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  • Problem with keyboard language

    - by user300484
    Hello you all! I just made an application which purpose is to find an x result using the rule of three. It runs fine and everything but there is a small problem. I am using WinXP Europpean Spanish version. As we all know, in many europpean countries the decimal dot is changed by a " , " comma. When I use my application, it turns out that when I press the dot key on my keyboard´s number pad, my application doesnt take it as a normal decimal dot and it ignores it... so I need to manually press the comma key so it can give me the right answer. How can I solve this problem?

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  • C Programming: malloc() inside another function

    - by vikramtheone
    Hi Guys, I need help with malloc() inside another function. I'm passing a pointer and size to the function from my main() and I would like to allocate memory for that pointer dynamically using malloc() from inside that called function, but what I see is that.... the memory which is getting allocated is for the pointer declared withing my called function and not for the pointer which is inside the main(). How should I pass a pointer to a function and allocate memory for the passed pointer from inside the called function? Can anyone throw light on this? Help!!! Vikram I have written the following code and I get the output as shown below SOURCE: main() { unsigned char *input_image; unsigned int bmp_image_size = 262144; if(alloc_pixels(input_image, bmp_image_size)==NULL) printf("\nPoint2: Memory allocated: %d bytes",_msize(input_image)); else printf("\nPoint3: Memory not allocated"); } signed char alloc_pixels(unsigned char *ptr, unsigned int size) { signed char status = NO_ERROR; ptr = NULL; ptr = (unsigned char*)malloc(size); if(ptr== NULL) { status = ERROR; free(ptr); printf("\nERROR: Memory allocation did not complete successfully!"); } printf("\nPoint1: Memory allocated: %d bytes",_msize(ptr)); return status; } PROGRAM OUTPUT: Point1: Memory allocated ptr: 262144 bytes Point2: Memory allocated input_image: 0 bytes

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  • Please recommend good books for telemetry / SCADA system design & programming

    - by Mawg
    I am looking at several projects, all with roughly the same fucntionality. Some instruments collect some data (or control some functionality). They commmunicate by Internet (Etehrnet/wifi/GPRS/sasatellite) with a databse server which stores the measurements and provides a browser based means of qeurying the data, prodcuing reports, etc (and possibly also allows control of the remote equipment). Can anyone recommend a good book describing an approach to developing such a software architecture, keeping it generic, which tools, languages. test methods, etc to use? (note to self: ask a similar question about possible existing frameworks)

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  • Object Oriented Programming Problem

    - by Danny Love
    I'm designing a little CMS using PHP whilst putting OOP into practice. I've hit a problem though. I have a page class, whos constructor accepts a UID and a slug. This is then used to set the properties (unless the page don't exist in which case it would fail). Anyway, I wanted to implement a function to create a page, and I thought ... what's the best way to do this without overloading the constructor. What would the correct way, or more conventional method, of doing this be? My code is below: <?php class Page { private $dbc; private $title; private $description; private $image; private $tags; private $owner; private $timestamp; private $views; public function __construct($uid, $slug) { } public function getTitle() { return $this->title; } public function getDescription() { if($this->description != NULL) { return $this->description; } else { return false; } } public function getImage() { if($this->image != NULL) { return $this->image; } else { return false; } } public function getTags() { if($this->tags != NULL) { return $this->tags; } else { return false; } } public function getOwner() { return $this->owner; } public function getTimestamp() { return $this->timestamp; } public function getViews() { return $this->views; } public function createPage() { // Stuck? } }

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  • Concatenate String to Evernote Markup Language (ENML) in python

    - by Adam the Mediocre
    I am looking to add a string containing the user's text input to the note.content of my note. After reading, I have found how to add resources, but I don't want the resource to be an attachment, I want it to be the actual text. Here is some of the code: title= self.textEditTitle.text() body= self.textEditBody.text() auth_token = "secret stuff!" client = EvernoteClient(token=auth_token, sandbox=True) note_store = client.get_note_store() nBody = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" nBody += "<!DOCTYPE en-note SYSTEM \"http://xml.evernote.com/pub/enml2.dtd\">" nBody += "<en-note>%s</en-note>" % body note = Types.Note() note.title = title note.content= nBody Any advice would be great, as I'm just starting out with this api and it looks like it's full of potential once I figure it out! Here is what I have been mostly reading from: http://dev.evernote.com/documentation/cloud/chapters/ENML.php

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  • blue tooth programming on android

    - by user121196
    I currently use blue tooth api on android and am able to pair with regular devices(eg. my pc with built-in blue-tooth). However it doesn't get a response when trying to connect to it. What is the meaning of connect in blue tooth? is this a built-in protocol of bluetooth?

