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  • Make interchangeable class types via pointer casting only, without having to allocate any new objects?

    - by HostileFork
    UPDATE: I do appreciate "don't want that, want this instead" suggestions. They are useful, especially when provided in context of the motivating scenario. Still...regardless of goodness/badness, I've become curious to find a hard-and-fast "yes that can be done legally in C++11" vs "no it is not possible to do something like that". I want to "alias" an object pointer as another type, for the sole purpose of adding some helper methods. The alias cannot add data members to the underlying class (in fact, the more I can prevent that from happening the better!) All aliases are equally applicable to any object of this type...it's just helpful if the type system can hint which alias is likely the most appropriate. There should be no information about any specific alias that is ever encoded in the underlying object. Hence, I feel like you should be able to "cheat" the type system and just let it be an annotation...checked at compile time, but ultimately irrelevant to the runtime casting. Something along these lines: Node<AccessorFoo>* fooPtr = Node<AccessorFoo>::createViaFactory(); Node<AccessorBar>* barPtr = reinterpret_cast< Node<AccessorBar>* >(fooPtr); Under the hood, the factory method is actually making a NodeBase class, and then using a similar reinterpret_cast to return it as a Node<AccessorFoo>*. The easy way to avoid this is to make these lightweight classes that wrap nodes and are passed around by value. Thus you don't need casting, just Accessor classes that take the node handle to wrap in their constructor: AccessorFoo foo (NodeBase::createViaFactory()); AccessorBar bar (foo.getNode()); But if I don't have to pay for all that, I don't want to. That would involve--for instance--making a special accessor type for each sort of wrapped pointer (AccessorFooShared, AccessorFooUnique, AccessorFooWeak, etc.) Having these typed pointers being aliased for one single pointer-based object identity is preferable, and provides a nice orthogonality. So back to that original question: Node<AccessorFoo>* fooPtr = Node<AccessorFoo>::createViaFactory(); Node<AccessorBar>* barPtr = reinterpret_cast< Node<AccessorBar>* >(fooPtr); Seems like there would be some way to do this that might be ugly but not "break the rules". According to ISO14882:2011(e) 5.2.10-7: An object pointer can be explicitly converted to an object pointer of a different type.70 When a prvalue v of type "pointer to T1" is converted to the type "pointer to cv T2", the result is static_cast(static_cast(v)) if both T1 and T2 are standard-layout types (3.9) and the alignment requirements of T2 are no stricter than those of T1, or if either type is void. Converting a prvalue of type "pointer to T1" to the type "pointer to T2" (where T1 and T2 are object types and where the alignment requirements of T2 are no stricter than those of T1) and back to its original type yields the original pointer value. The result of any other such pointer conversion is unspecified. Drilling into the definition of a "standard-layout class", we find: has no non-static data members of type non-standard-layout-class (or array of such types) or reference, and has no virtual functions (10.3) and no virtual base classes (10.1), and has the same access control (clause 11) for all non-static data members, and has no non-standard-layout base classes, and either has no non-static data member in the most-derived class and at most one base class with non-static data members, or has no base classes with non-static data members, and has no base classes of the same type as the first non-static data member. Sounds like working with something like this would tie my hands a bit with no virtual methods in the accessors or the node. Yet C++11 apparently has std::is_standard_layout to keep things checked. Can this be done safely? Appears to work in gcc-4.7, but I'd like to be sure I'm not invoking undefined behavior.

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  • Enabling Compiz Viewport Switcher key bindings

    - by David Moles
    I'm running compiz 0.8.2 with compizconfig on Scientific Linux 6.2 with Gnome 2.28.2. In the compizconfig "General Options" I have "Desktop Size" set as follows: Horizontal Virtual Size: 6 Vertical Virtual Size: 1 Number of Desktops: 1 This gets me the layout I want, i.e. 6 workspaces in a horizontal layout. Ctrl-alt-cursor-keys work fine for switching between them. However, I can't figure out how to get key bindings for specific workspaces. I've tried enabling "Viewport Switcher" in compizconfig, and tried various combinations both in "Number-based viewport switching" and "Go to specific viewport", to no apparent effect. My first thought was that something else was eating the specific key bindings I chose, but I think I've tried every combination of shift, control, alt and super (i.e., the Windows key) by now. I tried setting 6 desktops under "General Options" instead of one desktop with horizontal virtual size 6, but that doesn't seem to make a difference either. What am I missing?

