Search Results

Search found 20677 results on 828 pages for 'python team'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 186/828 | < Previous Page | 182 183 184 185 186 187 188 189 190 191 192 193  | Next Page >

  • Python Attributes and Inheritance

    - by user368186
    Say I have the folowing code: class Class1(object): def __init__(self): self.my_attr = 1 self.my_other_attr = 2 class Class2(Class1): def __init__(self): super(Class1,self).__init__() Why does Class2 not inherit the attributes of Class1?

    Read the article

  • Python 2.7 creating a multidimensional list

    - by poop
    I don't know why I am having so much trouble creating a 3 dimensional list. I need the program to create an empty n by n list. So for n = 4: x = [[[],[],[],[]],[[],[],[],[]],[[],[],[],[]],[[],[],[],[]]] I've tried using: y = [n*[n*[]]] y = [[[]]* n for i in range(n)] Which both appear to be creating copies of a reference. I've also tried naieve application of the list builder with little success: y = [[[]* n for i in range(n)]* n for i in range(n)] y = [[[]* n for i in range(1)]* n for i in range(n)] I've also tried building up the array iteratively using loops, with no success. In my rapid flurry of attempts to not post something stupidly easy to SO, I came upon a solution: y = [] for i in range(0,n): y.append([[]*n for i in range(n)]) Is there an easier/ more intuitive way of doing this?

    Read the article

  • Selecting dictionary items by key efficiently in Python

    - by user248237
    suppose I have a dictionary whose keys are strings. How can I efficiently make a new dictionary from that which contains only the keys present in some list? for example: # a dictionary mapping strings to stuff mydict = {'quux': ..., 'bar': ..., 'foo': ...} # list of keys to be selected from mydict keys_to_select = ['foo', 'bar', ...] The way I came up with is: filtered_mydict = [mydict[k] for k in mydict.keys() \ if k in keys_to_select] but I think this is highly inefficient because: (1) it requires enumerating the keys with keys(), (2) it requires looking up k in keys_to_select each time. at least one of these can be avoided, I would think. any ideas? I can use scipy/numpy too if needed.

    Read the article

  • python and regular expression with unicode

    - by bsn
    I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

    Read the article

  • Search inside dynamic array in python

    - by user2091683
    I want to implement a code that loops inside an array that its size is set by the user that means that the size isn't constant. for example: A=[1,2,3,4,5] then I want the output to be like this: [1],[2],[3],[4],[5] [1,2],[1,3],[1,4],[1,5] [2,3],[2,4],[2,5] [3,4],[3,5] [4,5] [1,2,3],[1,2,4],[1,2,5] [1,3,4],[1,3,5] and so on [1,2,3,4],[1,2,3,5] [2,3,4,5] [1,2,3,4,5] Can you help me implement this code?

    Read the article

  • How can i optimize this python code

    - by RandomVector
    def maxVote(nLabels): count = {} maxList = [] maxCount = 0 for nLabel in nLabels: if nLabel in count: count[nLabel] += 1 else: count[nLabel] = 1 #Check if the count is max if count[nLabel] > maxCount: maxCount = count[nLabel] maxList = [nLabel,] elif count[nLabel]==maxCount: maxList.append(nLabel) return random.choice(maxList) nLabels contains a list of integers. The above function returns the integer with highest frequency, if more than one have same frequency then a randomly selected integer from them is returned. E.g. maxVote([1,3,4,5,5,5,3,12,11]) is 5

    Read the article

  • Noob Python Question: List Confusion

    - by potatocubed
    I'm trying to transfer the contents of one list to another, but it's not working and I don't know why not. My code looks like this: list1 = [1, 2, 3, 4, 5, 6] list2 = [] for item in list1: list2.append(item) list1.remove(item) But if I run it my output looks like this: >>> list1 [2, 4, 6] >>> list2 [1, 3, 5] My question is threefold, I guess: Why is this happening, how do I make it work, and am I overlooking an incredibly simple solution like a 'move' statement or something?

    Read the article

  • Python point lookup (coordinate binning?)