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  • Grading your programming ability?

    - by Farstucker
    I understand this is a subjective question and very likely could be closed, and although there is no right or wrong answer I do believe its a legitimate question. At what point do you no longer consider someone a beginner (ie knowledge of loops, encapsulation, instantiation), an intermediate (design patterns, reflection, delegates, interfaces) or an expert (architecture, multi-threadding). My rational for asking such a question is two-fold, first, when do I stop labeling my questions as beginner and during a job interview how should I categorize myself?

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  • ClassCastException in iterating list returned by Query using Hibernate Query Language

    - by Tushar Paliwal
    I'm beginner in hibernate.I'm trying a simplest example using HQL but it generates exception at line 25 ClassCastException when i try to iterate list.When i try to cast the object returned by next() methode of iterator it generates the same problem.I could not identify the problem.Kindly give me solution of the problem. Employee.java package one; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class Employee { @Id private Long id; private String name; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public Employee(Long id, String name) { super(); this.id = id; this.name = name; } public Employee() { } } Main2.java package one; import java.util.Iterator; import java.util.List; import org.hibernate.Query; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.Transaction; import org.hibernate.cfg.Configuration; public class Main2 { public static void main(String[] args) { SessionFactory sf=new Configuration().configure().buildSessionFactory(); Session s1=sf.openSession(); Query q=s1.createQuery("from Employee "); Transaction tx=s1.beginTransaction(); List l=q.list(); Iterator itr=l.iterator(); while(itr.hasNext()) { Object obj[]=(Object[])itr.next();//Line 25 for(Object temp:obj) { System.out.println(temp); } } tx.commit(); s1.close(); sf.close(); } }

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  • Leverage cloud and programming to share GB's of photos

    - by jcmoney
    My friends and I went on a trip and we have over 8 GB of photos we want to share. We live in different geographic locations and all of us (14 people) have a part of the 8 GB. I was wondering if there's a way to leverage my php skills to share all these photos. My current plan is to make a simple site that you can upload a bunch of files and also list those files for people to download (probably a compressed folder of a bunch of selected ones) but was wondering if there's a better way or if I'm grossly underestimating scalability issues. All of us have high speed internet (essentially T1) and I was planning on using Amazon EC2 since this is a heavy task but for a short time period. That's also the reason I can't use dropbox or similar services since they have a 2GB cap (and I don't want to have everyone sign up and install something). I also don't want to set up anything too tricky since not all of them are tech savvy.

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  • jQuery programming style?

