mysql table - Page 190 - Developer IT

Two drop down lists in Ajax and MySQL

- by Milla

I'm trying to learn some Ajax and MySQL... Basically, the code that I have right now is similar to: http://www.w3schools.com/PHP/php_ajax_database.asp I was wondering how should I modify those codes (both html, javascript and php) to create two drop down lists. The first drop list would be used for choosing the Lastname (eg. Swanson) and the second drop list would be used for choosing the Hometown (eg. Quahog). Then the user would click "Submit" button and the query would return the matching results (eg. all the Swansons living in Quahog). I'd be very thankful for all the ideas!

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How to find root cause for "too many connections" error in MySQL/PHP

- by Nir

I'm running a web service which runs algorithms that serve millions of calls daily and run some background processing as well. Every now and than I see "Too many connections" error in attempts to connect to the MySQL box" for a few seconds. However this is not necessarily attributed to high traffic times or anything I can put my finger on. I want to find the bottleneck causing it. Other than in the specific times this happens the server isn't too loaded in terms of CPU and Memory, and has 2-3 connections (threads) open and everything works smoothly. (I use Zabbix for monitoring) Any creative ideas on how to trace it?

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viewing data using php and mysql

- by circle

hello, i'm circle.very new in php and mysql.i need to develop a website include with database.but i have a problem with this. i'm using php and sql to develop it.my task is: i have two table, investor and commission. investor have three level which is coordinator, consultant and participant.what should i do is, only coordinator can add consultant and participant in their profile.and only coordinator can add participant in their profile. so here, when investor was login, and they go to view commission, they only can see their owned coordinator and participant. but i'm stuck when they want to view the commission.maybe it only a simple thing, but i cannot solved it. help me..:(

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php codeigniter MySQL search query

- by kalafun

I want to create a search query on MySQL database that will consist of 5 different strings typed in from user. I want to query 5 different table columns with these strings. When I for example have input fields like: first name, last name, address, post number, city. How should I query the database that I dont always get all the rows. My query is something like this: SELECT user_id, username from users where a like %?% AND b like %?% AND c like %?% AND d like %?% AND e like %?%; When I exchange the AND for OR I always get all the results which makes sense, and when I use AND I get only the exact matches... Is there any function or statement that would help me with this?

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advanced search with mysql

- by Arsenal

I'm creating a search function for my website where the user can put in anything he likes in a textfield. It get's matched against anything (name, title, job, car brand, ... you name it) I initially wrote the query with an INNER JOIN on every table that needed to be searched. SELECT column1, column2, ... FROM person INNER JOIN person_car ON ... INNER JOIN car ... This ended up in a query with 6 or 8 INNER JOINs, and a whole lot WHERE ... LIKE '%searchvalue%' Now this query seems to cause a time'out in MySql, and I even got a warning from my hosting provider that the queries just taking up too many resources. Now obviously I'm doing this very wrong, but I was wondering how the correct approach to these kind of search functions is. Thanks!

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Getting mysql syntax error and cant find source

- by eGGzy

I have function that updates log table. function wslog($userID, $log, $where) { safe_query("INSERT INTO ".PREFIX."log ( time, userID, log, where ) values( '".time()."', '".$userID."', '".$log."', '".$where."' ) "); } And I have this php code: wslog($userID, 'server|'.mysql_insert_id().'', 'servers'); But I keep getting syntax error: Query failed: errorno=1064 error=You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where ) values( '1269208030', '1', 'server|14', 'servers' )' at line 1 query=INSERT INTO ws_DII_log ( time, userID, log, where ) values( '1269208030', '1', 'server|14', 'servers' )

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Regular Expression for exclude something that has specific word inside bracked (MySQL)

- by bn

This Regular expression if for MySQL query: I want to exclude this row because it has 'something' in side the bracket "bla bla bla bla bla bla (bla bla bla something)" However I want to include this row, because it does not have 'something' inside the bracket "bla bla bla (bla bla bla)" I tried this query but it didnt work. SELECT * FROM table WHERE field NOT REGEXP '((%something%))'; I think this is wrong, I just did trial and error, I like to use regular expression, but never understand it completely. is there any good tutorial/books/links for learning the detail of regular expression? Thank You

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MySQL storage engine dilemma

- by burntblark

There are two MySQL database features that I want to use in my application. The first is FULL-TEXT-SEARCH and TRANSACTIONS. Now, the dilemma here is that I cannot get this feature in one storage engine. It's either I use MyIsam (which has the FULL-TEXT-SEARCH feature) or I use InnoDB (which supports the TRANSACTION feature). I can't have both. My question is, is there anyway I can have both features in my application before I am forced to make a choice between the two storage engines.

