Search Results

Search found 20931 results on 838 pages for 'mysql insert'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 189/838 | < Previous Page | 185 186 187 188 189 190 191 192 193 194 195 196  | Next Page >

  • how can I select data from MySQL based on date (unix time record)

    - by bn
    I have a record of data with unix time date in it i want to select the row based on the date/month/year only (not with time) currently Im using something like this select * from tablename where date > '$today' and date < '$tomorow' LIMIT 1; how ever this is not that accurate if the $today and $tomorrow have different time (but same date) is there any better way to do this?

    Read the article

  • block write access to table from an application in mysql

    - by hoberion
    Hello, We have a CMS plugin that writes statistics to 1 table, this creates performance issues on the entire platform. We decided to use another statistics plugin which can connect to a different database server (the first plugin couldn't!) however we need parts of the first plugin. I want to lock the statistics table to prevent misusage (not allowed to drop it by the developer) So I was wondering if a lock table could do this or if I can implement some sort of read only table

    Read the article

  • PHP Code- How to check duplicate entries in Mysql Database

    - by yash bhavnani
    Hi guys, I am working on Google checkout API notification URL. I want to apply a check in my php code which will see if transaction ID present in transaction table of my DB, it will exit not process. I am struggling into applying here. Can somebody help? I want to check if trasaction ID exists in table of DB it will exit, it will not process: *case "new-order-notification": $sql = "update transactions set remote_trans_id=\"".$_REQUEST["google-order-number"]."\", updated=now() where id=".$_REQUEST["shopping-cart_items_item-1_merchant-item-id"]." "; execute($sql, $conn); break;* Regards

    Read the article

  • mysql - combining columns and tables

    - by Phil Jackson
    Hi, I'm not much of a SQL man so I'm seeking help for this one. I have a site where I have a database for all accounts and whatnot, and another for storing actions that the user has done on the site. Each user has their own table but I want to combine the data of each user group ( all users that are "linked together" ) and order that data in the time the actions took place. Heres what I have; <?php $query = "SELECT `TALKING_TO` FROM `nnn_instant_messaging` WHERE `AUTHOR` = '" . DISPLAY_NAME . "' AND `TALKING_TO` != ''"; $query = mysql_query( $query, $CON ) or die( "_error_ " . mysql_error()); if( mysql_num_rows( $query ) != 0 ) { $table_str = ""; $select_ref_clause = "( "; $select_time_stamp_clause = "( "; while( $row = mysql_fetch_array( $query ) ) { $table_str .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . "`, "; $select_ref_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".REF`, "; $select_time_stamp_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".TIME_STAMP`, "; } $table_str = $table_str . "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; $select_ref_clause = substr($select_ref_clause, 0, -2) . ") AS `REF`, "; $select_time_stamp_clause = substr($select_time_stamp_clause, 0, -2) . " ) AS `TIME_STAMP`"; }else{ $table_str = "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; $select_ref_clause = "`REF`, "; $select_time_stamp_clause = "`TIME_STAMP`"; } $where_clause = $select_ref_clause . $select_time_stamp_clause; $query = "SELECT " . $where_clause . " FROM " . $table_str . " ORDER BY TIME_STAMP"; die($query); $query = mysql_query( $query, $CON ) or die( "_error_ " . mysql_error()); if( mysql_num_rows( $query ) != 0 ) { }else{ ?> <p>Currently no actions have taken place in your network.</p> <?php } ?> The code above returns the sql statement: SELECT ( `actvbiz_networks`.`john_doe.REF`, `actvbiz_networks`.`Emmalene_Jackson.REF`) AS `REF`, ( `actvbiz_networks`.`john_doe.TIME_STAMP`, `actvbiz_networks`.`Emmalene_Jackson.TIME_STAMP` ) AS `TIME_STAMP` FROM `actvbiz_networks`.`john_doe`, `actvbiz_networks`.`Emmalene_Jackson`, `actvbiz_networks`.`act_web_designs` ORDER BY TIME_STAMP I really am learning on my feet with SQL. Its not the PHP I have a problem with ( I can quite happly code away with PHP ) I'ts just help with the SQL statement. Any help much appreciated, REgards, Phil