    - by Sam Dufel
    I was recently asked to fix something on a site which I haven't worked on before. I haven't really worked with jQuery that much, but I figured I'd take a look and see if I could fix it. I've managed to mostly clear up the problem, but I'm still horrified at the way they chose to build this site. On document load, they replace the click() method of every anchor tag and form element with the same massive function. When clicked, that function then checks if the tag has one of a few different attributes (non-standard attributes, even), and does a variety of different tasks depending on what attributes exist and what their values are. Some hyperlinks have an attribute on them called 'ajaxrel', which makes the click() function look for another (hidden) hyperlink with an ID specified by the ajaxrel attribute, and then calls the click() function for that other hyperlink (which was also modified by this same click() function). On the server side, all the php files are quite long and have absolutely no indentation. This whole site has been a nightmare to debug. Is this standard jQuery practice? This navigation scheme seems terrible. Does anyone else actually use jQuery this way? I'd like to start incorporating it into my projects, but looking at this site is giving me a serious headache. Here's the click() function for hyperlinks: function ajaxBoxA(theElement, urltosend, ajaxbox, dialogbox) { if ($(theElement).attr("href") != undefined) var urltosend = $(theElement).attr("href"); if ($(theElement).attr('toajaxbox') != undefined) var ajaxbox = $(theElement).attr('toajaxbox'); // check to see if dialog box is called for. if ($(theElement).attr('dialogbox') != undefined) var dialogbox = $(theElement).attr('dialogbox'); var dodialog = 0; if (dialogbox != undefined) { // if dialogbox doesn't exist, then flag to create dialog box. var isDiaOpen = $('[ajaxbox="' + ajaxbox + '"]').parent().parent().is(".ui-dialog-container"); dodialog = 1; if (isDiaOpen) { dodialog = 0; } dialogbox = parseUri(dialogbox); dialogoptions = { close: function () { // $("[id^=hierarchy]",this).NestedSortableDestroy(); $(this).dialog('destroy').remove() } }; for ( var keyVar in dialogbox['queryKey'] ) eval( "dialogoptions." + keyVar + " = dialogbox['queryKey'][keyVar]"); }; $("body").append("<div id='TB_load'><img src='"+imgLoader.src+"' /></div>"); $('#TB_load').show(); if (urltosend.search(/\?/) > 0) { urltosend = urltosend + "&-ajax=1"; } else { urltosend = urltosend + "?-ajax=1"; } if ($('[ajaxbox="' + ajaxbox + '"]').length) { $('[ajaxbox="' + ajaxbox + '"]').each( function () { $(this).empty(); }); }; $.ajax({ type: "GET", url: urltosend, data: "", async: false, dataType: "html", success: function (html) { var re = /^<toajaxbox>(.*?)<\/toajaxbox>+(.*)/; if (re.test(html)) { var match = re.exec(html); ajaxbox = match[1]; html = Right(html, String(html).length - String(match[1]).length); } var re = /^<header>(.*?)<\/header>+(.*)/; if (re.test(html)) { var match = re.exec(html); window.location = match[1]; return false; } if (html.length > 0) { var newHtml = $(html); if ($('[ajaxbox="' + ajaxbox + '"]').length) { $('[ajaxbox="' + ajaxbox + '"]').each( function () { $(this).replaceWith(newHtml).ready( function () { ajaxBoxInit(newHtml) if (window.ajaxboxsuccess) ajaxboxsuccess(newHtml); }); }); if ($('[ajaxdialog="' + ajaxbox + '"]').length = 0) { if (dodialog) $(newHtml).wrap("<div class='flora ui-dialog-content' ajaxdialog='" + ajaxbox + "' style='overflow:auto;'></div>").parent().dialog(dialogoptions); } } else { $("body").append(newHtml).ready( function () { ajaxBoxInit(newHtml); if (window.ajaxboxsuccess) ajaxboxsuccess(newHtml); }); if (dodialog) $(newHtml).wrap("<div class='flora ui-dialog-content' ajaxdialog='" + ajaxbox + "' style='overflow:auto;'></div>").parent().dialog(dialogoptions); } } var rel = $(theElement).attr('ajaxtriggerrel'); if (rel != undefined) $('a[ajaxrel="' + rel + '"]').click(); tb_remove(); return false; }, complete: function () { $("#TB_load").remove(); } }); return false; }

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  • iPhone basic sheet programming?

    - by ryyst
    Hi, I want to program an "Add"-Window to my application, much like the "Add Contact"-window in the Contacts app or the "Add City"-window in the Weather app. My question is: how do I code the effect of sliding up that Contacts & Weather feature? -- Ry

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  • HIbernate query language problem.....

    - by mslatf
    I have a Project class that has a Set of userstories called userStories12many. I'm having troubles trying to get the project that has a certain userstory in its set getComponent(int userStoryID) I think im on the right track but i dont know what i did wrong public Projects getComponent(int userStoryID) { Session session = SessionFactoryHelper.getSessionFactory() .getCurrentSession(); session.beginTransaction(); List<Projects> compo = session.createQuery("select p " + "from Projects as p inner join fetch p.userStories12many as u " + "where u.storyId='" + userStoryID + "'").list(); session.getTransaction().commit(); return compo.get(0); }

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  • Does the concept of "magic number" change from language to language?

    - by Gerardo Marset
    Take the following code in C/C++, for example: int foo[] = {0, 0, 0, 0}; No magic numbers, right? Now, the Python "equivalent" of that would be: foo = [0, 0, 0, 0] Still no magic numbers. However, in Python, that same thing can be written like this: foo = [0] * 4 And now we DO have a magic number. Or do we? I'm guessing this and other similar things are present on these and other languages.

