Search Results

Search found 14016 results on 561 pages for 'mysql 5 5'.

Page 187/561 | < Previous Page | 183 184 185 186 187 188 189 190 191 192 193 194  | Next Page >

  • counting sub rows in mysql

    - by moustafa
    i have 2 table ok catgories and artilces i have this structure catgories web > design > photoshop > layers web > design > photoshop > effects and each one is a catgory and layers catgories has 100 article and effects catgories has 50 article now i want when count the articles 'web' catgory it show 150 article how i can do this give me an example

    Read the article

  • mysql join 3 tables and count

    - by air
    Please look at this image here is 3 tables , and out i want is uid from table1 industry from table 3 of same uid count of fid from table 2 of same uid like in the sample example output will be 2 records Thanks

    Read the article

  • mysql rollback when auto commit is on

    - by devang
    hi, by mistake i fired a update query and all the records in the table in dat field got updated nd also cannot rollback as auto_commit is on..is der ny other way in which i can retreive the records.plz help its urgent.. Thanks in advance

    Read the article

  • How can I update a field in a MySQL database table by addition in MySQL database in a single query

    - by undefined
    I have a table that stores a value that will be added to over time. When I want to add to the value I would like to do so in a single query rather than - Get oldValue from database newValue = oldValue + X update row with newValue $query1 = "SELECT value FROM table WHERE id = thisID"; $result1 = mysql_query($query1); while($row=mysql_fetch_array($result)) { $oldValue = $row['value']; } $newValue = $oldValue + x $query1 = "UPDATE table SET value = $newValue WHERE id = thisID"; Can this be done in a single query?

    Read the article

  • MySQL Database Query - Codeigniter

    - by user2450349
    I am building an application with Codeigniter and need some help with a DB query. I have a table called users with the following fields: user_id, user_name, user_password, user_email, user_role, user_manager_id In my app, I pull all records from the user table using the following: function get_clients() { $this->db->select('*'); $this->db->where('user_role', 'client'); $this->db->order_by("user_name", "Asc"); $query = $this->db->get("users"); return $query->result_array(); } This works as expected, however when I display the results in the view, I also want to display a new column called Manager which will display the managers user_name field. The user_manager_id is the id of the user from the same table. Im guessing you can create an outer join on the same table but not sure. In the view, I am displaying the returned info as follows: <table class="table table-striped" id="zero-configuration"> <thead> <tr> <th>Name</th> <th>Email</th> <th>Manager</th> </tr> </thead> <tbody> <?php foreach($clients as $row) { ?> <tr> <td><?php echo $row['user_name']; ?> (<?php echo $row['user_username']; ?>)</td> <td><?php echo $row['user_email']; ?></td> <td><?php echo $row['???']; ?></td> </tr> <?php } ?> </tbody> </table> Any idea of how I can form the query and display the manager name is the view? Example: user_id user_name user_password user_email user_role user_manager_id 1 Ollie adjjk34jcd [email protected] client null 2 James djklsdfsdjk [email protected] client 1 When i query the database, i want to display results like this: Ollie [email protected] James [email protected] Ollie

    Read the article

  • Help getting the following create table function to work with mysql and C#

    - by Matt
    string createTable = "CREATE TABLE IF NOT EXISTS " + m_strDatabase + "_TimeLogs (logName VARCHAR(16), logTime INTEGER, logCountry TEXT, UNIQUE(logName)) TYPE=MyISAM;"; When this runs, no table is created. No errors either. Im using an ODBC connector. the variable passes in the db name, so that the table created would be users_TimeLogs if the database was called users for example. Am I doing something wrong?

    Read the article

  • mysql update enums

    - by FFish
    I have a field with enums: 'preview','active','closed' When I query like this: $query = "UPDATE albums SET album_active = preview WHERE album_id = 3"; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); I get : Invalid query: Unknown column 'preview' in 'field list

    Read the article

  • How to display mysql records as preselected checkboxes?

    - by Jennifer
    I have a table column called post_tags within a table called posts where assigned tags are stored separated by the @ symbol. I also have a table called tags where all tag names are stored. I would like to design my database in a more normalized way but for the purpose I am trying to achieve this is the easiest option. Anyway, I want to display on the screen all the entries from the tags table as checkboxes, so I do: $query = mysql_query("SELECT * FROM tags ORDER BY name"); while ($row = mysql_fetch_assoc($query)) { $tag = $row['name']; echo "<input type='checkbox' name='tags[]' value='$tag' />\n"; } Next I want to have the tags that are assigned to a particular post be preselected. For example, if I have a post with the following in it's post_tags column: party@beaches@dolphins@ I want the "party", "beaches" and "dolphin" checkboxes to be checked by default (while the checkboxes for the other options are unchecked). How can this be done?