    Read the article

  • Does introducing foreign keys to MySQL reduce performance

    - by Tam
    I'm building Ruby on Rails 2.3.5 app. By default, Ruby on Rails doesn't provide foreign key contraints so I have to do it manually. I was wondering if introducing foreign keys reduces query performance on the database side enough to make it not worth doing. Performance in this case is my first priority as I can check for data consistency with code. What is your recommendation in general? do you recommend using foreign keys? and how do you suggest I should measure this?

    Read the article

  • MYSQL if statement question...

    - by Dennis_M
    Is there any way to get the if statement to evaluate a query? SELECT if(50,'EQ_Type','*') FROM EQUIPMENT; Resulting in: +-----------------------+ | IF(50,'EQ_Type','*') | +-----------------------+ | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | +-----------------------+ 9 rows in set (0.00 sec) I would like the above statement to be equivalent to the following: SELECT 'EQ_Type' FROM EQUIPMENT; And produce: +--------------+ | EQ_Type | +--------------+ | ENGINE | | ENGINE | | ENGINE | | TRAILER | | TRAILER | | TRAILER | | WATER TENDER | | WATER TENDER | | WATER TENDER | +--------------+ Thanks for any help

    Read the article

  • how to update mysql with inputs and checkboxes

    - by Ronnie Chester Lynwood
    hi. with this code: <? if (isset($_POST['onay'])) { foreach ($_POST['secilen'] as $zuha) { $olay = mysql_query("update mp3 SET aktif = '1' WHERE id = '$zuha'"); } if ($olay) { echo "islem tamam"; exit; } } ?> and with this form: (select * from mp3 aktif = '0') <form name="form" method="post"> <input readonly type="text" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <input type="checkbox" name="secilen[]" value="<?=$haciosman['id']?>"> <input type="submit" name="onay" value="Onayla" /> I can set "aktif to 1" for each row that i checked. but i want to update "baslik" too! how can i update each "baslik" with that php code?

    Read the article

  • MySQL ORDER BY rand(), name ASC

    - by Josh K
    I would like to take a database of say, 1000 users and select 20 random ones (ORDER BY rand(),LIMIT 20) then order the resulting set by the names. I came up with the following query which is not working like I hoped. SELECT * FROM users WHERE 1 ORDER BY rand(), name ASC LIMIT 20

    Read the article

  • Input questions mysql php html

    - by Marcelo
    (Q1)Hi I'm using textbox in my project and I can't receive the values that are typed <textarea rows="5" cols="60"> Type your suggestion </textarea> <br> <input type="submit" name="sugestao" value="Submit" /> Sorry I don't know how to 'kill' html code, that's why < is missing. All I'm getting in the column of the database from this text box is "Submit", I'd like to receive whatever is written in the text area. How can I make the value equal whaterever is typed? (Q2) How can I make sure that I'll only store the same type(int,varchar,text) that I setted,declared in the database. For example: age(int), but if someone types "abc" in the input it will be stored in my database as the value 0 . How can I forbid this, and only save the age when it's just int and all the other fields(like name, email) are filled ?. And if is still possible warn the user that he is typing something wrong, don't need to say where. Sorry for any mistake in English and Thanks for the attention.

    Read the article

  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

    Read the article

  • MYSQL Query with 2 columns in Table A related to 1 column in Table B

    - by CYREX
    I have 2 Tables, User and Mail. In User Table i have 2 columns that i will use, the ID column which makes the relation with the Mail Table and it is the Index of User Table and the Name column. In Mail Table i have Receiver Column and Sender Column. Both columns, Receiver and Sender have a number that relates to the ID Column in the User Table. In the User Table is where the name columns resides and i want to make a query that shows me the Receiver and Sender Columns but with the name of the user, not the ID. Up to this point i have this: SELECT name AS Send, name AS Receive FROM mail,user WHERE sender=guid; I know there is still a part of the query missing but i can not figure out what else to put to tell it to show in the SEND output column the name of the sender and in the RECEIVE output column the name of the receiver.