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[php + mysql] Save IP in database

- by Knarf

When a user logs inn I want to save their IP in the database. How would I do that? What type is best to use for the MySQL field? How would the PHP code to get IP look like? I'm thinking of using it as an extra security feature for the login/session stuff. I'm thinking of checking the IP the user logged in with from the DB with the IP the user have now as addition to checking the session. So that it first check the session, and then check if you have a valid IP. Is that an allright extra feature? And what other things can I do to make it more secure?

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MySQL query with 2 COUNT() of other tables with where conditions

- by Isern Palaus

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MySQL get content from web page (or other network resource)

- by Rescommunes

Is it possible to open a curl like object in MySQL? What I would like to do is create procedure which would check to see if a certain value is returned from a specific URL like http://example.com/inschedule?id=200&time=20m. The returned result would be a simple string like 1 or 0. I know it is better to have a script do this by putting a entry into a table etc. However, it would be much less complex for me to be able to do it this way. Thanks

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Select unseen random row from MySQL table

- by user1476925

We have a list of questions in a MySQL database and want it to show a random approved question to the user. When you click the Random button, we want another random question to be shown, but not any of the ones the user has already seen. Right now the script looks like this: <?php mysql_connect("localhost", "username", "password") or die(mysql_error()); mysql_select_db("aldrig") or die(mysql_error()); $result = mysql_query("SELECT * FROM spg WHERE approved='1' ORDER BY RAND() LIMIT 1;") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { echo "<div class='contentTitle'><h1>"; echo $row['text']; echo "</h1></div>"; } ?>

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mysql PHP query question

- by camran

Ok, i have a problem here... I am sending values of drop down lists via ajax to this PHP file. Now I want to search a mysql database using these values, which I have managed to do, BUT, only if I set the values to something... Take a look: $query = "SELECT * FROM cars_db WHERE price BETWEEN '$cars_price_from' AND '$cars_price_to' AND year BETWEEN '$cars_year_from' AND '$cars_year_to' AND mileage BETWEEN '$cars_mileage_from' AND '$cars_mileage_to' AND gearbox = '$cars_gearbox' AND fuel = '$cars_fuel'"; now, what if the user doesnt select any "price_from" or "year_from"... The fields are only optional, so if the user doesnt enter any "price from" or "year from", then the user wants ALL cars to show... Do I have to write a query statement for each case or is there another way?

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MYSQL -Incorrect Syntax

- by user1854392

WHILE x > 1 DO SET x = x - 1; SET totalTime = SELECT CONCAT(FLOOR(HOUR(TIMEDIFF(end_time,start_time)) / 24), ' days ', MOD(HOUR(TIMEDIFF(end_time,start_time)), 24), ' hrs ', MINUTE(TIMEDIFF(end_time,start_time)), ' minutes ') AS total_Time I don't see why I am having a syntax error? It is part of a bigger procedure but is pointing to this aas being incorrect Error message: SQL Error (1064): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT CONCAT(FLOOR(HOUR(TIMEDIFF(end_time,start_time)) / 24,' days',' at line 11 and totalTime is declared as a VARCHAR(50)

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MySQL Integer vs DateTime index

- by David Kuridža

Let me start by saying I have looked at many similar questions asked, but all of them relate to Timestamp and DateTime field type without indexing. At least that is my understanding. As we all know, there are certain advantages when it comes to DateTime. Putting them aside for a minute, and assuming table's engine is InnoDB with 10+ million records, which query would perform faster when criteria is based on: DateTime with index int with index In other words, it is better to store date and time as DateTime or UNIX timestamp in int? Keep in mind there is no need for any built-in MySQL functions to be used.

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MySQL query problem

- by FinalDestiny

I have 2 mysql tables 1. questions: with the following columns: id, title, answer1, answer2, answer3, answer4, answer5, nranswers. and 2. answers with the following columns: id, questionid, userid, answer Every question has maximum 5 answers( it can have between 2 and 5 answers). My problem is that I want to select from my database, for a given question, how many times was every option selected. For example, let's suppose I have the question with the id 46, with 4 answers, and 48 users voted for the option #2, 37 users for the option #1 and 39 for the option #4. I want a query that selects that and write these things: 1 37 2 48 3 0 4 39 P.S. VERY IMPORTANT! IT MUST COUNT ONLY NRANSWERS ANSWERS, AND IT MUST ECHO THE ONES THAT WEREN'T VOTED BEFORE.