    - by Rince
    Greetings, I am trying to bin an array of points (x, y) into an array of boxes [(x0, y0), (x1, y0), (x0, y1), (x1, y1)] (tuples are the corner points) So far I have the following routine: def isInside(self, point, x0, x1, y0, y1): pr1 = getProduct(point, (x0, y0), (x1, y0)) if pr1 >= 0: pr2 = getProduct(point, (x1, y0), (x1, y1)) if pr2 >= 0: pr3 = getProduct(point, (x1, y1), (x0, y1)) if pr3 >= 0: pr4 = getProduct(point, (x0, y1), (x0, y0)) if pr4 >= 0: return True return False def getProduct(origin, pointA, pointB): product = (pointA[0] - origin[0])*(pointB[1] - origin[1]) - (pointB[0] - origin[0])*(pointA[1] - origin[1]) return product Is there any better way then point-by-point lookup? Maybe some not-obvious numpy routine? Thank you!

    Read the article

  • Python: Closing a for loop by reading stdout

    - by user1732102
    import os dictionaryfile = "/root/john.txt" pgpencryptedfile = "helloworld.txt.gpg" array = open(dictionaryfile).readlines() for x in array: x = x.rstrip('\n') newstring = "echo " + x + " | gpg --passphrase-fd 0 " + pgpencryptedfile os.popen(newstring) I need to create something inside the for loop that will read gpg's output. When gpg outputs this string gpg: WARNING: message was not integrity protected, I need the loop to close and print Success! How can I do this, and what is the reasoning behind it? Thanks Everyone!

    Read the article

  • Python - Submit Information on a Website to Extract Data from Resulting Page

    - by bloodstorm17
    So I am trying to figure out how to post on a website that uses a drop down menu which is holding the values like this (based on the page source): <td valign="top" align="right"><span class="emphasis">Select Item Option : </span></td> <td align="left"> <span class="notranslate"> <select name="ItemOption1"> <option value="">Select Item Option</option> <option value="321_cba">Item Option 1</option> <option value="123_abcd">Item Option 2</option> ... Now there are two of these drop down menus on top of each other. I want to be able to select an item from drop down menu 1 and drop down menu 2 and then submit the page. Now based on the code it submits the information using the following code: <td colspan="2" align="center"> <input type="submit" value="View Result" onclick="return check()"> </td> </tr> </table> <input type="hidden" name="ItemOption1" value=""> <input type="hidden" name="ItemOption2" value=""> I have no idea how to select the items in the drop down menu and then submit the page and capture the information on the resulting page into a text file. Can someone please help me with this?

    Read the article

  • Recurrent yearly date alert in Python

    - by coulix
    Hello Hackerz, Here is the idea A user can set a day alert for a birthday. (We do not care about the year of birth) He also picks if he wants to be alerted 0, 1, 2, ou 7 days (Delta) before the D day. Users have a timezone setting. I want the server to send the alerts at 8 am on the the D day - deleta +- user timezone Example: 12 jun, with "alert me 3 days before" will give 9 of Jun. My idea was to have a trigger_datetime extra field saved on the 'recurrent event' object. Like this a cron Job running every hour on my server will just check for all events matching irs current time hour, day and month and send to the alert. The problem from a year to the next the trigger_date could change ! If the alert is set on 1st of March, with a one day delay that could be either 28 or 29 of February .. Maybe i should not use the trigger date trick and use some other kind of scheme. All plans are welcome.

    Read the article

  • A way to use Python which I don't know

    - by Konie
    In this quicksort function: def qsort2(list): if list == []: return [] else: pivot = list[0] # can't understand the following line lesser, equal, greater = partition(list[1:], [], [pivot], []) return qsort2(lesser) + equal + qsort2(greater) def partition(list, l, e, g): if list == []: return (l, e, g) else: head = list[0] if head < e[0]: return partition(list[1:], l + [head], e, g) elif head > e[0]: return partition(list[1:], l, e, g + [head]) else: return partition(list[1:], l, e + [head], g) I don't understand the sentence below the comment. Can someone tell me what is the meaning of this sentence here?

    Read the article

  • python check value not in unicode list

    - by John
    Hi, I have a list and a value and want to check if the value is not in the list. list = [u'first record', u'second record'] value = 'first record' if value not in list: do something however this is not working and I think it has something to do with the list values having a u at the start, how can I fix this? And before someone suggests the list is returned from Django queryset so I can't just take the u out of the code :) Thanks

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 182 183 184 185 186 187 188 189 190 191 192 193  | Next Page >