    Read the article

  • best way to prgram php and mysql query

    - by air
    most of times in our pages we need to print only 1 field value of table in loop. for example <?php for($i=1;$i<=mysql_num_rows($result);$i++) { echo $row['name']; $sql1="select industry from table_industry where profid='".$row['prof']."'"; $result1=mysql_query($sql1); $row1=mysql_fetch_array($result1); echo $row1['industry']; ?> } ?> above is one PHP code just for example where we think that $row['prof'] carry value of profession ID and we print profession of each person. for example we have 5000+ record in table and above loop will execute for 5000+ times what will be the best way to print value of industry field from table table_industry Same code which i write above ? any other php code suggestion for faster execution and less use of resources? Thanks

    Read the article

  • Union Distinct rows but order them by number of occurrences in mysql

    - by Baversjo
    Hi I have the following query: SELECT o.id,o.name FROM object o WHERE ( o.description LIKE '%Black%' OR o.name LIKE '%Black%' ) UNION ALL SELECT o2.id,o2.name FROM object o2 WHERE ( o2.description LIKE '%iPhone%' OR o2.name LIKE '%iPhone%' ) Which procude the following: id name 2 New Black iPhone 1 New White iPhone 2 New Black iPhone I would like to UNION DISTINCT, but I would also like the result ordered by the number of occurrences of each identical row (primary: id).

    Read the article

  • MySQL: 4 Table "has-many-through" Join?

    - by Nebs
    Let's say I have the following 4 tables (for examples' sake): Owners, Trucks, Boxes, Apples. An owner can have many trucks, a truck can have many boxes and a box can have many apples. Owners have an id. Trucks have an id and owner_id. Boxes have an id and truck_id. Apples have an id and box_id. Let's say I want to get all the apples "owned" by an owner with id = 34. So I want to get all the boxes that are in boxes that are in trucks that owner 34 owns. There is a "hierarchy" if you will of 4 tables that each only has reference to its direct "parent". How can I quickly filter boxes while satisfying conditions across the other 3 tables? I hope that made sense somewhat. Thanks.

    Read the article

  • MySQL: Question about SELECT WHERE AND/OR

    - by Andrew
    I'm trying to write a query that returns the same result from three different events, but I think I am doing it wrong. I can run my query against one event ID and it works. How can I select all three? Here's what I have so far: SELECT * FROM `Registrations` WHERE `Role` = "Attendee" AND `RegistrationStatus_ID` = "1" AND `DigSignature` IS NULL AND `Event_ID` = "147" OR `Event_ID` = "155" OR `Event_ID` = "160"

    Read the article

  • How do i know if a mysql table is using myISAM or InnoDB Engine

    - by kamal
    I want to confirm if the statement below is indeed true: There is no way to specify a storage engine for a certain database, only for single tables, You can, however, specify a storage engine to be used during one session with: SET storage_engine=InnoDB; so you don't have to specify it for each table. How do i confirm, if indeed all the tables are using InnoDB All the tables were using myISAM.

    Read the article

  • MySQL Join issue

    - by mouthpiec
    Hi, I have the following tables: --table sportactivity-- sport_activity_id, home_team_fk, away_team_fk, competition_id_fk, date, time (tuple example) - 1, 33, 41, 5, 2010-04-14, 05:40:00 --table teams-- team_id, team_name (tuple example) - 1, Algeria Now I have the following SQL statment that I use to extract Team A vs Team B SELECT sport_activity_id, T1.team_name AS TeamA, T2.team_name AS TeamB, DATE_FORMAT( DATE, '%d/%m/%Y' ) AS DATE, DATE_FORMAT( TIME, '%H:%i' ) AS TIME FROM sportactivity JOIN teams T1 ON home_team_fk = T1.team_id JOIN teams T2 ON ( away_team_fk = T2.team_id OR away_team_fk = '0' ) WHERE DATE( DATE ) >= CURDATE( ) ORDER BY DATE( DATE ) My problem is that when team B is empty, I am having irrelevant information .... it seems that it is returning all the combinations. I need a query that when team B is equal to 0, (this can occur in my scenario) I get only Team A - Team B (as 0) once.