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  • How can I see the structure of a webpage inline?

    - by Coldblackice
    How can I see a webpage's structure "inline" with the visual representation of the actual page, all at once? I'm trying to understand HTML layout better, but it's hard to get a feel for it, even having the source open on a separate monitor, because there's just so much expansive and miscellaneous code. I suppose I could sift through it, clean it up, and set up some type of custom collapsible tree system, but that would take too long for the amount of pages I'd like to get a quick view of the layout/structure of. For reference, I'm using Firefox for my internet browsing.

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • Java SWT - placing image buttons on the image background

    - by foma
    I am trying to put buttons with images(gif) on the background which has already been set as an image (shell.setBackgroundImage(image)) and I can't figure out how to remove transparent border around buttons with images. I would be grateful if somebody could give me some tip about this issue. Here is my code: import org.eclipse.swt.widgets.*; import org.eclipse.swt.layout.*; import org.eclipse.swt.*; import org.eclipse.swt.graphics.*; public class Main_page { public static void main(String[] args) { Display display = new Display(); Shell shell = new Shell(display); Image image = new Image(display, "bg.gif"); shell.setBackgroundImage(image); shell.setBackgroundMode(SWT.INHERIT_DEFAULT); shell.setFullScreen(true); Button button = new Button(shell, SWT.PUSH); button.setImage(new Image(display, "button.gif")); RowLayout Layout = new RowLayout(); shell.setLayout(Layout); shell.open(); while (!shell.isDisposed()) { if (!display.readAndDispatch()) display.sleep(); } display.dispose(); } } Sorceror, thanks for your answer I will definitely look into this article. Maybe I will find my way. So far I have improved my code a little bit. Firstly, I managed to get rid of the gray background noise. Secondly, I finally succeeded in creating the button as I had seen it in the first place. Yet, another obstacle has arisen. When I removed image(button) transparent border it turned out that the button change its mode(from push button to check box). The problem is that I came so close to the thing I was looking for and now I am a little puzzled. If you have some time please give a glance at my code. Here is the code, if you launch it you will see what the problem is(hope you didn't have problems downloading images): import org.eclipse.swt.widgets.*; import org.eclipse.swt.layout.*; import org.eclipse.swt.*; import org.eclipse.swt.graphics.*; public class Main_page { public static void main(String[] args) { Display display = new Display(); Shell shell = new Shell(display); Image image = new Image(display, "bg.gif"); // Launch on a screen 1280x1024 shell.setBackgroundImage(image); shell.setBackgroundMode(SWT.TRANSPARENT); shell.setFullScreen(true); GridLayout gridLayout = new GridLayout(); gridLayout.marginTop = 200; gridLayout.marginLeft = 20; shell.setLayout(gridLayout); // If you replace SWT.PUSH with SWT.COLOR_TITLE_INACTIVE_BACKGROUND // you will see what I am looking for, despite nasty check box Button button = new Button(shell, SWT.PUSH); button.setImage(new Image(display, "moneyfast.gif")); shell.open(); while (!shell.isDisposed()) { if (!display.readAndDispatch()) display.sleep(); } display.dispose(); }

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  • Ubuntu's file-roller problem 5010. "Cannot open display"

    - by Denis
    Hello everybody! I use "file-roller" to manage with archieves on my Ubuntu. But it fails on running without user interface(just teminal). The error is shown below. ** (file-roller:5453): CRITICAL **: Failed to parse arguments: Cannot open display: How can I prevent file-roller from using GUI or can you recommend me any other archieve manager I can use from terminal. It would be perfect, if this manager can handle as much formats as it is possible.

