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  • Rails: how to represent available view actions in a stateful model?

    - by Greg
    I have a model that is stateful. In each state there are a selection of actions that the user might want to perform on an instance of the model. Currently I am translating the model state to actions that get represented in the view using a view helper. Something like this... in the model: Class Thing def state_is_A? state == 'A' end end In the helper: def display_available_actions(thing) if thing.state_is_A? link_to <action1> link_to <action2> end end And in the view: <%= display_available_actions(@thing) %> I don't like the fact that the model state is translated into view actions in the helper. I would like this to be incorporated into the model. On the other hand, it doesn't seem healthy for the model and view to get so coupled. Is there a Ruby or Rails idiom that suits this kind of situation better than my approach? Should each state be a separate model perhaps?

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  • How do I control the background color during the iPhone flip view animation transition?

    - by Rob S.
    I have some pretty standing flipping action going on: [UIView beginAnimations:@"swapScreens" context:nil]; [UIView setAnimationTransition:UIViewAnimationTransitionFlipFromLeft forView:self.view cache:YES]; [UIView setAnimationDuration:1.0]; [self.view exchangeSubviewAtIndex:0 withSubviewAtIndex:1]; [UIView commitAnimations]; To Apple's credit, this style of animation is amazingly easy to work with. Very cool, and I've been able to animate transitions, flips, fades etc. throughout the app very easily. Question: During the flip transition, the background visible 'behind' the two views during the flip is white and I'd like it to be black. I've: Set the background of the containing view (self.view above) - no dice. I really thought that would work. Set the background of each view to black - no dice. I didn't think this would work although you give different things a shot to understand better :) Google'd like crazy; keep landing on Safari-related listings. Thanks in advance!

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  • WPF MVVM View with varying number of objects. How to?

    - by 0xDEAD BEEF
    HI! I want to design view which will contain multiple objects in different locations. For example - it would be great if viewmodel could have field like list of objects (rectangles) and when i change/add members to list, new rectangles appear on view in specified positions. How do i create such view/viewmodel?

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  • Modelview navigation problem

    - by Allen
    i have a navigation controller displaying as a modelview controller. That model view controller calling from another view controller. In that modelview controller im navigating to different controllers and its working fine. but when i return to that model view controller the navigfation is not smooth and i can see space between that controllers while navigating. what is the reason?

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  • Why does my Spring Controller direct me to the wrong page?

    - by kc2001
    I am writing my first Spring 3.0.5 MVC app and am confused about why my controller mappings aren't doing what I expect. I have a VerifyPasswordController that is called after a user tries to log in by entering his name and password. // Called upon clicking "submit" from /login @RequestMapping(value = "/verifyPassword", method = RequestMethod.POST) @ModelAttribute("user") public String verifyPassword(User user, BindingResult result) { String email = user.getEmail(); String nextPage = CHOOSE_OPERATION_PAGE; // success case if (result.hasErrors()) { nextPage = LOGIN_PAGE; } else if (!passwordMatches(email, user.getPassword())) { nextPage = LOGIN_FAILURE_PAGE; } else { // success } return nextPage; } I can verify in the debugger that this method is being called, but afterwards, the verifyPassword page is displayed rather than the chooseOperation page. The console output of WebLogic seems to show that my mapping are correct: INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation] onto handler 'chooseOperationController' INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation.*] onto handler 'chooseOperationController' INFO : org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping - Mapped URL path [/chooseOperation/] onto handler 'chooseOperationController' Here is the ChooseOperationController: @Controller @SessionAttributes("leaveRequestForm") public class ChooseOperationController implements PageIfc, AttributeIfc { @RequestMapping(value = "/chooseOperation") @ModelAttribute("leaveRequestForm") public LeaveRequest setUpLeaveRequestForm( @RequestParam(NAME_ATTRIBUTE) String name) { LeaveRequest form = populateFormFromDatabase(name); return form; } // helper methods omited } I welcome any advice, particularly "generic" techniques for debugging such mapping problems. BTW, I've also tried to "redirect" to the desired page, but got the same result. servlet-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure --> <!-- Enables the Spring MVC @Controller programming model --> <annotation-driven /> <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory --> <resources mapping="/resources/**" location="/resources/" /> <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory --> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> <context:component-scan base-package="com.engilitycorp.leavetracker" /> <beans:bean id="leaveRequestForm" class="com.engilitycorp.leavetracker.model.LeaveRequest" /> </beans:beans> The constants: String LOGIN_FAILURE_PAGE = "loginFailure"; String LOGIN_PAGE = "login"; String CHOOSE_OPERATION_PAGE = "chooseOperation";

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  • How to import data from a Lotus private view into Access?