    Read the article

  • MySQL - Join as zero if record Not IN

    - by Zurahn
    To explain by example, take two tables, A and B Table A id foo 1 x 2 y 3 z Table B id aid bar 1 3 50 2 1 100 An example join SELECT foo, bar FROM a, b WHERE a.id = b.aid; Garners a result of foo bar z 50 x 100 What I would like to do is get all values of foo and for any instances where there isn't a corresponding bar value, return 0 for that column. My best guess was something along the lines of SELECT foo, bar AS br FROM a, b WHERE a.id = b.aid OR a.id NOT IN (SELECT aid FROM b); But that returns duplicates and non-zero values for bar. Possible?

    Read the article

  • mysql stored funtion usage

    - by shikhar
    I just wrote a stored function to calculate the working days between two dates. This works select CountWeekDays('2010-03-07','2010-04-07') This doesn't work select CountWeekDays(o.order_date,o.created_date) from orders o; Any idea how to make this one work ?? function definition delimiter $$; CREATE FUNCTION CountWeekDays (sdate VARCHAR(50), edate VARCHAR(50)) RETURNS INT BEGIN DECLARE wdays, tdiff, counter, thisday smallint; DECLARE newdate DATE; SET newdate := sdate; SET wdays = 0; if DATEDIFF(edate, sdate) = 0 THEN RETURN 1; END IF; if DATEDIFF(edate, sdate) < 0 THEN RETURN 0; END IF; label1: LOOP SET thisday = DAYOFWEEK(newdate); IF thisday BETWEEN 2 AND 6 THEN SET wdays := wdays + 1; END IF; SET newdate = DATE_ADD(newdate, INTERVAL 1 DAY); IF DATEDIFF(edate, newdate) < 0 THEN LEAVE label1; END IF; END LOOP label1; RETURN wdays; END

    Read the article

  • many to many relationship mysql select

    - by zeina
    Let's consider 2 tables "schools" and "students". Now a student may belong to different schools in his life, and a school have many students. So this is a many to many example. A third table "links" specify the relation between student and school. Now to query this I do the following: Select sc.sid , -- stands for school id st.uid, -- stands for student id sc.sname, -- stands for school name st.uname, -- stands for student name -- select more data about the student joining other tables for that from students s left join links l on l.uid=st.uid -- l.uid stands for the student id on the links table left join schools sc on sc.sid=l.sid -- l.sid is the id of the school in the links table where st.uid=3 -- 3 is an example this query will return duplicate data for the user id if he has more than one school, so to fix this I added group by st.uid, yet I also need the list of school name related to the same user. Is there a way to do it with fixing the query I wrote instead of having 2 queries? So as example I want to have Luci of schools ( X, Y, Z, R, ...) etc

    Read the article

  • PHP MySQL Select multiple tables

    - by Jordan Pagaduan
    Is it posibble to select 3 tables at a time in 1 database? Table 1: employee -- employee_id -- first_name -- last_name -- middle_name -- birthdate -- address -- gender -- image -- salary Table 2: logs -- log_id -- full_name -- employee_id -- date -- time -- status Table 2: logout -- log_id -- full_name -- employee_id -- date -- time -- status I wanted to get the value of employee table where $id of selected. Then the $id also get the value of log.time, log.date, logout.time, and logout.date. I already try using UNION but nothing happens.

    Read the article

  • How to refactor this MySQL code?

    - by Jader Dias
    SELECT * ( SELECT * FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE `col4` = 5 ) group by `col2` having sum(`col3`) > 0 UNION SELECT * FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE `col4` = 5 ) group by `col2` having sum(`col3`) = 0 ) t1; For readability and performance reasons, I think this code could be refactored. But how?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 185 186 187 188 189 190 191 192 193 194 195 196  | Next Page >