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  • Tomcat does not persist UserPrinciple during restart

    - by mabuzer
    How to force Tomcat to serialize UserPrinciple so that the user is kept logged in when Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.26

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  • Tomcat does not persist Session during restart

    - by mabuzer
    How to force Tomcat to serialize Session so that the user is kept logged in when Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.24

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  • error Caused by: java.lang.OutOfMemoryError Load Image

    - by user2493770
    This is my method to load images in background, the first and second load normally. But after these loading, a memory error appears. How can I fix this? public class MainArrayAdapterViewHolder extends ArrayAdapter<EmpresaListaPrincipal> { private final Context context; private ArrayList<EmpresaListaPrincipal> data_array; public DisplayImageOptions options; public ImageLoader imageLoader = ImageLoader.getInstance(); public MainArrayAdapterViewHolder(Context context, ArrayList<EmpresaListaPrincipal> list_of_ids) { super(context, R.layout.main_list_rowlayout, list_of_ids); this.context = context; this.data_array = list_of_ids; //------------- read more here https://github.com/nostra13/Android-Universal-Image-Loader options = new DisplayImageOptions.Builder().showImageForEmptyUri(R.drawable.ic_launcher).showImageOnFail(R.drawable.ic_launcher).resetViewBeforeLoading() .cacheOnDisc().imageScaleType(ImageScaleType.IN_SAMPLE_INT).bitmapConfig(Bitmap.Config.RGB_565).delayBeforeLoading(0).build(); File cacheDir = StorageUtils.getCacheDirectory(context); ImageLoaderConfiguration config = new ImageLoaderConfiguration.Builder(context).memoryCacheExtraOptions(720, 1280) // default = device screen // dimensions .discCacheExtraOptions(720, 1280, CompressFormat.JPEG, 100).threadPoolSize(3) // default .threadPriority(Thread.NORM_PRIORITY - 1) // default .memoryCacheSize(2 * 1024 * 1024).discCache(new UnlimitedDiscCache(cacheDir)) // default .discCacheSize(50 * 1024 * 1024).discCacheFileCount(100).discCacheFileNameGenerator(new HashCodeFileNameGenerator()) // default .imageDownloader(new BaseImageDownloader(context)) // default .tasksProcessingOrder(QueueProcessingType.FIFO) // default .defaultDisplayImageOptions(options) // default .build(); imageLoader.init(config); } @Override public View getView(int position, View convertView, ViewGroup parent) { ViewHolder viewholder; View v = convertView; //Asociamos el layout de la lista que hemos creado e incrustamos el ViewHolder if(convertView == null){ LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); //View rowView = inflater.inflate(R.layout.main_list_rowlayout, parent, false); v = inflater.inflate(R.layout.main_list_rowlayout, parent, false); viewholder = new ViewHolder(); viewholder.textView_main_row_title = (TextView) v.findViewById(R.id.textView_main_row_title); viewholder.imageView_restaurant_icon = (ImageView) v.findViewById(R.id.imageView_restaurant_icon); viewholder.textView_main_row_direccion = (TextView) v.findViewById(R.id.textView_main_row_direccion); v.setTag(viewholder); } ImageLoadingListener mImageLoadingListenr = new ImageLoadingListener() { @Override public void onLoadingStarted(String arg0, View arg1) { // Log.e("* started *", String.valueOf("complete")); } @Override public void onLoadingComplete(String arg0, View arg1, Bitmap arg2) { // Log.e("* complete *", String.valueOf("complete")); } @Override public void onLoadingCancelled(String arg0, View arg1) { } @Override public void onLoadingFailed(String arg0, View arg1, FailReason arg2) { // TODO Auto-generated method stub } }; try { viewholder = (ViewHolder) v.getTag(); viewholder.textView_main_row_title.setText(data_array.get(position).getNOMBRE()); viewholder.textView_main_row_direccion.setText(data_array.get(position).getDIRECCION()); String image = data_array.get(position).getURL(); // ------- image --------- try { if (image.length() > 4) imageLoader.displayImage(image, viewholder.imageView_restaurant_icon, options, mImageLoadingListenr); } catch (Exception ex) { } //textView_main_row_title.setText(name); //textView_main_row_address.setText(address); } catch (Exception e) { // TODO: handle exception } return v; } public class ViewHolder { public TextView textView_main_row_title; public TextView textView_main_row_direccion; //public TextView cargo; public ImageView imageView_restaurant_icon; } }

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  • Setting custom SQL in django admin

    - by eugene y
    I'm trying to set up a proxy model in django admin. It will represent a subset of the original model. The code from models.py: class MyManager(models.Manager): def get_query_set(self): return super(MyManager, self).get_query_set().filter(some_column='value') class MyModel(OrigModel): objects = MyManager() class Meta: proxy = True Now instead of filter() I need to use a complex SELECT statement with JOINS. What's the proper way to inject it wholly to the custom manager?

