Search Results

Search found 18084 results on 724 pages for 'graphics programming'.

Page 189/724 | < Previous Page | 185 186 187 188 189 190 191 192 193 194 195 196  | Next Page >

  • Generate a polygon from line.

    - by VOX
    I want to draw a line with thickness in j2me. This can easily be achieved in desktop java by setting Pen width as thickness value. However in j2me, Pen class does not support width. My idea is to generate a polygon from the line I have, that resembles the line with thickness i want to draw. In picture, on the left is what I have, a line with points. On the right is what I want, a polygon that when filled, a line with thickness. Could anyone know how to generate a polygon from line? http://www.freeimagehosting.net/uploads/140e43c2d2.gif

    Read the article

  • GDI+, Smaller images ?

    - by Tony
    Hi I create a bitmap from bytes coming from the web, and I downsample it, the resulted Jpg is still too big although I use small pixel format, someone know how to manipulate compression of the image, because I had impression that the saved image is not compressed anymore. Thanks

    Read the article

  • What is the most efficient functional version of the following imperative code?

    - by justin.r.s.
    I'm learning Scala and I want to know the best way of expressing this imperative pattern using Scala's functional programming capabilities. def f(l: List[Int]): Boolean = { for (e <- l) { if (test(e)) return true } } return false } The best I can come up with is along the lines of: l map { e => test(e) } contains true But this is less efficient since it calls test() on each element, whereas the imperative version stops on the first element that satisfies test(). Is there a more idiomatic functional programming technique I can use to the same effect? The imperative version seems awkward in Scala.

    Read the article

  • How can you deflect a direction/magnitude vector based on a direction/magnitude vector and a collided triangle?

    - by JeanOTF
    So, I have a Triangle-AABB collision algorithm and I have it returning the triangle that the AABB collided with. I was hoping with the 3 vectors of the triangle and the direction/magnitude of the movement would let me determine a deflected vector so that when you run against the wall at an angle you move slower, depending on the angle of collision, but along side the wall. This would remove the sticky collision problem with only moving when there is not a collision. Any suggestions or references would be greatly appreciated! Thanks.

    Read the article

  • How to create lines with Athens?

    - by Kilon
    I have no clue how to create lines with Athens. I took a look at Cairo docs but I cant see how Athens is related to Cairo. http://zetcode.com/gfx/cairo/basicdrawing/ In the above link I cant find any equivalent for cairo_set_line_width(cr, 1); I tried to look inside Athens but is nowhere to be found. Overall I find the Athens architecture quite confusing though Cairo looks simple. Any idea how to makes this work ?

    Read the article

  • Detecting coincident subset of two coincident line segments

    - by Jared Updike
    This question is related to: How do I determine the intersection point of two lines in GDI+? (great explanation of algebra but no code) How do you detect where two line segments intersect? (accepted answer doesn't actually work) But note that an interesting sub-problem is completely glossed over in most solutions which just return null for the coincident case even though there are three sub-cases: coincident but do not overlap touching just points and coincident overlap/coincident line sub-segment For example we could design a C# function like this: public static PointF[] Intersection(PointF a1, PointF a2, PointF b1, PointF b2) where (a1,a2) is one line segment and (b1,b2) is another. This function would need to cover all the weird cases that most implementations or explanations gloss over. In order to account for the weirdness of coincident lines, the function could return an array of PointF's: zero result points (or null) if the lines are parallel or do not intersect (infinite lines intersect but line segments are disjoint, or lines are parallel) one result point (containing the intersection location) if they do intersect or if they are coincident at one point two result points (for the overlapping part of the line segments) if the two lines are coincident

    Read the article

  • Inner shadow issue in Illustrator CS5

    - by Joe Conlin
    I gave a comp to my client that I did in Photoshop. I used an inner shadow but now have realized the in Illustrator CS5 I have no such "easy" filter. I have spent 2 days seaching the web, trying tutorials, etc. to no avail. Every tutorial seems to use text but I am not using text. Anyone that can answer I would forever been in debt... :) This is the image with the inner shadow inside the stripes that I am needing to duplicate. Thanks!

    Read the article

  • PDF Making with Rotated Image for iPhone

    - by MobiHunterz
    I'm having problems with drawing rotated images on PDF, my output is worse. My case is, we don't know have any fixed co-ordinates. X,Y, rotation, etc. depends on ImageView itself. I select the ImageView and rotate it through Sliders. Check on ZOSH application. I need to implement functionalities like that app. I want to make PDF by adding images one by one. Please send me link for any example that can help me out, I'm stuck here. I'm drawing the image on PDF based on center of the imageview. Please help me, Thank You.

