32M # Try number of CPU's*2 for thread_concurrency thread_concurrency = 8 character-set-server=utf8 [mysqld-safe] basedir=/usr/local/mysql_community_5.5 datadir=/usr/local/mysql_community_5.5/data mysqld_safe_syslog.cnf: /etc/mysql/conf.d/mysqld_safe_syslog.cnf: [mysqld_safe] syslog

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  • How to make shortcut link for a website for each browser?

    - by metal gear solid
    I want to make a shortcut link for same website for each browser is it possible. For example: I have 5 link shortcut on windows desktop for Superuser.com and PC has all browsers installed. Upon double clicking on shortcut: Shortcut one should be open in IE (Which is default browser) Shortcut two should be open in Firefox Shortcut two should be open in Safari Shortcut two should be open in Opera

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  • Configured MySQL for SSL , but SLL is still not in use..!

    - by Sunrays
    I configured SSL for MySQL using the following script. #!/bin/bash # mkdir -p /root/abc/ssl_certs cd /root/abc/ssl_certs # echo "--> 1. Create CA cert, private key" openssl genrsa 2048 > ca-key.pem echo "--> 2. Create CA cert, certificate" openssl req -new -x509 -nodes -days 1000 -key ca-key.pem > ca-cert.pem echo "--> 3. Create Server certificate, key" openssl req -newkey rsa:2048 -days 1000 -nodes -keyout server-key.pem > server-req.pem echo "--> 4. Create Server certificate, cert" openssl x509 -req -in server-req.pem -days 1000 -CA ca-cert.pem -CAkey ca-key.pem -set_serial 01 > server-cert.pem echo "" echo echo "" echo "--> 5. Create client certificate, key. Use DIFFERENT common name then server!!!!" echo "" openssl req -newkey rsa:2048 -days 1000 -nodes -keyout client-key.pem > client-req.pem echo "6. Create client certificate, cert" openssl x509 -req -in client-req.pem -days 1000 -CA ca-cert.pem -CAkey ca-key.pem -set_serial 01 > client-cert.pem exit 0 The following files were created: ca-key.pem ca-cert.pem server-req.pem server-key.pem server-cert.pem client-req.pem client-key.pem client-cert.pem Then I combined server-cert.pem and client-cert.pem into ca.pem (I read in a post to do so..) I created a ssl user in MySQL: GRANT ALL ON *.* to sslsuer@hostname IDENTIFIED BY 'pwd' REQUIRE SSL; Next I added the following in my.cnf [mysqld] ssl-ca = /root/abc/ssl_certs/ca.pem ssl-cert = /root/abc/ssl_certs/server-cert.pem ssl-key = /root/abc/ssl_certs/server-key.pem After restarting the server,I connected to mysql but SSL was still not in use :( mysql -u ssluser -p SSL: Not in use Even the have_ssl parameter was still showing disabled.. :( mysql> show variables like '%ssl%'; +---------------+---------------------------------------------+ | Variable_name | Value | +---------------+---------------------------------------------+ | have_openssl | DISABLED | | have_ssl | DISABLED | | ssl_ca | /root/abc/ssl_certs/ca.pem | | ssl_capath | | | ssl_cert | /root/abc/ssl_certs/server-cert.pem | | ssl_cipher | | | ssl_key | /root/abc/ssl_certs/server-key.pem | +---------------+---------------------------------------------+ Have I missed any step, or whats wrong.. Answers with missed steps in detail will be highly appreciated..

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  • Ubuntu, user can't write to a directory and I don't see why not.

    - by Peter
    I've got a directory, /var/www/someProject/backup/mysql, and I want the user mysql to write to it. Each time I try to write to it with the mysql user, I get a "can't read/write" error. Yet the directory is 777 as you can see here: drwxrwxrwx 2 aUser users 4096 2010-03-17 17:14 mysql I also tried to chown the directory to mysql:mysql, just like the home dir of the mysql user, but no luck, that changed nothing. What am I doing wrong here? Or is the mysql user limited to his home dir in some other way in Ubuntu? Been bugging me for days now, this problem so any help greatly appreciated.