    Read the article

  • MySQL: Selecting One Record When Others Have Same Data

    - by LoganFrederick
    I have a table of cities that all share the same area code: 367 01451 Harvard Worcester Massachusetts MA 978 Eastern 368 01452 Hubbardston Worcester Massachusetts MA 978 Eastern 369 01453 Leominster Worcester Massachusetts MA 978 Eastern The table has multiple area codes, all with multiple cities. What I'd like to do is only select one city from each area code and delete any extra cities from duplicate area codes. What would be the best query to accomplish this? I believe: http://stackoverflow.com/questions/596629/mysql4-sql-for-selecting-one-or-zero-record Is coming close to what I need but didn't quite get what/how those answers were working. Note The "978" row is the "area_code" row, table name is "zip_code".

    Read the article

  • MySQL Query, Date Range From "Blacklist"

    - by erbaker
    I have 2 databases. One is properties and the other is dates. In dates I have associated the land_id and a date (In YYYYMMDD format) which means that the date is not available. I need to formulate a query that a user can specify a start and end date, and then choose a property for which dates are available (not in the date database). How do airline and hotel websites do this kind of logic? I was thinking about taking the date range and picking all days in between and doing a query where the dates do not match and ordering it by number of results, but I can see how that could easily turn into an intense query. CREATE TABLE IF NOT EXISTS `dates` ( `id` int(11) NOT NULL AUTO_INCREMENT, `land_id` int(11) NOT NULL, `date` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=44 ; -- -- Dumping data for table `dates` -- INSERT INTO `dates` (`id`, `land_id`, `date`) VALUES (43, 1, '20100526'), (39, 1, '20100522'), (40, 1, '20100523'), (41, 1, '20100521'), (42, 1, '20100525');

    Read the article

  • MySQL Query - WHERE and IF?

    - by Prash
    I'm not quite sure how to right this query. Basically, I'm going to have a table with two columns (OS and country_code) - more columns too, but those are the conditional ones. These will be either set to 0 for all, or specific ones, separated by commas. Now, what I'm trying achieve is pull data from the table if the OS and country_code = 0, or if they contain matching data (separated by commas). Then, I have a column for time. I want to select rows where the time is GREATER than the time column, unless the column time_t is set to false, in which case this shouldn't matter. I hope I explained it right? This is what I kind of have so far: $get = $db->prepare("SELECT * FROM commands WHERE country_code = 0 OR country_code LIKE :country_code AND OS = 0 OR OS LIKE :OS AND IF (time_t = 1, expiry > NOW()) "); $get->execute(array( ':country_code' => "%{$data['country_code']}%", ':OS' => "%{$data['OS']}%" ));

    Read the article

  • MySQL COUNT() multiple columns

    - by liam
    Hello, I'm trying to fetch the most popular tags from all videos in my database (ignoring blank tags). I also need the 'flv' for each tag. I have this working as I want if each video has one tag: SELECT tag_1, flv, COUNT(tag_1) AS tagcount FROM videos WHERE NOT tag_1='' GROUP BY tag_1 ORDER BY tagcount DESC LIMIT 0, 10 However in my database, each video is allowed three tags - tag_1, tag_2 and tag_3. Is there a way to get the most popular tags reading from multiple columns? The record structure is: +-----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | flv | varchar(150) | YES | | NULL | | | tag_1 | varchar(75) | YES | | NULL | | | tag_2 | varchar(75) | YES | | NULL | | | tag_3 | varchar(75) | YES | | NULL | | +-----------------+--------------+------+-----+---------+----------------+

    Read the article

  • php array into mysql

    - by mckenzie
    Hello, $sql_where = ''; $exclude = '30,35,36,122,123,124,125'; if($exclude != '') { $exclude_forums = explode(',', $exclude); foreach ($exclude_forums as $id) { if ($id > 0) { $sql_where = ' AND forum_id <> ' . trim($id); } } } $sql = 'SELECT topic_title, forum_id, topic_id, topic_type, topic_last_poster_id, topic_last_poster_name, topic_last_poster_colour, topic_last_post_time FROM ' . TOPICS_TABLE . ' WHERE topic_status <> 2 AND topic_approved = 1 ' . $sql_where . ' ORDER BY topic_time DESC'; The above code i use to exclude the id of forum to be displayed on sql queries. Why doesn't it work and still display it? Any solution

    Read the article

  • effective counter for unique number of visits in PHP & MySQL

    - by Adnan
    Hello, I am creating a counter for unique number of visits on a post, so what I have until now is a table for storing data like this; cvp_post_id | cvp_ip | cvp_user_id In cases a registered user visits a post, for the first time a record is inserted with cpv_post_id and cvp_user_id, so for his next visit I query the table and if the record is available I do not count him as a new visitor. In cases of an anonymous user the same happens but now the cvp_ip and cpv_post_id are used. My concerns is that I do a query every time anyone visits a post for checking if there has been a visit, what would be a more effective way for doing this?