    Read the article

  • Cannot save Adobe Illustrations as .pdf files

    - by Parastar
    Hi, I use adobe Illustrator creative suite 3. Now there seems to be a problem. I can't save my Illustrations In the .pdf format, since this format seems to preserve the graphic quality this Is vitally Important to me. If I save the Graphic In .jpef /.gif or png there Is some serious loss of quality so I need to find out a way to get this sorted. when I try to save the graphic as pdf It says "An unknown error has occured" please can anyone help me out here? Thank you,

    Read the article

  • Transform shape built of contour splines to simple polygons

    - by Cheery
    I've dumped glyphs from truetype file so I can play with them. They have shape contours that consist from quadratic bezier curves and lines. I want to output triangles for such shapes so I can visualize them for the user. Traditionally I might use libfreetype or scan-rasterise this kind of contours. But I want to produce extruded 3D meshes from the fonts and make other distortions with them. So, how to polygonise shapes consisting from quadratic bezier curves and lines? There's many contours that form the shape together. Some contours are additive and others are subtractive. The contours are never open. They form a loop. (Actually, I get only contour vertices from ttf glyphs, those vertices define whether they are part of the curve or not. Even though it is easy to decompose these into bezier curves and lines, knowing the data is represented this way may be helpful for polygonizing the contours to triangles)

    Read the article

  • How Do Sockets Work in C?

    - by kaybenleroll
    I am a bit confused about socket programming in C. You create a socket, bind it to an interface and an IP address and get it to listen. I found a couple of web resources on that, and understood it fine. In particular, I found an article Network programming under Unix systems to be very informative. What confuses me is the timing of data arriving on the socket. How can you tell when packets arrive, and how big the packet is, do you have to do all the heavy lifting yourself? My basic assumption here is that packets can be of variable length, so once binary data starts appearing down the socket, how do you begin to construct packets from that?

    Read the article

  • Cloning ID3DXMesh with declration that has 12 floats breaks?

    - by meds
    I have the following vertex declration: struct MESHVERTInstanced { float x, y, z; // Position float nx, ny, nz; // Normal float tu, tv; // Texcoord float idx; // index of the vertex! float tanx, tany, tanz; // The tangent const static D3DVERTEXELEMENT9 Decl[6]; static IDirect3DVertexDeclaration9* meshvertinstdecl; }; And I declare it as such: const D3DVERTEXELEMENT9 MESHVERTInstanced::Decl[] = { { 0, 0, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_POSITION, 0 }, { 0, 12, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_NORMAL, 0 }, { 0, 24, D3DDECLTYPE_FLOAT2, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TEXCOORD, 0 }, { 0, 32, D3DDECLTYPE_FLOAT1, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TEXCOORD, 1 }, { 0, 36, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TANGENT, 0 }, D3DDECL_END() }; What I try to do next is copy an ID3DXMesh into another one with the new vertex declaration as such: model->CloneMesh( model->GetOptions(), MESHVERTInstanced::Decl, gd3dDevice, &pTempMesh ); When I try to get the FVF size of pTempMesh (D3DXGetFVFVertexSize(pTempMesh-GetFVF())) I get '0' though the size should be 48. The whole thing is fine if I don't have the last declaration, '{ 0, 36, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TANGENT, 0 },' in it and the CloneMesh function does not return a FAIL. I've also tried using different declarations such as D3DDECLUSAGE_TEXCOORD and that has worked fine, returning a size of 48. Is there something specific about D3DDECLUSAGE_TANGENT I don't know? I'm at a complete loss as to why this isn't working...

    Read the article

  • What did they program this toy with?

    - by Trix
    A rather strange question: I'm often asking myself with what programming languages things were created. I recently found this toy mini computer I played with when I was 13 or so at home. (Note: It is not one of those toy "notebooks", it's really small and came as an extra with a magazine) "Features": Hadware: LCD with a small field of pixels where the games were going on, besides that some stats such as score, highscore etc. Sounds and horrible music when started A really small "keyboard" with a wire Software: At least 14 or so games, from Snake over Tetris and Breakdown to some abomination of a car racing game A calculator Game selecting menu An alarm clock Inside there is a really small circuit board, I don't want to open the thing up now, though. Can you imagine if the games and "Operating System" of this thing where actually programmed using a language? If yes, what language could it be? If not with a programming language, how else was it created?

    Read the article

  • Merging and splitting overlapping rectangles to produce non-overlapping ones

    - by uj
    I am looking for an algorithm as follows: Given a set of possibly overlapping rectangles (All of which are "not rotated", can be uniformly represented as (left,top,right,bottom) tuplets, etc...), it returns a minimal set of (non-rotated) non-overlapping rectangles, that occupy the same area. It seems simple enough at first glance, but prooves to be tricky (at least to be done efficiently). Are there some known methods for this/ideas/pointers? Methods for not necessarily minimal, but heuristicly small, sets, are interesting as well, so are methods that produce any valid output set at all.