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  • connection to apache server switches sockets connection

    - by Newben
    I have just post a question but I post an other one because the problem is not the one I had in thought when asking the latter. So, I am running some rails app on osx, when I run rails s, everything works fine. If I shut down the apache server (mamp) and if I run rails s again, I have this message Can't connect to local MySQL server through socket '/Applications/MAMP/tmp/mysql/mysql.sock', which for sure is normal. For info, my mamp server is running, and the connection must pass through /Applications/MAMP/Library/bin/mysql, so I aliased it by setting in my bash profile : alias mysql="/Applications/MAMP/Library/bin/mysql" Now, when I launch a rails generate command type, I get this message : /$root/vendor/bundle/ruby/2.0.0/gems/mysql2-0.3.11/lib/mysql2/client.rb:44:in `connect': Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2) (Mysql2::Error) So how it can be ?

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  • How to I set what browser Adobe Reader uses to open links?

    - by Sindri
    I have a Windows XP computer with Chrome set as the default browser. However whenever I click a link embedded in a pdf document I'm viewing with Adobe Reader 8.2.1 I get a popup security warning asking if this is ok, and then the Reader opens the link in IE. Is there a way to change Adobe Readers default browser?

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  • How can give privilege for DB to a user [ ERROR 1044 (42000): Access denied for user ''@'localhost']

    - by Ahn
    I have created user in mysql 5.1 and given the ALL privilege, details given below, mysql> show GRANTS FOR test; +-------------------------------------------------------------+ | Grants for test@% | +-------------------------------------------------------------+ | GRANT ALL PRIVILEGES ON *.* TO 'test'@'%' WITH GRANT OPTION | | GRANT ALL PRIVILEGES ON `tt`.* TO 'test'@'%' | +-------------------------------------------------------------+ 2 rows in set (0.00 sec) But the show databases is not showing the databases on the mysql. It only shows as given below. How can give privilege for other DB s tables as well for the user 'test'? mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | test | +--------------------+ Error while I tried to use the mysql DB as user test: mysql> use mysql; ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'mysql'

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  • Trouble Starting MySL Community Server on Windows 7

    - by CodeAngel
    I have installed Netbeans 7 on my Windows 7. In addition, the MySQL Community Server 5.6.12 is installed with the MSI installer on thesame 7 PC. The MySQL server is integrated with the Netbeans IDE. However , it is not possible to start or stop the MySQL server from the command prompt or the Netbeans IDE. I am only able to start or stop the server from the Windows 7 services tool. Also , it is difficult running SQL queries from the Netbeans IDE even though it shows there is connection with the MySQL server. I have added the my.ini file to the installed directory of the MySQL server , that is : C:\Program Files\MySQL\MySQL Server 5.6 below is the my.ini file : # For advice on how to change settings please see # http://dev.mysql.com/doc/refman/5.6/en/server-configuration-defaults.html # *** DO NOT EDIT THIS FILE. It's a template which will be copied to the # *** default location during install, and will be replaced if you # *** upgrade to a newer version of MySQL. [mysqld] # Remove leading # and set to the amount of RAM for the most important data # cache in MySQL. Start at 70% of total RAM for dedicated server, else 10%. # innodb_buffer_pool_size = 128M # Remove leading # to turn on a very important data integrity option: logging # changes to the binary log between backups. # log_bin # These are commonly set, remove the # and set as required. # basedir = ..... # datadir = ..... port = 3306 # server_id = ..... # Remove leading # to set options mainly useful for reporting servers. # The server defaults are faster for transactions and fast SELECTs. # Adjust sizes as needed, experiment to find the optimal values. # join_buffer_size = 128M # sort_buffer_size = 2M # read_rnd_buffer_size = 2M sql_mode=NO_ENGINE_SUBSTITUTION,STRICT_TRANS_TABLES Any suggestion is welcomed.