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  • Two Script Managers in one .aspx webform

    - by still Dummy
    Using two ScriptManagers(ASP.Net and Telerik) will effect the page performance ? I have both ASP.Net and Telerik Controls on the same page and I'm using both ASP.Net and Telerik Script managers. Can I avoid using one script manager ? How will the page performance is varried if I use two script managers ? and Refering Source/SCript files in one Script manager can be used accross the other controls ?

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  • Android framework

    - by Anxious
    Hi, If someone asks me the below questions What an Android Framework is? What does it do? How should I answer? Also what is the role of API's such as Activity Manager, Location Manager etc in the Framework?

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  • how to generate an N level tree using datatable?

    - by Kishore Kumar
    I have a DataTable with column ID, Name, RootID. The tree stucture is implmented using the RootId field. If the RootId is null it is considered as Root Node. How to create an Nlevel tree using the DataTale. eg. 1 Manager null, 2 Project Lead 1, 3 Test Lead 1, 4 Sr Soft Eng 2, 5 Soft eng 2, 6 HR Manager Null, 7 HR exec 6, ......

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  • C++: How to require that one template type is derived from the other

    - by Will
    In a comparison operator: template<class R1, class R2> bool operator==(Manager<R1> m1, Manager<R2> m2) { return m1.internal_field == m2.internal_field; } Is there any way I could enforce that R1 and R2 must have a supertype or subtype relation? That is, I'd like to allow either R1 to be derived from R2, or R2 to be derived from R1, but disallow the comparison if R1 and R2 are unrelated types.

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  • how to use JSF 1.2 and JPA in Netbeans ?

    - by user364746
    Hello... I'm trying to use JPA to connect my JSF components to database but the problem is that I can't figure out how to get this all combination works.I have done entity classes from database, also create persistence.xml file and now I don't know where to go!! I don't know how to use entity manager and entity manager factory. Is there any tutorial helps me how to use Java EE 5,JSF 1.2 and JPA in netbeans? any help appreciated Thanks

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  • Software loading error problem

    - by Gopal
    VB6 & SQL Server 2005 When i run the Windows based Software exe file, it is showing the login page, after login page - no screen is displaying, I checked the task manager, in task manager it is showing as software as running, But there is no page is appearing. Is any firewall blocking or some other issue. But software is running with out displaying anythings. How to solve this issue?

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  • C++ require that one template type is derived from the other

    - by Will
    In a comparison operator: template<class R1, class R2> bool operator==(Manager<R1> m1, Manager<R2> m2) { return p1.internal_field == p2.internal_field; } Is there any way I could enforce that R1 and R2 must have a supertype or subtype relation? That is, I'd like to allow either R1 to be derived from R2, or R2 to be derived from R1, but disallow the comparison if R1 and R2 are unrelated types.

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  • SharePoint and COMException (0x80004005): Cannot complete this action

    - by Damon
    I ran into a small issue today working on a deployment.  We were moving a custom ASP.NET control from my development environment into a SharePoint layout page on a staging environment .  I was expecting some minor issues to arise since I had developed the control in an ASP.NET website project, but after getting everything moved over we got an obscure COMException error the that looked like this: Cannot complete this action. Please try again. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Runtime.InteropServices.COMException: Cannot complete this action. [COMException (0x80004005): Cannot complete this action. .Lengthy stack trace goes here. Everything in the custom control was built using managed code, so we weren't sure why a COMException would suddenly appear. The control made use of an ITemplate to define its UI, so there was a lot of markup and binding code inside the template. As such, we started taking chunks of the template out of the layout page and eventually the error went away.  It was being caused by a section of code where we were calling a custom utility method inside some binding code: <%# WebUtility.FormatDecimal(.) %> Solution: It turns out that we were missing an Assembly and Import directive at the top of the page to let the page know where to find this method.  After adding these to the page, the error went away and everything worked great.  So a COMException (0x80004005) Cannot complete this action error is just SharePoint's friendly way of letting you know you're missing an assembly or imports reference.