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dates when saving to mysql database

- by Patrick

in my php code I was asking the user to choose day, month and year from some dropdown fields where values where 1, 2, 3 etc instead of 01, 02, 03. these were then combined to form a string like "YYYY-MM-DD" for the insertion in a db (in a date field). Having missed the initial 0, I thought I was sending strings in the wrong format, eg "YYYY-M-D" or YYYY-MM-D", but then I've noticed they appear in the right format in the database anyway: even if I submitted YYYY-M-D, it appeared as YYYY-MM-DD. is this the normal behaviour of mysql? if so, can i just avoid worrying about changing the code in my application?

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foreach invalid argument supplied and mysql fetch array issue

- by La Myse

i have this code which i use to print some fields from the database. My problem is that i get this error about foreach invalid argument supplied and a mysql fetch array problem. The code is this: foreach( $checked1 as $key => $value){ echo "<th> $value </th>"; } echo "</tr></thead>"; while($row = mysql_fetch_array($result)){ Where $checked1 is an array $checked1 = $_POST['checkbox']; What's the problem here? Thanks..

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How to easily get the unmatched condition in mysql

- by leivli

I have a "server" table which has a column named 'SN' in mysql, when do query to retrive servers with some sns from 'sn1' to 'sn10000', we can: select * from server where sn in ('sn1','sn2','sn3',...'sn10000'); If there is only one sn in 'sn1'-'sn10000' which not exists in database, then the query above will retrive 9999 rows of result. The question is how can I easily get which one in 'sn1'-'sn10000' is not exists in database except the additional work, such as handling the result with shell script etc. I have an ugly sql like below can use: select * from (select 'sn1' as sn union select 'sn2' union select 'sn3' .... union select 'sn10000') as SN where not exists (select id from server where server.sn=SN.sn); Is Anyone has other better methods? Thanks.

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Separating MySQL SELECT statement based on data in a column

- by NightMICU

Hi everyone, I need to retrieve data (vehicle details, in this case) from a MySQL table tabled and then loop through the results to generate separate lists for each category of vehicle. Is there a simple way to do this without having to have a SELECT statement for each type of vehicle? If I were just doing this for one category, I would use the following: <?php $sql = "SELECT * FROM apparatus WHERE vehicleType = 'Support'; $getSQL = mysql_query($sql); ?> <ul> <?php while ($vehicleData = mysql_fetch_assoc($getSQL)) {?> <li><?php echo $vehicleData['name'];?></li> <?php } ?> </ul> ..etc. Need to do this for four different types of vehicles. Thanks!

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Error comparing hash to hashed mysql password (output values are equal)

- by Charlie

Im trying to compare a hashed password value in a mysql database with the hashed value of an inputted password from a login form. However, when I compare the two values it says they aren't equal. I removed the salt to simply, and then tested what the outputs were and got the same values $password1 = $_POST['password']; $hash = hash('sha256', $password1); ...connect to database, etc... $query = "SELECT * FROM users WHERE username = '$username1'"; $result = mysql_query($query); $userData = mysql_fetch_array($result); if($hash != $userData['password']) //incorrect password { echo $hash."|".$userData['password']; die(); } ...other code... Sample output: 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361| 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361 Any thoughts?

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Create a PHP cache system in MySQL database?

- by Zach Smith

I'm creating a web service that often scrapes data from remote web pages. After scraping this data, I have a simple multidimensional array of information to use. The scraping process is fairly taxing on my server, and the page load takes a while. I was considering adding a simple cache system using a MySQL database, where I create one row per remote web page with a the array of information pulled from it stored as a JSON encoded string. Is this a good enough system? Or would something like a text file per web page be a better idea?

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Export XML with only one MySQL request ?

- by mere-teresa

I want to export in XML format some data from 7 tables (MySQL database), and then I want to import in another database. And I have a update or insert rule for data. I already have a SQL query retrieving all data, with JOINs on my 7 tables. But...when I try to put data in XML format, I reach a limit. My PHP loop can catch each row, but I would like to benefit from hierachical structure of the XML, and all I have are rows with the same data repeated. It is better to query once and to construct the XML tree in PHP or to query each time I want access to a lower level ?

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MySQL COUNT help

- by space

I'm trying to count all the ids form table3 that are related to the first two tables but I think my SQL code is wrong can some one help me fix it? Here is the code: $dbc = mysqli_query($mysqli,"SELECT table1.*, table2.*, COUNT(id) as num, table3.id FROM table1 INNER JOIN table2 ON table1.id = table2.id INNER JOIN table3 ON table2.id = table3.id WHERE table2.id = '$id'"); Here is the error message. Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 4

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Getting Null value with JSON from MySQL, how to retrive data from MySQL to JSON correctly?

- by sky

I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script> This is the table: message Try iPhone post! Welcome to Yo~ :) ??!

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- by user1854392

- by David Kuridža

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