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  • Do you play Sudoku ?

    - by Gilles Haro
    Did you know that 11gR2 database could solve a Sudoku puzzle with a single query and, most of the time, and this in less than a second ? The following query shows you how ! Simply pass a flattened Sudoku grid to it a get the result instantaneously ! col "Solution" format a9 col "Problem" format a9 with Iteration( initialSudoku, Step, EmptyPosition ) as ( select initialSudoku, InitialSudoku, instr( InitialSudoku, '-' )        from ( select '--64----2--7-35--1--58-----27---3--4---------4--2---96-----27--7--58-6--3----18--' InitialSudoku from dual )    union all    select initialSudoku        , substr( Step, 1, EmptyPosition - 1 ) || OneDigit || substr( Step, EmptyPosition + 1 )         , instr( Step, '-', EmptyPosition + 1 )      from Iteration         , ( select to_char( rownum ) OneDigit from dual connect by rownum <= 9 ) OneDigit     where EmptyPosition > 0       and not exists          ( select null              from ( select rownum IsPossible from dual connect by rownum <= 9 )             where OneDigit = substr( Step, trunc( ( EmptyPosition - 1 ) / 9 ) * 9 + IsPossible, 1 )   -- One line must contain the 1-9 digits                or OneDigit = substr( Step, mod( EmptyPosition - 1, 9 ) - 8 + IsPossible * 9, 1 )      -- One row must contain the 1-9 digits                or OneDigit = substr( Step, mod( trunc( ( EmptyPosition - 1 ) / 3 ), 3 ) * 3           -- One square must contain the 1-9 digits                            + trunc( ( EmptyPosition - 1 ) / 27 ) * 27 + IsPossible                            + trunc( ( IsPossible - 1 ) / 3 ) * 6 , 1 )          ) ) select initialSudoku "Problem", Step "Solution"    from Iteration  where EmptyPosition = 0 ;   The Magic thing behind this is called Recursive Subquery Factoring. The Oracle documentation gives the following definition: If a subquery_factoring_clause refers to its own query_name in the subquery that defines it, then the subquery_factoring_clause is said to be recursive. A recursive subquery_factoring_clause must contain two query blocks: the first is the anchor member and the second is the recursive member. The anchor member must appear before the recursive member, and it cannot reference query_name. The anchor member can be composed of one or more query blocks combined by the set operators: UNION ALL, UNION, INTERSECT or MINUS. The recursive member must follow the anchor member and must reference query_name exactly once. You must combine the recursive member with the anchor member using the UNION ALL set operator. This new feature is a replacement of this old Hierarchical Query feature that exists in Oracle since the days of Aladdin (well, at least, release 2 of the database in 1977). Everyone remembers the old syntax : select empno, ename, job, mgr, level      from   emp      start with mgr is null      connect by prior empno = mgr; that could/should be rewritten (but not as often as it should) as withT_Emp (empno, name, level) as        ( select empno, ename, job, mgr, level             from   emp             start with mgr is null             connect by prior empno = mgr        ) select * from   T_Emp; which uses the "with" syntax, whose main advantage is to clarify the readability of the query. Although very efficient, this syntax had the disadvantage of being a Non-Ansi Sql Syntax. Ansi-Sql version of Hierarchical Query is called Recursive Subquery Factoring. As of 11gR2, Oracle got compliant with Ansi Sql and introduced Recursive Subquery Factoring. It is basically an extension of the "With" clause that enables recursion. Now, the new syntax for the query would be with T_Emp (empno, name, job, mgr, hierlevel) as       ( select E.empno, E.ename, E.job, E.mgr, 1 from emp E where E.mgr is null         union all         select E.empno, E.ename, E.job, E.mgr, T.hierlevel + 1from emp E                                                                                                            join T_Emp T on ( E.mgr = T.empno ) ) select * from   T_Emp; The anchor member is a replacement for the "start with" The recursive member is processed through iterations. It joins the Source table (EMP) with the result from the Recursive Query itself (T_Emp) Each iteration works with the results of all its preceding iterations.     Iteration 1 works on the results of the first query     Iteration 2 works on the results of Iteration 1 and first query     Iteration 3 works on the results of Iteration 1, Iteration 2 and first query. So, knowing that, the Sudoku query it self-explaining; The anchor member contains the "Problem" : The Initial Sudoku and the Position of the first "hole" in the grid. The recursive member tries to replace the considered hole with any of the 9 digit that would satisfy the 3 rules of sudoku Recursion progress through the grid until it is complete.   Another example :  Fibonaccy Numbers :  un = (un-1) + (un-2) with Fib (u1, u2, depth) as   (select 1, 1, 1 from dual    union all    select u1+u2, u1, depth+1 from Fib where depth<10) select u1 from Fib; Conclusion Oracle brings here a new feature (which, to be honest, already existed on other concurrent systems) and extends the power of the database to new boundaries. It’s now up to developers to try and test it and find more useful application than solving puzzles… But still, solving a Sudoku in less time it takes to say it remains impressive… Interesting links: You might be interested by the following links which cover different aspects of this feature Oracle Documentation Lucas Jellema 's Blog Fibonaci Numbers