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  • language specific virtual keyboard with java

    - by user343285
    Hello everyone! I have to make an on-screen keyboard using JAVA on linux. the problem is it has to work on the most languages. for start, i need to et the current locale, that's clear, but after that, is there any way of getting the keyboard layout and maping of that locale? i searched for hours, but couldn't find a thing, so i really hope you can help me. Thanks in advance, Adam!

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  • Programming an IPTV application- Client/Server

    - by Sumit Ghosh
    I am part of a team which has been given a task to deploy an IPTV solution for a company. The system has been architect-ed like this. There is Video capture card , which receives satellite signals from a satellite receiver. This video capture card is part of a windows 7 machine. The signals need to be trans coded here and passed to a streaming server which will be received by end users. The end users will be desktop users having a C#.NET application installed to view the channels. I am confused at the choice of server software as I have multiple choices - Windows Media Server, VideoLan (VLC project), or Flash Media Server, it also supports MPEG-2 HD. My main aim to be able to stream MPEG-2 channels with HD quality and encrypt the channels at the server end so that the streams can be protected. I know reversing is possible but it wont be easy as for every naive user with wireshark snooping my streams. If any of you here has ever done such an implementation please do suggest me the best technologies I should go for. Iam open to C#,C++ and other similar languages. Any help shall be deeply appreciated. edit: End Users shall be part of Internet and not necessarily a lan, reason for this question is internet doesn't support multicast like Lan, so I need some suggestions.

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  • How to convert this procedural programming to object-oriented programming?

    - by manus91
    I have a source code that is needed to be converted by creating classes, objects and methods. So far, I've just done by converting the initial main into a separate class. But I don't know what to do with constructor and which variables are supposed to be private. This is the code : import java.util.*; public class Card{ private static void shuffle(int[][] cards){ List<Integer> randoms = new ArrayList<Integer>(); Random randomizer = new Random(); for(int i = 0; i < 8;) { int r = randomizer.nextInt(8)+1; if(!randoms.contains(r)) { randoms.add(r); i++; } } List<Integer> clonedList = new ArrayList<Integer>(); clonedList.addAll(randoms); Collections.shuffle(clonedList); randoms.addAll(clonedList); Collections.shuffle(randoms); int i=0; for(int r=0; r < 4; r++){ for(int c=0; c < 4; c++){ cards[r][c] = randoms.get(i); i++; } } } public static void play() throws InterruptedException { int ans = 1; int preview; int r1,c1,r2,c2; int[][] cards = new int[4][4]; boolean[][] cardstatus = new boolean[4][4]; boolean gameover = false; int moves; Scanner input = new Scanner(System.in); do{ moves = 0; shuffle(cards); System.out.print("Enter the time(0 to 5) in seconds for the preview of the answer : "); preview = input.nextInt(); while((preview<0) || (preview>5)){ System.out.print("Invalid time!! Re-enter time(0 - 5) : "); preview = input.nextInt(); } preview = 1000*preview; System.out.println(" "); for (int i =0; i<4;i++){ for (int j=0;j<4;j++){ System.out.print(cards[i][j]); System.out.print(" "); } System.out.println(""); System.out.println(""); } Thread.sleep(preview); for(int b=0;b<25;b++){ System.out.println(" "); } for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ System.out.print("*"); System.out.print(" "); cardstatus[r][c] = false; } System.out.println(""); System.out.println(" "); } System.out.println(""); do{ do{ System.out.print("Please insert the first card row : "); r1 = input.nextInt(); while((r1<1) || (r1>4)){ System.out.print("Invalid coordinate!! Re-enter first card row : "); r1 = input.nextInt(); } System.out.print("Please insert the first card column : "); c1 = input.nextInt(); while((c1<1) || (c1>4)){ System.out.print("Invalid coordinate!! Re-enter first card column : "); c1 = input.nextInt(); } if(cardstatus[r1-1][c1-1] == true){ System.out.println("The card is already flipped!! Select another card."); System.out.println(""); } }while(cardstatus[r1-1][c1-1] != false); do{ System.out.print("Please insert the second card row : "); r2 = input.nextInt(); while((r2<1) || (r2>4)){ System.out.print("Invalid coordinate!! Re-enter second card row : "); r2 = input.nextInt(); } System.out.print("Please insert the second card column : "); c2 = input.nextInt(); while((c2<1) || (c2>4)){ System.out.print("Invalid coordinate!! Re-enter second card column : "); c2 = input.nextInt(); } if(cardstatus[r2-1][c2-1] == true){ System.out.println("The card is already flipped!! Select another card."); } if((r1==r2)&&(c1==c2)){ System.out.println("You can't select the same card twice!!"); continue; } }while(cardstatus[r2-1][c2-1] != false); r1--; c1--; r2--; c2--; System.out.println(""); System.out.println(""); System.out.println(""); for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ if((r==r1)&&(c==c1)){ System.out.print(cards[r][c]); System.out.print(" "); } else if((r==r2)&&(c==c2)){ System.out.print(cards[r][c]); System.out.print(" "); } else if(cardstatus[r][c] == true){ System.out.print(cards[r][c]); System.out.print(" "); } else{ System.out.print("*"); System.out.print(" "); } } System.out.println(" "); System.out.println(" "); } System.out.println(""); if(cards[r1][c1] == cards[r2][c2]){ System.out.println("Cards Matched!!"); cardstatus[r1][c1] = true; cardstatus[r2][c2] = true; } else{ System.out.println("No cards match!!"); } Thread.sleep(2000); for(int b=0;b<25;b++){ System.out.println(""); } for(int r=0;r<4;r++){ for(int c=0;c<4;c++){ if(cardstatus[r][c] == true){ System.out.print(cards[r][c]); System.out.print(" "); } else{ System.out.print("*"); System.out.print(" "); } } System.out.println(""); System.out.println(" "); } System.out.println(""); System.out.println(""); System.out.println(""); gameover = true; for(int r=0;r<4;r++){ for( int c=0;c<4;c++){ if(cardstatus[r][c]==false){ gameover = false; break; } } if(gameover==false){ break; } } moves++; }while(gameover != true); System.out.println("Congratulations, you won!!"); System.out.println("It required " + moves + " moves to finish it."); System.out.println(""); System.out.print("Would you like to play again? (1=Yes / 0=No) : "); ans = input.nextInt(); }while(ans == 1); } } The main class is: import java.util.*; public class PlayCard{ public static void main(String[] args) throws InterruptedException{ Card game = new Card(); game.play(); } } Should I simplify the Card class by creating other classes? Through this code, my javadoc has no constructtor. So i need help on this!