    Read the article

  • MySQL : Calculate business day difference between two dates column

    - by yokoyoko
    My sql query returns back two columns, first column is "date created" and second column is "date updated", first column has a prior timestamp with respect to second column. I need to add a third column which can display business day hrs (9:00am to 5:00pm) response i.e. if date created is 2012-01-01 09:00:20 and "dated updated" is 4:00pm same day then third column should display 7 hrs If date created is 2012-01-01 16:00:20 (4:00pm) and "date updated" is 10:00m on 2012:01:02 (2nd Jan) then third column should display 2 hrs. It should exclude Saturday and Sunday. Can you please suggest appropriate SQL query for this.

    Read the article

  • php/mysql append state to city

    - by mike
    Hello, Having a hard time figuring out the best way to do this... I have a search function that takes "search terms" and "search location". In the location input, I have an suggestion feature that brings up "city, state abbreviation" but it seems some users just do not use it(or can't) so they end up entering just a city name... I need to append the state abbreviation after the form is submitted. I have a table with all city and state names in the U.S. but the problem is... there are multiple cities with the same name in different states... I would like to add the state abbreviation for the state that the city is most popular for(does that make sense?). For example, if the user enters "Miami" I would like it to become "Miami, FL" as opposed to "Miami, WV"... Any ideas? Thanks!

    Read the article

  • Help with MySQL Query?

    - by Devyn
    I have two tables rooms and users. I want to get only rooms.room_id, users.user_name with user_id = 1. I can get the result of all users with following sql... select rooms.room_id, rooms.user_id, users.user_name from rooms LEFT JOIN users ON rooms.user_id = users.user_id When I do like this to filter the result with user_id = 1 ... I got error. select rooms.room_id, rooms.user_id, users.user_name from rooms where rooms.user_id = 1 LEFT JOIN users ON rooms.user_id = users.user_id What should I do?

    Read the article

  • Multidimensional Array To Mysql Codeigniter

    - by rochellecanale
    A little help how can I create an input query using this array? Or how can I pass it in the table? my table layout sample is this: sales_table id | product_name | price | qty | subtotal This is derived from the var_dump() function. Here is my code in array //array code from unserialized function $products = unserialize($this->session->userdata('product_list')); //This is the output. Array ( [2] => Array ( [id] => 2 [product_name] => NOKIA 5110 [product_desc] => Cellphone [product_price] => 500.00 [product_qty] => 1 [product_amount] => 500 [product_code] => NOKI2012-84353 ) [3] => Array ( [id] => 3 [product_name] => HP IPAQ RW6828 [product_desc] => Cellphone [product_price] => 1500.00 [product_qty] => 1 [product_amount] => 1500 [product_code] => HP I2012-08386 ) )

    Read the article

  • delete row from mysql through generated table with records

    - by HennySmafter
    I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

    Read the article

  • Union - Same table, excluding previous results MySQL

    - by user82302124
    I'm trying to write a query that will: Run a query, give me (x) number of rows (limit 4) If that query didn't give me the 4 I need, run a second query limit 4-(x) and exclude the ids from the first query A third query that acts like the second I have this: (SELECT *, 1 as SORY_QUERY1 FROM xbamZ where state = 'Minnesota' and industry = 'Miscellaneous' and id != '229' limit 4) UNION (SELECT *, 2 FROM xbamZ where state = 'Minnesota' limit 2) UNION (SELECT *, 3 FROM xbamZ where industry = 'Miscellaneous' limit 1) How (or is?) do I do that? Am I close? This query gives me duplicates

    Read the article

  • php mysql error beginner

    - by Marcelo
    Hi, I'm trying to print some values on the screen from a table but I having a problem, I don't know much about string, vector and array but I think that my problem is related to them. I'm getting this on the screen Fatal error: Cannot use [] for reading ... My code $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql) or trigger_error(mysql_error().$sql); while($row = mysql_fetch_array($result)){ $DATA = $row[]; } //line with probelm mysql_close(); //html part <table> <? foreach($DATA as $row): ?> <tr> <td><?=$row['id']?></td> //more stuff </tr> <? endforeach ?> </table> What I'm trying to do is print somevalues form a database. But I'm getting this error. I'm sorry for any mistake in English, and thanks in advance for any help.

    Read the article

  • Which mysql construct is faster?

    - by Olaseni
    SELECT ..WHERE COL IN(A,B) or SELECT ... WHERE (COL = A or COL = B) I'm trying to find out what are the differences between the two constructs? Would there be significant performance gains either way if utilized on resultsets that are nearing the 1 million mark?

    Read the article

< Previous Page | 183 184 185 186 187 188 189 190 191 192 193 194  | Next Page >