    - by PowerUser
    I'm experimenting with Lotus private views for the first time and I finally made a private view that (more or less) has the data I want. I just need to get it into MS Access. If this was a standard shared view, I'd just fire up the ODBC administrator, and make a DSN to the database using the NotesSQL driver. Been there, done that. But you can't get to private views that way. So, how do I import the data from my private view into Access? (Also, I'm not one of the IT gurus in our company, so I can't just make a view and share it, even if it's hidden)

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  • How can I render an in-memory UIViewController's view Landscape?

    - by Aaron
    I'm trying to render an in-memory (but not in hierarchy, yet) UIViewController's view into an in-memory image buffer so I can do some interesting transition animations. However, when I render the UIViewController's view into that buffer, it is always rendering as though the controller is in Portrait orientation, no matter the orientation of the rest of the app. How do I clue this controller in? My code in RootViewController looks like this: MyUIViewController* controller = [[MyUIViewController alloc] init]; int width = self.view.frame.size.width; int height = self.view.frame.size.height; int bitmapBytesPerRow = width * 4; unsigned char *offscreenData = calloc(bitmapBytesPerRow * height, sizeof(unsigned char)); CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); CGContextRef offscreenContext = CGBitmapContextCreate(offscreenData, width, height, 8, bitmapBytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast); CGContextTranslateCTM(offscreenContext, 0.0f, height); CGContextScaleCTM(offscreenContext, 1.0f, -1.0f); [(CALayer*)[controller.view layer] renderInContext:offscreenContext]; At that point, the offscreen memory buffers contents are portrait-oriented, even when the window is in landscape orientation. Ideas?

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  • How to launch a browser in view source mode?

    - by JorgeLarre
    I want to open a file in a web browser (anyone will do) and I want to see it in the view source mode instead of in the standard browser window. This can be done in two steps, by opening the file and then go to the view source window (different shortcuts in each browser), but I want to directly go to the view source window. I have not found any such command line argument for Firefox nor Chrome. Is this possible just with the base browser functionality?

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  • How to access view items inside a ListView android?

    - by Yasir Khan
    I have ListView. i am successfully able to populate that ListView but what is want now is when user long press on ListItem it should make a button visible which i made invisible when i am populating ListView. here is snippet i have tried. mItemListView.setOnItemLongClickListener(new OnItemLongClickListener() { @Override public boolean onItemLongClick(AdapterView<?> adapterview, View arg1, int arg2, long arg3) { LinearLayout view=(LinearLayout) mItemListView.getChildAt(arg2); view.getChildAt(0).setVisibility(View.VISIBLE); return false; } }); My adapter is extending BaseAdapter

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  • How can I hook up an IBAction method to a plain view for a touch up event?

    - by Thanks
    I have created a blank new view-based application project in Xcode. It generated a myProjectViewController and an nib for it. In that nib for that view controller, there is just one view. I wanted to test some event handling stuff and created an -(IBAction) method that will just log a "hello world" when I touch the view. But for some reason, IB doesn't give me a chance to hook up the action. What am I doing wrong there? I also tried to put a UIView as subview there. When I drag from that to File's Owner (whoose class is the myProjectViewController, where I have the IBAction in the header), doesn't even mention the IBAction. But it actually should, right?

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  • View / ViewModel - what is the sense (in a WPF control)?