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  • Java Programming Homework

    - by user1427476
    Write a program to read in a file containing the names of the employ of a company and store them in an array of Strings named Employ []. Read another file containing the Salaries of each employ written in the same order and store them in another array of integers named salary[] (contents of both files are shown below). Finally create a file stating for example. Mr. XYZ receive $75,500.00 per year (Note that salary is stored as integer but displayed here as double with a comma separating thousands. This formatting needs to be done using DecimalFormat Class)

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  • programming question about numbers

    - by Syom
    it's a task, on which i think during whole day. i have four integer numbers a, b, c, d, and ineger x[1,40]. i must write a program, which can find the values of {a,b,c,d}, for which one of following equations is true for any (x<=40, x=1) x=a or x=b or x=a+b or x=a+b+c+d or x+a=c+d or x+a+b=c+d or ... x+a+b+c=d or ... it is very difficult to explain what i want to say. maybe the example will be helpful. example: if x=17, by {a=1,b=2,c=5,d=15} i can write x+a+b=c+d whole question is to present any x[1,40] by {a,b,c,d}. hope that you understand what i want to say, and thanks in advance

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  • Why my print current date time (C language) gives different answer

    - by vodkhang
    I want to get the current date (day, mon and year). I found out there are some functions in C to do that like ctime (get the string of time), localtime and gmtime. I tried with following code but the output are different. I get this output: The date and time is Tue Apr 20 2010 (which is correct) The year is : 110 The year is : 110. Does anybody know why? int main(int argc, char** argv) { time_t now; if((now = time(NULL)) == (time_t)-1) { puts("Failure in getting time"); } else { printf("The date and time is: %s\n", ctime(&now)); printf("The year is: %ld\n", localtime(&now)->tm_year); printf("The year is: %ld\n", gmtime(&now)->tm_year); } getchar(); }

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