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  • MySQL - ODBC Data Connector

    - by Stuart Brierley
    Having previsouly installed and then configured MySQL, you may now need to install the ODBC Data Connector driver in order to connect to your MySQL database. Following the Splash screen the first thing to choose is the Setup Type for your installation.  As usual I chose custom so that I could see the components that were actually being installed.  In this case the custom set up screen allows you to choose to install the driver and the documentation. Finally you can complete the installation Assuming it completes okay you have now installed the MySQL ODBC driver. My intention for installing all these MySQL components is so that I can now attempt to get BizTalk 2009 talking to the MySQL database for a solution that I am currently working on.  For this I will next be looking at the Community ODBC Adapter.

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  • SQL Query Builder/Designer and code Formating

    - by DavRob60
    I write SQL query every now and then, I could easily write them freehand, but sometimes I do create SQL queries using SQL Query Designers for various reason. (I wont start to enumerate them here and/or argue about their usefulness, so let's just say they are sometime useful.) Anyway, I currently use 2 Query Designers : SQL server management studio's Query Designer. Visual Studio 2010's Query Builder (must often within the Table adapter Query Configuration Wizard.) There's something I hate about those two (I don't know about the others), it's the way they throw away my Code formatting of SQL queries after an edit. Is there any way to configure something to automatically reformat the SQL output or is there any external tool/plug-in that I could use to do that job?

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  • How to install mysql?

    - by batman
    I tried mysql in my command line : I get : The program 'mysql' is currently not installed. You can install it by typing: sudo apt-get install mysql-client-core-5.5 But when I do: sudo apt-get install mysql-client-core-5.5 But I get: Reading package lists... Done Building dependency tree Reading state information... Done mysql-client-core-5.5 is already the newest version. 0 upgraded, 0 newly installed, 0 to remove and 47 not upgraded. I'm very much confused! Thanks in advance.

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  • Updating query results

    - by Francisco Garcia
    Within a DDD and CQRS context, a query result is displayed as table rows. Whenever new rows are inserted or deleted, their positions must be calculated by comparing the previous query result with the most recent one. This is needed to visualize with an animation new or deleted rows. The model of my view contains an array of the displayed query results. But I need a place to compare its contents against the latest query. Right now I consider my model view part of my application layer, but the comparison of two query result sets seems something that must be done within the domain layer. Which component should cache a query result and which one compare them? Are view models (and their cached contents) supposed to be in the application layer?