    - by TomTom
    Not as funny as it sounds. Normally the View / ViewModel should decouple the presentation from the business logic. Good. Now, a Control in WPF is basically invisible unless made different (with the exceptions of UserControl and Window that have XAML directly attached). The Style is putting in the "visual presentation" - which basically means a Control does not need a view mechanism as WPF already has one? In addition. the ViewModel is actually part of the Control, or? Just fighting with that stuff. I know in ASP.NET, WinForms the separation makes a lot of sense - but there, basically, controls HAVE an intrinsic look. In WPF, I have some where it makes sense (derived from UserControl), but for the majority of the controls I write, the View & ViewModel look like pretty much totally superflous thanks to the already presenting view mechanism.

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  • Retain a list of objects and pass it to the create/edit view when validation fails in ASP.NET MVC 2

    - by brainnovative
    I am binding a Foreign key property in my model. I am passing a list of possible values for that property in my model. The model looks something like this: public class UserModel { public bool Email { get; set; } public bool Name { get; set; } public RoleModel Role { get; set; } public IList<RoleModel> Roles { get; set; } } public class RoleModel { public string RoleName { get; set; } } This is what I have in the controller: public ActionResult Create() { IList<RoleModel> roles = RoleModel.FromArray(_userService.GetAllRoles()); UserModel model = new UserModel() { Roles = roles }; return View(model); } In the view I have: <div class="editor-label"> <%= Html.LabelFor(model => model.Role) %> </div> <div class="editor-field"> <%= Html.DropDownListFor(model => model.Role, new SelectList(Model.Roles, "RoleName", "RoleName", Model.Role))%> <%= Html.ValidationMessageFor(model => model.Role)%> </div> What do I need to do to get the list of roles back to my controller to pass it again to the view when validation fails. This is what I need: [HttpPost] public ActionResult Create(UserModel model) { if (ModelState.IsValid) { // insert logic here } //the validation fails so I pass the model again to the view for user to update data but model.Roles is null :( return View(model); } As written in the comments above I need to pass the model with the list of roles again to my view but model.Roles is null. Currently I ask the service again for the roles (model.Roles = RoleModel.FromArray(_userService.GetAllRoles());) but I don't want to add an extra overhead of getting the list from DB when I have already done that.. Anyone knows how to do it?

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  • Default controller name is removed on browser refresh (CodeigniterPHP/Nginx issue?)

    - by tim peterson
    For all pages in my codeigniter app except my default controller, when I refresh the browser the url isn't affected as one would expect. However for my default controller, main.php, when when I refresh the browser at "http://localhost/main" or "http://mysite.com/main", the main part is stripped off the url. So the browser bar shows just "http://localhost" or "http://mysite.com". Totally lost on where to start with this but was just wondering if anyone has come across this before...? Here's what I think could be the relevant part of my nginx.conf (if Nginx is the problem). if ($request_uri ~* ^(/main(/index)?|/index(.php)?)/?$) { rewrite ^(.*)$ / permanent; }

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  • Oracle: Is there a way to get the column data types for a view?

    - by rally25rs
    For a table in oracle, I can query "all_tab_columns" and get table column information, like the data type, precision, whether or not the column is nullable. In SQL Developer or TOAD, you can click on a view in the GUI and it will spit out a list of the columns that the view returns and the same set of data (data type, precision, nullable, etc). So my question is, is there a way to query this column definition for a view, the way you can for a table? How do the GUI tools do it?

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  • How can I display the camera view in the main window in real time?

    - by Mongrel Warfare
    I'm trying to make an augmented reality application with a waypoint structure, like Yelp, and I'm wondering how to set up my main view so that it displays the camera view on the whole screen. I've heard of using the UIImagePickerController Class, but I'm unsure how to manipulate the code so that it doesn't actually take a picture, but just stays in the view mode. Any help would be appreciated, thanks!

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  • How to call a php controller method using jquery?

    - by chandru_cp
    I am developing a web application and i am integrating jquery in it... Now looking for ajax calls with jquery to my controller function.... jquery.ajax() would be useful i think so... But how to call my controller method.... $.ajax({ type: "POST", url: "", data: "", contentType: "application/json; charset=utf-8", async: false, dataType: "json", success: function(jsonObj) { function loadbookdetails() { //Paging $college=$_SESSION['college']; $this->load->library('pagination'); $data['bookdetails'] = $this->librarymodel->selectbook($college); //$data['rackOptionData'] = $this->librarymodel->selectrack(); if(empty($data['bookdetails'])) { $data['comment'] = 'no record found!'; } $this->load->view('bookdetials',$data); } I am fetching this records here how to use it with jquery.ajax() function and how to convert $data to json and use it with jquery and iterate with a table...