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  • Data Web Controls Enhancements in ASP.NET 4.0

    Traditionally, developers using Web controls enjoyed increased productivity but at the cost of control over the rendered markup. For instance, many ASP.NET controls automatically wrap their content in <table> for layout or styling purposes. This behavior runs counter to the web standards that have evolved over the past several years, which favor cleaner, terser HTML; sparing use of tables; and Cascading Style Sheets (CSS) for layout and styling. Furthermore, the <table> elements and other automatically-added content makes it harder to both style the Web controls using CSS and to work with the controls from client-side script. One of the aims of ASP.NET version 4.0 is to give Web Form developers greater control over the markup rendered by Web controls. Last week's article, Take Control Of Web Control ClientID Values in ASP.NET 4.0, highlighted how new properties in ASP.NET 4.0 give the developer more say over how a Web control's ID property is translated into a client-side id attribute. In addition to these ClientID-related properties, many Web controls in ASP.NET 4.0 include properties that allow the page developer to instruct the control to not emit extraneous markup, or to use an HTML element other than <table>. This article explores a number of enhancements made to the data Web controls in ASP.NET 4.0. As you'll see, most of these enhancements give the developer greater control over the rendered markup. Read on to learn more! Read More >Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Data Web Controls Enhancements in ASP.NET 4.0

    Traditionally, developers using Web controls enjoyed increased productivity but at the cost of control over the rendered markup. For instance, many ASP.NET controls automatically wrap their content in <table> for layout or styling purposes. This behavior runs counter to the web standards that have evolved over the past several years, which favor cleaner, terser HTML; sparing use of tables; and Cascading Style Sheets (CSS) for layout and styling. Furthermore, the <table> elements and other automatically-added content makes it harder to both style the Web controls using CSS and to work with the controls from client-side script. One of the aims of ASP.NET version 4.0 is to give Web Form developers greater control over the markup rendered by Web controls. Last week's article, Take Control Of Web Control ClientID Values in ASP.NET 4.0, highlighted how new properties in ASP.NET 4.0 give the developer more say over how a Web control's ID property is translated into a client-side id attribute. In addition to these ClientID-related properties, many Web controls in ASP.NET 4.0 include properties that allow the page developer to instruct the control to not emit extraneous markup, or to use an HTML element other than <table>. This article explores a number of enhancements made to the data Web controls in ASP.NET 4.0. As you'll see, most of these enhancements give the developer greater control over the rendered markup. Read on to learn more! Read More >

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  • How To Add Image And Text Watermarks to MS Word Documents

    - by Kavitha
    Watermark is a faint image that appears behind your text in MS Word Documents. Draft/Confidential are the most common background watermarks that we see in the documents circulated at office. MS Word 2007/2010 makes it very easy add watermarks as well as customize them based on the requirements. Add Image Watermark To MS Word Document To add image watermark to your document follow these steps 1. Switch to Page Layout tab of Ribbon Menu 2. Click on Watermark drop down menu and choose Custom Watermark option 3. Choose Picture watermark option, click on the button Select Picture.. and choose watermark image 4. Click Ok. That all. You are done. Add Text Watermark To MS Word Document To add image watermark to your document follow these steps 1. Switch to Page Layout tab of Ribbon Menu 2. Click on Watermark drop down menu 3. In the opened window, you can select one of the predefined text watermarks like Confidential, Draft, ASAP, URGENT, etc. If you are looking for one of these watermarks, you can choose them otherwise click on the option Custom Watermark… 4. Choose the option Text watermark and enter the text you want to set as watermark in the input area Text: (highlighted below). 5. Click on OK button. That’s all. This article titled,How To Add Image And Text Watermarks to MS Word Documents, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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