    Read the article

  • What is it like working as a computer programmer

    - by Luke101
    I have a day job as an IT system administrator, but I do a lot of c# asp.net programming on my spare time. I have always wondered what its like to be a real software developer. I have taken a look at big CMS systems like umbraco and Dotnetnuke and said to myself that these developers must have decades of programming experience. Just the design of these products are overwhelming let alone the actual code. I just would like your comments on what it is like being a programmer.

    Read the article

  • Can a JPEG compressed image be rotated without a loss in quality?

    - by Mat
    JPEG is a lossy compression scheme, so decompression-manipulation-recompression normally reduces the image quality further for each step. Is it possible to rotate a JPEG image without incurring further loss? From what little I know of the JPEG algorithm, it naively seems possible to avoid further loss with a bit of effort. Which common image manipulation programs (e.g. GIMP, Paint Shop Pro, Windows Photo Gallery) and graphic libraries cause quality loss when performing a rotation and which don't?

    Read the article

  • Changing direction of rotation Pygame

    - by czl
    How would you change the direction of a rotating image/rect in Pygame? Applying positive and negative degree values works but it seems to only be able to rotate one direction throughout my window. Is there a way to ensure a change in direction of rotation? Perhaps change up rotation of a spinning image every 5 seconds, or if able to change the direction of the spin when hitting a X or Y axis. I've added some code below. It seems like switching movement directions is easy with rect.move_ip as long as I specify a speed and have location clause, it does what I want. Unfortunately rotation is't like that. Here I'l adding angles to make sure it spins, but no matter what I try, I'm unable to negate the rotation. def rotate_image(self): #rotate image orig_rect = self.image.get_rect() rot_image = pygame.transform.rotate(self.image, self.angle) rot_rect = orig_rect.copy() rot_rect.center = rot_image.get_rect().center rot_image = rot_image.subsurface(rot_rect).copy() return rot_image def render(self): self.screen.fill(self.bg_color) self.rect.move_ip(0,5) #Y axis movement at 5 px per frame self.angle += 5 #add 5 anglewhen the rect has not hit one of the window self.angle %= 360 if self.rect.left < 0 or self.rect.right > self.width: self.speed[0] = -self.speed[0] self.angle = -self.angle #tried to invert the angle self.angle -= 5 #trying to negate the angle rotation self.angle %= 360 self.screen.blit(self.rotate_image(),self.rect) pygame.display.flip() I would really like to know how to invert rotation of a image. You may provide your own examples.

    Read the article

  • How to get ImageButton size within Android GridView?

    - by wufoo
    I'm subclassing ImageButton in order to draw lines on it and trying to figure out where the actual button coordinates are within my gridview. I am using onGlobalLayout to setup Top, Bottom, Right and Left, but these seem to be for the actual "square" within the grid, and not the actual button (see image). The purple lines are drawn in myImageButton.onDraw() using coords gathered from myImageButton.onGlobalLayout(). I thought these would be for the button, but they seem to be from something else. Not sure what. I'd like the purple lines to match the outline of the button so the lines I draw appear on the button and not just floating out in the LinearLayout somewhere. The light blue is the background color of the vertical LinearLayout holding the Textview (for the number) and myImageButton. Any way to get the actual button size? XML Layout: <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/lay_cellframe" android:layout_width="fill_parent" android:layout_height="fill_parent" > <LinearLayout android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="fill_vertical|fill_horizontal" android:orientation="vertical" > <TextView android:id="@+id/tv_cell" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2dp" android:gravity="center" android:text="TextView" android:textSize="10sp" /> <com.example.icaltest2.myImageButton android:id="@+id/imageButton1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_gravity="center" android:layout_margin="0dp" android:adjustViewBounds="false" android:background="@android:drawable/btn_default" android:scaleType="fitXY" android:src="@android:color/transparent" /> </LinearLayout> </FrameLayout> myImageButton.java public myImageButton (Context context, AttributeSet attrs) { super (context, attrs); mBounds = new Rect(); ViewTreeObserver vto = this.getViewTreeObserver (); vto.addOnGlobalLayoutListener (ogl); Log.d (TAG, "myImageButton"); } ... OnGlobalLayoutListener ogl = new OnGlobalLayoutListener() { @Override public void onGlobalLayout () { Rect b = getDrawable ().getBounds (); mBtnTop = b.centerY () - (b.height () / 2); mBtnBot = b.centerY () + (b.height () / 2); mBtnLeft = b.centerX () - (b.width () / 2); mBtnRight = b.centerX () + (b.width () / 2); } }; ... @Override protected void onDraw (Canvas canvas) { super.onDraw (canvas); Paint p = new Paint (); p.setStyle (Paint.Style.STROKE); p.setStrokeWidth (1); p.setColor (Color.MAGENTA); canvas.drawCircle (mBtnLeft, mBtnTop, 2, p); canvas.drawCircle (mBtnLeft, mBtnBot, 2, p); canvas.drawCircle (mBtnRight, mBtnTop, 2, p); canvas.drawCircle (mBtnRight, mBtnBot, 2, p); canvas.drawRect (mBtnLeft, mBtnTop, mBtnRight, mBtnBot, p); }