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  • How to call a jquery function from an action method in controller?

    - by Hasan Fahim
    I have a requirement to open a popup from an action method in controller. The action method is basically registering a user. [HttpPost] public ActionResult Register(RegisterModel model) { if (ModelState.IsValid) { MembershipCreateStatus createStatus; Membership.CreateUser(model.UserName, model.Password, model.Email, null, null, true, null, out createStatus); if (createStatus == MembershipCreateStatus.Success) { FormsAuthentication.SetAuthCookie(model.UserName, false /* createPersistentCookie */); //------------------------------------------ //I need to call a jquery function from here //------------------------------------------ return RedirectToAction("Index", "Home"); } else { ModelState.AddModelError("", ErrorCodeToString(createStatus)); } } return View(model); } The jquery function, present in the view, would just make a hidden DIV, visible, and set the opacity, etc, to represent a popup. I need to call such a jquery function from the controller's action method shown above.

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  • Is it bad to use a model directly from a view in codeigniter?

    - by jason
    I know normally the data is passed thru to the view with the controller. however, currently in my view I load my model ($this-load-model('Db_model');) so i can use it in a loop to retrieve a users profile picture path from a array of IDs that is passed from controller. Will loading the db model in the view to accomplish this make my site more vulnerable or bad form? To me it seems to be outside of MVC concept but its working atm. thanks

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  • In which controller do you put the CRUD for the child part of a relationship?

    - by uriDium
    I am using ASP.Net MVC but this probably applies to all MVC patterns in general. My problem, for example I have companies and in each company I have a list of contacts. When I have selected a company I can see its details and a list of the contacts for that company. When I want to add a new contact for that company, should the implementation of that action go into the company controller as an "AddContact" action or should it go into the contact controller into a "New" action and we pass the Company ID in the URL? What is the usual way of dealing with this sort of thing in ASP.Net MVC? Is there a better stategy?

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  • How to show empty view when ListView is empty?

    - by Sheehan Alam
    Here is my layout. For some reason the empty view (TextView in this case) always appears, even when the List is not empty. I thought the ListView would automatically detect when to show the empty view. How can I hook up the empty view properly? <RelativeLayout android:id="@+id/LinearLayoutAR" android:layout_height="fill_parent" android:layout_width="fill_parent"> <ListView android:layout_width="fill_parent" android:layout_height="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/ARListView"></ListView> <ProgressBar android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/arProgressBar" android:layout_centerHorizontal="true" android:layout_centerVertical="true"></ProgressBar> <!-- Here is the view to show if the list is emtpy --> <TextView android:id="@id/android:empty" android:layout_width="match_parent" android:layout_height="match_parent" android:text="No Results" /> </RelativeLayout>

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  • Send copy of class to view class so it can render him? ( iPhone )

    - by Johannes Jensen
    I'm making a game for the iPhone, and I have a class called Robot. Then I have a class called View, which renders everything. I want to send a copy of my Robot, which I defined in my ViewController, and I send it to gameView (which is View *gameView), like this: robot = [Robot new]; [gameView setRobot: [robot copy]]; I tried to make a copy but that didn't work, I could also do it with a pointer to Robot (&robot) but sometimes it just crashes ? I tried this in my View.h @interface definition: @property (copy) Robot* robot; but I get the error /RobotsAdventure/Classes/View.h:24: error: setter '-robot' argument type does not match property type :/ Help? I'm pretty new at this, heh.

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  • Loading an external NIB, how do I set the view property?

    - by Sheehan Alam
    If I am loading a view from another NIB, how do I set the File's Owner view property? IB is not letting me hook it up to my View Controller which is loading the external NIB. My NIB looks like this: File's Owner - Identity is set to LBRootViewController First Responder LBTableViewController - Identity is set to LBTableViewController, NIB Name is LBTableViewController

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