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  • query in codeIgniter style

    - by troy
    I have below query: SET @sql = NULL ; SELECT GROUP_CONCAT( DISTINCT CONCAT( 'select latitude,longitude,max(serverTime) as serverTime,', deviceID, ' AS device from d', deviceID, '_gps' ) SEPARATOR ' UNION ALL ' ) INTO @sql FROM devices WHERE accountID =2; PREPARE stmt FROM @sql ; EXECUTE stmt; Can someone help me to write the above query in codeIgniter style.... ANd another thing is :What is the difference between writing the query in 1 and 2 formats 1. $query = $this->db->query('YOUR QUERY HERE'); 2. $this->db->select("..."); $this->db->from(); $this->db->where(); Will it have any effect on performance if we use 2nd style... Thank You

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  • Webmatrix fails to connect PHP website to MySQL

    - by Roni
    I downloaded the latest versions of Webmatrix and MySQL. I downloaded a PHP-MySQL Connector: http://dev.mysql.com/downloads/connector/php-mysqlnd/ In the "Databases" Workspace I pressed "New Connection" button and choose "MySQL Connection" In the Dialog box I filled-in all connection details -- It looks like the database was added. But then when I double-click on the database, I get a short error message saying it cannot connect. I tried everything, searched the web... I'm sure it's a very simple question, so please whoever can help I'll be grateful. I think best solution for me would be if someone could please just give me a link to download of: Webmatrix,MySQL,Connector; and instructions on how to install and then how to connect. This would be the safest way to help me.

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  • MySQL User Group Meeting in Madrid, Spain

    - by Lenka Kasparova
    We are pleased to announce another MySQL User Group meeting scheduled for June 5 in Madrid, Spain. Keith Hollman, the MySQL Principal Sales Consultant will be talking about MySQL & Oracle strategy and MySQL Cluster. A small demo of MySQL Cluster will be part of the presentation.  Details about the event: Date: June 5, 2014 Time: 7:00 pm-8:30 pm Place: Edificio Telefonica, Gran via 28, Madrid, Entrada por C/ Valverde 2 We are looking forward to seeing you in Madrid! See more information & registration.

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  • How to make a tree view from MySQL and PHP and jquery

    - by Mac Taylor
    hey guys i need to show a treeview of my categories , saved in my mysql database . Database table : table : cats : columns: id,name,parent Here is a sample of what I want the markup to be like: <ul id="browser" class="filetree"> <li><span class="folder">Folder 1</span> <ul> <li><span class="file">Item 1.1</span></li> </ul> </li> <li><span class="folder">Folder 2</span> <ul> <li><span class="folder">Subfolder 2.1</span> <ul id="folder21"> <li><span class="file">File 2.1.1</span></li> <li><span class="file">File 2.1.2</span></li> </ul> </li> <li><span class="file">File 2.2</span></li> </ul> </li> <li><span class="file">File 4</span></li> </ul> i used this script to show treeview : http://www.dynamicdrive.com/dynamicindex1/treeview now problem is in php part : //function to build tree menu from db table test1 function tree_set($index) { global $menu; $q=mysql_query("select * from cats where parent='$index'"); if(!mysql_num_rows($q)) return; $menu .= '<ul>'."\n"; while($arr=mysql_fetch_assoc($q)) { $menu .= '<li>'; $menu .= '<span class="file">'.$arr['name'].'</span>';//you can add another output there $menu .=tree_set("".$arr['id'].""); $menu .= '</li>'."\n"; } $menu.= '</ul>'."\n"; return $menu; } //variable $menu must be defined before the function call $menu = ' <link rel="stylesheet" href="modules/Topics/includes/jquery.treeview.css" /> <script src="modules/Topics/includes/lib/jquery.cookie.js" type="text/javascript"></script> <script src="modules/Topics/includes/jquery.treeview.js" type="text/javascript"></script> <script type="text/javascript" src="modules/Topics/includes/demo/demo.js"></script> <ul id="browser" class="filetree">'."\n"; $menu .= tree_set(0); $menu .= '</ul>'; echo $menu; i even asked in this forum : http://forums.tizag.com/showthread.php?p=60649 problem is in php part of my codes that i mentioned . i cant show sub menus , i mean , really i dont know how to show sub menus is there any chance of a pro php coder helping me here ?

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  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

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