    Read the article

  • how to dynamically recolor a CGGradientRef

    - by saintmac
    I have three CGGradientRef's that I need to be able to dynamically recolor. When I Initialise the CGGradientRef's the first time I get the expected result, but every time I attempt to change the colors nothing happens. Why? gradient is an instance variable ins a subclass of CALayer: @interface GradientLayer : CALayer { CGGradientRef gradient; //other stuff } @end Code: if (gradient != NULL) { CGGradientRelease(gradient); gradient = NULL; } RGBA color[360]; //set up array CGColorSpaceRef rgb = CGColorSpaceCreateDeviceRGB(); gradient = CGGradientCreateWithColorComponents ( rgb, color, NULL, sizeof (color) / sizeof (color[0]) ); CGColorSpaceRelease(rgb); [self setNeedsDisplay];

    Read the article

  • Calculating the angle between two points

    - by kingrichard2005
    I'm currently developing a simple 2D game for Android. I have a stationary object that's situated in the center of the screen and I'm trying to get that object to rotate and point to the area on the screen that the user touches. I have the constant coordinates that represent the center of the screen and I can get the coordinates of the point that the user taps on. I'm using the formula outlined in this forum: How to get angle between two points? -It says as follows "If you want the the angle between the line defined by these two points and the horizontal axis: double angle = atan2(y2 - y1, x2 - x1) * 180 / PI;". -I implemented this, but I think the fact the I'm working in screen coordinates is causing a miscalculation, since the Y-coordinate is reversed. I'm not sure if this is the right way to go about it, any other thoughts or suggestions are appreciated.

    Read the article

  • Why are my lines getting thicker and thicker?

    - by mystify
    I try to draw some lines with different colors. This code tries to draw two rectangles with 1px thin lines. However, the second rectangle is drawn with 2px width lines, while the first one is drawn with 1px width. - (void)addLineFrom:(CGPoint)p1 to:(CGPoint)p2 context:(CGContextRef)context { // set the current point CGContextMoveToPoint(context, p1.x, p1.y); // add a line from the current point to the wanted point CGContextAddLineToPoint(context, p2.x, p2.y); } - (void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGPoint from, to; // ----- draw outer black frame (left, bottom, right) ----- CGContextBeginPath(context); // set the color CGFloat lineColor[4] = {26.0f * colorFactor, 26.0f * colorFactor, 26.0f * colorFactor, 1.0f}; CGContextSetStrokeColor(context, lineColor); // left from = CGPointZero; to = CGPointMake(0.0f, rect.size.height); [self addLineFrom:from to:to context:context]; // bottom from = to; to = CGPointMake(rect.size.width, rect.size.height); [self addLineFrom:from to:to context:context]; // right from = to; to = CGPointMake(rect.size.width, 0.0f); [self addLineFrom:from to:to context:context]; CGContextStrokePath(context); CGContextClosePath(context); // ----- draw the middle light gray frame (left, bottom, right) ----- CGContextSetLineWidth(context, 1.0f); CGContextBeginPath(context); // set the color CGFloat lineColor2[4] = {94.0f * colorFactor, 94.0f * colorFactor, 95.0f * colorFactor, 1.0f}; CGContextSetStrokeColor(context, lineColor2); // left from = CGPointMake(200.0f, 1.0f); to = CGPointMake(200.0f, rect.size.height - 2.0f); [self addLineFrom:from to:to context:context]; // bottom from = to; to = CGPointMake(rect.size.width - 2.0f, rect.size.height - 2.0f); [self addLineFrom:from to:to context:context]; // right from = to; to = CGPointMake(rect.size.width - 2.0f, 1.0f); [self addLineFrom:from to:to context:context]; // top from = to; to = CGPointMake(1.0f, 1.0f); [self addLineFrom:from to:to context:context]; CGContextStrokePath(context); }

    Read the article

< Previous Page | 185 186 187 188 189 190 191 192 193 194 195 196  | Next Page >